We live in universe driven by dark energy consists stars and planets where every object have some mass and contains other properties too.
Dark energy has the cosmoslogists scratching their heads. Perceptions taken by NASA's Hubble Space Telescope and future space telescopes will be required to decide the properties of dull energy, which makes up around 70% of the universe.
Testing dark energy, the energy in void space making the growing universe speed up, calls for precisely estimating how that development rate is expanding with time. Dark energy is remembered to divide space.
Cosmologists accept around 70% of the universe comprises of dull energy, 25% is dim matter, and just four percent typical matter (the stuff that stars, planets and individuals are made of). Hubble perceptions recommend the dim energy might be Einstein's cosmological consistent, an energy permeating out of the vacuum of the space between universes.
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The speed of apendulum bob is largest when it isdirectly below the support. Give twoways you could increase this speed.
The speed of the pendulum is dependent on the length of the pendulum and the angle of displacement.
On increasing the length of the pendulum and the angle of displacement, the extreme position of the pendulum increases, or displacement from its mean position increases.
This results in an increase of potential energy at the extreme points.
When the pendulum bob reaches the mean position, all the potential energy gets converted to kinetic energy.
This increase in kinetic energy results in increased speed.
Thus, the speed of the pendulum can be increased by increasing the length and the angle of displacement from the mean position.
the range of possible frequencies of radiation is called the ______ spectrum.
The range of possible frequencies of radiation is called the electromagnetic spectrum.
What is the electromagnetic spectrum and how is it classified?The electromagnetic spectrum is the variety of all possible frequencies of electromagnetic radiation. This consists of radio waves, microwaves, infrared radiation, seen mild, ultraviolet radiation, X-rays, and gamma rays. The spectrum is classed based totally at the frequency and wavelength of the radiation, with each sort of radiation occupying a specific area of the spectrum. The class is primarily based on their capability to tour thru one of a kind substances and their interactions with matter. The distinct areas of the spectrum have an expansion of realistic applications, from conversation technology to medical imaging.
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compute the density for nickel at 500°c, given that its room-temperature density is 8.902 g/cm3 . assume that the volume coefficient of thermal expansion, αv, is equal to 3αl.
The density for a nickel at 500° C, given that its room-temperature density is 8.902 g/cm³, is 8.9 g/cm³.
To compute the density of nickel at 500°C, we need to use the formula:
\(\rho = \rho_0 / (1 + \alpha_v (T - T_0))\)
where ρ₀ is the room-temperature density of nickel (8.902 g/cm³), \(\alpha_v\) is the volume coefficient of thermal expansion (assumed to be \(3\alpha_l\)), T is the temperature in Kelvin (773.15 K), and T₀ is the room-temperature in Kelvin (293.15 K).
Substituting these values into the formula, we get:
ρ = 8.902 g/cm³ / (1 + \(3\alpha_l\) (773.15 K - 293.15 K))
Since we don't know the linear coefficient of thermal expansion, \(\alpha_l\), we can't compute the density of nickel at 500°C exactly.
However, we can estimate it using the fact that for most materials, the volume coefficient of thermal expansion is roughly three times the linear coefficient of thermal expansion.
Therefore, we can assume that \(\alpha_v = 3\alpha_l\), and substitute this into the formula:
ρ = 8.902 g/cm³ / (1 + \(3\alpha_l\) (773.15 K - 293.15 K))
ρ ≈ 8.902 g/cm³ / (1 + \(9\alpha_l\) (°C))
Assuming that \(\alpha_l\) is roughly constant over this temperature range, we can use the value for \(\alpha_l\) at room temperature (which is readily available) to estimate its value at 500°C.
For nickel, \(\alpha_l\) at room temperature is about 13.4 × 10⁻⁶ °C.
Substituting this value into the formula, we get:
ρ ≈ 8.902 g/cm³ / (1 + 9 × 13.4 × 10⁻⁶ (°C))
ρ ≈ 8.9 g/cm³
Therefore, the estimated density of nickel at 500°C is approximately 8.9 g/cm³.
