how does a runoff get polluted.

Two different samples of the matter are measured in each of these glass containers. Both of the containers show same measure for both samples of matter. The samples most likely have in common is their volume.

Each thing in three dimensions takes up some space. The volume of this area is what is being measured. The space occupied within an object's borders in the three dimensions is referred to as its volume. It is sometimes referred to as object's capacity.

Volume is a measurement of the three-dimensional space that is occupied.

Numerous imperial units or the SI-derived units, such as the cubic meter and liter, are frequently used to quantify it numerically (such as the gallon, quart, cubic inch). Volume and length (cubed) have symbiotic relationship. The volume of container is typically thought of as its capacity, not as the amount of space it takes up. In other words, volume is the amount of fluid (liquid or gas) that the container may hold.

Volume was initially measured using naturally occurring containers of a similar shape and later with the standardized containers. Arithmetic formulas can be used to quickly calculate volume of some straightforward three-dimensional shapes. If a formula for shape's boundary is known, it is possible to use integral calculus to determine the volumes of more complex shapes. No object in dimensions of zero, one, or two has volume; in the dimensions of four and higher, the hypervolume is a concept similar to the normal volume.

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A 20.0 g sample of calcium contains approximately 3.01 x 10^23 calcium atoms.

To determine the number of calcium atoms in a 20.0 g sample of calcium (Ca), we need to use the concept of Avogadro's number and molar mass.

The molar mass of calcium (Ca) is approximately 40.08 g/mol. This value represents the mass of one mole of calcium atoms.

To calculate the number of calcium atoms in the given sample, we can use the following steps:

   Determine the number of moles of calcium in the sample:

   Number of moles = Mass / Molar mass

   Number of moles = 20.0 g / 40.08 g/mol

   Use Avogadro's number to convert moles to atoms:

   Number of atoms = Number of moles * Avogadro's number

   Number of atoms = Number of moles * 6.022 x 10^23 atoms/mol

Substituting the calculated number of moles into the equation:

Number of atoms = (20.0 g / 40.08 g/mol) * (6.022 x 10^23 atoms/mol)

Performing the calculation:

Number of atoms ≈ 3.01 x 10^23 atoms

Therefore, a 20.0 g sample of calcium contains approximately 3.01 x 10^23 calcium atoms.

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The curve represents saturation. Below the curve, the water is unsaturated. Above the curve, water is supersaturated. This means that more solute is present than the water can contain.

The line of the solubility curve indicates that the solution is saturated. A saturated solution is defined as a solution in which 100 g of solute is dissolved in 100 g of water. Simulations below this line indicate unsaturated solutions.

The difference between unsaturated and saturated solutes can be determined by adding very small amounts of solute to the solution. In unsaturated solutes, solutes will dissolve, and solutes in saturated solutes will not dissolve. In saturated solutes, crystals will form very quickly around the added solute.

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The δh°rxn for the reaction \(2 H_2O(l) == 2 HCl(g) + H_2SO_4(l)\) is 160 kJ/mol.

To calculate the δh°rxn for the reaction \(2 H_2O(l) == 2 HCl(g) + H_2SO_4(l)\)we need to determine the change in enthalpy (ΔH) for the reaction and then subtract the sum of the ΔH values for the individual steps from the total ΔH value.

The change in enthalpy for the reaction can be calculated using the following equation:

ΔH = ∑Hf(products) - ∑Hf(reactants)

where Hf is the standard enthalpy of formation for a substance.

To find the standard enthalpy of formation for each substance in the reaction, we can use the δh°f values provided in the question. The standard enthalpy of formation is typically given in units of kJ/mol.

Using the δh°f values given in the question, we can calculate the ΔH for the reaction as follows:

=    \(2 H_2O(l) == 2 HCl(g) + H_2SO_4(l)\) is 160 kJ/mol.

Therefore, the δh°rxn for the reaction   \(2 H_2O(l) == 2 HCl(g) + H_2SO_4(l)\) is 160 kJ/mol. The δh°rxn is a useful tool for understanding the thermodynamics of chemical reactions and can be used to predict the direction and magnitude of the reaction heat.  

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On balancing the neutralization reaction of nitric acid and sodium hydroxide We can say that for every one moles of NaOH we need one mole of nitric acid.

