how do i find the median in this question.

Answer:

Put a point at -5 on the Y axis.

Then move up 6 (still on the Y axis)

Then move to the right 1 (this should be the point 1,1 on the graph)

Draw a line through the points

Shade to the right of the line you drew

Answer:3 7/10

Step-by-step explanation:

Answer 3 7/10  or three and seven tenths

Step-by-step explanation:

The graph is shown in the attached image.

Answer:

-243

Step-by-step explanation:

the pattern is multiplying the last number by -3. (-3 * -3 = 9, 9 * -3 = -27, etc)

Answer:

234

Step-by-step explanation:

that is the enswer and it is right

Answer:

Real Zeros(roots):

x = 0.383270701869999 ≈ 0.38

x = 14.1834135032869 ≈ 14.18

Imaginary Zeros(roots):

x =

−1.78334210257844 − 1.52917185852188i

x = −1.78334210257844 + 1.52917185852188i

Step-by-step explanation:

Im trying to see if I can simplify these decimals.

The solution to the integral of f(t) = t^2 + sin(2t) + 2cos(2t) + e^(-t)sin(3t) is:

F(t) = (1/3)t^3 - (1/2)cos(2t) + (1/2)sin(2t) - 4e^(-t)cos(3t) + C

where F(t) represents the antiderivative or the indefinite integral of f(t).

To find the solution for the function f(t) = t^2 + sin(2t) + 2cos(2t) + e^(-t)sin(3t) manually, we need to analyze each term separately.

Term: t^2

The integral of t^2 with respect to t is (1/3)t^3.

Term: sin(2t)

The integral of sin(2t) with respect to t is -(1/2)cos(2t).

Term: 2cos(2t)

The integral of 2cos(2t) with respect to t is (1/2)sin(2t).

Term: e^(-t)sin(3t)

To integrate this term, we can use integration by parts. Let's define u = e^(-t) and dv = sin(3t) dt.

Taking the derivatives and integrals:

du = -e^(-t) dt

v = -(1/3)cos(3t)

Using the integration by parts formula:

∫ u dv = uv - ∫ v du

∫ e^(-t)sin(3t) dt = -e^(-t)(1/3)cos(3t) - ∫ -(1/3)cos(3t)(-e^(-t)) dt

= -e^(-t)(1/3)cos(3t) + (1/3)∫ cos(3t)e^(-t) dt

We can apply integration by parts again to the remaining integral:

Let u = cos(3t) and

dv = e^(-t) dt.

Taking the derivatives and integrals:

du = -3sin(3t) dt

v = -e^(-t)

Using the integration by parts formula again:

∫ cos(3t)e^(-t) dt = -e^(-t)cos(3t) - ∫ (-e^(-t))(-3sin(3t)) dt

= -e^(-t)cos(3t) + 3∫ e^(-t)sin(3t) dt

Substituting the value we found for the previous integral:

∫ e^(-t)sin(3t) dt = -e^(-t)(1/3)cos(3t) + (1/3)(-e^(-t)cos(3t) + 3∫ e^(-t)sin(3t) dt)

Now we can solve for the integral:

∫ e^(-t)sin(3t) dt = (-e^(-t)(1/3)cos(3t) - (1/3)e^(-t)cos(3t))/(1 - 1/3)

= -3e^(-t)(1/3)cos(3t) - 3e^(-t)cos(3t)

= -e^(-t)cos(3t) - 3e^(-t)cos(3t)

= -4e^(-t)cos(3t)

Now we can put all the terms together:

∫ f(t) dt = (1/3)t^3 - (1/2)cos(2t) + (1/2)sin(2t) - 4e^(-t)cos(3t)

Let's continue with the expression for the integral:

∫ f(t) dt = (1/3)t^3 - (1/2)cos(2t) + (1/2)sin(2t) - 4e^(-t)cos(3t) + C

where C is the constant of integration.

So, the solution to the integral of f(t) = t^2 + sin(2t) + 2cos(2t) + e^(-t)sin(3t) is:

F(t) = (1/3)t^3 - (1/2)cos(2t) + (1/2)sin(2t) - 4e^(-t)cos(3t) + C

where F(t) represents the antiderivative or the indefinite integral of f(t).

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Answer:

yes, because there aren't other even prime numbers.

Step-by-step explanation:

2 Is the only even prime number

3 is odd

5 is odd

7 is odd

11 is odd

13 is odd

And so on

The number of ways to form an 8-person committee with 4 men and 4 women is 9,180. The number of ways to form a committee with at least 2 men is 70,320. The number of ways to form a committee with more women than men is 7,620. This can be solved by the concept of  Permutation and Combination.