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compare and contrast the theories about the origin of the universe
Answer:
The best-supported theory of our universe's origin centers on an event known as the big bang. This theory was born of the observation that other galaxies are moving away from our own at great speed in all directions, as if they had all been propelled by an ancient explosive force.
Explanation:
hope this helps tho i don't quite know what you mean
2- How many layers slab waveguide consists of? 02 3 O 4 05
The correct answer is (b). A slab waveguide consists of three layers.
A slab waveguide is a type of optical waveguide that consists of three layers. These layers are typically referred to as the core, cladding, and substrate. The core layer is the central region where light propagates, and it has a higher refractive index compared to the cladding layer. The cladding layer surrounds the core and has a lower refractive index, helping to confine the light within the core. The substrate layer provides structural support for the waveguide.
The three-layer configuration of a slab waveguide allows for the guiding of light along a specific path within the core, preventing excessive light loss by total internal reflection at the core-cladding interface. The refractive index contrast between the core and cladding layers determines the guiding properties of the waveguide, such as the effective refractive index and the mode confinement.
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1. Define and compare the process of external and internal respiration
2. Summarise the physical principles controlling air movement in and out of the lungs and muscles responsible
3. Summarise the physical principles of gas diffusion in and out of blood and body tissues
4. Summarise the function of haemoglobin and transport of oxygen and carbon dioxide in the blood
5. Describe age-related changes in the respiratory system
1. External respiration refers to the exchange of gases (oxygen and carbon dioxide) between the lungs and the external environment. It involves inhalation of oxygen-rich air into the lungs and the diffusion of oxygen into the bloodstream, while carbon dioxide diffuses out of the bloodstream into the lungs to be exhaled.
Internal respiration, on the other hand, is the exchange of gases between the blood and the body tissues. It occurs at the cellular level, where oxygen diffuses from the blood into the tissues, and carbon dioxide diffuses from the tissues into the blood.
2. Air movement in and out of the lungs is governed by the principles of pressure gradients and Boyle's law. During inhalation, the diaphragm and intercostal muscles contract, expanding the thoracic cavity and decreasing the pressure inside the lungs, causing air to rush in. During exhalation, the muscles relax, the thoracic cavity decreases in volume, and the pressure inside the lungs increases, causing air to be expelled.
3. Gas diffusion in and out of blood and body tissues is facilitated by the principle of concentration gradients. Oxygen moves from areas of higher partial pressure (in the lungs or blood) to areas of lower partial pressure (in the tissues), while carbon dioxide moves in the opposite direction. The exchange occurs across the thin walls of capillaries, where oxygen and carbon dioxide molecules passively diffuse based on their concentration gradients.
4. Hemoglobin is a protein in red blood cells that binds with oxygen in the lungs to form oxyhemoglobin. It serves as a carrier molecule, transporting oxygen from the lungs to the body tissues. Additionally, hemoglobin also aids in the transport of carbon dioxide, binding with it to form carbaminohemoglobin, which is then carried back to the lungs to be exhaled.
5. Age-related changes in the respiratory system include a decrease in lung elasticity, reduced muscle strength, and decreased lung capacity. The lungs become less efficient in gas exchange, leading to reduced oxygen uptake and impaired carbon dioxide removal. The respiratory muscles may weaken, affecting the ability to generate sufficient airflow. These changes can result in decreased respiratory function and increased susceptibility to respiratory diseases in older individuals.
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When a 4-kg ball is thrown upwards at 40 m/s, at what
height is the potential energy equal to the kinetic
energy
Answer:
the height of the potential energy is 3,200 J
Explanation:
The computation of the kinetic energy is shown below:
Kinetic energy = 1 ÷ 2 × mass × velocity^2
= 1 ÷ 2 × 4 kg × 40 m/s^2
= 3,200 J
Hence the height of the potential energy is 3,200 J
Describe two different ways that crumple zones lessen the force felt by the passenger during a crash?
Which image shows the correct way of lining up vectors to add them together? A. two arrows lined up facing away from each another B. two arrows lined up one after the another C. two arrows lined up facing each another D. two arrows facing opposite to each other
The image shows the correct way of lining up vectors to add them together, that the two arrows lined up one after the other, therefore the correct answer is option B.
What is a vector quantity?The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.
Examples of vector quantities are displacement, velocity acceleration, force, etc.
Thus, the image shows the correct way of lining up vectors to add them together, that the two arrows lined up one after the other, therefore the correct answer is option B.
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a pole vaulter clears 6.00 m. with what speed does he strike the mat in the landing area?
To determine the speed with which the pole vaulter strikes the mat in the landing area, more information is needed, such as the vaulter's body position and the efficiency of the energy transfer during the landing.
To calculate the speed at which the pole vaulter strikes the mat in the landing area, additional information is required. The height cleared by the pole vaulter (6.00 m) alone is not sufficient to determine their landing speed.
Factors that would affect the landing speed include the vaulter's body position during descent, their technique in releasing the pole, and the efficiency of the energy transfer during the landing phase.
Additionally, factors like air resistance and the stiffness of the landing mat could also impact the final speed.
To accurately determine the landing speed, more detailed information about the specific pole vaulter's technique, body position, and other relevant factors would be necessary. Without this information, it is not possible to provide a precise numerical answer.
Pole vaulting is a complex athletic event that involves a combination of skills, technique, and physical abilities.
The landing speed can vary based on multiple factors, and a thorough analysis of the vaulter's performance would be required to determine their actual speed upon striking the mat in the landing area.
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A 60.0 cmcm, uniform, 60.0 NN shelf is supported horizontally by two vertical wires attached to the sloping ceiling (Figure 1). A very small 20.0 NN tool is placed on the shelf midway between the points where the wires are attached to it.
Each wire exerts a tension of 40.0 N to support the shelf.
The 60.0 cm, uniform, 60.0 N shelf is supported horizontally by two vertical wires attached to the sloping ceiling. A very small 20.0 N tool is placed on the shelf midway between the points where the wires are attached to it.
To analyze this situation, we need to consider the forces acting on the shelf and the tool.
1. The weight of the shelf is acting downward with a force of 60.0 N.
2. The vertical wires are exerting an upward force on the shelf to balance its weight. Let's call the tension in each wire T.
3. The tool exerts a downward force of 20.0 N on the shelf.
From the given information, we know that the shelf is uniform and supported horizontally. This means that the net force acting on the shelf in the vertical direction must be zero. Therefore, the sum of the upward forces (the tensions in the wires) must equal the sum of the downward forces (the weight of the shelf and the tool).
Using this information, we can set up an equation to solve for the tension in each wire:
2T - 60.0 N - 20.0 N = 0
Simplifying the equation, we have:
2T = 80.0 N
Dividing both sides by 2, we find that the tension in each wire is:
T = 40.0 N
So, the conclusion in one line is: Each wire exerts a tension of 40.0 N to support the shelf.
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55 points question
please put the answer in order by up to down
please help me
Answer:
animal and plant
Explanation:
1st is animal
mitochondria
cell membrane
nucleus
endoplasmic reticulum
golgi body
plant cell
cell wall
cell membrane
chloroplast
nucleus
vacuole
endoplasmic reticulum
mitochondria
golgi body
Theorem
Impulse-Momentum
A force of 58 N acts on a 29 kg body for 15 s. Find the:
11-12. (a) impulse produced by the force,
13. (b) the resulting change in momentum of the bod
14-15. (c) speed of the body at the end of 15 s.
To find the impulse produced by the force, we can use the formula:
Impulse = Force × Time
(a) Impulse produced by the force = 58 N × 15 s = 870 N·s
The impulse produced by the force is 870 N·s.
To find the resulting change in the momentum of the body, we can use the formula:
Change in Momentum = Mass × Change in Velocity
(b) Since the force acts on the body for 15 seconds, the change in velocity can be calculated using the formula:
Change in Velocity = (Force / Mass) × Time
Change in Velocity = (58 N / 29 kg) × 15 s = 116 m/s
The resulting change in momentum of the body is given by:
Change in Momentum = Mass × Change in Velocity = 29 kg × 116 m/s = 3364 kg·m/s
The resulting change in momentum of the body is 3364 kg·m/s.
To find the speed of the body at the end of 15 seconds, we need to calculate the final velocity. We can use the formula:
Final Velocity = Initial Velocity + (Change in Velocity)
Since the problem doesn't mention the initial velocity, we assume it to be zero (at rest).
(c) Speed of the body at the end of 15 s = Final Velocity = Change in Velocity = 116 m/s
The speed of the body at the end of 15 seconds is 116 m/s.
the ostringstream member function ____ returns the contents of an ostringstream buffer as a string.
The ostringstream member function "str" returns the contents of an ostringstream buffer as a string. Here's how you can use it:
1. Create an ostringstream object:
ostringstream oss;
2. Write data to the ostringstream buffer using the insertion operator (<<):
oss << "Hello";
oss << " World";
3. Retrieve the contents of the buffer as a string using the "str" member function:
string result = oss.str();
The variable "result" will now contain the string "Hello World".
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Q. A train accelerates from 36 km/h to 54 km/h in 10 sec. (i) Acceleration (ii) The distance travelled by car.
u=10m/s
v=15m/s
acceleration=
v_u/ t
5/10
0.5
1. What are the two main gases responsible for lowering down the pH.
2. Can we control an acid rain? Why or Why not?
3. When pH changes from 6 to 3, how many times does acidity increase?
Answer:
1. The three main acidic gases responsible for lowering the pH of rainwater are non-metal oxides produced by the burning of fossil fuels like coal, oil and natural gas. Sulfur dioxide is produced when fossil fuels containing sulfur impurities are burned.
2. A great way to reduce acid rain is to produce energy without using fossil fuels. Instead, people can use renewable energy sources, such as solar and wind power. Renewable energy sources help reduce acid rain because they produce much less pollution.
3. The pH scale is logarithmic, meaning that an increase or decrease of an integer value changes the concentration by a tenfold. For example, a pH of 3 is ten times more acidic than a pH of 4.
When a race car drives around a circular path, it must accelerate toward the center of the track so it doesn’t hit the outer wall due to what?
a. centripetal force
b. gravitational force
c. friction force
d. momentum
Answer:
Gravitational Force
Explanation:
If you enter a turn too fast, the front wheels will lose grip and possibly even the back wheels. This happens because of the gravitational force on the car.
A person exerts 12.0 N on a 0.145 kg baseball for 0.480 s. What is the change in velocity of the base ball?
The change in velocity of the baseball is 39.72 m/s
What is change in velocity?
This is the difference between the final and the initial velocity of a body.
To calculate the change in velocity of the ball, we use the formula below.
Formula:Ft = mΔv.............. Equation 1Where:
F = Force exerted by the persont = timem = mass of the baseballΔv = Change in velocity.Make Δv the subject of the equation
Δv = Ft/m........... Equation 2From the question,
Given:
F = 12 Nt = 0.480 sm = 0.145 kgSubstitute these values into equation 2
Δv = (12×0.48)/0.145Δv = 39.72 m/s.Hence, The change in velocity of the baseball is 39.72 m/s
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Remember KE=M*V2/2… A model airplane moves twice as fast as another identical model airplane. Compared with the kinetic energy of the slower airplane, the kinetic energy of the faster airplane is
Answer: 4 times as much
Explanation:
When a rocket accelerates through space is there work done?
What do ethical guidelines for research with human subjects mean in psychology?
Explanation:
Research in humans should be based on from library and animal experimentation . Research protocols should be reviewed by an independent committee prior to initiation
Which gas is least likely to obey the ideal gas laws at very high pressures and very low temperatures?
Answer:
Xe
Explanation:
At low temperatures or high pressures, real gases deviate significantly from ideal gas behavior. It is also good to know that ideal gas law assumes that the gas molecules have negligible/no size.
Keeping that in mind, Xe is the largest of the bunch, and therefore is expected to have the greatest deviation of the ideal gas when under high pressure or low temperature.
Hope this helped
Why do wool socks stick to my cotton shirt when tumbled in the dryer
In a road there are 1500 vehicles running in a span of 3 hours. Maximum speed of the vehicles has been fixed at 90km/hr. due to pollution control norms a vehicle can emit harmful gas up to a level of 30g/s. the wind speed normal to the road is 4 m/s and moderately stable conditions prevails. Estimate the level of harmful gas does wind of the road at 100m and 500m respectively
At 100m from the road, the estimated level of harmful gas is approximately 1.84 g/m³, and at 500m from the road, it is approximately 0.18 g/m³.
The level of harmful gas at the different intervalsConsidering the dispersion of pollutants due to wind speed and stability conditions using the Gaussian plume model.
Calculating the emission rate of harmful gas for all the vehicles on the road.
Each vehicle can emit up to 30 g/s, and there are 1500 vehicles running in 3 hours.
Total emission rate = (30 g/s) × (1500 vehicles) × (1 / (3 hours) × (3600 seconds/hour))
Total emission rate = 600 g/s
Now, we can estimate the level of harmful gas at different distances from the road using the Gaussian plume model. The equation for the ground-level concentration of a pollutant at a downwind distance x from the source is given by:
C = (Q / (2πuσy)) × exp(-(x - ux / H)² / (2σx²))
Where:
C = Ground-level concentration of the pollutant
Q = Emission rate (g/s)
u = Wind speed normal to the road (m/s)
σy = Vertical dispersion parameter (dependent on atmospheric stability conditions)
x = Downwind distance from the source (m)
H = Effective stack height (m)
σx = Horizontal dispersion parameter (dependent on atmospheric stability conditions)
For moderately stable conditions, the following values can be used:
σx = 0.09x
σy = 0.35x^0.8
The level of harmful gas at 100m and 500m from the road.
At 100m:
x = 100m
σx = 0.09x = 0.09 * 100 = 9m
σy = 0.35x^0.8 = 0.35 * (100^0.8) ≈ 24.92m
C = (Q / (2πuσy)) × exp(-(x - ux / H)² / (2σx²))
C = (600 g/s / (2π * 4 m/s * 24.92m)) × exp(-(100m - 0m)² / (2 * (9m)²))
C ≈ 1.84 g/m³ (rounded to two decimal places)
At 500m:
x = 500m
σx = 0.09x = 0.09 * 500 = 45m
σy = 0.35x^0.8 = 0.35 * (500^0.8) ≈ 124.60m
C = (Q / (2πuσy)) × exp(-(x - ux / H)² / (2σx²))
C = (600 g/s / (2π * 4 m/s * 124.60m)) × exp(-(500m - 0m)² / (2 * (45m)²))
C ≈ 0.18 g/m³ (rounded to two decimal places)
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5.
1
Shown above is a wire that is carrying current in a magnetic field. The magnetic field
is coming out the plane of the page.
What is the direction of deflection of the wire?
A) Upwards
B) Downwards
C) To the left
D) To the right
Answer:
The direction of defliection of the site to the left I think ..
Cómo están relacionadas la energía y materia en la química?
Answer:
La materia y energía interactúa entre sí de forma continua. De hecho, la materia estaría en un estado estático de forma estable si no fuera por la energía. De esta forma, materia y energía están interactuando entre sí constantemente, donde la materia sería el sujeto pasivo que padece la acción de la energía, mientras que la energía sería el sujeto activo que modificaría el estado de reposo o movimiento de la materia.
Explanation:
What is power when 3.2 A flows through an 18 ohm resistor?
To find the power formula on the electrical side you should have to know ohm's law of voltage that is V=I*R.
Here power formula is P=V*I.
Interms of resistance P=(IR)*I ==>I² R.
Here the power dissipated when 3.2 ampere of current flows through an 18-ohm resistor is
P=I² R ==>(3.2)² (18).
====>10.24(18)=184.32W.
W= Watts.
Watts is a unit of power.
Hope this helps
The specific tension of muscle is about 30 N/cm^2. The cross-sectional areas of the prime movers for elbow flexion and extension have been measured as follows:
Muscles Cross-sectional area
Biceps brachii 3.6 cm2
Brachialis 6.0 cm2
Brachioradialis 1.5 cm2
Triceps brachii 17.8 cm2
A. Determine the maximum force that the elbow flexors (as a group of muscles) can exert.
B. Consider the elbow flexors to act together with a moment arm of 4 cm, and the triceps with a moment arm of 2.5 cm. If all of these muscles were activated fully, would the elbow flex or extend?
A. We need to compute the entire cross-sectional area of the prime movers for elbow flexion and multiply it by the specific tension of muscle to get the maximum force that the elbow flexors can produce. The elbow flexors have a total cross-sectional area of 3.6 + 6.0 + 1.5 = 11.1 cm2. As a result, the elbow flexors may exert the following amount of force:
Cross-sectional area times a certain tension equals force.
Force = 333 N Force = 11.1 cm2 x 30 N/cm2
B. We must compare the torques generated by the triceps and the elbow flexors in order to determine whether the elbow will flex or extend. A muscle's torque is determined by multiplying the force it exerts by the moment arm. The moment arm is the angle at which the muscle's line of action is perpendicular to the axis of rotation.
The total torque for the elbow flexors is:
Torque equals force times moment arm
Torque equals 333 N/4 cm.
1332 N cm of torque
The total torque for the triceps is:
Torque equals force times moment arm
Torque is equal to 17.8 cm2 x 30 cm2 x 2.5 cm.
1335 N cm of torque
Since the triceps generate slightly more torque than the elbow flexors do, the elbow would extend if all of these muscles were fully engaged.
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A. To determine the maximum force that the elbow flexors can exert, we need to calculate the total cross-sectional area of the prime movers for elbow flexion, and then multiply it by the specific tension of the muscle:
The total cross-sectional area of elbow flexors = Biceps brachii + Brachialis + Brachioradialis
= 3.6 cm2 + 6.0 cm2 + 1.5 cm2
= 11.1 cm2
The maximum force that the elbow flexors can exert = Total cross-sectional area x Specific tension of muscle
= 11.1 cm2 x 30 N/cm2
= 333 N
Therefore, the maximum force that the elbow flexors can exert is 333 N.
B. To determine whether the elbow would flex or extend if all of these muscles were activated fully, we need to calculate the net torque generated by the muscles:
Net torque = (Force x Moment arm)flexors - (Force x Moment arm)triceps
Where force is the maximum force that the elbow flexors can exert (333 N), the moment arm of the elbow flexors is 4 cm, and the moment arm of the triceps is 2.5 cm.
Net torque = (333 N x 4 cm) - (333 N x 2.5 cm)
= 999 Ncm - 832.5 Ncm
= 166.5 Ncm
Since the net torque is positive (166.5 Ncm), the elbow would flex if all of these muscles were activated fully.
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How is the answer D?
The graph that corresponds to 0.1 s in one complete cycle is graph D.
option D is the correct answer.
What is the period of a wave?The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.
Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.
From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;
Period = 1 s / 10
Period = 0.1 s
From the graphs, the only option that has one complete cycle in one second is option D.
Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.
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How fast is lightening
Answer:
According to online, it shows that lightning can be traveling at 186,000 miles in only one second!
Hope it was helpful