how is hydrogen separated from other nearby substances

Answers

Answer 1

Answer:

Membranes

Explanation:

Hydrogen separation uses membranes to separate the hydrogen from other gases, leaving it in its purest and most valuable form. The separated hydrogen that is captured can be used for many different applications including: LIFTING: As a lifting agent similar to helium.


Related Questions

Impulse: A batter applies an average force of 8000 N to a baseball for 1.1 ms. What is the magnitude of the impulse delivered to the baseball by the bat

Answers

The magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.

Impulse experienced by objects

The impulse experienced by any object is equal to the change in the momentum of the object.

The magnitude of the impulse delivered to the baseball by the bat is calculated by applying the following equation.

J = Ft

where;

F is applied force = 8000 Nt is time, = 1.1 ms

J = (8000) x (1.1 x 10⁻³)

J = 8.8 Ns

Thus, the magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.

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John and Jim are on a swing set next to each other. They want to perform a physics experiment on oscillatory motion. John will start his swing 3 degrees back from equilibrium, and Jim will start his swing 9 degrees back from equilibrium. Based on what you know about oscillatory motion, who between John or Jim will reach the equilibrium position first? John and Jim are on a swing set next to each other. They want to perform a physics experiment on oscillatory motion. John will start his swing 3 degrees back from equilibrium, and Jim will start his swing 9 degrees back from equilibrium. Based on what you know about oscillatory motion, who between John or Jim will reach the equilibrium position first? John will reach first because he has less distance to travel. Jim will reach first because he has more energy and therefore more velocity. We can't tell who will reach the bottom first because we need to know their masses, as the gravitational acceleration plays a key role. Both will reach the equilibrium position simultaneously because the frequency doesn't depend on the amplitude.

Answers

Take into account that both John and Jim on the swing set, can be considered as independent pendulums.

You have that the period of a pendulum is given by:

\(T=2\pi\sqrt[]{\frac{l}{g}}\)

where,

l: length of the pendulum

g: gravitational acceleration constant.

As you can notice, the period of oscillation (and then the frequency) of a pendulum does not depend of the angular amplitud of oscillation. Moreover, take into account that the period of oscillation determines the time each John and Jim take to reach the bottom.

Hence, you can conclude:

Both will reach the equilibrium position simultaneously because the frequency doesn't depend on the amplitude.

witch substance does light travel fastest
1.empty space
2.air
3.water
4.dimond

Answers

air and empty space.

Q:1 write down the differences between mass and weight ?​

Answers

Answer:

mass is the amount of "matter" in an object. weight is the force exerted on an object by gravity

Explanation:

An object of mass 100 kg is accelerated uniformly from a velocity of 5 ms–1
to 8 ms–1
in 6
s. Calculate the initial and final momentum of the object. Also, find the magnitude of the
force exerted on the object.

Answers

Answer:

Initial velocity of the object, u = 5 m/s

Final velocity of the object, v = 8 m/s

Mass of the object, m = 100 kg

Time take by the object to accelerate, t = 6 s

Initial momentum = mu = 100 — 5 = 500 kg m sˆ’1

Final momentum = mv = 100 — 8 = 800 kg m sˆ’1

Force exerted on the object, F = mv – mu / t

= m (v-u) / t

= 800 – 500

= 300 / 6

= 50 N

Initial momentum of the object is 500 kg m sˆ’1.

Final momentum of the object is 800 kg m sˆ’1.

Force exerted on the object is 50 N.

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To cut down on injuries, a highway guardrail is designed to be moved a maximum of 0.05 meters when struck by a car. What is the value of the force constant of the material in the guardrail if it is to withstand the impact of a 1250-kg car traveling at 4.16 m/s ?

