how do the dancer move while dancing
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the work done to raise a 25kg book to a 1.5 m shelf is 367.5J and the potential energy of the book will be 367.5

Work done by a force is equal to the scalar product of the force applied and displacement. If d displacement happens on applying a force F, then work done, W by the force is

W = F. d

given:

mass, m = 25 kg

height, d = 1.50 m

work has to be done against the weight of the book, F = mg

work done W = F. d

W = mgd

W = (25) ×(9.8)×(1.50)

W = 367.5 J

This work is stored as the potential energy of the book.

Therefore, the work done to raise a 25kg book to a 1.5 m shelf is 367.5J and the potential energy of the book will be 367.5J

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Answer:

12.5 grams

Explanation:

From the question,

E' = E/2⁽ⁿ/a⁾....................... Equation 1

Where E' = mass left, E = Original mass, n = time, a = half-life.

Given: E = 200 grams, n = 40 years, a = 10 years.

Substitute these values into equation 1

E' = 200/2⁽40/10⁾

E' = 200/2⁴

E' = 200/16

E' = 12.5 grams.

Hence 12.5 grams of the isotope will be left.

The volume of the dilated prism (with a volume of 450 ft³ is dilated by a factor of 2) = 3600 ft³

The volume of the dilated prism will be 8 times the volume of the original prism. This is because the volume of a prism is related to its linear dimensions by the formula:

V = lwh

Where.

V is the volume

l is the length

w is the width, and

h is the height.

When a prism is dilated by a factor of 2, each of its linear dimensions is multiplied by 2, so the volume will be multiplied by 2³, or 8.

Therefore, the volume of the dilated prism will be 450 ft³ × 8

= 3600 ft³.

So the answer is 3600 ft³.

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the guy above me is correct^^

yw<33

Answer:

B

Explanation:

The weight of the object from the information provided in the question is  1500 N.

We know that pressure = Force/area. We have the following information from the question;

Pressure =500 Nm-2

Area = 3 m2

Hence;

Force = Pressure × area

Force = 500 Nm-2 × 3 m2

Force = 1500 N

Hence, the weight of the object is 1500 N

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We want to see if the Trust SSC can archive a higher maximum speed.

Remember the second Newton's law:

Force = mass*acceleration.

And acceleration is the rate of change of the velocity.

Assuming the mass of the Trust SSC does not change, increasing the force would mean that we increase the acceleration, and thus, larger velocities can be reached.

Now there are some problems.

How we do increase the force?.

It is hard to ve precise, mostly because we don't really know how the system works, we just got some given random data that we can't use without context.

Another thing we need to remember, this velocity is measured in only one mile. So because we have a fixed distance to measure it, we only can get larger velocities by increasing the acceleration.

And to increase the acceleration we can increase the force, as discussed, or, decrease the mass.

How to decrease the mass? Using lighter materials.

Now let's see an example on how decreasing the mass would affect the acceleration.

Then an aproximate force is given by:

F = 10,700kg*20.8 m/s^2 = 222,560 N

Now, if we decrease the mass a little bit, for example to 10,000kg, and we do not change the force, the new acceleration will be given by:

10,000kg*a = 222,560 N

a = (222,560 N)/(10,000kg) = 22.3 m/s^2

So decreasing the mass a little, increases the acceleration, which would make a larger maximum velocity.

Concluding, there are two ways of increasing the maximum velocity:

Increasing the force.

Decreasing the mass of the car.

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Answer:

-2 kg x m/s

Explanation:

-17 + 54 = 35 + x

x = -2

Explanation:

here's the answer to your question

Answer:

truuuuuuuuuuuuuuuuuuuuuuuuujuuuuuuuur

Answer:

true

Explanation:

I took a test this year and I know the answer

The angle θ0 at which the electron is incident between the two plates, we can use the relationship θ0 = arctan(E * L / (2d)).

determine the angle θ0 at which the electron is incident between the two plates, we can consider the forces acting on the electron due to the electric field.

The electric field between the plates is directed from left to right. The force experienced by the electron due to the electric field is given by the equation:

F = q * E

where F is the force, q is the charge of the electron, and E is the electric field strength.

Since the electron is negatively charged, it experiences a force in the opposite direction to the electric field. This force will cause the electron to accelerate in the opposite direction.

When the electron enters the region between the plates:

The force due to the electric field will act on the electron in the opposite direction to its initial motion, causing it to decelerate. The electron will follow a curved path due to this deceleration.

When the electron exits the region between the plates:

The force due to the electric field will act on the electron in the same direction as its final motion, causing it to accelerate. The electron will follow a curved path due to this acceleration.

Since the situation is symmetrical, the angle at which the electron exits the region between the plates will be the same as the angle at which it enters.

We need to determine the angle θ0 at which the electron enters the region between the plates.

Consider a small portion of the path between the plates and assume that the electric field is constant within this small region.

In this small region, the net force acting on the electron can be expressed as:

F_net = F_electric - F_centrifugal

where F_electric is the force due to the electric field, and F_centrifugal is the centrifugal force.

The force due to the electric field can be calculated as:

F_electric = q * E

The centrifugal force can be calculated as:

F_centrifugal = m * \(v^2 / r\)

where m is the mass of the electron, v is its velocity, and r is the radius of the curved path.

The electron is moving in a curved path, the net force acting on it is responsible for the centripetal force required to maintain this curved path.

Setting the net force equal to the centripetal force, we have:

F_electric - F_centrifugal = m * \(v^2 / r\)

Substituting the expressions for F_electric and F_centrifugal, we get:

q * E - m * v^2 / r = m * \(v^2 / r\)

Simplifying the equation, we have:

q * E = 2 * m * \(v^2 / r\)

Since the electron enters and exits the region between the plates with the same speed v, we can simplify further:

q * E = 2 * m *\(v^2 / r\)

The forces acting on the electron when it enters the region between the plates:

The force due to the electric field is acting in the opposite direction to the initial motion, causing deceleration.

The centrifugal force is acting in the same direction as the initial motion, opposing the deceleration.

For the electron to enter the region between the plates, the force due to the electric field must be greater than the centrifugal force.

We have:

q * E > m * \(v^2 / r\)

Since the electron is moving perpendicular to the electric field, the electric force can be expressed as:

q * E = q * (V/d)

where V is the voltage between the plates, and d is the spacing between the plates

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From Coulomb's law, the sets of charges of +2 C and -2 C, and +2 C and +2 C are experiencing the strongest forces, both with a magnitude of 36 N.

The strength of the electrostatic force between two charges depends on the magnitudes of the charges and the distance between them, as given by Coulomb's law. The larger the magnitude of the charges and the smaller the distance between them, the stronger the force.

A fundamental characteristic of matter called charge describes how it interacts with magnetic and electric fields. It is commonly measured in coulombs (C), can be positive or negative, and can also be zero.

Protons and electrons are examples of subatomic particles that have electric charge.

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If the second generator emits the longer wavelength, the wavelength would be 680 nm.

The length of a wave can be defined as the distance between two consecutive crests (or troughs) of a wave. The distance between two consecutive crests of a wave is the wavelength. The energy and frequency of electromagnetic radiation are directly proportional. As a result, the shorter the wavelength, the higher the frequency and energy. The formula that connects frequency, wavelength and the speed of light is used to relate them. The formula is given as,λν = c Where λ is the wavelengthν is the frequency c is the speed of light when one of the variables is known, this formula may be utilized to calculate the other two variables. In this case, we know that the second generator emits a longer wavelength. As a result, the wavelength would be more significant than the first generator's wavelength of 640 nm. Thus, the second generator's wavelength is calculated to be 680 nm as it emits a longer wavelength.

Therefore, if the second generator emits the longer wavelength, the wavelength would be 680 nm.

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Answer:Electrical conduction is the transfer of electrically charged particles through a medium, such as electricity traveling through the power lines in your house. Sound conduction (or acoustic conduction) is the transfer of sound waves through a medium, such as vibrations from loud music passing through a wall.

Explanation: Trust

answer:

the first one  

Explanation:

i think it is this one because 4k is bigger than 2k . also it is asking which one has the lager magnitude so it is the first one

Answer:

Explanation:

1.wrap bar magnet in a plastic baggie and remove the iron filings from the mixture by using a bar magnet. Place a small piece of scrap paper on the scale and “tare” the scale. Then place filings on the scrap paper and record (e) the mass of the iron filings. Don't throw out the iron–save it to be recollected.

2.When sand is added to water it either hangs in the water or forms a layer at the bottom of the container. Sand therefore does not dissolve in water and is insoluble. It is easy to separate sand and water by filtering the mixture. Salt can be separated from a solution through evaporation.

3.Sand (mostly silicon dioxide) is not.

Pour the salt and sand mixture into a pan.

Add water. ...

Heat the water until the salt dissolves. ...

Remove the pan from heat and allow it to cool until it's safe to handle.

Pour the salt water into a separate container.

Now collect the sand.

Pour the salt water back into the empty pan.

Heat the salt water until the water boils. Continue boiling it until the water is gone and you're left with the salt.

Another way you can separate the salt water and sand is to stir up the sand/salt water and pour it through a coffee filter to capture the sand.

Answer:

1. Separating iron from mixture

2. Separating sand from mixture

3. Separating Salt mixture

Given data

*The given mass of the car is m = 1610 kg

*The given effective force constant is k = 5.75 × 10^4 N/m

(a)

The formula for the period of oscillation of a 1610 kg car is given as

Substitute the known values in the above expression as

Hence, the time period of oscillation of a 1610 kg car is T = 1.05 s

(b)

As from the given data, the amplitude of the oscillation of the car decreases by a factor of 5.00. Then, the expression for the amplitude of the oscillation, and the damping constant (b) is calculated as

Substitute the known values in the above expression as

Hence, the damping constant is b = 9871.2 kg/s

Part A. We are given that a dart travels from rest to a velocity of 30 m/s with an acceleration of 330 m/s^2 to determine the time we will use the following equation of motion:

Where:

Since the dart is launched from rest this means that the initial velocity is zero, therefore:

Now, we divide both sides by "a":

Now, we plug in the values:

Solving the operation:

Part B. Now, we are asked to determine the distance. To do that we will use the following equation of motion:

Now, we divide both sides by "2a":

Now, we plug in the values:

Solving the operations we get:

Therefore, the distance is 1.36 meters.

Answer:

20 m/s

Explanation:

the final velocity of the car = 20 m/s

Change in the velocity = final velocity - initial velocity

Change in the velocity= 20 - 0

= 20 m/s

Thus, the change in the velocity would be 20 m/s.

Answer:

Yes

Explanation:

A system is said to be in equilibrium when the state of the system is balanced such that there is an equal amount of powers acting in opposite direction

For an object moving at a constant speed of 1000 m/s, given that, according to Newton's first law of motion, a body will continue in motion or at rest unless acted by a force, the object continue moving indefinitely, then the motion  in the object is in equilibrium or balanced or in agreement with the general external surrounding of the object.

a. The overall displacement Δx of the particle is 75 m to the east.

b. The average velocity vav of the particle over the time interval Δt=50.0s is 1.5 m/s to the east.

c. To find the instantaneous velocity v of the particle at t=10.0s, we can calculate the derivative of the position function x(t) with respect to time t at t=10.0s.

From the given position function x(t) = 0.25t³ - 1.5t² + 3t, we can find the velocity function v(t) by taking the derivative: v(t) = dx/dt = 0.75t² - 3t + 3. At t=10.0s, the instantaneous velocity v of the particle is v(10.0) = 57.0 m/s to the east.

The displacement of the particle can be found by subtracting its initial position from its final position, which gives Δx = x(60.0s) - x(10.0s) = 3000 m - 2925 m = 75 m to the east. The average velocity of the particle over the time interval is given by the formula vav = Δx/Δt = 75 m/50.0 s = 1.5 m/s to the east.

Finally, the instantaneous velocity of the particle at t=10.0s can be found by taking the derivative of the position function x(t) with respect to time t and evaluating it at t=10.0s, giving the value of the velocity at that instant.

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Calculations of displacement, average velocity, and instantaneous velocity require specific information about the motion of the particle. Each of these calculations can be performed using calculus when the motion of the particle is defined as a function of time.

The questions are about the interpretation of the motion and the velocity of a particle. However, the actual values, for displacement Δx, average velocity vav, and instantaneous velocity v, could not be directly calculated without additional specific information about the motion of the particle. But here's a general method:

a. The overall displacement, Δx, of the particle can be calculated by integrating the velocity function, v(t), over the time interval.

b. The average velocity, vav, of a particle over a time interval, Δt, can be found by dividing the total displacement, Δx, by the total time, Δt.

c. The instantaneous velocity, v, of a particle at a specific time, t, can be calculated by taking the derivative of the position function, x(t), at that time.

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Answer:

Its orbit is elongated (eccentricity > 0)  

m v R = const      angular momentum is a constant (only centripetal force)

then v R = constant so the maximum radius of the orbit must be twice the minimum radius of the orbit)

Speed:-

\(\\ \rm\rightarrowtail Speed=\dfrac{45}{9}=5m/s\)

Momentum:-

\(\\ \rm\rightarrowtail 45(5)\)

\(\\ \rm\rightarrowtail 225kgm/s\)

We are given:

Initial velocity (u) = 0 m/s            [starting from rest]

Final velocity (v) = 10 m/s

Acceleration (a) = 2 m/s²

Time taken = t

Solving for time taken:

v = u + at             [first equation of motion]

10 = 0 + (2)(t)       [plugging the values]

10 = 2t

t = 5 seconds

Answer:

Explanation:

Use the calorimetry formula.

Q = mc∆T; where Q = heat energy, c = specific heat capacity, and ∆T = change in temperature

Known and Unknown

Q = ? J

m = 0.05 kg

c = 4190 J/kg•°C

T(i) = initial temperature = 30 °C

T(f) = final temperature = 65 °C

∆T = T(f) - T(i) = 65 °C - 30 °C = 35 °C

Calculate the heat energy.

Q = 0.05 kg × 4190 J/kg•°C × 35 °C = 7332.5 J

The light from the green glow stick held by the Olympic sprinter will appear redshifted.

The phenomenon of redshift occurs when the source of light is moving away from the observer. In this case, as the sprinter is running towards you, the distance between you and the glow stick is decreasing over time. This decrease in distance causes a Doppler shift in the frequency of the light emitted by the glow stick.

Since the light is redshifted, its wavelength increases and the frequency decreases compared to its original emitted frequency. As a result, the light that reaches your eyes appears more towards the red end of the visible spectrum.

It is important to note that the color of the glow stick itself remains the same, but due to the relative motion between the source (the sprinter) and the observer (you), the light undergoes a change in frequency and appears redshifted.

This phenomenon is similar to the redshift observed in cosmology, where the light from distant galaxies appears to be redshifted due to the expansion of the universe.

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The magnitude of the acceleration is greater as it was while it was rolling down the ramp because the speed of the object that is rolling down is going to increase every time.

Accelaration is the rate of the change of velocity of an object with respect to the time.

The greater the angle of the incline on which the object is rolling down, the greater speed the ball will attain and acceleration because of the gravitational force that acts on the body attract the object which ultimately increase the speed of the rolling object. So when the object rolls down on a sloppy surface its speed increases as well as its acceleration and the object will cover a large distance or hit the wall with high speed.

So we can conclude that The magnitude of the acceleration is greater as it was while it was rolling down the ramp because the speed of the object that is rolling down is going to increase every time.

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Hence, a 200.7 joule change in the box's potential energy has occurred (J).

Potential energy has a simple definition: It is a type of energy that possesses the ability to perform work but is not now performing work or exerting any force on any other objects. In other words, potential energy concerns object positions rather than object motion.

The following equation provides the potential energy (PE) gained by lifting an object against gravity:

PE = m * g * h

where m is the object's mass, g is its gravitational acceleration, and h is the height to which it is raised.

Substituting the given values, we get:

PE = 11 kg * 9.81 m/s² * 1.7 m

PE = 200.7 J

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