Homeboy Joe is riding his skateboard and playing Among Us. Because he's distracted he doesn't notice he's about to skate right off the 69.0 m cliff he's on. If he lands 22.0 m from the cliff, how fast was he skating?

Answers

Answer 1
Answer: He wasn’t skating he was on Ice ;)

Related Questions

A 6 kg blue ball rolls across the ground and collides with a stationary 1 kg red ball.
Before the collision the blue ball moved right with a speed of 4 m/s, and after the
collision it moved left with a speed of 1 m/s. If the red ball was not moving before the
collision, how fast is it moving after the collision?

Answers

The final velocity of the red ball is 18 m/s.

What is momentum?

The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.

Then;

Mass of the blue ball =  6 kg

Mass of the red ball =  1 kg

Initial velocity of the blue ball =  4 m/s

Initial velocity of the red ball = 0 m/s

Final velocity of the red ball = ??

Final velocity of the blue ball =  1 m/s

We now have;

(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)

24 = v + 6

v = 24 - 6

v = 18 m/s

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When scientists look at very distant galaxies through powerful telescopes, they see the galaxies as they were millions or billions of year ago. Why is this?

Answers

Answer:

speed of light

Explanation:

the sun's light is 8 mins behind imaging that a billion fold

What is the magnitude and direction of the net force on a ball that has a force of 27N North and 18N North applied to it?

Answers

Answer:

Magnitude: =  32.45 Direction: =  33.69

Explanation:

The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object, as shown in this formula. We find its magnitude using the Pythagorean Theorem or the distance formula, and we find its direction using the inverse tangent function. Given a position vector →v=⟨a,b⟩, the magnitude is found by |v|=√a2+b2. The direction is equal to the angle formed with the x-axis, or with the y-axis, depending on the application.

which of the following would be most helpful for a baseball pitcher to know the exact speed of their pitch?

Answers

The greatest speed of a given pitch at any point from the moment it is released until it passes home plate is represented by velocity, one of the methods used to assess pitchers most commonly.

What is Velocity (VELO)?Pitching tracking in every MLB stadium was handled by PITCHf/x until Statcast was introduced. This system's reporting of each pitch's velocity at a distance of 50 feet from the rear tip of home plate rather than at the point of release set it apart from Statcast. Some organizations started utilizing 55 feet as the point of reference and extrapolating what the velocity would be at 55 feet based on the PITCHf/x data for the reported velocity at 50 feet in order to obtain velocity readings that were closer to pitchers' actual release positions.In contrast, Statcast can offer the maximum speed of a pitch at any point in its flight, with the highest speed always occurring at the release point due to physics, enabling a more accurate assessment of pitch velocity.

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A modern electric bicycle achieves a 100 mile range per
charge. To improve battery life, an owner decides they only
want to discharge the battery to 25% of the total capacity. If
they have a commute that is 12 miles round trip, how many
round trips can they make before they need to recharge (given
the 25% limit on discharge depth)?

Answers

The remaining battery capacity would be 76%, which is still above the 25% limit on discharge depth.

What is the remaining battery capacity?

If the electric bicycle can go 100 miles on a full charge, and the owner wants to limit the discharge depth to 25%, then they can only use up to 25 miles of the battery's capacity before needing to recharge.

Since the owner's commute is 12 miles round trip, they can make one round trip without depleting the battery more than 25% of its capacity.

Therefore, the owner can make 2 round trips (2 x 12 = 24 miles) before needing to recharge, but they will still have some battery capacity left.

The remaining battery capacity would be (100 - 24)/100 x 100% = 76%, which is still above the 25% limit on discharge depth. So the owner could make a few more round trips before needing to fully recharge the battery.

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Two pieces of clay, one white and one gray, are thrown through the air. The white clay has a momentum 25kg. M/s and the grey clay has a momentum of -30kg. m/s immediately before they collide


What is the magnitude and direction of their final momentum immediately after the collision?

Your answer should have one significant figure.

___ kg. m/s

Two pieces of clay, one white and one gray, are thrown through the air. The white clay has a momentum

Answers

Two clay pieces—one white and the other gray—are hurled through the air. The white clay has a momentum of 25 kg/m/s.

What direction is momentum after a collision?

The momentum will be conserved in each direction separately for a collision if the moving objects are travelling in two dimensions (for example, x and y) (as long as there is no external impulse in that direction). In other words, both before and after the impact, the total momentum will be the same in the x direction.

The momentum of the cue ball is defined as mass times velocity. Because it isn't moving yet, the 8 ball has no momentum. Due to the conservation of momentum, if you strike it straight on and the cue ball stops at the point of collision, all of its momentum must transfer to the 8 ball.

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A uniform solid cylindrical flywheel has a mass of 50 kg and a radius of 40 cm. The flywheel begins to rotate faster with an acceleration of 1.5 rad/s2. The kinetic energy of the flywheel after 1 minute of rotation is:
A. 16.2 KJ
B. 180 KJ
C. 40.5 KJ
D. 32.4 KJ

Answers

The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

How do I determine the kinetic energy?

We'll begin by obtaining the velocity of the flywheel. This is shown below:

Radius (r) = 40 cm = 40 / 100 = 0.4 mAcceleration (a) = 1.5 rad/s² = 1.5 × 0.4 = 0.6 m/s²Time (t) = 1 minute = 1 × 60 = 60 sVelocity (v) = ?

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

Mass (m) = 50 KgVelocity (v) = 36 m/sKinetic energy (KE) =?

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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Lisa made the electromagnet shown. (Image above) What can Lisa do to increase the strength of the electromagnet?
O She can use a nail with weaker magnetic properties.


O She can change the direction of the nail.
O She can increase the number of wire loops.
O She can reduce the current in the wire.

If correct first gets Brainliest​ Please hurry this is a timed test( this is second time just in case I didn't go through)​

Answers

Answer:

I think C

Explanation:

if im wrong then what is it im taking the exam too

Answer: C. She can increase the number of wire loops.

Explanation:

Why do astronomers use spectroscopes to analyze light from distant objects?

Answers

Spectroscopy — the use of light from a distant object to work out the object is made of — could be the single-most powerful tool astronomers use, says Professor Fred Watson from the Australian Astronomical Observatory. ... "It lets you see the chemicals being absorbed or emitted by the light source.

Suppose a car is traveling at 18.6 m/s, and the driver sees a traffic light turn red. After 0.500 s has elapsed (the reaction time), the driver applies the brakes, and the car decelerates at 4.00 m/s2. What is the stopping distance of the car, as measured from the point where the driver first notices the red light

Answers

Answer:

s = 52.545 m

Explanation:

First, we calculate the distance covered during the 0.5 s when the driver notices the light and applies the brake.

\(s_{1} = vt\\\)

where,

s₁ = distance covered between noticing light and applying brake = ?

v = speed = 18.6 m/s

t = time = 0.5 s

Therefore,

\(s_{1} = (18.6\ m/s)(0.5\ s)\\s_{1} = 9.3\ m\\\)

Now, we calculate the distance for the car to stop after the application of brakes. For that we use 3rd equation of motion:

\(2as_{2} = V_{f}^{2} - V_{i}^{2}\\\\\)

where,

s₂ = distance covered after applying brake = ?

a = deceleration = - 4 m/s²

Vf = final speed = 0 m/s

Vi = initial speed = 18.6 m/s

Therefore,

\(2(- 4\ m/s^{2})s_{2} = (0\ m/s)^{2} - (18.6\ m/s)^{2}\\\\s_{2} = \frac{(18.6\ m/s)^{2})}{8\ m/s^{2}}\\\\s_{2} = 43.245\ m\)

So the total distance covered by the car before stopping is:

\(s = s_{1} + s_{2}\\s = 9.3\ m + 43.245\ m\\\)

s = 52.545 m

What does the lines
between atoms represent?and howThe lines between molecules?

Answers

A single line indicates a bond between 2 atoms .

Two blocks, 1 and 2, are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105

. The figure illustrates the configuration.

A system of two blocks connected by a rope passing over a pulley. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle. Box M subscript 1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M sub 1 and the surface is mu subscript 1. Box M subscript 2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle. The coefficient of friction between box M sub 2 and the surface is mu subscript 2.

Answers

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Which of the following is most consistent with the modern theory of evolution?
O Parents pass their physical traits to their offspring; those offspring with traits that help the
O Parents change their physical traits in order to survive in the environment, then those pa
O Life on this planet came from another planet far out in space.
O Living organisms have not changed for hundreds of millions of years.

Answers

Answer:

The theory of evolution by natural selection, first formulated in Darwin's book "On the Origin of Species" in 1859, is the process by which organisms change over time as a result of changes in heritable physical or behavioral traits

How do we turn uranium into electrical energy we can use (describe the power plant)?

Answers

Answer:

Nuclear Power Plant

Explanation:

Heat produced during nuclear fission to heat water. In nuclear fission, atoms are split apart to form smaller atoms, releasing energy. Fission takes place inside the reactor of a nuclear power plant. At the center of the reactor is the core, which contains uranium fuel.

the gravitational force exerted by the planet earth on a unit mass at a distance from the center of the planet is

Answers

The gravitational force put by the planet earth on a unit mass at a distance from the center of the planet is "the strength of the gravitational field at that location".

It is directly proportional to the mass of the planet and inversely proportional to the square of the distance between the unit mass and the center of the planet. The formula for gravitational force is

      F = G * (m1 * m2) / r^2,

where

G is the gravitational constant,m1 and m2 are the masses of the planet and the unit mass, and r is the distance between the two.

The strength of the gravitational field decreases with increasing distance from the planet.

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HELP ME ASAPPPPPPPPPPP
A penny sinks to the bottom of a wishing well
What type of frictional force is that?

Answers

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

prepare a report on why a vehicle needs to be maintained/serviced after a certain period of time. How is servicing different in a petrol/diesel and electric vehicle?​

Answers

Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

Why should cars be maintained and / or serviced ?

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?

Answers

The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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A transformer has 100 turns in its primary coil and 200 turns in its secondary coil. If the primary coil is supplied with 1.20 A and 270 V, what is the power output of the secondary coil?

Answers

The transformer formula may be written as follows:

\(\frac{I_1}{I_2}=\frac{V_2}{V_1}=\frac{N_2}{N_1}\)

where:

\(\begin{gathered} I_1\text{ = current in primary coil} \\ I_2=\text{ current in secondary coil} \\ V_1=\text{ tension in primary coil} \\ V_2=\text{ tension in secondary coil} \\ N_1=\text{ number of turns in primary coil} \\ N_2=\text{ number of turns in secondary coil} \end{gathered}\)

We have to find V2 and I2. So:

\(\begin{gathered} \frac{V_2}{V_1}=\frac{N_2}{N_1} \\ \frac{V_2}{270}=\frac{200}{100} \\ V_2=540V \end{gathered}\)

Also:

\(\begin{gathered} \frac{V_2}{V_1}=\frac{I_1}{I_2} \\ \frac{540}{270}=\frac{1.20}{I_2} \\ I_2=0.60A \end{gathered}\)

Then power output of the secondary coil is:

\(\begin{gathered} P_2=V_2\cdot I_2_{} \\ P_2=540\cdot(0.60) \\ P_2=324W \end{gathered}\)

Power output of the secondary coil equals 324 W.

A quarterback throws a pass at an angle of 35° above the horizontal with an initial speed of 25 m/s. The ball is caught by the receiver 2.55 seconds later. Determine the distance the ball was thrown.

Answers

The distance the ball was thrown is 52.22m by A quarterback throws a pass at an angle of 35° above the horizontal with an initial speed of 25 m/s. The ball is caught by the receiver 2.55 seconds later.

How to calculate distance?

Every motion under constant acceleration is projectile motion

Angle above horizontal Ф = 35°, initial speed v1 = 25m/s , time 2.55s

Substituting value in the below equation

x=x₁ + (v₁*cosθ)(t)+1/2 *a*t²

a= 0 as acceleration in horizontal direction is zero

x= 25*cos(35)*2.55

x=52.22 m

Projectile motion is a form of motion in which object influenced when it is launched into the gravitational force from the surface of Earth along a curved path.

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Which Model represents a lithium isotope? Use your periodic table for this one!
Answer:-D

Which Model represents a lithium isotope? Use your periodic table for this one! Answer:-D

Answers

Answer:

The model D

Explanation:

what is attribute conformity? what is the resulting decision from attribute measurement results?

Answers

Attribute conformity is one that classifies each item in the sample as either having some attribute or not having it.

Variation present in your measurement system will affect the quality of the product and can damage your company's brand.

Purpose of Attribute measurement system analysis:

Accuracy check:

To access the customer standard, need to fulfill the customer's requirement, which means MSA performs to identify how good is our measurement system with our masters.

Precision check:

To determine that, the inspector can measure correctly. Is he checking with the same criteria across all shifts, machines, etc… to measure and evaluate parts and also called Repeatability

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what is the speed of a 1290kg car with a momentum of 38700

Answers

The momentum of the car is the product of its speed and mass. Hence, the speed of the car of 1290 kg with a momentum of 38700 kg m/s is 30 m/s.

What is momentum ?

Momentum of an object is its ability to bring the force applied to make a maximum displacement. In physics momentum is the product of mass and speed of the object. It is a vector quantity and thus characterized by a magnitude and direction.

P be the linear momentum and M and V be the mass and velocity respectively. Then,

P  = M V

given P  = 38700 kg m/s

m = 1290 kg

Then, speed of the car is calculated as follows:

V = P/M

  =  38700 kg m/s / 1290 kg

  = 30 m/s.

Therefore, the speed of the car is 30 m/s.

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the relationship between portable electric tool and portable battery tool​

Answers

Answer:

attractive

Explanation:

a battery is charged with electricity so they share a special bond eg boy and girl

A bar has a 20 N weight at one end, as shown in Figure 7.22. You have a weight of 15 N to hang somewhere on the bar so that the bar is in equilibrium. Where would you hang the 15 N weight on each of these bars? Consider the bar to have no mass.​

Answers

The weight of 15N should be hung at a distance of 4/3 units from the fulcrum, on the opposite side of the bar to a weight of 20N.

The fulcrum is attained equilibrium when the principle of moments is equal to zero. The principle of momentum is defined as the body is said to be balanced when the clockwise movement about the point is equal to the anticlockwise movement about the same point.

When a weight of 15N is hung on the bar, it produces an anticlockwise movement with the same magnitude, opposes the clockwise moment produced by the weight of 20N on the fulcrum.

To find the distance (d) at which the 15N weight should be hung, the distance from the 20N weight to the fulcrum is 1 unit.

20×1 = 15×d

d = 20/15

  =4/3 m

Thus, the weight of 15N should be hung by the distance of 4/3 units from the fulcrum, on the opposite side of the bar having the weight of 20N, to make the fulcrum to be at equilibrium.

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Which is a device that stores electric charge by separating positive and negative charges?

Answers

a camera flash or lighting bolt because stored separated positive and negative charges --> caused them to do work by briefly lighting a bulb as the separated charges moved back together

How do I find the mass in kg

How do I find the mass in kg

Answers

To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.

The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.

When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.

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A tennis player tosses a tennis ball straight up and then catches it after 2.21 s at the same height as the point of release.

(a) What is the acceleration of the ball while it is in flight?
magnitude
_____ m/s2
direction
---Select---

(b) What is the velocity of the ball when it reaches its maximum height?
magnitude
_____ m/s
direction
---Select---

(c) Find the initial velocity of the ball.
____ m/s upward

(d) Find the maximum height it reaches.
____ m

A tennis player tosses a tennis ball straight up and then catches it after 2.21 s at the same height

Answers

(a) To determine the acceleration of the ball while it is in flight, we can use the equation of motion:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

In this case, the ball is thrown straight up, so its final velocity at the highest point is 0 m/s. The initial velocity is unknown, the acceleration is due to gravity and is approximately -9.8 m/s^2 (negative since it acts in the opposite direction of motion), and the time of flight is 2.21 s.

Using the equation, we can solve for the acceleration:

0 = u - 9.8 * 2.21

u = 9.8 * 2.21

u ≈ 21.658 m/s

Therefore, the acceleration of the ball, while it is in flight, is approximately 21.658 m/s^2 in the upward direction.

(b) When the ball reaches its maximum height, its velocity is 0 m/s. This occurs when the ball is momentarily at rest before falling back down. Therefore, the magnitude of the velocity when the ball reaches its maximum height is 0 m/s.

(c) To find the initial velocity of the ball, we can use the equation:

v = u + at

At the highest point, the final velocity is 0 m/s, the acceleration is -9.8 m/s^2 (due to gravity), and the time is 2.21 s.

0 = u - 9.8 * 2.21

u = 9.8 * 2.21

u ≈ 21.658 m/s upward

Therefore, the initial velocity of the ball is approximately 21.658 m/s upward.

(d) The maximum height reached by the ball can be determined using the equation for vertical displacement:

s = ut + (1/2)at^2

At the highest point, the final displacement is 0 m, the initial velocity is 21.658 m/s upward, and the time of flight is 2.21 s.

0 = 21.658 * 2.21 + (1/2) * (-9.8) * (2.21)^2

0 = 47.864 + (-5.5294)

5.5294 = 47.864

Therefore, there seems to be an error in the calculations as the equation does not hold true. Please check the given values and equations to ensure accuracy.

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How do electrons conduct electricity?Please explain in terms of charges

Answers

The electrons are usually at a constant distance from the nucleus of an atom in precious shells. The flow of charges to the per unit of time helps the conductor to conduct electricity. The mathematic representation of the electric current is given in the terms of charges as

\(I=\frac{q}{t}\)

*Here 'q' is the charge

*Here 't' is the time

The movement of electrons

The flow of charges inside the metal (conductor) is known as the electric current.

A car drives horizontally off a 63-m-high cliff at a speed of 29 m/s . Ignore air resistance.

1. How long will it take the car to hit the ground? (in seconds)
a) 2.9
b) 4.0
c) 3.6
d) 1.9
e) 5.2

2. How far from the base of the cliff will the car hit? (in meters)
a) 54
b) 190
c) 100
d) 210
e) 250

I already know the answers to these questions, but if I could have an explanation as to how to solve these problems I would greatly appreciate it!!

Answers

The car's vertical position \(y\) at time \(t\) is

\(y = 63\,\mathrm m - \dfrac12 gt^2\)

since it starts 63 m above the ground, and after leaving the cliff it accelerates downward due to gravity.

Its horizontal position \(x\) is

\(x = \left(29\dfrac{\rm m}{\rm s}\right) t\)

since the car leaves the cliff horizontally at 29 m/s, and is not influenced by any other acceleration in this plane.

1. Solve for \(t\) such that \(y=0\).

\(63\,\mathrm m - \dfrac12 gt^2 = 0 \implies t = \sqrt{\dfrac{126\,\rm m}g} \approx \boxed{3.6}\,\rm s\)

2. Solve for \(x\) at this value of \(t\).

\(x = \left(29\dfrac{\rm m}{\rm s}\right) \sqrt{\dfrac{126\,\rm m}g} \approx 104\,\rm m \approx \boxed{100}\,\rm m\)

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