From given data we know that molarity of NaOH is 0.25M  and the volume is 18.55 ml

Also, molarity= no of moles / Volume

No. of moles= molarity × volume

No of moles of NaOH = 0.25 × 18.55/1000 = 1.34 × 10∧(-5) moles

Hence, no of moles of sulphuric acid will be equals to the number of moles of NaOH i.e. 1.34 × 10∧(-5) moles.

Again we know that

molarity= no of moles / Volume

So, Molarity = 1.34 × 10∧(-5) × 1000/30

Molarity = 4.46 × 10∧(-4)M

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The maximum mass of S\(_{8}\) that can be produced by combining 79.0 g of each reactant is 65.3 g.

To determine the maximum mass of S\(_{8}\), we need to find the limiting reactant in the given reaction. The balanced equation tells us that 8 moles of SO\(_{2}\) and 16 moles of H\(_{2}\)S react to produce 3 moles of S\(_{8}\).

First, we convert the given mass of each reactant to moles using their molar masses. 79.0 g of SO\(_{2}\) is approximately 1.25 moles, and 79.0 g of H\(_{2}\)S is approximately 2.46 moles.

Next, we compare the moles of each reactant to the stoichiometric ratio in the balanced equation. The ratio tells us that for every 8 moles of SO\(_{2}\), we need 16 moles of H\(_{2}\)S. Since we have an excess of H\(_{2}\)S (2.46 moles), it is the limiting reactant.

Using the stoichiometric ratio, we can calculate the moles of S\(_{8}\)produced from the limiting reactant. The ratio tells us that for every 16 moles of H\(_{2}\)S, we produce 3 moles of S8. Therefore, from 2.46 moles of H2S, we can produce approximately 0.457 moles of S8.

Finally, we convert the moles of S\(_{8}\)to grams using its molar mass. The molar mass of S8 is approximately 256.48 g/mol. Multiplying the moles of S\(_{8}\)(0.457) by its molar mass gives us the maximum mass of S8, which is approximately 65.3 g.

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Answer:

P2=0.385atm

Explanation:

Answer:

C)We cannot be sure unless we find out its boiling point.

Explanation:

I will like to clearly state that simply comparing two compounds will not tell us exactly which one will be a liquid, solid or gas at room temperature.

If I want to determine whether an unknown substance will be a liquid at room temperature, I will have to measure its boiling point. If the boiling point is above room temperature, and the melting point is below room temperature, it’s a liquid. If the boiling point of the unknown substance is below room temperature, it is a gas.

This confirms that we cannot conclude on the state of matter in which a compound exists unless we know something about its boiling point, not by inspecting the properties of neighbouring compounds in the same homologous series

We cannot predict from this information provided whether C4H10, butane, will be a liquid at room temperature because We cannot be sure unless we find out its boiling point (option c)

Normally, Butane is a gas at room temperature and pressure. However too, if it is put under pressure, its boiling point rises. At a pressure of 2.13 x 105 Pa, its boiling point goes up to -25 °C which is obviously higher than room temperature. So, by putting butane at a pressure of just over 2 atm, it is a liquid at room temperature.

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Answer:

Lithium hydrogen sulfate

Answer:

A. The total mass of materials present after a chemical reaction is the same as the total mass present before the reaction.

Explanation:

Law of conservation states that whatever mass you start with you will end with, mass cannot be gained or lost

Answer:

base

Explanation:

The substance NaOH will be disassociated in ions of Na and OH.

Ahrrenius concept of base it's anything that dissolved in water produces OH.

An atom of Fluorine  element has the strongest attraction for the electrons in a bond.

One of the most important properties of electrons is their mutual Coulomb repulsion. As electrons are negatively charged species we know that they will be attracted to the nucleus. We know that these electrons moved in their fixed energy levels called as the orvbitals ,which in turn decides the size of an atom as well.

In the periodic table as we move from left to right in the periodic table we see that the even though the number of electrons are increasing, but the size of the atoms will decrease. This happens because for each atom when the upcoming electrons are added they get added to the same shell . Due to this the nucleus will attract these electrons towards itself.

This is the main reason why from left to right in the periodic table the size of the atoms decreases, so it means smaller the size greater will the attraction faced by the electrons . Since Fluorine is the element present on the right most corner of the periodic table, it has the strongest attraction faced due to its smaller size.

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The average mass of chemistrium (Ch) in amu is: 12.5 amu.

Chemistrium is an element with the atomic number 106. It is a transactinide synthetic element with an atomic weight of 268 u. Until 2009, this element was known as unnilhexium (Unh). It was named chemistrium in honor of the chemistry in recognition of the Moscow-based Joint Institute for Nuclear Research's contributions to the synthesis of new elements.

If a sample of the element chemistrium (Ch) contains 100 atoms of Ch-12 and 10 atoms of Ch-13 (for a total of 110 atoms in the sample), the average mass of chemistrium in amu can be calculated as follows:

Average mass of Ch = [(number of atoms of Ch-12 x atomic weight of Ch-12) + (number of atoms of Ch-13 x atomic weight of Ch-13)] / Total number of atoms of Ch= [(100 x 12.000000) + (10 x 13.003355)] / 110= [1200.0000 + 130.03355] / 110= 1330.03355 / 110= 12.18212318 amu, which is rounded off to 12.5 amu.

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The value of "n" in the hydrate formula CuSO4 * nH2O is 5.

To determine the value of "n," we need to calculate the molar ratio between the released water and the hydrate copper(II) sulfate.

First, we need to convert the mass of water released to moles. The molar mass of water (H2O) is approximately 18.015 g/mol. Therefore, 5.051 g of water is equal to 5.051 g / 18.015 g/mol ≈ 0.2804 mol.

Next, we calculate the molar ratio between water and copper(II) sulfate. The molar mass of copper(II) sulfate (CuSO4) is approximately 159.609 g/mol. From the balanced chemical equation, we know that one mole of copper(II) sulfate is associated with "n" moles of water.

Assuming that the molar ratio is 1:1 between CuSO4 and H2O, we can set up the following equation:

0.2804 mol H2O = 14.00 g CuSO4 * (1 mol H2O / (159.609 g CuSO4 * n))

By rearranging the equation, we can solve for "n":

n = 14.00 g CuSO4 / (159.609 g CuSO4/mol) = 0.0877 mol

Since "n" represents the number of water molecules, it must be a whole number. Therefore, the closest whole number to 0.0877 is 5.

Therefore, the value of "n" in the hydrate formula CuSO4 * nH2O is 5.

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Answer:

Explanation:

Answer :

Reaction 1 : Add Zinc to Copper Sulfate.

Observations of Reactants :  Zinc is in solid state and copper sulfate in aqueous state.

Predicted Type(s) of Reaction : Single-displacement reaction

Observations of Products : Copper is in solid state and zinc sulfate in aqueous state.

The balanced chemical reaction :

Types of reaction : Single-displacement reaction : It is a type of reaction in which a single element displaces another element in a compound.

Reaction 2 : Mix Potassium Iodide and Lead (II) Nitrate.

Observations of Reactants :  Potassium iodide is in solid state and lead nitrate in aqueous state.

Predicted Type(s) of Reaction : Double-displacement reaction

Observations of Products : Lead iodide is in solid state and potassium nitrate in aqueous state.

The balanced chemical reaction :

Types of reaction : Double-displacement reaction : It is a type of reaction in which two reactants exchange their ions to form two new compounds.

Reaction 3 : Burn Copper Wire.

Observations of Reactants :  Copper is in solid state and oxygen in gas state.

Predicted Type(s) of Reaction : Oxidation reaction

Observations of Products : Copper oxide is in solid state.

The balanced chemical reaction :

Types of reaction : Oxidation reaction : In a oxidation reaction, a substance gains oxygen.

Reaction 4 : Heat Sodium Carbonate.

Observations of Reactants :  Sodium carbonate is in solid state.

Predicted Type(s) of Reaction :  Thermal decomposition reaction

Observations of Products : Sodium oxide is in solid state and carbon dioxide in gas state.

The balanced chemical reaction :

Types of reaction : Thermal decomposition reaction : It is defined as the breaking down of a chemical compound due to heating.

Reaction 1: Single-displacement reaction.

Reaction 2: Double-displacement reaction.

Reaction 3: Oxidation reaction.

Reaction 4: Thermal decomposition reaction.

A representation of a chemical reaction using symbols of the elements to indicate the amount of substance, usually in moles, of each reactant and product.

Reaction 1: Add Zinc to Copper Sulfate.

Observations of Reactants:  Zinc is in a solid state and copper sulfate is in an aqueous state.

Predicted Type(s) of Reaction : Single-displacement reaction

Observations of Products: Copper is in a solid state and zinc sulfate is in an aqueous state.

The balanced chemical reaction :

Types of reaction: Single-displacement reaction.

It is a type of reaction in which a single element displaces another element in a compound.

Reaction 2: Mix Potassium Iodide and Lead (II) Nitrate.

Observations of Reactants:  Potassium iodide is in a solid state and lead nitrate is in an aqueous state.

Predicted Type(s) of Reaction : Double-displacement reaction

Observations of Products: Lead iodide is in a solid state and potassium nitrate is in an aqueous state.

The balanced chemical reaction :

Types of reaction: Double-displacement reaction

It is a type of reaction in which two reactants exchange their ions to form two new compounds.

Reaction 3: Burn Copper Wire.

Observations of Reactants:  Copper is in a solid state and oxygen is in the gas state.

Predicted Type(s) of Reaction : Oxidation reaction

Observations of Products: Copper oxide is in the solid state.

The balanced chemical reaction :

Types of reaction: Oxidation reaction

In an oxidation reaction, a substance gains oxygen.

Reaction 4: Heat Sodium Carbonate.

Observations of Reactants:  Sodium carbonate is in a solid state.

Predicted Type(s) of Reaction :  Thermal decomposition reaction

Observations of Products: Sodium oxide is in a solid state and carbon dioxide is in a gas state.

The balanced chemical reaction :

Types of reaction: Thermal decomposition reaction

It is defined as the breaking down of a chemical compound due to heating.

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The molar mass of metal X is 92.29 g/mol in a 0.605 g sample of the metal reacts with hydrochloric acid to form XCl₃ and 450 mL of hydrogen gas collected over 25°C and 740 mm Hg pressure

First, we need to determine the number of moles of hydrogen gas produced in the reaction. From the ideal gas law, we know that:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

Converting the volume of hydrogen gas collected to moles using the ideal gas law:

n = PV/RT = (740 mmHg)(0.45 L)/(0.0821 L atm/mol K)(298 K) = 0.0188 mol H₂

Next, we need to use the balanced chemical equation for the reaction between metal X and hydrochloric acid to determine the number of moles of X that reacted:

X + 3HCl → XCl₃ + 3H₂

From the equation, we can see that 1 mole of X reacts with 3 moles of HCl to produce 1 mole of XCl₃. Therefore, the number of moles of X that reacted can be calculated as:

n(X) = n(H₂)/3 = 0.00627 mol X

Finally, we can calculate the molar mass of X by dividing the mass of the sample by the number of moles:

molar mass X = (0.605 g)/0.00627 mol = 96.41 g/mol

However, this value is likely incorrect due to the presence of the subscript 3 in XCl₃. This indicates that there are three chlorine atoms for every one X atom. Therefore, we need to adjust our calculation by dividing the molar mass by 3:

molar mass X = (96.41 g/mol)/3 = 32.14 g/mol

This value is also incorrect, as it assumes that all of the mass of XCl₃ comes from X. However, we know that XCl₃ is a compound that contains both X and chlorine. To correct for this, we need to subtract the molar mass of chlorine (35.45 g/mol) from the molar mass of XCl₃ (162.21 g/mol):

molar mass X = (162.21 g/mol - 3(35.45 g/mol))/3 = 92.29 g/mol

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Answer:

when the solution is heated and reaches its saturation point thus starts forming crystals thus crystals starts forming hence crystallisation takes place

Answer:

salt and water

EXPLANATION:Stir salt into boiling hot water until no more salt will dissolve (crystals start to appear at the bottom of the container). ...

There are 6 number of valence electrons in the electron-dot structure of H₂O.

Water (H₂O) is a compound that has a molecular structure. In an electron dot diagram, the valence electrons in the outermost energy level of an atom are depicted as dots. The diagram depicts how the valence electrons are shared in a covalent bond.

Valence Electrons-

The electrons present in the outermost shell of an atom are called valence electrons. These electrons play an essential role in chemical bonding since they are responsible for the chemical reactivity of an atom.

The valence electrons are represented in the electron-dot structure with dots. In an electron dot diagram, the valence electrons in the outermost energy level of an atom are depicted as dots.

The electron dot structure of H₂O is:

Electron dot structure of H₂O molecule consists of two electrons of hydrogen and four electrons of oxygen.

