What mass of water can be heated from 15.0° C to 43.1° C by the addition of 1282 J?
The mass of water that can be heated from 15.0° C to 43.1° C by the addition of 1282J is 10.9grams.
How to calculate mass?The mass of water can be calculated using the following expression;
Q = mc∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperatureAccording to this question, a sample of water can be heated from 15.0° C to 43.1° C by the addition of 1282J. The mass of the substance can be calculated as follows;
1282 = m × 4.184 × (43.1 - 15)
1282 = 117.57m
m = 10.9grams
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Prioritise the type of hammer you would use to drive or shape material that could easily be damaged by hammers such as the following:
Some common types of hammers and their uses are
Claw hammer - used for driving nails and removing themSledgehammer - used for heavy-duty jobs like breaking concrete or driving stakesFraming hammer - used for framing houses and other construction workWhich hammers are used for delicate shpaes?When working with delicate shapes, the following types of hammers can be used
Rubber Mallet - It has a rubber head that is used to avoid damage to the surface of the material while striking.
Soft-Face Hammer - This hammer has replaceable soft tips made of materials like nylon, brass, or plastic that prevent damage to the surface.
To mention a few.
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Which portion of a molecule of F2O has partial positive charge?
Question 3 options:
A)
The F atoms
B)
The central O atom
C)
The partial charge on each atom is zero
D)
The partial charge on each atom is negative
The partial charges on each fluorine atom are negative. Option B) The central O atom is the correct answer. Option B
The partial charges in a molecule are determined by the electronegativity values of the atoms involved. Electronegativity is the ability of an atom to attract electrons towards itself in a chemical bond. In the case of \(F_2O\), fluorine (F) is more electronegative than oxygen.
Fluorine is the most electronegative element on the periodic table, meaning it has a high ability to attract electrons. Oxygen is also relatively electronegative but less so than fluorine. When fluorine atoms bond with oxygen, the shared electrons will be pulled more towards the fluorine atoms, creating a polar covalent bond.
In \(F_2O\), each fluorine atom will pull the shared electrons towards itself, resulting in a higher electron density around the fluorine atoms. This creates a region of partial negative charge around the fluorine atoms.
Conversely, the oxygen atom will have a region of lower electron density and, therefore, a partial positive charge. This is because the shared electrons spend more time around the fluorine atoms due to their higher electronegativity.
Option B
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wer the following items on a separate piece of paper.
LTIPLE CHOICE
-.Which of the following relationships is true?
A. Higher-energy light has a higher frequency
than lower-energy light does.
B. Higher-energy light has a longer wavelength
than lower-energy light does.
C. Higher-energy light travels at a faster speed
than lower-energy light does.
D. Higher-frequency light travels at a slower
speed than lower-energy light does.
The answer option which indicates a true relationship is: A. Higher-energy light has a higher frequency than lower-energy light does.
A wave can be defined as a disturbance in a medium that progressively transports energy from its source to another location, without an equivalent transportation of matter.
In Science (Physics), there are two main types of wave:
Mechanical wave.Electromagnetic wave.Light energy is an example of electromagnetic wave because it does not require a medium of propagation for it to travel.
Hence, light energy can travel through a vacuum (space), where no particles exist.
In Science, light energy are grouped into two main categories and these are:
I. Higher-energy light: it has a higher frequency in comparison with others.
II. Lower-energy light: it is typically characterized by a lower frequency.
In conclusion, a higher-energy light has a higher frequency while lower-energy light has a lower frequency.
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Answer:
A. Higher-energy light has a higher frequency than lower-energy light does.
Explanation:
Correct Answer
A 200 N force is applied to an object, which then accelerates at 2 m/s². What is the mass of the object?
The mass of the object that is acted on by a force of 200 N is 100 kg
What is mass?Mass can be defined as the quantity of matter a body contains.
To calculate the mass of the object, we use the formula below.
Formula:
m = F/a................ Equation 1Where:
m = Mass of the objectF = Force of the objecta = Acceleration due to gravityFrom the question,
F = 200 Na = 2 m/s²Substitute these values into equation 1
m = 200/2m = 100 kgHence, the mass of the object is 100 kg.
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perform the following mathematical operation, and report the answer to the correct number of significant figures. 0.34 x 0.568=?
How do I know how many significant figures to round to?
The correct answer to the problem is 0.193 which is three significant figures.
What are significant figures?The term significant figures has to do with the figures that have a mathematical meaning. We know that the result has to correspond to the highest number of significant figures.
Hence, If we multiply 0.34 x 0.568 the result ought to be recorded as 0.193 which is three significant figures.
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Marlon is viewing a paramecium. He wants to use his observations to correctly classify it into the appropriate Kingdom. He observes that it has a nucleus. What conclusion can he make about the cell?
Marlon can conclude that the cell belongs to the Kingdom Protista if he observes that the paramecium has a nucleus.
The presence of a nucleus is a characteristic feature of eukaryotic cells, which are found in Protists, Fungi, Plants, and Animals. Therefore, if Marlon observes that the paramecium has a nucleus, he can conclude that the cell belongs to the Kingdom Protista, which includes unicellular eukaryotic organisms.
The presence of a nucleus is one of the defining features of eukaryotic cells, which are found in Protists, Fungi, Plants, and Animals. The Protista Kingdom includes unicellular organisms that have a nucleus and other membrane-bound organelles.
However, he would need to observe other features of the cell to further classify it into a specific group or species within the Protista Kingdom.
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17 Which changes decrease the rate of reaction between magnesium and air?
1.heating the magnesium to a higher temperature
2.using a higher proportion of oxygen in the air
3.using magnesium ribbon instead of powdered magnesium
A 1, 2 and 3
B 1 only
C 2 only
D 3 only
Using magnesium ribbon instead of powdered magnesium decrease the rate of reaction between magnesium and air.
What is rate of reaction?Rate of reaction tells about the duration of the completion of the reaction.
Rate of any reaction is directly proportional to the concentration and surface area of the reactant, temperature, catalyst, no. of collision, activation energy, etc.
So, if we magnesium in the ribbon instead of powdered magnesium the surface area of the reactant side decreases which results in the decrease of the rate of reaction.
Hence, option (D) is correct i.e. rate of reaction decreases on using magnesium ribbon instead of powdered magnesium.
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130 cm of a gas at 20°C exerts a pressure of
750 mm Hg. Calculate its pressure if its volume
is increased to 150 cm3 at 35 °C.
Answer: The pressure is 1137.5 mm Hg its pressure if its volume is increased to 150 \(cm^{3}\) at 35 °C
Explanation:
Given: \(P_{1}\) = 750 mm Hg, \(V_{1} = 130 cm^{3}\), \(T_{1} = 20^{o}C\)
\(P_{2}\) = ?, \(V_{2} = 150 cm^{3}\), \(T_{2} = 35^{o}C\)
Formula used to calculate the new pressure is as follows.
\(\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\)
Substitute the values into above formula as follows.
\(\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{750 mm Hg \times 130 cm^{3}}{20^{o}C} = \frac{P_{2} \times 150 cm^{3}}{35^{o}C}\\P_{2} = 1137.5 mm Hg\)
Thus, we can conclude that the pressure is 1137.5 mm Hg its pressure if its volume is increased to 150 \(cm^{3}\) at 35 °C.
Convert 355 kJ to Cal
how did the scientist explain the relationship beetween the colors observed and the structure of the atom
Answer:
The colors observed is a sign that definite energy transformations occurs inside the atom gives off light. It follows that electrons must occupy orbits of fixed energy.
Hope that helps!
Q16. Choose whether this is a physical or chemical change. *
cream
being
whipped
Because air puffs up the cream as it is whipped, there is a physical change even though the ingredients are still cream and air.
What is physical change ?Physical modifications are those that affect a chemical substance's form but not its chemical content. Physical changes may normally be used to separate compounds into chemical elements or simpler compounds, but they cannot be used to separate mixtures into their component compounds.
Liquid cream is extensively combined with small air bubbles to form the foam colloid known as whipped cream. Because milk is transformed from a colloid (cream) to a solid (butter) without changing its chemical makeup, turning milk into butter is a physical transformation. This change in the body can be undone.
Thus, there is a physical change even though the ingredients are still cream and air.
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Grams, Moles, Atoms, MoleculesShow calculation setups, including units, and enter answers with correct significant figures andunits on the line(s) provided.1. Find the molar mass to 3 decimal places of (a) magnesium sulfate, (b) diphosphorus heptoxide,and (c) iron(III) hydroxide. Use these values as needed in problems 2 - 4(a)MasoMgS-Ou(b)(c)
To find the molar mass of each compound we need the molar masses of the elements in the compound and its chemical formula.
For magnesium sulfate, MgSO₄, there are 1 atom of magnesium, one of sulfur and 4 of oxygen. Multiply each molar mass by the number of atoms of the element and then find the sum of those products:
\(\begin{gathered} Mg\to24.3\cdot1=24.3 \\ S\to32.01\cdot1=32.01 \\ O\to16.0\cdot4=64.0 \\ mm=24.3+32.0+64.0=120.310 \end{gathered}\)The molar mass of magnesium sulfate is 120.310g/mol.
For diphosphorus heptoxide, P₂O₇, there are 2 atoms of phosphorus and 7 of oxygen:
\(\begin{gathered} P\to30.97\cdot2=61.94 \\ O\to16.00\cdot7=112 \\ mm=61.94+112=173.94 \end{gathered}\)The molar mass of diphosphorus heptoxide is 173.940g/mol.
For iron(III) hydroxide, Fe(OH)₃, there are 1 atom of iron, 3 of hydrogen and 3 of oxygen:
\(\begin{gathered} Fe\to55.84\cdot1=55.84 \\ H\to1\cdot3=3 \\ O\to16.00\cdot3=48.00 \\ mm=55.84+3+48=106.84 \end{gathered}\)The molar mass of iron(III) hydroxide is 106.840g/mol.
Find the density if the volume is 15 mL and the mass is 8.6 g. (5 pts)
Find the volume if the density is 2.6 g/mL and the mass is 9.7 g.(5 pts)
Find the mass if the density is 1.6 g/cm3 and the volume is 4.1 cm3 (5 pts)
Find the density if the initial volume of water is 12.8 mL, the final volume is 24.6 mL and the mass of the object is 4.3 g. Make a drawing to show the water displacement using a graduated cylinder. (gdoc, gdraw)
Answer:
\(\large \boxed{\text{0.57 g/mL; 3.7 mL; 6.6 g; 0.366 g/mL}}\)
Explanation:
1. Density from mass and volume
\(\text{Density} = \dfrac{\text{mass}}{\text{volume}}\\\\\rho = \dfrac{m}{V}\\\\\rho = \dfrac{\text{8.6 g}}{\text{15 mL}} = \text{0.57 g/mL}\\\text{The density is $\large \boxed{\textbf{0.57 g/mL}}$}\)
2. Volume from density and mass
\(V = \text{9.7 g}\times\dfrac{\text{1 mL}}{\text{2.6 g}} = \text{3.7 mL}\\\\\text{The volume is $\large \boxed{\textbf{3.7 mL}}$}\)
3. Mass from density and volume
\(\text{Mass} = \text{4.1 cm}^{3} \times \dfrac{\text{1.6 g}}{\text{1 cm}^{3}} = \textbf{6.6 g}\\\\\text{The mass is $\large \boxed{\textbf{6.6 g}}$}\)
4. Density by displacement
Volume of water + object = 24.6 mL
Volume of water = 12.8 mL
Volume of object = 11.8 mL
\(\rho = \dfrac{\text{4.3 g}}{\text{11.8 mL}} = \text{0.36 g/mL}\\\text{The density is $\large \boxed{\textbf{0.36 g/mL}}$}\)
Your drawing showing water displacement using a graduated cylinder should resemble the figure below.
What is the molar mass
MgCrO4
The molar mass of MgCrO4 is approximately 140.30 g/mol.
To determine the molar mass of MgCrO4 (magnesium chromate), we need to calculate the sum of the atomic masses of each individual element in the compound.
The chemical formula MgCrO4 indicates that the compound consists of one magnesium atom (Mg), one chromium atom (Cr), and four oxygen atoms (O).
The atomic masses of the elements can be found on the periodic table:
Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol.
Chromium (Cr) has an atomic mass of around 51.99 g/mol.
Oxygen (O) has an atomic mass of about 16.00 g/mol.
Now, we can calculate the molar mass of MgCrO4 by summing up the atomic masses of each element, considering the respective subscripts:
Molar mass = (Atomic mass of Mg) + (Atomic mass of Cr) + 4 × (Atomic mass of O)
Molar mass = (24.31 g/mol) + (51.99 g/mol) + 4 × (16.00 g/mol)
Molar mass = 24.31 g/mol + 51.99 g/mol + 64.00 g/mol
Molar mass ≈ 140.30 g/mol
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If you have a 1.45-mol sample of iron, how many moles of Fe2O3 will there be after the iron has
rusted completely?
Answer:
3/4 of a mol of Rust
Explanation:
The first thing you have to do is work from a balanced equation.
4Fe + 3O2 ====> 2Fe2O3
Left
4 Fe
6 Oxygens
Right
4Fe
2*3 = 6 Oxygens
So you have a balanced equation
4Fe + 3O2 ====> 2Fe2O3
1.5 x
The next (and last) thing to do is to set up a proportion
4/1.5 = 2/x Cross multiply
4x = 1.5*2 Combine
4x = 3 Divide by 4
4x/4 = 3/4
x = 3/4 mol
mass of 1×10^25 molecules of water
Answer:
1.E25 it is the answer the answer to mass of 1×10^25 molecules of water
Explanation:
this is just EXPLINATION find your answer using this
first divide the number of molecules by Avogadro's number 6.022*10^25
you will
l get no. of Moles of water
multiply the no. of Moles with mass of 1 Mole of water 18g per mole
if get answer you comment
you should try on your own you will understand better
25 ml of 10m ch3cooh aq is titrated with 0.050M naoh aq k 1.8 10 5 . what is the ph at the neutralization point
the pH at the neutralization point is: \(pH = -log[H3O^+] = -log(1.68 \times 10^-4) = 3.77\)
What is the pH at the neutralization point?To determine the pH at the neutralization point, we first need to calculate the moles of \(NaOH\) used to neutralize the acetic acid:
moles of \(CH3COOH =\) (volume in liters) x (concentration in mol/L) = \((25/1000) x 10 = 0.25 mmol\)
moles of \(NaOH =\) (concentration in mol/L) x (volume in liters) \(= 0.050 x\)(volume in liters)
At the neutralization point, the moles of \(NaOH\) will be equal to the moles of \(CH3COOH\) :
\(0.25 mmol = 0.050 \times\) (volume in liters)
volume in liters \(= 5 mL\)
So, it takes \(5 mL\) of \(0.050 M NaOH\) to neutralize \(25 mL\) of 0.10 M \(CH_3COOH.\)
Now, we need to calculate the concentration of \(CH3COOH\) and \(CH3COO-\)(acetate ion) in the solution after the addition of 5 mL of NaOH:
moles of CH3COOH remaining = moles of \(CH_3COOH\) initially - moles of NaOH added
\(= 0.25 mmol - 0.050 mmol = 0.20 mmol\)
volume of final solution \(= 25 mL + 5 mL = 30 mL\)
concentration of \(CH_3COOH =\) (moles of \(CH_3COOH\) remaining) / (volume in liters) \(= 0.20 mmol / 0.030 L = 6.67 mM\)
concentration of CH3COO- = (moles of NaOH added) / (volume in liters) \(= 0.050 mmol / 0.030 L = 1.67 mM\)
Next, we can use the equilibrium expression for the dissociation of acetic acid to calculate the pH:
\(CH3COOH + H2O \rightleftharpoons CH3COO- + H3O+\)
\(Ka = [CH3COO-][H3O+] / [CH3COOH]\)
At the neutralization point, \([CH3COOH] = [CH3COO-] = 0.5 \times 6.67 mM = 3.33 mM\)
\(Ka = 1.8 x 10^-5\)
Solving for \([H3O^+]\), we get:
\([H3O+] = \sqrt (Ka x [CH3COOH]) = \sqrt (1.8 \times 10^-5 \times 3.33 \times 10^-3) = 1.68 \times 10^-4 M\)
Therefore, the pH at the neutralization point is: \(pH = -log[H3O^+] = -log(1.68 \times 10^-4) = 3.77\)
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A patient needs 3.30×10−2 g of a sulfa drug. There are 5.00 mg tablets in stock. How many tablets should be given?
Answer: 6.6.0gdm^-3
Bamstep
What are the possible values of 1 and m for
n=4 ?
Answer:
If n = 4, then the possible values of 1 and m depend on the equation or expression being used. Without more information, it is impossible to determine what the possible values of 1 and m might be. Can you please provide more context or information about the problem you are trying to solve?
Determine the total kilojoules in two tablespoons
The total kilojoules in two tablespoons is 836.8 kJ.
To determine the total kilojoules in two tablespoons of a substance, we need to know the specific substance and its energy content per tablespoon. Different substances have different energy values, so without this information, it is not possible to provide an accurate calculation.
The energy content of food or substances is typically measured in kilocalories (kcal) or kilojoules (kJ). 1 kilocalorie is equal to 4.184 kilojoules. The energy content of a substance is often listed on food labels or in nutritional databases.
For example, if we have the energy content of a substance as 100 kilocalories (kcal) per tablespoon, we can convert it to kilojoules by multiplying it by 4.184:
100 kcal * 4.184 kJ/kcal = 418.4 kJ
So, if we have two tablespoons of this substance, the total energy would be:
418.4 kJ/tablespoon * 2 tablespoons = 836.8 kJ
It's important to note that the energy content of a substance can vary depending on its composition, density, and other factors. Therefore, it is always recommended to refer to reliable sources such as food labels, nutritional databases, or consult a qualified professional to obtain accurate information regarding the energy content of specific substances.
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An unknown element is a mixture of isotopes ¹²⁹X and ¹³²X. The average atomic mass of X is 131.01 amu. What is the percent abundance of ¹³²X?
Answer: 67%
Explanation: The weighted averages of the two isotopes must add to 131.01. Let Y be the percentage of isotope 129. Then (1-Y) will be the percentage of isotope 132. The weighted average of each is:
129: 129Y
132: 132(1-Y)
Their sum is equal to 131.01
129Y + 132(1-Y) = 131.01
Y = 0.33, or 33%
(1-Y) = 0.67, or 67%
Check: 129*(0.33) = 42.57
132*(0.67) = 88.44
Sum = 131.01 It checks OK The 132 isotopes is 67% of the sample.
Considering the definition of atomic mass, isotopes and atomic mass of an element, the percent abundance of ¹³²X is 67%.
Definition of atomic massFirst of all, the atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus of a chemical element.
Definition of isotopeThe same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.
Definition of atomic massOn the other hand, the atomic mass of an element is the weighted average mass of its natural isotopes. In other words, the atomic masses of chemical elements are usually calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.
Percent abundance of ¹³²XIn this case, you know:
An isotope has an atomic mass of 132 amu and a percent natural abundance of y.An isotope has an atomic mass of 129 amu and a percent natural abundance of 1-y. The average atomic mass of X is 131.01 amuThen, the average mass of X can be calculated as:
132 amu×y + 129 amu×( 1-y)= 131.01 amu
Solving, you can find the percent abundance of ¹³²X:
132 amu×y + 129 amu×1 - 129 amu×y= 131.01 amu
132 amu×y + 129 amu - 129 amu×y= 131.01 amu
132 amu×y - 129 amu×y= 131.01 amu - 129 amu
3 amu×y= 2.01 amu
y= 2.01 amu÷ 3 amu
y= 0.67= 67%
Finally, the percent abundance of ¹³²X is 67%.
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a. Identify the structures shown in the diagram. b. Identify the information that is contained within these structures. c. Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person. d. Explain why the structures are in pairs.
The answer responses to the structures shown in the diagram are:
A. chromosomes
C. They would be the same.
B. They are in pairs because each one comes from a different parent.
What is the structure about?The chromosomes are in pairs because humans have a diploid number of chromosomes, meaning they have two sets of chromosomes, one inherited from each parent.
The nucleus is important in eukaryotic cells and has many important parts that help the cell work properly. There are some parts inside cells called the nuclear membrane, nucleoplasm, nucleolus, and chromatin. Chromatin is made up of DNA and other proteins.
Every part of a person's body has the same genes, but the way they are organized can be different in different types of cells. The chromosomes in our skin cells might not be the same as the chromosomes in our muscle cells, even if they come from the same person.
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Identify the structures shown.
A. chromosomes
B. mitochondria
C. nuclei
D. vacuoles
C
Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.
A. There would be longer.
B. They would be shorter.
C. They would be the same.
D. They would be different.
Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.
A. There would be longer.
B. They would be shorter.
C. They would be the same.
D. They would be different.
Explain why the structures are in pairs.
A. They aren't in pairs.
B. They are in pairs because each one comes from a different parent.
C. This cell is making a copy of itself.
D. The cell always has 2 copies in case 1 is damaged.
HIGH SCHOOL CHEMISTRY 25 PTS
Consider the following intermediate chemical equations.
3 equations. 1: upper C solid plus upper o subscript 2 gas right arrow upper C upper O subscript 2 gas Delta H 1 equals negative 393.5 kilojoules. 2: 2 upper C upper O gas plus upper O subscript 2 gas right arrow 2 upper C upper O subscript 2 gas Delta H 2 equals negative 566.0 kilojoules. 3: 2 upper H subscript 2 upper o gas right arrow 2 upper H subscript 2 gas plus upper O subscript 2 gas delta H 3 equals 483.6 kilojoules.
The overall chemical equation is Upper C (s) plus upper H subscript 2 upper O (g) right arrow upper C upper o (g) plus upper H subscript 2 (g).. To calculate the final enthalpy of the overall chemical equation, which step must occur?
~Reverse the first equation, and change the sign of the enthalpy. Then, add.
~Reverse the second equation, and change the sign of the enthalpy. Then, add.
~Multiply the first equation by three, and triple the enthalpy. Then, add.
~Divide the third equation by two, and double the enthalpy. Then, add.
Answer: The enthalpy of the second intermediate equation is halved and has its sign changed.
Explanation:
Let us take a look at the first and second intermediate reactions as well as the overall reaction equation for the process under review;
First reaction;
Ca (s) + CO₂ (g) + ½O₂ (g) → CaCO₃ (s) ΔH₁ = -812.8 kJ
Second reaction;
2Ca (s) + O₂ (g) → 2CaO (s) ΔH₂ = -1269 kJ
Hence the overall equation is now;
CaO (s) + CO₂ (g) → CaCO₃ (s) ΔH = ?
According to the Hess law of constant heat summation, the enthalpy of the overall reaction is supposed to be obtained as a sum of the enthalpy of both reactions but this will not give the enthalpy of the overall reaction in this case. The enthalpy of the overall reaction is rather obtained by halving the enthalpy of the second intermediate reaction and reversing its sign before taking the sum as shown below;
Enthalpy of Intermediate reaction 1 + ½(- Enthalpy of Intermediate reaction 2) = Enthalpy of Overall reaction
The final enthalpy will be:
The enthalpy of the second intermediate equation is halved and has its sign changed.
Hess's law:First reaction:
Ca (s) + CO₂ (g) + ½O₂ (g) → CaCO₃ (s) ΔH₁ = -812.8 kJ
Second reaction:
2Ca (s) + O₂ (g) → 2CaO (s) ΔH₂ = -1269 kJ
Overall reaction:
CaO (s) + CO₂ (g) → CaCO₃ (s) ΔH = ?
According to the Hess law of constant heat summation, the enthalpy of the overall reaction is the sum of the enthalpy of both reactions but this will not give the enthalpy of the overall reaction in this case. The enthalpy of the overall reaction is rather obtained by halving the enthalpy of the second intermediate reaction and reversing its sign before taking the sum as shown below;
Enthalpy of Intermediate reaction 1 + ½(- Enthalpy of Intermediate reaction 2) = Enthalpy of Overall reaction
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How are radiation levels kept in balance?
Outgoing
Earth emits
Back toward the sun in the form of
Answer:
Explanation:We known that Earths energy machine is driven by sunlight which acts as fuel for this machine and to strike a balance between outgoing long wave radiation and short wave radiation there are many factors which are involved in this process.Sun emits this energy in the form of short wave radiation because of the huge energy it has and short wave radiation are higher in energy.Hence, they reach the earth surface mostly as visible and UV rays.After reaching the earths surface what happens with these rays is that they get absorbed by the clouds and other constituents of Earth.
Now, this energy needs to be emitted back in to space in order to balance out the energy budget of earth and that is why this energy is emitted back as long wave radiation which have less energy and also earth has less energy unlike the sun.Loss of this energy is essential as Earth looses most of its energy through this and results in cooling.But when this OLR decreases it should be a cause of concern for us.
This imbalance is caused by a wide range of different human induced activities which has a cumulative effect on the temperature of earth.These activities gives rise to a huge gain in the CO2 concentration which is why this word has gain so much popularity and a cause of widespread concern for us.At community level we contribute to this heating by increasing usage of personal automobiles rather than going for public transport , advancement in technology has greatly changed our lifestyles making it more simpler and easier but this demands more energy consumption.Landscape changes are one of the most important because its taking place at a faster rate.Most of the land being cleared off to built new houses which means clearing off the existing vegetation which leads to temperature rise.Setting up of Industry depending on its type can reduce the amount of OLR escaping the surface by introducing more amount of GHGs in to the atmosphere.
Its these small communities which add up to become the entire human population causing a massive damage and hence at community level if people realize and take necessary steps things will start to change.
Calcium carbonate decomposes to form calcium oxide and carbon dioxide, like this:
CaCO3(s)→CaO(s)+CO2(g)
At a certain temperature, a chemist finds that a 9.0L reaction vessel containing a mixture of calcium carbonate, calcium oxide, and carbon dioxide at equilibrium has the following composition:
Compound Amount
CaCO3 25.3 g
CaO 14.9 g
CO2 33.7 g
Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.
Answer: The value of the equilibrium constant Kc for this reaction is 0.088
Explanation:
\(Molarity=\frac{x}{M\times V_s}\)
where,
x = given mass
M = molar mass
\(V_s\) = volume of solution in L
Equilibrium concentration of \(CaCO_3\) = \(\frac{25.3}{100\times 9.0}=0.028M\)
Equilibrium concentration of \(CaO\) = \(\frac{14.9}{56\times 9.0}=0.029M\)
Equilibrium concentration of \(CO_2\) = \(\frac{33.7}{44\times 9.0}=0.085M\)
The given balanced equilibrium reaction is,
\(CaCO_3(s)\rightleftharpoons CaO(s)+CO_2(g)\)
The expression for equilibrium constant for this reaction will be,
\(K_c=\frac{[CaO]\times [CO_2]}{[CaCO_3]}\)
Now put all the given values in this expression, we get :
\(K_c=\frac{0.029\times 0.085}{0.028}=0.088\)
Plate Tectonic Theory is the theory that the world was once 1 continent called Pangea.
O True
O False
Answer:
true
Explanation:
a specialist that study substance obtained by attained mining is called a what
Answer:
Explanation:
Mining:
Mining is when certain substances are removed from the Earth, usually in large quantities. Mining can occur below the surface of the Earth via tunnels and caves. It can also occur at surface level through methods such as strip mining, which removes huge amounts of soil in the process
8. What is the boiling point elevation (AT) of a solution containing 255 grams of non- electrolyte sucrose (molar mass-342 g/mole) in 812 g of water (Ko(water) = 0.520 °C/m)?
PLSASE HURRY I REALLY NEED IT
Consider this graph showing temperature over time. What would happen in the situation? The temperature decreases from 25° to 15°C, the material ____ heat and its kinetic energy ____ as the material, freezes to become a solid.
Answer:
One of the major effects of heat transfer is temperature change: heating increases the temperature while cooling decreases it. We assume that there is no phase change and that no work is done on or by the system. Experiments show that the transferred heat depends on three factors—the change in temperature, the mass of the system, and the substance and phase of the substance.