How is the mathematical analysis of pressure loss in noncircular channels different from circular? Please show equations (S)
Answers
The mathematical analysis of pressure loss in noncircular channels is different from circular channels because the equations used to calculate pressure loss are different.
In a circular channel, the Darcy-Weisbach equation is used to calculate pressure loss:
ΔP = f * (\(\frac{L}{D}\)) * (ρ\(\frac{v^{2} }{2}\))
Where ΔP is the pressure loss, f is the friction factor, L is the length of the channel, D is the diameter of the channel, ρ is the density of the fluid, and v is the velocity of the fluid.
In a noncircular channel, the hydraulic diameter (Dh) is used instead of the diameter (D) in the Darcy-Weisbach equation:
ΔP = f * (\(\frac{L}{D}\)) * (ρ\(\frac{v^{2} }{2}\))
The hydraulic diameter (Dh) is calculated as:
Dh = (4 * A)/P
Where A is the cross-sectional area of the channel and P is the wetted perimeter of the channel.
So, the main difference between the mathematical analysis of pressure loss in circular and noncircular channels is the use of hydraulic diameter (Dh) instead of diameter (D) in the Darcy-Weisbach equation.
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Related Questions
discuss the cyclical nature of searching for information and the research process in general.
Answers
The cyclical nature of searching for information and the research process in general highlights the importance of being flexible and adaptable, and continuously evaluating and refining the research question and approach as new information becomes available.
What are the stages involved in research process?
The research process is cyclical in nature because it involves a series of steps that are repeated until the desired information is found and the research goals are met. The main stages in this cycle include:
1. Identifying the research topic or question: This is the starting point, where you determine the focus of your research based on your interests or the requirements of your assignment.
2. Conducting a literature review: This involves searching for and reviewing existing research on your topic to gain an understanding of the current state of knowledge, identify gaps, and establish the context for your study.
3. Developing a research plan: Based on the literature review, you'll develop a plan for your research, including the methods, data sources, and tools you'll use to answer your research question.
4. Collecting data: You'll then gather the necessary data for your study, whether it's through experiments, surveys, interviews, or other methods.
5. Analyzing and interpreting the data: After collecting the data, you'll analyze it to draw conclusions and make sense of your findings.
6. Reporting your findings: You'll present your research results, either in a written report, presentation, or other format, so others can learn from your work.
7. Reviewing and refining: After receiving feedback on your research, you may need to refine your methods, conduct additional analysis, or update your literature review to incorporate new information.
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what is the radial load in bearing b when the motor is stopped with zero tension in the chain? ponder: does it make logical sense that the load in the bearing is higher when the motor is stopped than when it is running and putting tension in the chain? if you have an intuitive understanding of statics then this will be very logical. (hopefully you were not a plug-and-chug engineer when you took your statics class but rather took time to understand the principles intuitively.) incorrect answer: 200
Answers
The radial load in bearing b when the motor is stopped with zero tension in the chain is 300 lb. It is logical that the load in the bearing is higher when the motor is stopped than when it is running and putting tension in the chain due to the principle of statics.
Here's why:When the motor is running, the chain is stretched due to the tension force applied to it. This tension force counteracts the radial load on the bearings, which is why the load is lower in this scenario.On the other hand, when the motor is stopped with zero tension in the chain, the weight of the load is entirely supported by the bearings.
The radial load on the bearing is given by the formula:Radial load on bearing = (Weight of load / Number of bearings) + Axial load due to belt tensionTherefore, when the motor is stopped with zero tension in the chain, the radial load on bearing b can be calculated as follows:Radial load on bearing b = (300 lb / 2) + 0Radial load on bearing b = 150 lbHence, the radial load in bearing b when the motor is stopped with zero tension in the chain is 150 lb.
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Drag each tile to the correct box. Not all tiles will be used.
Adam wants to become a certified professional engineer. What are the steps that he will have to follow?
Answers
Answer:
I think it is the 2,3,5 and 1 ones
IV. An annealed copper strip 9 inches wide and 2.2 inches thick, is rolled to its maximum possible draft in one pass. The following properties of annealed copper are given: strength coefficient is 90,000 psi; true strain at the onset of non-uniform deformation is 0.45; and, engineering strain at yield is 0.11. The coefficient of friction between strip and roll is 0.2. The roll radius is 14inches and the rolls rotate at 150 rpm. Calculate the roll-strip contact length. Calculate the absolute value of thetrue strain that the strip undergoes in this operation. Determine the average true stress of the strip in theroll gap. Calculate the roll force. Calculate the horsepower required.
Answers
Answer:
13.9357 horse power
Explanation:
Annealed copper
Given :
Width, b = 9 inches
Thickness, \($h_0=2.2$\) inches
K= 90,000 Psi
μ = 0.2, R = 14 inches, N = 150 rpm
For the maximum possible draft in one pass,
\($\Delta h = H_0-h_f=\mu^2R$\)
\($=0.2^2 \times 14 = 0.56$\) inches
\($h_f = 2.2 - 0.56$\)
= 1.64 inches
Roll strip contact length (L) = \($\sqrt{R(h_0-h_f)}$\)
\($=\sqrt{14 \times 0.56}$\)
= 2.8 inches
Absolute value of true strain, \($\epsilon_T$\)
\($\epsilon_T=\ln \left(\frac{2.2}{1.64}\right) = 0.2937$\)
Average true stress, \($\overline{\gamma}=\frac{K\sum_f}{1+n}= 31305.56$\) Psi
Roll force, \($L \times b \times \overline{\gamma} = 2.8 \times 9 \times 31305.56$\)
= 788,900 lb
For SI units,
Power = \($\frac{2 \pi FLN}{60}$\)
\($=\frac{2 \pi 788900\times 2.8\times 150}{60\times 44.25\times 12}$\)
= 10399.81168 W
Horse power = 13.9357
what feature eliminates the need for a separate electrical outlet for your wap?
Answers
The PoE feature eliminates the need for a separate electrical outlet for your wireless access point (WAP).
What is a wireless access point (WAP)?A wireless access point (WAP) is a device that connects wireless devices to a wired network. Wireless devices, such as smartphones and laptops, use a wireless access point to connect to a wired network.
The WAP allows wireless devices to communicate with each other and with the wired network by transmitting wireless signals.
PoE, or Power over Ethernet, is a technology that allows network cables to carry electrical power. In other words, it is a system that allows a single Ethernet cable to provide both data and electrical power to a device.
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The Power over Ethernet (PoE) feature eliminates the need for a separate electrical outlet for your Wireless Access Point (WAP). With PoE, power is transmitted over Ethernet cables along with data.
This means that a single Ethernet cable can provide both data connection and power to the WAP, making installation and maintenance easier.
This feature is especially useful in locations where there are limited electrical outlets or where electrical wiring is difficult or expensive to install, such as in outdoor areas, warehouses, and remote locations. PoE also allows for greater flexibility in the placement of WAPs, as they can be installed in locations that are not near electrical outlets. In addition, PoE can help to reduce energy costs, as it allows for more efficient use of power by eliminating the need for separate power supplies for each device. Overall, the PoE feature provides a cost-effective, efficient, and convenient way to power WAPs and other network devices.
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A horizontal piston/cylinder arrangement is placed in a constant-temperature bath. The piston sides in the cylinder with negligible friction and an external force holds it in place against an initial gas pressure of 14 bar. The initial gas volume is 0.03 m3. The external fore on the piston is reduced gradually and the gas expands isothermally as its volume triples. If the volume of the gas is related to its pressure so that the product PV is constant.
(a) What is the work by the gas in moving the external force?
(b) How much work would be done if the external force were suddenly reduced to half its initial value instead of being gradually
reduced?
Answers
Answer:
\(W=46141.72~J\)
Explanation:
Given:
initial pressure, \(P_1=14~bar=1.4\times10^6~Pa\)
initial volume, \(V_1=0.03~m^3\)
After isothermal expansion:
final volume, \(V_2=3V_1=0.09~m^3\)
a)
We have the work done in isothermal process as:
\(W=P_1.V_1\ln(\frac{V_2}{V_1} )\)
\(W=1.4\times10^6\times 0.03\ln(\frac{0.09}{0.03} )\)
\(W=46141.72~J\) is the work by the gas in moving the external force
b)
When the force on piston is suddenly reduced to half the initial value then the process becomes near to adiabatic.
\(P_1V_1^{\gamma}=P_2V_2^{\gamma}\)
\(14\times 0.03^{1.4}=P_2\times 0.09^{1.4}\)
\(P_2=3~bar\)
Now, using the formula for work done in adiabatic process:
\(W=\frac{P_1V_1-P_2V_2}{\gamma-1}\)
\(W=\frac{1.4\times10^6\times 0.03-3\times10^5\times 0.09}{1.4-1}\)
\(W=3750~J\)
Technician A says that 5W-30 would be better to use than 20W-50 in most vehicles in
cold weather conditions. Technician B says 20W-50 flows better than 5W-30 in cold
weather. Who is correct?
Answers
20
Explanation:
Technician A says that primary vibration is created by slight differences in the inertia of the pistons between top dead center and bottom dead center. Technician B says that secondary vibration is a strong low-frequency vibration caused by the movement of the piston traveling up and down the cylinder. Who is correct? O A. Neither Technician A nor B OB. Technician B O C. Both Technicians A and B D. Technician A
Calculate the work done in lifting a 300N weight to a height of
1Omwith anacceleration of 0.5ms. Take g- 10ms
Answers
Note that ,the work done in lifting a 300 N weight to a height of 10 m with an acceleration of 0.5 m/s² is 3000 Joules.
How is this so?
To calculate the work done in lifting a 300 N weight to a height of 10 m, we need to use the formula -
Work = Force x Distance
In this case, the force is the weight being lifted, which is 300 N, and the distance is the height the weight is lifted, which is 10 m.
Work = 300 N x 10 m
= 3000 N·m
= 3000 J (Joules)
Therefore, the work done in lifting a 300 N weight to a height of 10 m with an acceleration of 0.5 m/s² is 3000 Joules.
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5. It seems likely that young people will be at war with old people in another 15 or 20 years.
war
You can see it coming in the numbers. In 1900 only 1 percent of the population was older
than 75. Today 4 percent of all Americans are more than 75 years old, and in a few years it's
going to be 5 percent... 13 million people.
Answers
The following argument can best be interpreted as being inductive
What is an inductive sentence?An inductive sentence is one that arrives at conclusions by moving from the specifics to the general ideas. In the sentence above, there is a specific conclusion at the onset of the text.
This conclusion is that there will likely be a war between old and young people in some years to come. Now, the author gives general instances that led to the conclusion set forth in the sentence. Deductive sentences are the opposites of inductive sentences for they tend to move from general to specific.
Complete Sentence:
I. Determine whether the following arguments are best interpreted as being inductive or deductive. Also state the criteria you use in reaching your decision (i. e., the presence of indicator words, the nature of the inferential link between premises and conclusion, or the character or form of argumentation).
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Validating Solutions: Let's show that equations (4) and (9) are actually the behavior we expect for these circuits (assuming the differential equations (3) and (8) hold). Note that we're not actually deriving these formulas, just showing that they do work (i.e., that they solve the differential equation like we want them to). This has the following steps:O Differential Equation, LR Circuits: Take (4), and plug it into (3) (taking a derivative where necessary). Do the algebra to show that you get the same thing on both sides. O Differential Equation, LC Circuits: Take (9), and plug it into (8) (taking derivatives where necessary). Do the algebra to show that you get the same thing on both sides.O Initial Conditions, LR Circuits: Take (4), and plug in t = 0. Show that you get the same thing on both sides (i.e., I(0) = 10). O Initial Conditions, LR Circuits: Take (9), and plug in t= 0. Show that you get the same thing on both sides (i.e., Q(0) = Q(0)). Also, take a derivative of (9) w.r.t. time, then plug in t= 0 and show that both sides are consistent (i.e., you get Q'(0) = Q'(0)).
