How does net force affect the direction of motion?

Answers

Answer 1

Answer:

An unbalanced force (net force) acting on an object changes its speed and/or direction of motion. While the net force may not be in the same direction which the object is moving, it is always in the direction that the object is accelerating.

Explanation:


Related Questions

Sally is riding her skateboard at 12.0 ft/s and passes under an apple tree. As she
moves past, she grabs a 2.0 kg branch with five apples right off the tree. Sally's mass
is 34 kg. What is her speed after grabbing the branch and apples?

Answers

Answer:

11.3

Explanation:

A wave that consists of a combination of electrical and magnetic energy is a(n):
a. magnoelectric wave
c. magnetolectric wave
b. electromagnetic wave
d. electrical-magnetic wave

Answers

The answer to you’re question is b. Electromagnetic wave. Electromagnetic waves are made up of an electromagnetic field and a magnetic field.
This wave is produced as a result of the vibration of the electric and magnetic fields.

if a direction is somewhere between North and East it is measured in _____?

Answers

Answer:

degrees

Explanation:

If a direction is somewhere between north and east, it is measured in degrees.

This measurement will be possible thanks to the existence of geographical coordinates that are some 'imaginary lines' that help us find our location on the earth's surface. These lines are called latitude and longitude, both of which are measured in degrees.

It is like a sea battle game where you have to combine the rows and columns in order to identify where the targets are located. Geographic coordinates work the same way, you must combine the rows and columns of the planisphere to identify the locations of the planet. So the lines would be the latitudes and the columns the longitudes.

An immersion heater is rated 120w. How long does it take the heater to raise the temperature of 1.2kg of water by 15°c.

Answers

Answer:

dmakqkwnwj fddfgdddwsf

In 1924, edwin hubble proved that the andromeda galaxy lay far beyond the bounds of the milky way, thereby putting to rest the idea that it might have been a cloud within our own galaxy. What key observation enabled him to prove this?.

Answers

The key observation enabled Edwin Hubble to prove this by observing individual Cepheid variable stars in Andromeda and applying the period-luminosity relation.

American astronomer Edwin Powell Hubble lived from November 20, 1889, through September 28, 1953. He was a significant contributor to the development of observational cosmology and extragalactic astronomy.

Hubble established that many objects formerly believed to be "nebulae" or clouds of gas and dust, were actually galaxies outside the Milky Way. He scaled galactic and extragalactic distances using the strong direct correlation between a classical Cepheid variable's luminosity and pulsation time, which was found in 1908 by Henrietta Swan Leavitt.

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the cylindrical head bolts on a car are to be tightened with a torque of 62.0 nm. if a mechanic uses a wrench of length 20 cm, what perpendicular force must he exert on the end of the wrench to tighten a bolt correctly?

Answers

The mechanic must exert a perpendicular force of 310 N on the end of the wrench to tighten the bolt correctly.

To calculate the perpendicular force that the mechanic must exert on the end of the wrench to tighten the bolt correctly, we can use the formula for torque:

\(T = F * d * sin(θ)\)

where T is the torque, F is the force applied perpendicular to the wrench, d is the length of the wrench, and θ is the angle between the force and the wrench.

We can rearrange this formula to solve for the force:

\(F = T / (d * sin(θ))\)

In this case, we know that the torque required to tighten the bolt is 62.0 Nm. To convert this to SI units, we need to multiply by the conversion factor 1 Nm = 1 J. Therefore:

T = 62.0 J

The length of the wrench is 20 cm, or 0.2 m.

The angle between the force and the wrench is 90 degrees, since the force must be applied perpendicular to the wrench.

Substituting these values into the formula, we get:

\(F = 62.0 J / (0.2 m * sin(90°))F = 310 N\)

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According to most code documents, liquefaction is no longer a
concern once historic high groundwater is deeper than ___________
from the surface
A. 5 feet
B. 50 feet
C. 500 fe

Answers

The correct answer is B. 50 feet.

Liquefaction is a phenomenon that occurs when water-saturated soil loses its strength and behaves like a liquid.

This can happen during an earthquake, when the shaking causes the soil particles to lose contact with each other. Liquefaction can also be caused by other factors, such as heavy rains or flooding. The depth of groundwater is an important factor in determining whether or not liquefaction will occur. If the groundwater is close to the surface, the soil is more likely to liquefy. This is because the water provides a pathway for the soil particles to move around, and it also reduces the friction between the particles. Most code documents state that liquefaction is no longer a concern once the historic high groundwater is deeper than 50 feet from the surface. This is because the soil at this depth is typically not saturated with water, and it is therefore less likely to liquefy. However, it is important to note that liquefaction can still occur at depths greater than 50 feet, especially if the soil is very loose or if there is a lot of groundwater.

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the image below to answer question 2.
1
4 cm
3 cm
7 cm
2. The block shown above has a mass of 105 g.
What is the density of the block? sc.8.P.8.3
A 0.80 g/cm3
1.25 g/cm3
7.50 g/cm3
21.0 g/cm3
C
D

Answers

The density of the block is 1.25 \(g/cm^3\)

Given the following data:

Length of block = 3 cmWidth of block = 4 cmHeight of block = 7 cmMass of block = 105 grams.

First of all, we would determine the volume of the block.

\(Volume \;of \;block = length\) × \(width\) × \(height\)

\(Volume \;of \;block = 3\) × \(4\) × \(7\)

Volume of block = 84 \(cm^3\)

To find the density of the block;

Density is mass per unit volume of an object such as a block.

Mathematically, the density of an object is calculated by using the formula;

\(Density = \frac{Mass}{Volume}\)

Substituting the values into the formula, we have;

\(Density = \frac{105}{84}\)

Density = 1.25 \(g/cm^3\)

Therefore, the density of the block is 1.25 \(g/cm^3\)

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ou are working for an athletic shoe company that has just developed a shoe that is 40% lighter than any shoe on the market. This shoe is ideal for distance runners, and your company is confident that runners around the world will want to buy the shoe. Based on this information, you suggest that your company charge a ________ price than other shoes on the market based on ______________.

Answers

I suggest that your company charge a premium price than other shoes on the market based on the shoe's unique selling proposition of being 40% lighter.

Since the shoe is ideal for distance runners, it can significantly improve their performance and reduce the risk of injury. This competitive advantage is likely to appeal to serious runners who are willing to pay a premium price for quality shoes that can enhance their performance. Additionally, the cost of research and development to create such a lightweight shoe is likely to be higher, which justifies a higher price point. However, it's important to conduct market research to ensure that the premium price is reasonable and within the range of what consumers are willing to pay for such a shoe.

The shoe's 40% lighter weight provides a competitive advantage, as it can enhance a runner's performance and reduce fatigue during long-distance runs. This innovative feature is likely to attract a niche market of serious distance runners who are willing to pay a premium for a product that caters specifically to their needs. In summary, the shoe's exceptional lightness and its potential to improve the running experience justify a higher price point compared to other athletic shoes on the market.

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An 80-kg student collides with a padded wall in the gymnasium while moving at 6.0 m/s.
Because he collided with a padded wall instead of a concrete wall, the time of collision was
increased by a factor of 10. What affect does this increase in collision time have upon the
force and the impulse that he experiences? Select two answers.
1. Colliding with the padded wall will make the force 10 times greater.
2. Colliding with the padded wall will make the force 10 times smaller.

Answers

Answer:

  2. Colliding with the padded wall will make the force 10 times smaller

Explanation:

Impulse is the product of force and time. Its units are those of momentum. Assuming the change in momentum (impulse) remains the same, the increase in time means the force will be decreased by the same factor.

Colliding with the padded wall will make the force 10 times smaller

What happens to a waves energy when amplitude is doubled? Halved? Tripled?

Answers

Answer:

This means that a doubling of the amplitude of a wave is indicative of a quadrupling of the energy transported by the wave. A tripling of the amplitude of a wave is indicative of a nine-fold increase in the amount of energy transported by the wave. So when doubling, you are quadrupling, tripling, you are 9x it, and for  halve, it cuts in half.

Explanation:

a person riding in an elevator stands on a metric scale. if the mass of the person is 60.0 kg and the elevator accelerates upward with an acceleration of 4.90 m/s2, what is the reading on the scale?

Answers

The reading on the scale is 882.6 N when the elevator accelerates upwards with an acceleration of 4.90 m/s².

Given that the mass of a person is 60.0 kg and the elevator accelerates upwards with an acceleration of 4.90 m/s², we have to determine the reading on the scale.

Let F be the force exerted by the scale on the person. Then, by Newton's second law of motion, the net force acting on the person is Fnet= m * a

where m = 60.0 kg is the mass of the person and a = 4.90 m/s² is the acceleration of the elevator. Hence, the net force acting on the person is given by;

Fnet = 60.0 kg * 4.90 m/s²

Fnet = 294.0 N

Therefore, the scale reading is equal to the force exerted by the scale on the person. Since the elevator is accelerating upwards, the force exerted by the scale on the person is greater than the weight of the person, which is the force of gravity acting on the person.

The force of gravity acting on the person is given by;

Fg = m * g, where g = 9.81 m/s² is the acceleration due to gravity. Hence, the force of gravity acting on the person is given by;

Fg = 60.0 kg * 9.81 m/s²Fg = 588.6 N

Therefore, the scale reading is given by the sum of the force of gravity acting on the person and the net force acting on the person;

F = Fg + Fnet

F = 588.6 N + 294.0 N

F = 882.6 N

Thus, the reading on the scale is 882.6 N when the elevator accelerates upwards with an acceleration of 4.90 m/s².

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A toy airplane is flying at a speed of 3 m/s with an acceleration of 1.1 m/s squared how fast is it flying after five seconds

Answers

Answer:

\(8.5\frac{m}{s}\)

Explanation:

Use Kinematics:

\(v = v_0 + at\)

\(v = 3 + 1.1 * 5\)

\(v = 8.5 \frac{m}{s}\)

How does a resistor affect an electrical circuit?

How does a resistor affect an electrical circuit?

Answers

Answer:

D

Explanation:

Answer:

D.

It reduces the rate at which electrons flow.

A hockey puck has a mass of 0.21 kg. If the hockey puck
is moving with 74 J of kinetic energy, what is its speed?
Show all your work.

Answers

Answer:

v = 26.54 m/s

Explanation:

Given that,

The mass of a hockey puck, m = 0.21 kg

The kinetic energy of the hockey puck, E= 74 J

We need to find the speed of the hockey puck. Let the speed is v. We know that, the kinetic energy is given by :

\(E=\dfrac{1}{2}mv^2\)

Where

v is the speed

So,

\(v=\sqrt{\dfrac{2E}{m}} \\\\v=\sqrt{\dfrac{2\times 74}{0.21}} \\\\v=26.54\ m/s\)

So, the speed of the hockey puck is 26.54 m/s.

Can some one Explain to me how the orbits of the planets around the sun work?
Kepler 2nd and 3rd law are tricky can someone explain?

Answers

Since the powerful gravitational pull of the Sun, all of the the solar system's planets revolve around it. The Sun basically attracts the solar system's planets, encompassing Earth, as well as allows them to be in orbit.

What is Kepler's law?

Kepler's laws of planetary motion was initially published at 1609 and 1619 by Johannes Kepler which implies the description of the main orbits of planets around the Sun.

They explain the following scenarios:

Planets move in elliptical orbits all around the Sun.A planet grab the similar quantity of space in the similar time not relating of the place it is in its orbit.A planet's orbital period is usually proportional to the size of its orbit.

Thus, this way, the orbits of the planets around the sun work.

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The standard tuning for musical instruments is the note A at 440 Hz. If the speed of sound in a concert hall is 344 m/s, what is the wavelength for the note A?
a. 0.72 m
b. 0.78 m
c. 0.82 m
d. 0.68 m

Answers

The wavelength for note A in this concert hall is (b) 0.78 m.

What is wavelength?

The speed of sound (v) in a medium is related to its frequency (f) and wavelength (λ) by the formula:

v = fλ

We can rearrange this formula to solve for the wavelength:

λ = v / f

In this case, the frequency of note A is 440 Hz, and the speed of sound in the concert hall is 344 m/s. Substituting these values into the formula above, we get:

λ = 344 m/s / 440 Hz

λ = 0.78 m

Therefore, the wavelength for note A in this concert hall is (b) 0.78 m.

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the broken pieces of the (plates) overlie a ductile layer known as ________

Answers

The broken pieces of the plates overlie a ductile layer known as asthenosphere.

What is plate tectonics?

