how is carbon dioxide manufacture in the industry ​

Answer:

The given isotope is Br 80

If 35 protons present then its atomic number is 35

Mass number is 80 so its meutrons are 45 because proton+ neutron = mass number

Its electron are 36 because of negative one charge

Explanation:

The correct answer is d.) The masses of the two reactants cannot be added until they are each multiplied by their coefficient in the balanced equation.

This is because the law of conservation of mass only applies when the reactants and products are in their balanced equation form. In order to determine the total mass of a product, the law of conservation of mass states that the mass of the reactants must be multiplied by the coefficients of the reactants in the balanced equation. This is because the coefficients represent the amount of each reactant or product present in the reaction, and the total mass of the product must be equal to the total mass of the reactants. Therefore, the masses of the two reactants cannot be added until they are each multiplied by their coefficient in the balanced equation.

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The carburizing time necessary to achieve a carbon concentration of 0.30 wt% at a position 4 mm into an iron-carbon alloy is 63.4 hours.

To determine the carburizing time necessary to achieve a carbon concentration of 0.30 wt% at a position 4 mm into an iron-carbon alloy, we can use Fick's second law of diffusion:

\(DC_{surface} / 2 = (C_{surface} - C_{4mm}) / erf(x / (2 * \sqrt{Dt} ))\\\)

where D is the diffusion coefficient, \(C{surface}\\\) is the surface carbon concentration (0.90 wt%), C_4mm is the carbon concentration at the position 4 mm into the alloy (0.10 wt%), x is the distance from the surface (4 mm), and t is the carburizing time we want to find.

We can use the diffusion coefficient for γ-Fe at 1100°C from Table 5.2, which is D = \(6.0 * 10^{-12} m^2/s.\)

Substituting the given values, we get:

\((6.0 * 10^{-12} m^2/s) * (0.90 - 0.30) / 2 = (0.90 - 0.10) / erf(4 mm / (2 * \sqrt{6.0 * 10^{-12} m^2/s} ))\)

Simplifying the left-hand side, we get:

\(1.8 * 10^{-12} m^2/s = (0.80) / erf(4 mm / (2 * \sqrt{(6.0 * 10^{-12} m^2/s) * t)})))\)

Taking the inverse error function of both sides, we get:

\(erf(4 mm / (2 * \sqrt{6.0 * 10^{-12} m^2/s) * t)} ) = 0.000346\)

Substituting this back into the previous equation, we get:

\(1.8 * 10^{-12} m^2/s = (0.80) / 0.000346\)

Solving for t, we get:

t = 63.4 hours

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Answer:

c. 800.0 mL

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Here are the answers to your questions:

1. The amount of energy produced by 0.2 kg of the gaseous fuel is approximately 10,383 BTU.

2. The amount of energy produced by 2000 gallons of the gaseous fuel is approximately 79.54 MJ.

3. The specific gravity of the gas is approximately 0.559.

To calculate the energy produced, we need to consider the calorific values of each component in the gaseous fuel. The calorific value represents the amount of heat energy released when a specific amount of fuel is burned. Here are the calorific values for each component:

- CH₄ (Methane): 23,886 BTU/lb

- C₂H₆ (Ethane): 22,287 BTU/lb

- C₃H₈ (Propane): 21,474 BTU/lb

- C₄H₁₀ (Butane): 20,891 BTU/lb

First, we need to convert the given mass of 0.2 kg into pounds. Since 1 kg is approximately 2.2046 lbs, 0.2 kg is approximately 0.441 lbs. Now, we can calculate the energy produced by multiplying the mass of each component by its respective calorific value and then summing them up:

Energy produced = (0.441 lbs * 0.6 * 23,886 BTU/lb) + (0.441 lbs * 0.14 * 22,287 BTU/lb) + (0.441 lbs * 0.1 * 21,474 BTU/lb) + (0.441 lbs * 0.08 * 20,891 BTU/lb) = 10,383 BTU.

To calculate the energy produced by 2000 gallons of fuel, we need to convert gallons to pounds. Since 1 gallon of gaseous fuel weighs approximately 5.6 lbs, 2000 gallons weigh approximately 11,200 lbs. Using the same calculation as above, we can find the energy produced:

Energy produced = (11,200 lbs * 0.6 * 23,886 BTU/lb) + (11,200 lbs * 0.14 * 22,287 BTU/lb) + (11,200 lbs * 0.1 * 21,474 BTU/lb) + (11,200 lbs * 0.08 * 20,891 BTU/lb) ≈ 79.54 MJ.

To determine the specific gravity of the gas, we need to calculate the weighted average of the specific gravities of each component. The specific gravity of each component is as follows:

- CH₄ (Methane): 0.554

- C₂H₆ (Ethane): 1.04

- C₃H₈ (Propane): 1.52

- C₄H₁₀ (Butane): 2.01

Specific gravity = (0.6 * 0.554) + (0.14 * 1.04) + (0.1 * 1.52) + (0.08 * 2.01) ≈ 0.559.

Finally, to determine if 2000 m³ of the gaseous fuel with a calorific value of 53.26 MJ/m³ and a specific gravity of 0.9 produces the same volume of heat, we can calculate the energy produced:

Energy produced = 2000 m³ * 53.26 MJ/m³ ≈ 106,520 MJ.

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Answer:

phosphorus

Explanation:

Answer: The speed of the wave is 5.307 meters per second.

Explanation: The speed of a wave can be calculated using the equation:

speed = wavelength / period

Substituting the given values:

speed = 69 m / 13 s

Simplifying:

speed = 5.307 m/s

Answer:

Beryllium fluoride - BeF2

Barium fluoride - BaF2

Strontium sulfide - SrS

Titanium(II) chloride - TiCl2

Iron(II) sulfate - FeSO4

Vanadium(III) cyanide - V( CN )3

Answer:

Scientists must look in their experiment/data to check for accuracy because they don't want to make any mistakes, and most importantly have to make sure they have the right information to proceed.

Explanation:

^

The given statement "A hot plate is the only heat source available in the lab room to heat the hydrate in a crucible at least 2 times for 10-15 minutes at medium-high setting" is true because the water in hydrate can be removed by heating.

The crucible is the type of the laboratory glassware that is designed to melt or to burn the solid chemicals over the burner. Crucible is made from the heat resistant ceramic or the metal. The hot plates are the laboratory tools that is used for the  uniformly heat the samples. The hot plates are available with Varity of the  number of the different heating top styles.

Thus, the hot plate is the heating tool to heat the hydrate in the crucible.

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Answer: I hope this helps :

An element in Group 5 = Bismuth (Bi)

A halogen = Fluorine (F) or Astatine (At)

An alkali Metal = Lithium (L)

A metal in Group 6 = Selenium (Se) , Tellurium (Te) , Polonium (Po)

A gas made up of individual atoms = Argon (Ag)

An element that forms 1+ ions = Lithium

The most reactive element in Group 1 = francium (it doesn't appear in the image)

The most reactive element in Group 7 = Fluorine

An element that is a good catalyst= Iron (Fe) Cobalt (Co) , Nickel (Ni)

An element that does not react with anything  = Argon

A metal that floats on water = Lithium

An element with a full outer energy of electrons = Helium (He), neon (Ne), and argon (Ar)

A transition Metal = Iron (Fe) Cobalt (Co) , Nickel (Ni)

A noble gas = Argon (Ar)

The element in Group 6 , Period 5 =   Molybdenum , Tellurium

A non-metal = Fluorine , Argon

A gas made up of Diatomic molecule = Argon (Ar)

An element that forms 1- ions =

The Group 1 element with the highest melting point =  Lithium

The Group 7 element with the highest boiling point = Astatine (As)

An element with 3 electrons in it's outer energy level = Boron

An element that forms coloured compounds = Iron

An element that has a coloured vapour = Chlorine  Fluorine

A metal that can form ions with different charges = Iron, Cobalt , Lead

Explanation:

Halogen : Are any of the six nonmetallic elements that make up Group 17  of the periodic table e.g  fluorine (F), chlorine (Cl), bromine (Br), iodine (I), astatine (At).

All elements in Group 1 are Alkali metals( except hydrogen)

Examples :lithium (Li), sodium (Na), potassium (K), rubidium (Rb), caesium (Cs), and francium (Fr).

A pure gas may be made up of individual atoms (e.g. a noble gas like neon), elemental molecules made from one type of atom (e.g. oxygen)

Argon is one of the inert gases that normally exist as single atoms.

Transition metals are good metal catalysts because they easily lend and take electrons from other molecules. A catalyst is a chemical substance that,  does not affect the thermodynamics of a reaction but increases the rate of reaction.

Transition metals ; Scandium. Titanium. Vanadium. Chromium. Manganese. Iron. Cobalt. Nickel.

Noble gases(inert gases) don't react with anything . The family of noble gases includes helium, neon, argon, krypton, xenon, and radon.

Lithium is the lightest metal and has density about half of water.

Group 18 elements (helium, neon, and argon are shown) have a full outer, or valence, shell.

chlorine, fluorine, carbon, nitrogen, arsenic, phosphorus, selenium are examples of non-metal.

Noble gases : helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn).

The following 5 element gases are found as diatomic molecules at room temperature and pressure:

Hydrogen – H. ...

Nitrogen – N. ...

Oxygen – O. ...

Fluorine – F. ...

Chlorine – Cl.

Lithium, Li melts at 180°C.

From the lowest boiling and melting point to the highest, the group in order is fluorine, chlorine, bromine, iodine and astatine.

Like other transition metals, iron forms coloured compounds. The table shows some examples of these. Note that iron can form two different ions in its compounds. Iron(II) compounds contain the Fe 2+ ion and iron(III) compounds contain the Fe 3+ ion.

Elements in group seven(Halogens)  : As you move down the group the halogens become darker in colour. For example fluorine is a very pale yellow whereas iodine will be dark purple in colour when it is in a vapour state.

A few elements, all metals, can form more than one possible charge. For example, iron atoms can form 2+ cations or 3+ cations. Cobalt is another element that can form more than one possible charged ion (2+ and 3+), while lead can form 2+ or 4+ cations.

The standard cell potential (E°cell) for the given equation is -2.107 V. The negative sign indicates that the reaction is not spontaneous under standard conditions.

To calculate the standard cell potential (E°cell) for the given equation, we need to look up the standard reduction potentials (E°red) for the half-reactions involved and use the following formula:

E°cell = E°red(cathode) - E°red(anode)

The half-reactions are:

Zn(s) → Zn2+(aq) + 2e- E°red = -0.763 V

F2(g) + 2e- → 2F-(aq) E°red = +2.87 V

To use the formula, we need to reverse the first half-reaction and flip its sign to obtain the oxidation half-reaction:

Zn2+(aq) + 2e- → Zn(s) E°red = +0.763 V

Now we can substitute the values into the formula:

E°cell = E°red(cathode) - E°red(anode)

= +0.763 V - (+2.87 V)

= -2.107 V

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The correct name of the compound CuCl is copper I chloride.

An ionic compound is formed two atoms when one loose electrons and the other atoms gains those electrons. Ionic bonds are actually an ion pair, a pair of oppositely charged ions held together by electrostatic interaction. Transition metals are elements with incompletely filled d orbitals. Copper is a transition element.

The compound CuCl is named copper I chloride. We can see that the copper is in the +1 oxidation state in this compound hence the name.

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Answer:

copper(I) chloride

Explanation:

Edge 2021

This problem is describing a reaction whereby aluminum oxide and iron metal are produced from iron (II) oxide and aluminum metal. Since the question is not specific, it is assumed the reaction should be written and also balanced as follows:

In chemistry, a chemical equation is used to represent a chemical reaction in which the reactants undergo a chemical change to yield specific products. Both sides are separated by a right-pointed arrow and the phase of each substance must be specified as well as balanced according to the law of conservation of mass, which demands the number of atoms to be the same before and after the reaction.

Here, in this problem, we can start by writing the reaction according to the given description:

\(Al(s)+FeO(s)\rightarrow Al_2O_3(s)+Fe(s)\)

However, it is not initially balanced because unequal number of atoms of aluminum and oxygen are present on both sides of the equation. In such a way, to overcome the aforementioned, we set a 2 on Al, a 3 on FeO and a 3 on Fe to obtain:

\(2Al(s)+3FeO(s)\rightarrow Al_2O_3(s)+3Fe(s)\)

Which now is abided by the law of conservation of mass.

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Answer:

The vascular system, also called the circulatory system, is made up of the vessels that carry blood and lymph through the body. The arteries and veins carry blood throughout the body, delivering oxygen and nutrients to the body tissues and taking away tissue waste matter.

Explanation:

First nations people along the west coast of British Columbia used smelting technology to create copper plaques is false.

Smelting process is the form of extractive metallurgy to produce a metal from its ore. it is the process of melting and separation of charges .  it is extensive energy process. Plaques are made by pouring molten metal in to a mold. and when it gets cools , it solidified into a copper solid plaque. first nation people use copper as hunting weapons, spear tools etc. copper is metal.

Thus, First nations people along the west coast of British Columbia used smelting technology to create copper plaques is false.

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Answer:

[HI] = 0.0255M

[H₂] = 0.00466M

[I₂] = 0.00257M

Explanation:

Para la reacción:

H₂(g) + I₂(g) ⇄ 2HI(g)

La constante de equilibrio, K, se define como:

54.3 = [HI]² / [H₂] [I₂]

Donde cada concentración [] será la concentración en equilibrio para cada especie

Para saber la dirección del equilibrio definiremos Q como:

Q = [HI]² / [H₂] [I₂]

Donde las concentraciones [] serán las concentraciones actuales de cada gas

Reemplazando:

Q = [0.0224M]² / [0.00623M] [0.00414M]

Q = 19.5

Como Q<K, la reacción se desplazará hacia la derecha produciendo más [HI]. Así, las concentraciones en equilibrio serán:

[HI] = 0.0224M +2X

[H₂] = 0.00623M - X

[I₂] = 0.00414 - X

54.3 = [0.0224M +2X]² / [0.00623M - X] [0.00414M - X]

54.3 = 0.00050176 + 0.0896 X + 4 X² / 0.0000257922 - 0.01037 X + X²

0.00140052 - 0.563091 X + 54.3 X² =  0.00050176 + 0.0896 X + 4 X²

0.00089876 - 0.652691 X + 50.3 X² = 0

Resolviendo la ecuación cuadrática:

X = 0.001566M → Solución verdadera

X = 0.01141M → Falsa solución. Produciría concentraciones negativas

Reemplazando:

[HI] = 0.0224M +2*0.001566M

[H₂] = 0.00623M - 0.001566M

[I₂] = 0.00414 - 0.001566M

[HI] = 0.0255M

[H₂] = 0.00466M

[I₂] = 0.00257M

Siendo estas últimas, las concentraciones de las especies luego de alcanzar el equilibrio.

A scientific law is different from a scientific theory because it describes something in nature without attempting to explain it, this statement is true.

A scientific law foretells the outcomes of particular beginning circumstances. It may tell you what color hair your unborn kid would have or how far a baseball will go when fired at a specific angle.In contrast, a theory seeks to offer the best plausible justification for why events take place the way they do.

A scientific law often describes an observable phenomena. It doesn't explain the phenomenon's existence or its origins. A scientific theory is the explanation for a phenomena. It is untrue that with enough study, hypotheses become laws.

Thus, a scientific law is different from a scientific theory because it describes something in nature without attempting to explain it, this statement is true.

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Answer:

D i belive

Explanation:

Total, 41.46 grams of sulfuric acid (H₂SO₄) would be required to react completely with 7.6 grams of aluminum (Al) in the given reaction.

Balanced chemical equation for the reaction between aluminum (Al) and sulfuric acid (H₂SO₄) is;

2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂

From the balanced chemical equation, we can see that 2 moles of aluminum (Al) react with 3 moles of sulfuric acid (H₂SO₄) to produce 1 mole of aluminum sulfate (Al₂(SO₄)₃) and 3 moles of hydrogen gas (H₂).

First, we need to calculate the molar mass of aluminum (Al) and sulfuric acid (H₂SO₄) from the periodic table;

Molar mass of Al = 26.98 g/mol

Molar mass of H₂SO₄ = 2 x (1.01 g/mol) + 32.07 g/mol + 4 x (16.00 g/mol) = 98.08 g/mol

Now, we can use the given mass of aluminum (7.6 g) and its molar mass (26.98 g/mol) to calculate the moles of aluminum;

moles of Al = mass of Al / molar mass of Al = 7.6 g / 26.98 g/mol ≈ 0.2817 moles

Since 2 moles of aluminum (Al) react with 3 moles of sulfuric acid (H₂SO₄), the number of moles of sulfuric acid (H₂SO₄) required is;

moles of H₂SO₄ = (3/2) x moles of Al = (3/2) x 0.2817 moles ≈ 0.4226 moles

Finally, we can calculate the mass of sulfuric acid (H₂SO₄) required using its molar mass (98.08 g/mol);

mass of H₂SO₄ = moles of H₂SO₄ x molar mass of H₂SO₄ = 0.4226 moles x 98.08 g/mol

≈ 41.46 g

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This equation shows that when hydrochloric acid (HCl) reacts with calcium hydroxide (Ca(OH)2), calcium chloride (CaCl2) and water (H2O) are produced.

Therefore, the H2O component in the reaction can be described as 2 molecules of water (2H2O), as shown in the balanced equation. Option A, "2 molecules H2O", is the correct way to describe the H2O component in the reaction.

2HCl(aq) + Ca(OH)₂ (aq) ⇒ A. 2 molecules H₂O B.

Option B, "1 molecule H2O", is incorrect as two molecules of water are produced in the reaction, not one.

Option C, "2 LH2O", is also incorrect as the symbol "L" is not used to represent water molecules in chemical equations.

Option D, "4 moles H2" is also incorrect as hydrogen gas (H2) is not produced in this reaction.

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Answer:

20 degrees Celsius

Explanation:

To find the final temperature at thermal equilibrium, we can use the principle of conservation of energy. The heat lost by gold is equal to the heat gained by water. The heat lost by gold can be calculated using the formula: q = m * c * ∆T, where q is the heat lost, m is the mass of gold, c is the specific heat capacity of gold, and ∆T is the change in temperature.

The heat gained by water can be calculated using the same formula, but with the mass and specific heat capacity of water.Setting these two equations equal to each other, we can solve for the final temperature.

Using the given values:
m(gold) = 31.5 g
m(water) = 63.3 g
c(gold) = 0.128 J/(g⋅∘C)
c(water) = 4.18 J/(g⋅∘C)
∆T(gold) = T(final) - 69.9 ∘C
∆T(water) = 26.9 ∘C - T(final)
Solving the equation gives the final temperature of both substances at thermal equilibrium.

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Carbon dioxide molecules can absorb and emit infrared radiation, and they are one of the most abundant constituents of Earth's atmosphere.

Thus, the correct options are:d) Are one of the most abundant constituents of Earth's atmospheree) Can move in many ways, thus absorbing and emitting infrared radiation

Carbon dioxide is a trace gas present in the Earth's atmosphere. It's a vital component of Earth's carbon cycle, which helps to regulate Earth's temperature and support life as we know it. Carbon dioxide molecules are one of the most common gases in the atmosphere, accounting for around 0.04% of the Earth's atmosphere.

The greenhouse effect is caused by carbon dioxide, methane, and other greenhouse gases. When the Sun's energy reaches the Earth's surface, it is absorbed and then radiated back into space as infrared radiation. Greenhouse gases absorb this radiation and trap it in the atmosphere, which causes the Earth's temperature to rise and the climate to change.

Carbon dioxide molecules are capable of absorbing and emitting infrared radiation due to their molecular structure, which consists of one carbon atom and two oxygen atoms. This property of carbon dioxide is the main reason it's classified as a greenhouse gas.

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Answer:

In which organ would you expect the contents of food to be more ground up? (Gizzard)

These external structures are the penis, scrotum, epididymis, and testes. The internal organs of the male reproductive system are called accessory organs. ... To discharge sperm within the female reproductive tract.

We can use the formula:

M1V1 = M2V2

where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

In this case, we know:

M1 = 12.0 M

V1 = ?

M2 = 0.100 M

V2 = 500.0 mL = 0.500 L (since 1 mL = 0.001 L)

We can rearrange the formula to solve for V1:

V1 = (M2V2) / M1

Substituting the values we know, we get:

V1 = (0.100 M)(0.500 L) / 12.0 M

V1 = 0.00417 L = 4.17 mL

Therefore, we need to measure 4.17 mL of 12.0 M hydrochloric aqueous solution and add it to 500.0 mL of water to prepare 500.0 mL of a 0.100 M diluted solution.

1) Chemical formula

2) Mg Lewis structure

3) O2 Lewis structure

4) MgO Lewis structure

5) Chemical formula written as Lewis dot structure

.

Answer:

They are irreversible

Explanation:

This is because it cannot be separated by physical means

Answer:

are you a kid bruh xd

Explanation:

H2O

Answer:

\(\huge\boxed{H_{2}O}\)

Explanation:

Water is made up of two elements => Hydrogen and Oxygen

There are two hydrogen and one oxygen

So,

The chemical formula for water is:

=> H₂O