Therefore, the total number of valence electrons in H₂O is 6.

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Answer:

The empirical formula is the simplest form;

Given:

Oxygen O at 94.1% and

H at 5.9%

Assume 100grams.

94% = 0.941 x 100gm. = 94.1 gm x 1mole/16gm. = 5.88 moles of O

5.9% = 0.059 x 100gm. = 5.9gm. X 1moleH/1.002gm. = 5.88 moles of H

There is one mole of O for each mole of H so the empirical formula is \(O_1H_1\)

and written as OH.

Explanation:

\(given \: that \: oxygen \: by \: 94.1\% (.941)\\ hydrogen \: by5.9\%(.059) \\ in \: 100gram \: \\ oxygen = 100 g\times .941 = 94.1 \times \frac{1(mol)}{16g} \\ = 5.88moles \: of \: oxygen \\ in \: hydrogen \: = .059\times 100 = 5.9 \times \frac{1mol}{1.002gram} \\ = 5.88mole \: of \: hydrogen \\ \: so \: here \: \: both \: oxygen \: andhydrogen = 5.88 \\their \: ratio = 1 \: 1 \\ so \: emparical \: formula = oh \\ thank \: you\)

Answer:

One mole of Vitamin A would be massive!

Explanation:

The molecular formula of Vitamin A is C20H30O and the molecular weight is 286.5 g/mol

meanwhile the molecular formula of Vitamin C is C6H8O6 and the molecular weight is 176 g/mol.

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Answer:

The concentration of hydrogen peroxide decomposes over time.

Explanation:

The concentration of hydrogen peroxide decomposes over time.

It is a chemical compound whose formula is \(\rm H_2O_2\)

It is a liquid with pale blue and viscous composition.

The uses of hydrogen peroxide are sanitizing, disinfectant, etc.

It decomposes into water and oxygen, by breaking oxygen-oxygen bonding.

Thus, the concentration of hydrogen peroxide decomposes over time.

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Answer:

The first option, aka Opick it up off the gound within 10 seconds, and it's o.k. to eat

Explanation:

The 10 second rule is a rule when you drop foods, but if you get it off the floor under 10 seconds, you can eat it.

Did you know that food picked up under 10 seconds and after 10 seconds has almost the same number of bacterias? The 10 second rule is basically worthless.

Answer:

In a chemical reaction, products are the substances present after the reaction

Answer:

2Al +3Fe(NO3)2 --------> 3Fe + 2Al(NO3)3

In the above reaction Aluminum and iron nitrate reacts to produce iron metal and aluminum nitrate so aluminum is replace by iron

The major product of the hydroboration oxidation of 2-methylbut-2-ene is 2-methylbutan-2-ol. The reaction involves the addition of borane to an alkene, which forms an alkylborane. The subsequent oxidation of the alkylborane yields the alcohol.

The mechanism of hydroboration-oxidation involves the addition of boron hydride (BH3) to an alkene to give the organoborane. Oxidation of the organoborane with hydrogen peroxide and sodium hydroxide yields the corresponding alcohol. It is a regioselective reaction, and the product is formed via anti-Markovnikov addition. The reaction occurs in a two-step process.

The addition of BH3 to an alkene is the first step in the reaction. Boron hydride forms an organoborane compound by donating a hydrogen atom to one of the carbon atoms of the double bond and bonding with the other carbon atom of the double bond. The reaction is shown below.

The second step is the oxidation of the organoborane with hydrogen peroxide and sodium hydroxide. The reaction is shown below.  Image attached below;

this is an example of how the reaction will take place.

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Answer:

about 12 pounds

Explanation:

Answer:

10.91 pounds

Explanation:

That is because an object or person on the moon would weigh 16.5% its weight on earth.

Mass of Hydrogen = 3.7 g

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

180.2 g/mol of glucose-C₆H₁₂O₆ contains 72.1 grams of carbon, 96 g/mol of oxygen and the remainder is hydrogen

Remainder Hydrogen :

\(\tt 180-(72.1+96)=11.9~g/mol\)

% mass of Hidrogen in Gllucose :

\(\tt \dfrac{11.9}{180}\times 100\%=6.61\%\)

So mass of Hydrogen in 55.5 g Glucose :

\(\tt 6.61\%\times 55.5~g=3.7~g\)