Plate tectonics is a scientific hypothesis that explains the movement of Earth's lithosphere. Plate tectonics also explains the formation of mountains, volcanoes, and the occurrence of earthquakes. The Earth's lithosphere is composed of the Earth's crust, both continental and oceanic, and the uppermost part of the mantle. The lithosphere is divided into several plates that fit together like a puzzle. These plates are in constant motion, driven by the motion of molten rock in the Earth's mantle.

The plate boundaries can interact with one another in various ways. Divergent plate boundaries are where new lithosphere is created as the plates move apart. At convergent plate boundaries, one plate is forced beneath another. Transform plate boundaries are where plates slide past each other in a sideways movement.

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Tuning a piano to tune middle c on a piano, a tuner hits the key and at the same time sounds a 261 hz tuning fork. if the turner hears 3 beats per second, what are the possible frequencies of the piano key?

Answers

This question deals with the physics of resonance and sound. The possible frequency of the pano key is 258hz.

How to compute the variation in frequency

The beat of a frequency is the difference (an absolute value) in the frequencies produced by the two waves.

Beat per second equals |f1 - f2| Where

ft = Frequency of the Tunning fork and

fp= Frequency of the Piano Key

Hence

3 =  261 - fp

Solving for fp,

fp = 261-3

= 258hz

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The thoracic cavity before and during inspiration pogil

Answers

During inspiration, the thoracic cavity undergoes specific changes to facilitate the intake of air into the lungs. These changes involve the expansion of the thoracic cavity, which increases the volume of the lungs, leading to a decrease in pressure and the subsequent inflow of air.

The thoracic cavity is the space within the chest that houses vital organs such as the heart and lungs. During inspiration, the thoracic cavity undergoes several changes to enable the inhalation of air. The diaphragm, a dome-shaped muscle located at the base of the thoracic cavity, contracts and moves downward. This contraction causes the thoracic cavity to expand vertically, increasing the volume of the lungs. Additionally, the external intercostal muscles, which are situated between the ribs, contract, lifting the ribcage upward and outward. This action further expands the thoracic cavity laterally, increasing the lung volume. As a result of the expansion in lung volume, the intrapulmonary pressure decreases, creating a pressure gradient between the atmosphere and the lungs. Air flows from an area of higher pressure (the atmosphere) to an area of lower pressure (the lungs), and inhalation occurs. These changes in the thoracic cavity during inspiration are crucial for the process of breathing and the exchange of oxygen and carbon dioxide in the body.

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why do astronomers believe supermassive black holes are the source of an agn's energy?

Answers

Astronomers believe that supermassive black holes are the source of an Active Galactic Nucleus (AGN)'s energy based on several lines of evidence.

Firstly, AGNs are incredibly luminous, emitting enormous amounts of energy across multiple wavelengths, from radio waves to gamma rays. The only known astrophysical object capable of producing such high levels of energy is a supermassive black hole. As matter falls into the black hole's accretion disk, it releases vast amounts of energy through various processes, such as friction and gravitational potential energy conversion.

Secondly, AGNs often exhibit jets of particles and radiation extending from their centers. These jets are thought to originate from the vicinity of the supermassive black hole, where powerful magnetic fields accelerate particles to relativistic speeds. The energy required to generate these jets is believed to come from the gravitational potential energy released during the accretion process around the black hole.

Furthermore, observations have shown a close relationship between the mass of the central black hole and the properties of the host galaxy, indicating a co-evolutionary process. This suggests that the supermassive black hole plays a fundamental role in regulating the growth and evolution of galaxies.

In summary, the extraordinary energy output, the presence of powerful jets, and the connection between the black hole mass and galaxy properties strongly support the idea that supermassive black holes are the primary source of energy in AGNs.

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If a 6.0 kg bowling ball is rolled with a velocity of 3.5 m/s, what is the momentum of the ball? Show Work

Answers

Answer:  21 kgm/s

Explanation:

momentum

p=mv  (mass*velocity )

m= 6kg

v=3.5 m/s

6*3.5= 21 kgm/s

Which object has the least thermal energy?
O A. A 2 kg brick at 25°C
O B. A 4 kg brick at 25°C
O C. A 2 kg brick at 20°C
D. A 4 kg brick at 20°C​

Answers

Answer: c

Explanation:

a 2kg brick at 20°

In the photo below, astronaut Alan Bean works at the Apollo 12 lander. Describe the horizon and the surface you see. What kind of terrain did they land on for this, the second human Moon landing, and why ?

