how light warms up matter​

Answer:

3) 1.25

Explanation:

I had the same question and somehow got it right :)

The new volume will be determined by molarity and which will be  1.25 ml.

The volume of an object is just a measurement of how much space it takes up.

The molality refers to the moles of a solute in relation to the mass of the solvent, whereas the molarity refers to the moles of a solute in based on the volume of the solution. It can be denoted by M.

The formula of Molarity is

\(M_{1} V_{1} =M_{2}V_{2}\)

where, M is molarity and V is volume.

Calculation of volume.

It is given that,\(M_{1} = 0.1 M, M_{2} =0.0025 M.\)

Now, puts the value of given data in molarity equation.

\(M_{1} V_{1} = M_{2} V_{2}\)

\(V_{1} = M_{2} V_{2} /M_{1}\)

\(V_{1}\) = 0.005×25/0.1 = 1.25 ml

Therefore, the correct answer will be option 3.

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Answer:

alkali metals

Explanation:

alkali metals only have one valence electron, meaning they are extremely reactive. they are considered the most reactive on the periodic table.

The word "symptom" refers to a specific manifestation or indication of a condition, disease, or disorder that is experienced or observed by an individual.

Symptoms are subjective or objective changes in the body's normal functioning that may be recognized as abnormal, uncomfortable, or problematic. Symptoms can manifest in various ways depending on the nature of the underlying condition. They can be physical, such as pain, rash, cough, fever, or fatigue, indicating an illness or injury affecting the body. Symptoms can also be psychological, such as anxiety, depression, or confusion, reflecting disturbances in mental health.

Symptoms serve as important clues for medical professionals to identify and diagnose diseases or disorders. They provide valuable information about the nature, severity, and progression of an illness, helping healthcare providers formulate appropriate treatment plans. Additionally, symptoms may also be important for individuals to self-assess their own health status and seek appropriate medical attention.

It is essential to note that symptoms alone may not provide a definitive diagnosis, as they can overlap across different conditions. Further evaluation, including medical tests and examinations, is often necessary to confirm a diagnosis and determine the appropriate course of action.

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Answer:

true

because with the both states we increase the surface of reaction

Answer:

D

Explanation:

i took the test and got it right :)

To solve this problem using the gas laws, we need to use the Ideal Gas Law. This law states that the product of the pressure and the volume of a gas is proportional to the absolute temperature.

The equation of the Ideal Gas Law is the following:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\dfrac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} } \end{gathered}$} }\)

Where:

We clear for V₂:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{P_1V_1T_2}{P_2T_1 } } \end{gathered}$} }\)

Where:

Substituting the known values:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{760\not{kPa}\times0.050 \ L\times20.0\not{k} }{ 380\not{kPa}\times10.0\not{k} } } \end{gathered}$} }\)

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{760 \ L}{3800 } } \end{gathered}$} }\)

\(\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2\approx0.2 \ Liters} \end{gathered}$} }}\)

Answer:

calcium donates two vanence electrons to sulfur atom to form Ca2+ ion and an S2+ - ion

To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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The energy in joules of one mole of photons of visible light having a wavelength of 4.11×10^2 nm? can be expressed as 2.9*10^5 J

From the question we were told to find the energy and the parameters that is needed to calculate these are;

c=3*10^8

h= 6.626 * 10^-34 J.s

1 mol photons = 6.023x10^23 photon

λ = 4.11×10^2 nm  = 4.11 × 10-7 meters

The parameters can be input  as Energy of one mole photon (E) = ( 6.023x10^23 * 6.626 * 10^-34 * 3*10^8)/ (4.11 × 10^-7)

=291302

=2.9*10^5 J

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The concentration of the new potassium permanganate, KMnO solution is 0.06 M.

To find the concentration of the new solution, we can use the formula,

C₁V₁ = C₂V₂,

C₁ = 0.75,

V₁ = 20.0 mL,

V₂ = 250.0mL

C₂ is what we have to find. Plugging in the values we know, we get,

0.75 M x 20.0 mL = C₂ x 250.00 mL

Solving for C₂, we get the final concentration of the potassium permanganate.

C₂ = (0.75 M x 20.0 mL) / 250.00 mL

C₂ = 0.06 M

Therefore, the concentration of the solution has changed to 0.06 M from 0.75M.

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The enthalpy of combustion for 1kg of urea is -1223525.84 J/mol.

Urea is a compound that is used in fertilizers and in some plastics.The enthalpy of combustion for urea is the amount of energy that is released when urea is burned. In order to calculate the enthalpy of combustion for 1kg of urea, we need to use the information that is provided to us in the question. Let us start by writing down the balanced equation for the combustion of urea: CO(NH2)2 + 3/2 O2 → CO2 + 2H2O + N2
The balanced equation shows that 1 mole of urea reacts with 1.5 moles of oxygen gas to produce 1 mole of carbon dioxide, 2 moles of water, and 1 mole of nitrogen gas. The enthalpy change for this reaction is equal to the amount of energy that is released when 1 mole of urea is burned.
The heat of combustion (ΔHc) of urea is -632.6 kJ/mol. This means that 632.6 kJ of energy is released when 1 mole of urea is burned. We know that 12g of urea raised the temperature of water by 30°C. We can use this information to calculate the amount of energy that was released when 12g of urea was burned.
The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 J of energy to raise the temperature of 1 gram of water by 1°C. Therefore, it takes 4.18 x 1000 = 4180 J of energy to raise the temperature of 1 kg of water by 1°C.
We know that 12g of urea raised the temperature of water by 30°C. Therefore, the amount of energy that was released when 12g of urea was burned is:
Energy = mass x specific heat capacity x temperature change
Energy = 0.012 kg x 4180 J/kg°C x 30°C
Energy = 1497.6 J
We can now use this information to calculate the enthalpy of combustion for 1kg of urea:
Enthalpy of combustion = energy released / moles of urea burned
Enthalpy of combustion = 1497.6 J / (0.012 kg / 60.06 g/mol)
Enthalpy of combustion = - 1223525.84 J/mol
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Answer:

0.273 mol H₂O

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

4.92 g H₂O

Step 2: Identify Conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

\(4.92 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O} )\) = 0.27303 mol H₂O

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

0.27303 mol H₂O ≈ 0.273 mol H₂O

Answer:

Project shadow #KARMA be there

Explanation:

Answer:

ECUACIÓN:HClO 2 + H 2O → ClO− 2 + H 3O

ACIDO: HClO2

BASECONJUGADA:ClO-2

Explanation:

Answer:

The speed of molecules in a gas is directly proportional to the square root of the temperature and inversely proportional to the square root of the molar mass.

Since both gases are at the same temperature, we only need to compare their molar masses.

The molar mass of carbon dioxide (CO2) is 44 g/mol and the molar mass of hydrogen (H2) is 2 g/mol.

Therefore, the square root of the molar mass of hydrogen is smaller than the square root of the molar mass of carbon dioxide.

This means that the speed of hydrogen molecules is greater than the speed of carbon dioxide molecules at the same temperature.

The mass of carbon dioxide produced by the complete combustion of 48.0g of hexane is 147.35g.

The mass of a substance can be calculated by using the stoichiometry approach.

The balanced equation of the complete combustion of hexane is as follows:

2C6H14(g) + 19O2(g) → 12CO2(g) + 14H2O(g)

48g of hexane to moles is calculated as:

48g ÷ 86g/mol = 0.56 mol

2 moles of hexane produces 12 moles of CO2

0.56 mol of hexane will produce 0.56 × 12/2 = 3.35 mol

Next, we convert 3.35 moles of CO2 to mass as follows:

3.35 moles × 44g/mol = 147.35g

Therefore, the mass of carbon dioxide produced by the complete combustion of 48.0g of hexane is 147.35g.

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Answer:

\(\boxed {\tt 1.0 \ g/mL}\)

Explanation:

Density can be found by dividing the mass by the volume.

\(d=\frac{m}{v}\)

The mass of the water is 50.0 grams.

The volume of the water is 50.0 milliliters.

\(m= 50.0\ g \\v=50.0 \ mL\)

Substitute the values into the formula.

\(d=\frac{50.0 \ g}{50.0 \ mL}\)

Divide.

\(d= 1.0 \ g/mL\)

The density of the water is 1.0 grams per milliliter. Also, remember that the density of pure water is always 1.0 g/mL or g/cm³

Answer:

Shortcoming:-After some time cell stops working because + electrolyte becomes more + and - ve electrolyte become more -ve with time.So there is difficulty in flowing of current.So it stops working after some time.

This Problem can be solved by using a u shaped tube salt bridge.Salt bridge completes the circuit and will maintain liquid liquid junction potential.And now there will be countinuous flow of e- or current.

Based on the given reactions, the compounds are as follows:

A: The specific product formed from the reaction between prop-1-yne and either 2HBr or H2O2.

B: The product formed when compound A reacts with 2H2O.

C: The product formed when compound B reacts with K2CO3(aq).

D: The product formed from the heat-induced reaction of compound C.

E: The product formed when compound D reacts with HBr.

Based on the given reactions, let's analyze the compounds involved:

Reaction 1: prop-1-yne + 2HBr/H2O2 = A

The reactant prop-1-yne reacts with either 2HBr or H2O2 to form compound A. The specific product formed will depend on the reaction conditions.

Reaction 2: A + 2H2O = B

Compound A reacts with 2H2O (water) to form compound B.

Reaction 3: B + K2CO3(aq) = C

Compound B reacts with K2CO3(aq) (potassium carbonate dissolved in water) to form compound C.

Reaction 4: C + heat = D

Compound C undergoes a heat-induced reaction to form compound D.

Reaction 5: D + HBr = E

Compound D reacts with HBr (hydrobromic acid) to form compound E.

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The current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

To calculate the current in amperes, we need to use Faraday's laws of electrolysis and the stoichiometry of the reaction.

Faraday's laws state that the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the cell. The relationship is given by:

Q = nF

Where Q is the electric charge in coulombs (C), n is the number of moles of substance involved in the reaction, and F is Faraday's constant, which is equal to 96,485 C/mol.

In this case, the substance being produced is Cl2, and we know the mass of Cl2 produced, which is 4.8 x 10^5 g.

First, we need to calculate the number of moles of Cl2 produced:

Molar mass of Cl2 = 35.45 g/mol

Moles of Cl2 = mass / molar mass = (4.8 x 10^5 g) / (35.45 g/mol) ≈ 1.354 x 10^4 mol

Now we can calculate the quantity of electricity passed through the cell using Faraday's laws:

Q = nF

Q = (\(1.354 x 10^4\)mol) * (96,485 C/mol)

Q ≈ 1.308 x 10^9 C

The quantity of electricity is given in coulombs. To find the current, we need to divide this value by the time in seconds.

Given that the time is 18 hours, we convert it to seconds:

Time = 18 hours * 60 minutes/hour * 60 seconds/minute

Time = 6.48 x 10^4 seconds

Finally, we can calculate the current:

Current (I) = Q / Time

I = (1.308 x 10^9 C) / (6.48 x 10^4 s)

I ≈ 2.02 x 10^4 Amperes

Therefore, the current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

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Answer:

1.68 mol Ca(NO₃)₂

General Formulas and Concepts:

Atomic Structure

Stoichiometry

Explanation:

Step 1: Define

[Given] 275 g Ca(NO₃)₂

[Solve] mol Ca(NO₃)₂

Step 2: Identify Conversions

[PT] Molar Mass of Ca: 40.08 g/mol

[PT] Molar Mass of N: 14.01 g/mol

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of Ca(NO₃)₂: 40.08 + 2[14.01 + 3(16.00)] = 164.10 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.67581 mol Ca(NO₃)₂ ≈ 1.68 mol Ca(NO₃)₂

Answer:

1.68 mol Ca(NO₃)₂

Explanation:

Answer:

4f its the last orbital of the above

According to the Aufbau principle and electronic configuration, orbital  which is farthest from the nucleus is 4f.

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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Answer: 7.52*10^23 molecules.

Explanation: This is a classic Stoichiometry problem.

In one mole of any substance, there are 6.02*10^23 molecules. This number is called Avogadro's number. We are given 55 grams of Co2 so to convert that to moles, we divided by the molar mass of Co2. We find the molar mass by adding the molar masses of the elements that make up the compound.

There is one molecule of Carbon and two molecules of Oxygen in one molecule of Co2. From the periodic table, the molar mass of Carbon is 12.01 and 16.00 for Oxygen. 1(12.01)+2(16.00) gives us the molar mass. We then divided 55 grams by that mass to find the number of moles. We then multiply the number of moles by Avogadro's number (6.02*10^23) to find the total number of molecules.

You can use this method for solving any problem that asks you to find the number of atoms or molecules of some number of grams of a substance.

Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Answer:

C

Explanation:

The stomach digests the food (Digestive System) are the nerves and they send the protein etc.

When a substance or radiation's heat is stated quantitatively, it is called its temperature.

Three different categories of temperature scales exist:

those, like Kelvin's original definition, that solely rely on macroscopic characteristics and thermodynamic concepts;

those that rely on actual, empirical particle qualities as opposed to theoretical concepts;

Additionally, there are scales like the SI scale that are determined by the typical translational kinetic energy per freely moving tiny particle, such as an atom, molecule, or electron in a body.

The equation q = mcΔT, where m is the sample mass, c is the specific heat, and T is the temperature change, can be used to determine how much heat a a sample gains or loses (q).

Therefore,

q = m*c*ΔT

2072.87 = 335 * 4.184 * ΔT

ΔT = 1.479 °c

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