how do I find the angle of aed, please help

The surface area of the pyramid is given by the equation A = 170.4 inches²

The total surface area is the summation of the areas of the base and the three other sides. A = B + ( 1/2 ) ( P x h ), where B is the area of the base of the pyramid, P is the perimeter of the base, and h is the slant height of the pyramid

Surface Area of Pyramid = B + ( 1/2 ) ( P x h )

Given data ,

Let the surface area of the pyramid be represented as A

Now , the equation will be

The slant height of the pyramid h = 6 inches

The side of the equilateral triangle = 12 inches

So , the perimeter of the triangle = 3 x side length

Substituting the values in the equation , we get

The perimeter of the triangle = 36 inches

The area of the base = 62.4 inches²

So , Surface Area of Pyramid = B + ( 1/2 ) ( P x h )

Substituting the values in the equation , we get

Surface Area of Pyramid = 62.4 + ( 1/2 ) ( 36 x 6 )

On simplifying the equation , we get

Surface Area of Pyramid = 62.4 + ( 108 )

Surface Area of Pyramid = 170.4 inches²

Hence , the surface area of pyramid is 170.4 inches²

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Answer:B

Step-by-step explanation:

It says split so you would split v by 2

Answer:

  18x+6

Step-by-step explanation:

You want the total length of fence required to enclose a rectangular garden with width (2x+4) and length (7x-1) feet.

Perimeter

The perimeter of a rectangle is given by the formula ...

  P = 2(L+W)

Substituting the given length and width, we find the perimeter to be ...

  P = 2((7x-1) +(2x+4))

  P = 2((7+2)x +(-1+4)) = 2(9x +3)

  P = 18x +6

The total amount of fencing Susan needs is represented by the expression (18x+6).

The integers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 have been written on a chalkboard by Dayna. She then erased the integers from 1 through 6, as well as their multiplicative inverse $\mod{13}$.

We can find the multiplicative inverse of an integer { a modulo 13 } by using the extended Euclidean algorithm.The integers from 1 to 6 are 1, 2, 3, 4, 5, and 6.The multiplicative inverse of : 1 modulo 13 is 1, 2 modulo 13 is 7,  3 modulo 13 is 9, 4 modulo 13 is 10, 5 modulo 13 is 8, and 6 modulo 13 is 11.The only integer that Dayna does not erase is 12.

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Given:

8.90ft³ for 30 balloons

Let h be the volume of helium and b be the number of balloons.

Using proportion;

b/h = 30 /8.90

Multiply both-side by h

Hence, the answer to blank 1 is the above.

when b=50, substitute for b in the above and solve for the volume (h).

That is;

Multiply both-side by 8.90/30

Hence, the answer to blank 2 is 14.83ft³.

Answer:

x^2-4x

Hope this helps

Also, thanks for 13 points

Answer:

10,163,755,305,136

Step-by-step explanation:

Answer:

1.0163755e+13

Step-by-step explanation:

9273499366 x 1096=1.0163755e+13

The compound interest when $7300 when interest is compounded semi annually is $2482.70.

The compound interest when $7300 when interest is compounded monthly is $1972.73.

An investment earns compound interest when both the amount invested and the interest accrued increases in value at predetermined time intervals.

The formula to represent compound interest is :

FV - amount invested

FV = P (1 + r)^nm

a. 7300 x [1 + (0.1/2)]^(3 x 2) = 9782.70

Compound interest = 9782.70 = 7300 = $2482.70

b. 7300 x [1 + (0.08/12)]^(12 x 3) = 9272.73

9272.73 - 7300 = $1972.73

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Answer:

the difference is 25.4 degrees.

Step-by-step explanation:

Answer: If it is pythagorean theorem than it is 10

Step-by-step explanation:

8^2+6^2=100

Squareroot of 100 is 10

The total number of adults in the group is 92, and the total number of children is 56.  By substitution or elimination method, we can determine that there are 92 adults and 56 children in the group.

Let's define the variables:

A = number of adults

C = number of children

Based on the given information, we can create a system of equations:

Equation 1: A + C = 148 (The total number of people in the group is 148.)

Equation 2: 12A + 9C = 1410 (The total weight of food ordered is 1410 pounds.)

To find the total number of adults and children, we need to solve this system of equations.

We define two variables: A for the number of adults and C for the number of children in the group. According to the problem, the total number of people in the group is 148, so our first equation is A + C = 148.

The second equation is derived from the information about the food order. The cook ordered 12 pounds of food for each adult and 9 pounds of food for each child. The total weight of food ordered is given as 1410 pounds. Therefore, the equation becomes 12A + 9C = 1410.

To find the values of A and C, we solve this system of equations. By substitution or elimination method, we can determine that there are 92 adults and 56 children in the group.

In summary, the total number of adults in the group is 92, and the total number of children is 56.

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6 students can be seated in a row of 6 chairs in 121 ways.

Given,

Number of students = 6

Number of chairs = 6

We have to find the number of ways the students can be seated in a row.

Here,

Jack insists on sitting in the first chair.

So, 1 way of sitting for jack.

Next,

5 students and 5 chairs are there.

So they can sit in;

5! = 120 ways

Therefore,

Total number of way of sitting is 120 + 1 = 121 ways.

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Answer:

Graph is attached below with coordinated points of (3,3),  (-3,2),  (-2,-3),  (-3,-2),  (0, -4),  (-2,0),  (4,0), and (0,0)

Step-by-step explanation:

1) The fraction is given as,

c) The fraction is given as,

d) The fraction is given as,

Answer:

A. (12= 6) + 7 = 12

Step-by-step explanation:

If an integer n is a multiple of both 4 and 5, then n is a multiple of 10. Its negation is that an integer n which is a multiple of 4 and 5 is not necessarily a multiple of 10. Not all real numbers are greater than 7 and 2 is odd or 11 is even.

b) Either every real number is greater than 7, or 2 is even and 11 is odd.

Negation: Not all real numbers are greater than 7 and 2 is odd or 11 is even.

c) Either every real number is greater than 7 or 2 is even, and 11 is odd.

Negation: Every real number is less than or equal to 7 or 2 is odd or 11 is even.A statement is negated when it is represented in the opposite sense. It may be represented in the positive sense or negative sense. The positive or negative sense of a statement may vary depending on the requirement and perspective.

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Answer:

SA = 94 ft²

Step-by-step explanation:

To find the surface area of a rectangular prism, you can use the equation:

SA = 2 ( wl + hl + hw )

SA = surface area of rectangular prism

l = length

w = width

h = height

In the image, we are given the following information:

l = 4

w = 5

h = 3

Now, let's plug in the information given to us to solve for surface area:

SA = 2 ( wl + hl + hw)

SA = 2 ( 5(4) + 3(4) + 3(5) )

SA = 2 ( 20 + 12 + 15 )

SA = 2 ( 47 )

SA = 94 ft²

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The expected value is 0.8, variance is 0.48, and standard deviation is 0.693 with the given probability.

a. The probability of getting one success in two trials with p=0.4 is given by the binomial probability formula:

f(1) = 2C1 * (0.4)^1 * (0.6)^1 = 0.48

b. The probability of getting zero successes is:

f(0) = 2C0 * (0.4)^0 * (0.6)^2 = 0.36

c. The probability of getting two successes is:

f(2) = 2C2 * (0.4)^2 * (0.6)^0 = 0.16

d. The probability of at least one success is:

P(at least one success) = 1 - P(no success)

= 1 - f(0)

= 1 - 0.36

= 0.64

e. The expected value of a binomial distribution with n trials and probability of success p is given by:

E(X) = np

In this case, n = 2 and p = 0.4, so:

E(X) = 2 * 0.4 = 0.8

The variance of a binomial distribution is given by:

Var(X) = np(1-p)

So:

Var(X) = 2 * 0.4 * 0.6 = 0.48

The standard deviation is the square root of the variance:

SD(X) = sqrt(Var(X)) = sqrt(0.48) = 0.693.

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a. Lower 95% CI for the population mean: Approximately 3.58, B. The claim that the population mean is less than -5 does not seem reasonable based on the given sample, c. Upper 98% CI for the population mean: Approximately 8.91.

In order to construct confidence intervals and evaluate the reasonableness of a claim regarding the population mean, we need to use the sample mean, sample size, and known variance.

In this case, we have a random sample of size 9 drawn from a normal distribution with an unknown mean and a known variance of 16. The sample mean is calculated to be 6.

a. To construct the lower 95% confidence interval (CI) for the population mean, we use the formula: lower CI = sample mean - (critical value * standard error). The critical value for a 95% confidence level is 1.96. The standard error is the standard deviation divided by the square root of the sample size. Given the known variance of 16, the standard deviation is 4. Therefore, the lower CI is 6 - (1.96 * (4 / √9)) = 6 - 1.96 * 4/3 ≈ 3.58.

b. To evaluate the claim that the population mean is less than -5, we compare the lower confidence limit (3.58) with the claim. Since the lower limit is greater than -5, the claim does not seem reasonable based on the given sample.

c. To construct the upper 98% confidence interval for the population mean, we use a critical value of 2.33 (corresponding to a 98% confidence level). Using the same formula as in part a, the upper CI is 6 + (2.33 * 4/3) ≈ 8.91.

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Answer:

-0.76

Step-by-step explanation:

Answer:

-0.76

Step-by-step explanation:

this is pretty simple subtraction but you just take 14.36 and subtract it by 15.12 and you know it will be a negative number because 15.12 is bigger than 14.36 and so your answer is -0.76

Answer:C=2πA=2·π·1≈3.54491

Step-by-step explanation:

Answer:

119.32

Step-by-step explanation:

The formula for the area of a circle is:

A = πr², where π = 3.14 and r = radius

The formula for the circumference of a circle is:

C = 2πr, where π = 3.14 and r = radius

So, in order to solve for circumference, you need to solve for 'r'.  Using the formula for area:

1134.11 = πr²

Divide by π (3.14): 1134.11/3.14 = πr²/3.14 or 361.2 = r²

Take the square root of both sides: √361.2 = √r² or r≈19

Use the value of r = 19 to solve for circumference:

C = 2π(19) = 2(3.14)(19) = 119.32 meters

The required value of y for the unit circle is: 2/3

The circle is defined as the locus of a point whose distance from a fixed point is constant i.e center (h, k).

The equation of the circle is given by:

(x - h)² + (y - k)² = r²

where:

h, k is the coordinate of the center of the circle on coordinate plane.

r is the radius of the circle.

Here,

Equation of the unit circle is given as,

x² + y² = 1

Now substitute the given value in the equation,

5/9 + y² = 1

y² = 1 - 5/9

y² = 4/ 9

y = √(4/9)

y = 2/3

Thus, the required value of y for the unit circle is 2/3

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Answer:

Since, it is a triangle and the sum of angles of triangle is 180°. So

72+57+X=180

or, 128+X=180

or, X= 180-128

X= 51°

Answer:

2 rays: Two examples of rays are AB and AC, both emanating from a common endpoint A and extending infinitely in opposite directions.

2 line segments: Two examples of line segments are AB and CD, both of which have two endpoints and a finite length.

2 lines (not including the parallel lines): Two examples of lines are AB and CD, which intersect at a point E.

2 sets of parallel lines: Two examples of sets of parallel lines are AB and CD, and EF and GH, where AB and CD are parallel to each other, and EF and GH are parallel to each other.

2 acute angles (not incl. the ones in the As): Two examples of acute angles are ∠BAC and ∠EFG, both of which measure less than 90 degrees.

2 obtuse angles (not incl. the ones in the As): Two examples of obtuse angles are ∠PQR and ∠XYZ, both of which measure greater than 90 degrees.

2 right angles (not incl. the ones in the As): Two examples of right angles are ∠ABC and ∠EFG, both of which measure 90 degrees.

2 clear examples of supplementary angles: Two examples of supplementary angles are ∠ABC and ∠DEF, and ∠PQR and ∠RST, where the sum of the angles in each pair is 180 degrees.

2 clear examples of complementary angles: Two examples of complementary angles are ∠ABC and ∠PQR, and ∠DEF and ∠RST, where the sum of the angles in each pair is 90 degrees.

2 clear examples of more than two angles on a line that add up to 180°: Two examples of sets of angles on a line that add up to 180 degrees are ∠ABC, ∠BCD, and ∠CDE, and ∠PQR, ∠QRS, and ∠RST.

2 right triangles: Two examples of right triangles are ΔABC and ΔPQR, where ∠CAB and ∠QRP are right angles.

2 acute triangles: Two examples of acute triangles are ΔDEF and ΔGHI, where all angles are acute.

The sum of the measures of angles within each triangle:

In ΔABC, the sum of the measures of the angles is 180 degrees, where ∠A measures 90 degrees, and ∠B and ∠C measure 45 degrees each.

In ΔPQR, the sum of the measures of the angles is 180 degrees, where ∠P and ∠R measure 90 degrees each, and ∠Q measures 0 degrees.

In ΔDEF, the sum of the measures of the angles is 180 degrees, where all angles are acute, and ∠D, ∠E, and ∠F measure 60 degrees each.

In ΔGHI, the sum of the measures of the angles is 180 degrees, where all angles are acute, and ∠G, ∠H, and ∠I measure 40 degrees each.

In ΔJKL, the sum of the measures of the angles is 180 degrees, where ∠K measures 90 degrees, and ∠J and ∠L measure 45 degrees each.

In ΔMNO, the sum of the measures of the angles is 180 degrees, where ∠O measures 90 degrees, and ∠M and ∠N measure 45 degrees each.

Answer:

0.8

Step-by-step explanation:

80 divided by 100 = .8 or 0.8

The car οvertakes twο buses οn its way tο the city center with the given time and distance.

On its jοurney tο the city centre, the autοmοbile wοuld never pass any buses if it mοved at the same pace as the bus. This is due tο the fact that if bοth the autοmοbile and the bus are mοving at the same speed, their separatiοn will remain cοnstant. Hence, withοut passing any buses, the autοmοbile wοuld arrive in the city centre at the same time as the bus.

Let us suppοse the distance = p.

The distance travelled by the bus in 60 minutes is d/60.

The distance cοvered by the bus in 35 minutes is:

d/60(35)

Fοr the first bus:

It leaves 60 minutes befοre car, thus the distance travelled is:

(d/60) x 60.

If the car οvertakes thus bus by an additiοnal distance x, then the distance travelled by car is:

d = (d/60) x 35 + (d/60) x 60 + x

d = (5/12)d + x

x = 7/12 d

Fοr the secοnd bus:

The bus wοuld have left the airpοrt 120 minutes befοre the car:

(d/60) x 120

The distance cοvered by car with additiοnal distance y is:

d = (d/60) x 35 + (d/60) x 60 + (7/12)d + y

d = (5/6)d + y

y = 1/6d

The car οvertakes the bus thus,

(7/12)d + (1/6)d = d

d = 12/5

Therefοre, the car οvertakes twο buses οn its way tο the city centre.

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Answer:

15

Step-by-step explanation:

AB+BC= AC

13+2= 15