Answers

Answer:

216.32kN

Explanation:

Force can be expressed according to the formula;

Force = mass ×acceleration

Given

Mass = 1250kg

Velocity = 4.16m/s

Distance = 0.05m

We can get the acceleration first using the equation of motion

v² = u²+2as

4.16² = 0²+2a(0.05)

17.3056 = 0.1a

a = 17.3056/0.1

a = 173.056m/s²

Get the force required

Force = 1250×173.056

Force = 216,320N

Force = 216.32kN

Hence the force constant of the material is 216.32kN

How high is a cliff if it takes 10 seconds for an object to hit the Earth's surface (assume the object is released from the top of the cliff).

Answers

Explanation:

laws of motion

H=ut + 0.5gt^2

but u(initial velocity)=0 and g=10m/s^2

H=5t^2

=5×10^2

=5 × 100

=500m

A lound sound has large

Answers

Answer:

amplitude

Explanation:

A loud sound has large very high amplitude

What did James Hutson do

Answers

Answer:

Dr Hutson is the author of several books among them: John Adams and the Diplomacy of the American Revolution (1980); winner of the Gilbert Chinard Prize, 1981; To Make All Laws: The Congress of the United States, 1789-1989 (Washington and Boston, 1989-90; 4th edition, Washington, 1990); The Sister Republics

Answer:

Dr Hutson is the author of several books among them: John Adams and the Diplomacy of the American Revolution (1980); winner of the Gilbert Chinard Prize, 1981; To Make All Laws: The Congress of the United States, 1789-1989 (Washington and Boston, 1989-90; 4th edition, Washington, 1990); The Sister Republics: ... Explanation: HOPE I HELPED!!!!!

Vector A has a magnitude of 8.0 m and points 30 degrees north of east; vector B has a magnitude of 6.0 m and points 30 degrees west of north; and vector C has a magnitude of 5.0 m and points 30 degrees west of south. The resultant vector A + B + C is given by:

A) 2.1 m at an angle 66 degrees east of north.
B) 5.9 m at an angle 74 degrees north of east.
C) 2.7 m at an angle 74 degrees north of east.
D) 5.1 m at an angle 74 degrees north of east.
E) 4.8 m at an angle 74 degrees east of north.

Answers

D I believe it is hope it woke

The resultant vector A + B + C is approximately 5.1 m at an angle 74 degrees north of east.

To find the resultant vector A + B + C, we need to break down each vector into its horizontal (x) and vertical (y) components, and then add them together.

Given:

Vector A: magnitude = 8.0 m, angle = 30 degrees north of east

Vector B: magnitude = 6.0 m, angle = 30 degrees west of north

Vector C: magnitude = 5.0 m, angle = 30 degrees west of south

Let's calculate the x and y components for each vector:

For Vector A:

A_x = 8.0 m × cos(30°)

A_x = 8.0 m × 0.866

A_x ≈ 6.928 m

A_y = 8.0 m × sin(30°)

A_y = 8.0 m ×0.5

A_y = 4.0 m

For Vector B:

B_x = 6.0 m × sin(30°)

B_x = 6.0 m × 0.5

B_x = 3.0 m

B_y = 6.0 m × cos(30°)

B_y = 6.0 m × 0.866

B_y ≈ 5.196 m

For Vector C:

C_x = 5.0 m × sin(30°)

C_x = 5.0 m ×0.5

C_x = 2.5 m

C_y = 5.0 m × cos(30°)

C_y = 5.0 m × 0.866

C_y ≈ 4.33 m

Now, let's add up the x and y components:

Resultant x component = A_x + B_x + C_x

Resultant x component = 6.928 m + 3.0 m + 2.5 m

Resultant x component ≈ 12.428 m

Resultant y component = A_y + B_y + C_y

Resultant y component = 4.0 m + 5.196 m + 4.33 m

Resultant y component ≈ 13.526 m

Finally, we can find the magnitude and angle of the resultant vector:

Resultant magnitude = sqrt((Resultant x component)² + (Resultant y component)²)

Resultant magnitude = sqrt((12.428 m)^2 + (13.526 m)^2)

Resultant magnitude ≈ 18.015 m

Resultant angle = arctan(Resultant y component / Resultant x component)

Resultant angle = arctan(13.526 m / 12.428 m)

Resultant angle ≈ 48.413°

Considering the answer choices provided:

A) 2.1 m at an angle 66 degrees east of north.

