Explanation:
study of social sciencake us an effcient citizen of a democracy ,and it also help us to solve the practical problem in our daily life.
An object moves from point A to point C along the rectangle shown in the figure below.
a) Find the distance covered by the moving object.
b) Find the magnitude of the displacement of the object.
Answer:
Hello friend where is the figure of the question
7) Find F1 and F2
HELP PLEASEEE
The force F1 is equal and opposite to the downward force thus, F1 is equal to 60 N. The force F2 is inclined to 30 ° from leftward force and it is equal to 38.97 N in magnitude.
What is force?Force is an external agent acting on a body to deform it or to change its state of motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction.
If two forces acting on a body from the same directions, then the net force will be the sum of these two forces. If they are acting from opposite directions, they will cancel each other in magnitude.
The force F1 is equal and opposite to the force acting downward. Thus its magnitude is 60 N. The force F2 is inclined to 30 ° from horizontal direction.
F2 = 45 cos 30 = 38.9 N.
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how often do industrial oxygen cylinders need to be tested
Answer:
5 years\(\)
A rock is thrown straight up with an initial speed of 24.0 m/s. Neglect air resistance. At t = 1.0 s what are the directions of the velocity and acceleration of the rock? Is the speed of the rock increasing or decreasing? The acceleration is upward. The velocity is upward and the speed is increasing. The acceleration is downward. The velocity is downward and the speed is increasing. The acceleration is upward. The velocity is upward and the speed is decreasing. O The acceleration is downward. The velocity is upward and the speed is decreasing. O The acceleration is downward. The velocity is downward and the speed is decreasing. Submit Previous Answers Request Answer Part B At t = 3.0 s what are the directions of the velocity and acceleration of the rock? Is the speed of the rock increasing or decreasing? The acceleration is upward. The velocity is upward and the speed is decreasing. The acceleration is upward. The velocity is upward and the speed is increasing. The acceleration is downward. The velocity is upward and the speed is decreasing. The acceleration is downward. The velocity is downward and the speed is decreasing. The acceleration is downward. The velocity is downward and the speed is increasing.
The acceleration remains in the same direction (downward) throughout, but the velocity of the rock changes from positive (upward) to negative (downward).
At t = 1.0 s, the rock has an initial velocity of 24.0 m/s in the upward direction and an acceleration of 9.8 m/s2 in the downward direction. This means that the speed of the rock is increasing as it accelerates downward.
At t = 3.0 s, the rock has a velocity of -48.0 m/s in the downward direction and an acceleration of 9.8 m/s2 in the downward direction. This means that the speed of the rock is decreasing as it accelerates downward.
The acceleration of the rock remains in the same direction (downward) as it moves, but the velocity of the rock changes from positive (upward) to negative (downward).
To sum up, the rock has an initial velocity of 24.0 m/s in the upward direction and an acceleration of 9.8 m/s2 in the downward direction at t = 1.0 s.
This means that the speed of the rock is increasing as it accelerates downward. At t = 3.0 s, the rock has a velocity of -48.0 m/s in the downward direction and an acceleration of 9.8 m/s2 in the downward direction.
This means that the speed of the rock is decreasing as it accelerates downward.
The acceleration remains in the same direction (downward) throughout, but the velocity of the rock changes from positive (upward) to negative (downward).
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If the bolt is subjected to a compressive force of P = 21.1 kN, determine the average normal stress in the steel The 10-mm-diameter steel bolt in (Fiqure 1) is surrounded by a bronze sleeve . The outer diameter of this sleeve is 20 mm, and its inner diameter is 10 mm. Est 200 GPa, Br = 100 GPa. Express your answer to three significant figures and include appropriate units Figure 1 #1 of 1 MPa Submit My Answers Give Up Incorrect; One attempt remaining; Try Again Not quite. Check through your calculations; wrong number of significant figures ,you may have made a rounding error or used the 10 mm Part B 20 mm If the bolt is subjected to a compressive force of P = 21.1 kN, determine the average normal stress in the bronze Express your answer to three significant figures and include appropriate units u-Value Units
The average normal stress in the bronze sleeve is approximately 89,564.1 Pa (or 89.6 kPa) to three significant figures.
To determine the average normal stress in the steel and bronze components, we can use the formula for stress:
Stress = Force / Area
a) Average normal stress in the steel bolt:
Given:
Diameter of the steel bolt = 10 mm
First, we need to calculate the area of the steel bolt:
Area = π * (diameter/2)^2
Area = π * (10 mm / 2)^2
Area = π * (5 mm)^2
Area = 78.54 mm^2
Now, let's calculate the average normal stress in the steel bolt using the compressive force:
Stress = Force / Area
Stress = 21.1 kN / 78.54 mm^2
To convert the stress to the appropriate units, we need to convert kilonewtons (kN) to newtons (N) and millimeters (mm^2) to square meters (m^2):
Stress = (21.1 kN * 1000 N/kN) / (78.54 mm^2 * (10^-6 m^2/mm^2))
Stress = 268,216.4 N/m^2
The average normal stress in the steel bolt is approximately 268,216.4 Pa (or 268.2 MPa) to three significant figures.
b) Average normal stress in the bronze sleeve:
Given:
Outer diameter of the bronze sleeve = 20 mm
Inner diameter of the bronze sleeve = 10 mm
First, we need to calculate the area of the bronze sleeve:
Area = π * (outer diameter/2)^2 - π * (inner diameter/2)^2
Area = π * (20 mm / 2)^2 - π * (10 mm / 2)^2
Area = π * (10 mm)^2 - π * (5 mm)^2
Area = 235.62 mm^2
Now, let's calculate the average normal stress in the bronze sleeve using the compressive force:
Stress = Force / Area
Stress = 21.1 kN / 235.62 mm^2
To convert the stress to the appropriate units, we need to convert kilonewtons (kN) to newtons (N) and millimeters (mm^2) to square meters (m^2):
Stress = (21.1 kN * 1000 N/kN) / (235.62 mm^2 * (10^-6 m^2/mm^2))
Stress = 89,564.1 N/m^2
The average normal stress in the bronze sleeve is approximately 89,564.1 Pa (or 89.6 kPa) to three significant figures.
Note: The units used are in Pascal (Pa), which is equivalent to N/m^2.
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V=25 dm3(cubic decimeter) in meters
a 1000kg car moving at 23.9 m/s on a flat road slams on the brakes and skids to a stop. the coefficient of kinetic friction between the road and car tires is 0.739. how many meters does the car go before it comes to a complete stop? (hint: think of work-energy theorem, and friction equation)
The car will skid to a stop after traveling approximately 80.5 meters.
To solve this problem, we can use the work-energy theorem and the equation for friction. The work done by the frictional force is equal to the change in kinetic energy of the car:
W_friction = ΔKThe work done by the frictional force is equal to the force of friction times the distance traveled:
W_friction = F_friction * dThe force of friction is equal to the coefficient of friction times the normal force, which is equal to the weight of the car:
F_friction = μ * m * gSubstituting these equations and solving for d, we get:
d = (K_i - K_f) / (μ * m * g)where K_i is the initial kinetic energy of the car, which is equal to (1/2) * m * v², and K_f is the final kinetic energy of the car, which is equal to 0.
Plugging in the given values, we get:
d = (1/2 * m * v²) / (μ * m * g)= (1/2 * v²) / (μ * g)= (1/2 * 23.9²) / (0.739 * 9.81)≈ 80.5 metersTo learn more about work-energy theorem, here
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Which of these best describes why your weight would be different on another celestial body?
A. Different celestial bodies have different gravitational pulls
B. The smaller the celestial body, the greater weight
C. The farther the celestial body from the sun, the more the gravitational pull
D. Weight is constant, so it would not change
Answer:
A
Explanation:
The answer is A due to the gravity is stronger the greater the mass but the less the mass is the weaker the gravity. In conclusion, the answer is A because the strength of gravity depends on the mass.
Which object would have the greatest kinetic energy? *
A car driving down a hill at a speed of 40 m/s A person walking on the street at 2 m/s A ball rolling across the field at 5m/s A leaf falling at 10 m/s
13. Which one of the colors has the longest wavelength A, Red B. Yellow C. Blue 14. The sky appears blue due to A. Diffraction of light C. Refraction of light B. Reflection of light D. Scattering of light
13.The color with the longest wavelength is option A. Red.
14.The sky appears blue due to option D. Scattering of light.
Red light has a longer wavelength compared to yellow and blue light.The color that has the longest wavelength is red. The color of the sky appears blue due to scattering of light. The distance between one peak and the next in a series of waves, particularly electromagnetic waves traveling through space or along a wire is referred to as wavelength.
The wavelength of light, for example, determines its color. Red light has the longest wavelength, followed by orange, yellow, green, blue, and purple, with violet light having the shortest wavelength. When light is reflected off a surface or passes through a medium, it can be deflected in various directions, a phenomenon known as scattering of light.
The Earth's atmosphere scatters sunlight in all directions, but the shorter blue wavelengths are scattered more than the longer wavelengths. As a result, we perceive the sky as blue during the day. The light becomes scattered when it interacts with particles in the atmosphere, causing the sky to appear blue during the day and red during sunset or sunrise. The scattering of light is the process that causes the sky to appear blue.
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which type of star spends the shortest time as a main sequence star?
The type of star that spends the shortest time as a main sequence star is the O-type star. These stars are the most massive, with a mass of at least 16 times that of our Sun.
Due to their high mass, they burn through their hydrogen fuel at a much faster rate than other stars. This means that they spend a relatively short amount of time as a main sequence star, typically only a few million years.
Once an O-type star has burned through its hydrogen fuel, it enters into the next stage of its life cycle, which is known as the post-main sequence. During this phase, the star undergoes a rapid evolution, and can become a red supergiant, a Wolf-Rayet star, or even a black hole or neutron star.
Although O-type stars spend a relatively short amount of time as main sequence stars, they are still important objects of study for astronomers. These stars are extremely luminous and can be seen from great distances, which makes them useful for studying the properties of galaxies and other large-scale structures in the universe.
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The speed of a car is decreased uniformly from 30. meters per second to 10. meters per second in 4.0 seconds.
Answer: The car slows down by 10 meters per second every second.
Explanation:
AnswerThe speed of a car is decreased uniformly from 30. meters per second to 10. meters per second in 4.0 seconds. What was the car's acceleration ?
We have the following data:
V (final velocity) = 10 m/s
Vo (initial velocity) = 30 m/s
ΔV (speed interval) = V - Vo → ΔV = 10 - 30 → ΔV = - 20 m/s
ΔT (time interval) = 4.0 seconds
a (average acceleration) = ? (in m/s²)
Explanation:
A wave travels through a medium. As the wave passes, the particles of the medium vibrate in a direction perpendicular to the direction of the wave’s motion. The wave is:.
Answer:
this kind of waves is are called mechanical tranverse examples are surface ripples on water
A graph labeled velocity versus time with horizontal axis time (seconds) and vertical axis velocity (meters per second). A blue line runs straight across at 2 units on the vertical axis for all horizontal axis values.
Based on the graph of velocity over time, which could be the initial velocity and the final velocity for this graph?
initial = 0 m/s; final = 2.5 m/s
initial = 2.5 m/s; final = 2.5 m/s
initial = 3.0 m/s; final = 6.0 m/s
initial = 6.0m/s; final = 3.0 m/s
Answer:
B
Explanation:
If you dident pay for the no ad thing its okay all u have to do is answer one person's question every day befor you ask a question no ad's just answers you gotta do it every day tho
Answer:
Second option is correct.
The initial and the final velocity for the graph is
initial=2.5m/s; final=2.5m/s.
Explanation:
In given velocity time graph, the line is horizontal and parallel to the x-axis (time-axis).It means the body is moving at the constant velocity.Its acceleration is zero.Explain Velocity-Time graph?The graph plotted between velocity and time, is called velocity time graph.
by it acceleration can be find out.the area of the graph shows distance travelled.it can be plotted in all the quadrants because velocity is a vector quantity.Hence, second option is correct.
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What is net force?
A. When an object moves
B. The sum of all forces actingon an object
C. The force of gravity on anobject
D. A calculation to find work PLEASE HELP!!
Answer:
B
Explanation:
what type of viscometer is used to measure the pvp viscosity?
The type of viscometer that is commonly used to measure the viscosity of PVP (polyvinylpyrrolidone) is a rotational viscometer.
What's!PVP (polyvinylpyrrolidone) ?This type of viscometer measures the resistance of a liquid or semi-solid substance to flow under applied force.
In the case of PVP, the rotational viscometer applies a rotational force to a sample of PVP, causing it to flow in a circular motion. The resistance to flow is measured and used to calculate the viscosity of the substance.
Rotational viscometers are popular because they offer a high degree of precision and accuracy, and can be used for a wide range of substances.
They are also relatively easy to use and require only a small sample size, making them ideal for laboratory settings.
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Solue the Selmultaneous equations:
3y +2x =5 and y-5x = 13
Answer:
x=-2 and y=3
Explanation:
Isolate y and then x to get: y=13+5(-2)
Simplify to get y=3 then plug it back in to get x=-2
We can check, 9+ (-4)=5 hope this helps
Which statement compares the attractive forces that hold particles together?
A. Covalent bonding and Van der Waals forces join separate
molecules together, while ionic and hydrogen bonding produce
compounds.
B. Covalent and hydrogen bonding produce compounds, while ionic
bonding and Van der Waals forces join separate molecules
together.
C. lonic and covalent bonding produce compounds, while hydrogen
bonding and Van der Waals forces join separate molecules
together.
D. Ionic and covalent bonding join separate molecules together, while
hydrogen bonding and Van der Waals forces produce compounds.
Answer:
Ionic and covalent bonding produce compounds, while hydrogen bonding and Van der Waals forces join separate molecules together.
Ur welcome:)
Answer:
C) lonic and covalent bonding produce compounds, while hydrogen bonding and Van der Waals forces join separate molecules together.
Explanation:
Please help!! Energy work!
Atividade 1) A presença do campo magnético terrestre proporciona alguns efeitos interessantes. Dentre eles estão as auroras polares. Faça uma pesquisa e explique como esse fenômeno ocorre. Atividade 2 Utilizando a simulação mostrada na figura abaixo, aproxime o ímã da bússola em várias posições ao longo do plano. a) O que representam as pequenas agulhas ao redor do ímã? b) O que acontece com a agulha da bússola quando o ímã é movimentado ao seu redor? c) Marque a seleção "Mostrar medidor de campo". Movimente o medidor de campo O que você observa em relação ao campo magnético⃗ , quando o medidor de campo se aproxima do imã? c) Marque a caixa de seleção "planeta Terra". Como são mostradas as polaridades do ímã? Por que aparece dessa forma?
A 15.2 kg mass has a gravitational potential energy of -342 J. How high from the ground is it? Group of answer choices GPE cannot be negative 2.3 m 22.5 m 530 m
A. The height above the ground reached by the mass is 2.3 m.
Height traveled by the mass
P.E = mgh
where;
m is mass h is height reached by the objectg is acceleration due to gravityh = P.E/mg
h = (342)/(15.2 x 9.8)
h = 2.3 m
Thus, the height above the ground reached by the mass is 2.3 m.
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the frequency of the fundamental of the guitar string is 320 hz. at what speed \(\texttip{v}{v}\) do waves move along that string?
Waves move along the string with a speed of v = 640L where L is the length of the string.
The velocity of waves refers to both the speed and direction of the wave. It is calculated as a product of the wavelength and frequency of a wave. To find the velocity of waves with which they move along the string, we need to know the length of the string.
Let us assume that the length of the string is 'L'.
If the waves are propagating in the fundamental frequency, then
using the formula
\(f = v/2L\)
where f is frequency, v is velocity, and L is the length of the string.
v = 2fL
v = 2 * 320 * L
v = 640L
Therefore, the velocity of waves is 640L.
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Which of Galileo's theories drew fire from the Catholic Church and led to his
house arrest?
Answer:
imma have to come back to you on that one
Answer:
The Sun is at the center of the solar system and the planets move around it.
Explanation:pluto/edmentum
The displacement (in centimeters) of a particie s moving back and forth along a straight ine is giver by the equation s=4 sin(st) +2 cosi(at), where f is measured in scoonds. (Round yout answers to two decimal places.) (a) Find the average velocity during each time period. (1) [1,2] cm/s (ii) [1,1,1] cm/s (iii) [1,1.01] conve (iv) [1,1,001] cm/s (0) Estimate the instantanecus velocity of the particle nticn f - 1 .
To find the average velocity during each time period, we need to calculate the displacement and divide it by the time interval.
(a) Average velocity from t = 1 to t = 2:
Displacement: s(2) - s(1) = [4 sin(2s) + 2 cos(2a)] - [4 sin(s) + 2 cos(a)]Time interval: 2 - 1 = 1 secondAverage velocity = Displacement / Time interval
(b) Average velocity from t = 1 to t = 1.1:
Displacement: s(1.1) - s(1) = [4 sin(1.1s) + 2 cos(1.1a)] - [4 sin(s) + 2 cos(a)]Time interval: 1.1 - 1 = 0.1 secondAverage velocity = Displacement / Time interval
(c) Average velocity from t = 1 to t = 1.01:
Displacement: s(1.01) - s(1) = [4 sin(1.01s) + 2 cos(1.01a)] - [4 sin(s) + 2 cos(a)]Time interval: 1.01 - 1 = 0.01 secondAverage velocity = Displacement / Time interval
(d) Average velocity from t = 1 to t = 1.001:
Displacement: s(1.001) - s(1) = [4 sin(1.001s) + 2 cos(1.001a)] - [4 sin(s) + 2 cos(a)]Time interval: 1.001 - 1 = 0.001 secondAverage velocity = Displacement / Time interval
To estimate the instantaneous velocity at t = 1, we can take the derivative of the displacement function with respect to time and evaluate it at t = 1:
Instantaneous velocity at t = 1:
v(1) = d/dt [4 sin(st) + 2 cos(at)] evaluated at t = 1
About VelocityVelocity is a vector quantity that indicates how fast an object is moving. The magnitude of this vector is called speed and is expressed in meters per second.
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If a star is 720 , 000 , 000 , 000 , 000 meters from Earth, how many seconds does it take light to travel from the Earth to the star
Answer:
anywhere between 100000 to about 400000 human years .
Explanation:
The ________ smooths out the pressure pulses in the exhaust system, allowing them to be released at an even and constant rate.
The muffler smooths out the pressure pulses in the exhaust system, allowing them to be released at an even and constant rate.
An exhaust system is a system used by an engine to channel out gasses created when the fuel and air are burned in the combustion chamber.
Some components of an exhaust system include:
clampsoxygen sensor andMufflersThe muffler of the exhaust system helps it to achieve its functions which include it:
control noise, carry away gases, improve engine performance and improve fuel consumptionThe muffler are used mainly to dissipate the loud sounds created by the engine's pistons and valves.
Therefore, muffler smooths out the pressure pulses in the exhaust system, allowing them to be released at an even and constant rate.
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air is blown through a cone. if the density of the stream is decreasing, then the mass flow rate of the outlet stream is ____________ the mass flow rate of the inlet stream.
Air is blown through a cone. if the density of the stream is decreasing, then the mass flow rate of the outlet stream is as follow:
If the density of the stream is decreasing, then the mass flow rate of the outlet stream is greater than the mass flow rate of the inlet stream.
What is mass flow?
Mass flow refers to the amount of mass that passes through a certain area per unit time. It's typically measured in units of kg/s or lb/s.
What is density?
Density refers to the amount of matter in a particular area, typically measured in kg/m3 or lb/ft3. It's a measure of how much mass there is per unit volume.What happens when the density of the stream decreases?The mass flow rate of the outlet stream is greater than the mass flow rate of the inlet stream when the density of the stream decreases. As a result, the mass flow rate of the outlet stream will be higher than the mass flow rate of the inlet stream
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A student is using a sound machine to produce the sound waves presented in the data table below. How could the student manipulate the sounds to make them match in pitch but make sound wave #1 louder than sound wave #2?
Answer: Make the frequency higher for number 1 and have the same amplitude.
Explanation: Wavelength and frequency are directly related so if you change one of those then you can't keep the other one the same. You would need to raise the frequency which would make 1 louder and keep amplitude the same for both so that 1 is louder.
To make the sounds match in pitch while making sound wave 1 louder than sound wave 2 : Increase the frequency for wave #1 while setting their amplitudes at the same value
The wavelength of a sound wave is inversely proportional to its frequency therefore when the frequency of wave 1 is increased its wavelength decreases with equal proportion.
Since the increase in frequency results to a decrease in wavelength. therefore to make wave 1 louder, both waves we will have to set the amplitude values of the waves at the same amplitude.
Hence we can conclude that to make the sounds match in pitch while making sound wave 1 louder than sound wave 2 ; Increase the frequency for wave #1 while setting their amplitudes at the same value.
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Felipe drives his car at a velocity of 28 m/s. He applies the brake, which slows the vehicle down at a rate of 6.4 m/s2 and causes it to slow to a stop. How long does it take for the car to stop? Round your answer to the nearest tenth.
Answer:
Explanation:
Use the one-dimensional equation
\(v_f=v_0+at\) where v is the final velocity, v0 is the initial velocity, a is the acceleration, and t is the time it takes to reach that final velocity. We are solving for t. Filling in the other values:
0 = 28 + (-6.4)t and
-28 = -6.4t so
t = 4.4 seconds
Answer:
4.4
Explanation:
Which process is represented inside of the dashed circle?
Evaporation
Condensation
Precipitation
Transpiration