The molar absorption coefficient and color intensity are closely related.
The molar absorption coefficient refers to the measure of how much light is absorbed by a solution at a particular wavelength, and it is directly proportional to the concentration of the absorbing species in the solution. On the other hand, the color intensity of a solution is a measure of the strength of the color perceived by the human eye. The more light absorbed by a solution, the stronger the color intensity will be. Therefore, the higher the molar absorption coefficient, the more intense the color of the solution will appear to the human eye.
the relationship between the molar absorption coefficient and color intensity can be explained using the Beer-Lambert law. The Beer-Lambert law states that the absorbance (A) of a solution is directly proportional to its molar concentration (c) and the path length (l) through which light passes. The molar absorption coefficient (ε) is a constant that relates these variables: A = εcl.
In this equation, color intensity is represented by absorbance (A). A higher molar absorption coefficient (ε) means that a substance absorbs more light and appears more intensely colored at a given concentration. Therefore, the molar absorption coefficient and color intensity are directly related.
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Next calculate the mass of H₂O in the oceans. To do this, assume that the density of seawater is 1.025 gm/cm³ and that seawater is 96.5 percent H₂O. Express the answer in grams.
Finally compare
The mass of H₂O in the oceans is only about 0.02% of the mass of the Earth.
Given that seawater has a density of 1.025 gm/cm³ and that seawater is 96.5% H₂O. We want to calculate the mass of H₂O in the oceans. To calculate this, we first need to calculate the mass of seawater present in the oceans.
The mass of seawater present in the oceans is calculated as follows:Mass of seawater = volume of seawater × density of seawater Volume of the ocean is approximately 1.3 billion km³.Therefore, mass of seawater = volume of seawater × density of seawater= 1.3 × 10⁹ km³ × 1 × 10³ m³/km³ × 1.025 × 10³ kg/m³= 1.33 × 10²¹ kgNext, we want to find the mass of H₂O in the oceans.
To calculate this, we need to find 96.5% of the mass of seawater present in the oceans.
Therefore, the mass of H₂O in the oceans is:Mass of H₂O = 96.5% × mass of seawater= 96.5/100 × 1.33 × 10²¹= 1.28 × 10²¹ gTherefore, the mass of H₂O in the oceans is 1.28 × 10²¹ g.Finally, let us compare the mass of H₂O in the oceans to the total mass of the Earth. The mass of the Earth is approximately 5.97 × 10²⁴ kg, which is equal to 5.97 × 10²⁷ g. Therefore, the mass of H₂O in the oceans is only about 0.02% of the mass of the Earth.
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a student mixes 25 cm3 sample of dilute hcl with different volume of sodium hydroxide. i each case the student measure the change of temperature to check if it is exothermic. which apparatus is not needed
The apparatus that is not needed for this experiment is a pH meter. The experiment only requires the measurement of temperature changes, not the pH of the solution.
The necessary apparatus for this experiment includes a graduated cylinder or pipette to measure the volume of the HCl sample, a burette or pipette to add the NaOH solution, a thermometer to measure the temperature change, and a calorimeter or insulated container to hold the reaction mixture and prevent heat loss to the surroundings.
The pH of the reaction mixture may change as the HCl and NaOH react, but the student is only interested in the temperature change, not the pH. Therefore, a pH meter is not needed for this experiment.
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in blood plasma, ph is maintained by the carbonic acid-bicarbonate buffer system. how is ph maintained when acid or base is added to the buffer system?
The blood interacts with the bicarbonate, C03²-, from the acid to balance it when acid is supplied to the blood buffer system.
How does a buffer system operate and what does it mean?A buffer is a substance that can withstand a pH shift when acidic or basic substances are added. Small additions of acid or base can be neutralized by it, keeping the solution's pH level largely constant. For procedures and/or reactions that call for certain and stable pH ranges, this is significant.
Give an example of what a buffer system is.Buffer solutions can resist the pH change when a strong acid or base is added sparingly. A strong acid and also its salt can be used as a buffer. It is a mixture of sodium acetate and acetic acid, CH3COOH + CH3COONa.
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If the specific heat of the solid is 1.56J/gC, the specific heat for the liquid is 3.11 J/gC, the specific heat of the gas is .988 J/gC, the heat of fusion is 107 J/g, and the heat of vaporization is 854 J/g, Calculate all the energy absorbed by the sample as described above.
The total energy absorbed by the sample is 34276m + 30075.2 J.
What is the heat of fusion?The heat of fusion is the amount of heat required to melt one unit of mass of a substance at its melting point without a change in temperature.
What is the heat of vaporization?The heat of vaporization is the amount of heat required to vaporize one unit of mass of a substance at its boiling point without a change in temperature.
To calculate the energy absorbed by the sample, we need to know the mass of the sample and the temperature changes it undergoes. Assuming the sample starts as a solid at a temperature of -20°C, is heated to its melting point, melted, then heated to its boiling point, and finally vaporized, the calculations are as follows:
Energy absorbed to heat the sample from -20°C to 0°C:
Q = m * C * ΔT
Q = m * 1.56 J/g°C * (0°C - (-20°C))
Q = 31.2 * m J
Energy absorbed to melt the sample at 0°C:
Q = m * Hfus
Q = 107 J/g * 31.2 g
Q = 3338.4 J
Energy absorbed to heat the sample from 0°C to 100°C:
Q = m * C * ΔT
Q = m * 3.11 J/g°C * (100°C - 0°C)
Q = 311 * m J
Energy absorbed to vaporize the sample at 100°C:
Q = m * Hvap
Q = 854 J/g * 31.2 g
Q = 26636.8 J
Energy absorbed to heat the sample from 100°C to 200°C:
Q = m * C * ΔT
Q = m * 0.988 J/g°C * (200°C - 100°C)
Q = 98.8 * m J
Total energy absorbed:
Qtotal = 31.2m + 3338.4 + 311m + 26636.8 + 98.8m
Qtotal = 34276m + 30075.2 J
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What device will you use to determine the volume of a liquid?
O Balance
Metric beaker
O Graduated cylinder
O Flask
Answer:
graduated cylinder
calculate the ph of a solution prepared by mixing 40.7 ml of 0.249 m hci with 36.4ml of 0.108m naoh.
The pH of the solution is approximately 1.093.
To solve this problem, we need to use the equation for the neutralization of an acid and a base:
acid + base → salt + water
In this case, the acid is HCl and the base is NaOH, so the balanced equation is:
HCl + NaOH → NaCl + H2O
According to the equation, 1 mole of HCl reacts with 1 mole of NaOH to produce 1 mole of NaCl and 1 mole of water. We can use this fact to determine how much of each reactant is used up in the reaction.
First, we need to calculate the number of moles of HCl and NaOH in the solution:
moles of HCl = concentration × volume = 0.249 M × 0.0407 L = 0.01015 moles
moles of NaOH = concentration × volume = 0.108 M × 0.0364 L = 0.00394 moles
Next, we need to determine which reactant is limiting. The limiting reactant is the one that is completely used up in the reaction, and determines how much product can be formed. To do this, we compare the number of moles of each reactant:
HCl:NaOH = 0.01015:0.00394 = 2.58:1
Since the ratio is greater than 1:1, we can see that HCl is in excess and NaOH is limiting.
Therefore, all the NaOH will react with the HCl to form NaCl and water:
NaOH + HCl → NaCl + H2O
The number of moles of NaOH used up is equal to the number of moles of HCl that reacts:
moles of NaOH used up = 0.00394 moles
The remaining moles of HCl that did not react is:
moles of HCl remaining = 0.01015 - 0.00394 = 0.00621 moles
To calculate the concentration of the NaCl solution formed, we divide the number of moles of NaCl by the total volume of the solution:
total volume = 40.7 mL + 36.4 mL = 77.1 mL = 0.0771 L
moles of NaCl = moles of NaOH used up = 0.00394 moles
concentration of NaCl = moles of NaCl / total volume = 0.00394 moles / 0.0771 L = 0.0511 M
Finally, we can calculate the pH of the solution using the formula:
pH = -log[H+]
Since NaCl is a salt of a strong acid (HCl) and a strong base (NaOH), it will not contribute to the pH of the solution. Therefore, the pH is determined by the excess H+ ions from the HCl. To calculate the concentration of H+ ions in the solution, we can use the following formula:
[H+] = moles of HCl remaining / total volume
[H+] = 0.00621 moles / 0.0771 L = 0.0804 M
pH = -log[H+] = -log(0.0804) = 1.093
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experiment 1: what can be said about the mass of the 1.0 m hcl and 1.0 m naoh solutions after they were combined?
