Boiling water can be turned into mist in very cold weather. This occurs due to the boiling water turning into vapor quickly. However, the temperature at which boiling water will turn into vapor depends on numerous factors, such as humidity, atmospheric pressure, and air temperature.
Boiling water's temperature is 212 degrees Fahrenheit, and the heat energy causes water molecules to break down into steam. The steam will rise into the air when it becomes hotter than the air around it. Therefore, boiling water will turn into steam in cold weather if the conditions are ideal.
It is possible to experiment with boiling water in freezing temperatures to produce steam and, at times, water vapor or mist. The ideal temperature for the steam to be visible is 20 degrees below freezing.However, if the conditions are not ideal, the boiling water can quickly freeze in mid-air before it has a chance to evaporate.
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What is the volume of 8.8g of carbon dioxide at STP?
The volume of 8.8g of carbon dioxide at STP is 4.38 L.
At STP, what is 22.4 L?1 mole of any gas will take up 22.4 L of space at standard temperature and pressure (STP). A balanced chemical equation and the Ideal Gas Law can be used to determine the amount or mass of gas consumed or created in a chemical process.
n = m/M
where m is the molar mass of carbon dioxide and M is its mass in terms of molecules.
Considering that the molar mass of carbon dioxide is 44.01 g/mol:
n = 8.8 g / 44.01 g/mol
n = 0.1998 mol
Next, we can plug in the values of n, R, P, and T into the ideal gas law and solve for V:
V = (nRT)/P
V = (0.1998 mol x 0.0821 L·atm/(mol·K) x 273.15 K) / 1 atm
V = 4.38 L
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iodine-131 undergoes beta emission with a decay constant of 0.0864 1/days. if you start with 50.0 mg of the i-131, how many days will it take for the amount of i-131 to drop to 17.5 mg?
It will take approximately 8.26 days for the amount of iodine-131 to drop from 50.0 mg to 17.5 mg.
To determine the number of days it will take for the amount of iodine-131 (I-131) to drop from 50.0 mg to 17.5 mg, we can use the radioactive decay formula:
Amount(t) = Amount(0) * e^(-λt)
Where:
- Amount(t) is the amount of I-131 at time t.
- Amount(0) is the initial amount of I-131.
- λ (lambda) is the decay constant.
- t is the time elapsed.
We can rearrange the formula to solve for t:
t = (1/λ) * ln(Amount(0) / Amount(t))
Substituting the given values:
- Amount(0) = 50.0 mg
- Amount(t) = 17.5 mg
- λ = 0.0864 1/days
t = (1/0.0864) * ln(50.0 / 17.5)
Using a calculator, we can compute the value:
t ≈ 8.26 days
Therefore, it will take approximately 8.26 days for the amount of iodine-131 to drop from 50.0 mg to 17.5 mg.
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Look again at the properties of sodium and chlorine. Then look at the properties of the compound sodium chloride. What do you notice?
explain how the principle of faunal succession connects prehistoric life to the age of sedimentary rocks
The principle of faunal succession is a key concept in the study of prehistoric life and the age of sedimentary rocks. It is based on the idea that the fossilized remains of different species of animals and plants found in sedimentary rocks can be used to infer the relative age of the rocks and the conditions that existed when they were formed.
What are sedimentary rocks?The principle of faunal succession states that over time, the species of animals and plants that lived in a particular area changed and evolved. As a result, the fossilized remains of different species found in sedimentary rocks can be used to infer the relative age of the rocks.
This principle is based on the idea that the fossil record is a record of the evolution of life on Earth. In addition, the principle of faunal succession also provides insight into the ancient environment and climate. For example, the presence of certain types of fossils, such as coral reefs or tropical plants, may indicate that the area was once a warm, shallow sea.
In all, the principle of faunal succession is a powerful tool that connects prehistoric life to the age of sedimentary rocks. By studying the fossilized remains of different species found in sedimentary rocks, scientists can infer the relative age of the rocks and the conditions that existed when they were formed.
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What is 1 mole of CO2?
1 mole of CO2 is 6.022 x 10^23 molecules of CO2. It is also 44.01 g of CO2. Here 44.01 g comes as the sum of individual atoms of CO2 i.e. 12.01 + 16 + 16 i.e. 44.01 g
CO2 is composed of one carbon atom and two oxygen atoms, which have the atomic masses of 12.01 g/mol and 16.00 g/mol respectively. So, the molar mass of CO2 is the sum of the atomic masses of the atoms that make up CO2, which is 12.01 + 16.00 + 16.00 = 44.01 g/mol. Carbon dioxide (CO2) is a naturally occurring compound made up of one carbon atom and two oxygen atoms. It is a colorless, odorless gas and is a byproduct of many biological and industrial processes. CO2 is a greenhouse gas, which means it helps trap heat in the Earth's atmosphere and contributes to global warming.
Therefore, one mole of CO2 weighs 44.01 grams.
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why would you use an excess of a reactant in a chemical reaction?
Using an excess of a reactant in a chemical reaction ensures complete reaction, increases yield, compensates for side reactions or losses, and facilitates reaction monitoring.
It's is a common practice for several reasons:
Ensuring Complete Reaction: By providing an excess of one reactant, it ensures that the other reactant is entirely consumed in the reaction. This is particularly important when the stoichiometry of the reaction requires a specific ratio between the reactants.
Having an excess ensures that the limiting reactant is not exhausted prematurely, allowing the reaction to proceed to completion.
Increasing Reaction Yield: In some cases, having an excess of a reactant can increase the overall yield of the desired product. This is especially true when the excess reactant is less expensive or easier to handle than the other reactant.
By ensuring a surplus of the cheaper or more accessible reactant, the reaction can maximize the production of the desired product.
Compensation for Side Reactions or Losses: In complex reactions, side reactions or losses can occur, leading to a decrease in the yield of the desired product.
Having an excess of one reactant can help compensate for these losses by providing an ample supply to continue the main reaction pathway.
Facilitating Reaction Monitoring: In some cases, the excess reactant can act as a reference or marker, making it easier to monitor the progress of the reaction.
By tracking the consumption of the excess reactant, it becomes simpler to determine the extent of the reaction and the reaction rate.
It's important to note that the decision to use an excess of a reactant depends on the specific reaction and its requirements. Factors such as cost, reactant availability, and desired product yield need to be carefully considered when determining the appropriate stoichiometry for a reaction.
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A chemical reaction is a process where reactants are transformed into new products.
Reactants are the initial chemicals, and products are the new chemicals that are generated. There are times when the amount of reactants utilized in a reaction is more than the amount theoretically needed. This is known as an excess of reactants. The excess of reactants can be added for various reasons.
The reasons are as follows:
1.Incomplete reaction:
When a reaction is incomplete due to a lack of sufficient amounts of reactants, the reaction does not proceed to completion.
Therefore, to guarantee that the reaction goes to completion, it is critical to use an excess of reactants.
2. Reaction Yield:
Using excess reactants increases the yield of the desired product. This means that more products are generated.
3. Catalyst:
In certain reactions, the excess of reactants serves as a solvent or diluent that keeps the catalyst in an optimal concentration, hence allowing the reaction to continue at a faster pace.
For instance, in a reaction that employs sulfuric acid as a catalyst, excess sulfuric acid will keep the reaction going at a rapid pace.
4. Error margin:
When conducting experiments, it is important to have a good margin of error. Adding an excess of reactants ensures that there are enough reactants to get the desired product. The correct amount of reactants can be determined by calculating the percentage yield.
For example, if the theoretical yield is 100 g but the actual yield is only 150 g, the percentage yield will be (150 / 100) x 100 = 150 percent.
The given terms used in the answer are:
1. 1502. Excess3. Chemical
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Which of the following aqueous solutions contains the lowest amount of ions or molecules dissolved in water? 500 ml of 2.25 M CH3OH 500 ml of 0.75 M Nal 1.5L of 0.5 M Na3PO4 20L of 225 M CUCI 1.75L of 1.25 M HBO,
To determine the solution with the lowest amount of ions or molecules dissolved in water, we need to calculate the total number of ions or molecules in each solution.
1. 500 ml of 2.25 M \(CH_3OH\):
Methanol \(CH_3OH\) does not ionize or dissociate in water. Therefore, the total number of ions or molecules in this solution is equal to the number of moles of \(CH_3OH\). Since the molarity is given as 2.25 M, the number of moles can be calculated as follows:
Moles of \(CH_3OH\)= molarity × volume
Moles of \(CH_3OH\)= 2.25 M × 0.5 L (converting 500 ml to liters)
Moles of \(CH_3OH\) = 1.125 mol
Thus, this solution contains 1.125 moles of \(CH_3OH\):.
2. 500 ml of 0.75 M NaI:
Sodium iodide (NaI) dissociates into Na+ and I- ions in water. The total number of ions in this solution can be calculated as follows:
Moles of NaI = molarity × volume
Moles of NaI = 0.75 M × 0.5 L
Moles of NaI = 0.375 mol
Since NaI dissociates into one Na+ ion and one I- ion, the total number of ions in this solution is twice the number of moles of NaI:
Total ions = 2 × Moles of NaI
Total ions = 2 × 0.375 mol
Total ions = 0.75 moles of ions
Thus, this solution contains 0.75 moles of ions.
3. 1.5 L of 0.5 M \(Na_3PO_4\):
Sodium phosphate \(Na_3PO_4\) dissociates into three Na+ ions and one \(PO_4^{3-}\) ion in water. The total number of ions in this solution can be calculated as follows:
Moles of \(Na_3PO_4\) = molarity × volume
Moles of \(Na_3PO_4\) = 0.5 M × 1.5 L
Moles of \(Na_3PO_4\) = 0.75 mol
Since \(Na_3PO_4\) dissociates into three Na+ ions and one \((PO)_4^{3-}\) ion, the total number of ions in this solution can be calculated as follows:
Total ions = 3 × Moles of \(Na_3PO_4\) + 1 × Moles of \(Na_3PO_4\)
Total ions = 3 × 0.75 mol + 1 × 0.75 mol
Total ions = 3.75 moles of ions
Thus, this solution contains 3.75 moles of ions.
4. 20 L of 225 M CuCl:
Copper chloride (CuCl) dissociates into one Cu2+ ion and two Cl- ions in water. The total number of ions in this solution can be calculated as follows:
Moles of CuCl = molarity × volume
Moles of CuCl = 225 M × 20 L
Moles of CuCl = 4500 mol
Since CuCl dissociates into one Cu2+ ion and two Cl- ions, the total number of ions in this solution can be calculated as follows:
Total ions = 1 × Moles of CuCl + 2 × Moles of CuCl
Total ions = 1 × 4500 mol + 2 × 4500 mol
Total ions = 13500 moles of ions
Thus, this solution
contains 13,500 moles of ions.
5. 1.75 L of 1.25 M HBO:
Boric acid (HBO) does not fully dissociate in water. Therefore, we need to consider the undissociated molecules in this solution. The total number of molecules in this solution can be calculated as follows:
Moles of HBO = molarity × volume
Moles of HBO = 1.25 M × 1.75 L
Moles of HBO = 2.1875 mol
Thus, this solution contains 2.1875 moles of HBO molecules.
Comparing the total number of ions or molecules in each solution, we can conclude that the solution with the lowest amount of ions or molecules dissolved in water is 500 ml of 2.25 M CH3OH, which contains only 1.125 moles of CH3OH molecules.
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what does the charge on the electron cloud do
Answer:
Explanation: Of course the negative charge of the electron cloud is balanced by the positive charge of the atomic nucleus for neutral molecules. ... If we were doing this again today, we would designate the electronic charge as positive (and of course the nuclear charge would thus be NEGATIVE!)
Explanation:
Question 1:Describe an electron and how its movement creates an electric current.
Answer
- What is an electron?
An electron a stable subatomic particle with a negative charge of electricity, it is found in all atoms and acting as the primary carrier of electricity in solids.
- How does the electrons movement creates an electric current?
Electrons flow in a certain rate, creating an electric current. So the electrons moving freely from one place to another place will conduct electric current.
48 liters of co2 is kept at -33 degrees Celsius,at what temperature will the volume double
Answer:
The temperature is kept constant. What new volume does the gas occupy? Two hundred liters of gas at zero degrees Celsius are kept under a pressure of 150 kPa.
Explanation:
Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters.
Help! Hurry! I will mark brainliest if you get it correct. NO SPAM!!!!!!!!
S + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O
In the above equation how many moles of water can be made when 134 grams of HNO3 are consumed?
Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0
Answer:
S + HNO3 = H2SO4 + NO2 + H2O
Explanation:
Answer:
Based on stoichiometry HNO3 to H2O is 6:2
Use 9 grams to find the moles of HNO3
9 grams/63g/mol=0.143 moles of HNO3
HNO3:H2O
6:2
0.143*2/6=0.048
H2O moles is 0.048moles
Mass of water =0.048moles*18g/mol=0.864g
To the nearest tenth=0.9grams
Explanation:
I think this is right
what is the molarity of a solution prepared by dissolving 30.0g NaCl in enough water to make a 0.300 L solution?
A. 1.82 M NaCl
B. 0.154 M NaCl
C. 0.833 M NaCl
D. 1.71 M NaCl
Answer:
D.) 1.71 M NaCl
Explanation:
Molarity equation: M= n/v
n= moles of solute
v=liters of solution
NaCl= 58.443 g/mol
30g NaCl / 58.443g/mol = 0.5133(this is n)
0.5133 mols/0.300 L=1.71115674 M
Plz help on question 4
100 points
In an equilibrium expression, the concentrations of ___ are on top.
A:products B:solids C:reactants D:liquids
Answer:
products, it's answer A.
Answer:
products
Explanation:
This exercise uses the radioactive decay model.
The half-life of strontium-90 is 28 years. How long will it take a 70-mg sample to decay to a mass of 56 mg? (Round your answer to the nearest whole number.)
yr
It will take approximately 196 years for a 70-mg sample of strontium-90 to decay to a mass of 56 mg.
Radioactive decay is a process in which unstable atomic nuclei lose energy by emitting radiation. The rate at which radioactive decay occurs can be described using a parameter called the half-life. The half-life is the time it takes for half of the radioactive material to decay.
In this case, the half-life of strontium-90 is given as 28 years. This means that after 28 years, half of the initial amount of strontium-90 will decay.
To calculate the time it takes for the sample to decay to a mass of 56 mg, we can use the concept of half-lives.
Initially, we have a 70-mg sample of strontium-90. After the first half-life of 28 years, the mass will be reduced to 35 mg (half of 70 mg). After the second half-life, it will be reduced to 17.5 mg (half of 35 mg). This process continues until we reach a mass of 56 mg.
By calculating the number of half-lives required to reach a mass of 56 mg, we can determine the time it takes.
Starting with 70 mg, we need to divide it by 2 repeatedly until we reach 56 mg:
70 mg ÷ 2 = 35 mg
35 mg ÷ 2 = 17.5 mg
17.5 mg ÷ 2 = 8.75 mg
8.75 mg ÷ 2 = 4.375 mg
4.375 mg ÷ 2 = 2.1875 mg
2.1875 mg ÷ 2 = 1.09375 mg
1.09375 mg ÷ 2 = 0.546875 mg
0.546875 mg ÷ 2 = 0.2734375 mg
It takes a total of 7 half-lives to reach a mass of approximately 56 mg. Since each half-life is 28 years, we multiply the number of half-lives by the length of each half-life:
7 half-lives × 28 years/half-life = 196 years
Therefore, it will take approximately 196 years for a 70-mg sample of strontium-90 to decay to a mass of 56 mg.
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Write the name of Co4(SiO4)3
Answer:
Copper siliconquadoxide
Explanation:
identify the first step in preparing a spectrophotometer for use.
We have that the first step is to put the Power source into an on state,Thereby powering the Light point and the Spectrophotometer.
From the question we are told
identify the first step in preparing a spectrophotometer for use.
Generally
A SpectrophotometerThis is a device is out there to help scientist i the mostly in the field of chemistry.
This device is used to Know or arcertain particle with light consuming properties.
The Spectrophotometer is Mostly found in laboratories.
And usually in the use of a Spectrophotometer the first step is to put the Power source into an on state.Thereby powering the Light point and the Spectrophotometer
Therefore
The first step is to put the Power source into an on state,Thereby powering the Light point and the Spectrophotometer.
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Earths seasons in Northern Hemisphere: Choose ALL that apply.
Question 4 options:
More concentrated sunlight makes for cooler temperatures
The summer solstice occurs when the earth is in a position so that the North Pole is tilted most directly toward the sun.
The atmosphere absorbs some of the sun's rays
The tilt and revolution of the earth as it moves around the sun cause the different seasons of the year.
The summer solstice occurs when the earth is in a position so that the North Pole is tilted most directly toward the sun.
What is the summer solstice?The summer solstice happens when a pole on either the northern hemisphere or southern hemisphere, is found most inclined toward the sun.
The summer solstice then represents two different moments during the year according to the hemisphere. The summer solstice happens on June 21, and this period represents the longest day of the year.In conclusion, the summer solstice occurs when the earth is in a position so that the North Pole is tilted most directly toward the sun.
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Answer: B and D also hi
Explanation:
The mechanism of glyceraldehyde-3-phosphate dehydrogenase does NOT involve. true or fasle?
The mechanism of glyceraldehyde 3-phosphate dehydrogenase in glycolysis does not include phosphorylation of the substrate using ATP. Hence, option a is false.
What is glyceraldehyde 3-phosphate dehydrogenase ?Glyceraldehyde 3-phosphate dehydrogenase, or GAPDH, is an enzyme with a molecular mass of approximately 37 kDa that catalyzes glycolysis' sixth stage, converting glucose into energy and carbon molecules.
Initially, the carbonyl group of GAP is attacked by a cysteine residue in the active site of GAPDH, resulting in the formation of a hemithioacetal intermediate (covalent intermediate).
At the active site of the enzyme, a histidine residue deprotonates the hemithioacetal . In the ensuing thioester intermediate, deprotonation promotes the reformation of the carbonyl group and the ejection of a hydride ion. Not any step include the use of ATP. Thus, option a is false.
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Your question is incomplete. But, your complete question probably was:
The mechanism of glyceraldehyde-3-phosphate dehydrogenase does NOT involve. true or false?
A phosphorylation of the substrate using ATP.
B oxidation and phosphorylation of the substrate.
C a covalent intermediate.
D an active site histidine to serve as a proton acceptor.
how many grams of N2 are used to produce 35 grams of H2
Approximately 162 grams of N2 are needed to produce 35 grams of H2.
To solve this problem
The balanced chemical equation for the reaction between nitrogen gas (N2) and hydrogen gas (H2) to produce ammonia (NH3) is:
N2 + 3H2 → 2NH3
From this equation, we can see that the mole ratio of N2 to H2 is 1:3. This means that for every 1 mole of N2 used, 3 moles of H2 are consumed.
To calculate how many grams of N2 are needed to produce 35 grams of H2, we first need to convert the mass of H2 to moles:
moles of H2 = mass / molar mass
molar mass of H2 = 2.016 g/mol
moles of H2 = 35 g / 2.016 g/mol ≈ 17.37 mol
Since the mole ratio of N2 to H2 is 1:3, the number of moles of N2 needed is one-third of the number of moles of H2:
moles of N2 = (1/3) × moles of H2
moles of N2 = (1/3) × 17.37 mol ≈ 5.79 mol
We can convert the moles of N2 to grams using the molar mass of N2:
molar mass of N2 = 28.02 g/mol
mass of N2 = moles × molar mass
mass of N2 = 5.79 mol × 28.02 g/mol ≈ 162 g
Therefore, approximately 162 grams of N2 are needed to produce 35 grams of H2.
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the equivalence point of any acid-base titration can be determined visually from a titration curve by finding the place where
Answer:
where the slope of the titration curve is the greatest
The titration curve can be used to identify the equivalency point of the titration.The volume of titrant is where the titration curve has the steepest slope.
How do you find the equivalence point on a titration curve?
The equivalency point for acid-base titrations can be identified quite quickly.A simple pH meter is used to measure the pH of the solution being titrated after different amounts of titrant have been introduced to create a titration curve.The curve can then be read to determine the equivalency point. The equivalency point is identified using thermometric titrimetry, which gauges the rate at which a chemical reaction alters temperature.The inflection point in this instance denotes the threshold at which an exothermic or endothermic process is equivalent. The pH of a solution during a titration is represented graphically by a titration curve.The equivalence point in a strong acid-strong base titration is reached when the moles of acid and base are equal, and the pH is 7. The [H+] and [OH] concentrations must be equal at some point to be considered the equivalency point.Just a little bit beyond that is the endpoint, where the indicator color totally changes and the pH shifts from acidic to basic, or vice versa. The precise halfway point between the reactions of the titrant and the acid in the buffer solution is known as the half equivalence point.Because the pKa of the acid and the pH of the solution are equal at the half equivalence point, finding this point is not too difficult. A weak-acid/strong-base titration will have an equivalent point at a somewhat basic pH.The reason for this is that while the acid is not nearly as strong and does not completely dissociate to neutralize each equivalent of the base, the base is stronger and dissociates to a greater extent.To learn more about acid base titration refer
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A sample of gas collected at 685 mm Hg occupies 131 mL. At constant temperature, what pressure does the gas exert if the volume increases to 478 mL? a. 188 b. 1320 c. 128 d. -88.8
Answer:
a. P=188mmHg
Explanation:
A gas undergoing a change of volume and pressure at constant temperature (and not changing the number of molecules), follows Boyle's Law: \(P_1V_1=P_2V_2\)
The units of these quantities can be any measure of pressure and volume, so long as long as the units are the same between beginning and ending conditions.
Substitute and solve:
\(P_1V_1=P_2V_2\)
\((685[mmHg])(131[mL])=P_2(478[mL])\)
\(\dfrac{(685[mmHg])(131[mL\!\!\!\!\!\!\!\!\!{--}])}{478[mL\!\!\!\!\!\!\!\!\!{--}]}=\dfrac{P_2(478[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}{478[mL] \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----}}\)
\(187.730125523[mmHg]=P_2\)
Accounting for significant figures, \(P_2=188[mmHg]\)
For the chemical reaction3 KOH + H3PO4 → K3PO4 + 3H₂Owhat mass of potassium phosphate is produced from 2.11 mol of potassium hydroxide?
They give us the balanced equation of the reaction.
3 KOH + H3PO4 → K3PO4 + 3H2O
So we can continue with the calculations.
We first find the moles of K3PO4 that will be formed. For that we look at the stoichiometric coefficients of the reaction. The K3PO4 to KOH ratio is 1/3. So the moles of K3PO4 will be:
\(\begin{gathered} molK_3PO_4=givenmolKOH\times\frac{1molK_3PO_4}{3molKOH} \\ molK_3PO_4=2.11molKOH\times\frac{1molK_3PO_4}{3molKOH}=0.703molK_3PO_4 \end{gathered}\)To find the mass we must multiply the moles found by the molar mass of potassium phosphate. The molar mass of potassium phosphate is:212.3g/mol
\(\begin{gathered} MassK_2PO_4=givenmolK_2PO_4\times\frac{MolarMass,gK_2PO_4}{1molK_2PO_4} \\ MassK_2PO_4=0.703molK_2PO_4\times\frac{212.3gK_2PO_4}{1molK_2PO_4}=149.2gK_2PO_4 \end{gathered}\)Answer: The mass of potassium phosphate produced is 149 grams
Mixing two clear liquids results in the formation of a whit solid. Is this a physical or chemical change?
Answer:
Chemical Change
Explanation:
It became white and became solid which makes it a chemical change.
A 1600 watts electric oven is used for 9 hours. Calculate the Cost of using the #3.00 per unit of of energy (Energy consu- med = power x time). What are the functions of the ammeter and Voltmeter ? Solution ( (A
The cost of using 14,400 watts hour would be $43.2.
What is Energy ?Energy is defined as the capacity to do work.
It is given in the question that
A 1600 watts electric oven is used for 9 hours
Power * Time
power = 1600 watts
Time = 9 hours
Total energy consumed = 1600 watts * 9 hours
= 14,400 watts hour
energy is measured in Kilowatts hour
= 14,440 watts hour
14,440/1000 kwh
= 14.4 kwh
It is given that the cost per unit of energy is $3.00 per kwh
Therefore , the cost of using 14,400 watts hour would be 14.4 * 3
= $43.2
The function of Voltmeter and Ammeter is to measure Voltage and Current respectively.
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Which element has higher electronegativity: Nitrogen or Arsenic
Answer:
Definetly Nitrogen
Explanation:
Nitrogen is the most electronegative
If you had a business and you wanted to capitalize on your information about the population age distribution, what would you sell and why?
What a person will sell in a business venture depends on the population age distribution of the target population.
What is a business?Business refers to any venture that an individual or group of individuals indulges in for the purpose of making profit. You do not get into a business blindly. You need accurate information about the business before you can engage in it.
What a person will sell in a business venture depends on the population age distribution of the target population.
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What is the freezing point of neon?
248.4 °C
Explanation:
Boiling point: -246 °C
Atomic mass: 20.1797 u
Symbol: Ne
the formula c12h22o11, which can describe sugar at either the macroscopic or microscopic levels, is an example of which domain?
a. macroscopic domain
b. microscopic domain
c. symbolic domain
The formula C₁₂H₂₂O₁₁, which describes sugar, is an example of the symbolic domain.
In this context, the macroscopic domain refers to the observable properties and behavior of substances at a larger scale, while the microscopic domain refers to the structure and interactions at the molecular or atomic level. The symbolic domain, on the other hand, involves the use of symbols, such as chemical formulas, to represent substances.
The formula C₁₂H₂₂O₁₁ represents a sugar molecule. It provides information about the composition and ratio of atoms in the molecule, allowing us to identify and differentiate it from other substances. This representation belongs to the symbolic domain because it employs chemical symbols (C, H, and O) to represent the elements and subscripts to denote the number of atoms in the molecule.
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Which of the following correctly illustrates the conservation of mass for the reaction below? I choose B but I’m not sure if I’m correct!
Answer: A
\(Na(23\times4=92g);O2(16\times2=32g);Na2O(23+23+16)\times2=124\)Explanation: Based on the Law of conservation of mass the total mass of the reactants will equal to the total mass of the products. This happens as matter is not destroyed.