HELPPP PLS
Write the correct postulate, theorem, property, or definition that justifies the statement below the
diagram.

Answer:

275

Step-by-step explanation:

If they pay $2,200 to screen a movie and charge $8 a head then it's just division. 2200/8 is equal to 275.

the tickets should be 275 tickets..

In the given options, the only relation that is also a function is;

option C: (−1, 1), (0, 0), (1, 1), (2, 4)

The domain of a function is the set of all possible input values (x-values) for which the function is defined. The range of a function is the set of all possible output values (y-values) that the function can produce.

A function is a relation between two sets, where each input from the first set (domain) corresponds to exactly one output in the second set (range).

In the given options, the only relation that is also a function is option C: (−1, 1), (0, 0), (1, 1), (2, 4)

This is because each input in the domain appears only once in the relation, and corresponds to exactly one output in the range. In other words, there are no two points in the relation with the same x-coordinate but different y-coordinates.

In options A, B, and D, there are two or more points with the same x-coordinate but different y-coordinates, which violates the definition of a function. Therefore, they are relations but not functions.

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In the given options, the only relation that is also a function is;

option C: (−1, 1), (0, 0), (1, 1), (2, 4)

The sets of all the x-coordinates as well as the y-coordinates of ordered pairs, respectively, make up the domain and range of a relation. A function's domain and range are its constituent parts. A function's range is its potential output, while its domain is the set of all possible input values.

The phrase "all the outcomes" that can enter a function without producing undefined values is referred to as the domain of a function. The collection of all feasible inputs for the function is known as the domain in mathematics.

A relation between two sets is called a "function" when every input from the first set (called the "domain") corresponds to exactly one output from the second set. (range).

The only relationship that also functions in the options is C: (−1, 1), (0, 0), (1, 1), (2, 4)

This is due to the fact that every input in the domain corresponds to only one output in the range and only one appearance in the relation. There are no

points in the connection that have the same x-coordinate but distinct y-coordinates, in other words.

The concept of a function is broken in choices A, B, and D because there are two or more points with the same x-coordinate but distinct y-coordinates. They are therefore relations rather than functions.

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The solution set of the example inequality, 2•x + 3 ≤ -3, is the option;

A possible inequality that can be used to get one of the options, (the inequality is not included in the question) is as follows;

Solving the above inequality, we have;

2•x + 3 ≤ -3

2•x ≤ -3 - 3 = -6

2•x ≤ -6

Therefore;

x ≤ -6 ÷ 2 = -3

x ≤ -3

Which gives;

-∞ < x ≤ -3 in interval notation is (-∞, -3]

The solution set of the inequality, 2•x + 3 ≤ -3, is therefore the option;

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It is not surjective because there is no element in the range that maps to the value 2. The absolute value function only takes non-negative values, so the range is limited to [0, 2), excluding 2.

The function f(x) = |x|, defined on the interval [-2, 1] with the range [0, 2], is injective but not surjective.

To show that it is injective, we need to demonstrate that distinct elements in the domain map to distinct elements in the range. Since the absolute value function |x| always returns a non-negative value, any negative value in the domain will be mapped to its positive counterpart in the range. For example, f(-2) = |-2| = 2 and f(1) = |1| = 1. Thus, distinct elements in the domain have distinct images in the range, establishing injectivity.

However, It is not surjective because there is no element in the range that maps to the value 2. The absolute value function only takes non-negative values, so the range is limited to [0, 2), excluding 2.

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To find the mean of the random variable Z in each case, we can use the properties of linear combinations of random variables.

Case 1: Z = 2X + 3Y

The mean of Z is given by:

E(Z) = 2 * E(X) + 3 * E(Y)

E(X) = 15

E(Y) = 35

Substituting the values:

E(Z) = 2 * 15 + 3 * 35

    = 30 + 105

    = 135

Therefore, the mean of Z in Case 1 is 135.

Case 2: Z = X - Y

The mean of Z is given by:

E(Z) = E(X) - E(Y)

E(X) = 15

E(Y) = 35

Substituting the values:

E(Z) = 15 - 35

    = -20

Therefore, the mean of Z in Case 2 is -20.

Case 3: Z = X + 2Y

The mean of Z is given by:

E(Z) = E(X) + 2 * E(Y)

E(X) = 15

E(Y) = 35

Substituting the values:

E(Z) = 15 + 2 * 35

    = 15 + 70

    = 85

Therefore, the mean of Z in Case 3 is 85.

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Answer:

If the units in the equation are in feet, it lef5t at a height of 7.4 feet (or meters, etc.).

Step-by-step explanation:

p(x) = - 0.013x2 + 0.02x + 7.4

When x, the time, = 0 [just before it leaves the pitcher's hand]

p(0) = 7.4

Jane travels 8 miles much farther than her trainer. The solution is obtained using arithmetic operations.

What are arithmetic operations?

By combining operands with one arithmetic operator, an arithmetic operation is given. The built-in functions add, subtract, divide, and multiply additionally allow for the specification of arithmetic operations.

3. Using pythagoras theorem, we get the equation as D² = 12² + 16².

⇒D² = 144 + 256

⇒D² = 400

⇒D = √400

⇒D = 20

4. Jane has traveled 28 miles in total whereas her trainer has traveled 20 miles.

So, the difference is 28-20= 8 miles

Hence, Jane travels 8 miles much farther than her trainer.

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We can form the eq. for y,

→ 6x - y = 2

→ y = 6x - 2

Then the value of x will be,

→ -4x + 3y = 1

→ -4x + 3(6x - 2) = 1

→ -4x + 18x - 6 = 1

→ 14x = 1 + 6

→ x = 7/14

→ [ x = 1/2 ]

Hence, the value of x is 1/2 (or) 0.5.

Now the value of y will be,

→ y = 6x - 2

→ y = 6(1/2) - 2

→ y = 3 - 2

→ [ y = 1 ]

Hence, the value of y is 1.

According to the information, the volume of the new package will be:\(V = 197.07^{3}\)

To calculate the volume of the new package we must perform the following procedure:

\(V = \pi r^{2} h\)

According to the above, we must substitute the values of the radius and the height to obtain the volume of the new package. If we increase the diameter by 2 in, then the new diameter will be 9.8 in. On the other hand, the radius will be:

9.8 in / 2 = 4.9 in

So, to find the volume we must solve the following formula:

\(V = \pi * 4.9 * 12.8\)

\(V = 197.07^{3}\)

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Answer:

u = 7

Step-by-step explanation:

-21 + 7u = 28

add 28 to both sides

7u = 49

divide by 7

u = 7

Answer:U=7

Step-by-step explanation:

Answer:

B. 30

Step-by-step explanation:

2m^2 + 12

m = 3

2(3)^2 + 12

3 squared is 9

2(9) + 12

2 times 9 is 18

18 + 12 = 30

2m^2 + 12 = 30

So we subtitute 3 to any "m" in your problem so,

2m^2+12

2(3)^2+12

2(9)+12

18+12

30

So,  B is the correct answer!

Answer:

It can't be solved - there are no real roots

10.5 lawn tickets and 3.5 pavilion seats were sold, which equals the total cost of $462.

We can utilise substitution to solve this set of equations. Let x represent the number of lawn tickets and y represent the number of pavilion seats. We can create two equations to represent the total cost of the tickets.

26x + 54y = 462

x + y = 14

To find the value of y, we can change the value of x from the second equation into the first equation.

26(14 - y) + 54y = 462

364 - 26y + 54y = 462

-26y + 54y = 462 - 364

28y = 98

y = 3.5

The second equation can then be solved for x by reintroducing the value of y.

x + 3.5 = 14

x = 10.5

This means that 10.5 lawn tickets were sold, and 3.5 pavilion seats were sold. To check if this solution makes sense, we can substitute our answer into the first equation to calculate the total cost.

26(10.5) + 54(3.5) = 462

This equation does equal 462, so our solution is correct. This makes sense in the context because it is a valid combination of tickets that adds up to the total cost of $462.

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ANSWER:

this the answer it's d

The graph that represents Ramon's initial step is, On a coordinate plane, the point (0, 3) is graphed.

The ordinate and abscissa of the x coordinate, along with two values specified in parentheses in a specific order, make up an ordered pair.

Pair in Order = (x, y) where x represents the abscissa, the measure of a point's separation from the main axis, and y represents the ordinate, the measure of a point's separation from the secondary axis.

Given, Ramon is graphing the function f(x) = 3 + (4)x.

We know the initial value of a function is determined when the independent variable is set to zero.

Here the independent variable is 'x'.

Now, at x = 0,

f(0) = 3 + (4)(0).

f(0) = 3.

So, The ordered pair is (0, 3).

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Answer:

a

Step-by-step explanation:

Answer:

Step-by-step explanation:

so Jada for 1 day, gets charged $30 flat

now, she drove 2 days, so...she's charged 2 * 30 or 60 bucks

plus the mileage

is 0.5 per mile.... so... 1 mile is 0.5

2  miles 2 * 0.5

3 miles 3 * 0.5

4 miles 4 * 0.5

5 miles 5 * 0.5

x miles x * 0.5

she drove "x" miles, whatever that is

we also know, her total cost in the end, was 360

so... those 360 include the 2 days charge, 30 * 2

plus the mileage,  x * 0.5 or 0.5x

so... one can say that

360 = (30 * 2) + 0.5x    <---- solve for "x"

Answer:

150, I believe.

Step-by-step explanation:

If it takes about 30 dollars a day, that would be $60 for 2 days.

The mile expenses should be $300, right? If this is true, we should be able to do: $0.50 * 300.

The answer is 150.

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The right triangle is rotated one time to the right with respect to the left triangle. Then the pairs are:

e and g, f and h.

Here we have two similar triangles, this means that one of the triangles can be a rotation + dilation of the other.

If you look at the dimensions of the second triangle and multiply these by 2, you see that the dimensions become:

2*2 = 4

2*3 = 6

2*4 = 8

Which are the same dimensions of the left triangle, but rotated one time to the right.

Now, knowing that, we caonclude that the corresponding angles are:

Then the correct option is the third one.

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We have \(\(1+x=0\)\(x=-1\)\) So the only critical point is -1. Now let's test for critical points using the first derivative test.

\(\(f'(-2)=e^{-2}-2e^{-2}\\=-e^{-2} < 0\)\(f'(0)\\=e^{0}=1 > 0\)\(f'(1)\\=e^{1}+e=2.7 > 0\)\)

Hence the critical point is at x=-1, which is the only critical point. Therefore, the function has a local minimum at \(x = -1.4. \\)

(a)

\(f(x)=(2-x)e^{-x}\)\\Let \\f(x)=(2-x)e^(-x)\(f'(x)\\=e^{-x}+e^{-x}(x-2)\)\(f'(x)\\=-e^{-x}(x-1)\)\)

Now, setting the derivative equal to zero and solving for x.\(\(-e^{-x}(x-1)=0\)\((x-1)=0\) when \(e^{-x}\)\)is not equal to zero. \(\(x=1\)\) So the critical point is at x = 1. Now we test critical points using the first derivative test.

\(\(f'(0)=1 > 0\)\(f'(2)\\=e^{-2}-e^{-2}(2-1)\\=0\)\(f'(3)\\=-e^{-3} < 0\)\)

Hence the critical point is at x = 1, which is the only critical point. Therefore, the function has a local maximum at x = 1.

(b)As we see, there is no local minimum.

(c) We can see that the function is decreasing to the left of 1 and increasing to the right of 1. Hence it's possible for a global maximum or minimum to exist. The graph shows a decreasing function to the left of 1 and an increasing function to the right of 1. Therefore, the function has no global minimum or maximum.

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a) A basis for V is {(-1, 1, 1, 0), (-1, 0, 0, 1)}. b) The (-1, 1, 1, 0) and (-1, 0, 0, 1) form a basis for the subspace V.

To find a basis for the subspace V = {x ∈ R^4 | u · x = 0 and v · x = 0}, we need to find a set of linearly independent vectors that span V.

(a) To find a basis of V:

We have two conditions for vectors in V: u · x = 0 and v · x = 0.

u · x = 0:

Substituting the values of u and x into the dot product equation:

(1, 1, 1, 1) · (x₁, x₂, x₃, x₄) = x₁ + x₂ + x₃ + x₄ = 0

This equation implies that the components of x must satisfy the relationship x₁ + x₂ + x₃ + x₄ = 0.

v · x = 0:

Substituting the values of v and x into the dot product equation:

(3, 3, 2, 1) · (x₁, x₂, x₃, x₄) = 3x₁ + 3x₂ + 2x₃ + x₄ = 0

This equation implies that the components of x must satisfy the relationship 3x₁ + 3x₂ + 2x₃ + x₄ = 0.

To find a basis for V, we need to find a set of linearly independent vectors that satisfy both of these conditions.

One way to find a basis is to solve the system of equations formed by these conditions:

x₁ + x₂ + x₃ + x₄ = 0

3x₁ + 3x₂ + 2x₃ + x₄ = 0

By row reducing the augmented matrix of this system, we find the following solution:

x₁ = -x₃ - x₄

x₂ = x₃

x₃ is a free variable

x₄ is a free variable

Based on the free variables, we can express the solution as:

x = (-x₃ - x₄, x₃, x₃, x₄) = x₃(-1, 1, 1, 0) + x₄(-1, 0, 0, 1)

So, a basis for V is {(-1, 1, 1, 0), (-1, 0, 0, 1)}.

(b) Explanation of why the vectors form a basis:

The vectors (-1, 1, 1, 0) and (-1, 0, 0, 1) satisfy both conditions u · x = 0 and v · x = 0. Therefore, they belong to the subspace V.

To show that these vectors form a basis, we need to demonstrate that they are linearly independent and that they span V.

Linear independence:

The vectors (-1, 1, 1, 0) and (-1, 0, 0, 1) are linearly independent if and only if there is no nontrivial solution to the equation a(-1, 1, 1, 0) + b(-1, 0, 0, 1) = (0, 0, 0, 0).

Solving this equation gives:

-a - b = 0

a = 0

b = 0

The only solution is a = b = 0, which confirms that the vectors are linearly independent.

Spanning V:

Since the vectors satisfy both conditions u · x = 0 and v · x = 0, any vector x ∈ V can be written as a linear combination of (-1, 1, 1, 0) and (-1, 0, 0, 1). Therefore, these vectors span the subspace V.

Hence, (-1, 1, 1, 0) and (-1, 0, 0, 1) form a basis for the subspace V.

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Answer:

correct answer is 4 fish

Step-by-step explanation:

4 is the perfect number

Answer:

Yes

Step-by-step explanation:

Here is an ugly drawing of it......

Answer:

\(48a^{2}\)

Step-by-step explanation:

First, multiply the numbers

-8a ( -6)a

48aa

Next, We can combine the exponents

\(48a^{2}\)

That is all you need to do. : - )

2y + 5 <=> 2y = -5 <=> y = -2.5

Then you substitute it in the other one.

4y -3 <=> 4 . (-2.5) -3 = -13

All three sides are the same length.

Answer:

15% of the Lego set is blue

Step-by-step explanation:

Percentage of a lego set being blue:

We divide the number of blue pieces by the number of total pieces, and multiply by 100.

We have:

150 blue pieces

700 + 150 + 150 = 1000 blue pieces

15% of the Lego set is blue

Given:

1. Angle B is congruent to Angle D.

2. Angle BAC is congruent to Angle DCA

To prove that triangles ABC and CDA are congruent, we first note that reflexive property means that anything is equal to itself. This means that:

Notice that both triangles share one side and we know that every side is congruent to itself. Hence, we can prove that triangles ABC and CDA are congruent by AAS Congruence Theorem as we have pairs of two congruent angles and non-included sides.

Therefore, the answer is:

The probability of getting a sum of 2 is 1/16, a sum of 3 is 2/16, a sum of 4 is 3/16, a sum of 5 is 4/16, a sum of 6 is 3/16, a sum of 7 is 2/16, and a sum of 8 is 1/16.

The probability distribution of Z, which represents the sum of the numbers on two balls drawn from an urn containing balls numbered 1, 2, 3, and 4, can be determined by considering all possible outcomes.

To calculate the probability distribution, we need to find the probability of each possible sum (Z) occurring. Let's break it down step by step:

Step 1: Determine the sample space.
The sample space is the set of all possible outcomes. In this case, there are four balls in the urn, so the total number of possible outcomes is 4 * 4 = 16 (since each ball can be paired with any of the other four balls).

Step 2: List all possible sums (Z).
Since there are four balls, the possible sums range from 1 + 1 = 2 to 4 + 4 = 8. Therefore, the possible sums (Z) are:
2, 3, 4, 5, 6, 7, 8

Step 3: Determine the probability of each sum (Z).
To find the probability of each sum (Z), we need to count the number of outcomes that result in each sum and divide it by the total number of possible outcomes.

- Z = 2: There is only one way to get a sum of 2, which is by drawing balls 1 and 1. Therefore, the probability of Z = 2 is 1/16.
- Z = 3: There are two ways to get a sum of 3: drawing balls 1 and 2 or balls 2 and 1. Therefore, the probability of Z = 3 is 2/16.
- Z = 4: There are three ways to get a sum of 4: drawing balls 1 and 3, balls 2 and 2, or balls 3 and 1. Therefore, the probability of Z = 4 is 3/16.
- Z = 5: There are four ways to get a sum of 5: drawing balls 1 and 4, balls 2 and 3, balls 3 and 2, or balls 4 and 1. Therefore, the probability of Z = 5 is 4/16.
- Z = 6: There are three ways to get a sum of 6: drawing balls 2 and 4, balls 3 and 3, or balls 4 and 2. Therefore, the probability of Z = 6 is 3/16.
- Z = 7: There are two ways to get a sum of 7: drawing balls 3 and 4 or balls 4 and 3. Therefore, the probability of Z = 7 is 2/16.
- Z = 8: There is only one way to get a sum of 8, which is by drawing balls 4 and 4. Therefore, the probability of Z = 8 is 1/16.

Step 4: Summarize the probability distribution.
The probability distribution of Z is:
Z = 2: 1/16
Z = 3: 2/16
Z = 4: 3/16
Z = 5: 4/16
Z = 6: 3/16
Z = 7: 2/16
Z = 8: 1/16

This means that the probability of getting a sum of 2 is 1/16, a sum of 3 is 2/16, a sum of 4 is 3/16, a sum of 5 is 4/16, a sum of 6 is 3/16, a sum of 7 is 2/16, and a sum of 8 is 1/16.

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Therefore, the due date of the note is August 9 adding the number of days in the note's term to the note's date adding the number of days in the note's term to the note's date.

To determine the due date of the note, we need to add the number of days in the note's term to the note's date.

Given:

Note term: 120 days

Note date: April 9

To find the due date, we add 120 days to April 9.

April has 30 days, so we can calculate the due date as follows:

April 9 + 120 days = April 9 + 4 months = August 9

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Told to walk in first week = 5km

Told to walk in second week = 8km

Told to walk in third week = 11km

It is forming a pattern,

5km      8km      11km       ..........

     +3       +3        +3

5km      8km     11km     14km     17km     20km    23km     26km   29km     32km

    +3       +3        +3       +3        +3        +3        +3         +3      +3  

The patient has to walk 32km in the 10th week.

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Answer:

X= 1/3

Step-by-step explanation: