How is the average American diet affected by our current food system?"

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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Answer:

Flowing lava can carve or build paths very much like the riverbeds and canyons etched by water, and this probably explains at least one of the meandering channels on the surface of Mars. These results were presented on March 4, 2010 at the 41st Lunar and Planetary Science Conference by Jacob Bleacher at NASA’s Goddard Space Flight Center, Greenbelt, Md. Whether channels on Mars were formed by water or by lava has been debated for years, and the outcome is thought to influence the likelihood of finding life there.

Explanation:

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Answer: Yes they should keep on exploring Mars because they would find out and learn a lot of information that can be helpful later in life

Explanation:

Explanation:

Formula:

\(velocity = (d \div t)\)

d = distance given

t = the amount of time given

Substitute the given values into the formula for velocity:

\(v = 8 \div 4\)

velocity is shortened for v.

8 (distance) divided by 4 (time) equals the velocity.

Solve:

\(2 = 8 \div 4\)

The velocity of the toy car equals: B. 2 m/s.

A 0.842g sample of Hydrogen-3 decays to 0.0526g. Approximately 4.206 half-lives have occurred.

To determine the number of half-lives that have occurred, we can use the decay equation and the concept of exponential decay. The decay equation for radioactive decay is given by:

N(t) = N₀ * (1/2)^(t/T),\((1/2)^(^t^/^T^),\)

where N(t) is the remaining amount of the substance at time t, N₀ is the initial amount, t is the time elapsed, and T is the half-life of the substance.

In this case, we have an initial mass of 0.842g (N₀) and a remaining mass of 0.0526g (N(t)). We can set up the equation as follows:

0.0526g = 0.842g \(* (1/2)^(^t^/^1^2^.^3^2)\),

where t represents the number of half-lives that have occurred.

To solve for t, we can take the logarithm of both sides of the equation:

log(0.0526g/0.842g) = log\([(1/2)^(^t^/^1^2^.^3^2^)\)].

Using the logarithmic property log(\(a^b\)) = b*log(a), we can rewrite the equation as:

log(0.0526g/0.842g) = (t/12.32) * log(1/2).

Simplifying further:

log(0.0526g/0.842g) = (t/12.32) * (-log2),

where log2 is the logarithm base 2.

Now, we can solve for t:

t = (12.32 * log(0.0526g/0.842g)) / (-log2).

Using the given values and performing the calculation, we find:

t ≈ 4.206.

Therefore, approximately 4.206 half-lives have occurred.

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The answer is  "frequency of radio station that transmits a radio wave with half the wavelength of the 720 kHz radio station is 1440 kHz".

The frequency (f) and wavelength (λ) of a radio wave are related by the equation: c = f λ

Where, c is the speed of light (approximately 3.00 x \(10^8\) m/s) in vacuum.

As for the first radio station, \(f_{1}\) = 720 kHz.

the wavelength \(\lambda_{1}\) of its radio waves can be calculated by using the above equation, i.e.

c = \(f_{1}\)\(\lambda_{1}\)

\(\lambda_{1}\) = c / \(f_{1}\)

   = (3.00 x \(10^8\) m/s) / (720 x \(10^3\) Hz)

\(\lambda_{1}\)= 416.67 m

And for the second radio station, as given, its radio waves have half the wavelength of the first radio station. So, the wavelength \(\lambda_{2}\) of its radio waves is \(\lambda_{1}\)/2 = 208.33 m.

We can find the frequency \(f_{2}\) of the second radio station using the same equation:

c = \(f_{2}\).\(\lambda_{2}\)

\(f_{2}\) = c / \(\lambda_{2}\)

    = (3.00 x \(10^8\) m/s) / (208.33 m)

\(f_{2}\) = 1440 kHz

Therefore, frequency of radio station that transmits a radio wave with half the wavelength of the 720 kHz radio station is 1440 kHz.

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Answer:

Explanation:

A cargo spacecraft was orbiting the earth. It is equipped with rocket and has an initial mass of 30 metric ton. It wants to catch up with the international space station to deliver the cargo. So its rocket engine was fired for 1 minute. The engine ejects mass at a rate of 30 kg/s with an exhaust velocity of 3.1 km/s. The pressure at the nozzle exit is 5 kPa and the diameter of exit area is 94.4 cm. What is the thrust of the eng

Answer:

This is because the age of the universe is determined by the pace of expansion in the past, and each model forecasts a different pace.

Explanation:

The age of the universe is determined by the pace of expansion in the past, and each model forecasts a different pace.

This is due to the fact that the expansion rate in the coasting model is constant and never changes. Because the cosmos is growing faster now than during the old days, recollapsing and critical models give shorter ages. According to the accelerating model, the universe is growing at a slower rate currently than in the past, implying an older age.

Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).

Answer:

45.6 J

Explanation:

PE=mgh

m=0.155 kg

g=9.81 m/s^2

h=30.0 m

0.155(9.81)(30)=45.6

The estimated mass of the Milky Way Galaxy from the fact that the Sun orbits the galactic center every 230 million years at a distance of 27,000 light-years. is 1.08 × 10⁴¹ kg.

A Milky Way is a galaxy that includes the whole solar system which includes a collection of stars, planets, dust, and gases. It has a spiral shape, with the sun located at one of the spiral arms.We can estimate the mass of the Milky Way Galaxy by using the laws of gravitation and centripetal force.

The force of gravity between the Sun and the Milky Way is given by:

F = G(M₁)(M₂) / r²

where G is the gravitational constant, M₁ is the mass of the Sun, M₂ is the mass of the Milky Way, and r is the distance between the Sun and the galactic center.

The centripetal force required to keep the Sun in orbit around the Milky Way is given by:

F = (M₁)(v²) / r

where v is the orbital speed of the Sun around the Milky Way.

Since the two forces must be equal, we can equate the two equations and solve for the mass of the Milky Way:

G(M₁)(M₂) / r² = (M₁)(v²) / r

M₂ = vr² / G

The orbital speed of the Sun around the Milky Way is given by:

v = 2πr / T

where T is the orbital period, which is equal to 230 million years.

v = 2π(27,000 light-years) / (230 million years) = 220 km/s

Converting the distance to meters and the time to seconds, we get:

r = 2.54 × 10¹⁷ m

T = 7.26 × 10¹⁵ s

Using the values for v, r, and G (6.6743 × 10⁻¹¹ m³/kg s²), we can calculate the mass of the Milky Way:

M₂ = (220 km/s)² (2.54 × 10¹⁷ m) / (6.6743 × 10⁻¹¹ m³/kg s²) = 1.08 × 10⁴¹ kg

Therefore, the estimated mass of the Milky Way Galaxy is 1.08 × 10⁴¹ kg.

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Answer:

For a body moving at a uniform velocity you can calculate the speed by dividing the distance traveled by the amount of time it took, for example one mile in 1/2 hour would give you 2 miles per hour. If the velocity is non-uniform all you can say is what the average speed is.

The rms voltage measured across the secondary coil is 565.68 V.

The root mean square (RMS) value of an alternating current (AC) or voltage is the equivalent steady direct current (DC) value that produces the same heating effect or power dissipation in a resistor. In other words, it is the DC voltage or current that would produce the same amount of heat as the AC voltage or current over a given time period.

The rms voltage (V_rms) across the secondary coil can be calculated using the formula:

V_rms,secondary = (N_secondary/N_primary) * V_rms,primary

where N_secondary is the number of turns in the secondary coil, N_primary is the number of turns in the primary coil, and V_rms,primary is the rms voltage across the primary coil.

The rms voltage across the primary coil can be found from the given voltage function:

V_rms,primary = (1/√2) * V_peak,primary

where V_peak,primary = 200 V is the peak voltage across the primary coil.

Substituting the values, we get:

V_rms,primary = (1/√2) * 200 V = 141.42 V

Now, using the formula above, we can calculate the rms voltage across the secondary coil:

V_rms,secondary = (700/175) * 141.42 V = 565.68 V

Therefore, the rms voltage measured across the secondary coil is 565.68 V.

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Answer:

thermal energy

Explanation:

This is the definition of the thermal energy of a substance.  It's the sum of the KE and PE of all its particles.

The tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

To calculate the total displacement of the tank division, we need to find the vector sum of the two legs of their journey.

We can see that the tank division travelled 30 miles to the west (W30) and then 70 miles to the north (N70), so their total displacement is the vector sum of these two legs.

To add vectors, we need to break them down into their horizontal and vertical components.

For the first leg, the tank division travelled 30 miles to the west, so its horizontal component is -30 (since it's to the left of the base) and its vertical component is 0 (since it didn't travel up or down).

For the second leg, the tank division travelled 70 miles to the north, so its horizontal component is 0 (since it didn't travel left or right) and its vertical component is 70 (since it travelled directly north).

Now we can add these components to get the total displacement:

Horizontal component = -30 + 0 = -30

Vertical component = 0 + 70 = 70

So the total displacement is a vector with a horizontal component of -30 and a vertical component of 70.

We can use the Pythagorean theorem to find the magnitude of this vector:

|displacement| = √((-30)² + 70²) ≈ 75.9 miles

And we can use trigonometry to find the direction of this vector:

\(\theta = tan^{-1}\dfrac{70} { -30}\)

θ ≈ -67.4°

So the tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

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When an item is raised, the work is done in opposition to gravity. When an item is worked on, energy is transmitted to it, and it develops gravitational potential energy. If the same thing falls from that height, gravity must do the same amount of effort to bring it back to the Earth's surface.

The momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.

The momentum transfered to the more massive cart is determined by applying the principle of conservation of linear momentum as shown below;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

⁻ΔP₁ = ΔP₂

ΔP₂ = m₂v₂ - m₂u₂

ΔP₂ = m₂(v₂ - u₂)

ΔP₂ = 3m₁(v₂ - u₂)

ΔP₂ = 3 x 3.8 x (1.7 - 0)

ΔP₂ = 19.38 kgm/s

Thus, the momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.

The complete question is beblow

A cart of mass 3.8 kg is traveling to the right (which we will take to be the positive x-direction for this problem) at a speed of 6.9 m/s. It collides with a stationary cart that is three times as massive. After the collision, the more massive cart is moving at a speed of 1.7 m/s, to the right.

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Answer: Weight refers to the force of gravity acting upon an object.

(Answer B)

The force applied on the body that is on the inclined plane is given as, F=mgsinθ, F=2×9.8×sin30  =9.8N and f=μmgcosθ f=0.7×2×9.8cos30 =11.88N.

Any increase in the moving force will result in slippage; limiting friction only exists when the moving force and the force opposing motion are equal.

The limiting frictional force is independent of the area of contact and proportional to the normal reaction between the contacting surfaces.

The amount of friction that can be produced when two static surfaces come into touch. A motion will start as soon as the force applied to the two surfaces surpasses the limiting friction. The normal response force and the coefficient of limiting friction are combined to get the limiting friction for two dry surfaces.

Therefore, The force applied on the body that is on the inclined plane is given as, F=mgsinθ, F=2×9.8×sin30  =9.8N and f=μmgcosθ f=0.7×2×9.8cos30 =11.88N.

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Answer:

900 lb to the right

Explanation:

Newton's third law of motion states that for every action there is equal and opposite reaction.

Hence if the two cars (i.e. car A and car B) crash head on and there is an impact on car A of 900 lb to the left, car B would have to generate a force of equal magnitude and in an opposite direction. Since car A had a force of 900 lb to the left, the impact force exerted on car B would be 900 lb to the right.

The answer is 900 lb to the right

Topic: The Effect of Temperature on Enzyme Activity in Plants
Hypothesis: I predict that as the temperature increases, the rate of enzyme activity in plants will also increase. As the temperature decreases, the rate of enzyme activity in plants will decrease.

Temperature is the measure of the average kinetic energy of the particles in a substance. It is measured in degrees Celsius (°C), Fahrenheit (°F), or Kelvin (K). Temperature is determined by the amount of heat present in a substance, which is a measure of the average kinetic energy of its particles. Heat is the energy transferred from a hotter object to a cooler one. When two objects of different temperatures come into contact, heat will flow from the hotter object to the cooler one until both objects reach the same temperature. Temperature can be affected by many factors, such as the weather, the amount of sunlight, and the activity of the particles in a substance.

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Answer:

F = 1280 N

Explanation:

Given that,

Acceleration experienced by a space shuttle, a = 32 m/s²

Mass of the astronauts, m = 40 kg

We need to find the force experienced by the astronaut.

We know that the net force is equal to the product of acceleration and its mass. So,

F = ma

F = 40 kg × 32 m/s²

So,

F = 1280 N

So, 1280 N of force is experienced by the Astronaut.

The value of the force, F₀, at equilibrium is equal to the horizontal

component of the tension in string 2.

Response:

Given:

The weight of the rod = The sum of the vertical forces in the strings

Therefore;

M·g = T₂·cos(37°) + T₁

The weight of the rod is at the middle.

Taking moment about point (2) gives;

M·g × L = T₁ × 2·L

Therefore;

\(T_1 = \mathbf{\dfrac{M \cdot g}{2}}\)

Which gives;

\(M \cdot g = \mathbf{T_2 \cdot cos(37 ^{\circ})+ \dfrac{M \cdot g}{2}}\)

\(T_2 = \dfrac{M \cdot g - \dfrac{M \cdot g}{2}}{cos(37 ^{\circ})} = \mathbf{\dfrac{M \cdot g}{2 \cdot cos(37 ^{\circ})}}}\)

F₀ = T₂·sin(37°)

Which gives;

\(F_0 = \dfrac{M \cdot g \cdot sin(37 ^{\circ})}{2 \cdot cos(37 ^{\circ})}} = \dfrac{M \cdot g \cdot tan(37 ^{\circ})}{2} \approx \mathbf{0.377 \cdot M \cdot g}\)

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Answer:

D. Neptune, Uranus, Jupiter

Explanation:

Just took test

Answer:

yes u can flag football has everything that pad football has so you can enlist on being offensive position but you have to play like you want that position

Explanation:

According to the question by Coulomb's Law the final value of the equation is 0.00 N .

Coulomb's Law is a fundamental law of physics that states the magnitude of the electrostatic force between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. In equation form, the law states F = k * (q1 * q2)/r², where F is the magnitude of the force, k is a constant, q1 and q2 are the magnitudes of the two charges, and r is the distance between the two charges.

Note that by Coulomb's Law,
F = kq1q2/r²
where
k = 8.99E9 Nm²/kg²
q1, q2 = the two interacting charges
r = the distance of separation of the two charges
Thus, for force of B on A points to the right, as opposite charges attract.
qA = 1.0E-9 C
qB = -1.0E-9 C
r = 0.01 m
Thus,
F(B on A) = 8.99E-5 N
Now, for force of C on A points to the left, as like charges repel.
Thus, as
qA = 1.0E-9 C
qC = 4.0E-9 C
r = 0.02 m
F(C on A) = -8.99E-5 N    [the negative sign because it is to the left]
Thus,
Fnet (A) = F(B on A) + F(C on A)
Fnet (A) = 0.00 N

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Answer:

The charge is believed to be from the charge of the quarks that make up the nucleons (protons and neutrons). A proton is made of two Up quarks, with 2/3 positive charge each and one Down Quark with a negative 1/3 charge (2/3 + 2/3 + -1/3 = 1).

Explanation:

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