hi please help me with this

The least positive integer we can get as the product is 2.

Here we have the following set of numbers:

{-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5}

And we want to take the product between 3 of them and find the least positive integer that we can get as the product.

So it makes sence to choose the smallest absolute value numbers (not zero) such that one is positive and two are negative (we want two negative ones so the signs cancell eachother)

Then we will get:

1*(-1)*(-2) = 2

That is the least positive integer we can get as the product.

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Answer:

P≈14.14

Step-by-step explanation:

Diagonal

5

Using the formulas

P=4a

d=2a

Solving forP

P=22d=2·2·5≈14.14214

Answer:

About 14

Step-by-step explanation:

The diagonal BD is the hypotenuse of the triangol ΔBCD. You can find the lenght of the side BC (BC = BD × cos α = 5 × cos 45° = 3.54) or the lenght of the side CD (CD = BD × sin α = 5 × sin 45° = 3.54). Now you can multiply 3.54 by four to find the perimeter (P = 3.54 × 4 = 14.16).

Answer: 14.16 (I don't know the unit of measurement).

I hope I helped you :D

Harper would have $8,817 in her account.

To find out how much money Harper would have in her account when Alyssa's money has tripled in value.

We need to calculate the future value of Alyssa's investment and then find the corresponding value for Harper's investment.

The formula for calculating the future value with compound interest is:

Future Value = Principal * (1 + \((interest \hspace{1mm} rate / number of \hspace{1mm} compounding \hspace{1mm} periods))^{(number \hspace{1mm} of compounding \hspace{1mm} periods \times time)}\)

In this case, Alyssa's principal is $5,700, the interest rate is 5 1/4% (or 5.25% as a decimal), and the compounding is daily.

The time it takes for Alyssa's investment to triple in value is not given, so we'll need to determine it.

Let's assume it takes t years for Alyssa's investment to triple. We can use the formula for compound interest to find the value of t:

$\(5,700 * (1 + 0.0525/365)^{(365t)}\) = $5,700 * 3

Simplifying the equation, we have:

\((1 + 0.0525/365)^{(365t)} = 3\)

Take the natural logarithm of both sides:

\(ln[(1 + 0.0525/365)^{(365t)}] = ln(3)\)

365t * ln(1 + 0.0525/365) = ln(3)

Solve for t:

t = ln(3) / (365 * ln(1 + 0.0525/365))

Using a calculator, we find that t is approximately 7.587 years.

Now we can calculate the future value of Alyssa's investment:

Future Value of Alyssa's Investment = $\(5,700 * (1 + 0.0525/365)^{(365 * 7.587)}\)

To find out how much money Harper would have in her account when Alyssa's money has tripled, we need to calculate the future value of Harper's investment with continuous compounding.

The formula for continuous compound interest is:

Future Value = \(Principal * e^{(interest rate\hspace {1mm} \times time)}\)

In this case, Harper's principal is also $5,700, and the interest rate is 5 3/4% (or 5.75% as a decimal). The time will be the same as it took for Alyssa's investment to triple, which is approximately 7.587 years.

Future Value of Harper's Investment =\($5,700 * e^(0.0575 * 7.587)\)

Using a calculator, we can calculate the approximate future value of Harper's investment.

Calculating the expression $\(5,700 * e^{(0.0575 * 7.587)},\) we get:

$\(5,700 * e^{(0.4372375)}\) ≈ $5,700 * 1.548366 ≈ $8,817

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Answer:

6,881.9755

Step-by-step explanation:

A = P(1 + r/n)^nt

   = 5000(1 + \(\frac{.04}{12}\))^12(8)

   = 5000(1.00333)⁹⁶

   = 5000(1.37639)

    = 6,881.9755

Answer:

i got the same qeuston pls help

Step-by-step explanation:

The defect rate for your product has historically been about 1.50% For a sample size of 200, the upper and lower 3​-sigma  The upper control limit (UCL) is approximately 0.0450.

The upper control limit (UCL) for a 3-sigma control chart is given by:

\(\[UCL\) = defect rate + 3 * sqrt((defect rate * (1 - defect rate)) / sample size)

Substituting the values, where the defect rate is 1.50% (0.015) and the sample size is 200, we get:

\(\[UCL = 0.015 + 3 \times \sqrt{\frac{0.015 \times (1 - 0.015)}{200}}\]\)

Calculating this expression, we find:

\(\[UCL \approx 0.0450\]\)

Therefore, the upper control limit (UCL) is approximately 0.0450.

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Answer:

The equation of a line passing through the points (2, 3) and (4, 6) is 3x - 2y = 0.

Step-by-step explanation:

Answer:

d 812 821 here is the answer

Answer:

\( f(x) = \frac{20}{3} x\)

Step-by-step explanation:

\(f(x) = \frac{20}{3} x \: ... (required function) \\

Plug \: x = 3 \\ f(3) = \frac{20}{3} \times 3 \\ f(3) = 20\)

Answer:

it SHOULD be (3, 11/2)

Step-by-step explanation:

When we subtract 3 from 22, the simplified answer is 19. The subtraction operation involves removing or deducting one value from another, resulting in the difference between the two quantities.

To subtract 3 from 22, we can perform the subtraction operation as follows:

22

3

19

We align the numbers vertically and subtract each corresponding place value from right to left. In this case, subtracting 3 from 2 requires borrowing or regrouping. However, since 2 is greater than 3, we can directly subtract 3 from 2 and write the difference, which is 1, in the one's place.

Therefore, the simplified answer is 19.

The subtraction process involves taking away or removing a certain quantity from another. In this case, we subtracted 3 from 22, resulting in a difference of 19. The process of simplifying the answer is simply expressing the result in its most concise and reduced form.

By subtracting 3 from 22, we removed 3 units from the original value of 22, leaving us with 19. This can be visualized as taking away three objects from a group of 22 objects, resulting in a remaining count of 19.

In summary, when we subtract 3 from 22, the simplified answer is 19. The subtraction operation involves removing or deducting one value from another, resulting in the difference between the two quantities.

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Answer:

3/40

Step-by-step explanation:

Therefore, the answer is 3/40!

The solution to the equation x - 5y = -31 is (-1,6)

From the question, we have the following equation that can be used in our computation:

x - 5y = -31

Also, we have the ordered pairs

Next, we test each of the ordered pairs

(6,-2)

6 - 5 * -2 = -31

16 = -31 ---- false

(6,-1)

6 - 5 * -1 = -31

11 = 31 --- false

(-1,6)

-1 - 5 * 6 = -31

-31 = -31 --- true

Hence, the solution to the equation is (-1,6)

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Answer:

(n+3)(n+5)

Step-by-step explanation:

the common factor between 8 and 15 is 3 and 5. If you add 3 and 5 together, you get 8. If you multiply 3 and 5, you get 15. So using the FOIL method, it should go back to n^2+8n+15

Answer:

Slope: 1/4

Y intercept: (0,-3)

Slope intercept equation: y= 1/4x - 3

Step-by-step explanation:

The system will be consistent and will have unique solution.

Given,

Coefficient matrix of 5 equation in 5 variables.

Here,

Let A be a 5x5 coefficient matrix such that its each column has a pivot element, then

Rank A = 5, rank of augmented matrix [A|b] = 5 and number of unknowns = 5

Rank A = rank of augmented matrix [A|b] = number of unknowns = 5

Hence , System is consistent

There is a unique intersection point of all three lines, so values of variables is unique.

Hence, solution of system if unique.

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An example of a rational expression is 2x+3/x-2.

The complete question wasn't found. Therefore, a overview will be given. It should be noted that a rational expression simply means quotient of two polynomials.

A rational expression is a fraction whose numerator and denominator are polynomials.

In this case, an example of a rational expression is 2x+3/x-2

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Answer: 3x+2 and  3x-4 when graphed will be parallel

Step-by-step explanation:

The Nash equilibrium (P1 = 0, P2 = 0) would be the intersection of the respective strategies for both players, resulting in a single point on the graph.

To determine the Nash equilibrium in the "guess the number" game, we need to analyze the payoffs of each player and identify the strategies that are best responses to each other.

Let's denote P1 as Player 1's probability of guessing 1 and P2 as Player 2's probability of guessing 2. The payoffs for Player 1 and Player 2 are as follows:

Player 1's Payoff:

- If Player 1 guesses 1 and Player 2 guesses 1, Player 1's payoff is 0.

- If Player 1 guesses 1 and Player 2 guesses 2, Player 1's payoff is -1.

- If Player 1 guesses 2 and Player 2 guesses 1, Player 1's payoff is 1.

- If Player 1 guesses 2 and Player 2 guesses 2, Player 1's payoff is 0.

Player 2's Payoff:

- If Player 1 guesses 1 and Player 2 guesses 1, Player 2's payoff is 0.

- If Player 1 guesses 1 and Player 2 guesses 2, Player 2's payoff is 1.

- If Player 1 guesses 2 and Player 2 guesses 1, Player 2's payoff is -1.

- If Player 1 guesses 2 and Player 2 guesses 2, Player 2's payoff is 0.

Now, let's analyze the strategies and payoffs to identify the Nash equilibrium:

If Player 1 chooses P1 = 0:

- Player 2's best response is to choose P2 = 0, as Player 2's payoff is 0 regardless of their choice.

- This results in Player 1's payoff of 0.

If Player 1 chooses P1 = 1/3:

- Player 2's best response is to choose P2 = 0, as Player 2's payoff is -1 regardless of their choice.

- This results in Player 1's payoff of -1.

If Player 1 chooses P1 = 0 and Player 2 chooses P2 = 1/3:

- Player 1's best response is to choose P1 = 0, as Player 1's payoff is 0 regardless of their choice.

- This results in Player 2's payoff of 1.

If Player 1 chooses P1 = 1/3 and Player 2 chooses P2 = 1/3:

- There is no best response for either player in this case, as their payoffs are the same regardless of their choice.

- This results in Player 1's payoff of 0 and Player 2's payoff of 0.

Based on the analysis, we can see that the Nash equilibrium in this game is (P1 = 0, P2 = 0), where both players choose not to guess. In this scenario, both players receive a payoff of 0, and no player can improve their payoff by unilaterally deviating from this strategy combination.

Graphically, the Nash equilibrium can be represented as a point on a 2x2 payoff matrix with P1 on the x-axis and P2 on the y-axis. The Nash equilibrium (P1 = 0, P2 = 0) would be the intersection of the respective strategies for both players, resulting in a single point on the graph.

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▪︎Side 15 cm, 18 cm and x cm form a right angle triangle.

We know that :

\( =\tt {hypotenuse}^{2} = {leg}^{2} + {leg}^{2} \)

Which means :

\( =\tt {15}^{2} + {x}^{2} = {18}^{2} \)

\( =\tt 225 + {x}^{2} = 324\)

\( =\tt {x}^{2} = 324 - 225\)

\( = \tt {x}^{2} = 99\)

\(\color{plum} =\tt x = 9.9 \: cm\)

Thus, x (radius) = 9.9 cm

We know that :

\(\color{hotpink}\tt \: Surface \: area \: of \: cone \color{plum}=\pi r(r + \sqrt{ {h}^{2} + {r}^{2} } \)

Then, the surface area of this cone :

\( = \tt3.14 \times 9.9 \times( 9.9 + \sqrt{ {15}^{2} + {9.9}^{2} } )\)

\( =\tt 3.14 \times 9.9 \times( 9.9 + \sqrt{323.01} )\)

\( =\tt 3.14 \times 9.9 \times (9.9 + 18)\)

\( =\tt 3.14 \times 9.9 \times 27.9\)

\( = \tt31.09 \times 27.9\)

\(\color{plum} =\tt\bold{ 867.4 \: cm}\)

Therefore, the surface area of this cone = 867.4 cm

The regression estimate for how much he parties is 6.4.

Using the data, the regression line can be computed using any spreadsheet program. The regression line for this data will be in the format of y = ax + b where y is the dependent variable (drinking), x is the independent variable (partying hours), a is the slope, and b is the y-intercept.

To fill in the blanks, calculate the slope and intercept of the regression line. The formula for the slope of the regression line is given by:

Slope (a) = [(nΣxy) - (ΣxΣy)] / [(nΣx²) - (Σx)²]
where n is the number of data points, Σx and Σy are the sums of the x and y values, respectively, and Σxy is the sum of the product of x and y for each data point.

Similarly, the formula for the y-intercept is given by:
b = (Σy - aΣx) / n
Substituting the given data into the formulas, we get:
Slope (a) = [(6 × 638) - (21 × 6)] / [(6 × 91) - 6²] = 0.89
Intercept (b) = (21 - (0.89 × 91)) / 6 = 2.54

Therefore, the regression line is given by:
y = 0.89x + 2.54.

The regression estimate for how much the students reported drinking is given by the y value, while the regression estimate for how much they reported partying is given by the x value.

Using the last line of the table, where the number of drinks one student reported having per week is 8, the regression estimate for how much he parties is calculated by:
x = (8 - 2.54) / 0.89 = 6.4 (approx)

Therefore, the regression estimate is 6.4.

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Answer:

n = m-a

Step-by-step explanation:

a = m-n

a+n =m

n = m-a

Answer:

the difference of 12 and 5 is 7 so it would be 0

Answer:

Step-by-step explanation:

x    - an integer  then  2x + 1 is an odd number  (the smallest one)

consecutive odd numbers increase by 2

so the next odd number (the middle number) is:

2x + 1 + 2 = 2x + 3

and the third (the largest) consecutive is:

2x + 3 + 2 = 2x + 5

the sum of the the two largest numbers is:

2x + 3 + 2x + 5

3 times the smallest number is:  

3(2x + 1)  

the sum of the two largest is seven less than three times the smallest, so:

2x + 3 + 2x + 5 = 3(2x + 1) - 7

4x + 8 = 6x + 3 - 7

   -6x       -6x

-2x + 8 = -4

   -8       -8

-2x  = -12

÷(-2)    ÷(-2)

  x = 6

2x+1 = 2•6+1 = 13

2x+3 = 2•6+3 = 15

2x+5 = 2•6+5 = 17

Check:

2x+3+2x+5 = 15+3+15+5 = 38

38+7 = 45

45÷3 = 15

The equation that reflects the graph of f(x) = x^2 - 4x across the y-axis is y = -(x^2 - 4x).

To graph both equations, we can start by plotting the original equation f(x) = x^2 - 4x. This is a quadratic function with a downward-opening parabola.

To reflect the graph across the y-axis, we change the sign of the x terms in the equation. So, the reflected equation becomes y = -(x^2 + 4x).

Now, let's plot the reflected equation on the same coordinate system. The reflected graph will be symmetric to the original graph with respect to the y-axis.

Here is a visual representation of both equations on a graph:

Original equation: f(x) = x^2 - 4x

Reflected equation: y = -(x^2 + 4x)

(Insert graph of f(x) = x^2 - 4x and y = -(x^2 + 4x) on the same coordinate system)

By comparing the graphs, you can observe that the reflected equation is a mirror image of the original equation across the y-axis.

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Answer:

x = 6, y = 45

Step-by-step explanation:

\(scale \: factor = \frac{13}{32.5} \\ = \frac{2}{5} \\ \\ \frac{x}{15} = \frac{18}{y} = \frac{2}{5} \\ \\ \implies \frac{x}{15} = \frac{2}{5} \\ \\ x = \frac{2 \times 15}{5} \\ \\ x = 6 \\ \\ \frac{18}{y} = \frac{2}{5} \\ \\ y = \frac{5 \times 18}{2} \\ \\ y = 45\)

Answer:

2

1

0

1

2

Step-by-step explanation:

Answer:

B. 40

Step-by-step explanation:

She starts with 46 and sells half of them

That leaves her with 23 stamps left.

She then buys 17 more, 23 + 17 is 40

Answer is B

Answer:

B. 40 stamps

Step-by-step explanation:

We know that she sold half of her stamps. She started with 46 stamps.

First, find 1/2 of 46.

Multiply 1/2 and 46, or divide 46 by 2.

1/2 *46= 23

46/2=23

She sold 23 stamps, and was left with 23 stamps.

Then, she bought 17 more. If she bought more, she added to the amount she already had.

Therefore, we can add 23 and 17.

23+17=40

She has 40 stamps now.

Volume = 40.03 cm^3

The given expression for the volume is 2V34 cm x 6 cm. To solve for the volume, we first need to evaluate the value of V34. To do so, we use the formula for the volume of a sphere, which is V = (4/3)πr^3, where r is the radius.

In this case, the radius is 3 cm, since V34 refers to a sphere with a diameter of 6 cm. Plugging the value of r into the formula gives us:

V34 = (4/3)π(3 cm)^3 = 113.1 cm^3

Now, we can substitute this value into the given expression for the volume:

Volume = 2(113.1 cm^3) x 6 cm = 678.6 cm^3

Finally, we simplify the expression by multiplying and dividing by 2π:

Volume = 678.6 cm^3 / (2π) x (2π) = 40.03 cm^3

Therefore, the volume of the given expression is 40.03 cm^3.

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Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

In the question some iformation is missing, which can be defined as follows:

Given:

The value of males:

\(n_1= 59\\s_1= 1.46\\\bar y_1=2.91\\\)

The value of Females:

\(n_2=60\\s_2= 2.48\\\bar y_2=7.42\\\)

Calculating Degrees of Freedom:

\(\bold{ df=\frac{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}{ \frac{1}{n_1-1} (\frac{s_1^2}{n_1})^2+\frac{1}{n_2-1} (\frac{s_2^2}{n_2})^2}}\\\\\\\)

    \(=\frac{(\frac{1.46^2}{59}+\frac{2,48^2}{60})^2}{ \frac{1}{59-1} (\frac{1.46^2}{59})^2+\frac{1}{60-1} (\frac{2.48^2}{60})^2}\\\)

    \(=9.58 or 95\)

\(\alpha= 1-0.95\\\\\)

   \(= 0.05\)

for 95% confidence interval are:

\(\frac{\alpha}{2} = \frac{0.05}{2} = 0.025\)  

From its t-distribution table , the value of t has an region of (\(\frac{\alpha}{2} \ \ 0.025\)) for (df=95) in its upper tail.

shall be given by = t {0.025}=1.985

Calculating the margin of Error:

\(M_OE =t_{0.025} \times \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}\)

         \(=1.985\times \sqrt{\frac{1.46^2}{59}+\frac{2.48^2}{60}}\\\\=0.739\)

The difference in mean bill color "\(\mu_2 -\mu_1\)" with 95% confidence intervals:

\(\to (7.42 - 2.91) \pm 0.739\\\\\to 4.51 \pm 0.739\)

Lower limit=3.771

Upper limit = 5.249