How many 1/4 inch cubes does it take to fill a box with width 1 inches, length 3 3/4 inches and height 1 1/2 inches?

Answer:

12x12 12x6 H = 46cm

Step-by-step explanation:

took quiz

Answer:

46 cm

Step-by-step explanation:

I learned this formula in math last year

Answer:

D

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

We can solve for H by isolating it on one side of the equation, as follows:

J/H - I/H = G

Taking H as the common denominator:

(J - I)/H = G

Multiplying both sides by H:

J - I = GH

Adding I to both sides:

J = GH + I

Dividing both sides by G:

H = (J - I)/G

So the answer is

(A)

H = (J - I)/G.

Answer:   A

Step-by-step explanation:

\(\frac{J}{H} = G + \frac{I}{H}\)                >Since you are solving for H bring I/H to the other side

                                   by subtracting I/H from both sides

\(\frac{J}{H}- \frac{I}{H} = G\)               >There is a common denominator so you can

                                   combine the fractions

\(\frac{J-I}{H} = G\)                   >Multiply both sides by H or cross multiply whichever

                                  way your mind things about how to get H on top

\(J-I = G(H)\)           >Divide both sides by G

\(\frac{J-I}{G} = H\)                   >Answer is A

Answer:

75+50x=25+70x

Step-by-step explanation:

x= the number of hours

Solve:

75+50x=25+70x

    -50x        -50x

75=  25+20x

-25  -25

50=  20x

/20   /20

x=2.5 hours

Answer:

3 cups is 6 dollars

5 is 10 dollars

and 7 is 14 dollars

Step-by-step explanation:

If one cup is equal to a worth of 2 dollars

than 2 cups would be 4 dollars

and 3 cups 6 dollars

and so on... to get the price, the amount of cups is just multiplied by 2

Answer:

3 cups = $6

5 cups = $10

and 7 cups = $14

Step-by-step explanation:

Answer:

it's Zac Efron for sure, Leonardo DiCaprio is just not the same...

Answer:

43.75 litters of petrol

Step-by-step explanation:

105/60 = 1.75

1.75(25) = 43.75

The Adjacent angle to <LON are <NOP, <NOK and <LOK.

When two angles share a shared vertex and side, they are said to be neighbouring angles. The vertex of an angle is the terminal of the rays that create the sides of an angle. When two adjacent angles have a common vertex and side, they might be complimentary or supplementary angles.

Now, the adjacent angle to <LON are <NOP, <NOK and <LOK.

Dexter claim is wrong because <MON is not adjacent to <LON, <MON is just a part of <LON.

and, the part of an angle cannot be considered as Adjacent angle.

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Answer:

.466.7 miles

Step-by-step explanation:

\(total \: cost - rental \: cost = \: the \: total \: cost \: for \: travel \: in \: miles\)

\(200 - 59.99 = 140.01 \)

\(\ 140.01 \div 0.30 = 466.7 \: miles\)

Answer:-4/15 - 17

negative 4 over 15 plus negative 17

Answer:14

Step-by-step explanation:

Answer:

Mike had 14 to begin with.

Step-by-step explanation:

16 - 9 = 7

7 x 2 = 14

14 / 2 = 7

9 + 7 = 16

Answer:

4

Step-by-step explanation:

(2^2)^1 =4

Answer:

A and B

Step-by-step explanation:

I took some paper and cut it to the shapes and folded them to see which ones are the answer and got those 2. :3

Answer:

-56 + 3 sqrt(2) /2

Step-by-step explanation:

f(x) = x^2 +2/sqrt{x}.

2f(2) - f(8).

First find f(2)

f(2) = 2^2 +2/sqrt{2} = 4 + 2/ sqrt(2)

Then f(8)

f(8) = 8^2 +2/sqrt{8} = 64 + 2 / sqrt(4)sqrt(2) = 64+ 2/2sqrt(2) = 64 + 1/ sqrt(2)

2f(2) - f(8).

2 * (4 + 2/ sqrt(2)) - (64 + 1/ sqrt(2))

8 + 4/ sqrt(2)  - 64 - 1/ sqrt(2)

Combine like terms

-56 +  3 / sqrt(2)

Rationalizing the second term

-56 + 3/ sqrt(2) * sqrt(2)/sqrt(2)

-56 + 3 sqrt(2) /2

Answer:

Prediction for 200 trials: A- 40 times, B- 56 times, C- 48 times, D- 32 times, E- 24 times

Step-by-step explanation:

A=10/50=1/5 (then multiply by 200)

B=14/50=7/25 (then multiply by 200)

C=12/50=6/25 (then multiply by 200)

D=8/50=4/25 (then multiply by 200)

E=6/50=3/25 (then multiply by 200)

Answer:

30 points

Step-by-step explanation:

\(\frac{16+26+20+28}{5} =24\)

90 + x = 24 * 5 = 120

x = 120 - 90 =30

Answer:

FG: 30

Sw: 27

Step-by-step explanation:

I came up with the same answer as dinahrosesoto

Part A: To calculate the measures of center, we can find the median and the mean for each school.

For Bay Side School, the median class size is the average of the 8th and 9th values when the data is sorted in ascending order. The 8th and 9th values are both 25, so the median class size is 25.

To find the mean class size for Bay Side School, we can add up all the class sizes and divide by the total number of classes. The sum of the class sizes is 12 + 12 + 12 + 14 + 15 + 15 + 16 + 16 + 18 + 18 + 20 + 20 + 23 + 25 + 25 = 243. There are 15 classes, so the mean class size is 243/15 ≈ 16.2.

For Seaside School, the median class size is the average of the 8th and 9th values when the data is sorted in ascending order. The 8th and 9th values are both 15, so the median class size is 15.

To find the mean class size for Seaside School, we can add up all the class sizes and divide by the total number of classes. The sum of the class sizes is 10 + 10 + 10 + 11 + 12 + 15 + 15 + 16 + 17 + 17Part A (continued):

18 + 18 + 20 + 20 + 25 = 222. There are 14 classes, so the mean class size is 222/14 ≈ 15.9.

Therefore, the measures of center for Bay Side School are: median = 25, mean ≈ 16.2.

The measures of center for Seaside School are: median = 15, mean ≈ 15.9.

Part B: To calculate the measures of variability, we can find the range and the interquartile range (IQR) for each school.

For Bay Side School, the range is the difference between the largest and smallest class sizes. The largest class size is 25, and the smallest class size is 12, so the range is 25 - 12 = 13.

To find the IQR for Bay Side School, we need to find the first quartile (Q1) and the third quartile (Q3) of the data. From the stem-and-leaf plot, we can see that Q1 is 15 and Q3 is 20. Therefore, the IQR is 20 - 15 = 5.

For Seaside School, the range is the difference between the largest and smallest class sizes. The largest class size is 25, and the smallest class size is 10, so the range is 25 - 10 = 15.

To find the IQRPart B (continued): for Seaside School, we need to find the first quartile (Q1) and the third quartile (Q3) of the data. From the stem-and-leaf plot, we can see that Q1 is 12 and Q3 is 18. Therefore, the IQR is 18 - 12 = 6.

Therefore, the measures of variability for Bay Side School are: range = 13, IQR = 5.

The measures of variability for Seaside School are: range = 15, IQR = 6.

Part C: If you are interested in a smaller class size, Seaside School is a better choice because its measures of center are lower than those of Bay Side School, indicating that its class sizes tend to be smaller on average. Additionally, Seaside School has a smaller range and IQR, indicating less variability in class size. Therefore, there is less chance of encountering very large classes at Seaside School compared to Bay Side School.

Answer:24

Step-by-step explanation:Exponential functions are of the form f(x) = ab^x

The complete statements: Function f → the linear function f(x) = 6x and consecutive differences are constant and  function g → the exponential function g(x) =  6(2)ˣ and consecutive quotients are constant.

When b > 0 and b ≠ 1, an exponential function has the form f(x) = (b)ˣ. The base is b, and the exponent is x, just as in any exponential equation.

Linear functions have constant first differences.

Here,  if a and b is the first and second term.

Then the first difference is b-a.

Exponential functions have a constant ratio.

The ratio of first term and second term is b/a.

Let f(x) = y

Here, from the table;

y₂-y₁ = 12 - 6 = 6

y₃-y₂ = 18 - 12 = 6

y₄-y₃ = 24 - 18 = 6

Consecutive differences are constant.

And the linear function is f(x) = 6x

From the first differences, we have linear function.

To find the common ratio, b :

Let g(x) = g

Then,

g₂/g₁ = 12/6 = 2

g₃/g₂ = 24 / 12 = 2

g₄/g₃ = 48 / 24 = 2

b =2

And the exponential function g(x) = 6(2)ˣ.

Therefore, the complete statements: Function f → the linear function f(x) = 6x and consecutive differences are constant and  function g → the exponential function g(x) =  6(2)ˣ and consecutive quotients are constant.

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Step-by-step explanation:

12• the graph pass by in × intercept - 3 / 2 or - 1 • 5

in y intercept 1 because

y - 1 = 2 / 3× means y = 2/3 × + 1 and y intercept we can get by assuming if × is = 0 and × value by assuming if y is equal to 0

so; × = { -3/ 2 , 0 } or { - 1 • 5 , 0 }

y= { 0 ,1 }

13 • by the same formula become the graph pass in × intercept -4/ 3 or 1• 3`

y intercept 4

Answer:

.1

Step-by-step explanation:

14.5-14.4=.1

Answer:

At 4:00 pm it was 31 F so at 3:30 it's at 30 F and at 12:00 it would be 23 F

Step-by-step explanation:

8 - 4 = 4pm

2 * 4 = 8 degrees

49 - 8 = 31 F

2 - 1 = 1 which is a half so 60 min divided by 1/2 is 30 so take 4:00 - 30min is 3:30

4pm to 12pm in time is 4

2 * 4 = 8

31 - 8 = 23 F

Answer:

At 4:00 pm it 31 F  at 3:30 it at 30 F and at 12:00 it will be 23 F

Step-by-step explanation: