Hiro has 5 kilog of potatos a 2 kg of onions he plans to use 3. 25 kg of potatoes and 550 grams of onions for recipe. How many total kilograms of the produce will not be used?

Answer:

Around 18.18%

Step-by-step explanation:

We can use the percentage increase formula to find the gain here. The formula goes:

\(\frac{new-original}{original}\cdot100\).

We know that the new value is 6500, and the old value is 5500, so we can substitute inside the equation.

\(\frac{6500-5500}{5500}\cdot100\\\\\frac{1000}{5500}\cdot100 \\\\0.\overline{18} \cdot100\\\\18.\overline{18}\)

Which rounds to 18.18%.

Hope this helped!

Answer:

the two variables are meters and seconds,. meters are graphed on the y- axis, seconds is the independent variable....2,4,5

Answer:

right answer lol

Step-by-step explanation:

Answer:

B $240.00

Step-by-step explanation:

thats the correct answer

Answer:

9/10 or 0.9

Step-by-step explanation:

Slope of a line passing through two points (x1, y1) and (x2, y2) is given by
Slope m = rise/run

where
rise = y2 - y1
run = x2 - x1

Given points (- 6, - 5) and (4, 4),

rise = 4 - (-5) = 4 + 5 = 9

run = 4 - ( - 6) = 4 + 6 = 10

Slope = rise/run = 9/10 or 0.9

The equation of parabola will be x^2 = 20y.

The given focus is (0, 5) and the given directrix is y = -5.

Let (x, y) be any point on the parabola.

The distance from (x, y) to the focus (0, 5) is given by:

sqrt((x-0)^2 + (y-5)^2)

The distance from (x, y) to the directrix y = -5 is simply |y - (-5)| = |y + 5|

By definition of a parabola, these distances are equal. Therefore, we have:

sqrt((x-0)^2 + (y-5)^2) = |y + 5|

Squaring both sides, we get:

\((x-0)^{2} + (y-5)^{2} = (y + 5)^{2}\)

Simplifying and rearranging, we get:

\(x^{2}\) = 4(5)y

Therefore, the equation of the parabola with focus (0, 5) and directrix y = -5 is:

\(x^{2}\) = 20y.

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Ainsley's initial investment was approximately $660.184.

Let's denote Ainsley's initial investment as x.

The expression 680(1.031) represents the account balance after one year, given that the initial investment of x earns an interest rate of 3.1% (or 0.031 in decimal form) compounded yearly.

So, we can set up the equation:

x(1.031) = 680

To solve for x, we need to divide both sides of the equation by 1.031:

x = 680 / 1.031

Evaluating the expression:

x ≈ 660.184

Therefore, Ainsley's initial investment was approximately $660.184.

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The complete system of linear inequalities represented by the graph is y ≥ 2x – 2 and x + 4y ≥ -12.

A mathematical phrase in which the sides are not equal is referred to as being unequal. In essence, a comparison of any two values reveals whether one is less than, larger than, or equal to the value on the opposite side of the equation.

As per the given graph.

The inequality y ≥ 2x – 2 is represented by the red line.

The blue line goes from (0,-3) so it must satisfy the inequality.

Thus,  0 + 4(-3) = -12

Thus, x + 4y ≥ -12 will be the inequality.

Hence "The complete system of linear inequalities represented by the graph is y ≥ 2x – 2 and x + 4y ≥ -12".

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The given question is incomplete, the complete question follows,

Which number completes the system of linear inequalities represented by the graph?

y >= 2x – 2 and x + 4y >= ?

Dominic receives 12 pounds on an item whose usual price is 80 pounds

The given parameters are:

Discount =15%

Price = p

Amount of discount = d

The equation that represents the amount of discount offered (d) on an item whose usual price is p is

d = Discount * p

This gives

d = 15% * p

Evaluate

d = 0.15p

In (a), we have

d = 0.15p

Here, p = 80

So, we have

d = 0.15 * 80

Evaluate

d = 12

Hence, Dominic receives 12 pounds on an item whose usual price is 80 pounds

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Answer:

If the store is offering a discount of 15% off the usual price

the equation is \(D=0.15p\)

Dominic gets a £12

discount on an item whose usual price i

Answer:

\(p\leq 56\)

Step-by-step explanation:

Plz mark brainliest!

This can be easily solved, especially with a calculator.
With the calculator, you can find that \(\sqrt{42}\) is about 6.4807.
Multiply that by 2, you get about 13 inches.

If you can't use a calculator, then you can just estimate. Since we know that \(\sqrt{36}\) is 6 and \(\sqrt{49}\) is 7, \(\sqrt{42}\) is in between them, so you can just say somewhere around 6.5.

Multiply 2 * 6.5 and you get 13 inches.

The appropriate inference procedure is a one-sample z-test for p.

A one-sample z-test for the percentage would be the proper inference method in this case.

This is due to the fact that we only have one sample of coin flips and wish to determine whether the population's genuine percentage of heads (p), which represents the proportion of heads in the population, differs substantially from 0.5 (our null hypothesis).

In a one-sample z-test for the percentage, the sample proportion (p-hat) is calculated, and the standard error formula is used to get a z-statistic, which is then compared to a normal distribution to provide a p-value.

If the p-value is less than the significance level, which is typically 0.05, the null hypothesis is rejected.

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The Venn diagram shows the correct relationship among different sets of numbers and the correct placement of -648 is (f) rational number , integer (-648) and whole number

Whole number the numbers without fractions and it is a collection of positive integers and zero.

-648 is not a whole number because it is negative.

Integers is  a whole number that can be positive, negative, or zero

Integers can be negative so -648 is an integer

Rational number any number that can be written as a fraction, where both the numerator (the top number) and the denominator (the bottom number) are integers, and the denominator is not equal to zero.

Rational includes integer and whole number.

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The given question is incomplete the complete question is :

Which Venn diagram shows the correct relationship among different sets of numbers and the correct placement of -648?

Answer:

Step-by-step explanation:

x^2 + 8x +15 is the area

x+5 is the length

x+3 is the width

(x+5)(x+3)=

x^2 + 3x +5x +15

x^2 +8x + 15

The value of the variable h in the given fraction problem (h/6) - 1 = -3 is; h = -12

We are given the fraction problem as (h/6) - 1 = -3

Now, from this given fraction problem, the first step will be to rearrange the equation by adding 1 to both sides to get;

(h/6) - 1 + 1 = -3 + 1

(h/6) = -2

Now, the next step will be to multiply both sides by 6 to get;

(h/6) * 6 = -2 * 6

h = -12

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Complete question is;

Solve for h if (h/6) - 1 = -3

The perimeter of the new scaled copy of the figure is:

40 feet + 20.5 feet = 60.5 feet

Perimeter is the total length of the boundary or the sum of all the sides of a two-dimensional shape, such as a polygon or a circle.

To enlarge the figure given below by a scale factor of 2.5, we need to multiply all the dimensions of the figure by 2.5.

4 feet x 2.5 = 10 feet

Therefore, the new side length of the square base is 10 feet.

The height of the triangle is 3 feet, and the hypotenuse is 5 feet. To find the length of the base, we can use  Pythagorean theorem:

a² + b² = c²

3² + b² = 5²

9 + b² = 25

b² = 16

b = 4

To scale the triangle by a factor of 2.5, we need to multiply both the height and the base by 2.5:

3 feet x 2.5 = 7.5 feet

4 feet x 2.5 = 10 feet

The square base has four sides, each of length 10 feet, so its perimeter is:

4 x 10 feet = 40 feet

We need to add up all three sides to find the perimeter,

10 feet + 7.5 feet + 3 feet = 20.5 feet

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Step-by-step explanation:

novels : cookbooks : reference books

Answer:

6 : 33 : 8

Step-by-step explanation:

cookbook = C

novel = N

reference book = R

C : N = 2 : 11

C : R = 3 : 4

C : N : R = ?

Start with C : N = 2 : 11

2 is not divisible by 2, so multiply this ratio by 3.

C : N = 6 : 33

C : R = 3 : 4 multiply by 2 to get

C : R = 6 : 8

C : N : R = 6 : 33 : 8

Answer:

27000

Step-by-step explanation:

600(45)=27000

Answer:

27000

Step-by-step explanation:

a) the dimension of its column space is also 2. b) the rank of A is 2. c) the nullity of matrix A is 1. d) the dimension of the solution space of the homogeneous system \(A_x = 0\) is also 1.

(a) The dimension of the row space of a matrix is equal to the dimension of its column space. So, if the dimension of the row space of matrix A is 2, then the dimension of its column space is also 2.

(b) The rank of a matrix is defined as the maximum number of linearly independent rows or columns in the matrix. Since the dimension of the row space of matrix A is 2, the rank of A is also 2.

(c) The nullity of a matrix is defined as the dimension of the null space, which is the set of all solutions to the homogeneous equation Ax = 0. In this case, the matrix A is a 3 x 3 matrix, so the nullity can be calculated using the formula:

nullity = number of columns - rank

nullity = 3 - 2 = 1

Therefore, the nullity of matrix A is 1.

(d) The dimension of the solution space of the homogeneous system Ax = 0 is equal to the nullity of the matrix A. In this case, we have already determined that the nullity of matrix A is 1. Therefore, the dimension of the solution space of the homogeneous system \(A_x = 0\) is also 1.

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The square root of the decimal number is √0.0016 = 0.04

Here we can find the square root of the decimal number:

N = 0.0016

Notice that we can write this number as:

0.0016 = 16*10⁻⁴

Now we can take the square root of that, so we will get:

√(16*10⁻⁴)

We can distribute the square root to get:

√16*√10⁻⁴

These two are easy, we will get:

√16*√10⁻⁴ = 4*10⁻² = 0.04

That is the square root.

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Carbon-14 Dating Skeletal remains that had lost 70% of the C-14 they initially contained need to be evaluated for their age.

To approximate the age of the bones, carbon-14 dating method is used.

Carbon-14 dating is a technique used to determine the age of an artifact containing organic material by measuring the amount of carbon-14 remaining in the sample. C-14 is formed in the atmosphere when neutrons from cosmic radiation interact with nitrogen atoms.

When a living organism dies, it stops taking in carbon-14, and the carbon-14 it contains starts to decay into nitrogen-14 at a steady rate. So the remaining amount of C-14 can be used to determine the age of the sample.

Carbon-14 has a half-life of about 5730 years which means that after 5730 years, half of the initial amount of C-14 will remain in the sample. The time elapsed for the decay of a radioactive substance to half of its initial amount is known as its half-life.

Therefore, if an organism had 100 units of C-14 when it died, it would have 50 units of C-14 after 5730 years, 25 units of C-14 after 11,460 years, and so on.

To determine the approximate age of the bones, we use the following formula:

Amount of C-14

Remaining = Initial amount of C-14 x (0.5)^(t/h)where t is the time elapsed and h is the half-life of carbon-14.  

The skeletal remains had lost 70% of the C-14 they only contained.

Therefore, the remaining amount of C-14 is 30% or 0.30 of the initial amount of C-14.

Therefore,

Amount of C-14

Remaining = 0.30 x Initial amount of C-14

Putting this value in the formula we get,0.30 x Initial amount of C-14 = Initial amount of C-14 x (0.5)^(t/h

)Dividing by Initial amount of C-14 on both sides we get,0.30 = 0.5^(t/h)

Taking natural logarithm on both sides we get,

ln 0.30 = (t/h) ln 0.5

Solving for t, we get,

t = (ln 0.30)/(ln 0.5 x h)t = (ln 0.30)/(ln 0.5 x 5730)≈ 11,113

Therefore, the bones are approximately 11,113 years old. Rounding this to the nearest whole number, the approximate age of the bones is 11,113 years.

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Answer:

\(10x^2-x+3\) miles.

Step-by-step explanation:

It is given that,

Total length of park trail = \(10x^2+4x+2\) miles

Total length traveled by hiker = \(5x-1\) miles

We need to find the length of trail hiker need to travel to get to the end of the trail.

Required length \(=10x^2+4x+2-(5x-1)\)

               \(=10x^2+4x+2-5x+1\)

               \(=10x^2+(4x-5x)+(2+1)\)

               \(=10x^2-x+3\)

Therefore, hiker need to travel \(10x^2-x+3\) miles to get to the end of the trail.

Answer:

B. 4:3

Step-by-step explanation:

Divide both by 3:

12/3 = 4

9/3 = 3

4:3

Answer:

Step-by-step explanation:

4 is the answer

Answer:

\(y(t)=c_1e^{-t}+c_2te^{-t}+\frac{1}{2}t^2\ln(t)e^{-t}-\frac{3}{4} t^2e^{-t}\)

Step-by-step explanation:

Given the second-order differential equation. Solve by using variation of parameters.

\(y''+2y'+y=e^{-t}\ln(t)\)

(1) - Solve the DE as if it were homogeneous to find the homogeneous solution

\(y''+2y'+y=e^{-t}\ln(t) \Longrightarrow y''+2y'+y=0\\\\\text{The characteristic equation} \rightarrow m^2+2m+1=0, \ \text{solve for m}\\\\m^2+2m+1=0\\\\\Longrightarrow (m+1)(m+1)=0\\\\\therefore \boxed{m=-1,-1}\)

\(\boxed{\left\begin{array}{ccc}\text{\underline{Solutions to Higher-order DE's:}}\\\\\text{Real,distinct roots} \rightarrow y=c_1e^{m_1t}+c_2e^{m_2t}+...+c_ne^{m_nt}\\\\ \text{Duplicate roots} \rightarrow y=c_1e^{mt}+c_2te^{mt}+...+c_nt^ne^{mt}\\\\ \text{Complex roots} \rightarrow y=c_1e^{\alpha t}\cos(\beta t)+c_2e^{\alpha t}\sin(\beta t)+... \ ;m=\alpha \pm \beta i\end{array}\right}\)

Notice we have repeated/duplicate roots, form the homogeneous solution.

\(\boxed{\boxed{y_h=c_1e^{-t}+c_2te^{-t}}}\)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Now using the method of variation of parameters, please follow along very carefully.

\(\boxed{\left\begin{array}{ccc}\text{\underline{Variation of Parameters Method(1 of 2):}}\\ \text{Given a DE in the form} \rightarrow ay''+by"+cy=g(t) \\ \text{1. Obtain the homogenous solution.} \\ \Rightarrow y_h=c_1y_1+c_2y_2+...+c_ny_n \\ \\ \text{2. Find the Wronskain Determinant.} \\ |W|=$\left|\begin{array}{cccc}y_1 & y_2 & \dots & y_n \\y_1' & y_2' & \dots & y_n' \\\vdots & \vdots & \ddots & \vdots \\ y_1^{(n-1)} & y_2^{(n-1)} & \dots & y_n^{(n-1)}\end{array}\right|$ \\ \\ \end{array}\right}\)

\(\boxed{\left\begin{array}{ccc}\text{\underline{Variation of Parameters Method(2 of 2):}}\\ \text{3. Find} \ W_1, \ W_2, \dots, \ W_n.\\ \\ \text{4. Find} \ u_1, \ u_2, \dots, \ u_n. \\ \Rightarrow u_n= \int\frac{W_n}{|W|} \\ \\ \text{5. Form the particular solution.} \\ \Rightarrow y_p=u_1y_1+u_2y_2+ \dots+ u_ny_n \\ \\ \text{6. Form the general solution.}\\ y_{gen.}=y_h+y_p\end{array}\right}\)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

(2) - Finding the Wronksian determinant

\(|W|= \left|\begin{array}{ccc}e^{-t}&te^{-t}\\-e^{-t}&e^{-t}-te^{-t}\end{array}\right|\\\\\Longrightarrow (e^{-t})(e^{-t}-te^{-t})-(te^{-t})(-e^{-t})\\\\\Longrightarrow (e^{-2t}-te^{-2t})-(-te^{-2t})\\\\\therefore \boxed{|W|=e^{-2t}}\)

(3) - Finding W_1 and W_2

\(W_1=\left|\begin{array}{ccc}0&y_2\\g(t)&y_2'\end{array}\right| \ \text{Recall:} \ g(t)=e^{-t} \ln(t)\\\\\Longrightarrow \left|\begin{array}{ccc}0&te^{-t}\\e^{-t} \ln(t)&e^{-t}-te^{-t}\end{array}\right|\\\\\Longrightarrow 0-(te^{-t})(e^{-t} \ln(t))\\\\\therefore \boxed{W_1=-t\ln(t)e^{-2t}}\)

\(W_2=\left|\begin{array}{ccc}y_1&0\\y_1'&g(t)\end{array}\right| \ \text{Recall:} \ g(t)=e^{-t} \ln(t)\\\\\Longrightarrow \left|\begin{array}{ccc}e^{-t}&0\\-e^(-t)&e^{-t} \ln(t)\end{array}\right|\\\\\Longrightarrow (e^{-t})(e^{-t} \ln(t))-0\\\\\therefore \boxed{W_2=\ln(t)e^{-2t}}\)

(4) - Finding u_1 and u_2

\(u_1=\int \frac{W_1}{|W|}; \text{Recall:} \ W_1=-t\ln(t)e^{-2t} \ \text{and} \ |W|=e^{-2t} \\\\\Longrightarrow \int\frac{-t\ln(t)e^{-2t}}{e^{-2t}} dt\\\\\Longrightarrow -\int t\ln(t)dt \ \text{(Apply integration by parts)}\\\\\\\boxed{\left\begin{array}{ccc}\text{\underline{Integration by Parts:}}\\\\uv-\int vdu\end{array}\right }\\\\\text{Let} \ u=\ln(t) \rightarrow du=\frac{1}{t}dt \\\\\text{an let} \ dv=tdt \rightarrow v=\frac{1}{2}t^2 \\\\\)

\(\Longrightarrow -\Big[(\ln(t))(\frac{1}{2}t^2)-\int [(\frac{1}{2}t^2)(\frac{1}{t}dt)]\Big]\\\\\Longrightarrow -\Big[\frac{1}{2}t^2\ln(t)-\frac{1}{2}\int (t)dt\Big]\\\\\Longrightarrow -\Big[\frac{1}{2}t^2\ln(t)-\frac{1}{2}\cdot\frac{1}{2}t^2 \Big]\\\\\therefore \boxed{u_1=\frac{1}{4}t^2-\frac{1}{2}t^2\ln(t)}\)

\(u_2=\int \frac{W_2}{|W|}; \text{Recall:} \ W_2=\ln(t)e^{-2t} \ \text{and} \ |W|=e^{-2t} \\\\\Longrightarrow \int\frac{\ln(t)e^{-2t}}{e^{-2t}} dt\\\\\Longrightarrow \int \ln(t)dt \ \text{(Once again, apply integration by parts)}\\\\\text{Let} \ u=\ln(t) \rightarrow du=\frac{1}{t}dt \\\\\text{an let} \ dv=1dt \rightarrow v=t \\\\\Longrightarrow (\ln(t))(t)-\int[(t)(\frac{1}{t}dt )] \\\\\Longrightarrow t\ln(t)-\int 1dt\\\\\therefore \boxed{u_2=t \ln(t)-t}\)

(5) - Form the particular solution

\(y_p=u_1y_1+u_2y_2\\\\\Longrightarrow (\frac{1}{4}t^2-\frac{1}{2}t^2\ln(t))(e^{-t})+(t \ln(t)-t)(te^{-t})\\\\\Longrightarrow\frac{1}{4}t^2e^{-t}-\frac{1}{2}t^2\ln(t)e^{-t}+ t^2\ln(t)e^{-t}-t^2e^{-t}\\\\\therefore \boxed{ y_p=\frac{1}{2}t^2\ln(t)e^{-t}-\frac{3}{4} t^2e^{-t}}\)

(6) - Form the solution

\(y_{gen.}=y_h+y_p\\\\\therefore\boxed{\boxed{y(t)=c_1e^{-t}+c_2te^{-t}+\frac{1}{2}t^2\ln(t)e^{-t}-\frac{3}{4} t^2e^{-t}}}\)

Thus, the given DE is solved.

Answer:

8.25 feet

Step-by-step explanation:

3 2/3 times 2 1/4 equals 8.25

Use the formula shown:

6^2 + 2.5^ = c^2

36 + 6.25 = c^2

42.25 = c^2

Take the square root of both sides:

c = 13/2 as a fraction or 2.5495 as a decimal (round off as needed)

The Expected Value of a Discrete Probability Distribution

Given a number of events:

x = {x1, x2, x3,..., xn}

And their respective probabilities:

P = {p1, p2, p3,..., pn}

The expected value is calculated as follows:

We are given:

x = {-1.25, -0.25, 0, 1.25}

P = {0.1, 0.4, 0.2, 0.3}

Substituting:

Calculating:

The expected value is $0.15