Answers
The paragraph describes a process for validating equations (4) and (9) for LR and LC circuits, respectively.The initial conditions for both LR and LC circuits are also checked by plugging in t=0 and ensuring that both sides are consistent.
What are the steps involved in validating the solutions for LR and LC circuits?The paragraph describes a process for validating equations (4) and (9) for LR and LC circuits, respectively.
To do so, the equations are plugged into the corresponding differential equations (3) and (8), and algebraic manipulation is done to show that both sides are equal.
The initial conditions for both LR and LC circuits are also checked by plugging in t=0 and ensuring that both sides are consistent.
Additionally, a derivative of (9) is taken with respect to time, then plugged in at t=0 to ensure consistency.
This process helps ensure that the equations accurately model the behavior of the circuits.
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Suppose a supermarket needs to store number of units sold of a particular product in their 20 locations. Which the following would be the best data structure to use and why?
Answers
Is.
The
Following ?
Identify this instrument.
Refracting telescope
Reflecting telescope
Microscope
Radio Telescope
Answers
Find the volume of the rectangular prism
9 cm
10 cm
Answers
Answer:
V= 90h cm³ where h is the height of the rectangular prism.
Explanation:
The formula for volume of a rectangular prism is ;
V=l*w*h where;
V=volume in cm³
l= length of prism=10cm
w =width of the prism = 9 cm
Assume the height of the prism as h cm then the volume will be;
V= 10* 9*h
V= 90h cm³
when the value of height of the prism is given, substitute that value with h to get the actual volume of the prism.
in a regular pyramid, the slant height is always longer than a lateral edge of the pyramid. true or false
Answers
The statement "In a regular pyramid, the slant height is always longer than a lateral edge of the pyramid" is false.
In a regular pyramid, the slant height refers to the distance from the apex (top) of the pyramid to any point on the lateral face, measured along the slanted surface. A lateral edge, on the other hand, refers to the length of an edge that connects the apex to a vertex of the base.
In a regular pyramid, the slant height and the lateral edge are typically not equal to each other. The slant height is generally longer than a lateral edge. This can be understood by considering the shape of a regular pyramid, where the slant height forms a diagonal along the lateral face, while the lateral edge is a straight line connecting the apex and a vertex of the base.
However, it is important to note that the specific lengths of the slant height and lateral edge depend on the dimensions of the pyramid, such as the base size and the height. The relationship between the slant height and lateral edge can vary depending on the specific measurements of the regular pyramid.
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Two stepped bar is supported at both ends.At the join point of two segments,the force F is applied(downwards).Calculate reactive forces R1 and R3 at the supports.What is value of absolute maximal stress?
Choose one answer nearest your result.
given= d1=10mm d2=20mm L1=20mm L2=10mm E=200GPa F=20kN
Answers
Answer:
F=200kN
Explanation:
Suggest how the following requirements might be rewritten in a
quantitative way:
a. The library system shall be easy-to-use.
b. The library system shall provide reliable service to all classes of
user.
c. The library system shall provide a rapid response to all user
requests for book information.
Answers
Answer:
answer letter c
Explanation:
yun anserr hhehehe
Match the description with the associated IOS mode. (Not all options are used.)
limited number of basic monitoring commands
user exec mode
privileged exec mode
global configuration mode
Answers
User exec mode is associated with a limited number of basic monitoring commands. This mode allows users to execute only a small subset of commands, including basic troubleshooting and monitoring tools such as ping, traceroute, and show commands. Users are not able to make any changes to the system configuration while in this mode.
Privileged exec mode is the mode that grants users full control of the system. In this mode, users have access to all the commands and features of the system. This includes the ability to make changes to the system configuration and to execute all the commands available in the user exec mode. Global configuration mode is the mode used for configuring the system. In this mode, users can configure various settings such as interfaces, IP addresses, routing, and other network-related features. This mode allows users to make changes to the system configuration and to execute all the commands available in the privileged exec mode. Overall, understanding these modes is essential for network administrators and IT professionals, as it allows them to effectively manage and configure their network devices.
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The limited number of basic monitoring commands corresponds to the User Exec Mode in IOS. Other modes like Privileged Exec Mode and Global Configuration Mode offer more advanced options.
Explanation:The IOS modes match to the descriptions as the following: limited number of basic monitoring commands matches with User Exec Mode. User Exec Mode provides a limited number of basic commands which are used for monitoring hardware status, see routing tables etc. But you cannot change the system's configuration in this mode. Privileged Exec Mode and Global Configuration Mode are advanced modes that include more than just basic monitoring commands, allowing for changes in system configuration and access to all other command levels respectively.
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What is the correct order of energy conversions? * 1. Nuclear to thermal to mechanical to electrical 2. Thermal to mechanical to electrical to potential 3. Nuclear to thermal to mechanical to potential 4. Electrical to mechanical to thermal to nuclear
Answers
Answer: Nuclear to thermal to mechanical to electrical.
Explanation:
Nuclear energy is also referred to as atomic energy which will then lead to the generation of the thermal energy. It should be noted that the thermal energy is also referred to as the heat energy and this is due to the rise in temperature which results in the faster movement of atoms and their collision with one another.
This in turn, brings about the mechanical energy which is simply the energy caused by the motion and this in turn, also lead to electrical energy.
Therefore, the correct answer is Nuclear to thermal to mechanical to electrical.
water at 25 o c flows in a 320 mm galvanized iron pipe. if the friction head loss gradient (friction loss divided by pipe length) is 0.007, determine the flow rate.
Answers
The flow rate of water, as determined by the Darcy-Weisbach equation, is approximately 0.0749 cubic meters per second (m^3/s). The pipe flow may be classified into laminar and turbulent flow based on the flow's Reynolds number (Re).
Turbulent flow is characterized by irregular, unpredictable flow while laminar flow is characterized by smooth, predictable flow.In order to determine the flow rate of water, we will apply the Darcy–Weisbach equation. It is given as:H_f = f (L/D) * (V^2/2g)where, H_f = friction head loss, L = pipe length, D = diameter of the pipe, V = velocity of flow, f = friction coefficient, and g = acceleration due to gravity (9.81 m/s^2)We can solve for V in the Darcy-Weisbach equation and set it equal to the volumetric flow rate Q divided by the cross-sectional area of the pipe A (πD^2/4):V = Q / APutting this value in the Darcy–Weisbach equation:H_f = f (L/D) * (Q^2/(πD^4*2g))We know the friction head loss gradient (dh/dL), which is defined as the frictional head loss divided by the pipe length. Thus, we can multiply both sides of the equation by the length of the pipe L to get the head loss:HL = dh/dL * L = f * (Q^2/(πD^4*2g)) * L/DWe can rearrange the above equation to solve for Q:Q = sqrt((2gL/d) * dh/dL * πD^5/f)Putting the given values, we get:dh/dL = 0.007, L = 1 m (given that the pipe length is not mentioned in meters or millimeters, it's safer to assume meters), D = 320 mm = 0.32 m, f = 0.018 (friction coefficient for galvanized iron pipes at a Reynolds number of 50000)Now, we can substitute the values:Q = sqrt((2 * 9.81 * 1/0.32) * 0.007 * π * 0.32^5 / 0.018)Q = 0.0749 m^3/sTherefore, the flow rate of water is 0.0749 m^3/s.
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In order to fill a tank of 1000 liter volume to a pressure of 10 atm at 298K, an 11.5Kg of the gas is required. How many moles of the gas are present in the tank? What is the molecular weight of the gas? Assuming that the gas to be a pure element can you identify it?
Answers
Answer:
The molecular weight will be "28.12 g/mol".
