how can you make a g o ogle m e e t without being warned

Answer:

10

Step-by-step explanation:

1+1=

Step-by-step explanation:

what are the free things

pls give me brainliest

Answer:

the solution means the answer to whatever question / statement

Answer:

42 minutes

Step-by-step explanation:

We can multiply 60 into 7/10 hours to convert 7/10 into hours, since 1 hour is 60 minutes.

= 60 (7/10)

= 420 / 10

= 42

Answer:

42 minutes

Step-by-step explanation:

you just have to remember to multiply and divide (its hard really hard to multiply like that and divide)

The weight is 140 kg, the diameter is 4 mm and the length is 54 m. We need to find diameter D in terms of the weight W and length.Diameter D in terms of weight W and length L is given by sqrt((W * (54 * 16)) / 140).

To solve this problem, we can use the joint variation equation:

W = k * L * D^2  where k is the constant of variation. We can plug in the given values to find the value of k:

140 = k * 54 * 4^2

Simplifying the equation, we have:

140 = k * 54 * 16

Dividing both sides by (54 * 16), we get:

k = 140 / (54 * 16)

Now we can substitute the value of k into the joint variation equation and solve for D:

W = (140 / (54 * 16)) * L * D^2

Rearranging the equation to solve for D, we have:

D^2 = (W * (54 * 16)) / 140

Taking the square root of both sides, we get:

D = sqrt((W * (54 * 16)) / 140)

Therefore, the diameter D in terms of the weight W and length L is given by sqrt((W * (54 * 16)) / 140).

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Step-by-step explanation:

\( \frac{2}{3} x = - 10 \\ \frac{2x}{3} = - 10 \\ 2x = - 10 \times 3 \\ 2x = - 30 \\ x = \frac{ -30}{2} \\ x = - 15\)

Reflection over the x-axis transforms the point (x,y) into (x, -y), then

A(1,8) → A''(1, -8)

M(6,8) → M''(6, -8)

P(2,3) → P''(2, -3)

Rotation 90° clockwise transform the point (x, y) into (y, -x), then

A''(1, -8) → A'(-8, -1)

M''(6, -8) → M'(-8, -6)

P''(2, -3) → P'(-3, -2)

Answer:

The Empty set............

Answer:

There is no solution for the intersection of these two sets, as they do not intersect! They don't have any numbers in common and thus form an empty set. The correct answer choice is option D. the empty set.

Step-by-step explanation:

The solution for { x | x <-5} is ---> x < -5

The solution for { x | x >5 } is ---> x > 5

If you placed the two sets on a number line close to each other, you would see that they do not intersect. Thus there is no solution for the intersection of set A and set B as defined in the given problem.

See the graph for better understanding. You see how there's an empty space or area between -5 and 5? Yeah, this is called the empty set which is option D from your answer choices.

Answer:

option (4)

Step-by-step explanation:

y = - 2x +7 → (1)

y = 4x - 5 → (2)

substitute y = 4x - 5 into (1)

4x - 5 = - 2x + 7 ( add 2x to both sides )

6x - 5 = 7 ( add 5 to both sides )

6x = 12 ( divide both sides by 6 )

x = 2

substitute x = 2 into either of the 2 equations and solve for y

substituting into (2)

y = 4(2) - 5 = 8 - 5 = 3

solution is (2, 3 )

\(\red{\boxed{ \green{\sf Option \: 4: (2 \: , 3)}}}\)

\( \\ \)

\( \sf First, \: we \: have \: to \: understand \: that: \\ \sf If \: \red{y} = \orange{a} \: and \: \red{y} = \blue{b}, \: then \: \orange{a} = \blue{b}.\)

\( \\ \)

\(\sf Let \: \orange{-2x+7} \: be \: \orange{a} \: and \: \blue{4x-5 \\ } \: be \: \blue{b}.\)

\(\star \: \sf Solve \: the \: equation \: \orange{a} = \blue{b}. \: \star\)

\( \\ \)

\( \sf \orange{a} = \blue{b} \\ \Longleftrightarrow \sf \orange{ - 2x + 7} = \blue{4x - 5} \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \diamond \: \sf Subtract \: 4x \: from \: both \: sides. \diamond \\ \\ \Longleftrightarrow \sf - 6x + 7 = - 5 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \diamond \: \sf Subtract \: 7 \: from \: both \: sides. \diamond \\ \\ \Longleftrightarrow \sf - 6x = - 12 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \diamond \: \sf Divide \: both \: sides \: by \: -6. \: \diamond \\ \\ \Longleftrightarrow \sf x = \dfrac{ - 12}{ - 6} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \Longleftrightarrow \boxed{\sf \purple{x = 2}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \)

\( \\ \)

\(\star \: \sf Remplace \: \purple{x} \: with \: \purple{2} \: in \: one \: of \: the \: given \: equations. \: \star\)

\( \\ \)

\( \sf \red{y }= - 2 \purple{x} + 7 \\ \implies \sf \red{y} = - 2 \purple{(2)} + 7 \: \: \: \: \: \: \\ \\ \implies \boxed{\sf \red{y= 3}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \)

\( \\ \)

Therefore, the point which is a solution to the system of equations is (2 , 3). This corresponds to option 4.

Answer: 1/2 of 12 = 1/4 of 24 and 1/3 of 90 = 2/3 of 45

Step-by-step explanation:

Answer:

1. 1/4 of 24

half of 12 is 6.

6+6+6+6 = 24

1/4 of 24 is 6

1/2 of 12 is 6

2. 2/3 of 45

1/3 of 90 is 30

15+15+15 = 45

so 2/3 would be 30

Answer:

The three medians intersect at a single point.

Step-by-step explanation:

PLATO MAKE BRAINLIEST PLZZ

Centroid is that point where median draw from the center of each side in a triangle meet.

The centroid is the centre point of the object. The point in which the three medians of the triangle intersect is known as the centroid of a triangle. It is also defined as the point of intersection of all the three medians.

Let,

There is a triangle ΔABC

Mark midpoints on sides AB, BC and CA which lets P, Q and R respectively.

Join PC, RB and QA

The point where PC, RB and QA meets called centroid.

Hence, the point of intersection of three medians is Centroid.

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Based on the ASA Congruence theorem, triangles FEG and DCG are congruent to each other.

Two triangles are considered congruent if their corresponding sides are equal in length and their corresponding angles are equal in measure.

The two-column proof would be expressed as follows:

Statement                                     Reason                                    

1. CD║FE; FG ≅ GD                     1. Given

2. <GFE ≅ <GDC                         2. Alternate interior angles theorem

3. <FGE ≅ <DGC                         3. Vertical angles theorem

4. ΔFEG ≅ ΔDCG                        4. ASA Congruence theorem

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The angles located at positions a, b, c is 70°,45°, 25°.

let's consider what happens with angle c

We can see that the angles a, b and c are the interior angles of a triangle.

we know that a triangle adds up to 180 degrees

If we found out that angle a = 70°, angle b = 45°

we can use this information to find angle c.

Therefore, the angle c = 25°.

The complete question is:

The parallel lines are marked with "feathers". Find the measures of the angles located at positions a, b, c, d, e, & f.

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literally put a picture

Step-by-step explanation:

= -2(x - 5) + 4(9 + x)

= -2x + 10 + 36 + 4x

= (-2 + 4)x + 10 + 36

= 2x + 46

Answer:

Question 1 )

given ,

height of cylinder = 9 cm

diameter of cylinder = 10 cm

\(\dashrightarrow \: radius = \frac{10}{5} \: cm \\ \)

now ,

\(Volume \: of \: cylinder = \pi \: r {}^{2} h \\ \\ substitutng \: the \: values \: of \: h \: and \: r \: \\ \\ \dashrightarrow \: \pi \: \times (\frac{10}{2} ) {}^{2} \times 9 \\ \\ \dashrightarrow \: \pi \: \times 25 \times 9 \\ \\ \dashrightarrow \: 225\pi \: cm {}^{3} \)

therefore ,

option (C) is correct.

______________________________________

______________________________________

Question - 2 )

dimensions of the rectangular prism are 2 × 3 × 4

\(Lateral \: surface \: area = 2h(l + b) \\ \\ \dashrightarrow \: 2 \times 3(4 + 2) \\ \\ \dashrightarrow \: 6(6) \\ \\ \dashrightarrow \: 36 \: cm {}^{2} \)

hope helpful :D

The volume of the cylinder is 225 \(\rm cm^3\)  and the lateral surface area of the rectangular prism is 36 square cm.

It is given that the radius of the cylinder is 10 cm and height is 9 cm.

It is required to find the volume of the cylinder.

It is defined as a three-dimensional space enclosed by an object or thing.

We know the volume of a cylinder given by:

\(\rm V = \pi r^2 h\)

We have diameter = 10 cm

Radius r = 10/2 = 5 cm

and height h = 9 cm

Volume will be:

\(\rm V= \pi \times5^2 \times 9\)

V = 225π cubic cm

For the lateral surface area = 2h(l+b)

= 2×3(4+2)

= 36 square cm

Thus, the volume of the cylinder is 225 \(\rm cm^3\)  and the lateral surface area of the rectangular prism is 36 square cm.

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Answer:

The surface area of the cube is 648.96 sq in.

Step-by-step explanation:

This problem is made a lot easier by the fact that it's a cube.

So we first calculate the area of one of the faces. The length of the side of the side is 10.4 inches, and 10.4 * 10.4 = 100.16.

There are six faces, so we multiply the area of 1 face by 6. 100.16 * 6 = 648.96.

Therefore, the surface area of the cube is 648.96 sq inches.

Hope This Helps!

The real root of the equation is x = 40 - 39√2, which gives a value of S = 2231 approximately.

Given,The strength, S, of a wooden beam depends on the width and depth of the rectangular cross-section of the beam, but not on the length of the beam.

For a particular type of wood, the value of S of a beam is proportional to the product of the width and the square of the depth of its cross-section.

The strength of an oak beam is 69, when the beam is 7 inches wide and 3 inches deep.Thus, we can conclude that k, a constant of proportionality exists, such that: S=k(W x D²), where W is the width, D is the depth of the rectangular cross-section and S is the strength of the beam.

Let's use this to calculate k: When the beam is 7 inches wide and 3 inches deep, S=69. Thus, we get:k = S/W x D²=69/(7 x 3²)=1.

Thus, the equation for S becomes:S = W x D²The radius of the oak tree is 28/2 = 14 inches and the beam must be 14 inches wide.

This implies that the rectangular cross-section of the beam must be square (or the largest rectangular cross-section is a square). Let the side of the square cross-section be x.

Thus, we can write:S = x²Diameter, d = 28 inches => radius, r = 14 inchesWe need to determine the depth of the beam. The depth of the beam is half the height of the cylindrical log from which the beam is cut. The cylindrical log has a diameter of 28 inches. The beam has a width of 14 inches.

The largest rectangular cross-section is a square with sides of length x. This cross-section can be obtained by cutting the log at a height of x/2 from its center.Since the diameter is 28 inches, the radius is 14 inches. The height at which the beam is cut is h = 14 - x/2.

Thus, the depth of the rectangular beam cut from the cylindrical log is given by: D = 2(h) = 2(14 - x/2) = 28 - x.Using the relationship S = W x D² with S = 69, W = 14 and k = 1, we can write:x² (28 - x)² = 69Simplifying the above equation,x⁴ - 56x³ + 784x² - 69 = 0.

Using polynomial long division, we get:(x² + 16x - 69)(x² - 40x + 1) = 0The real root of the equation is x = 40 - 39√2, which gives a value of S = 2231 approximately.Therefore, the  answer is (b) S = 2231.

The strength, S, of a wooden beam depends on the width and depth of the rectangular cross-section of the beam, but not on the length of the beam. Let the side of the square cross-section be x. Thus, we can write:S = x²Diameter, d = 28 inches => radius, r = 14 inches. Using the relationship S = W x D² with S = 69, W = 14 and k = 1, we can write:x² (28 - x)² = 69.The real root of the equation is x = 40 - 39√2, which gives a value of S = 2231 approximately.

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Answer:

\(SA \approx 439.82\:in^2\)

Step-by-step explanation:

Surface Area = \(2\pi r h+2\pi r^2\)

Putting the given values and simplifying, we get:

\(SA \approx 439.82\:in^2\)

Best Regards!

Answer:

7x²+5x+7

Step-by-step explanation:

7x²-3x+5+8x+2

7x²+5x+7

The answer is B. $15,100. The total capital investment in the defender, using the outsider viewpoint is $15,100.What is the outsider viewpoint?

The outsider viewpoint is how much it would cost someone from outside your company to purchase an asset. In this scenario, the outsider viewpoint will be used to determine the capital investment in the defender.

Here's how to go about it: The firm's current automobile (defender) can be sold on the open market for $10,000. Thus, the cost basis of the defender was $12,000 - $10,000 = $2,000 more than the current open market price.

This value ($2,000) is the unamortized value of the defender. To make the defender comparable in continued service to the challenger, your firm would need to make some repairs at an estimated cost of $1,500.

Therefore, the total capital investment in the defender, using the outsider viewpoint, is $10,000 (open market price) + $2,000 (unamortized value) + $1,500 (repair cost) = $15,100. The answer is B. $15,100.What is the unamortized value of the defender?

The unamortized value of the defender is $2,000.The cost basis of the defender was $12,000, and it can be sold on the open market for $10,000.

As a result, the unamortized value is $12,000 - $10,000 = $2,000. The answer is B. $2,000.

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The missing coordinate of point P on the unit circle in the given quadrant is (5, -12). Point P has a positive x-coordinate and lies below the x-axis.

To find the missing coordinate of point P on the unit circle, we need to consider the given information. In the first case, the x-coordinate of P is positive, and the y-coordinate of P is -5. Since the point lies on the unit circle, we can use the Pythagorean theorem to find the missing coordinate. The Pythagorean theorem states that for any point (x, y) on the unit circle, x^2 + y^2 = 1. Plugging in the given values, we have x^2 + (-5)^2 = 1. Solving this equation, we get x^2 + 25 = 1, which leads to x^2 = -24. Since the x-coordinate must be positive, we discard the negative solution, giving us x = sqrt(24) = 2√6. Therefore, the missing coordinate of P is (2√6, -5).

In the second case, the x-coordinate of P is missing, but we know that P lies above the x-axis. Since the point lies on the unit circle, the y-coordinate can be found using the Pythagorean theorem. Since the x-coordinate is missing, we can represent it as x = sqrt(1 - y^2). Plugging in the given y-coordinate of -12, we have x = sqrt(1 - (-12)^2) = sqrt(1 - 144) = sqrt(-143). However, since the x-coordinate cannot be imaginary, we conclude that there is no point P with a positive x-coordinate lying above the x-axis for this case.

Therefore, based on the given information, the missing coordinate of point P on the unit circle is (5, -12), satisfying the conditions of a positive x-coordinate and lying below the x-axis.

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A. Let x represent the number of lollipops produced. Then the weekly cost C in dollars is given byC = 3.50x + 420B. Let x represent the number of lollipops sold. Then the revenue R in dollars is given byR = 5.75x.

A candy producer charges $5.75 for its special lollipop. It costs them $3.50 to produce each lollipop. Additionally, they spend $420 per week to maintain the production. A. (3 points) Let C represent the weekly cost in dollars and let x represent the number of lollipops produced. Write down the producer’s weekly cost function.

B. (3 points) Let R represent the revenue in dollars and let x represent the number of lollipops sold. Write down the producer’s revenue function

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R(x) = 5.75x ,Where x is the number of lollipops sold.

The producer's weekly cost function, C, can be calculated by adding the cost of production per lollipop (which is $3.50) with the cost of maintaining production per week (which is $420). Since the cost of production per lollipop is constant regardless of the number of lollipops produced, we can express the weekly cost function as follows:

C(x) = 3.50x + 420

B. The producer's revenue function, R, can be calculated by multiplying the price at which each lollipop is sold (which is $5.75) by the number of lollipops sold (x). Since the price per lollipop is constant regardless of the number of lollipops sold, we can express the revenue function as follows:

R(x) = 5.75x ,Where x is the number of lollipops sold.

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The sample indicates that the data does not provide sufficient evidence to support the claim that 20% of plants are infected.

This given test is a test for single sample proportion

The test hypothesis are:

\(H_{o} :p=0.20\), null hypothesis

\(H_{1} :p\neq 0.20\), alternative hypothesis

The test statistic fallows a standard normal distribution and is given by:

\(Z=\frac{x-p}{{\sqrt{p(1-p)/n} } }\)

p=0.20

X=47 plants

Sample size, n=500

x, is the sample mean:

x=X/n=47/500

x=0.094

So, test statistic is calculated as:

\(Z=\frac{0.094-0.20}{\sqrt{0.20(1-0.20)/500} }\)

Z=-5.93

From the z-table, the p-value associated with Z=-5.93 is approximately 0

The decision rule based on p-vale, is to reject the null hypothesis if p-value is less than confidence level

In this case, the p-value is very small and less than confidence level of 0.20, we therefore reject the null hypothesis or the claim

So we conclude that the data does not provide sufficient evidence to support the claim that 20% of plants are infected.

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Answer:

below

Step-by-step explanation:

You've been asked to use specific x-values. Simply replace the x in the equation for each of your x-values then graph.

first equation!!

(x,y)

y=-2x+5

x-value: -2

y=-2(-2)+5

y=4+5

y=9

(-2, 9)

x-value: -1

y=-2(-1)+5

y=2+5

y=7

(-1, 7)

x-value: 0

y=-2(0)+5

y=0+5

(0, 5)

x-value: 1

y=-2(1)+5

y=-2+5

y=3

(1, 3)

x-value: 2

y=-2(2)+5

y=-4+5

y=1

(2, 1)

second equation :)

(x,y)

y=x^2 +2

x-value: -2

y=-2^2 +2

y=4+2

y=6

(-2, 6)

x-value: -1

y=-1^2 +2

y=1+2

y=3

(-1, 3)

x-value: 0

y=0^2 +2

y=0+2

(0, 2)

x-value: 1

y=1^2 +2

y=1+2

y=3

(1, 3)

x-value: 2

y=2^2 +2

y=4+2

y=6

(2, 6)

third equation

(x,y)

y=√2 x+1

x-value: 1

y=√2 1+1

y=1+1

y=2

(1, 2)

x-value: 4

y=√2 4+1

y=2+1

y=3

(4, 3)

x-value: 9

y=√2 9+1

y=3+1

y=4

(9, 4)

x-value: 16

y=√2 16+1

y=4+1

y=5

(16, 5)

x-value: 25

y=√2 25+1

y=5+1

y=6

(25, 6)

fourth (last) equation :-)

(x,y)

y=4/x

x-value: -4

y=4/-4

y=-1

(-4, -1)

x-value: -2

y=4/-2

y=-2

(-2, -2)

x-value: -1

y=4/-1

y=-4

(-1, -4)

x-value: 0

y=4/0

y=0

(0, 0)

x-value: 1

y=4/1

y=4

(1, 4)

x-value: 2

y=4/2

y=2

(2, 2)

x-value: 4

y=4/4

y=1

(4, 1)

Now we find the simplified form of algebraic expressions by algebra properties:

First part

Case A: 781 / 576

Case B: 3368 / 1125

Case C: 16

Case D: - 1077 / 200

Case E: - 145 / 144

Case F: - 41 /392

Second part

Case A: - 2 · x · a⁴

Case B: (4 · a⁵ · c³) / (- 3 · b²)

Case C: (4 · x² · w⁵) / (9 · y³)

Case D: (27 · x⁵ · y²) / (80 · z⁹)

Case E: (1600 · x¹⁷ · z⁴) / y¹⁸

Case F: 24 · a⁶ · b³

The first part of this question we find six cases of algebraic expressions involving powers, each of them can be simplified by algebra properties:

Case A:

(3 / 4)⁻² - (4 / 3)⁻³

3⁻² / 4⁻² - 4⁻³ / 3⁻³

3⁻²· 4² - 4⁻³ · 3³

4² / 3² - 3³ / 4³

(4³ · 4² - 3³ · 3²) / (3² · 4³)

(4⁵ - 3⁵) / (3² · 4³)

781 / 576

Case B:

(5 / 3)² - (- 5 / 3)⁻³

5² / 3² - (- 5)⁻³ / 3⁻³

5² / 3² - 3³ / (- 5)³

[5² · (- 5)³ - 3⁵] / [3² · (- 5)³]

3368 / 1125

Case C:

(1 / 4)⁻² - (- 3 / 2)³ - (- 2 / 3)⁻³

4² - (- 3)³ / 2³ - 3³ / (- 2)³

[4² · 2³ - (- 3)³] / 2³ - 3³ / (- 2)³

155 / 8 - 27 / 8

16

Case D:

- (- 2 / 5)⁻³ - [(- 5 / 2)⁻² ÷ 4⁻³]

- (5 / 2)³ - [(- 2 / 5)² ÷ (1 / 4)³]

- (5 / 2)³ - [(- 2)² · 4³] / 5²

- 125 / 8 - (- 256 / 25)

- 125 / 8 + 256 / 25

- 1077 / 200

Case E:

(- 1)¹⁰¹ - 12⁻²

- 1 - 1 / 12²

(- 12² - 1) / 12²

- 145 / 144

Case F:

(- 7)⁻² - 2⁻³

1 / (- 7)² - 1 / 2³

1 / 49 - 1 / 8

- 41 /392

And the second part implies other six cases:

Case A:

- 2 · x / a⁻⁴

- 2 · x · a⁴

Case B:

(4 · a · b⁻²) / (- 3 · a⁻⁴ · c⁻³)

(4 · a / b²) / [- 3 / (a⁴ · c³)]

[4 · a · (a⁴ · c³)] / (- 3 · b²)

(4 · a⁵ · c³) / (- 3 · b²)

Case C:

w · (3 · x · y)⁻² / [4 · y · (2 · x · w)⁻⁴]

[w / (3² · x² · y²)] / [(4 · y) / (2⁴ · x⁴ · w⁴)]

[w · (2⁴ · x⁴ · w⁴)] / [(3² · x² · y²) · (4 · y)]

(16 · x⁴ · w⁵) / (36 · x² · y³)

(4 · x² · w⁵) / (9 · y³)

Case D:

[(5 · x) / (3 · y² · z)]⁻³ × [(x² · y) / (2 · y · z³)]⁴

[(3 · y² · z)³ / (5 · x)³] × [(x² · y)⁴ / (2 · y · z³)⁴]

[(3 · y² · z)³ · (x² · y)⁴] / [(5 · x)³ · (2 · y · z³)⁴]

(27 · x⁸ · y⁶ · z³) / (80 · x³ · y⁴ · z¹²)

(27 · x⁵ · y²) / (80 · z⁹)

Case E:

(5 · x⁷ · y³ · z⁻¹)² × (2 · x · y⁻⁵)³ × (2 · y⁻³ · z²)³

(5² · x¹⁴ · y⁶ · z⁻²) × (2³ · x³ · y⁻¹⁵) × (2³ · y⁻⁹ · z⁶)

(1600 · x¹⁷ · z⁴) / y¹⁸

Case F:

√(2 · 6 · 8 · 3 · 2 · a¹² · b⁶)

24 · a⁶ · b³

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Teen awareness refers to the level of knowledge, understanding, and consciousness that teenagers have about various issues, including but not limited to social, environmental, health-related, and global concerns.

1) In Colorado, teens' awareness of seat belt messages increased by __ percentage points.
The answer choices provided are a.) 6 b.) 14 c.) 17 d.) 23.

2) In Nevada, teens' awareness of seat belt messages increased by __ percentage points.
The answer choices provided are a.) 6 b.) 14 c.) 17 d.) 23.

3) The result of changes in teen seat belt use is unclear as you did not provide any specific information or data to analyze.

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Answer:

Answer = 32

Step-by-step explanation:

p= 8

4p

(4)(8)

=32

Answer:

I got, 8 x 4 = 32

Answer:

\(y = 0.5\)

Step-by-step explanation:

Given

\(4y > 1.2\)

Required

Which value of y from \(\{ -0.5, -0.3, 0.3, 0.5 \}\) makes the inequality true

First, we need to solve the inequality:

\(4y > 1.2\)

Divide through by 4

\(\frac{4y}{4} > \frac{1.2}{4}\)

\(y > \frac{1.2}{4}\)

\(y > 0.3\)

This means that the value of y that makes the inequality true is greater than 0.3.

From the list: \(\{ -0.5, -0.3, 0.3, 0.5 \}\)

Only 0.5 is greater than 0.3.

Hence:

\(y = 0.5\)