\(CuCl_2+2NaNO_3 \rightarrow Cu(NO_3)_2 + 2NaCl\)
Use the chemical equation to complete the activity.
2Cu+S→Cu2S
Copper (Cu) reacts with sulfur (S) to form copper sulfide as shown in the equation. A scientist adds 12.7 grams of Cu to 3.2 grams of S to start the reaction. In this reaction, all of the copper and all of the sulfur react. Before running the experiment, the scientist expected the products of the reaction will be a total of 15.9 grams of copper sulfide (Cu2S). In 1–2 sentences, explain the law that the scientist used to predict that the product of the reaction would be 15.9 grams of copper sulfide.
The law the scientist used to predict that the product of the reaction would be 15.9 grams of copper sulfide is law of conservation of matter
Law of conservation of matterThe law of conservation of matter states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.
The above law suggest that the total mass of reactants must equal to the total mass of the product obtained in a chemical reaction.
With the above information, we can obtain the mass of Cu₂S as follow:
2Cu + S → Cu₂S
Mass of Cu + mass of S = Mass of Cu₂S
12.7 + 3.2 = Mass of Cu₂S
Mass of Cu₂S = 15.9 grams
Thus, from the above illustrations, we can conclude that the law the scientist used was the law of conservation of matter
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chemical formulae for sodium chloride and water
Answer:
There are different ways to write this:
N\(a^{+}\) + C\(l^{-}\) + H2O
N\(a^{+}\)(aq) + C\(l^{-}\)(aq)
Explanation:
(aq) means aqueous in water, which means dissolved in water.
Hope this helps.
- profparis
1. How many grams was each person's final serving of 1 burger?
Each person in the group gets two Burgers. (To Solve this Assume 4 persons per VIRTUAL group)
group)
(Key: 1 Pound = 453 grams; **burgers lose approximately 10% of their weight during
cooking.)
As per conversion units, 45.3 grams is each person's final serving of 1 burger.
As 1 burger has a weight of 1 pound which is equal to 453 grams ,and as each burger looses 10% of it's weight while cooking .
So the weight of 1 burger after cooking is,
10/100×453=45.3 g
Thus,each person's final serving of 1 burger is 45.3 grams.
What are conversion units?Conversion units or unit conversion expresses the same property with a different unit of measurement.It is a numerical expression or a number that is used to change one set of units to another.
It usually occurs through multiplicative conversion factors through which the measured quantity is changed without changing it's effects.
There are different conversion systems such as:
1) SI system
2)CGS system
3)MKS system
4) FPS system
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Calculate the pH and percent ionization of a .780 M HNO2 solution.
Since [H2NO2] is equal to zero in this case, the percent ionization is equal to 100%.
What is ionization ?Ionization is the process of adding an electrical charge to a neutral atom or molecule, resulting in the formation of positively or negatively charged ions. The process involves the transfer of electrons from one atom or molecule to another, which can occur through chemical reactions, physical collisions, or exposure to radiation. Ionization is an important process in many fields, including chemistry, physics, and biology.
The pH of a .780 M HNO2 solution can be calculated using the Henderson-Hasselbalch equation. This equation states that the pH of a solution is equal to the pKa of the acid plus the logarithm of the base to acid ratio. In this case, the pKa of HNO2 is 3.4, so the pH is equal to 3.4 + log(.780/1) = 2.10.
The percent ionization of the solution can be calculated using the formula:
% ionization = ( [HNO2] - [H2NO2] ) / [HNO2] * 100
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A vial of Ancef 1 g is reconstituted with 5 mL of normal saline to yield 125mg / m * L How many mL of the medication should be given if a patient is prescribed 250 mg of the medication?
Ancef (Cefazolin) is a first-generation cephalosporin antibiotic that is used to treat bacterial infections. Cefazolin is available in several formulations, including injectable, intravenous, and powder for injection.
A vial of Ancef 1 g is reconstituted with 5 mL of normal saline to yield 125mg / m * L. We need to determine how many milliliters of the medication should be given if a patient is prescribed 250 mg of the medication.To begin with, let us first calculate the concentration of the reconstituted solution using the given data.1 gram of Ancef (Cefazolin) = 1000 milligrams (mg)5 mL of normal saline = 5000 milligrams (mg)Therefore, the total volume of the reconstituted solution = 5 mL + the volume of Ancef (Cefazolin)1 g of Ancef (Cefazolin) = 125 mg/mL (Given)Therefore, the volume of Ancef (Cefazolin) = (250 mg)/(125 mg/mL) = 2 mLTherefore, the total volume of the reconstituted solution = 5 mL + 2 mL = 7 mLThus, the amount of medication that should be given to the patient is 2 mL.For such more question on antibiotic
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Scientific inquiry includes many different types of activities and processes. When someone makes measurements using scientific tools, what part of the inquiry process are they performing?
Answer:
Collecting data
Explanation:
Scientific inquiry can be explained as methods undertook by scientists to profer solutions, explanations, predict natural occurence and to some extent solve some of the problems of the earth through scientific study and processes. Evidence of solutions is made available to be built upon by also other scientists in the near future.
process of scientific inquiry include, in no particular order:
Note, that the explanation below doesn't follow any order.
1. Formulating questions: This is the problem that needed to be solved. Scientific inquiries usually begin with a question that can be proven scientifically.
2. Observation: taking neccessary information for the experiment. Collecting data (answer to the question) falls under this process as information collected are used to carry out the experiment.
3. Hypothesis: Based on the observation and test carried out, scientists provide answers to the experiment, however methods used remain open for further experiments by other scientists. This is done so the results are tested and proven before they can be generally accepted as a rule or law.
4. Experiment: the experiment is carried out here.
5. Data analysis: Here the data collected are analysed using scientific methods.
6. Results: This stage shows the other aforementioned stages took place. Results of the scientific research/experiment are published.
Answer:collecting data
Explanation:i did it on study island
Write condensed and bond-line structural formulas for all of the constitutional isomers Practice problem 4.1 with the molecular formula C7H16. (There are a total of nine constitutional isomers.)
Answer:
See figure 1.
Explanation:
In this case have to take into account that all structures must have the formula: \(C_7H_16\). If we remember the general formula for alkanes: \(C_nH_2_n_+_2\) if we have "7" carbons (n=7) we will have 16 hydrogens. Therefore all the structures that fit with this formula are alkanes.
1) How would the electron configuration of nitrogen change to make a stable configuration?
(1 point)
A) It would gain two electrons.
B) It would lose five electrons.
C) It would gain three electrons.
D) It would lose four electrons.
2. Which quantity determines how two atoms bond?(1 point)
A) their total number of valence electrons
B) the difference in their electronegativities
C) the sum of their electronegativities
D) the difference in the number of valence electrons
Answer:
C and B
Explanation:
1) In order for nitrogen to make a stable electronic configuration, it would have to gain three electrons.
Nitrogen is atomic number 7. Hence, the electronic configuration would be:
1s2, 2s2, 2p3
The p orbital is partially filled with 3 unpaired electrons. In order to be stable, the 3 electrons in the p orbital have to be paired. Hence, only by gaining 3 electrons can nitrogen obtain a stable electronic configuration.
2) The quantity the determines how two atoms would bond is the difference in the number of valence electrons in the atoms.
For example, an atom that is lacking 2 electrons will readily form a bond with another atom that has two free electrons.
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Question 6
How many significant figures are there in 31.1100?
Answer:
6 sig figs
Explanation:
sig figs are numbers that are more than 0, but in this case, after the decimal, the 0's at the end count as sig figs as well
There are 6 significant numbers in 31.1100.
If there is no decimal point in the figures then it will be 4 but since there is a decimal point then it is 6 significant figures.
Given the reaction at equilibrium:
2NO2(g) → N204(g) Heat of
reaction is -55.3 kJ) What type of
reaction is this?
O Endothermic
O Exothermic
When the equilibrium constant is higher than one, it indicates that the reaction prefers to produce products, whereas if the equilibrium constant is less than one, it indicates that the reaction prefers to produce reactants. If the equilibrium constant is equal to one, the reaction proceeds in both directions equally.
In a chemical reaction, exothermic reactions are defined as reactions that release heat into their environment. It implies that heat is given off when reactants are converted to products. At equilibrium, an exothermic reaction continues to be exothermic, meaning that heat is given off even after the reaction reaches a state of equilibrium.There are two types of reactions: exothermic and endothermic.
A reaction is classified as exothermic if it releases heat, and endothermic if it absorbs heat. The direction of the reaction is determined by whether it is exothermic or endothermic. At equilibrium, the reaction is no longer moving forwards or backwards. It's also worth noting that reactions can be exothermic in one direction and endothermic in the other.
The equilibrium constant (K) is defined as the ratio of the concentration of products to the concentration of reactants in the chemical reaction equation. It is used to express how much of the products is generated by the reaction in comparison to the reactants. the equilibrium constant aids in the identification of the direction in which the reaction will proceed at equilibrium.
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Shown below is a table with plants and animals with their adaptations.
Using the description of plants and animals in the table above, which biome would all of these organisms would be best adapted to?
Answer:
Desert
Explanation:
The adaptation shown by the given plants and animals shows that they will adapted to the desert biome.
It is so because, due to high temperature of desert some desert animals like camel have the storage of fat in humps or tails; some animals have large ears such as Jackrabbits, it helps to release body heat and adapt in high temperature; plants have thick water holding tissues to reduce water loss in heat and waxy coating that keeps the plants cooler and reduce moisture loss.
Hence, the correct answer is "Desert".
If 0.0687 mol CaCl, is dissolved in water to make a 0.280 M solution, what is the volume of the solution?
Answer: 4.076L
Explanation: The formular for Molarity is moles/Volume
So 0.280M = 0.0687 mol/Volume
Divide both sides by the moles
0.280M/0.0687mol = _______ liters
4.0756 = 4.076 Liters
The container seems to have about 650 mL of copper(II) sulfate
solution in volume. Convert this volume to liters (L) of
solution.
The volume of copper (II) sulfate in a container is equivalent to 0.650L.
How to convert units of volume?Volume is the three-dimensional measure of space that comprises a length, a width and a height. It is measured in units of cubic centimeters (cm³) in metric, cubic inches or cubic feet in English measurement.
According to this question, a container seems to have about 650 mL of copper(II) sulfate solution in volume. The volume can be converted to litres as follows:
1 millilitre = 0.001 litre
650 millilitres = 0.650 litres
Therefore, 0.650L is the volume of copper II sulfate in litres.
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The rate of reaction in terms of the "rate law expression" includes the rate constant (kk), the concentration of the reactants, and the orders of the reaction with respect to the different reactants. Consider the following reaction: A+B→C+DA+B→C+D The initial concentrations of the reactants AA and BB are 0.200 MM and 0.350 MM, respectively. The rate of reaction is 0.060 M⋅s−1M⋅s−1, and the orders of the reaction, with respect to reactants AA and BB, are 1 and 2, respectively. Determine the rate constant (kk) for the reaction using the rate law. Express your answer in M−2⋅s−1M−2⋅s−1 to three significant figures.
Answer:
\(k=2.45M^{-2}s^{-1}\)
Explanation:
Hello.
In this case, considering the given specific orders of reaction, we can write the rate law as:
\(r=k[A][B]^2\)
Thus, considering the concentrations of A and B to be 0.200 M and 0.350 M respectively and a rate of 0.060 M/s, the rate constant turns out:
\(k=\frac{r}{[A][B]^2}\\ \\k=\frac{0.060M/s}{(0.200M)(0.350M)^2} \\\\k=2.45M^{-2}s^{-1}\)
This is what we know as a third-order reaction since the specific orders both add to 3.
Best regards.
Balance the unbalanced equation
Zn(s) + CuSO4(aq)➡️ ZnSO4(aq)+Cu(s)
Answer:
It is balanced
Explanation:
This is an oxidation-reduction (redox) reaction
Do step 3 as outlined in the lab guide. Record your results in the appropriate blanks.
A =
B =
C =
D =
E =
F =
G =
H =
Some tips to follow when doing lab practical are:
Avoid parallax errorsRecord your observations and data accuratelyUse the appropriate lab equipment.How do we know?From the table, Column 1 represents the time in half-life cycles, ranging from the initial state to 8 cycles. Column 2 shows the predicted number of radioactive atoms at each time point, based on the assumption that the number of atoms reduces by half in each half-life cycle.
Column 3 represents the simulated number of radioactive atoms at each time point and corresponds to the predicted values of the simulation.
In conclusion, the results as outlined in the lab guide are A= 27 B= 16 C= 9 D= 4 E= 2 F= 2 G= 0 H= 0.
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#complete question:
Do step 3 as outlined in the lab guide. Record your results in the appropriate blanks. A = B = C = D = E = F = G = H = A 3-column table with 9 rows. Column 1 is labeled Time half-life cycles, n with entries Initial, 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Predicted radioactive atoms with entries 100, 50, 25, 13, 6, 3, 2, 1, 0. Column 3 is labeled Simulated radioactive atoms with entries 100, A, B, C, D, E, F, G, H.
What happens to the amount of solution when we add food colour to it?
Answer:
We need more? What else is in the question? This is unanswerable.
Explanation:
One kilometre equals to what centimeter
Answer:
100,000
Explanation:
1 kilometer equals 100,000 centimeters
You multiply the length value by 100,000
Answer:
One kilometre is 100,000 centimeters
Explanation:
(c) 45 g C,H, react with 45 g Cl₂ according to the equation:
Cl₂ + C6H6 C6H5Cl + HCI. What is the limiting reactant? What mass of HCI will be produced?
-
In the given reaction, the limiting reactant is C₆H₆ (benzene).
To determine the limiting reactant as well as calculate the mass of HCl produced, compare the moles of each reactant.
The number of moles for each reactant:
Molar mass of Cl₂ = 35.5 g/mol + 35.5 g/mol = 71 g/mol
Moles of Cl₂ = mass of Cl₂ / molar mass of Cl₂
= 45 g / 71 g/mol
= 0.634 moles of Cl₂
Molar mass of C₆H₆ (benzene) = 12 g/mol + 6(1 g/mol) = 78 g/mol
Moles of C₆H₆ = mass of C₆H₆ / molar mass of C₆H₆
= 45 g / 78 g/mol = 0.577 moles of C₆H₆
Determine the stoichiometry between Cl₂ and HCl:
Cl₂ + C₆H₆ → C₆H₅Cl + HCl
Here, we can see that 1 mole of Cl₂ produces 1 mole of HCl.
Thus, the limiting reactant is C₆H₆ (benzene).
Calculate the mass of HCl produced:
Molar mass of HCl = 1 g/mol + 35.5 g/mol = 36.5 g/mol
Moles of HCl produced = moles of C₆H₆ = 0.577 moles
Mass of HCl produced = moles of HCl produced × molar mass of HCl
Mass of HCl produced = 0.577 moles × 36.5 g/mol
≈ 21.04 g
Therefore, approximately 21.04 grams of HCl will be produced.
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Kinetic friction is the frictional force needed to start an object at rest into
motion.
O A. True
O B. False
Answer:false you are welcome
Explanation:
Answer: False I hope this helpful please mark me brainlist
Explanation:
Kinetic friction is the friction acting upon a moving object. It would be the frictional force against you if you pulled a box across a table.Static friction is the frictional force needed to overcome to get an object at rest into motion.
Sonar uses ____________ waves to tell how ____________things are in the water.
how many minutes does it take to drive 480 miles if you are driving 60 mph?
Answer:
480 mins
Explanation:
a solid is 5 cm tall 3 cm wide and 2 cm stick it has a mass of 129 g what is its density
Problem:
a solid is 5 cm tall 3 cm wide and 2 cm stick it has a mass of 129 g what is its density
Answer:
\(\sf{4.3g/cm³}\)
Solution:
To achieve a volume of 30, multiply 5,3, and 2 together. Density is defined as the ratio of mass to volume, thus divide 129 by 30. You'd obtain a mass of 4.3.
Therefore 4.3 g/cm³ would be the answer.The cylinder of a car's engine has a volume of 0.6250 L when the piston is at the bottom of the cylinder. When the piston is at the top of the cylinder the volume is 0.0600 L. If the cylinder is filled with air at an atmospheric pressure of 765.1 mm Hg the piston is at the bottom, what is the pressure in units of kPa when the piston is at the top of the cylinder?
The new pressure in the cylinder of the car engine as the piston is moved to the top is 1062.55kPa
Boyle's lawBoyle's law states that "volume of a given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.
It is expressed as;
P₁V₁ = P₂V₂
Given the data in the question;
Initial volume V₁ = 0.6250LNew volume V₂ = 0.0600LInitial pressure P₁ = 765.1mmHg = 1.0067107atmNew pressure P₂ = ?To determine the new pressure as the piston is at the top of the cylinder, we substitute our given values into the expression above.
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = ( 1.0067107atm × 0.6250L ) / 0.0600L
P₂ = 0.629194188Latm / 0.0600L
P₂ = 10.4865698atm
P₂ = 1062.55kPa
Therefore, the new pressure in the cylinder of the car engine as the piston is moved to the top is 1062.55kPa
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What is substitution
We need more context, but here are some definitions for substitution:
Substitution: the action of replacing someone or something with another person or thing.
Substitution effect: The substitution effect is the decrease in sales for a product that can be attributed to consumers switching to cheaper alternatives when its price rises.
But you asked this in chemistry so I think you may be looking for:
Substitution reaction: A substitution reaction is a chemical reaction during which one functional group in a chemical compound is replaced by another functional group. Substitution reactions are of prime importance in organic chemistry.
How many molecules are in 120.0 g of oxygen gas?
1.506 × 10²³ molecules in 120.0 g of oxygen gas.
What are molecules?The slightest particle of importance contains all of the physical and chemical properties of that substance. Molecules are made up of one or more atoms.
If they include more than one atom, the particles can be the same (an oxygen molecule has two oxygen atoms) or additional (a wetness molecule contains two hydrogen particles and one oxygen atom). Natural molecules, such as proteins and DNA, can be created up of many thousands of atoms.Particles are the introductory unit of an element. They consist of a nucleus and cover electrons. When an atom has an insufficient electron shell, it is said to have valence electrons. When two or more additional atoms come concurrently to share outer surface valence electrons, a chemical (covalent) bond is formed, and they join a lower power state. When atoms bond, significance is released in an exothermic response. If the covalent bond is broken and the molecule is split separated, it needs energy information and is thereby endothermic.To learn more about molecules, refer to:
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4. How many moles of oxygen gas are needed to react completely with
3.0 moles of C2,H6.?
Hey there!:
Mole ratio :
2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O
2 moles C₂H₆ -------------------- 7 moles O₂
3.0 moles C₂H₆ ------------------ moles O₂ ??
moles O₂ = 3.0 x 7 / 2
moles O₂ = 21 / 2
moles O₂ = 10.5 moles of O₂
Hope this helps!
Which of the following intermediates are not involved in the acid catalyzed esterification reaction of a carboxylic acid? O a R OH C OH COH O b R HOCH H- OH O c R-C-OH OCH3 O d R-C-OCH3 O e All of the above are intermediates.
All of the above compounds are not involved O R OH C OH COHO, R HOCH H- OH O, R-C-OH OCH3 O, R-C-OCH3 O.
An ester is created when a carboxylic acid is combined with an alcohol and an acid catalyst (along with water). The Fischer esterification is the name of this process. In reality, the reaction is an equilibrium. Alcohol is present in significant excess since it is typically utilized as a solvent.
An ester is created when a carboxylic acid is combined with an alcohol and an acid catalyst (along with water). The Fischer esterification is the name of this reaction.
Given that the entire reaction is reversible, the Fischer esterification mechanism must use either a significant excess of alcohol or a continual removal of water from the solution.
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determine the empirical and molecular formula of a compound composed of 18.24 g carbon, 0.51 g hydrogen, and 16.91 g fluorine and has a molar mass 562.0 g/mol.
Answer: The empirical formula for the given compound is \(C_3HF_2\) and molecular formula for the given compound is \(C_{24}H_8F_{16}\)
Explanation : Given,
Mass of C = 18.24 g
Mass of H = 0.51 g
Mass of F = 16.91 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =\(\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{18.24g}{12g/mole}=1.52moles\)
Moles of Hydrogen = \(\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.51g}{1g/mole}=0.51moles\)
Moles of Fluorine = \(\frac{\text{Given mass of Fluorine}}{\text{Molar mass of Fluorine}}=\frac{16.91g}{19g/mole}=0.89moles\)
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.51 moles.
For Carbon = \(\frac{1.52}{0.51}=2.98\approx 3\)
For Hydrogen = \(\frac{0.51}{0.51}=1\)
For Fluorine = \(\frac{0.89}{0.51}=1.74\approx 2\)
Step 3: Taking the mole ratio as their subscripts.
The ratio of C : H : F = 3 : 1 : 2
The empirical formula for the given compound is \(C_3H_1F_2=C_3HF_2\)
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is :
\(n=\frac{\text{molecular mass}}{\text{empirical mass}}\)
We are given:
Molar mass = 562.0 g/mol
Mass of empirical formula = 3(12) + 1(1) + 2(19) = 75 g/eq
Putting values in above equation, we get:
\(n=\frac{562.0}{75}=7.49\approx 8\)
Multiplying this valency by the subscript of every element of empirical formula, we get:
\(C_3HF_2=(C_3HF_2)_n=(C_3HF_2)_8=C_{24}H_8F_{16}\)
Thus, the molecular formula for the given compound is \(C_{24}H_8F_{16}\)
The proportionate of the atom found in a given compound is called the empirical formula while the molecular formula represents the actual digits of the atoms found in the given molecule of the compound.
The empirical formula for the given compound is \(\rm C_{3}HF_{2}\) and molecular formula for the given compound is \(\rm C_{24}H_{8}F_{16}\).
The empirical formula can be determined as:Given,
Mass of C = 18.24 gMass of H = 0.51 gMass of F = 16.91 gStep 1: For determining the empirical formula, convert mass into moles:
For Carbon:
\(\begin{aligned}&\rm Moles \;of \;Carbon = \dfrac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}\\\\&= \dfrac{18.24 \rm g}{ 12 \rm g/mol}\\\\&=1.52\text{ moles}\end{aligned}\)
For Hydrogen:
\(\begin{aligned}&\rm Moles \;of \;Hydrogen= \dfrac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}\\\\&= \dfrac{0.51\rm g}{ 1\rm g/mol}\\\\&=0.51\text{ moles}\end{aligned}\)
For Fluorine:
\(\begin{aligned}&\rm Moles \;of \;Fluorine= \dfrac{\text{Given mass of Fluorine}}{\text{Molar mass of Fluorine}}\\\\&= \dfrac{16.91\rm g}{ 19\rm g/mol}\\\\&=0.89\text{ moles}\end{aligned}\)
Step 2: Calculation of mole ratio for the assigned elements:
For this divide the moles of elements with the smallest number of moles calculated above.
\(\begin{aligned}\text{For Carbon} & = \dfrac{1.52 }{0.51}\\&= 2.98\end{aligned}\)
Moles of C = 3
\(\begin{aligned}\text{For Hydrogen}& = \dfrac{0.51}{ 0.51}\\&= 1\end{aligned}\)
Moles of Hydrogen = 1
\(\begin{aligned}\text{For Fluorine}& = \dfrac{0.89}{ 0.51}\\&= 1.74\end{aligned}\)
Moles of Fluorine = 2
Step 3: The calculated mole ratio will be the subscript of the elements.
C : H : F = 3 : 1 : 2
Therefore, the empirical formula will be,
\(\rm C_{3}H_{1}F_{2} \;or\; C_{3}HF_{2}\)
The molecular formula can be determined as:Determining the valency (n):
\(n = \dfrac {\text{molecular mass} }{\text{empirical mass}}\)
Given,
Molar mass = 562.0 g/molMass of empirical formula = \(3(12) + 1(1) + 2(19)\)= 75 g/eq
Substituting values in the above equation, we get:
\(\begin{aligned}n &= \dfrac{562 }{ 75}\\\\&= 7.49 \\\\&= 8\end{aligned}\)
Multiply the valency calculated with the empirical formula:
\(\begin{aligned}\rm C_{3}HF_{2} &=\rm (C_{3}HF_{2})n\\&= \rm (C_{3}\rm HF_{2})8\\\\\\\\&= \rm (C_{24}H_{8}F_{16})\end{aligned}\)
Therefore, the molecular formula is \(\rm C_{24}H_{8}F_{16}\).
Thus, the empirical formula is \(\rm C_{3}HF_{2}\) and the molecular formula is \(\rm C_{24}H_{8}F_{16}\).
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Compare and contrast the characteristics of metals and nonmetals.