HELPPP PLEASEEE!!! calculate the energy of radiation with a wavelength of 432 nm

The amount of KNO₃ would dissolve in 100g of water at 50 degrees celcuis to make a saturated solution is 44 g.

To create a saturated solution of KNO₃ in 100g of water at 50 degrees Celsius, the following steps should be taken:

Step 1: Find out the mass of the solvent in the saturated solution.

The solvent is water in this instance. So, using the formula for the mass of a solution, we can calculate the mass of the solvent in the saturated solution as follows:

Mass of solvent = Mass of solution - Mass of solute

= 100 g - Mass of KNO₃

Step 2: Determine the amount of solute that would be dissolved in the solution to make it saturated.

The mass of KNO₃ that would dissolve in 100 g of water at 50°C to create a saturated solution is 56g/100g of water.

Step 3: Calculate the mass of KNO₃ that would dissolve in 100g of water to make a saturated solution.

Mass of KNO₃ = Solubility of KNO₃ × Mass of solvent

Mass of KNO₃ = 56 g/100 g × (100 g - Mass of KNO₃)

Now, let's solve for Mass of KNO₃;

56 = 56g(100-Mass of KNO₃)/100100 - Mass of KNO₃ = 100

Multiply both sides of the equation by 100 to obtain;

5600 - 100 Mass of KNO₃ = 100

Mass of KNO₃ = 5600/10100 - 56

= 44 g

Therefore, 44 g of KNO₃ would dissolve in 100g of water to make a saturated solution.

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If the central atom in a molecule is sp3 hybridized, then it can have only one geometry.

In chemistry, hybridization is the idea of combining two atomic orbitals to create a brand-new category of hybridized orbitals. Typically, this mixing creates hybrid orbitals with completely distinct energies, morphologies, etc. One s orbital and three p orbitals combine to generate four sp3 orbitals, each of which has a 25% s character and a 75% p character. This process is known as sp3 hybridization. Anytime an atom is surrounded by four groups of electrons, this kind of hybridization is necessary.

Tetrahedral molecular geometry is the only one that can exist for sp3 hybridized center atoms. The form is tetrahedral if all the bonds are present.

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Answer:

59.46 g

Explanation:

To answer this question, the molecular weight of ammonium sulfate must be computed.  To accomplish this, the weights of the individual elements must be noted.
N=14.01\(\frac{g}{mol}\)

H=1.01\(\frac{g}{mol}\)

S=32.07\(\frac{g}{mol}\)

O=16.00\(\frac{g}{mol}\)

To compute the molecular weight:

\(2[14.01\frac{g}{mol}+4(1.01\frac{g}{mol})]+32.07\frac{g}{mol}+4(16.00\frac{g}{mol})=132.14\frac{g}{mol}\)

To calculate the mass:

\(0.45 mol(\frac{132.14g}{1mol})=59.463g\)

Answer:

See the answer below

Explanation:

A drop of syrup would spread through water because water molecules interact and dissolve the syrup molecules and the molecules of the syrup randomly diffuse into the water from the region of higher concentration to the region of lower concentration till they become evenly distributed in the water.

Once the molecules become evenly distributed into the water, an equilibrium is established and there is no longer net movement.

Answer:

The solutions that showed a color change upon the addition of phenolphthalein are bases. However, the lack of a change in color is NOT sufficient evidence to identify the other items as acids. This would only work if all substances were either acids or bases, which is not the case. Mark needs another indicator that shows a color when it is in an acid solution to support his conclusions.

No reasonable general conclusion can be drawn from Mark's work because there is no consistent pattern in the results.

If we look at the table carefully, we will notice that the table lacks consistency. What color can we definitely expect when a substance is acidic? we can not answer that question from the table.

Sometimes a substance is colorless after adding phenolphthalein and sometimes the substance is pale yellow after adding phenolphthalein and the same inference of acid substance is invoked in each case.

This leads to a lack of pattern and logic in the results therefore no reasonable conclusion can be deduced from the table.

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Answer:

second (S) is the SI unit of time.

Answer:

second

Explanation:

the gap between any two intervals is called time

time can be measured in hour,minute,second

but second is the SI unit of time

Answer:

air     water

Explanation:

Mediums that can have waves

Answer:

B.

Explanation: Because it's at the bottom of the layer so it gets least sun and solar energy.

The specific heat of mercury calculated from her data is 0.13 J/g°C.

Specific heat is a measure of how much energy is required to heat a substance. This is the amount of energy (in joules) required to heat 1 gram of a substance by 1°C. Different substances have different specific heats.

To answer this question, use the heat slaughter formula:

Q =mCΔT

In the question:

Heat energy: Q = 30.1 J

Mass of mercury: m = 12.5 g

T1 = 21.2

T2 = 39.6°C

Temperature:

ΔT = T2 –T1

∆T = 39.6 – 21.2

∆T = 18.4°C

The specific heat of mercury is?

Q =mCΔT

C = Q/mΔT

C = 30.1/12.5 x 18.4

C =30.1/230

C = 0.13 J/g°C

So, the specific heat of mercury is 0.13 J/g°C.

Question:

In the laboratory a student finds that it takes 30.1 Joules to increase the temperature of 12.5 grams of liquid mercury from 21.2 to 39.6 degrees Celsius.

The specific heat of mercury calculated from her data is_____J/g°C.

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The amount of salt in the tank as a function of time is f(t) = 70 + 4t, where f(t) is the amount of salt in the tank after t minutes.

The rate of salt entering the tank is 2 lb/gal x 2 gal/min = <<2*2=4>>4 lb/min, where the concentration of salt is 2 lb/gal. Initially, the tank contains 70 lb of salt and 280 gal of water. When the brine flows into the tank at a constant rate of 2 gal/min, the concentration of salt in the tank remains constant. When the tank is stirred, the salt will be uniformly distributed throughout the mixture. Let’s assume that t is the time in minutes. As a result, the number of minutes that the solution is in the tank will be t. Since the concentration of salt in the tank remains constant, the amount of salt in the tank after t minutes is 70 lb + 4 lb/min × t.

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Answer:

the formula is Cu(OH)2

Mark me as the brainliest

Answer:

Yes.

Explanation:

NH4Cl + H2O = NH4+ + HCl (equation 1). Cl- + H2O = H+ Cl- +H2O (equation 2). The chloride (Cl-) first associates with water ( H2O) to form hydrochloric acid (HCl) and the dissociation of HCl produces hydrogen ions (H+).

The percent yield will be 95.75%

Mass of copper = 0.3295 g

Mass of filter paper + copper (II) oxide = 0.5723

Mass of filter paper only = 0.2568

Mass of copper (II) oxide = 0.5723 - 0.2568 = 0.3155

Percent yield = yield/total x 100%

                      = 0.3155/0.3295 x 100% = 95.75%

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Answer:

C)peer review

Explanation:

Peer review involves the evaluation of scientific research work by other professionals working in the same field. It is one of the stages a manuscript passes through before it is published in any reputable journal.

Peer review is important because it ensures that only high quality and original scientific research is published for the consumption of other professionals in the same field.

Since we will be adding a strong acid, the pH will decrease. Therefore, we will need to subtract 0.07 units from the pH.

\($$p H-0.07-p K_a+\log \frac{\left[\mathrm{CO}_3^{2-}\right]}{\left[\mathrm{HCO}_3^{-} \mid\right.}$$\)

\(\Note \ that \ the \ added \ acid \ will \ react \ with \ $\mathrm{CO}_3^{2-} \cdot \mathrm{HCl}$ \ will \ dissociate \ first.\)

\($$\begin{gathered}\mathrm{HCl}+\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{H}_3 \mathrm{O}^{+}+\mathrm{Cl}^{-} \\\mathrm{CO}_3^{2-}+\mathrm{H}_3 \mathrm{O}^{+} \rightarrow \mathrm{HCO}_3^{-}+\mathrm{H}_2 \mathrm{O}\end{gathered}$$\)

\(As \ observed, \ the\ reaction \ also \ produced \ $\mathrm{HCO}_3^{-}$. Since all $\mathrm{H}_3 \mathrm{O}^{+}$were consumed, $\mathrm{CO}_3^{2-}$ will decrease in concentration by an unknown quantity we will denote as $x$. The same additional $x$ amount of $H C O_3^{-}$will also be produced. Therefore, our working equation will be...\)

\($$p H-0.17-p K_a+\log \frac{\left[\mathrm{CO}_3^{2-} \mid-x\right.}{\left[H C O_3^{-} \mid+x\right.}$$\)

\($$We have all the values of the variables in the equation for $x$ so now solve for $x$.$$\)

\($$\begin{aligned}& p H-0.07-p K_a+\log \frac{\left[\mathrm{CO}_3^{2-}\right]-x}{\left[\mathrm{HCO}_3^{-} \mid+x\right.} \\\log \frac{\left[\mathrm{CO}_3^{2-}\right]-x}{\left[\mathrm{HCO}_3^{-} \mid+x\right.}-p H-0.07-p K_a \\\frac{\left[\mathrm{CO}_3^{2-}\right]-x}{\left[\mathrm{HCO}_3^{-} \mid+x\right.}-10^{p H-0.07-p K_e}\end{aligned}$$\)

\($$Substitute the values first. Then, manipulate the equation.$$\)

\($$\begin{gathered}\frac{0.0165]-x}{[0.0247]+x}-10^{10.15-0.07-10.13} \\\frac{0.0165]-x}{0.0247]+x}-0.562 \\0.0165-x-0562(0.0247+x) \\0.562 x+x-0.0165-0.0139 \\1.562 x-0.0026 \\x-0.00166 \mathrm{M}\end{gathered}$$\)

\($$Therefore, $0.00166 \mathrm{M} \mathrm{HCl}$ should be added. Calculate the mass needed.$$\)

\($$m-0.00166 \frac{\mathrm{mol} \mathrm{HCl}}{L} \times 25.0 \mathrm{~mL} \times \frac{1 \mathrm{~L}}{1000 \mathrm{~mL}} \times \frac{36.46 \mathrm{~g} \mathrm{HCl}}{1 \mathrm{~mol} \mathrm{HCl}}-0.00143 \mathrm{gHCl}$$\)

pH stands for Hydrogen potentials or historically denoting "potential of hydrogen". It refers to the concentration of the hydrogen ions in a solution. It’s a scale used to specify the acidity or basicity of an aqueous solution. Acidic solutions are measured to have lower pH values than basic solutions. This is the indicator of a solution's acidity or alkalinity. On a pH scale, the pH value ranges from 0 to 14.

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Answer:

a. how much So² can be made in moles?

= 0.2 moles

b. how much So² can be made in grams?

= 12.8 grams

c. what is the Excess reactant?

= O²

Explanation:

mass of ZnS= 19.6g

mass of O²= 33.6g

i. start by determining if the equation is balanced (it is)

ii. calculate the molar mass of each reagent

- molar mass of ZnS

= (65) + (32) = 97g/mol

- molar mass of O²

= (16 x 2) = 32g/mol

iii. determine the reactants' number of moles

- no of moles of ZnS = mass of ZnS / molar mass of ZnS

= 19.6 / 97

= 0.2 mol

- no of moles of O² = mass of O² / molar mass of O²

= 33.6 / 32

= 1.05 mol

iv. determine the reactant mole ratio

0.2 moles of ZnS reacted with 1.05 moles of O²

ratio = 1.05 / 0.2 which will approximately be 5

therefore, we can say that there are x5 as many molecules of O² than ZnS

v. determine the reactant ideal ratio

from the equation, 2 moles of ZnS reacted with 3 moles of 0². therefore, the ideal ratio is 2:3, with O² having the greater ratio once again

vi. determine the limiting and excess reactant

we can say from both the mole and ideal ratio that O² is the excess reactant and ZnS is the limiting reactant (answer to the third question)

next phase,

vii. determine the ratio of limiting reactant to the product

from the equation,

2 moles of ZnS produced 2 moles of So²

therefore, mole ratio = 2:2 which is also 1:1

viii. to determine how much So² can be made in moles

= no of moles of limiting reactant x mole ratio of reactant and product

= 0.2 moles of ZnS x 1/1

= 0.2 x 1

= 0.2 moles of So² (answer to the first question)

ix. to determine how much So² can be made in grams

= no of moles of So² produced x molar mass of So²

- molar mass of So²

= 32 + (16 x 2)

= 32 + 32

= 64g/mol

therefore, how much So² produced in grams

= 0.2 x 64

= 12.8g of So² (answer to the second question)

answerer's note: I recently started learning about theoretical yield in school and so this is the result of what I know so far. You're free to make confirmations from others who are more experienced :)

The gas will now be under a new pressure of about 378.06 atm.

The combined gas law, which connects a gas's pressure, volume and temperature, can be used:

(P1V1) (P2V2) (T1)

Where

To begin, we can convert the starting temperature to Kelvin:

T1 = 39.6 + 273.15 = 312.75 K

The resulting temperature can alternatively be converted to Kelvin T2 = 508.1 + 273.15 = 781.25 K.

We can now enter the values we are aware of:

(P2 x 0.14 L)/781.25 K = (760.1 torr x 4.0 L)/312.75 K

P2 = (760.1 torr x 4.0 L x 781.25 K)/(312.75 K x 0.14 L) is the result of simplifying.

P2 = 287684.06 torr

Finally, we may translate torr to atm:

P2 is equal to 287684.06 torr/760 torr/atm.

P2 = 378.06 atm

Therefore, the gas will now be under a new pressure of about 378.06 atm.

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Answer:

im not 2100][dskcmaln,NMCS KHJBXsjk[pl,;maxkcjxnxxxxxxxxxxxxxas'j

Explanation:

mnkc

Answer:

It is a combustion reaction

Explanation:

Answer: a.Oxygen

Explanation:

A chemical equation is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.

A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation are the same.

According to this question, chlorine gas reacts with pottasium iodide to produce iodine and pottasium chloride as follows:

Cl₂ + 2KI → 2KCl + I₂

Therefore, the answers to the questions are as indicated in the main answer part.

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Answer:

5.0X10 -6 M-

Explanation:

The second radiation is less energetic than the former because it has a longer wavelength.

Recall that;

c = λf

c = Speed of light

λ = wavelength

f = Frequency

Now;

λ = c/f = 3 × 10^8 m/s/6.00 x 10^13 s-1

λ = 5  × 10^-6 m

Also;

When f = 5.40 x 10^13 s^-1

λ = c/f = 3 × 10^8 m/s/5.40 x 10^13 s^-1

λ = 5.6 × 10^-6 m

This radiation is less energetic than the former because it has a longer wavelength.

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Answer:

Blue Whale

Explanation:

I hope this helps:)

Answer:

The blue whale!

Explanation:

(a) To get the pH of the media to 5.8, you would add NaOH solution. NaOH is used as a basic solution, and when it is added to a solution, it will increase the pH of the solution.

(b) The molecular weight of BA is 225.3. To prepare a 1M solution, you would have to weigh out 225.3 grams of BA.(c) To convert a 1M solution of BA to mg/mL, you can use the following equation: 1 mole = molecular weight in grams; 1000 millimoles = 1 mole. So, 1 M = 1000 mg/mL. Therefore, a 1M solution of BA is equivalent to 1000 mg/mL .(d) To convert a concentration of 1000 mg/mL .

Therefore, to calculate the weight required for a 5 mM solution, use the following formula :Mass of BA = molarity × volume × molecular weight= 5 × 0.001 × 225.3= 1.1265 grams(f) To convert a concentration of 5 mM to mg/mL, we use the following formula: Concentration (mg/mL) = (Concentration (mM) × Molecular weight) / 1000= (5 × 225.3) / 1000= 1.1265 mg/mL(g)

To convert a concentration of 1.1265 mg/mL to mg/L, we multiply by 1000, so 1.1265 mg/mL = 1126.5 mg/L.(h) Given that the stock solution of BA is 5 mM and the working solution is 0.2 mg/mL.

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The water molecule has a total of 10 protons and 10 electrons (8 from the oxygen atom and 1 from each of the two hydrogen atoms). Since it has the same number of protons and electrons, the water molecule is neutral. The electron cloud model shows where electrons are in a molecule.

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Answer:

[Au] = 0.171 M

Explanation:

For this question, we assume the rock is 100 % gold.

First of all, we determine the moles of gold

67.3 g . 1mol/ 196.97g = 0.342 moles

Molar concentration is defined as the moles of solute, contained in 1L of solution.

Our solution volume is 2L.

M = 0.342 mol / 2L = 0.171

Molar concentration, also called molarity of solution is the most typical unit of concentration.

The lifting force on an airplane's wing  Increases with speed.

The lifting pressure, lifting force, or virtually lift is the sum of all of the forces on a body that forces it to transport perpendicular to the route of flow.

Drag and Thrust are all “mechanical forces.” A mechanical force is generated through the interplay between an item and a fluid (liquid or gas). Weight is a “field force.” A subject's pressure no longer has to be in physical contact with the item to have an impact on the object.

The lift equation states that carry L is identical to the carry coefficient Cl times the density r times half of the velocity V squared instances the wing region A. For given air conditions, form, and inclination of the item, we have to decide a value for Cl to determine the raise.

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The least common multiple of the charges for each combination of elements in the table. Ignoring the plus (+) and minus (−) signs of the charges and just entering the numerals. The table is complete as follows.

                          chlorine(Cl)      oxygen(O)         nitrogen(N)

Lithium(Li)                 1                        2                     3

magnesium(Mg)        2                       1                      3

aluminium(Al)            3                       2                     1

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Answer: the first one is incorrect

Explanation:

Answer: Cr2(SO4)3 its this

Explanation: