How is energy related to the change of state represented
by the model?
Atoms gain energy as a solid changes to a liquid.
Atoms gain energy as a solid changes to a gas.
O Atoms lose energy as a solid changes to a liquid.
O Atoms lose energy as a solid changes to a gas.

There don't seem to be any H atoms in that formula. All I see is Hg, which is mercury.

They form after violent eruptions blow lava fragments into the air, which then solidify and fall as cinders around the volcanic vent.

Usually the size of gravel, these cinders are filled with many tiny bubbles trapped in the lava as it solidifies. Cinder cones stand at heights of tens of meters to hundreds of meters. Cinder cones form from ash and magma cinders--partly-burned, solid pieces of magma, that fall to the ground following a volcanic eruption. This type of eruption contains little lava, as the magma hardens and breaks into pieces during the explosion.

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nswer

Explanation

An exothermic reaction is a type of chemical reaction that gives off heat to its surroundings. In an exothermic reaction, energy is released because the total energy of the products is less than the total energy of the reactants.

Answer:An exothermic Chemical Reaction

Explanation:

Answer:brainly

Explanation:

absolutely brainly

full of help and knowledge

The cylinder's volume is roughly 479.85 cm3 at a height of 11.76 cm and a diameter of 7.22 cm.

With no zero error, the diameter of a cylinder can be measured with vernier calipers. The Vernier scale's zero is discovered to be between 5.10 cm and 5.15 cm on the main scale. The 50 divisions on the Vernier scale are comparable to 2.45 cm.

V = πr²h

where r is the cylinder's radius, h is its height, and is the mathematical constant pi (approximately equal to 3.14159).

We must first determine the cylinder's radius in order to compute the volume of the cylinder with a height of 11.76 cm and a diameter of 7.22 cm:

r = d/2 = 7.22 cm / 2 = 3.61 cm

Now that the parameters have been entered, we can compute the cylinder's volume:

V = π(3.61 cm)²(11.76 cm)

V = 479.85 cm³

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Answer:

Running to catch the bus would be it

Explanation:

because you're running for the others you barly move

The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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The order of reaction is defined as the power to which the concentration of the reactants are raised in the rate equation of the reaction.

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The half life of the reaction  is 0.0087 s.

The half-life is the amount of time it takes for half of a substance (such as a radioactive isotope or a drug) to decay, disappear, or be reduced by half. In pharmacology, the half-life of a drug is the time it takes for the concentration of the drug in the body to be reduced by half.

The half-life of a substance is a useful metric for understanding its behavior over time and is used in many fields, including chemistry, biology, and physics.

We know that;

t1/2 = 1/k[A]o

t1/2 = half life

k = rate constant

[A]o = initial concentration

t1/2 = 1/7.98x10^9 * 1.46x10^-8

t1/2 = 0.0087 s

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Answer: Anode: \(Pb+SO_4^{2-}\rightarrow PbSO_4+2e^-\)

Cathode: \(PbO_2+4H^++SO_4^{2-}+2e^-\rightarrow PbSO_4+2H_2O\)

Overall cell reaction : \(Pb+2SO_4^{2-}+PbO_2+4H^+\rightarrow 2PbSO_4+2H_2O\)

Explanation:

Lead storage battery is a secondary cell used in automobiles and invertors. The anode is made up of lead and undergoes oxidation during discharging and cathode is made up of lead oxide and acts as cathode during discharging. The electrolyte used is dilute .

Lead storage battery acts as electrochemical cell while discharging.

Discharging reaction for  Anode:

Discharging reaction for  Cathode: \(PbO_2+4H^++SO_4^{2-}+2e^-\rightarrow PbSO_4+2H_2O\)

Overall cell reaction : \(Pb+2SO_4^{2-}+PbO_2+4H^+\rightarrow 2PbSO_4+2H_2O\)

A lead storage battery is an energy storage device. At the anode lead and sulfate ion reacts to produce Lead(II) sulfate and release two electrons.

In secondary cells or the recharge-discharge cells during recharge, the positive electrode is the anode, while during discharge cathode is the positive electrode.

The anode (lead) of the cell undergoes an oxidation reaction during the discharge, whereas the lead oxide or the cathode undergoes reduction.

