A rope is shaken and produces 2 waves each second. Calculate the time period of the rope waves.
Answer:
0.5 s
Explanation:
From the question given above, the following data were obtained:
Number of circle (n) = 2
Time (t) = 1 s
Period =?
Period of a wave is simply defined as the time taken to make one complete oscillation. Mathematically, it can be expressed as:
T = t / n
Whereb
T => is the period
t => is the space time
n => is the number of circle or oscillation.
With the above formula, we can obtain the period of the wave as follow:
Number of circle (n) = 2
Time (t) = 1 s
Period =?
T = t / n
T = 1 / 2
T = 0.5 s
Thus, the period of the wave is 0.5 s
In the rocket, what is the equal and opposite reaction?
Answer:
see below
Explanation:
Gases flying out at high velocity out the back
rocket flying forward
A solenoid with a length of 6.5 cm and 200 loops is carrying 5 A of current. What is the
strength of the magnetic field at the center of the solenoid? Label the north and south pole of
the solenoid.
The strength of the magnetic field at the center of the solenoid is 0.006 T
Magnetic field calculation.
The strength of the magnetic field at the center of a solenoid is given by:
B = μ₀ * n * I
where B is the magnetic field strength, μ₀ is the permeability of free space, n is the number of turns per unit length of the solenoid, and I is the current flowing through the solenoid.
In this case, the length of the solenoid is not given, but we can assume that it is much greater than the diameter of the solenoid, so we can treat it as a long solenoid. The number of turns per unit length is given as 200 loops divided by the length of 6.5 cm, or:
n = 200 / 0.065 m = 3076.92 turns/m
The current flowing through the solenoid is 5 A.
The permeability of free space, μ₀, is a constant with a value of 4π x 10^-7 T m/A.
Therefore, the magnetic field strength at the center of the solenoid is:
B = μ₀ * n * I
= 4π x 10^-7 T m/A * 3076.92 turns/m * 5 A
= 0.006 T
So the strength of the magnetic field at the center of the solenoid is 0.006 T. The north pole of the solenoid is the end from which the magnetic field emerges, and the south pole is the end where it enters.
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If a nearsighted person has a far point df that is 3.50m from the eye, what is the focal length f1 of the contact lenses that the person would need to see an object at infinity clearly? Express your answer in meters. If a farsighted person has a near point that is 0.600m from the eye, what is the focal length f2 of the contact lenses that the person would need to be able to read a book held at 0.350m from the person's eyes? Express your answer in meters.
The range at which an object can be seen clearly is referred to as the far range of the eye. The closest object can be seen clearly and without strain at the eye's near point, which is also the shortest distant object.
What is the myopia eye's far point?A myopic eye's far point is immediately anterior to a corneal plane. As they reach the eye, the rays coming from this point are still highly divergent. Rays coming from the far spot end up highly concentrated at the retina because this divergence balances out the excessive converge that is integrated into the myopic eye.
How far away is the myopic eye at 40 cm?The myopic person's (u) far point is 40 cm away. Final thought The place to start for the this question is 40 cm from the viewer and is a case of myopia. Therefore, the lens's focal length will be -40cm, or -0.4m.
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If two objects of the different masses are pushed with the same force; which will travel faster?
what is the minimum power that the engine of a 560kg car has to deliver to accelerate the car from rest to 100km/he in 6.0second
Answer:
what is the minimum power that the engine of a 560kg has to deliver to accelerate the car from the rest to 100 kilometers/he in 6.0 seconds per feet
Explanation:
the car's weight kilometeresseconds the car is going acceleration of the speed it is going at ofCalculate the average kinetic energy of the cup for the 100 mL and 400 mL masses.
show the work please
Answer:
169ml
Explanation:
Is there any difference between frame of reference and reference point in physics?
Answer: A frame of reference is a reference point combined with a set of directions. A frame of reference is similar to the idea of a reference point. A frame of reference is defined as a reference point combined with a set of directions. For example, a boy is standing still inside a train as it pulls out of a station.
Explanation: hope this helps!!!!
Which of the following statements concerning electrostatic situations is FALSE? (a) E is zero everywhere inside a conductor. (b) Equipotential surfaces are always perpendicular to E.(c) It takes zero work to move a charge along an equipotential surface. (d) If V is constant throughout a region of space the E must be zero in that region. (e) No force component acts along the path of a charge as it is moved along an equipotential surface.
The statement that is FALSE concerning electrostatic situations is (d) If V is constant throughout a region of space, the E must be zero in that region.
This statement is incorrect because it is possible for E to be non-zero even when the potential is constant. This occurs when there is a non-zero charge density present in the region. In such cases, the electric field is proportional to the gradient of the potential, which can be non-zero even when the potential is constant.
The other statements are true in electrostatic situations:
(a) E is zero everywhere inside a conductor: This is true because charges in a conductor are free to move, and they will rearrange themselves until the electric field inside the conductor is zero.
(b) Equipotential surfaces are always perpendicular to E: This is true because the electric field is perpendicular to the equipotential surfaces.
(c) It takes zero work to move a charge along an equipotential surface: This is true because the potential is constant along an equipotential surface, and the work done by an electric field on a charge is given by the product of the charge and the potential difference, which is zero when the potential is constant.
(e) No force component acts along the path of a charge as it is moved along an equipotential surface: This is true because the electric field is perpendicular to the equipotential surfaces, so there is no force component along the path of the charge.
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A 590g , 9.0-cm-diameter can is filled with uniform, dense food. It rolls across the floor at 1.2m/sWhat is the can's kinetic energy?
The kinetic energy of A 590g , 9.0-cm-diameter can is filled with uniform, dense food. It rolls across the floor at 1.2m/s is 1.6992 J
What is the kinetic energy?Kinetic energy can be defined as the form of energy possessed by a body due to its motion or change in velocity (acceleration).
Question Parameter(s):
A 590 g , 9.0-cm-diameter can is filled with uniform, dense food. It rolls across the floor at 1.2 m/s .
Generally, the equation for the Kinetic energy is mathematically given as
KE = 1/2mv²
K.E= 1/2 (0.59) (1.2)²
K.E=0.42J
In conclusion, the can's kinetic energy
K.E=1.6992 J
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Which of these events is an example of the Doppler shift?
As a star forms, put the following in order of their occurrence:
-Nuclear reactions begin and a star is born
-Clumps form from static electricity
-A wind blows from the central star.
-A disk forms because angular momentum is conserved
-A cloud contracts under gravity
-Planitesimals form from collision
The correct order of occurrence as a star forms:
A cloud contracts under gravity.A disk forms because angular momentum is conserved.Nuclear reactions begin and a star is born.Clumps form from static electricity.Planetesimals form from the collision.A wind blows from the central star.A star is a massive, luminous celestial object that is held together by its own gravity and emits light and other forms of radiation. Stars are formed from clouds of gas and dust that collapse under the force of gravity, and as the cloud collapses, it heats up and ignites, triggering a nuclear fusion reaction that produces immense amounts of energy. This energy is released in the form of light and heat, which radiate outwards into space.
Stars come in a variety of sizes, colors, and temperatures, and they play a crucial role in the universe by creating and distributing heavy elements, which are essential building blocks for planets, life, and the universe as a whole. They also provide energy for photosynthesis, which is the foundation of most ecosystems on Earth.
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It took 89.5 degrees to stop the wheel from 47.8 rpm. What is the angular acceleration?
Given:
The angular displacement, θ=89.5°
Initial angular velocity, ω₀=47.8 rpm
Final angular velocity, ω=0 rad/s
To find:
The angular acceleration of the wheel.
Explanation:
The angular velocity can be converted to rad/s as,
\(\begin{gathered} \omega_0=\frac{47.8\times2\pi}{60} \\ =5\text{ rad/s} \end{gathered}\)The angle is converted into the radians as,
\(\begin{gathered} \theta=\frac{89.5\times\pi}{180} \\ =1.56\text{ rad} \end{gathered}\)From the equation of motion,
\(\omega^2-\omega^2=2\alpha\theta\)Where α is the angular acceleration of the wheel.
On substituting the known values,
\(\begin{gathered} 0^2-5^2=2\times\alpha\times1.56 \\ \implies\alpha=\frac{-5^2}{2\times1.56} \\ =-8.01\text{ rad/s}^2 \end{gathered}\)Final answer:
Thus the angular acceleration of the wheel is -8.01 rad/s²
what equation links charge flow, current and time?
I will award Brainliest if CORRECT!
Answer:
Q=it
Explanation:
\( \purple {\bold {Q = it}} \) is the equation equation that links charge flow, current and time.
Here,
Q = Charge
i = current
t = time
Suppose now that we add two plane waves, E, and E2, (superposition still works!) to find the total electric field. Let E (r.) =E, cos(k. rwt +8.) and E:{r./) =Excos(kr-wt +8) so in this simple case the waves propagate in the same direction. Let's say the amplitudes are Ei Eiz and E2E z. Use complex notation (taking the real part only at the very end) to find Ex(r.1) - Ei(r.1)+E2(1,7) in the form Ey(r.1) =ET cos(klr #+giving expressions for the total amplitude and phase shift in terms of those from E (r.1) and Ex(r.1)
Ex(r, t) = Re[Ey(r, t)] = ET * cos(kr - ωt + Φ). This expression gives the total amplitude and phase shift in terms of E (r.1) and Ex(r.1) of the plane wave.
To find the total electric field Ex(r, t) by adding two plane waves E₁(r, t) and E₂(r, t) with the given expressions, we will use complex notation and superposition.
First, let's write E₁ and E₂ in complex notation:
E₁(r, t) = E₁z * exp[i(kr - ωt + δ₁)]
E₂(r, t) = E₂z * exp[i(kr - ωt + δ₂)]
Now, we add them together:
Ex(r, t) = E₁(r, t) + E₂(r, t)
Ex(r, t) = E₁z * exp[i(kr - ωt + δ₁)] + E₂z * exp[i(kr - ωt + δ₂)]
Next, let's factor out the common term exp[i(kr - ωt)]:
Ex(r, t) = exp[i(kr - ωt)] * (E₁z * exp[iδ₁] + E₂z * exp[iδ₂])
Now, we can define a total amplitude ET and phase shift Φ:
ET * exp[iΦ] = E₁z * exp[iδ₁] + E₂z * exp[iδ₂]
By finding ET and Φ, we can write the total electric field as:
Ey(r, t) = ET * cos(kr - ωt + Φ)
Finally, to obtain the real part of the total electric field, take the real part of Ex(r, t):
Ex(r, t) = Re[Ey(r, t)] = ET * cos(kr - ωt + Φ)
This gives us the total electric field Ex(r, t) in terms of the amplitudes E₁z, E₂z and phase shifts δ₁, δ₂ of the two plane waves E₁(r, t) and E₂(r, t).
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A light spring with force constant 3.70 N/m is compressed by 8.64 cm as it is held between a 0.261-kg block on the left and a 0.522-kg block on the right, both resting on a horizontal surface. The spring exerts a force on each block, tending to push them apart. The blocks are simultaneously released from rest. Find the acceleration with which each block starts to move, given that the coefficient of kinetic friction between each block and the surface is the following. (Let the coordinate system be positive to the right and negative to the left. Be sure to include the sign to indicate the direction of the acceleration.) (a) μ = 0 heavier block lighter block (b) μ = 0.110 heavier block lighter block (c) μ = 0.480 heavier block lighter block m/s² m/s² m/s² m/s² m/s² m/s²
The lighter block will also accelerate to the right with an acceleration of -0.82 m/s².
(a) μ = 0
The heavier block will accelerate to the right with an acceleration of:
a = F / m = k x / m = (3.70 N/m) (0.0864 m) / 0.261 kg = 1.22 m/s²
The lighter block will also accelerate to the right with an acceleration of 1.22 m/s².
(b) μ = 0.110
The heavier block will accelerate to the right with an acceleration of:
a = F - μk / m = k x / m - μk / m = (3.70 N/m) (0.0864 m) / 0.261 kg - (0.110)(0.261 kg)(9.80 m/s²) = 0.68 m/s²
The lighter block will not accelerate because the force of friction is greater than the force of the spring.
(c) μ = 0.480
The heavier block will accelerate to the right with an acceleration of:
a = F - μk / m = k x / m - μk / m = (3.70 N/m)(0.0864 m) / 0.261 kg - (0.480)(0.261 kg) (9.80 m/s²) = -0.82 m/s²
Therefore, the lighter block will also accelerate to the right with an acceleration of -0.82 m/s².
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Determine the present value of the following single amounts (FV of $1, PV of $1, FVA of $1, PVA of $1, FVAD of $1 and PVAD of $1)
FV= $20,000 I=7% N=10 PV= ?
FV= $14,000 I=8% N=12 PV= ?
FV= $25,000 I=12% N=20 PV= ?
FV= $40,000 I=10% N=8 PV= ?
The present value of the following single amounts are as follows;
PV for FV = $20,000, I =7%, N =10 years is $10,155.84
PV for FV = $14,000, I =8%, N =12 years is $4,489.92
PV for FV = $25,000, I =12%, N =20 years is $2,590.11
PV for FV = $40,000, I =10%, N =8 years is $18,520.89.
