Answer:
The horizontal velocity vector of the canonball does not change at all, but is constant throughout the flight.
Explanation:
First, I'll assume this is a projectile simulation, since no simulation is shown here. That been the case, in a projectile flight, there is only a vertical component force (gravity) acting on the body, and no horizontal component force on the body. The effect of this on the canonball is that the vertical velocity component on the canonball goes from maximum to zero at a deceleration of 9.81 m/s^2, in the first half of the flight. And then zero to maximum at an acceleration of 9.81 m/s^2 for the second half of the flight before hitting the ground. Since there is no force acting on the horizontal velocity vector of the canonball, there will be no acceleration or deceleration of the horizontal velocity component of the canonball. This means that the horizontal velocity component of the canonball is constant throughout the flight
Two stars, one twice as massive as the other, are 1.0 light-year (ly) apart. One light year is the distance light travels in one year at the speed of light, 3.00×10^8m/s. The gravitational potential energy of this double-star system is −6.5 ×10^34J.
Q: What is the mass of the lighter star?
The mass of the lighter star is 2.15 x 10³⁰ kg.
What is the mass of the light star?The mass of the lighter star is obtained by applying the formula force gravitational potential energy between the two stars.
According to Newton's law of universal gravitation, every two objects in the universe attracts each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects.
U = F x r
U = Gm₁m₂/r² x r
U = Gm₁m₂/r
where;
G is universal gravitation constantm₁ is the mass of the first starm₂ is the mass of the second starr is the distance between the two starsr = 3 x 10⁸ m/s x 3.154 x 10⁷ s/yr
r = 9.46 x 10¹⁵ m
let the lighter star = m₁
then, the heavier star = 2m₁
U = (G x m₁ x 2m₁)/r
U = 2Gm₁²/r
Ur = 2Gm₁²
m₁² = Ur/2G
m₁ = √(Ur/2G)
m₁ = √(6.5 x 10³⁴ x 9.46 x 10¹⁵ / 2 x 6.626 x 10⁻¹¹)
m₁ = 2.15 x 10³⁰ kg
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If the volume of the balloon is 500 m3m3 and the surrounding air is at 15.0 ∘C∘C, what must the temperature of the air in the balloon be for it to lift a total load of 290 kgkg (in addition to the mass of the hot air)? The density of air at 15.0 ∘C∘C and atmospheric pressure is 1.23 kg/m3
Answer:
Temperature of the air in the balloon = 272°C
Explanation:
Given:
Volume of balloon = 500 m³
Air temperature = 15° C = 273 + 15 = 288 K
Total weight = 290 kg
Density of air = 1.23 kg/m³
Find:
Temperature of the air in the balloon
Computation:
Density of hot air = Density of air - [Total weight / Volume of balloon]
Density of hot air = 1.23 - [290 - 500]
Density of hot air = 0.65 kg/m³
[Density of hot air][Temperature of the air in the balloon] = [Density of air][Air temperature ]
Temperature of the air in the balloon = [(1.23)(288)]/(0.65)
Temperature of the air in the balloon = 544.98
Temperature of the air in the balloon = 545 K
Temperature of the air in the balloon = 545 - 273 = 272°C
Temperature of the air in the balloon to lift a total load of 290 kg is 272°C.
What is temperature?Temperature is the degree of hotness or coldness of the object.
Given is Volume of balloon = 500 m³, Air temperature = 15° C = 273 + 15 = 288 K
Total weight = 290 kg and Density of air = 1.23 kg/m³
Density of hot air = Density of air - [Total weight / Volume of balloon]
Density of hot air = 1.23 - [290 - 500]
Density of hot air = 0.65 kg/m³
Density is inversely proportional to the temperature.
[ρ hot air] x [T air in the balloon] = [ρ air] x [T air ]
Putting the values, we get temperature of the air in the balloon is
T air = [(1.23)(288)]/(0.65)
T air in Kelvin is 545 K
T air in Celcius is 545 - 273 = 272°C.
Thus, the temperature of the air in balloon is 272°C.
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Two objects, A and B, have the same volume and are completely submerged in a liquid, although A is deeper than B. Which object, if either, experiences the greater buoyant force?
a. Object B, because the closer an object is to the surface, the greater is the buoyant force.
b. Both objects experience the same buoyant force.
c. Object A, because, being at a greater depth, it experiences a greater pressure.
Answer:it would probably be C
Explanation:
7. [Honors] A turn of radius 100 m is being designed for a speed of 25 m/s. At what angle should the turn be banked?
Answer:
The angle at which a turn should be banked depends on the speed of the vehicle, the radius of the turn, and the acceleration due to gravity. To calculate the angle, we can use the following formula:
tanθ = v^2 / (g * r)
where
θ is the angle at which the turn should be banked (in radians)
v is the speed of the vehicle (in m/s)
g is the acceleration due to gravity (approximately 9.81 m/s^2)
r is the radius of the turn (in meters)
Plugging in the values given in the problem, we get:
tanθ = (25 m/s)^2 / (9.81 m/s^2 * 100 m)
tanθ = 6.44
Taking the inverse tangent of both sides, we get:
θ = tan^-1(6.44)
θ ≈ 80.5 degrees
Therefore, the turn should be banked at an angle of approximately 80.5 degrees.
Help pls!!
What is the gravitational potential energy of an object of weight 24 N at a height of 3.2 m from the ground?
The gravitational potential energy (PE) of an object can be calculated using the formula:
PE = mgh
Where:
PE is the gravitational potential energy
m is the mass of the object
g is the acceleration due to gravity
h is the height or distance above the reference point (usually the ground)
In this case, you provided the weight of the object, which is 24 N. The weight of an object is the force due to gravity acting on it, and it can be calculated using the formula:
Weight = mg
Where:
Weight is the force due to gravity
m is the mass of the object
g is the acceleration due to gravity
Since you haven't provided the mass of the object, we can find it by rearranging the weight formula:
m = Weight / g
Now, we can calculate the mass of the object:
m = 24 N / 9.8 m/s² ≈ 2.45 kg
Now we have the mass (m = 2.45 kg), the height (h = 3.2 m), and the acceleration due to gravity (g ≈ 9.8 m/s²). Plugging these values into the formula for gravitational potential energy:
PE = mgh
= 2.45 kg × 9.8 m/s² × 3.2 m
≈ 76.736 J
Therefore, the gravitational potential energy of the object at a height of 3.2 m from the ground is approximately 76.736 joules (J).
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A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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A rectangular box is to have a square base and a volume of 20 ft3. The material for the base costs 30 cents/ft2, the material for the sides costs 10 cents/ft2, and the material for the top costs 20 cents/ft2. Letting x denote the length of one side of the base, find the function x giving the cost of constructing the box.
The function x giving the cost of constructing the box, cost = 50x² + 40xy
Does volume have a formula?A basic formula for volumes is length, breadth, and height, as opposed to length, width, and height for the area of the a rectangular shape. The calculation is unaffected by how you reference to the various dimensions; for instance, you can use "depth" instead of "height."
Let,
length = x ft
width = x ft
height = y ft
volume= x² × y = 20 ft³
y = 20/x²
cost = 30(x²) + 10(4)(xy) + x²( 20)
cost = x² ( 50 ) + 40(x)( 20x²)
cost = 50x² + 40xy
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a ball is thrown straight up into the air with an initial speed of 3.1 m/s. a. After 0.24 seconds what is the ball's velocity and b. what is it's acceleration?
a. The ball's velocity after 0.24 s is 0.75 m/s
b. The acceleration of the ball is given by the acceleration due to gravity
a. The ball's velocity can be calculated with the following equation:
\( v_{f} = v_{0} - gt \)
Where:
\( v_{f} \): is the final speed =?
\(v_{0}\): is the initial speed = 3.1 m/s
g: is the acceleration due to gravity = 9.81 m/s²
t: is the time = 0.24 s
The minus sign is because the acceleration is in the opposite direction (downward) of the motion of the ball (upward).
The final speed is:
\( v_{f} = v_{0} - gt = 3.1 m/s - 9.81 m/s^{2}*0.24 s = 0.75 m/s \)
Hence, the ball's velocity after 0.24 s is 0.75 m/s.
b. The acceleration of the ball is given by the acceleration due to gravity because the ball is thrown straight up (the motion of the ball is in the y-direction). The velocity of the ball in the x-direction is zero so the acceleration in the same direction is also zero.
