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A chemist determines that a substance is composed of 30.4% nitrogen by mass and 69.6% oxygen by mass. The molar mass of the compound is 230.5 g/mol, the molecular formula is NO₂.

We must compute the empirical formula in order to ascertain the compound's chemical composition.

If we have 100 grams of the compound.

This suggests we have:

30.4 g of nitrogen

69.6 g of oxygen

Now, we have to convert the mass of each element to moles.

The molar mass of nitrogen (N) = 14.01 g/mol

the molar mass of oxygen (O)  =  16.00 g/mol.

Number of moles of nitrogen (N):

2.17 mol

Number of moles of oxygen (O):

4.35 mol

The simplest whole-number ratio between the moles of nitrogen and oxygen must now be determined. To calculate the ratio, we divide both numbers by the smaller value.

Moles N / moles O = 2.17 mol / 2.17 mol = 1.00

Moles O / moles O = 4.35 mol / 2.17 mol = 2.00

The ratio is approximately N₁O₂.

We divide the subscripts by their greatest common divisor to obtain the simplest ratio, since we are looking for the empirical formula. The empirical formula is NO₂ since the greatest common divisor in this situation is 1.

The molecular formula of the compound is NO₂.

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Answer:

✔ Labor Relations Specialist

✔ Compensation and Benefits Manager

✔ Human Resources Assistant

✔ Human Resources Manager

B

D

A

C

Answer:

Helps employees and management negotiate:

✔ Labor Relations Specialist or B.)

Oversees payment of employees:

✔ Compensation and Benefits Manager or D.)

Maintains employee records, such as contact information:

✔ Human Resources Assistant or A.)

Oversees the Human Resources department of a company:

✔ Human Resources Manager or C.)

Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Answer: The correct answer is 2 moles.

Explanation:

The molecular formula for Dianabol is C₂₀H₂₈O₂.

Dianabol is one of the anabolic steroids composed of only C, H; and 0 that has been used by some athletes to increase the size and strength of their muscles. They artificially change our nervous system and tricks our brain to grow more indirectly. A 14.765 sample of Dlanabol is burned and 43.257 CO2 and 12.395 H₂O are formed second experiment, the molecular mass of Dianabol is found to be 300.44 g/mol. From here we can calculate that the molecular formula for Dianabol is C₂₀H₂₈O₂.

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The metal X has an approximate molar mass of 42.36 g/mol and the metal is most likely calcium.

The molar mass of the metal carbonate XCO₃ and identify the metal X, we need to calculate the number of moles of XCO₃ and CO₂ using the given masses and molar masses.

The molar mass of CO₂ (carbon dioxide) is 12.011 g/mol (for carbon) + 2 * 15.999 g/mol (for oxygen) = 44.01 g/mol.

The number of moles of CO₂ can be calculated using the formula:

moles of CO₂ = mass of CO₂ / molar mass of CO₂

moles of CO₂ = 0.855 g / 44.01 g/mol

moles of CO₂ ≈ 0.01944 mol

Since the reaction stoichiometry is 1:1 between XCO₃ and CO₂, the number of moles of XCO₃ is also approximately 0.01944 mol.

molar mass of XCO₃ = mass of XCO₃ / moles of XCO₃

molar mass of XCO₃ = 2.012 g / 0.01944 mol

molar mass of XCO₃ ≈ 103.38 g/mol

The molar mass of XCO₃ is approximately 103.38 g/mol.

To determine the metal X:

molar mass of X = molar mass of XCO3 - molar mass of CO3

molar mass of X = 103.38 g/mol - (12.011 g/mol + 3 * 15.999 g/mol)

molar mass of X ≈ 42.36 g/mol

Metal X is most likely Calcium that has a molar mass of 40 g/mol

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Unit' is the word used to describe how something is measured. When researching a question in science, we collect data, interpret it, and share the results with other scientists. A common measurement system allows us to make direct comparisons instead of having to know things like how much a certain animal weighs.

The relative atomic mass of atom X is 9.

The relative atomic mass of an element is the average mass of its atoms relative to 1/12th the mass of a carbon-12 atom.

Given that atom X is 9 times heavier than 1/12th the mass of a carbon-12 atom, we can calculate the relative atomic mass of X as follows:

Relative atomic mass of X = (9 × 1/12) × relative atomic mass of carbon-12

The relative atomic mass of carbon-12 is defined as exactly 12. Therefore, we have:

Relative atomic mass of X = (9 × 1/12) × 12

= 9

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Answer: if this is true or false, then this is false, something that is cold has slow moving particles, fast moving ones generate heat which will make it warm, this object has potential energy not kinetic.

Answer:

1. C

2. D

Explanation:

Explanation:

hybridization refers to the process of mixing atomic orbitals in a way that creates new hybrid orbitals. This is commonly observed in organic chemistry, where hybridization is used to explain the shapes and bonding properties of molecules.

The hybridization of atomic orbitals occurs when atoms bond to form molecules. In the hybridization process, the valence electrons of an atom are rearranged and redistributed in order to form new orbitals with different shapes and energies. This can result in stronger and more stable bonding between atoms.

The most common types of hybridization are sp, sp2, and sp3, which involve the mixing of s and p orbitals. For example, in the sp3 hybridization of carbon, the 2s orbital and three 2p orbitals are combined to form four sp3 hybrid orbitals, which are arranged in a tetrahedral shape.

The effects of hybridization in chemistry include changes in the bond angles, bond lengths, and overall shape of molecules. This can affect the reactivity and chemical properties of the molecule, such as its acidity or basicity.

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li

To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.

Let's analyze the given representations:

36Li:

This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.

613C:

This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.

3063Cu:

This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.

1530P:

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.

Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.

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we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.

The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.

In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.

The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.

On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.

In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.

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Answer;

Explanation:

Here, we want to select the option that is not true from the given set of options

We take a look at each of the statements as follows:

a) This is true.

The alpha helix is a spiral arrangement in which the amino acid chains are arranged. It is also associated with secondary structure

b) This is false

Since a protein can be a single unit. This means that not all are associated with a quarternary level

c) This is ture

d) This is true

Table salt does not melt on the stove, it dissolves in water and does not conduct electricity.

There are several substances listed in the table Epsom salt is another one of these substances. It does not melt on a stove, it dissolves in water and also conducts electricity.

Finally, potassium chloride does not melt on the stove, it dissolves in water and it does conduct electricity. These are the experiences one can have with these common substances.

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Answer:

The moon will be positioned so that the earth is between the moon and the sun

A solution is a homogeneous mixture of a solute and a solvent. Both can be solid, liquid, or gas. Solutions exist for every possible phase of the solute and the solvent.

A homogeneous mixture is a mixture in which the composition is uniform throughout the mixture. Remember, solutions are homogeneous mixtures.

You can find many solutions in your daily life.

For example, solutions are salt and water, rubbing alcohol, and sugar dissolved in water.

Let's take salt and water.

Solute here is the salt and the water is the solvent. The amount of solvent is higher than solute in a solution.

When you look closely, upon mixing salt with water, you can't see the salt particles anymore, making this a homogeneous mixture. That is why the mixture of salt and water is a solution.

Answer:

They are in the same group on the periodic table indicating that they have the same number of valence electrons.

Explanation:

The exit gas stream average molecular weight is 28.97 g/mol, and there will be 3.0 kg of leftover Phenanthrene in the reactor.

The balanced combustion equation for Phenanthrene is:

C₁₄H₁₀ + 21O₂ → 14CO₂ + 5H₂O

From the equation, we can see that 21 moles of oxygen are needed to combust 1 mole of Phenanthrene. Thus, to burn 10 kg of Phenanthrene, we need:

and

However, the supplied air is 30% less than the requirement, which means only 70% of the required O₂ will be supplied. Therefore, the actual amount of O₂ supplied will be:

Assuming the air is mostly nitrogen, we can calculate the exit gas stream average molecular weight using the following formula:

where 0.79 and 0.21 are the mole fractions of nitrogen and oxygen in air, respectively, and 28.01 and 32 are the molecular weights of nitrogen and oxygen, respectively.

Finally, we can calculate the amount of leftover Phenanthrene in the reactor:

However, this amount is negligible due to the large scale of the reaction. Therefore, we can round it off to:

Leftover Phenanthrene = 3.0 kg

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The conjugate base of the specie HS^- is S^-

We know that form the Bronsted Lowry perspective of the acid and the base, the acid is the substance that can be able to give out a proton while the base is the kind of substance that can be able to accept a proton.

We can see here that the conjugate base is the specie that can be obtained by the loss of a proton from the HS^- as such we would have it as S^-.

Hence, we can see that the base that is the conjugate base in this sense is S^-.

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Answer:

\(Molarity\,\,of\,\,the\,\,solution\,\,is\,\,S=0.039M\)

Explanation:

\(W=2.18 g\\M=322g\\V=175mL=0.175L\\\\S=\frac{W}{MV} \\=>S=\frac{2.18}{322*0.175} \\So,S=0.039M\)

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The molarity of the NiSO₄ solution made by dissolving 38.81 grams of nickel (ii) sulfate, NiSO₄, in enough water to make 0.467 liters of solution is 0.535 M

First, we shall obtain the mole of 38.81 grams of nickel (ii) sulfate, NiSO₄. Details below:

Mole of NiSO₄ = mass / molar mass

= 38.81 / 154.75

= 0.25 mole

Now, we shall determine the molarity of the solution. Details below:

Molarity of solution = mole / volume

= 0.25 / 0.467

= 0.535 M

Thus, the molarity of the solution is 0.535 M

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Answer:  Newton's first law is often called the law of inertia

Explanation:

Answer:

x = 150 dm

Explanation:

10 cm = 1 dm

100 cm² = 1 dm²

15,000 cm² = 150 dm²

Answer:

csc = (60)

cos = (390)

−4 = cot (−45)

Explanation:

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