The discharging reaction at the anode of the cell is given as,

\(\rm Pb + SO_{4}^{2-} \rightarrow PbSO_{4} + 2e^{-}\)

The discharging reaction at the cathode of the cell is given as,

\(\rm PbO_{2} + 4H^{+} + SO_{4}^{2-} + 2 e^{-} \rightarrow PbSO_{4} + 2H_{2}O\)

The overall cell reaction is given as,

\(\rm Pb + 2SO_{4}^{2-} + PbO_{2} + 4H^{+} \rightarrow 2PbSO_{4} + 2H_{2}O\)

Therefore, the gain and loss of electrons are represented at the cathode and the anode of the cell.

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Answer:

0.4699

Explanation:

The oxidation level in the first set from row 1 to row 5 is 4 , 1 ,1,2,1 and in the second set is 3,1,1,1,2. the compounds which  have the same oxidation level as the compound in row 1 in first set is 3 and in second set is none.

Hence, oxidation level of row 1 of first set is 4 with two electronegative O and one electronegative Nalong with an unsaturation. Also row 3 of the first set has oxidation level 4(two unsaturation and two 0) Similarly, oxidation level of row 1 of second set is 3. No other compounds in second set has oxidation level 3, hence first set - 3 and second set - none. The oxidation level of a compound is determined by the number of electronegative elements and unsaturations in the compound. The more number of electronegative elements there are, more is the oxidation level as we know that oxidation is the process of removal of electron or addition of electronegative elements like O and N. Also, the reverse reduction is defined as H being added to the compound. For example, in acetic acid, there are two O atoms and a C=O unsaturation. Hence, the oxidation level is 3. Similarly, in ethene, there is only one unsaturation. Hence, oxidation number is 1.

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the complete question is :

Which of the following compounds have the same oxidation level as the compound in row 1? (Enter your answer in numerical order as the row number(s) separated by commas, i.e. 2, 3, 5. If none of the compounds have the same oxidation level, write 'none'.)

The volume of O₂ produced when 8.52 g of Na₂O₂ is added to excess water is approximately 1.17 liters at STP.

When it comes to the ideal gas law, the underlying assumption is that the gas is in a state of thermodynamic equilibrium. This means that its molecules are not interacting with each other except through perfectly elastic collisions.

Equation:

We can use stoichiometry to determine the volume of oxygen gas produced from the reaction of 8.52 g of Na₂O₂.

First, we need to convert the mass of Na₂O₂ to moles using its molar mass:

8.52 g Na₂O₂ × (1 mol Na₂O₂ / 77.98 g Na₂O₂) = 0.1093 mol Na₂O₂

According to the balanced chemical equation, 1 mole of Na₂O₂ produces 1/2 mole of O₂:

2 Na₂O₂ + 2 H₂O → 4 NaOH + O₂

1 mol Na₂O₂ produces 1/2 mol O₂

So, the number of moles of O₂ produced is:

0.1093 mol Na₂O₂ × (1/2 mol O₂ / 1 mol Na₂O₂) = 0.05465 mol O₂

Finally, we can use the ideal gas law to determine the volume of O₂ produced at standard temperature and pressure (STP), which is defined as 0°C (273 K) and 1 atmosphere (1 atm) of pressure:

PV = nRT

At STP, the pressure and temperature are known, so we can rearrange the equation to solve for V:

V = nRT / P

Plugging the values, we get:

V = (0.05465 mol) × (0.08206 L atm mol⁻¹ K⁻¹) × (273 K) / (1 atm)

V ≈ 1.17 L

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The electrons move from left to right through the circle labeled "M" to reach the cathode, where reduction takes place.

If oxidation occurs on the left side of the fuel cell and reduction occurs on the right side, the movement of electrons can be described as follows: Electrons move from left to right through the circle labeled "M."

In a fuel cell, the process of oxidation takes place at the anode (labeled A) where the fuel is oxidized, releasing electrons. These electrons then flow through the external electrical circuit, represented by the wire connecting objects A and B. The electrons reach the cathode (also labeled A) on the right side of the cell, where reduction occurs.The circle labeled "M" represents the membrane or electrolyte in the fuel cell. This membrane allows the transport of ions but blocks the movement of electrons. As a result, electrons cannot flow directly through the electrolyte but must travel through the external circuit.

This movement of electrons through the external circuit is what generates an electric current that can be used to power electrical devices or systems.

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The amount, in mL, of the suspension that should be given to an infant weighing 17 lb will be 1.16 mL

0.8 mL of the liquid contains 80.0 mg of the drug.

The recommended dose is 15 mg per kg of body weight

The infant to be given the drug weighs 17 lb.

First, let's convert the weight of the infant to kg.

1 lb = 453.59 g

17 lb =       453.59 x 17/1

                   = 7711.03 g

1000 g = 1 kg

7711.03 g = 7711.03 x 1/1000

               = 7.711 kg

So, the baby's weight is 7.711 kg.

The drug dose for the baby can thus be calculated as:

15 mg x 7.711 = 115.67 mg

But 0.8 mL of the drug contains only 80.0 mg. How many mL will contain 115.67 mg?

                   0.8 x 115.67/ 80.0 = 1.16 mL

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Answer:

The answer is 82

Explanation:

Dude in the stop says so

Under these conditions, the cell potential, Ecell, would be somewhat lower than the usual cell potential, E°cell.

To determine whether the cell potential, Ecell, would be greater than, less than, or equal to the standard cell potential, E°cell, use the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

where:

Ecell = cell potential under the given conditions

E°cell = standard cell potential

R = gas constant (8.314 J/(mol·K))

T = temperature in Kelvin (25°C = 298 K)

n = number of electrons transferred in the overall cell reaction

F = Faraday constant (96,485 C/mol)

Q = reaction quotient

The balanced equation for the cell reaction is:

2Al(s) + 3Sn₂⁺(aq) → 2Al₃⁺(aq) + 3Sn(s)

The cell reaction involves the transfer of 3 electrons, so n = 3.

At standard conditions (1 M concentration for all species and 25°C), the cell potential, E°cell, can be calculated using the standard reduction potentials for the half-reactions:

Al₃⁺(aq) + 3e- → Al(s) E° = -1.66 V

Sn₂⁺(aq) + 2e- → Sn(s) E° = -0.14 V

E°cell = E°(cathode) - E°(anode) = (-0.14 V) - (-1.66 V) = 1.52 V

To calculate Q, use the given concentrations of Al3+ and Sn2+:

Q = ([Al₃⁺]²/[Sn⁺]³) = (1.90 M)² / (0.25 M)³ = 231.2

Now use the Nernst equation to calculate Ecell under the given conditions:

Ecell = E°cell - (RT/nF)ln(Q)

Ecell = 1.52 V - [(8.314 J/(mol·K))(298 K)/(3 mol)(96,485 C/mol)ln(231.2)]

Ecell = 1.52 V - (0.012 V) = 1.508 V

Therefore, the cell potential, Ecell, under these conditions would be slightly less than the standard cell potential, E°cell. This is because the concentration of Al₃⁺ is higher and the concentration of Sn₂⁺is lower than the standard conditions, which shifts the reaction towards the side with lower concentration of Al₃⁺ and higher concentration of Sn₂⁺. This means that the reaction is not occurring under standard conditions and the Nernst equation must be used to account for the non-standard conditions.

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Answer:

An area that has a lot of sun-light!

Explanation:

Answer:

17 protons, 20 neutrons, and 17 electrons​.

Explanation:

A periodic table can be defined as the standard arrangement of chemical elements by atomic number, electronic configuration and chemical properties in a tabular form.

Generally, a proper representation of the mass number and atomic number of chemical elements is key and very important in chemistry.

Furthermore, as a rule, it should be noted that the mass number (nucleon number) is always larger than the atomic number(number of proton).

The mass number of this neutral atom of Cl-37 is 37 and we know that the atomic number (number of protons) of chlorine is 17. Also, the atomic number of an element is equal to the number of its electrons.

A neutral atom of Cl-37 has 17 protons, 20 neutrons, and 17 electrons.

Hence, a neutral atom of Cl-37 can be identified based on its number of protons because it represent its atomic number, which is what is used to differentiate an atom of an element from the atom of another chemical element.

Two key criteria that engineers must prioritize are efficiency and safety. By emphasizing efficiency and safety during process development, engineers can create robust and reliable processes that not only maximize productivity but also prioritize the well-being of personnel and the environment.

When developing a process, engineers need to consider several important criteria. Two key criteria that engineers must prioritize are efficiency and safety.

Efficiency is crucial in process development to ensure optimal use of resources, time, and energy. Engineers strive to design processes that maximize productivity, minimize waste, and reduce costs. This involves optimizing reaction conditions, streamlining workflow, and implementing automation where possible. Efficiency considerations also extend to energy consumption, raw material utilization, and overall process sustainability.

Safety is another critical aspect that engineers must prioritize. They need to identify and mitigate potential hazards associated with the process, ensuring the safety of both personnel and the environment. This involves conducting thorough risk assessments, implementing safety protocols, and designing equipment and systems with safety features. Engineers must also consider the safe handling and storage of materials, as well as potential risks during transportation and disposal.

By emphasizing efficiency and safety during process development, engineers can create robust and reliable processes that not only maximize productivity but also prioritize the well-being of personnel and the environment.

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Answer: Less

Explanation:

Ethane is a non-polar molecule while water is a polar molecule

Standard state of the given equation will be:

Pb (s) + N2(g) + 3O2(g) --> Pb(NO3)2(s)

A chemical equation is a word used frequently in everyday chemistry. Jean Beguin, a French chemist, developed the first chemical equations in 1615. A chemical equation is simply a written representation of the process that occurs during a chemical reaction using numbers and symbols.

Explain:

Pb (NO3)2(s)

elements:

Pb, N, O

elemental states

Pb (s)   N2(g) , O2(g)

equation

Pb (s) + N2(g) + 3O2(g) --> Pb(NO3)2(s)

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Answer:

N, B, Be, C

Explanation:

N (Nitrogen) has 14.0067 B (Boron) has 10.81 Be (Beryllium) has 9 and C (Carbon) has 12

The symbols for every chemical element that has atomic number greater than 3 and atomic mass less than 15.4 u are C, N, O, F, and Ne.

To find elements with atomic number greater than 3 and atomic mass less than 15.4 u, we'll consider the periodic table. Elements with atomic numbers 4 (Be) and higher meet the atomic number criterion. For the atomic mass, we'll look at elements with atomic masses below 15.4 u.

The chemical elements that fulfill both criteria are: Carbon (C) with atomic number 6 and atomic mass 12.01 u, Nitrogen (N) with atomic number 7 and atomic mass 14.01 u, Oxygen (O) with atomic number 8 and atomic mass 16.00 u, Fluorine (F) with atomic number 9 and atomic mass 18.99 u, and Neon (Ne) with atomic number 10 and atomic mass 20.18 u.

These elements meet the conditions of having atomic number greater than 3 and atomic mass less than 15.4 u. Therefore, the symbols for these elements are C, N, O, F, and Ne.

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Answer:

1. Molecular equation

BaCl2(aq) + 2AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)

2. Complete Ionic equation

Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯(aq)

3. Net ionic equation

Cl¯(aq) + Ag⁺(aq) —> AgCl(s)

Explanation:

1. Molecular equation:

BaCl2(aq) + AgNO3(aq) –> AgCl(s) + Ba(NO3)2 (aq)

The above equation can be balance as follow:

There are 2 atoms of Cl on the left side and 1 atom on the right side. It can be balance by putting 2 in front of AgCl as shown below:

BaCl2(aq) + AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)

There are 2 atoms of Ag on the right side and 1 atom on the left side. It can be balance by putting 2 in front of AgNO3 as shown below:

BaCl2(aq) + 2AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)

Now, the equation is balanced

2. Complete ionic equation

In solution, BaCl2 and AgNO3 will dissociate as follow:

BaCl2(aq) —> Ba²⁺(aq) + 2Cl¯(aq)

AgNO3(aq) —> Ag⁺(aq) + NO3¯ (aq)

BaCl2(aq) + AgNO3(aq) –>

Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯

3. Net ionic equation

Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯(aq)

Cancel out the spectator ions i.e ions that appears on both side of the equation in order to get the net ionic equation. This is illustrated below:

2Cl¯(aq) + 2Ag⁺(aq) —> 2AgCl(s)

Cl¯(aq) + Ag⁺(aq) —> AgCl(s)

1. Molecular equation: \(BaCl_2(aq) + 2 AgNO_3(aq) \rightarrow 2 AgCl(s) + Ba(NO_3)_2(aq)\)

2. Complete Ionic equation:\(Ba^{2+} (aq)+ 2Cl^- (aq) + 2 Ag^+ (aq) + 2NO_3^-(aq) \rightarrow2AgCl(s) + Ba^{2+}(aq) + 2 NO_3^-(aq)\)3. Net ionic equation: \(Cl^- (aq) + Ag^+ (aq) \rightarrow AgCl(s)\)

1. Molecular equation:

\(BaCl_2(aq) + AgNO_3(aq) \rightarrow AgCl(s) + Ba(NO_3)_2(aq)\)

There are two Cl atoms on the left side and one on the right. Balance can be achieved by adding 2 in front of AgCl, as seen below:

\(BaCl_2(aq) + 2AgNO_3(aq) \rightarrow AgCl(s) + Ba(NO_3)_2(aq)\)

There are two Ag atoms on the right side and one on the left. It is possible to achieve equilibrium by adding 2 in front of \(AgNO_3\), as demonstrated below:

\(BaCl_2(aq) + 2 AgNO_3(aq) \rightarrow 2 AgCl(s) + Ba(NO_3)_2(aq)\)

2. Complete ionic equation

\(BaCl_2\) and \(AgNO_3\) will dissociate in solution as follows:

\(BaCl_2(aq) \rightarrow Ba^{2+}(aq) + 2Cl^-(aq)\)

\(AgNO_3(aq) \rightarrow Ag^+ (aq) + NO_3^-(aq)\)

\(Ba^{2+} (aq)+ 2Cl^- (aq) + 2 Ag^+ (aq) + 2NO_3^-(aq) \rightarrow2AgCl(s) + Ba^{2+}(aq) + 2 NO_3^-(aq)\)

3. Net ionic equation

To obtain the net ionic equation, cancel out the spectator ions, which are ions that appear on both sides of the equation. As an example, consider the following:

\(2Cl^-(aq) + 2Ag^+(aq) \rightarrow 2AgCl(s)\)

\(Cl^-(aq) + Ag^+(aq) \rightarrow AgCl(s)\)

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The pressure inside the canister at a campfire temperature of 1500°C is 0.227 atm

Given that the temperature of the campfire is 1500°C, the volume of the aerosol canister is 1500 milliliters, and the number of moles of gas in the canister is 3 moles.The ideal gas equation is given as PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is the absolute temperature of the gas in Kelvin.To convert 1500°C to Kelvin, we use the equation: T(K) = T(°C) + 273T(K) = 1500 + 273T(K) = 1773 KSubstitute the values given in the ideal gas equation:P = (nRT) / VWe are given n, R, V, and T, hence we substitute and solve for P as follows:P = (3 × 0.082 × 1773) / 1500P = 0.227 atm.It is not safe to put an aerosol canister in a campfire because the pressure inside the canister will increase at higher temperatures. If the pressure in the canister continues to increase beyond the safe limit, it can explode. Therefore, always keep aerosol canisters away from sources of high temperatures.

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Answer:

B

Explanation:

If AH and AS are both negative  will a low temperature make a reaction spontaneous.

A spontaneous reaction is a reaction that favors the formation of products at the conditions under which the reaction is occurring. A roaring bonfire (see figure below) is an example of a spontaneous reaction.

A fire is exothermic, which means a decrease in the energy of the system as energy is released to the surroundings as heat.

The products of a fire are composed mostly of gases such as carbon dioxide and water vapor, so the entropy of the system increases during most combustion reactions.

Therefore,  If AH and AS are both negative  will a low temperature make a reaction spontaneous.

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The charge on the ions in an ionic compound containing cobalt(III) and fluoride ions is Co³⁺ and F⁻¹ and the formula of the compound is CoF₃.

Ionic compounds are a type of chemical compound where the oppositely-charged ions of a metal and a nonmetal are attracted to each other to form an ionic bond.

The compound formed from the bonded ions will have very different properties from the elements that make up the compound.

While atoms are neutral because they have an equal number of protons and electrons, ions have a net charge and result when an atom loses or gains electrons.

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The Safety Data Sheet (SDS) for regular bleach can be obtained from the manufacturer or supplier of the specific brand or product. It contains important information regarding the hazardous properties, handling, storage, and emergency procedures related to the bleach.

An SDS typically includes details such as the product's chemical composition, physical and chemical properties, potential hazards to health and the environment, precautionary measures for safe handling and storage, first-aid procedures, and information about proper disposal. It also provides guidance on personal protective equipment (PPE) to be used when handling the product and steps to take in case of accidental release or exposure.

The SDS serves as a crucial resource for understanding the potential risks associated with the use of regular bleach and helps ensure that appropriate safety measures are implemented. It is important to review and follow the information provided in the SDS to minimize the risk of accidents, injuries, or adverse health effects associated with the use of the product.

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Answer:

The empirical formulae for the car fuel is C4H9

Answer:

neutral/no charge

Explanation: