It is the speed\(V=c×\sqrt{1-1/nx^{2} }\),far does an emperor ship have to sail in relation to an observer before its markings get confused
What is an easy way to define velocity?A particle or object's movement with function of time is expressed vectorially as velocity. The meter per second (m/s), usually referred to as speed, is the accepted unit of velocity magnitude. velocity
What distinguishes acceleration from speed?Velocityy a displacement changes. Speed changes occur at an accelerated rate. Given that it has both and direction, it is a vector quantity. As the rate about which velocity changes, acceleration is likewise a vector quantity.
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A. A wire of diameter 2.8mm supports a weight W. If the tensile stress in the wire is 2 x 10⁷Nmˉ². Find the value of W )
Answer:
The weight supported by the wire is 123.15 N
Explanation:
Given;
tensile stress in the wire, τ = 2 x 10⁷ Nm⁻²
diameter of the wire, d = 2.8 mm
radius of the wire, r = 1.4 mm = 1.4 x 10⁻³ m
The area of the wire is calculated as;
\(A = \pi r^2\\\\A = \pi (1.4 \times 10^{-3})^2\\\\A = 6.158 \times 10^{-6} \ m^2\)
The weight supported by the wire is calculated as;
W = F = τ x A
W = (2 x 10⁷ Nm⁻²) X (6.158 x 10⁻⁶ m²)
W = 123.15 N
Therefore, the weight supported by the wire is 123.15 N
The elevator moved from the 15th floor to the 10th floor at a constant speed. does the PE and KE increase, decrease, or stay constant?
As the elevator is moved from 15th floor to the 10th floor at a constant speed. It means that the height is decreasing but the speed of the elevator is moved at a constant.
It results that the kinetic stays the same but the potential energy is decreasing.
Two asteroids of equal mass in the asteroid belt between Mars and Jupiter collide with a glancing blow. Asteroid A, which was initially traveling at 40.0 m/s, is deflected 30 degrees from its original direction, while asteroid B, which was initially at rest, travels at 45 degrees to the original direction of A.
(a) Find the speed of each asteroid after the collision.
(b) What fraction of the original kinetic energy of asteroid A dissipates during this collision?
To solve this problem, we can apply the principles of conservation of momentum and conservation of kinetic energy.
(a) Find the speed of each asteroid after the collision:
1. Conservation of momentum:
Before the collision, the total momentum of the system is zero since asteroid B is initially at rest. After the collision, the total momentum of the system is still zero.
Let's assume the mass of each asteroid is m.
Before the collision:
Momentum of asteroid A = mass of asteroid A × velocity of asteroid A = m × 40.0 m/s
After the collision:
Momentum of asteroid A = mass of asteroid A × velocity of asteroid A (final)
Momentum of asteroid B = mass of asteroid B × velocity of asteroid B
Since the total momentum is conserved:
(m × 40.0 m/s) + (m × 0) = (m × velocity of asteroid A (final)) + (m × velocity of asteroid B)
Simplifying the equation:
40.0 = velocity of asteroid A (final) + velocity of asteroid B
2. Conservation of kinetic energy:
The initial kinetic energy of the system is given by:
Initial kinetic energy = (1/2) × mass of asteroid A × (velocity of asteroid A)^2
The final kinetic energy of the system is given by:
Final kinetic energy = (1/2) × mass of asteroid A × (velocity of asteroid A (final))^2 + (1/2) × mass of asteroid B × (velocity of asteroid B)^2
Since the collision is not perfectly elastic, some of the initial kinetic energy is lost. Therefore, the final kinetic energy will be less than the initial kinetic energy.
(b) What fraction of the original kinetic energy of asteroid A dissipates during this collision:
The fraction of the original kinetic energy dissipated is given by:
Fraction dissipated = (Initial kinetic energy - Final kinetic energy) / Initial kinetic energy
Now, let's calculate the values:
(a) To find the speed of each asteroid after the collision:
From the conservation of momentum:
40.0 = velocity of asteroid A (final) + velocity of asteroid B
From the given angles, we can use trigonometry to relate the velocities of the asteroids:
velocity of asteroid A (final) = velocity of asteroid A × cos(30°)
velocity of asteroid B = velocity of asteroid A × sin(30°) / sin(45°)
Substituting the trigonometric expressions into the momentum equation:
40.0 = velocity of asteroid A × cos(30°) + velocity of asteroid A × sin(30°) / sin(45°)
Now, we solve this equation to find the values of velocity of asteroid A (final) and velocity of asteroid B.
(b) To find the fraction of the original kinetic energy dissipated:
Calculate the initial kinetic energy using:
Initial kinetic energy = (1/2) × mass of asteroid A × (velocity of asteroid A)^2
Calculate the final kinetic energy using:
Final kinetic energy = (1/2) × mass of asteroid A × (velocity of asteroid A (final))^2 + (1/2) × mass of asteroid B × (velocity of asteroid B)^2
Finally, use the formula:
Fraction dissipated = (Initial kinetic energy - Final kinetic energy) / Initial kinetic energy
Performing these calculations will give you the specific values for the speeds of the asteroids after the collision and the fraction of the original kinetic energy dissipated.
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A uniform steel girder of weight 22KN and of length 12m is lifted off the ground at one end by means of a crane. When the raised end is 2.0m above the ground, the cable is vertical.
A. Sketch a free-body diagram of the girder in this position
b. Calculate the tension in the cable at this position and the force of the girder on the ground
Answer:
Explanation:
For free body diagram see attached sheet .
W is weight of steel girder acting at the middle point of its length . T is tension in the cable .
OB = √ ( 12² - 2² )
= 11.83 m .
OC = 11.83 / 2 = 5.915 m
Taking moment of tension T and weight W about point O
W x OC = T x OB
22 x 5.915 = T x 11.83
T = 22 x 5.915 / 11.83
= 11 kN
Considering forces acting in vertical direction and equating forces in opposite direction
T + R = W
R = W - T
= 22 - 11 = 11 KN
So force of grinder on the ground = R
= 11 KN.
What would the pressure and the temperature have been if the process had been isentropic? Assume the γ of Nitrogen is 1.40
The given data is gamma(γ) of Nitrogen is 1.4. We are supposed to find the pressure and temperature if the process had been isentropic. Let's first define the term "isentropic". An isentropic process is one that occurs without any entropy change, i.e., ΔS=0. In other words, it is a reversible adiabatic process.
Here, in this question, we need to find out the pressure and the temperature of Nitrogen if the process had been isentropic. We can make use of the below formula to find out the pressure of Nitrogen in the given process::For any isentropic process, we have the following relation: PV^γ= constantwhere,
γ = Ratio of specific heatsP
= Pressure of the gasV
= Volume of the gasNow, let's assume the final temperature is T2. Then the final pressure can be written as: P2
= P1 (V1/V2)^γ... (i)Similarly, let's assume the final temperature is T2.
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20.0 m [N] - 15 m [S20degreesE]
Answer:
thank for making me give up on life
Explanation:
I thought the stuff I had was hard wth is even that
An object is moving along a straight line. The graph shows the velocity of the object over
time.
What is the instantaneous acceleration of the object at time = 9.5 seconds?
A.-20 m/s2
B.0 m/s2
C.20 m/s2
D.-10 m/s2
Answer:
From 9 to 10 sec the velocity is decreasing at a constant rate.
Change in V = 20 m/s - 30 m/s = -10 m/s
Since acceleration is constant from point E to point F (straight line)
and t = 9.5 sec is on this line
a = (20 m/s - 30 m/s) / 1 sec = -10 m/s^2
The instantaneous acceleration of the object at time = 9.5 seconds is - 10 m/s².
What is acceleration?Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.
From t = 9 second to t =10 second the velocity of the object decreases at a constant rate.
Change in velocity of the object = final velocity - initial velocity
= 20 m/s - 30 m/s
= -10 m/s
time interval is = 10 sec - 9 sec = 1 sec.
Hence, acceleration of the object is: a = Change in velocity/ time interval
= - 10 m/s/1s
= -10 m/s²
Therefore, the instantaneous acceleration of the object at time = 9.5 seconds is - 10 m/s².
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Two stars are of equal luminosity. Star A is 3 times as far from you as star B. Star A appears _________ star B. Choose one: A. 3 times brighter than B. 9 times brighter than C. one-third as bright as D. the same brightness as E. one-ninth as bright as
The brightness of a star increases as it becomes bigger. It stands to reason that a larger star would have a larger surface. The larger surface area allows for the emission of more light and energy. The temperature of a star also affects its luminosity. Thus option E is correct.
What is the equal luminosity of stars?The amount of light emitted from a star's surface, on the other hand, is referred to as brightness. The relationship between apparent brightness and luminosity changes with distance.
The size and effective temperature of a star can be used to calculate its brightness. The former is often expressed in terms of solar radii, whilst the latter is typically expressed in kelvins, but neither is typically physically measurable.
Therefore, 1/9 as bright. So it must appear fainter. Since brightness scales as 1/d^2 it will appear 3^2=9 times fainter.
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A force of 20 N acts over an area of 2 m2. What is the pressure?
\(\text{Given that,}\\\\\text{Force, F = 20 N.} ~ \\\\ \text{Area , A = 2 m}^2 . \\\\ \text{Pressure, P =? }\\\\P = \dfrac FA = \dfrac{20}2 = 10~~ \text{Nm}^{-2}\)
An athlete from your school's cross country team goes for a training
run. she runs 3.6 km east, 4.5 km north, then another 2.4 km east. at the
end of her run, how far is the athlete from her starting position?
(remember, you can rearrange the vectors to make a right triangle and
use pythagorean theorem).
2.4 km
4.5 km
- 3.6 km
The athlete is 7.5 km North east from the starting point.
Consider the athlete's starting point as A. After running 3.6 km east from A, consider the point as B. After running 4.5 km north from B, consider the point as C. After running 2.4 km from C, consider the point as D.So the distance from starting point to ending point is AD.Total distance travelled east is 3.6 + 2.4 = 6 kmTotal distance travelled east is 4.5 kmThis forms a right angled triangle, where AD is the hypotenuse and the distance travelled east and north are the other two sidesAccording to Pythagoras theorem,
\(AD^{2}\) = \(6^{2}\) + \(4.5^{2}\)
AD = √ 36 + 20.25
AD = √ 56.25
AD = 7.5 km
Therefore, the athlete is 7.5 km North east from the starting point.
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What does the pressure at a point in a fluid depend on? Select all that apply: The depth of that point within the fluid. The pressure at the fluid's surface. The density of the fluid: The weight of the fluid directly above that point
The depth of that point within the fluid, the pressure at the fluid's surface, the density of the fluid, and the weight of the fluid directly above that point.
What is fluid?Fluid is a state of matter that is characterized by its ability to move and take on the shape of its container. Fluids are composed of particles that are free to move about, and can also exist as a gas or a liquid. Fluids are an important part of everyday life, with applications ranging from transportation of goods to the operation of complex machinery. Fluids are also used to study the behavior of particles in motion, as well as to understand the properties of matter in general.
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Does Milas battery pack create energy ? explain
When multiple sine waves interact and they are in phase with one another, this is known as ______ interference and results in a ______ in amplitude. Group of answer choices Destructive; increase
When multiple sine waves interact and they are in phase with one another, this is known as constructive interference and results in an increase in amplitude.
Constructive interference is a term used to describe the superposition of waves in which the resulting wave's amplitude is greater than that of the individual waves due to their coherent mixing. The term is commonly used in physics, where it refers to the interaction of waves that are completely in phase with one another, implying that the peak of one wave coincides with the peak of the other wave. As a result, the wave's total amplitude is increased when the waves are combined. The resulting wave's frequency is the same as that of the component waves in a constructive interference. When the interference is constructive, the waves combine to create a single wave that is larger than the original waves.
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a transformer si designed to change 021v into 10,000 v, and there are 164 turns in hte primary coil. how many turns are in the secondary coil?
There are approximately 7,808 turns in the secondary coil.