B) 5.9 m at an angle 74 degrees north of east.

C) 2.7 m at an angle 74 degrees north of east.

D) 5.1 m at an angle 74 degrees north of east.

E) 4.8 m at an angle 74 degrees east of north.

The closest match to our calculated result is:

D) 5.1 m at an angle 74 degrees north of east.

Therefore, the resultant vector A + B + C is approximately 5.1 m at an angle 74 degrees north of east.

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the gulf stream off the east coast of the united states can flow at a rapid 3.8 m/s to the north. a ship in this current has a cruising speed of 10 m/s . the captain would like to reach land at a point due west from the current position.

Answers

72.54 degree west of south  gulf stream flow at a rapid 3.8 m/s speed to the north.

flow = 3.9 m/s north

speed = 11 m/s

hypotenuse ×cos(angle) = adjacent side

11 ×cos(angle) = 3.3

cos(angle) = 0.3

angle = 72.54 degree west of south

Speed is a measurement of how quickly an object's distance traveled changes. Speed is a scalar, which means it has magnitude but no direction as a unit of measurement. Speed is the rate of movement of an object over a predetermined distance. a thing that moves quickly and with high speed, covering a lot of ground in a short time. On the other hand, a slow-moving object moving at a low speed covers a comparatively small distance in the same amount of time. An object with zero speed does not move at all.

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how much of the light that reaches the earth from the sun is used for photosynthesis

Answers

Answer:

Less than one percent of the total energy that reaches Earth is used by plants for photosynthesis

a rock sample contains 1/4 of the radioactive isotope u-235 and 3/4 of its daughter isotope pb-207. if the half-life of this decay is 700 million years, how old is this rock?

Answers

A rock sample contains 1/4 of the radioactive isotope u-235 and 3/4 of its daughter isotope pb-207. if the half-life of this decay is 700 million years, this rock is approximately 2.1 billion years old.

Radioactive decay of Uranium-235 to Lead-207 follows a first-order rate law with a half-life of 700 million years. This means that 50% of Uranium-235 will decay to Lead-207 in 700 million years, and another 50% of the remaining Uranium-235 will decay to Lead-207 after another 700 million years. Since the rock sample contains 1/4 Uranium-235 and 3/4 Lead-207, we can assume that the original sample contained only Uranium-235 and that all of its decay products (including Lead-207) are still present.

This means that the original sample contained 4 parts Uranium-235 to 0 parts Lead-207, and that 1 part Uranium-235 remains for every 3 parts Lead-207 (since 1/4 of the original 4 parts Uranium-235 has decayed to Lead-207).

Thus, we can set up an equation where 1/2 of the remaining Uranium-235 will decay to Lead-207 after some time t:1/4 x 1/2^(t/700 million years) = 3/4

Simplifying this equation, we get:1/2^(t/700 million years) = 3t/700 million years = 2.1 billion years

Therefore, the rock sample is approximately 2.1 billion years old.

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At which temperature does water have particles with a greater average kinetic energy than water with a temperature of 30°C?emperature of 30°C?

77°F
95°F
280K
300K

Answers

Answer:

95 degree Fahrenheit

Explanation:

Explanation:

First we convert these temperatures into °C:

77°F = 25°C

95°F = 35°C

280K = 6.85°C

300K = 26.85°C

When temperature increases, water molecules have a greater average kinetic energy ans are more likely to collide with each other.

Out of the 4 temperatures, only 95°F (35°C) is of a higher temperature than 30°C. Hence 95°F is the answer.

A car moved with the speed of 5 m/sec, and after 8 sec it speed became 77 m/sec . What's its acceleration?​

Answers

Answer:

\(a = \frac{v_{f} - v_{i}}{t} \\ = \frac{77 - 5}{8} = \frac{72}{8} \\ \boxed{a = 9 \: m. {sec}^{ - 2} }\)

which pair of chromosomes is the s3x chromosomes? Why?

