how long does it take an automobile traveling in the left lane at 64.2 km/h to overtake (become even with) another car that is traveling in the right lane at 42.1 km/h, when the cars' front bumpers are initially 81.2 m apart?

To determine the mass of granite, we must first understand the definition of density. Density is defined as the amount of matter present in a substance per unit volume.

We use the formula: density = mass/volume to calculate the mass of a substance given its density and volume. To calculate the mass of 54.3 m³ of granite, we use the following steps:

Given Density of granite = 2700 kg/m³Given volume of granite = 54.3 m³Let us substitute the values in the formula of density:density = mass/volume Solving for mass, we get:mass = density × volume Substitute the given values of density and volume into the formula:mass = 2700 kg/m³ × 54.3 m³

The m³ unit in the volume cancels out, leaving us with kg as the unit for mass.

We then solve the equation to get the mass:mass = 146,610 kg

Therefore, the mass of 54.3 m³ of granite is 146,610 kg.

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Answer:

14,400m

Explanation:

The formula for calculating speed is S=D/T.

S=speed( in meters per second- m/s)

D=distance(in meters)

T=time( in seconds)

For our case:

S=40m/s

D=?

Time=2 hours=60min x 60 sec=3600seconds

Now make D the subject.

D=S x T

D=4m/s x 3600s=14,400m

Therefore our answer is

14 400 m or 14.4 km

Answer:

The water table is the upper surface of the zone of saturation. The zone of saturation is where the pores and fractures of the ground are saturated with water. It can also be simply explained as, the upper level, below which the ground is saturated.

Answer:

hey

Explanation:

hey

Answer:

Conscience

Explanation:

Conscience refers to a person's moral sense to differentiate between right and wrong to judge one's behaviour.

Jerrold just broke up with his girlfriend and is describing his current feelings about the breakup to his friend.

So, he pull the information from the conscience of Jerrold's mind.

The mechanical equilibrium condition allows to find the value of the normal for the body is:

Newton's second law establishes a relationship between the force, the mass and the acceleration of bodies, in the special case that the acceleration is zero, it is called a mechanical equilibrium condition.

       ∑ F = 0

A free body diagram is a diagram of the forces without the details of the bodies, in the attachment we can see this diagram, let's write the equilibrium condition for each axis.

x- axis

          Fₓ -fr = 0

y-axis

          F_y + N – W =0

Let's use trigonometry to find the components of the applied force.

            Cos 30= \(\frac{F_x}{F} \)

            sin 30 = \(\frac{F_y}{F } \)

            Fₓ = F cos 30

            \(F_y\) = F sin 30

The weight of a body is the mass times the acceleration due to gravity.

           W = m g

Let's substitute.

           F sin 30 + N – m g = 0

           N= m g – F sin 30

Let's calculate.

           N = m 9.8 – 150 sin  30

           N = m 9.8 - 75

To finish the calculation, the mass of the body must be known, suppose a value of 10 kg.

          N=10 9.8 -75

          N = 23N

In conclusion using the mechanical equilibrium condition we can find the value of the normal for the body is:

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Answer:

Explanation:

If the passage of the waves is one crest every 2.5 seconds, then that is the frequency of the wave, f.

The distance between the 2 crests (or troughs) is the wavelength, λ.

We want the velocity of this wave. The equation that relates these 3 things is

\(f=\frac{v}{\lambda}\) and filling in:

\(2.5=\frac{v}{2.0}\) so

v = 2.5(2.0) and

v = 5.0 m/s

Answer: Use less water

only turn on lights when needed

electrical cars

less gas usage

Explanation:

When two fluids with densities of 1500 kg/m³ and 500 kg/m³ are mixed, the difference in densities of the resulting mixture is 1000 kg/m³. This can be calculated by subtracting the lower density from the higher density.

To determine the difference in densities of the mixture, we need to consider the mass and volume of each fluid in the two compartments. Let's assume that the mass and volume of each fluid are equal.

For the first compartment, with a fluid density of 1500 kg/m³, the mass of the fluid will be equal to the volume multiplied by the density. Similarly, for the second compartment, with a fluid density of 500 kg/m³, the mass of the fluid will also be equal to the volume multiplied by the density.

When the partition is removed and the fluids mix, the total mass of the mixture will be the sum of the masses of the fluids from both compartments. Since the masses of the fluids were equal, the total mass of the mixture will be twice the mass of each fluid.

The total volume of the mixture will also be the sum of the volumes of the fluids from both compartments, which is equal to twice the volume of each fluid.

Therefore, the difference in densities of the mixture for fluid with equal masses to that of fluid with equal volumes can be calculated as the total mass divided by the total volume. In this case, it will be twice the mass of each fluid divided by twice the volume of each fluid, which simplifies to the ratio of their individual densities.

So, the difference in densities of the mixture will be 1500 kg/m³ - 500 kg/m³ = 1000 kg/m³.

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Sorry your tired, ill try to make it worth reading.

One day I walked outside, I looked around. THEN BAM a wasp lands right on my face. Its hideously sharp stinger impaled my flesh. I could almost hear it going deeper and deeper. I screamed and ran around in circles until it finely flew away. As I started walking to the door I could feel my heart pules where the thing had stung. I opened the door and went into the bathroom. Right in the middle of my face just above my nose was a red dot, with a slightly less red ring around it, like an ateroid impact. I sat down and went over the entire event five times. I decided to go back outside, as I walked around the corner, another wasp landed on me.

Answer:

Gpe = 30000J

Explanation:

Given the following data;

Weight = 100N

Height = 300m

To find the gravitational potential energy (gpe);

Gravitational potential energy can be defined as an energy possessed by an object or body due to its position above the earth surface.

Mathematically, potential energy is given by the formula;

\( G.P.E = mgh\)

Where,

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Gpe = mgh

But weight = mg = 100N

Substituting into the equation, we have:

Gpe = 100*300

Gpe = 30000J

The cross product of A and B is perpendicular to both A and B.

A × B = (4i + 2j + 2k) × (4i - 4j + 8k)

A × B = 16 (i × i) - 16 (i × j) + 32 (i × k) + 8 (j × i) - 8 (j × j) + 16 (j × k) + 8 (k × i) - 8 (k × j) + 16 (k × k)

A × B = -16 (i × j) - 32 (k × i) - 8 (i × j) + 16 (j × k) + 8 (k × i) + 8 (j × k)

A × B = -16k - 32j - 8k + 16i + 8j + 8i

A × B = 24i - 24j - 24k

The magnitude of A × B is

||A × B|| = 24 ||i - j - k|| = 24√3

Dividing A × B by its magnitude gives a unit vector,

(A × B)/||A × B|| = 1/√3 (i - j - k)

To calculate the water pressure that acts on the hull of the boat, we can use the equation:

Pressure = Force / Area

The force acting on the hull is the buoyant force, which is equal to the weight of the water displaced by the boat. Since the boat is floating, the weight of the water displaced is equal to the weight of the boat. Therefore:

Force = Weight of boat = 20,000 N

The area of the hull that is in contact with the water is 4 m2

Therefore, the water pressure acting on the hull of the boat is:

Pressure = Force / Area = 20,000 N / 4 m2 = 5000 N/m^2

The pressure unit is Newtons per square meter (N/m^2) also known as Pascals (Pa).

It's important to note that the weight of the boat and the water displaced are in Newtons and the area of the hull is in square meter, that's why the pressure is in N/m^2.

The thermal conductivity of the material is 0.238 W/m°C and the initial temperature of the object is 209°C.

i. Length of the conductor, L = 20 cm = 0.2 m

Time taken, t = 6 s

Cross-sectional area, A = 55 cm² = 55 × 10⁻⁴ m²

Heat transferred, Q = 3000 J

Temperature difference, ΔT = 67°C

Thermal conductivity of the material, K = ?

Formula used: Heat transferred, Q = K × A × ΔT ÷ L

where Q is the heat transferred, K is the thermal conductivity of the material, A is the cross-sectional area, ΔT is the temperature difference and L is the length of the conductor.

So, K = Q × L ÷ A × ΔT

Substituting the given values, we get,

K = 3000 J × 0.2 m ÷ (55 × 10⁻⁴ m²) × 67°C

K = 0.238 W/m°C

ii. Area of the object, A = 55 mm²

= 55 × 10⁻⁶ m²

Emissivity of the object, ε = 0.7

Rate of energy loss, P = 35.6 J/s

Stefan's constant, σ = 5.6703 × 10⁻⁸ W/m²/K⁴

Initial temperature, T₁ = ?

Formula used: Rate of energy loss, P = ε × σ × A × (T₁⁴ - T₂⁴)

where P is the rate of energy loss, ε is the emissivity of the object, σ is the Stefan's constant, A is the area of the object, T₁ is the initial temperature and T₂ is the final temperature.

So, P = ε × σ × A × (T₁⁴ - T₂⁴)

Solving the above equation for T₁, we get

T₁⁴ - T₂⁴ = P ÷ (ε × σ × A)

T₁⁴ = (P ÷ (ε × σ × A)) + T₂

⁴T₁ = [ (P ÷ (ε × σ × A)) + T₂⁴ ]¹∕⁴

Substituting the given values, we get,

T₁ = [ (35.6 J/s) ÷ (0.7 × 5.6703 × 10⁻⁸ W/m²/K⁴ × 55 × 10⁻⁶ m²) + (30 + 273)⁴ ]¹∕⁴

T₁ = 481.69 K

≈ 208.69°C

≈ 209°C (approx.)

Therefore, the thermal conductivity of the material is 0.238 W/m°C and the initial temperature of the object is 209°C.

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Answer:

114.84

Explanation:

Impulse= F.ΔT

where F is the average force applied and ΔT is the change in time period

so,

Impusle= (522)x(0.22)

Impulse=114.84N-s

Answer: A

Explanation:

A

Explanation:

work = 0

Work is zero because it remains in its place x=0

Answer:

C

Explanation:

A rope is attached to a hook in the ceiling and is hanging straight down. The rope has a mass m, and nothing is attached to the free end of the rope. As a transverse wave travels down the rope from the top, the speed of the wave does not change as the tension and linear density do not change.

What is a transverse wave?

Transverse wave is a wave that oscillates perpendicular to the direction of propagation. In physics, a transverse wave is a wave whose oscillations are perpendicular to the direction of wave propagation. This type of wave is also called a transverse wave. For example, when a rope is shaken up and down, a transverse wave is produced.

What is the speed of the wave?

The velocity of a wave is a function of the medium through which it is traveling. The speed of a wave does not depend on its amplitude. The speed of a transverse wave is proportional to the square root of the tension in the rope divided by the rope's mass per unit length (the linear density).

Therefore, as a transverse wave travels down the rope from the top, the speed of the wave does not change since the tension and linear density do not change.

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Answer:

Voltmeter

Explanation:

Voltmeter is used to measure both terminal potential difference as well as electromotive force (e.m.f.) depending upon the connection state of the battery or cell.

Answer:

648.40N

Explanation:

Centripetal acceleration is the acceleration of an object around a circular path. Centripetal for e acting on the combined mass is expressed as:

F = ma

F = mv²/r

m is the mass of the object = 143kg

v is the linear velocity = 13.8m/s

r is the radius = 42.0m

Substitute the given parameters into the formula;

F = 143*13.8²/42

F = 27,232.92/42

F = 648.40N

Hence the magnitude of the centripetal force acting on the combined mass is 648.40N

According to Ohm's law: V = IR

The rate of flow of charges will depend on the voltage supplied and the resistance in the wire.

ELECTRIC CHARGE

Current can be defined as the rate of flow of charges. Where charge is the product of current and time. This means that electric charge is proportional to electric current. The current in a conducting wire depends on;

The two factors that can affect the flow of electric charge in the given options are voltage and resistance

Because according to Ohm's law: V = IR

The rate of flow of charges will depend on the voltage supplied and the resistance in the wire.

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Answer:

A. and D.

Explanation: Identifying Factors That Affect Current

Which factors affect the flow of electric charge? Select two options.

[voltage]

ampere X

ohmX

[resistance]

volt X

On a clear day, the total intensity of solar radiation incident at the Earth's surface is approximately 1000W/\(m^2\) the total power output of the Sun is approximately 4.9031 × 10²⁵ W.

The quantity of power per square meter is referred to as intensity. The amount of solar power incident on a certain region is referred to as intensity when referring to solar radiation.

We can use the information that the total intensity of solar radiation incident at the Earth's surface is around 1000 W/\(m^2\) and that the atmosphere absorbs 23% of the incoming solar radiation to determine the Sun's overall power output.

Following go through the atmosphere, the power that reaches the Earth's surface comes from:

P_surface = (1 - 0.23) * 1000 W/m²

We know that:

Surface Area = 4πr²

So,

Surface Area = 4π * (1.5 × 10¹¹ m)²

P = P_surface * Surface Area

P_surface = (1 - 0.23) * 1000 W/m²

P_surface = 0.77 * 1000 W/m²

P_surface = 770 W/m²

Surface Area = 4π * (1.5 × 10¹¹ m)²

Surface Area = 4 * 3.1415 * (1.5 × 10¹¹ m)²

Surface Area = 28.274 * (2.25 × 10²² m²)

Surface Area = 63.617 × 10²² m²

P = P_surface * Surface Area

P = 770 W/m² * 63.617 × 10²² m²

P = 770 W/m² * 63.617 × 10²² m²

P = 4.9031 × 10²⁵ W

Thus, the total power output of the Sun is approximately 4.9031 × 10²⁵ W.

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I don't know to be honest

Explanation:

91.655  mm of Hg pressure is lower when our blood pressure at  brain than it is at your heart.

pressure at brain= 121.8-30.135

pressure=91.655  mm Hg

Pressure is defined as force/area. To demonstrate the pressure from snow on a roof, divide the weight of the snow by the surface area of the roof. Gases are a typical pressure source in physics. A "vacuum" is used to describe the lack of pressure. Humans have long held the belief that vacuums are both improbably rare and unnatural since "nature abhors a vacuum." Actually, this is not the case.

The number of pressure units is ridiculous. It's common to use the torr or mmHg unit. This discussion is solely focused on the height of a mercury column. The atmosphere contains 760 torr, or mmHg. You could also look at mmH2O, which makes use of a comparable idea.

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The resistance of the ground wire is Rg  is mathematically given as Rg=0.025Ф

This is further explained below.

Take into account that the amount of electricity flowing through the worker's body does not surpass 0.1 mA.

The value of the earth's resistors should be extremely low in order to ensure that the greatest possible current is carried by the earth wire and, as a result, that the worker is not shocked.

Determine the highest possible value for R g s o.

\($\begin{aligned}&0.1 \mathrm{~mA}=(2)\left(\frac{R_g}{R_g+500}\right) \\&\frac{R_g+500}{R_g}=20000 \\&R_g+500=20000 R_g \\&\begin{aligned}R_g &=\frac{500}{20000-1} \\&=0.025 \Omega\end{aligned}\end{aligned} \\\\ Rg=0.025Ф\)

The current that flows through the worker is less than or equal to 0.1mA.

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CQ

A worker is standing on a wet concrete floor, holding an electric drill having a metallic case. The metallic case is connected through the ground wire of a three-terminal power outlet to the power-system ground. The resistance of the ground wire is Rg. The resistance of the worker's body is Rw = 500 ?. Due to faulty insulation in the drill, a current of 2 A flows into its metallic case. The circuit diagram for this situation is shown in the figure.Find the maximum value of Rgso that the current through the worker does not exceed 0.1 mA.

Answer:

the formula v = f×lambda.

v= 4.25× 5.6

therefore speed is

23.8 meters per second

After watching the Ted Talk, there were still a few questions that I had about supermassive black holes. Firstly, I wanted to know more about the event horizon and what it exactly entails. Although the speaker briefly touched upon this subject, I would have appreciated a more in-depth explanation. Additionally, I would have liked to know more about the role of supermassive black holes in the universe.

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