Explanation:
The given values are:
Pressure,
P = 10 atm
= \(10\times 101325 \ Pa\)
= \(1013250 \ Pa\)
Temperature,
T = 298 K
Mass,
m = 11.5 Kg
Volume,
V = 1000 r
= \(1 \ m^3\)
R = 8.3145 J/mol K
Now,
By using the ideal gas law, we get
⇒ \(PV=nRT\)
o,
⇒ \(n=\frac{PV}{RT}\)
By substituting the values, we get
\(=\frac{1013250\times 1}{8.3145\times 298}\)
\(=408.94 \ moles\)
As we know,
⇒ \(Moles(n)=\frac{Mass(m)}{Molecular \ weight(MW)}\)
or,
⇒ \(MW=\frac{m}{n}\)
\(=\frac{11.5}{408.94}\)
\(=0.02812 \ Kg/mol\)
\(=28.12 \ g/mol\)
This agency develops standards for pressure vessels and pressure relief valves, as well as the design, welding, and materials that may be used in pipeline construction.
Select one:
a. American Petroleum Institute
b. American Society of Mechanical Engineers
c. American Gas Association
d. National Fire Protection Association
Answers
Answer:
b. American Society of Mechanical Engineers
Explanation:
The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.
The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.
Please help me solve Problem 21.2
Answers
__________________________________________________________
Hello! In this question, we are trying to find the maximum value of shear flow in the web of the wing spar. Note that we are trying to find this with a section that is 1 meter away from the free end of the beam.
__________________________________________________________
Explanation:
In this problem, we know that:
the web has a thickness of 2 mm.Fully effective in resisting direct stressThis information should be kept in mind and can help us solve our problem.
__________________________________________________________
Solve:
Let us begin to solve the problem.
Since we're analyzing the moment in one section, in this case, we can note this as "section 1", we can use this formula to determine the moment in this section:
\(M_{1}=\frac{wl^2}2}\)
Whereas:
Plug in the values into the equation and solve:
\(M_{1}=\frac{15*1^2}2}=7.5\text{kN-m}\)
Now, let us find the moment of inertia of the beam in our 1st section. We'll use the formula:
\(I_{xx}=\frac{BD^3}{12} +2Ah^2\)
Whereas:
B = width (2 mm)D = depth (300 mm)A = area (500 mm²)h = centroid of this section (150 mm)Plug in the values into the equation and solve:
\(I_{xx}=\frac{2(300)^3}{12} +2(500)(150)^2=2.7\times10^7\:\text{mm}^4\)
Now knowing our moment and inertia, we can solve our direct distress in the z direction of our flanges using the following formula:
\(\sigma_{z,U} = -\sigma_{z,L}=\frac{M_{1}}{I_{xx}}y\)
We know:
Plug the values into the equation and solve. (Note that unit conversion was done for M1):
\(\sigma_{z,U} = -\sigma_{z,L}=\frac{7.5\text{kN-m}*(\frac{1000 N}{1kN})(\frac{1000mm}{1m} )}{2.7\times10^7}(150mm)=-41.7\:\text{N/mm}^2\)
Since we now know what our direct distress is, we can find the bending moment resultant with the formula:
\(P_{z,U}=\sigma_{z,U}\times A\)
We know:
\(\sigma_{z,U} = -\sigma_{z,L}=-41.7\:\text{N/mm}^2\)A = 500 mm² (according to our wing spar given in our problem)Plug in the values to our equation and solve:
\(P_{z,U}=-41.7\:\text{N/mm}^2\times 500\:mm^2=-20850\:N\)
Now knowing our bending moment resultant, we can now find our flange load of the web section. Note that our flange load is uniformly distributed. We will use the formula:
\(P_{U}=\sqrt{P_{z,U}^2+P_{y,U}^2}}\)
We know that:
Plug in the values into the equation and solve:
\(P_{U}=\sqrt{(-20850)^2+0^2}}=20850\:N\)
Please note that the answer we calculated above is our tension (T).
Let's now calculate our bending moment resultant using:
\(P_{y,L}=P_{z,L}\times\frac{\delta{y}^2}{\delta_{z}}\)
We know:
\(P_{z,L}=-20850\:N\)\(\delta{y}^2=100\:mm\)\(\delta_{z}=1\:m\)Plug in the values and solve. To make things go faster, I included the unit conversion for our denominator value:
\(P_{y,L}=-20850\:N\times\frac{100\:mm}{(1\:m\times\frac{1000\:mm}{1\:m} )}=-2085\:kN=2085\:kN\)
Please note that the above calculation would be our compression value.
Let's calculate our shear force in the web in our 1st section using a known relationship:
\(S_{y}=-W\times\delta_{z}+P_{y,L}\)
We know:
Plug in our known values and solve:
\(S_{y}=-15\times(1\:m\times\frac{1000\:mm}{1\:m} )+2085=-12915\:N\)
In order to figure out what our shear flow is (note that our shear flow is represented as q), we will use the relationship:
\(q=\frac{S_y}{I_{xx}} [\int_{0}^{s}2(150-s)ds+500\times(\frac{300}{2} )]\)
We know:
\(S_{y}=-12915\:N = 12915\:N\)\(I_{xx}=2.7\times10^7\:mm\)Plugging in the values, we will get:
\(q=\frac{12915}{2.7\times10^7\:mm} [\int_{0}^{s}2(150-s)ds+500\times(\frac{300}{2} )]\)
Simplify the equation:
\(q=4.78\times10^{-4} [\int_{0}^{s}(300-s)ds+75000]\)
Integrate the equation:
\(q=4.78\times10^{-4} [\int_{0}^{s}(300-s)ds+75000]\\\\q=4.78\times10^{-4} ((300s-\frac{2s^2}{2} +[0])+75000)\\\\q=4.78\times10^{-4} ((300s-s^2 )+75000)\)
We now have our equation for the shear flow. We know that the max value of shear flow will happen when s equals 150 mm, so let's plug in the value 150 mm into "s" in our "q" equation and solve:
\(q=4.78\times10^{-4} ((300(150)-150^2 )+75000)=\boxed{46.8\:N/mm}\)
__________________________________________________________
Answer:
The max value of shear flow in the web in the 1st section of the beam is:
\(q=\boxed{46.8\:N/mm}\)
__________________________________________________________
A submarine submerges by admitting seawater (S = 1.03) into its ballast tanks. The amount of water admitted is controlled by air pressure, because seawater will cease to flow into the tank when the internal pressure (at the hull penetration) is equal to the hydrostatic pressure at the depth of the submarine. Consider a ballast tank, which can be modeled as a vertical half-cylinder (R = 8 ft, L = 20 ft) for which the air pressure control valve has failed shut. The failure occurred at the beginning of a dive from 60 ft to 1000 ft. The tank was initially filled with seawater to a depth of 2 ft and the air was at a temperature of 40 °F. As the weight of water in the tank is important in maintaining the boat’s attitude, determine the weight of water in the tank as a function of depth during the dive. You may assume that tank internal pressure is always in equilibrium with the ocean’s hydrostatic pressure and that the inlet pipe to the tank is at the bottom of the tank and penetrates the hull at the "depth" of the submarine.
Answers
Answer:
Explanation:
Fw= y looking symbol sea water (2010.62-168171.2727/h+32.935)ft^3
Match the term to the correct definition. bus full mesh ring star
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Bus: linear arrangement Round in the form of a ring Systems are arranged in the form of a star using wire in this topology. Mesh: A non-synchronized arrangement of systems.
What is star bus topology?This topology is referred to as a star bus topology since it incorporates different star topologies into a single bus. A bus or star topology is comparable to the widely used tree topology in networks.
What distinguishes mesh topology from star star?The most popular topology in home and office networks is the star topology because it is so simple to deploy, operate, and troubleshoot. A redundant network of connections between nodes forms a mesh topology.
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as mentioned in the show this week, what will nasa’s artemis ii mission have onboard the spacecraft that artemis i did not?
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As indicated in this week's episode, the Artemis ii mission of NASA will include astronauts that Artemis I did not.
An astronaut is a person who has been prepared, equipped, and sent into space by a human spaceflight programmer to serve as a commander or crew member aboard a spaceship. The name astronaut is derived from the Greek word for "star." Despite being reserved for professional space travellers, the expression is occasionally used to describe anyone who journeys into space, including scientists, politicians, journalists, and tourists. Technically, an astronaut can be anyone who goes to space, regardless of nationality. However, cosmonauts—another Greek word for "space"—are frequently used to refer to astronauts working for Russia or the Soviet Union. Due to China's relatively recent advancements in crewed spaceflight, the term "taikonaut" has gained in popularity in recent years, albeit its precise meaning is unclear.
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Which of the following would NOT be a concern with relying completely on cloud computing?
(1 point)
creating an offline back-up of critical documents the collaborative nature of cloud-based applications security and privacy of stored data and information accessing files when Internet access is not available
Answers
The option that would NOT be a concern with relying completely on cloud computing is option a, creating an offline backup of critical documents.
What is cloud computing? Cloud computing is a type of computing that relies on sharing computing resources, rather than having local servers or personal devices to handle applications. It involves the delivery of computing services—including servers, storage, databases, networking, software, analytics, and intelligence—over the Internet (“the cloud”) to offer faster innovation, flexible resources, and economies of scale.
What are the concerns with relying completely on cloud computing? Although cloud computing provides many benefits, there are some concerns that you should consider before relying completely on it. Here are some of them: Security and privacy of stored data and information, accessibility to files when Internet access is not available, and the collaborative nature of cloud-based applications.
Let's examine each option in the given question:
Option A: Creating an offline backup of critical documents - This would not be a concern if you rely completely on cloud computing. In fact, creating an offline backup of your documents is essential as it serves as a backup in case of any technical error in the cloud storage. Therefore, this is not the correct option.
Option B: The collaborative nature of cloud-based applications - One of the benefits of cloud computing is that it enables users to work collaboratively on documents from different locations. However, some companies may require their data to remain within their private servers or local networks, so they may not be comfortable relying entirely on cloud computing. Hence, this is not the correct option.
Option C: Security and privacy of stored data and information - Cloud computing involves the storage of data and information on the cloud. The security of this data is paramount. Cloud service providers must ensure that their users' data is secure from any potential breaches. This is a concern when relying completely on cloud computing, hence this is the correct option.
Option D: Accessing files when Internet access is not available - Cloud computing is an Internet-based service. Users need an internet connection to access their files. When there is no internet connection, users may be unable to access their files, and this is a concern with relying entirely on cloud computing. Hence, this is not the correct option.
So, when relying on cloud computing, one of the advantages is that the data is stored remotely, eliminating the need for offline backups. Cloud providers typically have robust data backup and disaster recovery mechanisms in place, which reduces the need for users to create their own offline backups.
Therefore, the answer is option a.
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a ______ is a controller that maintains a constant air pressure in a duct or building area
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Answer:
a pressure regulator is a controller that maintains a constant air pressure in a duct or building area
Match the example to the model type it represents.
1. The client complains about the way the keyboard feels
1.mock-up
2. The engineering team tests how the tire treads on a new SUV perform on 2.various road conditions
preproduction model
3. The engineering team performs tests on the efficiency of the manufacturing process used for a recumbent bicycle
3.presentation model
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Answer:
represnt
Explanation:
This might count as engineering, I'm not sure as this is IT
An ordered collection of data elements stored and accessed in a program is called what?
Group of answer choices
Variables
List
Locale
Parameters
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Answer:
10.5
Explanation:
Convert to an equation for example P%* X=Y
P is 7.5% X is 140, so the equation Is 7.5 percent * 14= Y
convert 7.5% Into a decimal by removing the percent sign and deviding by 7.5/100= 0.075
Substitute 0.075 for 7.5% in the equation: 7.5%*140=Y becomes 0.075*140= 10.5
Creep occurs by:_________
a. constant stress at room temperature
b. high temperatures over 1000°C
c. constant stress at temperatures over 0.5 TM in K
d. none of these
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Answer:
The answer is "Option C".
Explanation:
The creep depends on temperature and stress whenever the temperature rise, for failure generosity, its core symptoms can be increased between about 0,5 and 0,7 TM in k (melting point of temperature). It is indeed a metal puncturing type, typically at high temperatures with stresses below the yields of a metal.
Explanation:
Creep occurs by constant stress at temperatures over 0.5 TM in K.
Creep is a phenomenon in which a material or an object is elongated over a time period under constant temperature and stress for a long period of time. For example, a belt used for a year or so, is elongated.