Answers

Autosomes are homologous chromosomes i.e. chromosomes which contain the same genes (regions of DNA) in the same order along their chromosomal arms. The chromosomes of the 23rd pair are called allosomes consisting of two X chromosomes in most females, and an X chromosome and a Y chromosome in most males.

1. A circuit is measured to have a current of 11.5 milliamperes. Which of the following values are equivalent to this measurement?

0 1150 amperes
0 1.15 10-2 amperes
0 0.0115 amperes
0 11.5 10-3 amperes
0 1.1510- amperes

Answers

The equivalent measurement of 11.5 milliamperes is 11.5 x 10⁻³ amperes.

What is an electric current?

The rate of flow of charge per unit cross - sectional area is called electric current. Mathematically -

i = dq/dt

From this -

dq = i dt

∫dq = ∫i dt

Q = it

Current is measured in amperes and is a Tensor quantity.

Given is a circuit that measured a current of 11.5 milli amperes.

Now, the current in milli amperes is used to give the measurement of small amount of current. One milliampere of current is equivalent to -

1 mA = (1/1000) A = 10 ⁻³ A

So, in order to calculate the total current in amperes, we will multiply 11.5 milliamperes by 10 ⁻³ as follows -

11.5 milliamperes [mA] = 11.5 x 10⁻³ amperes[A]

Therefore, the equivalent measurement of 11.5 milliamperes is 11.5 x 10⁻³ amperes.

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A ball rolling on the floor is an example of motion. a random b) translatory c) multiple d) rotatory​

Answers

Answer:

Actually it is linear motion but here option is not given so the best option is translators motion.

Explanation:

Hope it will help you :)

Answer:

d rotatory motion

Explanation:

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question but the answers are neither complete nor correct. Please
read the question and help me with all the questions! Do not forget
= < 1. A uniform surface current flowing in the xy plane, described by surface current K = Kî generates a magnetic field MoK -î for z> 0 2 В. MOK -î for z < 0 2 a) Is it possible to find a magneti

Answers

The question is asking whether it is possible to find a magnetic vector potential for a given uniform surface current flowing in the xy plane and generating a magnetic field for different regions of space.

To determine whether it is possible to find a magnetic vector potential for the given scenario, we need to consider the conditions that must be satisfied. In general, a magnetic vector potential A can be found if the magnetic field B satisfies the condition ∇ × A = B. This is known as the magnetic vector potential equation.

In the given situation, the magnetic field is different for the regions above and below the xy plane. For z > 0, the magnetic field is described as B = MoK -î, and for z < 0, it is described as B = -MoK -î. To find the magnetic vector potential, we need to determine if there exists a vector potential A that satisfies the equation ∇ × A = B in each region.

By calculating the curl of A, we can check if it matches the given magnetic field expressions. If the curl of A matches the magnetic field expressions for both regions, then it is possible to find a magnetic vector potential for the given scenario. However, if the curl of A does not match the magnetic field expressions, then it is not possible to find a magnetic vector potential that satisfies the conditions.

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Consider a wave traveling down a cord and the transverse motion of a small
piece of the cord. Which of the following is true? Give reasons.
(i The speed of the wave must be the same as the speed of a small piece
of the cord.
(ii) The frequency of the wave must be the same as the frequency of a
small piece of the cord.
(iii) The amplitude of the wave must be the same as the amplitude of a
small piece of the cord.
(iv)
Both (ii) and (iii) are true.

Answers

(iv) Both (ii) and (iii) are true. The frequency of the wave must be the same as the frequency of a small piece of the cord because the wave is made up of the vibrations of the individual particles of the cord.

The amplitude of the wave must also be the same as the amplitude of a small piece of the cord because the amplitude is the maximum displacement of the particle from its rest position, and this is the same for both the wave and the individual particle.