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HELP PLEASE THIS IS URGENT!!!
The neutron number of an atom X, which undergoes alpha, and beta decay reduces the neutron number by 6.
Alpha decay is the nuclear process in which the parent nucleus emits an alpha or helium particle to form a daughter nucleus. When a particle emits an alpha nucleus, the nucleus loses its two protons and two neutrons. Beta decay is the nuclear process in which the parent nucleus undergoes the emission of electrons to produce a daughter nucleus.
Alpha decay decreases the atomic mass number decreases by 4 and the atomic number decreases by 2. In beta decay, the neutron is converted into a proton and the atomic number decreases by one. The neutron number is affected by alpha decay.
From the given,
X atom undergoes alpha decay. X -----> ₐ₋₂Xᵇ⁻⁴ + He₂⁴. The neutron number decreases by two. ₐ₋₂Xᵇ⁻⁴ -----> ₐ₋₂₋₂Xᵇ⁻⁴⁻⁴ + He₂⁴. The neutron number decreases by two.
When the X atom undergoes beta decay, ₐ₋₄Xᵇ⁻⁸---> ₐ₋₅Xᵇ⁻⁸ + ₋₁e⁰. The neutron number does not get affected. When the atom again undergoes alpha decay, ₐ₋₅Xᵇ⁻⁸ -----> ₐ₋₇Xᵇ⁻¹². Thus, the neutron number decreases by 6 when the atom undergoes three alpha decay.
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What's the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s?
Question 16 options:
A)
12,000 J
B)
2,940 J
C)
6,000 J
D)
5,880 J
the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s is 6,000 J. Option C is correct answer.
The kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20 m/s can be calculated by using the formula:
K.E = 1/2 mv²
Where, K.E = Kinetic energy of the objectm = Mass of the objectv = Velocity of the object
Putting the given values in the above formula:
K.E = 1/2 mv²K.E = 1/2 × 30 kg × (20 m/s)²K.E = 1/2 × 30 × 400K.E = 6000 joules
The correct answer is C.
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What is mass divided by volume
Answer:
mass/volume is the density of an object
A passenger plane is travelling down the runway with a speed of 20\,\dfrac{\text{km}}{\text{h}}20 h km 20, start fraction, start text, k, m, end text, divided by, start text, h, end text, end fraction, then speeds up with constant acceleration over 2.4\,\text{km}2.4km2, point, 4, start text, k, m, end text over 59\,\text{s}59s59, start text, s, end text. We want to find the final velocity of the plane at the moment of take-off. Which kinematic formula would be most useful to solve for the target unknown?
Given that,
Initial speed, u = 20 km/s
Acceleration of plane, a = 2.4 km/h²
Time, t = 59 s
We need to find the expression to find the final velocity of an object.Let the final velocity is v.
Using the second equation of kinematics:
\(\Delta s=ut+\dfrac{1}{2}at^2\)
a is acceleration, \(a=\dfrac{v-u}{t}\)
So,
\(\Delta s=ut+\dfrac{1}{2}\times \dfrac{v-u}{t}\times t^2\\\\\Delta s=ut+\dfrac{1}{2}(v-u)t\\\\\Delta s=\dfrac{2ut+vt-ut}{2}\\\\\Delta s=\dfrac{vt+ut}{2}\\\\\Delta s=(\dfrac{v-u}{2})t\)
We can use the above formula to find the final velocity (v) of the plane.
Part 1
1. Consider the potential energy diagram shown below. This graph shows the chemical potential energy in a reaction system over time. The y–axis is potential energy in kilojoules. The x–axis is the reaction progress, or time.
a. Does this graph represent an endothermic or an exothermic reaction? Explain your answer.
b. What is the enthalpy change, ΔH, for this reaction? Show your work.
c. What is the activation energy, Ea, for this reaction? Show your work.
Part 2
2. In a particular chemical reaction, the energy of the reactants is 30 kJ and the energy of the products is 5 kJ. The maximum energy of the system is 40 kJ. Use this information to answer questions a – d.
a. Sketch a potential energy diagram for this reaction. Make sure to label the energy of the reactants, the energy of the products, the activation energy, and the enthalpy change for the reaction. (Note: You may use the graph provided below or sketch your own. Resize as needed.)
b. What is the activation energy for this reaction?
c. What is the enthalpy change for this reaction?
d. Is this reaction endothermic or exothermic? Explain your answer in two ways: first, using the energy values, and second, by referring to the shape of the graph.
Part 3
3. The coating on the head of a match is highly flammable. When it burns, it releases a great deal of energy. However, before the match can burn, it must gain a small amount of energy from a spark. That spark is typically produced by striking (rubbing) the match head against a rough surface.
a. Sketch a potential energy diagram that represents the striking and burning of the match. Remember to label the diagram with the energy changes that occur. (Note: you do not have to use actual energy values. And you may use the graph provided below or sketch your own.)
b. Describe a potential energy diagram that represents the striking and burning of the match.
1a) Energy is absorbed, and the reaction is endothermic.
1b) The products have higher potential energy, the enthalpy change is positive, indicating an endothermic reaction.
1c) The peak of the potential energy diagram.
2a) The activation energy labeled as the difference between the reactants and the peak
2b) The activation energy can be determined by calculating the difference between the reactants.
2c) The enthalpy change can be calculated by finding the difference between the energy of the reactants and the energy of the products.
2d) The reaction is exothermic. In terms of the graph's shape.
3a) A decrease in potential energy as the products form.
3b)This indicates that a small amount of energy from the spark is needed to overcome the activation energy barrier
Part 1:
1a. To determine if the reaction is endothermic or exothermic, we need to analyze the potential energy diagram. If the products have lower potential energy than the reactants, it indicates that energy is released, and the reaction is exothermic. Conversely, if the products have higher potential energy than the reactants, it suggests that energy is absorbed, and the reaction is endothermic.
1b. The enthalpy change (ΔH) for the reaction can be calculated by comparing the potential energy of the products and the reactants. If the products have lower potential energy, the enthalpy change is negative, indicating an exothermic reaction. If the products have higher potential energy, the enthalpy change is positive, indicating an endothermic reaction.
1c. The activation energy (Ea) can be determined by examining the energy difference between the reactants' potential energy and the peak of the potential energy diagram.
Part 2:
2a. Since the energy of the reactants is 30 kJ, the energy of the products is 5 kJ, and the maximum energy of the system is 40 kJ, we can sketch a potential energy diagram with the reactants at 30 kJ, the products at 5 kJ, the activation energy labeled as the difference between the reactants and the peak, and the enthalpy change as the difference between the reactants and products.
2b. The activation energy can be determined by calculating the difference between the reactants' energy and the peak of the potential energy diagram.
2c. The enthalpy change can be calculated by finding the difference between the energy of the reactants and the energy of the products.
2d. Based on the energy values, if the energy of the products is lower than the energy of the reactants, the reaction is exothermic. In terms of the graph's shape, if the potential energy decreases from reactants to products, it indicates an exothermic reaction.
Part 3:
3a. The potential energy diagram for the striking and burning of a match can be sketched to show the initial potential energy of the reactants, a peak representing the activation energy, and a decrease in potential energy as the products form.
3b. The potential energy diagram would show an initial higher potential energy for the reactants, a peak representing the activation energy required for the reaction to occur, and a decrease in potential energy as the products form. This indicates that a small amount of energy from the spark is needed to overcome the activation energy barrier, leading to the release of a greater amount of energy during the burning process.
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Calculate de speed of the wave
wavelength = 2.3 cm and frequency = 3.7 Hz
First we'll have to convert centimeter into meter.
\(\large\boxed{\bold{1 \: cm= 100 \: m}}\)
So we'll have to divide 2.3 cm by 100.
\(\frac{2.3}{100}\)
\(\bold{= 0.023 \: m}\)
Now, we can find the speed of the wave.\(\large \boxed{\bold{v= {f}{λ}}}\)
In this question all the values are given so we'll simply have to substitute and solve.
Let's solve!
To find the speed, we'll have to multiply the wavelength and frequency.
Substitute the values according to the formula.
\(v= 0.023\times 3.7\)
\(\large\boxed{\bold{v= 0.0851 \: m/s}}\)
Therefore, the speed of the given wave is 0.0851 m/s
Two identical circular loops of metal wire are lying on a table without touching each other. Loop -A carries a current which increases with time. In response, the loop-B:_________.
A. remains stationary
B. is attracted by the loop A
C. is repelled by the loop A
D. roatates about its CM with CM fixed
E. none of these
Answer:
E. none of these
Explanation:
If two loops are lying next to each other, with one of the loop carrying a time varying current, the other loop is induced with an induced current, causing an induced voltage to flow through the other loop. The phenomenon is known as electromagnetic induction. Options listed from A to D are all wrong, so we pick option E
which quanities are scalars
Answer:
they are quantities with magnitude without direction e.g weight,
PLS ANSWER QUICK PLS
How does the medium vibrate in a transverse wave?
A. Parallel to the direction the wave travels
B. With twice the force of the energy provided
C. With half the force of the energy provided
D. At right angles to the direction the wave travels
Answer:
A medium vibrates at right angles to the direction of travel (D transverse) such as an electrical wave in space
A medium vibrates parallel to the direction for a longitudinal wave such as a sound wave in air
Some free market economist think that people would lack motivation without monetary incentives .
It is possible to study the connection between motivation, rewards, and production from a variety of angles, including those of economics, psychology, and physics.
Do incentives exist in a free market system?Because producers are motivated to satisfy consumer demand, free markets offer a larger variety of commodities than any other system. What is created is under the control of the consumer.
What drawbacks exist in a free market economy?In theory, free markets work best because supply and demand are efficiently distributed by an invisible hand. Yet, in practise, open markets are prone to manipulation, false information, and imbalances of power and knowledge, which also contribute to wealth disparity.
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For a reaction for which the activation energies of forward and reverse reactions are equal:A.ΔH=0B.ΔS=0C.the order is zeroD.there is no catalyst
When the activation energies of the forward and backward processes are equal, the energy of the reactant and product becomes equal.
Therefore, E=EAEB=0. The reaction has reached equilibrium when the forward and reverse reaction rates are equal to one another. When the rate of the forward reaction equals the rate of the reverse reaction, a system is said to be in chemical equilibrium. The activation energy () of the reverse reaction is the SUM of the activation energy of the forward reaction AND the energy released from the forward reaction, according to the information provided.
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Three 7Ω resistors are connected in series across a 10 V battery. What is the equivalent resistance of the circuit?
ANSWER:
21Ω
STEP-BY-STEP EXPLANATION:
Given:
R1 = R2 = R3 = 7Ω
The resistance in a series circuit has the following equation
\(R_{eq}=R_1+R_2\ldots+R_n\)We replacing in this case:
\(\begin{gathered} R_{eq}=R_1+R_2+R_3 \\ R_{eq}=7+7+7 \\ R_{eq}=21\Omega \end{gathered}\)The equivalent resistance of the circuit is 21Ω
Suppose you have a barometer with mercury and a barometer with water. How does the height hwater compare with the height hmercury?.
The heaviest liquid is mercury. In order to equalize the air pressure, it only climbs 76 cm. Water will rise to a 13.6 because it is 13.6 times lighter than mercury. By a factor of 13.6, mercury is 13.6 times denser than water.
Therefore, the barometer's height would be 13.6 times higher if water were employed in place of mercury. Since water expands when it freezes, the glass tube would be broken.
Because of its high density, mercury is frequently employed in barometers, allowing for a column height that is appropriate for measuring atmospheric pressure. For example, a mercury barometer would need to be 13.6 times taller than a water barometer to measure the same change in pressure.
This is the primary justification for using mercury in thermometers. Mercury will provide accurate readings in comparison to water since it lacks the condensation property that water possesses. Mercury can be used to measure both negative and positive temperatures, whereas water cannot be used to measure either.
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7. A car stops at a red light. The light turns green
and the car accelerates up to a constant speed. After
several minutes, the car slows down and stops at the
next red light. Which graph shows the car's motion?
Answer:
Graph C
Explanation:
This is the answer because it is the only one that shows the vehicle accelerate to a constant speed before stopping and slowing down.
PLS HELP The moon orbits the Earth every 27 days. The distance between the Earth and the moon is 3.84 x 10^8 m. What is the tangential velocity of the moon?
Round your answer to the nearest whole number. Your answer should be in units of m/s.
The tangential speed of the moon as it leaves the orbit of the earth to the nearest whole number is 9 * 10^7 m/s.
What is the tangential velocity?We know that the tangential velocity has to do with the velocity of the moon when it leaves the circular orbit of the earth. For this we have to call to mind some of the basics of the circular motion. We have to use the formula that says;
V = 2πr/T
We now have to define each and every one of the terms that we have in the equation so that we can be able to apply them to be able to solve the problem meaningfully and we have;
V = velocity
r = Distance covered
T = Period
Where we have from the question;
V = ?
r = 3.84 x 10^8 m
T = 27 days
V = 2 * 3.142 * 3.84 x 10^8/27
V = 8.9 * 10^7 m/s
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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 60.0-kg man just before contact with the ground has a speed of 4.18 m/s. (a) In a stiff-legged landing he comes to a halt in 1.00 ms. Find the magnitude of the average net force that acts on him during this time. (b) When he bends his knees, he comes to a halt in 0.245 s. Find the magnitude of the average net force now. (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of the forces, find the magnitude of the force applied by the ground on the man in part (b).
Answer:
a) The average force that acts on the man is \(2.508\times 10^{8}\) newtons.
b) The average force that acts on the man is 1023.673 newtons.
c) The force of the ground on the man is 1612.093 newtons upwards.
Explanation:
a) After a careful reading of the statement we construct the following model by applying Impact Theorem, that is:
\(m\cdot \vec v_{A} + \vec F \cdot \Delta t = m\cdot \vec v_{B}\) (Eq. 1)
Where:
\(m\) - Mass of the man, measured in kilograms.
\(\vec v_{A}\) - Initial velocity of the man, measured in meters per second.
\(\vec v_{B}\) - Final velocity of the man, measured in meters per second.
\(\Delta t\) - Impact time, measured in seconds.
\(\vec F\) - Average net force, measured in newtons.
Now we proceed to clear average net force within expression:
\(\vec F \cdot \Delta t = m\cdot (\vec v_{B}-\vec v_{A})\)
\(\vec F = \frac{m}{\Delta t}\cdot (\vec v_{B}-\vec v_{A})\) (Eq. 2)
If we know that \(m = 60\,kg\), \(\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right]\), \(\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right]\) and \(\Delta t = 1\times 10^{-6}\,s\), we obtain the following vector:
\(\vec F = \frac{60\,kg}{1\times 10^{-6}\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right]\)
\(\vec F = 2.508\times 10^{8}\,\hat{j}\,\,\,[N]\)
The average force that acts on the man is \(2.508\times 10^{8}\) newtons.
(b) If we know that \(m = 60\,kg\), \(\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right]\), \(\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right]\) and \(\Delta t = 0.245\,s\), we obtain the following vector:
\(\vec F = \frac{60\,kg}{0.245\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right]\)
\(\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right]\)
The average force that acts on the man is 1023.673 newtons.
(c) From Second Newton's Law we find the following equation of equilibrium:
\(\vec F = \vec N -\vec W\) (Eq. 3)
Where:
\(\vec F\) - Average force that acts on the man, measured in newtons.
\(\vec N\) - Force of the ground on the man, measured in newtons.
\(\vec W\) - Weight of the man, measured in newtons.
By applying the concept of weight, we expand the previous equation:
\(\vec F = \vec N -m\cdot \vec g\) (Eq. 3b)
Where \(\vec g\) is the gravitational acceleration, measured in meters per square second.
And then we clear the force of the ground on the man:
\(\vec N = \vec F +m\cdot \vec g\) (Eq. 4)
If we get that \(\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right]\), \(m = 60\,kg\) and \(\vec g = 9.807\,\hat{j}\,\,\,\left[\frac{m}{s^{2}} \right]\), the average force is:
\(\vec N = 1023.673\,\hat{j}\,\,\,[N]+(60\,kg)\cdot (9.807\,\hat{j})\,\,\,\left[\frac{m}{s^{2}} \right]\)
\(\vec N = 1612.093\,\hat{j}\,\,\,\left[N\right]\)
The force of the ground on the man is 1612.093 newtons upwards.
A ball is allowed to fall freely from certain height it covers a distance of 1st sec equal to?
The distance covered by a ball in the first second of free fall is approximately 4.9 meters.
When an object falls freely under the influence of gravity, it experiences constant acceleration. In the case of Earth's gravity, the acceleration due to gravity is approximately 9.8 m/s². This means that the velocity of the falling object increases by 9.8 meters per second every second.
To determine the distance covered by the ball in the first second, we can use the equations of motion for uniformly accelerated motion.
The equation that relates distance (d), initial velocity (u), acceleration (a), and time (t) is:
d = ut + (1/2)at²
In this case, the initial velocity is zero (as the ball starts from rest), the acceleration is 9.8 m/s², and we want to find the distance covered in the first second (t = 1 second).
Plugging in the values:
d = 0 * 1 + (1/2) * 9.8 * (1)^2
d = 0 + (1/2) * 9.8
d = 0 + 4.9
d = 4.9 meters
Therefore, the ball covers a distance of approximately 4.9 meters in the first second of free fall.
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12. A satellite is put into an orbit at a distance from the center of the Earth equal to twice the distance from the center of the Earth to the surface. If the satellite had a weight at the surface of 4000 N, what is the force of gravity (weight) of the satellite when it is in its orbit? Give your answer in newtons, N.
Answer:
Explanation:
F = GmM/d²
As gravity force is proportional to the inverse of the square of the distance,
doubling the distance will reduce the weight to a forth.
F' = GmM/(2d)²
F' = ¼GmM/d²
F' = ¼F = ¼(4000)
F' = 1000 N
This question is based on Oscillations and waves. I tried it for days and I just couldn't get it right.
ANSWER:
The maximun velocity is 16.07 m/s
At x = 0.26
The velocity is 8.36 m/s
The accelearion is 286.67 m/s^2
The resorting force is 86 N
STEP-BY-STEP EXPLANATION:
Given:
k = 310 N / m
Max distance = 0.5 m
Mass of block = 0.3 kg
Max velocity:
Using conservation of energy:
\(\begin{gathered} \frac{1}{2}kx^2=\frac{1}{2}mv^2 \\ v^2=\frac{kx^2}{m} \\ \text{ replacing} \\ v^2=\frac{310\cdot0.5^2}{0.3} \\ v=\sqrt[]{258.33} \\ v=16.07\text{ m/s} \end{gathered}\)At x = 0.26 m:
\(\begin{gathered} v^2=\frac{kx^2}{m} \\ v^2=\frac{310\cdot0.26^2}{0.3} \\ v=\sqrt[]{69.85} \\ v=8.36\text{ m/s} \end{gathered}\)Acceleration:
\(\begin{gathered} F=k\cdot x \\ F=m\cdot a \\ \text{ therefore} \\ m\cdot a=k\cdot x \\ a=\frac{k\cdot x}{m} \\ \text{ replacing} \\ a=\frac{310\cdot0.26}{0.3} \\ a=286.67\text{ }\frac{m}{s^2} \end{gathered}\)The resorting force:
\(\begin{gathered} F=m\cdot a \\ \text{ replacing} \\ F=0.3\cdot286.67 \\ F=86\text{ N} \end{gathered}\)How much force is needed accelerate a 35 kg sled from 30 m/s to 65 m/s in 0.4 seconds?
Answer:
F = 3062.5 N
Explanation:
Given that,
The mass of a sled, m = 35 kg
The speed increase from 30 m/s to 65 m/s in 0.4 seconds.
We need to find the force needed to accelerate the car.
Net force is given by :
F = ma
where
a is acceleration of the car.
\(F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{35\times (65-30)}{0.4}\\\\F=3062.5\ N\)
So, the net force is 3062.5 N.
1. The Gravitational Constant, G, is 6.674 X 10-11 m3/kg-s. Using Equation 3 below, what is
the force of gravity (Fa) between you and a table that is 2 meters away, assuming your
table weighs 20 kg? Remember to convert your weight to kg (1 lb. = 0.45 kg). Show your
work, and report your answer with 3 significant figures.
Fy = GX
mi X m2
Equation (3)
d2
HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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