If the committee must contain four men and four women, there are 7,425 ways to form the committee. If there must be at least two men, there are 58,275 ways to form the committee. If there must be more women than men, there are 26,207,700 ways to form the committee.

To find the number of ways to form a committee with four men and four women, we can use combinations. The number of ways to choose 4 men out of 12 is 495, and the number of ways to choose 4 women out of 15 is 1,365.

To get the total number of ways, we can multiply these numbers:

495 x 1,365 = 7,425.

To find the number of ways to form a committee with at least two men, we need to consider two cases: 2 men and 6 women, and 3 men and 5 women. For the first case, we can choose 2 men out of 12 in 495 ways, and 6 women out of 15 in 5,005 ways. For the second case, we can choose 3 men out of 12 in 2,190 ways, and 5 women out of 15 in 3,003 ways.

To get the total number of ways, we can add these numbers:

495 x 5,005 + 2,190 x 3,003 = 58,275.

To find the number of ways to form a committee with more women than men, we can use a different approach. We can count all the possible committees with 1 man, 2 men, 3 men, and 4 men, and then subtract the committees that have more men than women. There are 15 ways to choose 1 man, 330 ways to choose 2 men, 3,960 ways to choose 3 men, and 12,870 ways to choose 4 men.

To count the committees with more men than women, we can use the complement rule. This means we need to count the committees with 4 men and 0, 1, 2, or 3 women, the committees with 3 men and 0 or 1 women, the committees with 2 men and 0 women, and the committee with 1 man and 0 women.

Adding these numbers gives us the total number of committees with more women than men:

15 + 330 + 1,320 + 2,772 + 330 + 15 = 26,207,700

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Adding the fractions 1/8 and 1/12 by using the LCM of 8 and 12 as the common denominator exists 5/24.

A fraction is a piece of the entire. In mathematics, the number is represented as a quotient, where the numerator and denominator are divided. Both are integers in a straightforward fraction. In the numerator or denominator of a complex fraction is a fraction. A correct fraction has a numerator that is lower than its denominator.

An element of a whole or, more broadly, any number of equal pieces, is represented by a fraction. When used in conversational English, a fraction indicates the number of components of a particular size, as in one-half, eight-fifths, and three-quarters.

Let the fractions be 1/8 and 1/12

8 = 2 × 4

12 = 3 × 4

By using LCM, we get

\($2 \times 3 \times 4=24 \quad\{L C M\}$\)

= 1/8 + 1/12

simplifying the equation, we get

\($=\frac{1 \times 3}{8 \times 3}+\frac{1 \times 2}{12 \times 2}$\)

= 3/24 + 2/24

= 5/24

Therefore, adding the fractions 1/8 and 1/12 by using the LCM of 8 and 12 as the common denominator exists 5/24.

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Answer:

Step-by-step explanation: The points that have a distance of 3 units between them are:

N=(1,4) and P=(1,1)

P=(1,1) and R=(1,-2)

P=(1,1) and Q=(3,1)

Answer:

-0.6000

Step-by-step explanation:

sin² A + cos² A = 1

sin² A = 1 - Cos² A

= 1 - (4/5)²

= 1 - 0.64

= 0.36

sin A = sqrt 0.36 = 0.6

in quadrant IV sin is negative

sin A = -0.6000

The area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.

Area of regular polygon = 1/2 × apothem × perimeter

perimeter = (s)side length of octagon × (n)number of side.

apothem = s/[2tan(180/n)].

11 = s/[2tan(180/12)]

s = 11 × 2tan15

s = 5.8949

perimeter = 5.8949 × 12 = 70.7388

Area of dodecagon = 1/2 × 11 × 70.7388

Area of dodecagon = 389.0634 in²

Area of pentagon = 1/2 × 5.23 × 7.6

Area of pentagon = 19.874 in²

Therefore, the area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.

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Mary will receive 1512.4931 more Yen if she makes her trade on the day with the most favorable exchange rate than that of the least favorable exchange rate.

It is the factor by which currency conversion of two countries is done.

The most Favorable day is Friday because the exchange rate on Friday is the highest.

So, Mary will receive on Friday= 311.75 x 92.7120 x 94/100

Mary will receive on Friday(a)=27168.788 Yen

The least Favorable day is Wednesday because the exchange rate on Wednesday is the least.

So, Mary will receive on Wednesday= 311.75 x 87.5507 x 94/100

So, Mary will receive on Wednesday(b)= 25,656.2949 Yen

Difference between (a) and (b) = 1512.4931 Yen

Hence, Mary will receive 1512.4931 more Yen if she makes her trade on the day with the most favorable exchange rate than if she makes her trade on the day with the least favorable exchange rate.

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Answer:

the answer is b) 42 + .02t

Answer:

x = 9.238 y = 4.619

Step-by-step explanation:

I kind of forgot how to do sohcahtoa but we do cosine for one of them. I used a calculator but the lengths seems reasonable so I'm sure they should be right.

Answer:

The measure of <TRU is 72 deg.

Step-by-step explanation:

<QRU is a right angle, so it measures 90 deg.

Since m<QRT = 18 deg, then m<TRU must be 72 deg since 72 + 18 = 90.

Answer: The measure of <TRU is 72 deg.

Angles of a triangle added together equal 180

A=180-143=37

B is 145 b/c like angles

C=A b/c lines are similar

D=143-85=58

E=C b/c like angles

F=90-E=53

G=48

H=180-48-G=180-48-48=84

K=180-H=96

M=180-K-D=180-96-58=26

P=180-85-M=69

R=180-P=180-69=111

S=P

Answer:

16

Step-by-step explanation:

18-7=11 2+3=5. 11+5=16

according to BODMAS rule

18 - 7 × 5

18 - 35

-17

Answer:

7

Step-by-step explanation:

Answer:

You will have exact seven.

Answer:

$22

Step-by-step explanation:

So if a videotape was on a 40% discount, then the person who is buying it pays 60% of the original price (100 - 40 = 60)

call "x" the original price, then set up a proportion to explain the relationship

13.2/x = 60/100

simplify

13.2/x = 3/5

solve using cross products

13.2/x = 3/5

13.2 * 5 = 3 * x

66 = 3x

22=x

Answer:

10

Step-by-step explanation:

(21-1)/2

Answer:

I think it is 5

Step-by-step explanation:

Answer:

P = 16w - 4

Step-by-step explanation:

P = (5w-2 + 3w)2

P = (8w-2)2

P = 16w - 4

Answer:

$ 37.50

Step-by-step explanation:

100% - 25% = 75%

75% = 0.75

50 × 0.75 = $ 37.50

Answer:  I will try

Step-by-step explanation:

Answer:

Step-by-step explanation:

set the height function = 0 and solve for t-16t2+6400=0t2 = -6400/(-16)=

Answer:

-24

Step-by-step explanation:

The Extreme Value Theorem states that if a function f is continuous on a closed interval [a, b], where a < b, then f attains its maximum and minimum values on that interval. For any ε > 0, there exists x₁ ∈ [a, b] such that y - ε ≤ f(x) ≤ y. Moreover, there exists a sequence (Xₙ)ₙ=1^∞ in (a, b) such that f(xₙ) → y as n → ∞. By considering the subsequence (X₂ₙ)ₙ=1^∞ in [a, b], we can show that f(2ₙ) → y. Hence, there exists r ∈ (a, b) such that f(x) = y.

The Extreme Value Theorem guarantees that a continuous function on a closed interval [a, b] has maximum and minimum values on that interval. By the definition of the supremum, for any ε > 0, there exists x₁ ∈ [a, b] such that y - ε < f(x₁) ≤ y. This justifies the existence of a point x₁ in [a, b] where f(x₁) is arbitrarily close to y.

Since f is continuous on [a, b], it is also continuous on the compact set [a, b]. By the Bolzano-Weierstrass theorem, there exists a sequence (Xₙ)ₙ=1^∞ in [a, b] that converges to a limit point x₀ ∈ [a, b]. As f is continuous, f(xₙ) → f(x₀) as n → ∞. Since f(x₀) = y and f(xₙ) → f(x₀), it follows that f(xₙ) → y as n → ∞.

Considering the subsequence (X₂ₙ)ₙ=1^∞ of (Xₙ), which contains only the even-indexed terms, we can show that f(2ₙ) → f(x₀) = y as n → ∞. This is because (X₂ₙ) converges to the same limit point x₀, and f is continuous.

Combining the above results, we conclude that there exists r ∈ (a, b) such that f(r) = y. This is possible because we have shown the existence of two sequences converging to x₀, one containing all points in (a, b), and another containing only the even-indexed points in [a, b]. Since f is continuous, the limit of f(xₙ) as n → ∞ is the same for both sequences, and thus f(r) = y.

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