How do I do this number 5 and 6

Answer:

(6r+4)+(3r+8)

Step-by-step explanation:

step 1: Do distributive property

6r+4+3r+8

Step 2: add like terms

6r+3r   and    4+8

Step 3: add

9r+12

I "think" this is answer.

I hope this helps   :)

9 inches = 15 hours

9/15 inches = 15/15 hours .... dividing both sides by 15

0.6 inches = 1 hour

The unit rate is 0.6 inches of snow per hour

Answer:

D) (0,3)

Step-by-step explanation:

Answer:

f > -1

Step-by-step explanation:

I hope this helps!

Hi there!

\(\large\boxed{\text{Average rate = 1}}\)

We can calculate the average rate of change using the following:

\(ARC = \frac{f(b)-f(a)}{b-a}\)

Thus, we can plug in the endpoints of -4 and -2. Find the corresponding y-values for these x-values:

f(-2) = -(-2)² - 5(-2) + 8  = -4 + 10 + 8 = 14

f(-4) = -(-4)² - 5(-4) + 8 = -16 + 20 + 8 = 12

Plug in the solved for values into the ARC equation:

\(ARC(slope) = \frac{14-12}{-2(-4)} = \frac{2}{2} = 1\)

Answer:

x = -1/4, or -0.25

Step-by-step explanation:

1/3 + 2/3x = -5/6x - 1/24

first lets write everything in the common denominator of 24

8/24 + 16/24x = -20/24x - 1/24

now we take all our x's onto 1 side, and all our numbers onto the other side

36/24x = -9/24

lets cancel out all the 24's

36x = -9

x = -9/36

now lets simplify

x = -1/4, or -0.25

Answer:

2.8kg

Step-by-step explanation:

There are 7 parts of meat for every 3 parts so there are 7+3=10 parts in total.

4/10=1 "part"

there are 7 parts of meat so (4/10)*7=28/10=2.8kg of meat.

The impulse response (b) hy(t) = cos(2t)u(t) corresponds to a stable LTI system. Option b is correct.

An LTI (Linear Time-Invariant) system is stable if and only if its impulse response h(t) is absolutely integrable, i.e., the integral of the absolute value of the impulse response over all time is finite:

For impulse response (a), hi(t) = e^-(1-2)t u(t), we can compute the integral of its absolute value:

Since the integral is finite, this impulse response corresponds to a stable LTI system. For impulse response (c), h(t) = 8δ(-21), where δ(t) is the Dirac delta function, the integral of the absolute value is:

Since the integral is finite, this impulse response also corresponds to a stable LTI system. For impulse response (b), hy(t) = cos(2t)u(t), we can compute the integral of its absolute value:

Since the integral is infinite, this impulse response does not correspond to a stable LTI system. Hence Option b is correct.

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For conducting experiment based on effect of a net force , to apply net force on the object two other quantities should be measured in each trial of the experiment is given by velocity and time.

As given in the question,

To conduct a experiment based on the effect of net force applied to an object the dependable quantities are as follow:

Force = mass × acceleration

As object remain same ⇒ mass is constant as object remain same.

And there is change in the acceleration.

Acceleration depends change in velocity over total time taken.

Acceleration depends on velocity and time.

Net force also depends on velocity and time.

Two measurements need to know  while conducting trail experiments are velocity and time.

Therefore, to conduct experiment based on effect of a net force , to apply net force on the object two other quantities should be measured in each trial of the experiment is given by velocity and time.

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Answer:

-5x-96/12

Step-by-step explanation:

Firstly we want ot combine the multiplied terms into one fraction:

(1x/3-3)+(-3/4 x-5)

Then we multiply by 1:

(x/3-3)+(-3/4 x-5)

Find common denominator:

(x/3+3(-3)/3)+(-3/4 x-5)

Combine fractions with common denominator:

(x+3(-3)/3)+(-3/4 x-5)

Multiply the numbers:

(x-9/3)+(-3/4 x-5)

Combine multiplied terms into a single fraction:

x-9/3+(-3x/4 -5)

Find common denominator:

x-9/3+(-3x/4 + 4(-5)/4)

Combine fractions with common denominator:

x-9/3+(-3x + 4(-5)/4)

Multiply the numbers:

x-9/3 + (-3x-20/4)

Find common denominator:

4(x-9)/12 + 3(-3x-20)/20

Combine fractions with common denominator:

4(x-9)+3(-3x-20)/12

Distribute:

4x-36+3(-3x-20)/12

Distribute:

4x-36-9x-60/12

Subtract the numbers:

4x - 96 - 9x/12

Combine like terms:

-5x - 96/12

Answer: -5x-96/12

Therefore, the correct statement is: "\(P(t) = 439(1.033)^t\), Population after 2 hours 28544 bacteria."

The equation for the population P in terms of time t in minutes can be found using the exponential growth formula: P(t) = P₀\(* (1 + r)^t\), where P₀ is the initial population, r is the growth rate, and t is the time.

In this case, the initial population P₀ is 439 and the population triples every 34 minutes, which means the growth rate r is 3.

Therefore, the equation for the population is:

\(P(t) = 439 * (1 + 3)^t \\= 439 * (1.033)^t.\)

To find the population after 2 hours (120 minutes), we substitute t = 120 into the equation:

\(P(120) = 439 * (1.033)^{120}\)

≈ 28544 bacteria.

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Answer:

the item would cost $9000

Answer:

4s-5+2/s

Step-by-step explanation:

9514 1404 393

Answer:

  y = 3x +6

Step-by-step explanation:

Put the numbers in the formula in their corresponding places.

  y = mx + b . . . . slope-intercept form with slope m, intercept b

  y = 3x +6 . . . . . slope-intercept form with slope 3, intercept 6

It is possible for Amy to raise her GPA to 3.0 with 47 credits left, depending on her performance in those remaining credits.

To determine if Amy can raise her GPA to 3.0 with 47 credits left, we need to consider her current GPA, the number of credits she has already completed, and the target GPA.

Let's assume Amy has completed a total of 60 - 47 = 13 credit hours so far. To calculate the GPA needed for the remaining 47 credits to achieve a 3.0 GPA, we can use the formula:

(GPA_needed * Total_credits) - (Current_GPA * Completed_credits) = Target_GPA * Remaining_credits

Substituting the values, we have:

(3.0 * 60) - (1.07 * 13) = 3.0 * 47

180 - 13.91 = 141

166.09 = 141

Since 166.09 is greater than 141, it is possible for Amy to raise her GPA to 3.0 with 47 credits left. She would need to earn a GPA of approximately 3.53 in her remaining credits to achieve the desired 3.0 GPA overall. However, the specific GPA required for each course will depend on the grading scale and the credit hours assigned to each course.

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Answer:

25 copies rented

Step-by-step explanation:

r = r1 - 5t, t is time in weeks, r is the number of copies rented, r1 how many people were renting at the start

we know on the 6 weeks passed and 4 copies were rented

4 = r1 - 5(6)

4 = r1 - 30; add 30 on both sides

34 = r1

r = 34 - 5t now plug t = 2 in for this function

r = 34 - 5(2)

r = 35 - 10

r = 25 copies rented

Answer:

B and C hope this helps ☜(ﾟヮﾟ☜)

Step-by-step explanation:

Answer:

b and c

Step-by-step explanation:

The relative probability that the excited state is occupied at T = 292 K is determined by the Boltzmann distribution and can be calculated using the formula P = exp(-ΔE/kT), where ΔE is the energy difference between the ground and excited states, k is the Boltzmann constant, and T is the temperature in Kelvin.

The relative probability of the excited state being occupied at a given temperature can be determined by the Boltzmann distribution, which describes the statistical distribution of particles in different energy states. According to this distribution, the probability (P) of occupying an energy state is proportional to the exponential of the negative energy difference (ΔE) between that state and the ground state, divided by the product of the Boltzmann constant (k) and the temperature (T) in Kelvin.

In this case, the energy difference between the ground and excited states is given as 2 eV. To convert this to joules, we can use the conversion factor 1 eV = 1.6 × 10^(-19) J. Thus, the energy difference ΔE is 2 × 1.6 × 10^(-19) J.

The Boltzmann constant, denoted by k, is approximately 1.38 × 10^(-23) J/K.

The temperature T is given as 292 K.

Plugging these values into the formula P = exp(-ΔE/kT), we can calculate the relative probability P.

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Answer:

y=-1/5x+3 or slope = -1/5

Step-by-step explanation:

The solution to the given differential equation y'(x) + log(y(x)) = log(y(x)) is y(x) = C, where C is a constant.

To solve the given differential equation, which is: y'(x) + log(y(x)) = log(y(x)), follow these steps:

Step 1: Rewrite the equation
Notice that the equation can be simplified as:
y'(x) = 0

Step 2: Solve the differential equation
To solve the equation y'(x) = 0, integrate both sides with respect to x:
∫y'(x) dx = ∫0 dx

The integral of y'(x) with respect to x is y(x), and the integral of 0 with respect to x is C, where C is the constant of integration:
y(x) = C

Therefore, the solution to the given differential equation y'(x) + log(y(x)) = log(y(x)) is y(x) = C, where C is a constant.

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Answer:

There would be $118,580 but to the nearest hundred there would be $118,600.

Step-by-step explanation:

The answer is 118,600 because 4.5% of 77,000 is 3465 and 3465 multiplied by 12 is 41580 and 77,000 plus 41580 is 118,580 but rounded to the nearest hundred it would be 118,600.

P.S Can I have brainliest?

Answer:

this answer is actually correct. the answer is 132100.

Step-by-step explanation:

Compounded Continuously:

A=Pe^{rt}

A=Pe

rt

P=77000          r=0.045         t=12

Given values

A=77000e^{0.045(12)}

A=77000e

0.045(12)

Plug in

A=77000e^{0.54}

A=77000e

0.54

Multiply

A=132132.528388

A=132132.528388

Use calculator (with e button)

A= aprroximatley  132100

A≈132100

Round to nearest hundred dollars

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Answer:

A = 210 cm²

Step-by-step explanation:

Perimeter of the triangle = the sum of the sides of the triangle.

70 = (3x - 1) + (4x + 1) + (3x)

70 = 10x  

7 = x     The length of the sides of the triangle are 3x - 1 = 20;  4x + 1 = 29 and                

             3x = 21.

 Looking at the given information, this triangle is a special type of triangle because the area of a triangle is Area = 1/2 bh and you do not know which side is the base and height of the triangle.

Trying a² + b² = c² to see if it is a right triangle.   20² + 21² = 29 ² ; yes it is a right triangle and now we know that the base and height is 20 and 21.   The longest side is the hypotenuse in a right triangle

A = 1/2bh

A = 1/2 (20)(21)

A = 10 · 21

A = 210 cm²

Certify Completion Icon Tries remaining: 3 A high school has 52 players on the football team. The summary of the players' weights is given in the box plot. The median weight of the players on the football team is 160 pounds.

The box plot shows that the median weight of the players is the middle value of the distribution. In this case, the median weight is halfway between the 26th and 27th players, which is 160 pounds.

The box plot also shows that the minimum weight of the players is 150 pounds and the maximum weight is 212 pounds. The interquartile range, which is the range of the middle 50% of the data, is 20 pounds.

In conclusion, the median weight of the players on the football team is 160 pounds. This means that half of the players on the team weigh more than 160 pounds and half of the players weigh less than 160 pounds.

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The partition where the bundle branches are located is called the interventricular septum. The interventricular septum is a wall of tissue that separates the ventricles of the heart. It plays a crucial role in electrical conduction within the heart.

Within the interventricular septum, there are specialized bundles of cardiac muscle fibers known as the bundle branches. These bundle branches are responsible for transmitting electrical signals from the atrioventricular (AV) node to the ventricles, coordinating the contraction and pumping of blood.

The bundle branches consist of the left bundle branch and the right bundle branch. The left bundle branch further divides into the anterior and posterior fascicles, while the right bundle branch extends towards the right ventricle. These branches distribute electrical impulses to specific regions of the ventricles, ensuring synchronized and efficient contraction.

In summary, the partition where the bundle branches are located is known as the interventricular septum. It serves as a pathway for electrical signals to reach the ventricles, facilitating coordinated contraction and efficient pumping of blood.

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Answer:

14/24 or 58%

Step-by-step explanation:

The approximate value of f(1) using Euler's method with two steps of equal size is 6.636. The range of f for t > 0 is 0 < f(t) < 6.

a. The limiting factor in this logistic differential equation is the carrying capacity, which is 6 in this case. As y approaches 6, the growth rate of y slows down, until it eventually levels off at the carrying capacity.

b. To use Euler's method, we first need to calculate the slope of the solution at t=0. Using the given differential equation, we can find that the slope at t=0 is y(0)/8(6-y(0)) = 8/8(6-8) = -1/6.

Using Euler's method with two steps of equal size, we can approximate f(1) as follows:

f(0.5) = f(0) + (1/2)dy/dx|t=0

= 8 - (1/2)(1/6)*8

= 7.333...

f(1) = f(0.5) + (1/2)dy/dx|t=0.5

= 7.333... - (1/2)(7.333.../8)*(6-7.333...)

= 6.636...

Therefore, the approximate value of f(1) using Euler's method with two steps of equal size is 6.636.

c. The range of f for t > 0 is 0 < f(t) < 6, since the carrying capacity of the logistic equation is 6. As t approaches infinity, f(t) will approach 6, but never exceed it. Additionally, f(t) will never be negative, since it represents a population size. Therefore, the range of f for t > 0 is 0 < f(t) < 6.

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Answer:

1.6425

Step-by-step explanation:

Answer:

25

Step-by-step explanation:

\(5x^{2} - 2 ( y + 1)+9 = 5*2^{2} - 2(1 + 1) + 9 = 5 *4 - 4 +9 = 20 - 4 + 9 = 20 + 5 =25\)

Answer:2 ounce of clay are left in the bucket

Step-by-step explanation:

Total amount of clay to share = 16 ounce

amount used by Ted = 5/ 8 x 16=10 ounce

Amount used by Carl = 1/4 x 16= 4 ounce

Amount of clay  remaining= Total clay - amount used by Ted and Carl

= 16-(10+4)

=16-14

=2 ounce of clay left in the bucket