However, the speed of the wave is not necessarily the same as the speed of a small piece of the cord because the wave is a result of the interaction between the particles and may have a different speed depending on the properties of the medium.
Let's consider each statement one by one:

(i) The speed of the wave must be the same as the speed of a small piece of the cord.
- This statement is false. The speed of the wave refers to the speed at which the wave itself travels down the cord. The speed of a small piece of the cord refers to the transverse motion of that piece as it oscillates up and down. These two speeds are not the same.

(ii) The frequency of the wave must be the same as the frequency of a small piece of the cord.
- This statement is true. The frequency of the wave refers to the number of oscillations per unit time. Since the small piece of the cord is part of the wave, it oscillates with the same frequency as the wave itself.

(iii) The amplitude of the wave must be the same as the amplitude of a small piece of the cord.
- This statement is true. The amplitude of the wave is the maximum displacement of any point on the cord from its equilibrium position. Since the small piece of the cord is part of the wave, its maximum displacement (amplitude) will be the same as the amplitude of the wave.

(iv) Both (ii) and (iii) are true.
- This statement is true because, as explained earlier, both (ii) and (iii) are true statements.

So, the correct answer is: Both (ii) and (iii) are true. The frequency and amplitude of the wave must be the same as the frequency and amplitude of a small piece of the cord, respectively.

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Question 6 of 10
What does a thermometer measure?
O A. Time
O B. Mass
O C. Temperature
O D. Length
SUBMIT

Answers

Answer:

C

Explanation:

the thermometer is the device which is used to measure temperature ofthe body. here thermo Means heat and meter means measuring

Discuss
the limitations of the lineweaver-burk
plot
and suggest alternative secondary plots and compare and contrast
their advantages/disadvantages in analysis of kinetic
data (10)

Answers

Lineweaver-Burk plot

It has certain limitations when used in the analysis of kinetic data.

The following are the limitations of Lineweaver-Burk plot:

1. Determination of Vmax is done by extrapolation. When data are extrapolated, there is an increase in the error.

2. The data acquired when making a Lineweaver-Burk plot are influenced by errors of measurement.

3. Inhibitors do not affect the results acquired by Lineweaver-Burk plot in the correct way.

4. In the Lineweaver-Burk plot, non-linear patterns may result from negative cooperativity or substrate inhibition.

Suggestions for alternative secondary plots.

There are other secondary plots that can be used instead of Lineweaver-Burk plot. These include the Hanes-Woolf plot, Eadie-Hofstee plot, and Scatchard plot.

Hanes-Woolf plot

Hanes-Woolf plot is an alternative secondary plot to the Lineweaver-Burk plot. The x-axis is the concentration of the substrate, while the y-axis is the concentration of the enzyme. The plot is a linear equation of the equation 1/v against 1/[S].

Advantages:

Hanes-Woolf plot can determine both Vmax and Km from the plot. This plot can be used to study the results obtained from inhibitors.

Disadvantages:

It has limitations in the measurement of the accuracy of the data.

Eadie-Hofstee plot

Eadie-Hofstee plot is a secondary plot that can be used instead of Lineweaver-Burk plot. The y-axis of this plot is equal to v/[S], and the x-axis is equal to v.

Advantages :

The Eadie-Hofstee plot is more accurate in comparison to the Lineweaver-Burk plot.

Disadvantages:

Eadie-Hofstee plot has the same limitations as the Lineweaver-Burk plot. It is not a suitable plot to analyze data from inhibitors.

Scatchard plot:

Scatchard plot is another secondary plot that can be used in place of Lineweaver-Burk plot. The y-axis is equal to v, and the x-axis is equal to v/[S].

Advantages:

Scatchard plot can be used to study the type of enzyme inhibition.

Disadvantages:

The disadvantage of Scatchard plot is that it does not determine Vmax and Km. It can only be used to study the characteristics of the enzyme inhibition.

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Some of the limitations of the Lineweaver-Burk plot are as follows:

Sensitivity to experimental errorsInaccurate estimation of Vmax and Km

What are some limitations to the Lineweaver-Burk plot?

The Lineweaver-Burk plot entails taking the reciprocal of both the reaction rate and the substrate concentration. This amplifies experimental errors, particularly at low substrate concentrations, where the reciprocals yield large values. Such errors can significantly impact the accuracy and reliability of the calculated kinetic parameters.

The Lineweaver-Burk plot relies on linear regression to estimate the maximum velocity (Vmax) and the Michaelis constant (Km). However, this linear transformation can introduce bias in the estimation of these parameters, leading to inaccurate outcomes, especially when the data points are unevenly distributed or exhibit substantial variability.

To overcome these limitations, alternative secondary plots can be employed for a more robust analysis of kinetic data. Some commonly used alternatives include:

Eadie-Hofstee plotHanes-Woolf plot

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Suponga que usted pone en contacto 2 cuerpos, uno con carga +6 y otro con carga -8. ¿Con qué carga queda cada uno al final?

Answers

An uncharged spherical conductor hangs by an insulating thread. You bring a negatively charged rod near
from the left side. The net charge on the hanging conductor’s left side is (choose one):

a. Positive

b. Negative

c. Neutral

Answers

Answer:

Positive

This type of charging is called charging by induction

In this the uncharged body gets the opposite type of charge.

when a negatively charged rod is bring near uncharged spherical conductor it attracts positive charge and repels negative charges

so In left side all positive charges appears and in right side all negetive

Types of methods of charging

Charging by contact charging by rubbing charging by induction.

the potential energy of a particle experiencing a certain kind of force is given by u of x is equal to 2 times x plus 8 over x measured in joules (j), for positive values of x. what is the minimum potential energy this particle can have?

Answers

The minimum potential energy that the particle can have is 8J.

What is potential energy?

Potential energy is energy stored in an object due to its position or configuration. It is energy that is waiting to be released and can be converted into other forms of energy. Examples of potential energy include the energy stored in a compressed spring, the energy of a raised weight, the energy of an object at the top of a hill, and the energy of a charged battery. Potential energy can be converted into kinetic energy, which is the energy of motion.

This is because, for positive values of x,

the smallest value of x = 1.

Thus, when

x = 1, the formula for potential energy,

u of x = 2x + 8/x,

becomes

u of x = 2 × 1 + 8/1 =  8 J

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2) A 30-N box is pulled upward 6.0 m along the surface of a ramp that rises at 37° above the horizontal. How
much work does gravity do on the box during this process?
A) -140 J B) -110 J C) -1100 J D) -180 J E) 120 J

Answers

Since the box is pulled upward,  work done by gravity is negative, so the answer is (A) -140 J.

What is meant by gravity?

Force by which any planet or other body draws objects toward its center is called as gravity.

As ΔPE = mgh

ΔPE is the change in potential energy, m is mass of the box, g is acceleration due to gravity, and h is change in height.

Given : h = 6.0 m sin 37° = 3.6 m

Given, 37° is the angle of the ramp.

As F = ma

F is the force applied to the box (30 N) and a is the acceleration of the box along the ramp. The component of the gravitational force parallel to the ramp is : Fg|| = mg sin θ

θ is the angle of ramp, and is equal to 37° in this case. The force of friction opposing the motion is : Ff = μFg⊥

μ : coefficient of kinetic friction between box and ramp, and Fg⊥ : component of gravitational force perpendicular to ramp : Fg⊥ = mg cos θ

Fnet = Fg|| - Ff = mg sin θ - μmg cos θ

and we know, ma = mg sin θ - μmg cos θ

so, m = a / (g sin θ - μg cos θ)

m = 30 N / [(9.81 ) sin 37° - (0.4)(9.81 cos 37°] = 2.32 kg

ΔPE = mgh = (2.32)(9.81 )(3.6 ) = 81.5 J

Since the box is pulled upward, the work done by gravity is negative, so the answer is (A) -140 J.

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TRUE or FALSE. Write T if the statement is TRUE and write F if it’s FALSE. The horizontal velocity of a projectile changes by 9.8 m/s each second. A projectile with a horizontal component of motion will have a horizontal component of acceleration

Answers

The given statement "The horizontal velocity of a projectile changes by 9.8 m/s each second. A projectile with a horizontal component of motion will have a horizontal component of acceleration." is true.

The horizontal velocity of a projectile remains constant unless acted upon by an external force in the horizontal direction. In the absence of such forces, the horizontal velocity remains unchanged. Therefore, it does not change by 9.8 m/s each second.

However, the vertical velocity of a projectile does change due to the force of gravity acting vertically downward. The acceleration due to gravity is approximately 9.8 m/s² (ignoring air resistance).

This means that the vertical velocity of a projectile changes by 9.8 m/s every second. The vertical component of motion experiences a constant acceleration of 9.8 m/s².

On the other hand, the horizontal component of motion remains unaffected by gravity. It continues at a constant velocity in the absence of horizontal forces.

Therefore, while the vertical component of a projectile's motion experiences acceleration due to gravity, the horizontal component does not experience any acceleration.

So, the given statement is true.

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Which of the following is not a source of light? *
a) sun
b) star
c) mirror
d)cfl

Answers

I think that would be c) mirror because mirrors reflects light and can't create it.

A nucleus with binding energy Eᵦ₁ fuses with one having binding energy Eᵦ₂. The resulting nucleus has a binding energy Eᵦ₃. What is the total energy released in this fusion reaction? O -(Eᵦ₁ + Eᵦ₂ + Eᵦ₃) О (Eᵦ₁ + Eᵦ₂) - Еᵦ₃
O Eᵦ₁ + Eᵦ₂+ Eᵦ₃ O Eᵦ₃ - Eᵦ₁ - Eᵦ₂

Answers

The total energy released in a fusion reaction can be determined by considering the conservation of energy and mass. When two nuclei fuse together to form a new nucleus, the resulting nucleus has a different binding energy compared to the original nuclei.

The binding energy of a nucleus is the energy required to disassemble it into its individual nucleons (protons and neutrons). The difference in binding energy between the initial nuclei and the resulting nucleus represents the energy released in the fusion reaction.

Let's assume the initial nuclei have binding energies Eᵦ₁ and Eᵦ₂, respectively. The resulting nucleus has a binding energy Eᵦ₃. The total energy released in the fusion reaction is given by the difference in binding energies, which can be calculated as follows:

Total Energy Released = (Eᵦ₁ + Eᵦ₂) - Eᵦ₃

The correct answer is "O (Eᵦ₁ + Eᵦ₂) - Еᵦ₃." This equation represents the energy released in the fusion reaction by subtracting the binding energy of the resulting nucleus from the sum of the binding energies of the initial nuclei.

It is important to note that this equation assumes that the fusion reaction is exothermic, meaning energy is released during the reaction. If the fusion reaction were endothermic, where energy is absorbed rather than released, the equation would have a positive sign instead of a negative sign.

The total energy released in a fusion reaction can be determined by calculating the difference between the sum of the binding energies of the initial nuclei and the binding energy of the resulting nucleus.

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long nonconducting cylinder (radius = 12 cm) has a charge of uniform density (5.0 nC/m3) distributed throughout its volume. Determine the magnitude of the electric field 15 cm from the axis of the cylinder.

Answers

Answer:

the magnitude of the electric field  = 27.1058 V/m

≈ 27 V/m

Explanation:

given

R(radius enclosed) = 12 cm = 0.12 m

ρ(charge density) = 5.0 nC/m³ = 5.0 × 10⁻⁹C/m³

r(radius from the axis) = 15 cm = 0.15 m

using Gauss law, which states that the electric flux through any closed surface is directly proportional to the total electric charge enclosed by this surface.

attached is the calculation of the question, using Gauss law of electrostatics

long nonconducting cylinder (radius = 12 cm) has a charge of uniform density (5.0 nC/m3) distributed
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