Answer:
41,41
Step-by-step explanation:
because thenumber of 41 is repeated
The weights X of an animal are distributed according to the
probability distribution shown.
What is the probability that the animal's weight will be less than
151 pounds?
O 0.25
O 0.50
O 0.60
O 0.75
The probability that the animal's weight will be less than 151 pounds is 0.50.
The correct option is B.
What is the probability that the animal's weight will be less than 151 pounds?Since the given probability distribution ranges from 148 to 152, and we need to find the probability that the animal's weight will be less than 151 pounds, we can add the probabilities corresponding to the weights less than 151.
From the distribution, we see that the probability of the animal's weight being less than 151 pounds is 0.2 + 0.3 = 0.5.
Therefore, the answer is O 0.50.
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Determine which relation is a function.
A. (0, 1), (1, 1), (2, 3), (3, 4), (4, 5)
B. (0,0), (0, 1), (1, 0), (2, 2), (3, 3)
C. (-2, 1), (0, 3), (-2, 2), (4, 1), (1, 4)
D. (-3,2), (1, 4), (0, 0), (2, 3), (-3, 5)
Answer:
A
Step-by-step explanation:
One easy way to determine if a coordinate is a function or not is to look at the number in the x's place only. There should not be the same number on the x's side for a different pair.
Every pair has a different number on the x's side, which is why A is the only possible answer.
1) Nikita wrote the expression 72 + 26. Bettina wrote the expression 4 x (72+26).Which sentence is true about the value of their expressions?a) The value of Bettina's expression is the value of Nikita's expression.b) The value of Bettina's expression is 4 times more than the value of Nikita's expression.
b) The value of Bettina's expression is 4 times more than the value of Nikita's expression.
Explanations:Nikita's expression = 72 + 26
Bettina's expression = 4 x (72 + 26)
For clarification, let us find the value of Nikita's expressions
Value of Nikita's expression = 72 + 26 = 98................(1)
Let us simplify Bettina's expression a little further:
Bettina's expression = 4 x (72 + 24)
Bettina's expression = 4 x 98 ..........................................(2)
Comparing equations (1) and (2), we would see that the value of Bettina's expression is 4 times the value of Nikita's expression.
Can y’all help me please?
Answer:
(A) \(5\frac{1}{4}*4\frac{1}{5}\)
Step-by-step explanation:
The area of a parallelogram is the same as the area of a rectangle which is A=bh where b is the base and h is the height. Therefore, Erica can use the expression \(5\frac{1}{4}*4\frac{1}{5}\) to find the area of the parallelogram.
PLEASE GIVE STEP BY STEP EXPLANATION !!
The linear functions f(x) and g(x) are represented on the graph, where g(x) is a transformation of f(x): A graph with two linear functions; f of x passes through 0, negative 1 and 5, 14, and g of x passes through negative 6, negative 1 and negative 1, 14. Part A: Describe two types of transformations that can be used to transform f(x) to g(x). (2 points) Part B: Solve for k in each type of transformation. (4 points) Part C: Write an equation for each type of transformation that can be used to transform f(x) to g(x). (4 points)
The two types of transformations that can be used to transform f(x) to g(x). g (x) = f(x) + 16 and g (x) = f(x + 8)
ABC has vertices at A (12, 8), B (4, 8)
What is the equation about?f(x)= 0, -1 ,5,14
g(x)= -6, -1, -1, 14
g(x)=f(x)+k
-6= 0+k
k= -6
A) g (x) = f(x) + 16 and
g(x) = f(x + 8)
B) g(x)=f(x)+k
-1= -1+ k
k= -1+1=0
g(x)=f(x)+k
-1= 5+k
k= -1-5=-6
g(x)=f(x)+k
14= 14+k
k= 0
k= -6,0,-6,0
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Find KL using the concurrency of median theorem
Note that from the information provided, KL is 24. This is solved using the Centroid Theorem.
What is the rationale for the above response?
According to the centroid theorem, the triangle's centroid is located 2/3 of the way between the vertex and the midpoint of the sides.
From the information given in the diagram, P is the centroid of the triangle. Therefore, applying the centroid theorem, thus,
⅔ of KL = LP
LP = 16
Plug in the value of LP
⅔ (KL) = 16
Multiply both sides by 3
2(KL) = 3*16
2(KL) = 48
Divide both sides by 2
KL = 48/2
Thus,
KL = 24
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Please indicate which one is the minimal complete set of relational algebra operations in the following: a. {0, 1, U, -, 1} b. {0, T, U, n, x} c. {0, 1, 0, -, *}d. {C, T, U, -, *}
D i.e. {C, T, U, -, *} is the minimal complete set of relational algebra operations.
What is relational algebra?
Relational Algebra is a query language that takes a Relation as input and returns another Relation as output. Relational algebra provides the theoretical basis for relational databases and SQL. The necessary column data for a relation is projected via projection.
Now,
As Five basic operations in relational algebra are : Selection, Projection, Cartesian product, Union, and Set Difference and all these are present in
{C, T, U, -, *}.
Hence,
D i.e. {C, T, U, -, *} is the minimal complete set of relational algebra operations.
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The triangle shown has an area of 46 square centimeters. Find the measure of the base (segment AB ). Triangle A B C. A line goes from point C to point D on side A B. Side A C is 11 centimeters, C B is 9 centimeters, and A B is question mark.
By answering the presented question, we may conclude that Therefore, triangle the length of the base AB is approximately 20.88 centimeters.
What precisely is a triangle?A triangle is a closed, double-symmetrical shape composed of three line segments known as sides that intersect at three places known as vertices. Triangles are distinguished by their sides and angles. Triangles can be equilateral (all factions equal), isosceles, or scalene based on their sides. Triangles are classified as acute (all angles are fewer than 90 degrees), good (one angle is equal to 90 degrees), or orbicular (all angles are higher than 90 degrees) (all angles greater than 90 degrees). The region of a triangle can be calculated using the formula A = (1/2)bh, where an is the neighbourhood, b is the triangle's base, and h is the triangle's height.
the length of the base AB,
Area = (1/2) * base * height
\(CB^2 = CD^2 + BD^2\\9^2 = x^2 + (AB - x)^2\\81 = x^2 + (AB^2 - 2ABx + x^2)\\AB^2 - 2ABx + 2x^2 = 81\\\)
We also know that the area of the triangle is:
\(46 = (1/2) * AB * CB\\46 = (1/2) * AB * \sqrt(x^2 + 81)\\Now we can solve for AB in terms of x:AB = (2 * 46) / \sqrt(x^2 + 81)\\AB = 92 / \sqrt(x^2 + 81)\\(92 / \sqrt(x^2 + 81))^2 - 2(92 / \sqrt(x^2 + 81))x + 2x^2 = 81\\\)
\(8464 / (x^2 + 81) - (184x) /sqrt(x^2 + 81) + 2x^2 = 81\\8464 - 184x(x^2 + 81) + 2x^2(x^2 + 81) * sqrt(x^2 + 81) = 81(x^2 + 81)\\2x^4 - 181x^2 + 7743 = 0\\x^2 = (181 + \sqrt(181^2 - 427743)) / (2*2)\\x^2 = (181 + sqrt(129961)) / 4\\x^2 = (181 + 361) / 4\\x^2 = 90^2 / 4\\x = 45\sqrt(2) / 2\\\)
\(AB = 92 / \sqrt(x^2 + 81)\\AB = 92 / \sqrt((45sqrt(2) / 2)^2 + 81)\\AB = 92 / \sqrt(4050)\\AB ≈ 20.88 cm\\\)
Therefore, the length of the base AB is approximately 20.88 centimeters.
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Ms. Turner drove 90 miles in March. She drove 3 times as many miles in March as she did in January. She drove 4 times as many miles in February as she did in January. How many miles did Ms. Turner drive in February?
Answer:
7.5 miles
Step-by-step explanation:
I think...
In March Ms. Turner drove 90 miles. If she drove 3 times as many miles in March as she did in January, then all we need to do at this point is multiply 3 to 90.
90 × 3 = 270
So Ms. Turner drove 270 miles in January.
Ms. Turner then drove 4 times as many miles in February as she did in January, so we will do the same here.
270 × 4 = 1080
Therefore, Ms. Turner drove 1,080 miles in February.
A hockey team has red sweaters, white sweaters, and blue sweaters. The team uses red or blue pants and red or white socks. Find the number ofpossible uniforms.571210
We have
--Sweaters: red, white and blue
Total = 3 colors
--Pants: red and blue
Total = 2 colors
Socks: red and white
Total = 2 colors
Therefore, the number of possible uniforms:
\(undefined\)Solve the equation for x^2=
625
Answer:
x = ±25
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Algebra I
Multiple RootsStep-by-step explanation:
Step 1: Define
x² = 625
Step 2: Solve for x
Square root both sides: x = ±25Step 3: Check
Plug in x into the original equation to verify it's a solution.
x = -25
Substitute in x: (-25)² = 625Exponents: 625 = 625Here we see that 625 does indeed equal 625.
∴ x = -25 is a solution to the equation.
x = 25
Substitute in x: 25² = 625Exponents: 625 = 625Here we see that 625 does indeed equal 625.
∴ x = 25 is a solution to the equation.
a service center receives an average of 0.7 customer complaints per hour. management's goal is to receive fewer than three complaints each hour. assume the number of complaints follows the poisson distribution. determine the probability that exactly four complaints will be received during the next eight hours.
The probability that exactly four complaints will be received during the next eight hours is 15.41%.
A discrete probability distribution called the Poisson distribution provides the likelihood that an event will occur a specific number of times over the course of a given period of time or location. The formula for this distribution is given by \(P(X=x)=\frac{e^{-\mu}\times \mu ^x}{x!}\) where x is the number of successes, μ is the mean, and e is Euler's number.
Given n = 8 hours then, μ = 0.7n = 0.7×8 = 5.6.
Then, the probability that exactly four complaints are received is,
\(\begin{aligned}P(X=4)&=\frac{e^{-5.6}\times5.6^4}{4!}\\&=0.1541\end{aligned}\)
The required answer is 15.41%.
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Calculate the unit rate:
write your answer as a decimal
1/2 mile in ever 1/3 hour
Answer:
\(unit \: rate = \frac{distance}{time} \)
unit rate is similar to speed / velocity:
\(unit \: rate = \frac{ (\frac{1}{2} )}{ (\frac{1}{3})} \\ \\ = \frac{1}{2} \div \frac{1}{3} \\ \\ = \frac{1}{2} \times \frac{3}{1} \\ \\ = > { \boxed{ \boxed{unit \: rate = \frac{3}{2} \: miles \: per \: hour}}}\)
[unit rate must have units including per <time> ]
Answer the following question based off of the following data set:
15, 17, 21, 25, 31, 32, 32, 32, 34
What is the range of the data set equal to? Round to two decimal places (if
need be)!
O 19
O26.56
32
31
The range of the data set is 19
How to calculate the Range ?Range can be described as the difference between the highest and lowest value
The set of data is
15, 17, 21, 25, 31, 32, 32, 32, 34
The highest value is 34
The lowest value is 15
Range= 34 - 15
= 19
Hence the Range of the data set is 19
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A committee of four people is formed by selecting members from a list of 12 people.
How many different committees can be formed?
__ committees
The number of different committees that can be formed is 495
How many different committees can be formed?From the question, we have the following parameters that can be used in our computation:
People = 12
Committee = 4
These can be represented as
n = 12 and r = 4
The number of different committees that can be formed is
Number = nCr
So, we have
Number = 12C4
Evaluate
Number = 495
Hence, the committee are 495
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what is the appropriate measure of the missing angle of the triangle shown
Answer:
it's answer is D. 33°
Let the unknown angle be x Then.
x + 100° + 47° = 180° [ being sum of angles of triangle ]
x + 147° = 180°
x = 180° - 147°
x = 33°
Step-by-step explanation:
which statements are true select all that apply. Extra points!!!
Find the distance between the two points in simplest radical form. (-6,1) and (−8,−4)
Answer: 5
Step-by-step explanation: I think it is 5
If Jan sells 2,500 glow sticks on the Fourth of July at $1.99 each, what will her total profit be if each stick cost her $0.87?
Answer:
This could be wrong I would get a second opinion
The profit would be 2800
Step-by-step explanation:
$1.99 - .87 = $1.12
$1.12 x 2500 = 2800
Rewrite the following statement as an equation.
The sum of a number squared and three less than twice the number is 129.
Convert the function to standard form:f(x) = -2(x + 9)(x - 3)
The answer is
\(f(x)=-2x^2-\text{ 12x+54}\)\(undefined\)Consider the following data representing the price of laptop computers (in dollars). 12041204, 12061206, 13451345, 13061306, 12071207, 10781078, 13571357, 12321232, 12281228, 13021302, 11891189, 11771177, 10831083, 10941094, 13261326, 10711071, 14271427, 13481348, 14201420, 12531253, 1270 Determine the frequency of the fifth class.
Answer:
Step-by-step explanation:
The given data is expressed as
1204, 1206, 1345, 1306, 1207, 1078, 1357, 1232, 1228, 1302, 1189, 1177, 1083, 1094, 1326, 1071, 1427, 1348, 1420, 1253, 1270
The number of items in the data, n is 21. The lowest value is 1071 while the highest value is 1427. The convenient starting point would be 1070.5 and the convenient ending point would be 1427.5
The number of class intervals is
√n = √21 = 4.5
Approximately 5
The width of each class interval is
(1427.5 - 1070.5)/5 = 72
The end of each class interval would be
1070.5 + 72 = 1142.5
1142.5 + 72 = 1214.5
1214.5 + 72 = 1286.5
1286.5 + 72 = 1358.5
1358.5 + 72 = 1430.5
The frequency for the fifth class, that is between 1358.5 to 1430.5 would be 2
Name one attribute of a square that is not an attribute
what is z in -5/2 = 3/4z + 1/2? please also explain the steps i’m really confused
A fifth grade teacher calculates that 27% of her students are late for class. If the teacher is right, what is the probability that the proportion of late students in a sample of 724 students would differ from the population proportion by less than 4%? Round your answer to four decimal places.
Answer:
answer: 0.9479
hope I helped
What is the fundamental difference in the algebraic representation of a polynomial function and a rational function? How do you the graphs differ?
The difference between polynomial functions and rational functions is that the the last, the rational functions, can be always expressed as a quotient of polynomials.
This will make them differ in the graphs: as in rational functions we will have a polynomial in the denominator, its roots will become discontinuities (holes or vertical asymptotes). They may also present horizontal or slant asymptotes.
An arrow is shot from 3 ft above the top of a hill with a vertical upward velocity of 108 ft/s. If it strikes the plain below after 9.5 s, how high is the hill?
If the arrow is launched at t0, then write an equation describing velocity as a function of time?
The height of the hill is approximately 25.73 ft. Where v0 is the initial velocity (108 ft/s), g is the acceleration due to gravity \((-32.2 ft/s^2)\),
To find the height of the hill, we can use the formula for the vertical position of an object under constant acceleration:
h = h0 + v0t + 1/2at^2
where h is the final height, h0 is the initial height, v0 is the initial velocity, t is the time, and a is the acceleration due to gravity (-32.2 ft/s^2).
In this case, we are given that the initial height h0 is 3 ft, the initial velocity v0 is 108 ft/s, and the time t is 9.5 s. We want to find the height of the hill, which we can denote as h_hill. The final height is the height of the plain, which we can denote as h_plain and assume is zero.
At the highest point of its trajectory, the arrow will have zero vertical velocity, since it will have stopped rising and just started to fall. So we can set the velocity to zero and solve for the time it takes for that to occur. Using the formula for velocity under constant acceleration:
v = v0 + at
we can solve for t when v = 0, h0 = 3 ft, v0 = 108 ft/s, and a = -32.2 ft/s^2:
0 = 108 - 32.2t
t = 108/32.2 ≈ 3.35 s
Thus, it takes the arrow approximately 3.35 s to reach the top of its trajectory.
Using the formula for the height of an object at a given time, we can find the height of the hill by subtracting the height of the arrow at the top of its trajectory from the initial height:
h_hill = h0 + v0t + 1/2at^2 - h_top
where h_top is the height of the arrow at the top of its trajectory. We can find h_top using the formula for the height of an object at the maximum height of its trajectory:
h_top = h0 + v0^2/2a
Plugging in the given values, we get:
h_top = 3 + (108^2)/(2*(-32.2)) ≈ 196.78 ft
Plugging this into the first equation, we get:
h_hill = 3 + 108(3.35) + 1/2(-32.2)(3.35)^2 - 196.78
h_hill ≈ 25.73 ft
If the arrow is launched at t0, the equation describing velocity as a function of time would be:
v(t) = v0 - gt
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Please help for brainliest !!
Answer:
i do bellieve it is c
Step-by-step explanation:
Is either x = 8 or x = 10 a solution to 5x < 52?
A. x = 8 is a solution, but x = 10 is not.
B. Neither is a solution.
O C. x = 10 is a solution, but x = 8 is not.
D. They are both solutions.
Answer:
B. neither of them are solutions
6.334*104=6.334*10<sup>4</sup>=
Answer:
what's that
Step-by-step explanation: