Here' a another graph if someone can please help me solve

Answer:   You can buy a 9-pound bag for $8.37.

Step-by-step explanation:

\(\frac{5lbs}{4.65} =\frac{p}{8.37}\)    

Then, we cross multiply, and we get:

5(8.37) = 4.65p

  41.85 = 4.65p   [We divided 4.65 by both sides]

         9 = p

if G is a finite group, the index of Z(G) cannot be prime.

Let's consider a finite group G with the center Z(G). We want to prove that the index of Z(G) in G cannot be a prime number.

Assume, for the sake of contradiction, that the index of Z(G) in G is a prime number, say p. By definition, the index [G:Z(G)] is equal to the number of distinct cosets of Z(G) in G, which would be p. Since G is a finite group, we can apply the Lagrange's theorem which states that the order of any subgroup (in this case, Z(G)) divides the order of the group (|G|). So, |Z(G)| divides |G| and |G| = p * |Z(G)|.

Now, let's consider the action of G on the set of left cosets of Z(G) by left multiplication. This action gives rise to a homomorphism from G to the symmetric group on p elements, S_p. By the First Isomorphism Theorem, we know that the image of this homomorphism, denoted as Im(φ), is isomorphic to G/Ker(φ), where Ker(φ) is the kernel of the homomorphism.

Observe that Z(G) is a subgroup of the kernel, as any element from Z(G) will fix each coset. This means |Ker(φ)| ≥ |Z(G)|. Furthermore, Ker(φ) is a normal subgroup of G, so the index [G:Ker(φ)] must divide |G| = p * |Z(G)|.

Since |G/Ker(φ)| = |Im(φ)| divides |S_p| = p!, and |Im(φ)| = [G:Ker(φ)], we must have either |Im(φ)| = p or |Im(φ)| = 1. If |Im(φ)| = p, then [G:Ker(φ)] = p, and Ker(φ) = Z(G). However, this would imply that the action is trivial, which is a contradiction. Thus, |Im(φ)| = 1, meaning that the action is trivial, and G = Z(G), which contradicts our initial assumption that the index of Z(G) in G is prime.

Hence, if G is a finite group, the index of Z(G) cannot be prime.

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The five number summary is the minimum, first quartile (25th percentile), median (50th percentile), third quartile (75th percentile), and the maximum.

To give the smallest interval that we know contains the 30th percentile, we would take the 25th percentile and the 30th percentile. So, the smallest interval that we know contains the 30th percentile would be [25th percentile, 30th percentile].

The smallest interval that contains the 30th percentile is [25th percentile, 30th percentile], which is found using the five number summary (minimum, first quartile, median, third quartile, and maximum).

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We have two right-angled triangles that share a common side, with side lengths 6 and 10. Let's label the sides of the triangles as follows:

Triangle 1:

Side adjacent to the right angle: 6 (let's call it 'a')

Side opposite to the right angle: x (let's call it 'b')

Triangle 2:

Side adjacent to the right angle: x (let's call it 'c')

Side opposite to the right angle: 10 (let's call it 'd')

Using the Pythagorean theorem, we can write the following equations for each triangle:

Triangle 1:\(a^2 + b^2 = 6^2\)

Triangle 2: \(c^2 + d^2 = 10^2\)

Since the triangles share a common side, we know that b = c. Therefore, we can rewrite the equations as:

\(a^2 + b^2 = 6^2\\b^2 + d^2 = 10^2\)

Substituting b = c, we get:

\(a^2 + c^2 = 6^2\\c^2 + d^2 = 10^2\)

Now, let's add these two equations together:

\(a^2 + c^2 + c^2 + d^2 = 6^2 + 10^2\\a^2 + 2c^2 + d^2 = 36 + 100\\a^2 + 2c^2 + d^2 = 136\)

Since a^2 + 2c^2 + d^2 is equal to 136, we can conclude that x (b or c) is between 11 and 12

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\({ \qquad\qquad\huge\underline{{\sf Answer}}} \)

Here we go ~

\(\qquad \sf  \dashrightarrow \: \sqrt{250 {h}^{4} {k}^{5} } \)

\(\qquad \sf  \dashrightarrow \: \sqrt{(2 \times 5 \times 5 \times 5) \times (h \times h \times h \times h )\times (k \times k \times k \times k \times k} )\)

[ take out one of the pair ~ ]

\(\qquad \sf  \dashrightarrow \: 5 \times h \times h \times k \times k \sqrt{2 \times 5 \times k} \)

\(\qquad \sf  \dashrightarrow \: 5 {h}^{2} {k}^{2} \sqrt{10k} \)

That's our simplified answer ~

Answer:

<--> V 250h4k5

√(2 × 5 × 5 × 5) × (h×h×h×

[ take out one of the pair ~]

5 xhxhxkx k√2 × 5 × k

--> 5h2k2✓10k

Answer:

5

Step-by-step explanation:

There are 4 equal sides on a square so 20/4 which is 5.

Hope this helps plz mark brainliest :D

Answer:

2√5

Step-by-step explanation:

Since all the sides of a square are the same, we can take the square root of the area.

√20 = 2√5

Best of Luck!

Answer:5

Step-by-step explanation:

30 chapters in 6 hours. 30/6 =5

Answer:

C, D and F

Step-by-step explanation:

Answer:

10 + 7 + 4 + . . .; n = 5​

The series is arithmetic

Common difference between terms = (-3)

10 - 3 = 7

7 - 3 = 4

Or:

10 + (-3) = 7

7 + (-3) = 4

--------------------------------------------------------------------------

Another example:

Arithmetic:

5, 9, 13, 17

common difference = 4

5 + 4 = 9

9 + 4 = 13

Geometric:

4, 8, 16, 32

4 × 2 = 8

8 × 2 = 16

16 × 2 = 32

common ratio = 2

--------------------------------------------------------------------------

10 + 7 + 4 + . . .; n = 5​

a₁ = 10

a₂ = 7

a₄ = a₃ + d = 4 + (-3) = 4 - 3 = 1     (d = common difference)

a₅ = a₄ - 3 = 1 - 3 = -2

Or with formula:

\(d=a_{n} -a_{n-1}\)

d = a₂ - a₁ = 7 - 10 = -3

aₙ = a₁ + (n - 1)d

fourth term = a₄ = 10 + (4 - 1)(-3) = 10 + 3(-3) = 10 + (-9) = 10 - 9 = 1

fifth term = a₅ = 10 + (5 - 1)(-3) = 10 + 4(-3) = 10 + (-12) = 10 - 12 = -2

Sum of the finite series (if n = 5):

\(S_{n} =\frac{n(a_{1} +a_{n} )}{2} \\S_{5} =\frac{5(a_{1} +a_{5} )}{2} \\S_{5} =\frac{5(10 +(-2) )}{2} \\S_{5} =\frac{5(8 )}{2} =\frac{40}{2} =20\)

Manual count: S₅ = 10 + 7 + 4 + 1 + (-2) = 20

Answer:

the rise and run would be 2/1 so the transformation would be 2

Step-by-step explanation:

By the Intermediate Value Theorem: Let's prove that Stan x – 1 = cosx has a solution in the interval [0, 1].For this, we know that the function cos x is a continuous function, and it takes values between -1 and 1.

Also, the function Stan x – 1, takes value -1 at x=0 and takes value 1 at x=π/2, therefore the function Stan x – 1= cosx should have at least one solution in the interval [0, π/2].Hence, by the Intermediate Value Theorem, Stan x – 1 = cosx has a solution in the interval [0, 1].2. By the Intermediate Value Theorem: Let's prove that the polynomial

P(x) = -7x5 + 3x4 +4x2 – 3x2 + 1

(0,1).Let f(x) = -7x5 + 3x4 +4x2 – 3x2 + 1.By the Intermediate Value Theorem, if f(x) is a continuous function on [0,1] and if f(0) and f(1) have opposite signs, then there exists a value c in the interval (0,1) such that f(c) = 0.Now f(0) = 1 > 0 and f(1) = -2 < 0.Therefore, there exists at least one real number c in (0,1) such that f(c) = 0. Therefore the polynomial

P(x) = -7x5 + 3x4 +4x2 – 3x2 + 1 has at least one root on (0,1).1. Check the continuity at the point x = 0, of the function given by: f(x) = {1-x/1+x, if x < 0 if x = 0From the given function, if x ≠ 0, then the function f(x) is continuous at x.If x = 0, then the left-hand limit of the function as x approaches zero is:

lim (x → 0-) f(x) = lim (x → 0-) [1 - x / 1 + x] = [1 - 0 / 1 + 0] = 1and the right-hand limit of the function as x approaches zero is:

lim (x → 0+) f(x) = lim (x → 0+) [1 - x / 1 + x] = [1 - 0 / 1 + 0] = 1.Since both the left-hand and right-hand limits of f(x) exist and are equal, therefore the function is continuous at x = 0.2. Find real constants a, b so that the following function is continuous on

R: f(x) = {x + 1, if x ≤ 0ax + b, if 0 < x < 2x - 1, if x ≥ 2.

We know that the function is continuous for all x values if the following conditions hold:

1. f(0-) = f(0) = f(0+)2. f(2-) = f(2) = f(2+)From the function given, we know that f(0-) = f(0) = 1, and f(2+) = f(2) = 2(2) - 1 = 3.

To find the value of a and b, we set the expressions for ax + b and x + 1 equal to each other at x = 0. This gives us:0 + 1 = a(0) + b or b = 1Therefore, the given function becomes:

f(x) = {x + 1, if x ≤ 0ax + 1, if 0 < x < 2x - 1, if x ≥ 2Also, we set the expressions for ax + 1 and x + 1 equal to each other at x = 2. This gives us:

2a + 1 = 2 + 1 or 2a = 2 or a = 1

Therefore, the function is:f(x) = {x + 1, if x ≤ 01x + 1, if 0 < x < 22x - 1, if x ≥ 2

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Answer:

Answer of this is... D... 59

According to the figure the value of ∠BOC is 59. So, the correct option is option D.

Given:

∠AOC = 77°

According to the figure ∠AOB = 3X and ∠BOC = 7X + 17

∠AOC = ∠AOB + ∠BOC.

Plugging the values in this equation.

Then we get,

77 = 3X + 7X + 17

Subtract 17 on both sides.

77 - 17 =  3X + 7X + 17 - 17

60 = 3X + 7X

After simplify we get,

60 = 10x.

X = 6

To find the ∠BOC.

∠BOC = 7X + 17.

Plugging the value of X in this equation.

∠BOC = 7 * 6 + 17

∠BOC = 42 + 17

∠BOC  = 59.

Therefore, the value of ∠BOC is 59.

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In order to find if the triangle is acute, right or obtuse, we need to compare the square of the bigger side (a) with the sum of squares of the other sides (b and c):

If a² > b² + c², the triangle is obtuse.

If a² = b² + c², the triangle is right.

If a² < b² + c², the triangle is acute.

So we have:

The triangle is obtuse, therefore the correct option is B.

Answer:

\( \frac{1}{ \sqrt[7]{ {12}^{4} } } \)

Step-by-step explanation:

\( {12}^{ - \frac{4}{7} } is \: the \: same \: as \\ \frac{1}{ {12}^{ \frac{4}{7} } } \\ {12}^{ \frac{4}{7} } can \: also \: be \: expressed \: as \\ \sqrt[7]{ {12}^{4} } \)

Therefore:

\( {12} ^ { -\frac{4}{7} } \: is \: equivalent \: to \\ \frac{1}{ \sqrt[7]{ {12}^{4} } } \)

Answer:

n=12

m=5

Step-by-step explanation:

The sides on the left and right are equal, and the sides on the top and bottom are equal.

Left and right: n=12

Top and bottom: m+1=6; subtract 1 on both sides to get m=5

Answer: C. 53 million

Step-by-step explanation:

Answer:

C or 53million

Step-by-step explanation:

Answer:

your answer is C

Step-by-step explanation:

i took the quiz, may i have brainliest please!  :D

Epidemiological survey is often used to monitor trends over time and to identify populations at risk of developing certain health problems.

The survey that is utilized to determine the extent of problems in a certain area and then express the findings as rates affected within the population is an Epidemiological survey.

Epidemiology is the study of the distribution and determinants of health-related states or events in specific populations and the application of this study to the control of health issues.

Epidemiological research is carried out to measure the rates of illness and diseases among populations.

The data collected through the Epidemiological survey is used to determine how diseases spread, which populations are most affected, and how to control or prevent outbreaks in the future.

The following are the characteristics of an epidemiological survey:

Epidemiological surveys are used to measure rates of illness or disease within populations.

They may be used to determine the incidence, prevalence, or morbidity rates of a particular disease or condition.

This type of survey is often used to monitor trends over time and to identify populations at risk of developing certain health problems.

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Answer:

The equation of the line or linear function is:

y = -2x

Step-by-step explanation:

Given the table

x        3       6       9        12

y      -6    -12      -18      -24

As there is a constant change in x and y values, so the table represents the linear function.

The slope-intercept form of the linear equation

y = mx+b

where

Taking any two points, let say

Determining the slope between (3, -6) and (6, -12)

\(\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\)

\(m=\frac{-12-\left(-6\right)}{6-3}\)

Refine

\(m=-2\)

Thus, the slope m = -2

now substituting m = -2 and (3, -6) in the slope-intercept form

y = mx+b

-6 = -2(3) +b

-6 = -6 + b

b = -6 + 6

b = 0

Thus, the y-intercept b = 0

now substituting m = -2 and b = 0  in the slope-intercept form of linear function

y = mx+b

y = -2x + 0

y = -2x

Therefore, the equation of line or linear function is:

y = -2x

Answer:

21

Step-by-step explanation:

Since the girls have the same age, let their age be x.
Then, their average is

\(\frac{x+x}{2} = \frac{2x}{2} = x\)

Let \(S_{i}\) denote the age of 'i' girls.
Then, \(S_{8} = S_{6} + x + x - eq(1)\)

Also, we have,

\(\frac{S_{8}}{8} =15 - eq(2)\)

\(\frac{S_{6}}{6} =13 - eq(3)\)

Then eq(2):

(from eq(1) and eq(3))

\(\frac{S_{6} + 2x}{8} =15\\\\\frac{13*6 + 2x}{8} = 15\\\\78+2x = 120\\\\2x = 120-78\\\\x = 21\)

The average of the other two girls with equal age​ is 21

Answer: line B is the best

The next three number in the pattern is - 64, +16 and -4

A number pattern is an ordered set of numbers or diagrams that follow a particular rule.

Let's find the rule in the pattern as follows:

The first term is + 4096. This is same as 2¹².

The second term is - 1024. This is same as 2¹⁰. Note the sign changed.

The third term is +256. This is same as 2⁸. The sign change also.

From the pattern we notice the exponential reduced by 2 and sign changes.

Therefore, the next three terms in the pattern are as follows;

The full pattern is as follows:

+ 4096,  - 1024, +256, - 64, +16, -4

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Answer:

y = -3/4x-5/2 and y = 2/3x-1/3

Step-by-step explanation:

y+1 = -3/4(x+2)

y+1 = -3/4x-3/2

y = -3/4x-3/2-1

y = -3/4x-5/2

-----

y-3 = 2/3(x-4)

y-3 = 2/3x-8/3

y = 2/3x-8/3+3

y = 2/3x-1/3

Answer:

x=17

Step-by-step explanation:

The total degree of a hexagon is 720 degrees.

720-110-116=494.

(8x-1)+(6x-2)+(7x+19)+(5x+36)=494

x=17.

Answer:

3.15

Step-by-step explanation:

in a polygon sum of all angles = 360°

116+110+8x-1+5x+36+7x+19+6x-2 = 360

226-1+36+19-2+26x = 360

26x = 82

x=3.15

Answer:

The probability of the 4th donation being Type O or Type B is:

P(Type O or B) = P(Type O) + P(Type B) = 0.49 + 0.20 = 0.69

The probability of the 4th donation being safe for someone with Type B blood is the probability that it is Type O or Type B, which is 0.69. Therefore, the probability that the 4th donation selected at random can be safely used in a blood transfusion on someone with Type B blood is:

P(safe for Type B) = 0.69

Answer: (0.69)³(0.31)

Answer:

(2,7)

Step-by-step explanation:

You are welcome ;)

Enrique's way of finding out the average age of football game is not the right way. No, this is not a good sample as it is an example of a selection bias.

By only asking every third person, Enrique is not taking a random sample of people in the audience. This means that the sample is not representative of the entire population and therefore, the results may not be accurate. In this case, the selection bias is called an "interval sampling bias" because Enrique is only selecting people based on an interval (every third person). This type of sampling can be biased because the ages of the people selected may not be evenly distributed throughout the population, leading to an inaccurate representation of the average age. It would be more representative to take a random sample of people in the audience, such as by randomly selecting 10 or 20 people and asking them their ages. This would give a more accurate representation of the average age of people at the high school football game.

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Answer:

It's 28

Step-by-step explanation

Answer:

t-6

Step-by-step explanation:

listen to how the statement is worded, it will help with other problems like this.