How fast can the new Bugatti Deron go.

Answer:

60 kg m/s

Explanation:

F= Force = 6 N

m = Mass of object = 3 kg

u = Initial velocity = 15 m/s

t = Time = 10 s

v = Final velocity

\(\Delta p\) = Change in momentum

Force is given by

\(F=\dfrac{\Delta p}{t}\\\Rightarrow Ft=\Delta p\\\Rightarrow \Delta p=6\times 10\\\Rightarrow \Delta p=60\ \text{Ns}\)

The change in  momentum of the object is 60 kg m/s.

Answer:

Explanation:

Polar coordinates formula

Summary. To convert from Polar Coordinates (r,θ) to Cartesian Coordinates (x,y) : x = r × cos( θ ) y = r × sin( θ )

The energy level from which is emitted is n = 6

The frequency is\(7.3 * 10^14\) Hz

The Rydberg equation is a mathematical formula that relates the wavelengths of light emitted by an atom to the energy levels of its electrons.

Using the Rydberg equation;

1/λ= RH (1/\(n_{2}^2\) - 1/\(n_{1} ^2\))

1/\(410.2 * 10^-9\) = \(1.097 * 10^7\)(1/\(2^2\) - 1/  /\(n_{1} ^2\))

1/\(4.102 * 10^-7\) = \(1.097 * 10^7\)(1/4 - 1/\(n_{1} ^2\))

1/\(4.102 * 10^-7\) * 1/ \(1.097 * 10^7\) = (1/4 - 1/\(n_{1} ^2\))

0.22 = 0.25 -  1/\(n_{1} ^2\)

0.22 - 0.25 = -  1/\(n_{1} ^2\)

-0.03 = -  1//\(n_{1} ^2\)

\(n_{1}\) = 6

Using;

f = c/λ

\(3 * 10^8/4.102 * 10^-7 \\f = 7.3 * 10^14 Hz\)

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The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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Answer:

spirit of the team / game

The amount of work done on the toboggan by the tension force of 105 N with a rope directed 32° above the snow is 3.12 KJ

W = F d cos θ

W = Work done

F = Force

d = Distance

θ = Angle between force and displacement vector

d = 35 m

F = 105 N

θ = 32°

W = 105 * 35 * cos 35°

W = 105 * 35 * 0.85

W = 3123.75 N m

W = 3.12 KJ

Work done is energy transferred to make an object move to a distance. Its unit is Joules which is denoted as J. It is the amount of work done by a force of 1 Newton to move a distance of 1 meter.

Therefore, the amount of work done on the toboggan by the tension force is 3.12 KJ

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Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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The work can be seen as a transfer of energy, and can be calculated with the formula below:

Where W is the work in Joules, F is the force in Newtons and d is the distance in meters.

When we have a positive work, that means the body or system is using its own energy and force to move a certain distance, for example.

A negative work means the system is receiving energy from an external source.

Therefore the statement is TRUE.

The distance traveled by the elevator is 2.0136 m.

Given values: Mass, m = 602 kg. Initial velocity, u = 0 m/s. Time taken, t = 2.60 s. Final velocity, v = 1.72 m/s.(a) Find the acceleration of the elevator. The formula to calculate the acceleration is given below:

a = (v - u)/t Substitute the given values in the above equation and get the acceleration value.

a = (1.72 - 0)/2.60a = 0.6615 m/s²Therefore, the acceleration of the elevator is 0.6615 m/s².

(b) Find the distance traveled by the elevator. The formula to calculate the distance is given below:

s = ut + 1/2at²Substitute the given values in the above equation and get the distance traveled by the elevator.

s = 0(2.60) + 1/2(0.6615)(2.60)²s = 2.0136 m.

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For a spacecraft is traveling with a velocity of Vox-5690 m/s:

To solve this problem, use the equations of motion to calculate the final velocity and the vertical component of the velocity. Assume that the initial velocity in the y-direction is zero.

Given:

Initial velocity in the x-direction (V₀ₓ) = -5690 m/s

Time of engine firing (t) = 865 s

Acceleration in the x-direction (ax) = 1.45 m/s²

Acceleration in the y-direction (ay) = -8.66 m/s²

(a) To calculate the final velocity (v), use the equation:

v = V₀ₓ + ax × t

Substituting the values:

v = -5690 m/s + 1.45 m/s² × 865 s

v = -5690 m/s + 1254.25 m/s

v ≈ 685.25 m/s

Therefore, the final velocity (v) is approximately 685.25 m/s.

(b) To calculate the vertical component of the velocity (vy), use the equation:

vy = ay × t

Substituting the values:

vy = -8.66 m/s² * 865 s

vy = -7484.9 m/s

Therefore, the vertical component of the velocity (vy) is -7484.9 m/s.

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Answer:

a)40 meters

b)2 m/s

c)2 m/s

d)0 m/s

e)45 degrees northeast

Explanation:

a) The displacement from C to A is the distance directly across the river, which is 40 meters.

b) The speed of the boat as seen by people standing at A is the magnitude of the boat's velocity vector, which is equal to the displacement divided by the time taken:

Speed = displacement / time = 40 m / 20 s = 2 m/s.

c) Let v be the speed of the water in the river. The boat is moving at right angles to the flow of the river, so the water exerts a perpendicular force on the boat. The time taken for the boat to travel from A to C is 20 seconds, during which time the boat will have been carried downstream by the river by a distance equal to v times the time taken.

Distance carried downstream = v × time = v × 20 m.

Since the boat landed at C, which is directly across the river from A, the distance it traveled horizontally is 40 meters. Therefore:

40 m = (boat speed) × (time taken) = (boat speed) × 20 s.

Hence, the speed of the boat is:

Boat speed = 40 m / 20 s = 2 m/s.

So, we have two equations:

Distance carried downstream = v × 20 m

Boat speed = 2 m/s

From the first equation, we get:

v × 20 m = 40 m

Therefore, the speed of the water in the river is:

v = 40 m / 20 m = 2 m/s.

d) The speed of the boat as seen by a fish drifting with the river is the difference between the speed of the boat and the speed of the water in the river:

Boat speed - Water speed = 2 m/s - 2 m/s = 0 m/s.

So, the speed of the boat as seen by a fish drifting with the river is zero.

e) The boat should head in a direction that makes its velocity vector point directly from A to B. Since A and B are directly opposite each other, this means the velocity vector should be perpendicular to the line connecting A and B.

We know the boat's velocity vector has a magnitude of 2 m/s and is at right angles to the velocity vector of the water in the river, which has a magnitude of 2 m/s. So, we can draw a vector diagram with the velocity vector of the boat pointing straight up and the velocity vector of the water pointing straight to the right. The vector connecting the tail of the water velocity vector to the head of the boat velocity vector will then point directly from A to B.

The angle between the boat's velocity vector and the line connecting A and B can be found using trigonometry. Let θ be this angle. Then:

tan(θ) = (boat speed) / (water speed) = 2 m/s / 2 m/s = 1.

Taking the inverse tangent of both sides gives:

θ = tan^(-1)(1) = 45°.

So, the boat should head in a direction 45 degrees to the right of straight up, or northeast.

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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Yes it can, an object can be moving a certain direction while the ACCELERATION is in the opposite direction.

Lets say your riding a bike... if your squeezing your handle bar breaks, the acceleration of the bike would be pushing in the opposite direction of the direction the bike is moving.

Hope this helped!

Answer: Endothermic  Reaction

Explanation: Photosynthesis requires energy right, making it an endothermic reaction. Light, generally sunlight, is the source of this energy. The process converts the sun's electromagnetic energy into chemical energy, which is then stored in chemical bonds in the plant. Which then leads to Photosynthesis occuring.

Acceleration of an object down a slope increases as the angle of the slope is increased

(a) The ball that arrives at the end first is ball A

(b) Racing cyclist select areas having a steeper slope on a hill that gives them a velocity boost

Reason:

A drawing to clarify the explanation and to represent the possible drawing of figure 3 in the question is attached

The acceleration of the balls on the inclined plane is given by the following formula;

Force, F = m·g·sin(θ)

Therefore, the acceleration, a, of ball A and ball B at the part having the same slope are equal

The acceleration of ball A at the part of its track that is almost vertical is approximately, g, (acceleration due to gravity). The velocity at the end of the drop is u' = v + g·Δt, therefore;

(b) The principle is applied by racing cyclist by selecting a steeper path that gives them a velocity boost much larger than what is being normally applied, by the force applied by pedaling

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.............................................

Answer:

no..

Explanation:

in balanced force it will or in this case u would stay still or u would move at the same speed.. but when u jumps the speed changes..so this is an unbalanced force

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The kinetic energy of the racing car is approximately 849952.4 J joules.

Kinetic energy is simply a form of energy a particle or object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Convert the speed from kilometers per hour to meters per second since the units of mass and velocity need to be consistent.

We know that 1 km/h = 0.27777 m/s, so:

120 km/h x (0.27777 m/s/km/h) = 33.3336 m/s (rounded to 4 decimal places)

Now we can substitute the values into the formula:

Kinetic Energy = (1/2) × 1530 kg x (33.3336 m/s)²

Kinetic Energy = 849952.4 J

Therefore, the kinetic energy is approximately 849952.4 joules.

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Answer:

Explanation:

Ginen:

m₁ = 200 kg

F₂ = 400 N

g ≈ 10 m/s²

__________

R - ?

F₁ = m₁·g = 200· 10 = 2000 N

R = √ (F₁² + F₂²) = √ ( 2000² + 400²) ≈ 2040 N

The net force acting on the refrigerator having a mass of 200 kg and the applied force to 400 n (to the right) is 2040 Newtons.

Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.

Newton is a unit of force used by physicists that is part of the International System (SI). The force required to move a body weighing one kilogram one meter per second is known as a newton.

Given:

The mass of the refrigerator, m = 200 kg,

The force, F = 400 N,

Calculate the net force by the formula given below,

F = m × g

here, g is the gravitational acceleration.

Substitute the values,

F= 200 × 10 = 2000 N

\(R = \sqrt{F_1^2 +F_2^2}\)

where R is the net force

\(R = \sqrt{2000^2 +400^2}\)

R  = 2040 Newton

Therefore, the net force acting on the refrigerator having a mass of 200 kg and the applied force to 400 n (to the right) is 2040 Newtons.

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Answer:(vi^2+d)^2=vf+a^2+2t

Explanation:

Answer:

A ant farm

Explanation:

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer: Newton's law of universal gravitation states that every point mass in the universe attracts every other point mass with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

Explanation:

Although it is true that scientific models and hypotheses have been updated and improved over time, this is not sufficient justification to reject science as a whole or to doubt what scientists claim.

Models aid in our comprehension of systems and their characteristics. An atomic model, for instance, depicts what an atom's structure may like based on what is known about how atoms function. It may not accurately represent the precise makeup of an atom. Models are frequently condensed.

Over time, this atomic model has evolved. The model was used by scientists to make predictions. Their trials occasionally yielded unexpected outcomes that did not match the pre-existing model. The model was modified by scientists so that it could account for the fresh data.

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Answer:

An isothermal process is a change of a system, in which the temperature remains constant: ΔT = 0.

Explanation:

:)

Answer:

A.) 355 m/s

B.) 0.71 m

C.) 500Hz

Explanation:

Given that a police car is traveling due east at a speed of 15.0 m/s relative to the earth. You are in a convertible following behind the police car. Your car is also moving due east at 15.0 m/s relative to the earth, so the speed of the police car relative to you is zero. The siren of the police car is emitting sound of frequency 500 Hz. The speed of sound in the still air is 340 m/s

a.) What is the speed of the sound waves relative to you?

Since the car is moving away from the observer, the relative velocity will be:

Relative velocity = 340 + 15

Relative velocity = 355 m/s

b.) What is the wavelength of the sound waves at your location?

Using the wave speed formula

V = frequency × wavelength

Make wavelength the subject of formula.

Wavelength = Velocity / frequency

Wavelength = 355/500

Wavelength = 0.71 m

c.) What frequency do you detect?

Fo = Fs ( C + V ) / ( C + v )

Fo = Fs

That is, the frequency of the observer will be equal to the frequency of the source.

Therefore, Fo = 500Hz

(a) The position-time equations for fishing boat is x = 3.4t + 40.8

(b) The time taken for the speedboat to catch up with the fishing boat is 7.1 seconds.

The position-time equations for fishing boat will be obtained by applying the principle of relative velocity as follows;

Let the time when the speedboat catches up = t

let the total time spent by fishing boat = t + 12

x = 3.4(t + 12)

x = 3.4t + 40.8

fishing boat is moving at a constant speed = 3.4 m/s

speed boat started moving 12 seconds later,

distance between the boats = 3.4 m/s  x 12 s = 40.8 m

v = u + at

v = 2.8 + 1.7t

set up the following equation to determine the time when the two boats meet.

vt - x = 40.8

t(2.8 + 1.7t) -  (3.4t + 40.8) = 40.8

2.8t + 1.7t² - 3.4t - 40.8 = 40.8

1.7t² - 0.6t  - 81.6 = 0

solve the quadratic equation using formula method as shown below;

a = 1.7, b = -0.6, c = -81.6

t = 7.1 seconds

Thus, the time taken for the speedboat to catch up with the fishing boat is 7.1 seconds.

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Take "to the right" to be the positive direction. By conservation of momentum,

m₁v₁ + m₂v₂ = m₁(v')₁ + m₂(v')₂

where the v-s denote initial velocities and the v'-s denote final velocities. m₁ and m₂ are of course masses, but we're told that m₁ = m₂, so we can eliminate these factors altogether:

v₁ + v₂ = (v')₁ + (v')₂

We're given that v₁ = +4.0 m/s, (v₁)' = -1.5 m/s, and (v')₂ = +4.0 m/s.

Solve for v₂ :

v₁ + v₂ = (v')₁ + (v')₂

4.0 m/s + v₂ = -1.5 m/s + 4.0 m/s

⇒   v₂ = -1.5 m/s