The mass of the 1 M of the HCl and the 1 M NaOH solution after the combination of the both was the sum of their masses.
The hydrochloric acid react with the sodium hydroxide will form the sodium chloride and water. The reaction is given as :
HCl + NaOH ---> NaCl + H₂O
Mass of HCl = 36.4 g/mol
Mass of NaOH = 39.9 g /mol
Mass of NaCl = 58.4 g/mol
Mass of H₂O = 18 g/ mol
The mass of the reactant = The mass of the product
36.4 + 39.9 = 58.4 + 18
76.4 g = 76.4 g
Thus, the mass neither be created nor be destroyed.
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Which of the following could you add to increase the solubility of CaBr2? A. HCl. B. HBr. C. H2SO4 D. NaNO3. E. KOH.
The following could you add to increase the solubility of CaBr2 are NaNO3 and KOH. Option D and Option E are correct.
Solubility refers to the degree to which a substance is dissolved in a solvent to create a homogeneous solution. The solubility of a solute can be influenced by several variables, including temperature, pressure, and the chemical properties of the solute and solvent.
When an ionic compound, such as calcium bromide (CaBr2), is added to water, the solubility of the compound determines the degree to which it will dissolve.The solubility of calcium bromide (CaBr2) in water is determined by the type and amount of other substances that are present in the water. If you want to increase the solubility of calcium bromide, you can add a substance that is soluble in water and that can be ionized.
When the added substance dissolves in water, it ionizes and generates ions that can interact with the calcium and bromide ions in CaBr2 and increase the solubility. Sodium nitrate (NaNO3) and potassium hydroxide (KOH) are two substances that can increase the solubility of calcium bromide.
Therefore, the correct answer is D. NaNO3. and E. KOH.
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According to the graph,
what part(s) of the
reaction are present at
the beginning of the
reaction?
Concentration (M)
Reaction: 2A A₂
A. only the reactant, A
B. only the product, A:
C. Both the reactant (A) and product (A:)
D. You cannot determine from the graph.
Time (sec)
4
According to the graph, only the reactant A was present at the beginning of the reaction.
What does the graph show?The graph shows the concentration for the reactant A and the product that is A2. In this graph, the concentration is displayed on the vertical axis, while the horizontal axis shows the time.
In general terms, it can be observed that at the beginning only the reactant A is present, but as the reaction occurs the concentration of this reactant decreases, while the concentration of the product A2 increases.
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The major chemical structures of hormones include____ l a. polysaccharides, esters, and steroids. b. 2 points only molecules containing amine groups. c. steroids, amino acid derivatives, and esters. d. steroids, polypeptides, and anino acid derivatives. e. only steroids.
The major chemical structures of hormones include c. steroids, amino acid derivatives, and esters.
Steroids are a class of lipids that are characterized by a specific arrangement of four fused carbon rings. They include hormones such as estrogen, testosterone, and progesterone. Amino acid derivatives are hormones that are derived from amino acids, such as thyroxine, which is derived from the amino acid tyrosine.Esters are compounds formed from the reaction between an alcohol and a carboxylic acid, such as adrenaline, which is a catecholamine ester. Polysaccharides, polypeptides, and anino acid derivatives, are not the major chemical structures of hormones, although some hormones may have these as part of their structure.
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What is the pH of a solution formed when 100 ML of an acid with a pH of two is diluted 1 L with pure water
Answer: look down hope I helped
Explanation:
1) First convert to pOH as OH is the dissociating species in a base equilibrium.pH + pOH = 14 (at 25 C)pH=13, hence pOH = 1,Hence [OH] = 10^-1 Mdiluting by factor of 10 with pure water gives [OH] = 10^-2 MThe new pOH = 2, hence the new pH is 12In general, dilution (with pure water) by a factor of 10 moves the pH 1 unit in the direction of the pH of water (pH 7). i.e. it moves up for acids, down for bases.(At infinite dilution of either acids or bases, you’d have pure water - obvious when you think of it like that)
A fish swims 0.8 m/s for 34 m. How much time does it take the fish to swim this distance?
Do not round.
NO UNITS NEEDED.
Answer:
42.4m
Explanation:
Given parameters:
Speed of the fish = 0.8m/s
Distance = 34m
Unknown:
Time taken for the fish to swim = ?
Solution:
Speed is the distance divided by the time taken;
Speed = \(\frac{distance}{time}\)
Time = \(\frac{distance}{speed}\)
Now, insert the parameters and solve;
Time = \(\frac{34}{0.8}\) = 42.4s
What does the salinity of seawater represent?
The concentration of salt dissolve in the ocean
The concentration of all dissolved chemicals in the ocean
The volume of salt in the ocean
the mass of salt in the ocean
Answer:
Salinity is a measure of the 'saltiness' of seawater, or more precisely the amount of dissolved matter within seawater.
Complete the following chart:
The atomic no., mass no., no. of protons, no of neutrons, and no of electrons respectively is as follows:
Uranium-235 = 92, 235, 92, 143, 92Calcium - 20, 48, 20, 28, 18Oxygen - 8, 17, 8, 9, 10What is atomic and mass number?Atomic number is the number of protons in an atom while the mass number is the total number of protons and neutrons in an atomic nucleus.
An atom is made up of three subatomic particles as follows; proton, electron and neutron.
The no of protons and electrons in an atom is usually the same for a neutral atom. However, for an ion, they differ depending on the charge.
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true/false. organocuprates are organometallic reagents with the general formula
Organocuprates are a class of organometallic reagents that have the general formula R-CuLi or R-CuMgX, where R represents an alkyl or aryl group, and X represents a halogen atom is True.
These reagents are widely used in organic synthesis as nucleophiles and can react with a variety of electrophiles such as carbonyl compounds, epoxides, and halides. Organocuprates are particularly useful in the synthesis of complex natural products and pharmaceuticals due to their high reactivity and ability to form carbon-carbon bonds. In addition, organocuprates are air and moisture-sensitive, which means that they must be prepared and handled under strictly controlled conditions. Despite this limitation, the versatility and utility of organocuprates make them a valuable tool for organic chemists. In summary, organocuprates are organometallic reagents with the general formula R-CuLi or R-CuMgX, and are widely used in organic synthesis as nucleophiles due to their ability to form carbon-carbon bonds with electrophiles.For more such question on Organocuprates
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List 2 metals that can be used as fuel
Answer:
Nickel and Copper
Explanation:
Titration for Acetic Acid in Vinegar-Lab Report Exercise 1: Determining the Concentration of Acetic Acid Data Table 1. NaOH Titration Volume Initial NaOH Volume (mL) 8.59 9.20 9.20 Final NaOH Volume Trial 1 Trial 2 Trial 3 (mL) 0.20 1.00 2.01 Total volume of NaOH used (mL) 8.39 8.20 7.19 Average Volume of NaOH Used (mL): 7.93 Data Table 2. Concentration of CH3COOH in Vinegar Average volume of NaOH Concentration CH3COOH % CH3C00H in vinegar used (mL) in vinegar (mol/L) 7.93 0.793 4.76% If the manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid, what would the percent error between your result and the manufacturer's statement be? Show your calculations. . Given Average volume of NaOH7.93mL Volume of acetic acid 5.0mL Conceptual Plan M1V1 M2V2 M1 M2V2/V1 Percent error((accepted value - experimental value)/accepted value) x 100 Solve 0.5M x 7.93mL 5.0mL 0.793M. . CH3COOH 0.793M Moles of acetic acid (1000mLx5 g/100mL) x 1mol /60.05g 0.833mol Molarity 0.833mol1L 0.833M Percent error-(0.833 M-0.793 M ) / 0.833 M) x 100-4.80 % Percent error = 4.80 %
The mass of acetic acid found to be 0.675g and percentage acetic acid in vinegar is 9.64%
Why are titrations performed?Titration is used to determine the equivalence point, or the point at which chemically equivalent amounts of the reactants have been incorporated. The quantity of reactants that have been mixed at the equivalence point will depend on the stoichiometry of the reaction.
In question which percentage of acetic acid in vinegar is asked it should be
M₁V₁ (acetic acid)= M₂ V₂ (NaOH)
M₁ = 1.5M ×7.5 mL = 11.25mmol
Mass of acetic acid = (11.25×60)/1000= 0.675 g
% acetic acid in vinegar = (0.675×100)/7= 9.64
Furthermore, the addition of phenolphthalein to the base will cause the color change at the end point to be undone.
Rest of answers appear to be accurate.
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Does the solubility of a solid increases with increasing temperature?
Yes, More heat speeds up the dissolving reaction by supplying energy to break bonds in the solid. This is the most prevalent case in which an increase in temperature causes an increase in solid solubility.
What happens to the solubility of a solid?As the temperature of the solution rises, so does the average kinetic energy of the solute molecules. As a result, the molecules are less able to stick together and disintegrate more easily. As a result, increasing the temperature increases the solubility of solid states.
Solute and solvent crystal structures must be identical. When the solvent and solute have the same valency, complete solubility occurs. A metal with a higher valency is more likely to dissolve a metal with a lower valency. The electronegativity of the solute and solvent should be comparable.
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What is a maritime air mass?
Answer:
Maritime air mass, vast body of air of oceanic origin; also, an air mass (q.v.) that has had a long trajectory over water and has been so modified that it has the characteristics of an air mass of oceanic origin
Use the drop-down menus to identify the class of compounds to which each structure belongs. A skeletal chain goes up, down, up, down to C double bonded to O, up to O H. A skeletal chain goes up to O, down, up, down, up. A hexagonal ring is single bonded to C l on one corner. N has a pair of electron dots above, and is single bonded to R Superscript 1, wedge bonded to H, and wavy bonded to H.
Functional group can be interconverted into each ther by the means of suitable reagent. Functional group are responsible for the chemical and physical properties of a compound.
What is functional group?A group of atoms forming a component of a molecule that accounts for a particular function or chemical behavior is called a functional group. There are so many functional group in organic chemistry.
a. A skeletal chain goes up, down, up, down to C double bonded to O, up to O H is Carboxylic group COOH.
b. A skeletal chain goes up to O, down, up, down, up. A hexagonal ring is single bonded to C l on one corner. this belongs to cyclic substituted compound.
c. N has a pair of electron dots above, and is single bonded to R Superscript 1, wedge bonded to H, and wavy bonded to H. This belongs to primary amine compound.
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Is iodine solution and vinegar soluble or insoluble?
Answer: lodine solution and vinegar are both soluble
Solution is the mixture of solute and solvent. Iodine solution and vinegar solution both are soluble. Iodine and vinegar are the homogenous mixture.
What is solution ?A solution is a homogeneous mixture of o solutes and solvent. Solvent is the material in which a solute dissolves to produce a homogeneous mixture. Solute is the material that dissolves in a solvent to produce a homogeneous mixture in phase
Common examples of solution are sugar in water and salt in water solutions, soda water etc. In a solution, all the components that are present as a single phase. Iodine and vinegar both molecule shows homogenous mixture.
Hence, the iodine solution and vinegar solutions are soluble, both compounds are homogenous mixture. Both are totally soluble.
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ASAP question also in pic will get Brainiest
What is the force of an egg that is thrown at a brick wall if the egg has a mass of .03 kg and an acceleration of 50 m/s/s
Use the formula F=ma ( dont forget the units )
Answer:
F=ma
=(0.3kg) (50m/s/s)
F =15 kg per m/s/s
s 6 hno3 --> h2so4 6 no2 2 h2o in the above equation how many moles of h2so4 can be made when 12.00 moles of hno3 are consumed?
Moles of H2SO4 that can be made when 12.00 moles of HNO3 are consumed is 72 g of H2O.
What do you understand by term mole?Mole, in chemistry, is a standard scientific unit for measuring large quantities of a very small entities such as atoms, molecules and other specified particles. The mole designates a large number of units, 6.02214076 × 10^23. Mole is widely used in chemistry as a way to express amounts of reactants and products of a chemical reaction.
Given; 12 mol HNO3
Moles of H2SO4 that can be made when 12.00 moles of HNO3 are consumed:
12 mol HNO3 x (2 mol H2O/6 mol HNO3) x (18 g H2O/1 mol H2O)
= 72 g H2O
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A 2.8-kg pile of aluminum (rho = 2.70 g/cm3) cans is melted, then cooled into a solid cube. What is the volume of the cube?
Answer:
Explanation:
mass of aluminum 2.8 kg = 2.8 x 1000 = 2800 g
ρ = density of aluminum given = 2.7 g / cm³
density = mass / volume
volume = mass / density
= 2800 / 2.7
= 1037 cm³
So volume of cube required = 1037 cm³.
Can you please give examples of metallic compounds that are not confused with ionic ones? I’ll give all points for who answers
Answer:
AgNO3 - Silver nitrate
CaCl2 - Calcium chloride
Al2S3, aluminum sulfide
Explanation:
THESE ARE NOT LINKS TO OTHER WEBSITES!!!! THESE ARE METALLIC COMPOUND FORMULAS!!!!
(My other answer was deleted because they thought i was posting websites but i was posting formulas for your question)
13.0 mol 3.0 mol methanegasand oxygengas react to form carbon dioxide gas and watervapor. suppose you have of and of in a reactor. suppose as much as possible of the reacts. how much will be left? round your answer to the nearest
The no. of moles of \(CH_4\) remaining after the reaction is found to be 11.5 moles.
The no. of moles of a material equals the ratio of its given mass to the mass of one mole of that molecule in a chemical reaction.
The coefficients reflect the number of moles, not simply molecules, that react.
Stoichiometric coefficients are the numbers that come before the chemical formula of a molecule participating in a reaction. They assist us in determining the relative amounts or no. of moles of each reactant consumed and product created during a reaction.
\(CH_4 (g) + 2O_2 (g) \rightarrow CO_2 (g) + 2H_2O (g)\)
No. of moles of \(CH_4\) = 13.0 mol
No. of moles of \(O_2\) = 3.0 mol
Here \(O_2\) is limiting reagent because moles of \(O_2\) is less.
Thus, \(CH_4\) is in excess
1 mol \(CH_4\) = 2 mol \(O_2\)
x mol \(CH_4\) = 3 mol \(O_2\)
Moles of \(CH_4\) used = 3 x 1 / 2 = 1.5 mol
Here we have 13 moles of \(CH_4\),
Therefore,
No. of moles of \(CH_4\) left = 13 - 1.5 = 11.5
Result:
11.5 moles of \(CH_4\) will remain after the reaction.
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If the North Pole is tilting away from the sun, what season is it experiencing?
Answer:
Winter
Explanation:
Answer:
winter
Explanation:
because it is away from the sun
PLEASE HELP ME QUICKLY!
Imagine you are at your favorite beach. The sun is shining and you are enjoying the ocean breeze. The temperature is about 89F. You take your shoes off and realize that the sand is almost too hot to walk on. You run to the water's edge to wet your feet after the walk over the sand and realize that the water is almost too cold. Explain the temperature difference between the sand and water using Thermodynamics.
Answer:
The specific heat of water is more specific than the heat of sand, therefore, it will take more energy to raise the same amount of water with the same temperature.
Explanation:
The temp is 89 F so, 31.67° C
The specific heat of the water is 4.184 J/g° C
The specific heat of the sand is 0.290 J/ g° C
The heat is the amount of energy that is needed to raise the temp. of the substance
You will need a lot more energy to raise the temp of the water then of the same amount of sand, therefore, because of the specific lower heat of the sand it will raise it's temperature quicker compared to water.
what step in reviewing a remittance advice comes after comparing the ra to the original insurance claim?
After comparing the RA to the original insurance claim, the next step in reviewing a remittance advice is to identify any discrepancies or variances. The remittance advice should be checked for accuracy in terms of the billed amount, allowed amount, and paid amount.
It is also essential to verify that the payment has been applied correctly to the correct patient account and service date. When reviewing the RA, it is critical to ensure that all charges have been received and accounted for. Any missing charges should be identified and investigated. It is also important to check for denial codes or any other relevant information that could impact the payment. Once all discrepancies have been identified, the next step is to make necessary corrections or adjustments in the patient's account.
It is also crucial to communicate with the insurance company regarding any discrepancies or questions about the payment. Furthermore, reviewing the RA can help identify trends or patterns in the payments, denials, and adjustments, which can help with the practice's overall revenue management.
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If 0.0309 mol CaCl2 is dissolved in water to make a 0.730 M solution, what is the volume of the solution
Answer:
0.0423 L
Explanation:
Molarity can be represented by the following ratio:
Molarity = moles / volume (L)
You can plug the given values into the equation and simplify to find the volume.
Molarity = moles / volume
0.730 M = 0.0309 moles / volume
(0.730 M) x volume = 0.0309 moles
volume = 0.0423 L