Future value (FV) =$20,000,
Interest rate (I) =7%,Time (n) = 10 years
The present value (PV) can be calculated as follows;
PV = FV / (1 + i)n = 20000 / (1 + 0.07)10PV = 20000 / 1.96715PV = $10,155.84
Future value (FV) =$14,000,
Interest rate (I) =8%,
Time (n) = 12 years
The present value (PV) can be calculated as follows;
PV = FV / (1 + i)n = 14000 / (1 + 0.08)12PV = 14000 / 3.12159PV = $4,489.92
Future value (FV) =$25,000,
Interest rate (I) =12%,Time (n) = 20 years
The present value (PV) can be calculated as follows;
PV = FV / (1 + i)n = 25000 / (1 + 0.12)20PV = 25000 / 9.64632PV = $2,590.11
Future value (FV) =$40,000,Interest rate (I) =10%,Time (n) = 8 years
The present value (PV) can be calculated as follows;
PV = FV / (1 + i)n = 40000 / (1 + 0.1)8PV = 40000 / 2.15893PV = $18,520.89
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what would happen if the louisiana purchase did not double the United States?
Answer:
The Louisiana Purchase eventually doubled the size of the United States, greatly strengthened the country materially and strategically, provided a powerful impetus to westward expansion, and confirmed the doctrine of implied powers of the federal Constitution.
For the circuit shown in the figure, the current in the 8 resistor is 0.50 A, and all quantities are accurate to 2 significant figures. What is the current in the 2 resistor?
The current through the 2Ω resistor is 9.5A
The terminal voltage is 10.8 V
How to calculatea) The voltage V across 8 Ω resistor is V = I*R = 8*0.5 = 4V
the current through 16Ω resistor is then I = V/R = 4/16 = 0.25 A
the current through 20Ω resistor is then I = current through 8Ω resistor + current through 16Ω resistor = 0.75 A
voltage across 20Ω is V = I*R = 0.75*20 = 15 V
the source voltage is Vs = V8 + V20 = 4+15 = 19 V
therefore the current through 2Ω resistor is
I = V/R = 19/2 = 9.5 A
b) The terminal voltage is
Vterminal = VR = I*R = 0.450*24 = 10.8 V
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If a toy train has a mass of 1.5 KG and accelerates at a rate of 20 M/S 2 calculate force acting on it?
Answer:
F = 30 N
Explanation:
Given that,
Mass of a toy train, m = 1.5 kg
The acceleration of the toy-train, a = 20 m/s²
We need to find the force acting on it. We know that, net force acting on an object is given by :
F = ma
Substitute all the values,
F = 1.5 × 20
F = 30 N
Hence, the net force acting on the toy train is equal to 30 N.
A small block sits at one end of a flat board that is 4.00 m long. The coefficients of friction between the block and the board are jis = 0.450 and pk = 0.400. The end of the board where the block sits is slowly raised until the angle the board makes with the horizontal is ao, and then the block starts to slide down the board. Part A If the angle is kept equal to ao as the block slides, what is the speed of the block when it reaches the bottom of the board? Express your answer with the appropriate units. Ii UA ? V= Value Units
The speed of the block when it reaches the bottom of the board is X m/s.
To determine the speed of the block at the bottom of the board, we need to consider the forces acting on the block and the conservation of energy. When the block is sliding down the board, the force of gravity acts on it, and there is also a frictional force opposing its motion.First, we calculate the height difference (Δh) between the starting position and the bottom of the board. This is given by Δh = 4.00 m * sin(αo), where αo is the angle the board makes with the horizontal.Next, we calculate the work done by gravity on the block as it slides down the board. This work is equal to the change in potential energy, which is m * g * Δh, where m is the mass of the block and g is the acceleration due to gravity.Finally, using the work-energy principle, we equate the work done by gravity to the kinetic energy of the block at the bottom. Therefore, 0.5 * m * v^2 = m * g * Δh, where v is the speed of the block at the bottom
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PLEASE HELP ASAP!! DUE IN AN HOUR :’))!!
Answer: The object moves with constant velocity
Explanation:
In this velocity vs time graph we're dealing with Ap physics or regents physics. If we look at the slope we can see it is constant or not changing. Even so lets check the other answers and prove them wrong
The objects speed increases: This is wrong because the line shows a steady 5m/s with no change
The object is in free fall: If the object was in freefall the speed would be increasing as a result of acceleration due to gravity
The object moves with a constant speed: This seems to be the case since the slope or line doesn't change at all
The object stays at rest: Can't be right because the object is at a speed of 5m/s so we know its moving at least
The objects speed decreases: Again the line isn't going up or down so we can't say speed increases or decreases
a. A random sample of 150 approved mortgage applications is
selected from a bank’s database. Customers of this bank can choose
either variable or interest-only mortgages. These mortgage choices
have
Out of 150 approved mortgage applications, a random sample may have variable or interest-only mortgages.
we are given that a random sample of 150 approved mortgage applications is either variable or interest-only mortgages. A variable mortgage, also known as an adjustable-rate mortgage (ARM), is a type of mortgage in which the interest rate fluctuates based on market conditions. An interest-only mortgage is a type of mortgage in which the borrower only pays interest on the loan for a certain period of time before beginning to make principal payments.To determine what percentage of the sample is variable or interest-only mortgages, we would need more information on the breakdown of the sample. However, we know that these are two different types of mortgages that borrowers can choose from when applying for a mortgage.
A home loan application is a report submitted to a bank when you apply for a home loan to buy land. The application is extensive and includes information about the borrower's employment history, financial situation, and the property being considered for purchase, among other things.
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What is the potential difference across a circuit that delivers 4.2A to a 500W motor?
Answer:
Thus, the potential difference is 119 V.
Explanation:
Current, I = 4.2 A
Power, P = 500 W
The rate of doing work is called power.
The SI unit of power is Watt.
The commercial unit of power is horse power.
1 horse power = 746 Watt
The formula of the electrical power is
P = V I
where, V is the voltage and I is the current.
Substitute the values in the formula
500 = 4.2 x V
V = 119 V
suppose the coil and the magnet in figure a above were each moving with the same velocity relative to the earth. would there be an induced current in the coil? explain\
No, there would be no induced current in the coil in this case.
A coil is a series of loops of wire that are wrapped around a central core. It is often used in electrical circuits to create a magnetic field or to convert electrical energy into mechanical energy.
The reason for this is that the changing magnetic field that induces a current in the coil is produced by the relative motion of the coil and the magnet. There would be no relative motion between the coil and the magnet if they were both travelling at the same velocity relative to the earth, and hence no changing magnetic field. As a result, no induced current would flow through the coil.
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pls help answer embed
Answer:
C = 1.01
Explanation:
Given that,
Mass, m = 75 kg
The terminal velocity of the mass, \(v_t=60\ m/s\)
Area of cross section, \(A=0.33\ m^2\)
We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,
Weight of the object = drag force
R = W
or
\(\dfrac{1}{2}\rho CAv_t^2=mg\)
Where
\(\rho\) is the density of air = 1.225 kg/m³
C is drag coefficient
So,
\(C=\dfrac{2mg}{\rho Av_t^2}\\\\C=\dfrac{2\times 75\times 9.8}{1.225\times 0.33\times (60)^2}\\\\C=1.01\)
So, the drag coefficient is 1.01.
The coefficient of kinetic friction between a couch and the floor is 0.65. If the
couch has a mass of 42 kg and you push it with a force of 600 N, what is the
net force on the couch as it slides?
A. 868 N
B. 188 N
C. 452 N
O D. 332 N
Answer: D. 332n
Explanation: I took the quiz and that was the correct answer
Where is Earth’s magnetic south pole located? What about the magnetic north pole? What does this say about how a compass needle will react to the poles?
Answer:
Currently, the magnetic south pole lies about ten degrees distant from the geographic north pole, and sits in the Arctic Ocean north of Alaska. The north end on a compass therefore currently points roughly towards Alaska and not exactly towards geographic north.
Explanation:
When fireworks explode, sound and light are produced. These are examples of
macroscopic outputs
microscopic outputs
microscopic inputs
macroscopic inputs
Answer: Macroscoptic Output
Explanation:
Answers to the rest:
1. B) macroscopic outputs.
2.A) a microscopic change creating a macroscopic output
3.B) Because the energy levels of the electrons in different metals are usually not the same, different metals usually emit different colors of visible light.
4.A) Heat is applied to a solid, causing its molecules to move quickly.
5.A) strontium, sodium, copper, potassium
When fireworks explode, sound and light are produced, these are examples of macroscopic outputs.
The macroscopic scale is a scale where objects are large enough to be visible using the eyes or any other sense.Fireworks produce sufficient sound and light to be observed without the need for any specific device.Conversely, microscopic scale refers to the scale in which we cannot be observed by using the eye and we need specific tools to observe these phenomena (e.g., a microscope).In conclusion, when fireworks explode, sound and light are produced, these are examples of macroscopic outputs.
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Calculate the speed in m/s of a skateboarder who accelerates from rest for 3 seconds down a ramp at an acceleration of 5m/s2
Answer: 15m/s
Explanation: