Answer:
You move the -5 to the other side.
Answer:
you move the -5 to the other side equation
Solve the proportion.
w 100
88
3
a.
1
b. 9
A
B
C. 8
d.
Please select the best answer from the choices provided
OD
000
C. 8
8/3 = g/3
, x3 both side
8/3 x 3 = g
8/3 x 3/1 = g
24/ 3 = g
8 = g
Hope this helps!
Find the range of f(-5)=-2|x-5|+8 please with explination.
Answer:
Domain: set of possible input values (x-values)
Range: set of output values (y-values)
The range for the function \(f(x)=-2|x-5|+8\) is:
\(f(x)\leq 8\)
(5, 8) is the vertex of the line
Because |x - 5| is absolute (so always positive) and it is multiplied by -2,
-2|x - 5| will always be negative unless x = 5 (when it will be zero). Therefore, the max y-value is 8.
However, your question actually asked what the function is when x = -5:
\(f(-5)=-2|x-5|+8\\\\= -2|-5-5|+8\\\\= -12\)
Step-by-step explanation:
Thats the all rhe answers step by step
Zev read 15% of his 56-page book. Kelly read 12% of her 64-page book. Marneisha read 14% of his 68-page book Aleisha read 10% of her 72-page book. what the grastest
Answer:
Marneisha with 9.52 pages.
Step-by-step explanation:
Zev: 56×0.15 = 8.4
Kelly: 64×0.12 = 7.68
Marneisha: 68×0.14 - 9.52
Aleisha: 72×0.10 = 7.2
Draw the net and calculate the surface area .
Hello!
surface area
= 2(4 x 2) + 2(12 x 4) + 2(12 x 2)
= 160cm²
Put these numbers in order from least to greatest.
-1/4
2/40
-16
9/25
Answer:
(-1/4)(-16)(2/40)(9/25)Step-by-step explanation:
What’s the chord BC?
Answer:
D) 3.8 cm
Step-by-step explanation:
There are several ways this problem can be solved. Maybe the easiest is to use the Law of Cosines to find angle BAC. Then trig functions can be used to find the length of the chord.
__
In triangle BAC, the Law of Cosines tells us ...
a² = b² +c² -2bc·cos(A)
A = arccos((b² +c² -a²)/(2bc)) = arccos((8² +6² -3²)/(2·8·6)) = arccos(91/96)
A ≈ 18.573°
The measure of half the chord is AB times the sine of this angle:
BD = 2(AB·sin(A)) ≈ 3.82222
The length of the common chord is about 3.8 cm.
_____
Additional comment
Another solution can be found using Heron's formula to find the area of triangle ABC. From that, its altitude can be found.
Area ABC = √(s(s-a)(s-b)(s-c)) . . . . where s=(a+b+c)/2
s=(3+8+6)/2 = 8.5
A = √(8.5(8.5 -3)(8.5 -8)(8.5 -6)) = √54.4375 ≈ 7.64444
The altitude of triangle ABC to segment AC is given by ...
A = 1/2bh
h = 2A/b = 2(7.64444)/8 = 1.911111
BD = 2h = 3.822222
Akili has two tests next week. The probability that he will pass the first test, science, is 3 4 . How he does on that test affects how he will do on his math test. If he passes science, then the probability that he will also pass the math test is 4 5 ; otherwise, the probability is only 1 3 that he will pass the math test. What is the probability he passes exactly one test
Answer:
0.2333 = 23.33% probability he passes exactly one test
Step-by-step explanation:
We have these following probabilities:
3/4 probability that he passes the first test.
If he passes the first test, 4/5 probability that he passes the math test.
If he does not pass the first test, 1/3 probability that he passes the math test.
What is the probability he passes exactly one test
Two scenarios:
Pass first(3/4 probability) and fails second(1/5 probability).
Fails first(1/4 probability) and passes second(1/3 probability). So
\(p = \frac{3}{4}*\frac{1}{5} + \frac{1}{4}*\frac{1}{3} = \frac{3}{20} + \frac{1}{12} = \frac{9 + 5}{60} = \frac{14}{60} = 0.2333\)
0.2333 = 23.33% probability he passes exactly one test
Solve the system of equations by elimination.
2x + 2y = -2
3x - 2y = 12
Answer:
Step-by-step explanation:
2x + 2y = -2
3x - 2y = 12
5x = 10
x = 2
2(2) + 2y = -2
4 + 2y = -2
2y = -6
y = -3
(2, -3)
Ali, Basti and Cian stand at three points A, B and C respectively. Suppose that the measure of angle ABC is 50 degrees , the measure of angle BAC is 60 degrees and Ali is exactly 150 ft away from Basti. Find the distance between Basti and Cian.
To find the distance between Basti and Cian, we can use the law of sines in triangle ABC. The law of sines states that the ratio of the length of a side to the sine of the opposite angle is constant for all sides and their corresponding angles in a triangle.
Let's label the distance between Basti and Cian as "x". We know that the measure of angle ABC is 50 degrees and the measure of angle BAC is 60 degrees. We also know that Ali is exactly 150 ft away from Basti.
Using the law of sines, we can set up the following equation:
sin(50°) / 150 = sin(60°) / x
To solve for "x", we can rearrange the equation:
x = (150 * sin(60°)) / sin(50°)
Using a calculator, we can evaluate the expression:
x ≈ (150 * 0.866) / 0.766
x ≈ 168.4 ft
Therefore, the distance between Basti and Cian is approximately 168.4 ft.
Angelina puts 3,000 milliliters of water in a tub that already has 5 liters of water in it. Jack says the tub now has 35 liters of water in it. Angelina explain he is wrong. Explain who is correct and why
Answer:
-Angelina is correct
Explaintion: Jack in incorrect because it seems that he messed up is place order. He might have thought that 1 liter is equal to 100 mililiters instead of 1,000. That way he might have gotten 30+5=35 instead of 5+3=8
Step-by-step explanation:
3000 ML+ 5L
1 milliliter has 0.001 liters in it.
3000ML= 3L
Angelina has 8 lieters of water in the tub now.
WHAT is the next sequence
Answer: its 21
Step-by-step explanation:
the sequence goes up by 1 each time
Answer:
21
Step-by-step explanation:
a1=1
a2=a1+2
a3=a2+3
a4=a3+4
...
a(n)=a(n-1)+n
PLEASE HELP ME
The function f(x) = -2(4)^x+1 +140
represents the number of tokens a child has x hours after arriving at an arcade.
What is the practical domain and range of the function?
If necessary, round to the nearest hundredth.
The practical domain of the situation is ?
The practical range of the situation is ?
PLEASE SEE PHOTO FOR FUNCTION
The function f(x) = -2(4)ˣ⁺¹ +140 represents the number of tokens a child has x hours after arriving at an arcade. The practical domain and range of the function are x ≥ 0 and The practical range of the situation is [140, ∞).
The given function is f(x) = -2(4)ˣ⁺¹+ 140, which represents the number of tokens a child has x hours after arriving at an arcade.
To determine the practical domain and range of the function, we need to consider the constraints and limitations of the situation.
For the practical domain, we need to identify the valid values for x, which in this case represents the number of hours the child has been at the arcade. Since time cannot be negative in this context, the practical domain is x ≥ 0, meaning x is a non-negative number or zero.
Therefore, the practical domain of the situation is x ≥ 0.
For the practical range, we need to determine the possible values for the number of tokens the child can have. Looking at the given function, we can see that the term -2(4)ˣ⁺¹represents a decreasing exponential function as x increases. The constant term +140 is added to shift the graph upward.
Since the exponential term decreases as x increases, the function will have a maximum value at x = 0 and approach negative infinity as x approaches infinity. However, due to the presence of the +140 term, the actual range will be shifted upward by 140 units.
Therefore, the practical range of the situation will be all real numbers greater than or equal to 140. In interval notation, we can express it as [140, ∞).
To summarize:
- The practical domain of the situation is x ≥ 0.
- The practical range of the situation is [140, ∞).
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Solve proportion, if necessary round to nearest hundredth.
Answer:
B=-3
Step-by-step explanation:
Multiply diagonally then simplify
help pls/////////////////
Answer:
It might be past the time, but I think the second one.
Step-by-step explanation:
Sixty men can build a wall in 40days but though they begin the work together, 55 men quit every ten days. The Time needed to build the wall is?
It would take 370 days to build the wall with the given conditions.
If 60 men can build a wall in 40 days, then the total man-days required to build the wall is:
60 men x 40 days = 2400 man-days
However, 55 men quit every ten days, which means that after 10 days, there are only 60 - 55 = 5 men left to work on the wall. After 20 days, there are only 5 - 55 = -50 men left, which means that the remaining 5 men cannot work any faster than they were already working. Therefore, we can assume that the remaining 5 men complete the wall on their own.
The number of man-days required for the first 10 days is:
60 men x 10 days = 600 man-days
The number of man-days required for the second 10 days is:
5 men x 10 days = 50 man-days
The total number of man-days required for the first 20 days is:
600 man-days + 50 man-days = 650 man-days
The remaining work can be completed by the 5 men in:
2400 man-days - 650 man-days = 1750 man-days
Therefore, the total time needed to build the wall is:
20 days + 1750 man-days / 5 men = 20 + 350 days = 370 days
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what are the seven wonders of the world?
Answer:
1. The Colosseum
2. The Great Wall of China
3. Chichen Itza
4. Petra
5. Machu Picchu
6. Christ the Redeemer
7. Taj Mahal
Step-by-step explanation:
Brady wants to purchase a skateboard that costs $245. So far, he has saved $98 and plans to save
an additional $25 per week.
What is the minimum number of weeks that Brady will be able to purchase the skateboard? Justify
your answer.
Answer:
five almost 6 weeks
Step-by-step explanation:
brady is saving up to 245 but he already has 98 which means he needs to save 147 more dollars. Brady is making 25 a week so if you divide 147 by 25 you get 5.88 so in 6 weeks he can have a new skateboard with a couple extra doll hairs.
2) Which of the following is the lowest ratio?
07:13
O 17:25
7:15
15:23
Answer:
7:15 is the smallest ratio.
Step-by-step explanation:
hope this helps :)
2
How can the additive inverse be used to evaluate the problem below?
Vx
-3-(-6)
Because 3+(-6) is an equivalent expression, the answer is –3.
Because 3+(-6) is an equivalent expression, the answer is 3.
O Because -3+6 is an equivalent expression, the answer is -3.
Because -3+6 is an equivalent expression, the answer is 3.
An additive inverse of a number (x) is a number which when added to x results in being 0.
The given problem is -3 - (-6)
The additive inverse of -6 is 6
-3 -(-6) = -3 + 6 = 3
Communities property: 6-3 = 3
The answer is:
Because -3+6 is an equivalent expression, the answer is 3
The units of an item available for sale during the year were as follows: Jan. 1 Inventory 50 units at $124 Mar. 10 Purchase 60 units at $132 Aug. 30 Purchase 20 units at $138 Dec. 12 Purchase 70 units at $142 There are 80 units of the item in the physical inventory at December 31. The periodic inventory system is used. Determine the ending inventory cost and the cost of goods sold by three methods. Round interim calculations to one decimal and final answers to the nearest whole dollar. blank Cost of Ending Inventory and Cost of Goods Sold Inventory Method Ending Inventory Cost of Goods Sold First-in, first-out (FIFO) $fill in the blank 1 $fill in the blank 2 Last-in, first-out (LIFO) fill in the blank 3 fill in the blank 4 Weighted average cost fill in the blank 5 fill in the blank 6
Ending Inventory Cost and Cost of Goods Sold using different inventory methods:
FIFO Method:
Ending Inventory Cost: $11,920
Cost of Goods Sold: $15,068
LIFO Method:
Ending Inventory Cost: $11,996
Cost of Goods Sold: $15,123
Weighted Average Cost Method:
Ending Inventory Cost: $11,974
Cost of Goods Sold: $15,087
Using the FIFO (First-In, First-Out) method, the cost of the ending inventory is determined by assuming that the oldest units (those acquired first) are sold last. In this case, the cost of the ending inventory is calculated by taking the cost of the most recent purchases (70 units at $142 per unit) plus the cost of the remaining 10 units from the March 10 purchase.
This totals to $11,920. The cost of goods sold is calculated by taking the cost of the units sold (50 units from the Jan. 1 inventory at $124 per unit, 60 units from the March 10 purchase at $132 per unit, and 20 units from the August 30 purchase at $138 per unit), which totals to $15,068.
Using the LIFO (Last-In, First-Out) method, the cost of the ending inventory is determined by assuming that the most recent units (those acquired last) are sold first. In this case, the cost of the ending inventory is calculated by taking the cost of the remaining 10 units from the December 12 purchase, which amounts to $1,420, plus the cost of the 70 units from the August 30 purchase, which amounts to $10,576.
This totals to $11,996. The cost of goods sold is calculated by taking the cost of the units sold (50 units from the Jan. 1 inventory, 60 units from the March 10 purchase, and 20 units from the August 30 purchase), which totals to $15,123.
Using the Weighted Average Cost method, the cost of the ending inventory is determined by calculating the weighted average cost per unit based on all the purchases. In this case, the total cost of all the purchases is $46,360, and the total number of units is 200.
Therefore, the weighted average cost per unit is $231.80. Multiplying this by the 80 units in the physical inventory at December 31 gives a total cost of $11,974 for the ending inventory. The cost of goods sold is calculated by taking the cost of the units sold (50 units from the Jan. 1 inventory, 60 units from the March 10 purchase, and 20 units from the August 30 purchase), which totals to $15,087.
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The circumference of the tire of Melvin’s cycle is 2.5m. He took part in a race of 2km. When
he had covered 1.2km, the tire burst. To finish the race, how many more times should the wheel go
round?
Answer:
320
Step-by-step explanation:
Distance to go
2km - 1.2 km = 0.8km = 800m
Revolutions needed
800/2.5 = 320
CAN SOMEONE HELP ASAP
Answer:
a = 3, b = -4
Step-by-step explanation:
You need to combine like terms in the expression. In the end, you get 3 - 4i. That's in the form of a + bi. So a = 3 and b = -4
Answer the following questions
The answers are given below.
What are trigonometric functions?In mathematics, trigonometric functions are real functions that relate an angle of a right-angled triangle to ratios of two side lengths. The six trigonometric functions are Sine, Cosine, Tangent, Secant, Cosecant, and Cotangent.
Given:
1) 2Sin(9θ).Cos(5θ)=1/2(Sin14θ+Sin4θ)
2) Sin(3θ)Sin(5θ)Cos(3θ)Cos(5θ)=1/2(Sin8θ+Sin2θ)
3)Cos6θ+Cos4θ=2Cos5θCosθ
4)Sin(13θ/2)+Sin9θ=2Sin(11θ/2)Sinθ
5)Cosθ=2√5/5
6)Cos2θ=23/2
7)Tan(π/12)=2-√3
8)Sin(165°)=√6-√2 /4
9)Cos(5π/18)Cos(2π/9)-Sin(5π/18)Sin(2π/9)=Cos(π/2)
=0
Hence, these are the answers .
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This graph shows the altitude of a helicopter over time.
What is the slope of the line and what does it mean in this situation?
The slope is –2000 . This means that the helicopter descends 2000 ft each minute.
The slope is –400 . This means that the helicopter descends 400 ft each minute.
The slope is 400. This means that the helicopter ascends 400 ft each minute.
The slope is 2000. This means that the helicopter ascends 2000 ft each minute.
Answer:
B. The slope is –400
Answer: -400
Step-by-step explanation:
Which relation is not a function?
The relation C is the relation that does not represent a function.
When does a relation represents a function?A relation represents a function if each value of the input is mapped to only one value of the output, that is, one input cannot be mapped to multiple outputs.
In the context of this problem, we look at option C, where there are two arrows departing from the input of 1, meaning that:
The input of 1 is mapped to an output of 4.The input of 1 is also mapped to an output of 6.As the input of 1 is mapped to multiple outputs, the relation does not represent a function.
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Question is on the picture
By answering the presented question, we may conclude that She spends equation 40% of her time at work and 15% of her time on other hobbies. She spends 20% of her time napping.
What is equation?In mathematics, an equation is an assertion that affirms the equivalence of two factors. An algebraic equation (=) separates two sides of an equation. For instance, the assertion \("2x + 3 = 9"\) states that the word \("2x + 3"\) Corresponds to the number "9".
The goal of solution solving is to figure out which variable(s) must still be adjusted for the equations to be true. It is possible to have simple or intricate equations, recurring or complex equations, and equations with one or more components.
For example, in the equations \("x2 + 2x - 3 = 0\) ," the variable x is lifted to the powercell. Lines are utilized in many areas of mathematics, include algebra, arithmetic, and geometry.
Abby, according to the picture, spent:
She spends 25% of her time in school.
She spends 40% of her time at work and 15% of her time on other hobbies.
Therefore, Furthermore, she spends \(20\) of her time napping.
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eight candy bars cost $6.00. Caulatue the cost per candy bar
Answer:
about $1.34
Step-by-step explanation:
Answer:
$0.75
Step-by-step explanation:
6.00/8 = 0.75
also check with
0.75 x 8 = 6.00
HOPE THIS HELPS :)
Mia hired a moving company. The company charged $500 or its services, and Mia gives the movers a 16% tip.
Answer:
The company charged $500 for its services,and Mia gives the movers a 16% tip. Now, we can add the tip amount to the cost of the service to find the total amount Mia paid: Total amount = Cost of service + Tip amount = $500 + $80 = $580
Step-by-step explanation:
Need help will give brainliest and 5 stars I have 5 minutes please help!
(Check picture for equation)
Write the domain of the rational function r(x) in INTERVAL NOTATION.
Answer: the domain of the given rational function in interval notation is (-∞, -5) U (-5, -2) U (-2, 3) U (3, ∞).
Step-by-step explanation:
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the eighth grade level. In an earlier study, the population proportion was estimated to be 0.22
.
How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 99%
confidence level with an error of at most 0.03
? Round your answer up to the next integer.
A sample size of 176 tenth graders would be needed in order to estimate the fraction of students with reading skills at or below the eighth grade level at a 99% confidence level having an error of at most 0.03.
To calculate the sample size required for estimating the fraction of tenth graders with reading skills at or below the eighth grade level, we can use the formula for sample size estimation for proportions;
n = (ZZ × p × (1 - p)) / (EE)
where; n = sample size
Z = Z-score corresponding to the desired confidence level (in this case, the Z-score for a 99% confidence level, which is approximately 2.626)
p = estimated population proportion (in this case, 0.22)
E = desired margin of error (in this case, 0.03)
Plugging in the given values;
n = (2.6262.626 × 0.22 × (1 - 0.22)) / (0.030.03)
n = 0.15774 / 0.0009
n ≈ 175.27
Since we need to round up to the next integer, the sample size required would be 176.
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