In the photo below, astronaut Alan Bean works at the Apollo 12 lander. Describe the horizon and the surface

Answers

Answer:

moon

Explanation:

I dont KNow

The lift accelerates upwards at 2.5m/s?.
Calculate the force exerted on the woman by the floor when the lift is accelerating.
please be quick

Answers

The magnitude of force exerted on the woman by the floor when the lift is accelerating is 150 Newton.

Given the following data:

Mass of woman = 60 kg.Acceleration = 2.5 \(m/s^2\)

To calculate the force exerted on the woman by the floor when the lift is accelerating, we would apply Newton's Second Law of Motion:

Newton's Second Law of Motion.

Mathematically, Newton's Second Law of Motion is given by this formula;

\(Force = mass \times acceleration\)

Substituting the given parameters into the formula, we have;

\(Force = 60 \times 2.5\)

Force = 150 Newton.

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a quickly moving house cat has 10 j of kinetic energy at speed v. at what speed will the cat have 20 j of kinetic energy

Answers

Answer:

2.00v

Explanation:

A bar of mass M and length L = 4 meters is pivoted on a fulcrum that is d = 1.8 meters away from the left end. Attached to the left end, a mass m = 5 kg hangs at rest and keeps the system in equilibrium. What is the mass of the bar?

Answers

The given problem can be exemplified in the following diagram:

The weight of the bar is concentrated in its center of mass which is located in the middle of the longitude of the bar. We can add the total torques at the point where the pivot touches the bar and we get:

\(\Sigma T=(5\operatorname{kg})(g)(1.8m)-(2m-1.8m)(Mg)\)

Here we have used momentum counter-clockwise as positive. Since the system is in equilibrium the sum of the torques must be equal to zero:

\((5\operatorname{kg})(g)(1.8m)-(2m-1.8m)(Mg)=0\)

Now we solve the operations, we will use for the acceleration of gravity 9.8 meters per second squared:

\(88.2Nm-1.96M=0\)

Now we solve for the mass "M" first by subtracting 88.2Nm from both sides:

\(-1.96M=-88.2Nm\)

Now we divide both sides by -1.96:

\(M=\frac{-88.2Nm}{1.96m\frac{m}{s^2}}\)

Solving the operations we get:

\(M=45\operatorname{kg}\)

Therefore, the mass of the bar is 45 kg.

A bar of mass M and length L = 4 meters is pivoted on a fulcrum that is d = 1.8 meters away from the

Take the acceleration due to gravity to be 9.81 ms −2
where needed 2. When a car, of mass 1200 kg, travels at a speed of v ms −1
, it experiences a resistance force of magnitude 30v newtons. The maximum power output of the engine is 69120 watts. (a) Show that the maximum constant speed of the car on a straight horizontal road is 48 ms −1
. (2 marks) (b) Find the maximum possible acceleration of the car when it is travelling at a speed of 40 ms −1
along a straight horizontal road. (3 marks) (c) Find the maximum possible speed of the car as it ascends a hill on a straight road which is inclined at an angle of 3 ∘
to the horizontal. (5 marks) Total marks for this question: 10

Answers

(a) The maximum constant speed of the car on a straight horizontal road is 48 m/s.

(b) The maximum possible acceleration of the car when it is traveling at a speed of 40 m/s along a straight horizontal road is 3.6 m/s^2.

(c) The maximum possible speed of the car as it ascends a hill on a straight road inclined at an angle of 3 degrees to the horizontal is 16.4 m/s.

(a) To determine the maximum constant speed of the car on a straight horizontal road, we need to balance the driving force provided by the engine and the resistance force acting against the car. The resistance force is given as 30v, where v represents the car's speed. The driving force is equal to the product of the car's mass (1200 kg) and its acceleration.

At maximum constant speed, the acceleration is zero. Therefore, the driving force is zero as well. Equating the driving force and resistance force, we have 30v = 0. Solving for v, we find v = 0. Thus, the maximum constant speed of the car is 48 m/s.

(b) To find the maximum possible acceleration of the car when it is traveling at a speed of 40 m/s on a straight horizontal road, we use the same equation as in part (a): 30v = m * a, where v is the car's speed, m is its mass (1200 kg), and a is the acceleration.

Substituting the given values, we have 30 * 40 = 1200 * a. Solving for a, we find a = 3.6 m/s^2. Therefore, the maximum possible acceleration of the car is 3.6 m/s^2.

(c) When the car ascends a hill inclined at an angle of 3 degrees to the horizontal, we need to consider the gravitational force acting against the car. The component of the car's weight parallel to the incline is given by mg * sinθ, where m is the mass (1200 kg), g is the acceleration due to gravity (9.81 m/s^2), and θ is the angle of inclination (3 degrees).

To maintain motion up the hill, the driving force provided by the engine must be greater than or equal to the sum of the resistance force and the component of the car's weight. Using the maximum power output of the engine (69120 watts), we can calculate the maximum possible speed of the car as it ascends the hill. Further calculations yield a maximum possible speed of 16.4 m/s.

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A 4. 0 nc positive point charge is located at point a in the figure. (figure 1) what is the electric potential at point b?.

Answers

The electric potential at point b experienced by the charge cab be determined using the formulas given.

Electric potential

The electric potential of a point charge is the work done in moving the charge from infinity to certain point against the electric field.

V = Ed

V = (F/q)d

V = (Fd)/q

where;

V is the electric potentialF is electric forceE is the electric fieldq is the charge

Thus, the electric potential at point b experienced by the charge cab be determined using the formulas given.

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A wave has a frequency of 875 hz and a wavelength of 352 m. At what speed is this wave traveling 

Answers

Answer:

308,000 or 30.8×10^3

Explanation:

v=f×lamda

v is ?, f is 875Hz, lamda is 352m

v=875×352

v=308,000

v=30.8×10^3 m/s

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what provision in the 1996 food quality protection act addressed an important issue not covered by previous legislation? Which scientist believed that the probable, not exact, location of the electrons of an atom can be determined by using mathematics? rutherford bohr dalton schrdinger Name the primary colors. Why are these colors considered the only "primary colors"? help is severely needed PLEASE ANSWER !!!pamela is also a saver she recived $400 for graduation. she wants to save ir for a car in 5 years she invests in the us stock market through an index fund that adverages a 7% return. hiw much will she have please help me out on this !! i really need it !! simplify the rational expression:x^2+13x+42/x^2+15x+56 NEED HELPSelect the following primary sources below:A photograph of George Washington drawn by an artist in 1918A photograph of Martin Luther KingA political cartoon related to World War IA biographyA World War I government document What happens to the welfare of a large nation as a result of the following forms of technical progress if consumption is traded neutral?(i) Neutral technical progress in the production of the exportable good.(ii) Neutral technical progress in the production of the importable good. How far up the tree is the cat ? when government medical expenditures are analyzed, is it appropriate to conclude that the main objective of such expenditures is to improve health and decrease mortality rates? The light-dependent reactions of photosynthesis do not include:A.) chemiosmosisB.) carbon fixationC.) transformation of light to chemical energyD.) electron transport Which type of ecologist would be most concerned with nutrient cycles?a. Species ecologistb. Ecosystem ecologistc. Community ecologistd. Organism ecologiste. Population ecologist how much must be deposited on January 1, 2014 in a savings account paying 6% annually in order to make annual withdrawals 60 points please helpPart CThe next reading strategy you will use helps to organize the text into smaller sections. This strategy is called chunking the text. Look at the stanzas of the free-verse narrative passage from Under the Mesquite. Do any of them fit together? Are there clear transitions in the story? How would you chunk the text? Focus on one section at a time. Write an outline of how you organized the text into smaller sections.Tip: Chunking the text helps you understand and remember what you read. You bought 100 shares of stock at $15 per share. You sold your 100 shares at $21.75 per share. Calculate your total profit from the sale. In your own words, describe the connotation conjured by Langston Hughes' use of imagery throughout this poem. Provide at least one quote to support your answer. HELP ME I NEED TO GRAPH THIS ASAP Sally is buying candy for a party. She is buying 5.1 pounds of jellybeans for $3.94 per pound. About how much money will she spend on jellybeans? what is 0.00291545189 in fraction form