To determine the number of turns in the secondary coil, we can use the formula for transformer voltage ratio, which states that the ratio of the number of turns in the secondary coil to the number of turns in the primary coil is equal to the ratio of the output voltage to the input voltage. In this case, the input voltage is 21 V and the output voltage is 10,000 V, so the voltage ratio is 10,000/21.
Using this voltage ratio formula, we can write:
number of turns in the secondary coil / 164 = 10,000 / 21
Solving for the number of turns in the secondary coil, we get:
number of turns in the secondary coil = (10,000 / 21) x 164
number of turns in the secondary coil = 7,808 turns (rounded to the nearest whole number)
So there are approximately 7,808 turns in the secondary coil. This allows the transformer to step up the voltage from 21 V to 10,000 V.
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if an engine applies a force of 600N on a 200kg scooter. what will be the change of speed? answer in m/s^2
what is the amount of mmf generated bya50-turn electromagnetic coil supplied by 12vdc a t a current of 1 amp
The amount of magnetomotive force (mmf) generated by the electromagnetic coil would be = 50 ampere/turn
What is magnetomotive force (mmf)?Magnetomotive force is defined as the type of magnetic force that is expressed in a magnetic field.
The number of turn in the electromagnetic coil = 50 turns
The voltage of the coil = 12 v
The current of the coil = 1 amp
The formula for magnetomotive force (mmf)= N I = (Flux) x (current)
Therefore, magnetomotive force (mmf) = 50×1 = 50 ampere/turn.
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in real life, is it possible to replicate the experiment newton is performing in the simulation? can you actually swing a ball in a horizontal circle with a perfectly horizontal string? explain your answer
No, it is not possible to replicate the experiment which Sir Newton had performed .
What is circular motion ?
A circular path is followed by an object as it moves along at a constant speed is termed a circular motion
The wire cannot be completely straight or horizontal, as you might expect given its weight. Gravity (mg) and the tension of the rope are the two forces that are constantly exerting pressure on the ball, ignoring the weight of the rope.
These must have a vector total that is mv2/r in the radial direction. The tension force must have an opposing vertical component in order to balance the vertical gravity pull, hence the rope cannot be perfectly horizontal. The angle will be less as the mass is rotated more quickly. Additionally, the mass moves in a perfectly horizontal motion in the absence of resistive losses. The same holds true if the youngster swinging the rope precisely balances the losses.
What is centrifugal acceleration ?
From inside the automobile, it seems as though you are being pushed out of the turn's centre. The centrifugal force is a hypothetical force. This effect is more pronounced the sharper the curve and the faster you are travelling.
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[Provide a solution for every item] A particle moves in a straight line whose position from starting point at any time (t) minutes is s(t) = 2t3 + 3t2 + t. a. What is the acceleration after 1 minute?
The acceleration of the particle after 1 minute is \(18 units/min^2.\)
To find the acceleration, we need to differentiate the position function twice with respect to time.
Given:
\(s(t) = 2t^3 + 3t^2 + t\)
To find the velocity, differentiate s(t) with respect to t:
\(v(t) = d/dt [2t^3 + 3t^2 + t]\)
\(v(t) = 6t^2 + 6t + 1\)
To find the acceleration, differentiate v(t) with respect to t:
\(a(t) = d/dt [6t^2 + 6t + 1]\)
\(a(t) = 12t + 6\)
Now, substitute t = 1 to find the acceleration after 1 minute:
\(a(1) = 12(1) + 6\)
\(= 12 + 6\)
\(= 18\)
Therefore, the acceleration after 1 minute is \(18 units/min^2\)
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which method is commonly used for improving cattle breeds and why?
Answer: Cross-breeding method is commonly used for improving cattle breeds. Cross-breeding between two good varieties of cattle will produce a new improved variety. Cross breeding is defined as the process or the act of producing offspring particularly through mating two pure bred individuals but come from different breeds, varieties, or even species. Crossbreeding is undertaken to: Utilise the desired attributes of two or more breeds. Produce progeny better suited to target markets while maintaining environmental adaption. Improve productivity quicker in traits which are slow to change within a breed i.e. environmental adaption, fertility and carcass traits.
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For a straight line on a position-time graph, the slope of the line represents:
Group of answer choices
velocity
displacement
acceleration
distance
The water from a fire hose follows a path described by y=4.0+0.8x-0.40x^(2) (units are in meters ). If v_(x) is constant at 5.0(m)/(s), find the resultant velocity at the point (2.0.4.0). Find velocity of water
The velocity of the water at the given points (2.0, 4.0) is approximately 5.06 m/s.
To find the velocity of the water at the point (2.0, 4.0), we need to calculate its components: the horizontal velocity (v_x) and the vertical velocity (v_y).
Given that v_x is constant at 5.0 m/s, the horizontal velocity component remains the same regardless of the position.
To find the vertical velocity component, we can differentiate the equation for the path of the water with respect to x:
y = 4.0 + 0.8x - 0.40x^2
Differentiating both sides with respect to x:
dy/dx = d/dx (4.0 + 0.8x - 0.40 \(x^2\))
= 0 + 0.8 - 0.80x
Now, substitute the x-coordinate of the point (2.0, 4.0) into the derivative:
dy/dx at x = 2.0 = 0.8 - 0.80(2.0)
= 0.8 - 1.6
= -0.8 m/s
Therefore, the vertical velocity component (v_y) at the point (2.0, 4.0) is -0.8 m/s.
To find the resultant velocity (v) at that point, we can use the Pythagorean theorem:
v = \(\sqrt{v_x^2 + v_y^2}\)
\(= \sqrt{5.0^2 + (-0.8)^2}\)
\(= \sqrt{25.0 + 0.64}\)
\(= \sqrt{25.64}\)
\(\approx 5.06 , \text{m/s}\)
Hence, the velocity of the water at the point (2.0, 4.0) is approximately 5.06 m/s.
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A paper airplane moves at a constant velocity of 10 m/s to the east when there is no wind of 19 m/s begins to blow?
Answer: So if the steady easterly wind of 19 m/s begins to blow more than the 10 m/s it just needs more wind and direction So the resultant has to be 29 m/s east.
Tor F
Science and technology
are
mutually beneficial.
Answer:
I believe that it's True.
Determine the magnitude of the counterweight w for which the maximum absolute value of the bending moment in the beam is as small as possible.
The magnitude of the counterweight w necessary to minimize the maximum absolute value of the bending moment in the beam is determined by considering the following two factors.
Firstly, the moment created by the weight w must be equal in magnitude but opposite in direction to the other forces acting on the beam. This will result in a balanced system and prevent the beam from buckling. Secondly, the relative size of the weight w must be adjusted to ensure that the maximum absolute value of the bending moment is minimized.
The value of w must be chosen to ensure that the weight is not too small or too large relative to the other forces, resulting in an unbalanced system with a larger maximum absolute value of the bending moment. In summary, the magnitude of w necessary to minimize the highest absolute value of the bending moment in the beam is determined by finding an appropriate balance in the opposing forces.
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A permanent magnet of length l is dropped from a height h through a coil. What is the ratio of the emf induced in the coil at the moment the bottom of the magnet enters the coil to the emf induced in the coil at the moment the top of the magnet leaves the coil?.
The emf induced in a coil is given by the equation:
emf = -N dΦ/dt
Where N is the number of turns in the coil, Φ is the magnetic flux through the coil, and dt is the change in time.
When the magnet is dropped from a height h through the coil, it induces a changing magnetic flux through the coil. As the magnet enters the coil, the flux through the coil increases, and as the magnet exits the coil, the flux through the coil decreases. The rate of change of the magnetic flux through the coil is therefore maximum at the moment the bottom of the magnet enters the coil and at the moment the top of the magnet leaves the coil.
The emf induced in the coil is proportional to the rate of change of the magnetic flux. Therefore, the ratio of the emf induced in the coil at the moment the bottom of the magnet enters the coil to the emf induced in the coil at the moment the top of the magnet leaves the coil is equal to the ratio of the rate of change of the magnetic flux at these two moments.
Since the magnet is of length 1, the rate of change of the magnetic flux is the same at both ends of the magnet. Therefore, the ratio of the emf induced in the coil at the moment the bottom of the magnet enters the coil to the emf induced in the coil at the moment the top of the magnet leaves the coil is 1:1 or simply 1.
refraction refers to the bending of light rays to bring the rays into focus on the
Refraction refers to the phenomenon of light rays changing direction as they pass from one medium to another, resulting in bending.
This bending allows the rays to converge or diverge in order to bring them into focus on a specific point or create various optical effects.
Refraction occurs when light travels through a medium with a different optical density, such as from air to water or from air to glass. The change in optical density causes the speed of light to change, leading to a change in its direction. As the light passes through the interface between the two media, the angle at which it approaches the interface (angle of incidence) differs from the angle at which it continues in the new medium (angle of refraction). This change in direction is responsible for the bending of light rays during refraction.
The bending of light rays during refraction allows them to focus on a particular point. This focusing phenomenon is commonly observed in lenses, where light passing through a lens is refracted and converges or diverges to form an image. The shape and curvature of the lens determine the degree of bending and the focal point where the rays converge or diverge.
Refraction is also involved in the functioning of optical instruments such as cameras, microscopes, and telescopes, which utilize lenses to manipulate and focus light to capture or observe objects.
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Calculate the period of oscillation of a pendulum with a small amplitude whose length is 2.5 meters
Answer:
T = 3.17 s
Explanation:
Given that,
The length of the pendulum, l = 2.5 m
We know that the period of oscillation of the pendulum is given by :
\(T=2\pi \sqrt{\dfrac{l}{g}}\)
Where
g is the acceleration due to gravity
\(T=2\pi \sqrt{\dfrac{2.5}{9.8}}\\\\T=3.17\ s\)
So, the period of oscillation is equal to 3.17 s.
The winter sport of curling involves sliding a large granite stone on ice with the objective of placing it closest to the center of the ring. The curler causes the path of the stone to curve by giving it an initial circular rotation. Sweepers use brooms to sweep the path in front of the stone. How does the motion of the sweepers relate to the conservation of angular momentum?
a) The sweepers minimize friction between the stone and ice which helps maintain the angular momentum.
b) The sweepers motion creates circular air motion which adds to the angular momentum.
c) The sweepers motion adds torque to the stone's angular momentum.
d) The sweepers create circular patterns in the ice to increase the angular momentum.
The winter sport of curling involves sliding a large granite stone on ice with the objective of placing it closest to the center of the ring. The curler causes the path of the stone to curve by giving it an initial circular rotation. Sweepers use brooms to sweep the path in front of the stone. The motion of the sweepers relate to the conservation of angular momentum by the sweepers' motion adds torque to the stone's angular momentum.
The correct answer is option C.
The motion of the sweepers in curling relates to the conservation of angular momentum in the following way:
Angular momentum is a property of rotating objects and is conserved in the absence of external torques. In curling, the initial circular rotation given to the stone by the curler sets its angular momentum. As the stone glides on the ice, the sweepers can influence its path by sweeping in front of it.
By sweeping, the sweepers apply a horizontal force to the ice, which creates a torque on the stone. This torque changes the angular momentum of the stone, causing it to deviate from a straight-line path and curve towards the desired target. The sweepers adjust the stone's path by selectively sweeping on one side or the other, effectively changing the torque applied and altering the angular momentum accordingly.
The motion of the sweepers does not directly affect friction, circular air motion, or circular patterns in the ice to increase angular momentum. Instead, their actions primarily focus on modifying the stone's angular momentum through torque, influencing its trajectory and optimizing its placement on the ice.
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May I get an answer?
Answer:
Explanation: all of them have made sentence structure (grammar point view) and from the physical aspect.
HELP!!!
7. A block rests on a frictionless table on Earth. After a 20-N horizontal force is applied to the
block, it accelerates at 3.9 m/s^2.Then the block and table are carried to the moon, where the
acceleration due to gravity is 1.62 m/s^2. A horizontal force of 10 N is then applied to the block.
What is the acceleration?
A)2.0 m/s2
B)2.1 m/s2
C)1.8 m/s2
D)2.3 m/s2
E)2.5 m/s2