h(j + i) - k5 + h
when h = 3, i = 4, j = 2, and k = 1
pls put how you did it

Answer:

Use the formula

Step-by-step explanation:

I think you can use the formula y=mx+b, but I'm not fully sure.

The length of the loop for the given curve x=9t-3t³, y=9t² is 36√3

The distance measured from one end to the other of an object's longer or longest side. additionally: any measured distance. the state or trait of being long. the duration of something duration of a visit. The length of something is defined as its measurement or extent from end to end. In other terms, it is the biggest of two or the highest of three geometrical forms or objects' dimensions.

Given,

x=9t-3t³, y=9t²

The loop starts from x=0 and with x=0

Therefore, x=0

9t-3t³=0

3t(3-t²)=0

3-t²=0

t=±√3

dx/dt=9-9t²

dy/dt=18t

Hence length of a loop of a curve,

By using the integration,

=\(\int\limits^a_b\)√(dx/dt)²+(dy/dt)²

Here a=√3, b= -√3

=\(\int\limits^a_b\)√(9-9t²)²+(18t)²dt

=\(\int\limits^a_b\)√(1-t²)²+4t²dt

=\(\int\limits^a_b\)√1-t⁴-2t²+4t²dt

=\(\int\limits^a_b\)√1+t⁴+2t²

=\(\int\limits^a_b\)√(1+t²)dt

=9(t+t²/3)

=36√3

Therefore, the length of the loop is given by 36√3.

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Answer:

C

Step-by-step explanation:

Answer:

Step-by-step explanation:4

\(\large\sf{\sqrt{\frac{1+sin\theta}{1-sin\theta}}+\sqrt{\frac{1-sin\theta}{1+sin\theta}}}\)

\(\\\)

\(\large \sf{=\frac{\left(\sqrt{1+sin\theta}\right)^{2}+\left(\sqrt{1-sin\theta}\right)^{2}}{\sqrt{(1-sin\theta)(1+sin\theta)}}}\)

\(\\\)

\(\large\sf{=\frac{1-sin\theta+1+sin\theta}{\sqrt{1^{2}-sin^{2}\theta}}}\)

\(\\\)

\(\large \sf{=\frac{2}{\sqrt{cos^{2}\theta}}}\)

\(\\\)

\(\large\sf{= \frac{2}{cos\theta}}\)

\(\\\)

\(\large\sf{= 2sec\theta}\)

\(\\\)

\(\large\sf{=RHS}\)

Therefore,

\(\large\sf\red{\sqrt{\frac{1+sin\theta}{1-sin\theta}}+\sqrt{\frac{1-sin\theta}{1+sin\theta}}=2sec\theta}\)

Answer + Step By Step Explanation:

There is no single value for y as the input could differ (x)

y = -3/4x

if x = 0, y = -3/4(0) than y = 0

if x = 1, y = -3/4(1) than y = -3/4

...

if x = 5, y = -3/4(5) than y = -15/4

Step-by-step explanation:

Z=2

3z2-5z+9=322-52+9=170+9=179

Answer:

The probability is 1/41664.

To calculate the probability, write a fraction. The numerator is the number of ways the outcome can occur. The denominator is the number of different outcomes.

Thus, 1 is the number of outcomes we want. 41664 is the total number of different combinations possible.

The given statement exists true. A matrix is broken down into orthogonal (Q) and upper triangular (R) matrices in a process known as QR decomposition (factorization).

A matrix can be expressed as the union of two distinct matrices, Q and R, using the QR matrix decomposition. R is a square upper/right triangular matrix and Q is an orthogonal matrix. R is also invertible because it is square and doesn't have zeros in its diagonal entries.

A matrix is broken down into orthogonal (Q) and upper triangular (R) matrices in a process known as QR decomposition (factorization). Finding eigenvalues and solving linear least squares problems both use QR factorization.

A = QR. Be aware that the QR-factorization of a rectangular matrix A is sometimes understood with Q square and R rectangular rather than Q rectangular and R square, as with the MATLAB command qr.

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Step-by-step explanation:

y=mx+c

2=-5/3(-3)+c

c=-3

y=-5/3x-3

a)There are \(2^m^n\) possible relation

b)Similarly \(n^m\)

c)\(\frac{n^m}{2^m^n}\)

a)Set A has m elements and set B has n elements

Firstly determine the number of elements A*B by using the multiplication rule

Number of elements\(=A*B=m*n=mn\)

For each element, \(A*B\) we have two option

First element 2 ways

Second element 2 ways

mn element 2 ways

By using the multiplication rule

\(2*2*2......=2^m^n }\)

Then there are \(2^m^n\) possible relation

b)Similarly \(n^m\)

c)\(\frac{n^m}{2^m^n}\)

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The probability of on- time arrival in class given that the subject is biology is 82.4%.

Given the following table relating to subject on tie assignment submission and on time arrival in class.

Subject              On time submission                    On time arrival

Physics                    89.7%                                             82.3%

Maths                       88.2%                                            88.7%

Chemistry                89.4%                                             83.1%

Biology                     90.1%                                              82.4%

Total                         88.5%                                             84.7%

We have to find the probability of on time arrival in class given that the subject is biology.

We have been given the corresponding percentages and percentages in itself shows some quantity. Percentage is the ratio of total favourable outcome to total outcome.

From the table the probability of on time arrival in class given that the subject is biology is 82.4%

Hence the probability of on- time arrival in class given that the subject is biology is 82.4%.

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Question is incomplete as it should includes the following table:

Subject              On time submission                    On time arrival

Physics                    89.7%                                             82.3%

Maths                       88.2%                                            88.7%

Chemistry                89.4%                                             83.1%

Biology                     90.1%                                              82.4%

Total                         88.5%                                             84.7%

Answer:

82.4%.

Step-by-step explanation:

Answer:

21. is 18 dollars

22. is 75 dollars

Step-by-step explanation:

Answer:

21. $18.00

22. $75.00

Step-by-step explanation:

21. you can first start by seeing that since two pairs of socks are $6, then one pair must be $3. So, by multiplying 6 by 3, you would get 18 which would show that the socks would cost $18.

22. By dividing 15 by 3, you can deduce that an hour of cleaning would yield $5. So, by multiplying that by 15, she would earn $75.

Hope this helped!

Answer:

15

Step-by-step explanation:

10.5 x (20/14)=14.99999999999...=15

Using proportions, it is found that he would have to ride his bike 3 miles a day to meet his goal.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.

He has already ridden the bike for 6 miles, and needs to run 21 - 6 = 15 miles in 5 days, hence the average is given by:

x = 15/5 = 3 miles a day.

He would have to ride his bike 3 miles a day to meet his goal.

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The required sample size for a population proportion and there is no pilot data available is 0. 50. option D

When performing statistical computations, 0. 50 is frequently utilized as a reliable approximation for the proportion or odds when no preliminary information or experimentation is available.

The reason for this is that a value of 0. 50 denotes the highest level of diversity or ambiguity in the proportion of the population.

By utilizing this worth, a cautious strategy is maintained since it presumes that when no supplementary data is accessible, the accurate ratio is most similar to 0. 50.

This approximation aids in determining an adequate sample size that is more probable to accurately reflect the actual proportion with the desired degree of accuracy and certainty.

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The oil mixture that will have the stronger vanilla smell is Mora oil.

The mixture with the stronger vanilla smell will be the mixture that has a lesser percentage of lavender as a percentage of vanilla in the oil.

Elfa's lavender  percentage :

= 8 / 12 x 100 %

= 67 %

Mora's lavender percentage :

= 6 / 10 x 100 %

= 60 %

This shows that Mora's mixture will have a stronger vanilla smell because the lavender is less.

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Answer:

Hi, there!!!

The solutions in pictures will help you.

Best of luck....

Answer:

27:38 no more simplfying

Step-by-step explanation:

The Blu-ray movie will cost approximately $36.42 in 5 years with an inflation rate of 12% and continuous compounding.

To calculate the future cost of the Blu-ray movie in 5 years with an inflation rate of 12% and continuous compounding, we can use the formula for continuous compound interest:

A = P * e^(rt)

Where:

A = Future value

P = Present value

e = Euler's number (approximately 2.71828)

r = Annual interest rate (in decimal form)

t = Time period in years

In this case, the present value (P) is $19.99, the inflation rate (r) is 12% or 0.12, and the time period (t) is 5 years. Substituting these values into the formula, we get:

A = 19.99 * e^(0.12 * 5)

Calculating the exponent first:

0.12 * 5 = 0.6

Then:

e^0.6 ≈ 1.82212

Finally:

A = 19.99 * 1.82212 ≈ 36.42

Using the formula for continuous compound interest, we calculated that a Blu-ray movie that costs $19.99 today will cost approximately $36.42 in 5 years, assuming an inflation rate of 12% and continuous compounding.

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When the probability is proportional to the length of the interval in which the random variable can assume a value, the random variable is uniformly distributed.

In probability theory and statistics, a uniformly distributed random variable follows a uniform distribution. This distribution occurs when the probability of the random variable assuming a value is equal across a given interval, and the probability is proportional to the length of that interval.
In a uniform distribution, every value within the interval has an equal likelihood of occurring. The probability density function (PDF) of a continuous uniform distribution is a constant within the interval and zero outside of it. The cumulative distribution function (CDF) is a linear function that increases uniformly from 0 to 1 over the interval.
For example, if we have a random variable representing the time it takes for a car to pass through a traffic light, and the probability of the car taking any specific amount of time is proportional to that time interval's length, then the random variable follows a uniform distribution.
Therefore, when the probability is proportional to the length of the interval in which the random variable can assume a value, the random variable is uniformly distributed.

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One example of something that is not expected to be normally distributed is the heights of professional basketball players. The distribution of heights in this population is typically not a normal distribution due to specific factors such as selection bias and physical requirements for the sport.

The heights of professional basketball players are unlikely to follow a normal distribution for several reasons. Firstly, there is a strong selection bias in this population. Professional basketball players are typically chosen based on their exceptional height, which results in a disproportionate number of tall individuals compared to the general population. This selection bias skews the distribution and creates a non-normal pattern.

Secondly, the physical requirements of the sport play a role in the distribution of heights. Due to the nature of basketball, players at the extreme ends of the height spectrum (very tall or very short) are more likely to be successful. This preference for extreme heights leads to a bimodal or skewed distribution rather than a symmetrical normal distribution.

Additionally, factors such as genetics, ethnicity, and individual variation further contribute to the non-normal distribution of heights among professional basketball players. All these factors combined result in a distribution that deviates from the normal distribution pattern.

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Answer:

54000

Step-by-step explanation:

Just do 300 feet multiplied by 180 feet, giving you 54000. Therefore, the area of the field is 54000.

Answer:

Answer: · 1.24 acres or 54,000 feet · by-step explanation: · 1.2396694 · 300*180=54000 · Then round up 1.2396694 and u get 1.24.

2 answers

·

12 votes:

It is 54,000 feet. Area is length times width (300 times 180).

Step-by-step explanation:

Answer: · 1.24 acres or 54,000 feet · by-step explanation: · 1.2396694 · 300*180=54000 · Then round up 1.2396694 and u get 1.24.

2 answers

·

12 votes:

It is 54,000 feet. Area is length times width (300 times 180).

Answer:

B im pretty sure

Step-by-step explanation:

Answer:

its b he right i did work

Step-by-step explanation:

Answer:

hii, the answer would be 320!

Step-by-step explanation:

Just did the test, and i chose 40 turned out wrong, the answer was 320. hope this helped!

To estimate the probability that the frog jumps off the board within 60 seconds, we need to simulate the frog's jumps using the provided random number table.

By tracking the jumps and determining if the frog reaches the edge within the given time frame, we can calculate the estimated probability.

We will simulate the frog's jumps using the random numbers provided in the table. Each random number will represent a jump duration in seconds. If the sum of the jump duration is equal to or exceeds 60 seconds, it means the frog jumps off the board within the time frame. We mark the jumps directly on or above the table to keep track of the simulation.

Repetition 1: Starting from the first random number 126, we mark the first jump. We continue adding the jump durations until the cumulative sum exceeds 60 seconds or we reach the end of the provided numbers. Let's say, after the fourth jump, the cumulative time is 68 seconds, which means the frog jumped off the board within 60 seconds.

Repetition 2: We repeat the process using the second set of random numbers starting from 127. We mark the jumps and calculate the cumulative time. Suppose after the fifth jump, the cumulative time is 56 seconds. In this case, the frog did not jump off the board within 60 seconds.

Repetition 3: We repeat the process using the third set of random numbers starting from 128. We mark the jumps and calculate the cumulative time. Suppose after the third jump, the cumulative time is 42 seconds. Again, the frog did not jump off the board within 60 seconds.

After performing the three repetitions, we count how many times the frog jumps off the board within 60 seconds. If the frog jumped off in one repetition out of three, then the estimated probability is 1/3 or approximately 0.333. This indicates that there is a 33.3% chance that the frog jumps off the board within 60 seconds based on the simulated data.

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