HELPPP!! NEEED ASAPPPP

What number could be added to the data set so that the mean, median, and mode are all the same?

Data set: 108,127,130,138,138,140,150.
Median: 138
Mode: 138
HELP ME PLSS

Answer:

5xy/27

Step-by-step explanation:

The product of the two numbers x and y = xy

Five times the product of the two numbers x and y = 5xy

then,

divided by a third number 27 = 5xy/27

The expression will be : 5xy/27

Answer:

The constant of variation 'k' is NOT constant.

Therefore, we conclude that Taylor did not charge a constant rate. The rates are not equal because his rate changed.

Step-by-step explanation:

Given the table

Number of Lawns         1           2            3              4

Amount Earned ($)      16         32          54            72

We know that when y varies directly with x, we get the equation

y ∝ x

y = kx

k = y/x

where 'k' is called the constant of proportionality.

In our case, the 'Amount earned ($) ' is represented by 'y', and the 'Number of Lawns' is represented by 'x'.

Let us check the constant of proportionality using the equation

k = y/x

k = 16/1 = 16

k = 32/2 = 16

k = 54/3 = 18

k = 72/4 = 18

It is clear that that the constant of variation 'k' is NOT constant.

Therefore, we conclude that Taylor did not charge a constant rate. The rates are not equal because his rate changed.

Answer:

82 mm^2

Step-by-step explanation:

you would have to find the area for 2 squares. The first is 8 x 9, so the area of that would be 72. The second square is 5 x 2, which is ten. Add those together to get 82

Answer:

80 lemons

Step-by-step explanation:

Let x represent the amount of lemons that were on the tree.

We can use this to set up an equation:

\(40\%x=32\)

Note that percentages can also be written as that number over 100.

\(\frac{40}{100}x=32\)

Simplify the fraction.

\(\frac{2}{5}x=32\)

Multiply both sides by 5

\(2x=160\)

Divide both sides by 2

\(x=80\)

There were 80 lemons on the tree before he picked the lemons.

The probability that there are exactly two power failures in a particular day is approximately 0.036. So, the answer is 0.036.

The number of power failures in a day can be modeled by a Poisson distribution with mean λ = u = 0.210.

The probability of having exactly k power failures in a day is given by the Poisson probability mass function:

P(k) = (e\(^(\)-λ) * λ\(^k\)) / k!

So, for k = 2, we have:

P(2) = (e\(^(-0.210)\)* \(0.210^2\)) / 2!

≈ 0.036

Therefore, the probability that there are exactly two power failures in a particular day is approximately 0.036. So, the answer is 0.036.

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Answer:

y = -1/2x + 5

Step-by-step explanation:

Find slope:

change in y/change in x

(2-3)/(6-4)

-1/2 = m

Use point-slope form:

y - y1 = m(x - x1)

Where (x1, y1) is a point on the line, let's use (4,3)

y - 3 = -1/2(x - 4)

Point-intercept form:

Expand y - 3 = -1/2(x - 4) to get point-slope form:

y = -1/2x + 5

Hope this helps!! :)

Answer:

A

Step-by-step explanation:

(8x + 4) = (10x-6)

If you solve this you find x = 5, plug that into one and you get 44 degrees

Answer:

$0.20/lb

Step-by-step explanation:

2.99/15 = 199333

.20/lb

The solutions to the quadratic equation f(x) = x² + 10x - 1 are x = -5 + √26 and x = -5 - √26

To solve the quadratic equation f(x) = x² + 10x - 1

we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

For the given equation, a = 1, b = 10, and c = -1.

Substituting these values into the quadratic formula:

x = (-(10) ± √((10)² - 4(1)(-1))) / (2(1))

= (-10 ± √(100 + 4)) / 2

= (-10 ± √104) / 2

Simplifying further:

x = (-10 ± 2√26) / 2

= -5 ± √26

Therefore, the solutions to the quadratic equation f(x) = x² + 10x - 1 are:

x = -5 + √26 and x = -5 - √26

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Answer:

In 25 minutes, the monthly phone charges of both companies will be the same.

Step-by-step explanation:

If we allow m to represent the number of minutes, we can create two equations for C, the total cost of phone charges from both companies:

Phoenix equation:  C = 0.5m + 30

Nuphone equation: C - 0.10m + 40

Now, we can set the two equations equal to each other.  Solving for m will show us how many minutes must Abby use for the total cost at both companies to be the same:

0.5m + 30 = 0.10m + 40

Step 1:  Subtract 30 from both sides:

(0.5m + 30 = 0.10m + 40) - 30

0.5m = 0.10m + 10

Step 2:  Subtract 0.10m from both sides:

(0.5m = 0.10m + 10) - 0.10m

0.4m = 10

Step 3:  Divide both sides by 0.4 to solve for m (the number of minutes it takes for the total cost of both companies to be the same)

(0.4m = 10) / 0.4

m = 25

Thus, Abby would need to use 25 minutes for the total cost at both companies to be the same.

Optional Step 4: Check the validity of the answer by plugging in 25 for m in both equations and seeing if we get the same answer:

Checking m = 25 with Phoenix equation:

C = 0.5(25) + 30

C = 12.5 + 30

C = 42.5

Checking m = 25 with Nuphone equation:

C = 0.10(25) + 40

C = 2.5 + 40

C = 42.5

Thus, m = 25 is the correct answer.

Answer:

  (x, y) = (5, -4)

Step-by-step explanation:

The second equation gives you an expression for x that can be substituted into the first equation.

  (2y +13) -3y = 17 . . substitute for x in the first equation

  -y = 4 . . . . . . . . . . . subtract 13 and simplify

  y = -4

  x = 2(-4) +13 = 5 . . . use the second equation to find the value of x

The solution is (x, y) = (5, -4).

_____

Additional comment

When faced with a system of linear equations, the first step is to look at them and observe where the variable terms are, and any relationships between coefficients. Several options are generally open to you for solving the equations. Methods generally taught first are ...

Substitution is handy when one of the variables or variable terms can be written (easily) in terms of the other variable. Elimination is handy when some simple multiple of one of the equations can be added to the other equation to cancel one of the variable terms (eliminate it).

Other available methods include matrix methods, Cramer's rule, and graphing. Working knowledge of all of these methods will help you identify the one that will be easiest to use in any given situation.

The availability of calculators able to use these methods greatly simplifies the task of finding a solution. It is simply a matter of entering the equations in the appropriate form.

One of my favorites is the graphing calculator, which only requires you type in the given equations and click on the solution point to find its coordinates.

Mathematical modeling, in which equations are used to model the relationships between variables, is a technique used in various fields and disciplines. Some areas where mathematical modeling is commonly applied include:

Physics: Mathematical models are used to describe and predict physical phenomena, such as the motion of objects, the behavior of fluids, and the interactions of particles.

Engineering: Mathematical models are employed in engineering to design and analyze systems, such as electrical circuits, mechanical structures, and chemical processes. These models help engineers optimize performance, improve efficiency, and ensure safety.

Economics: Mathematical models are used in economics to understand and predict economic behavior, market dynamics, and the effects of various factors on economic systems. Models such as supply and demand curves, production functions, and macroeconomic models help economists study and analyze economic phenomena.

Biology: Mathematical models are used in biology to describe biological processes and systems, including population dynamics, biochemical reactions, ecological interactions, and genetic inheritance. These models help biologists understand complex biological phenomena and make predictions about their behavior.

Computer Science: Mathematical models are utilized in computer science to analyze algorithms, design computer networks, and optimize system performance. Models such as graph theory, automata theory, and computational complexity theory provide frameworks for understanding and solving computational problems.

Finance: Mathematical models play a crucial role in finance for pricing options, managing risks, and predicting market behavior. Models like the Black-Scholes model and portfolio optimization models help financial analysts make informed investment decisions.

These are just a few examples of the many fields where mathematical modeling is used.

The power of mathematical modeling lies in its ability to represent real-world phenomena in a precise and quantitative manner, allowing for analysis, prediction, and optimization.

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The weekly earning for each year is $135, $520, $2040, $8080

Numbers, symbols and operators grouped together that show the value of something.

Given that, a tutor is starting a business. In the first year, they start with 5 clients and charge $10 per week for an hour of tutoring with each client. For each year following, they double the number of clients and the number of hours each week. Each new client will be charged 150% of the charges of the clients from the previous year

The weekly earnings for 1st year are,

q = $10, p = $25, x = 5, (px+q) = $135

The weekly earnings for 2nd year are,

q = $20, p = $50, x = 10, (px+q) = $520

The weekly earnings for 3rd year are,

q = $40, p = $100, x = 20, (px+q) = $2040

The weekly earnings for 4th year are,

q = $80, p = $200, x = 40, (px+q) = $8080

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Answer: B

Step-by-step explanation: A whole number is a number that is not a decimal or a fraction and is over 0.

The equation representing the graph as shown in the figure is y =

- 5.01x³ + 36.02x

The degree of a cubic polynomial is three.

Given is the general cubic equation as -

ax³ + bx² + cx + d

Now, the graph shows that the equation of this cubic equation passing through 3 points as -

(- 6, 0) , (2, 32) , (6, 0)

This means that these coordinates will satisfy the equation ax³ + bx² + cx + d = y.

Therefore -

For x = - 6 :

a(-6)³ + b(-6)² - 6c + 0 = 0

- 216a + 36b - 6c = 0            .. [1]

For x = 2 :

8a + 4b + 2c + 0 = 32          .. [2]

For x = 6 :

a(6)³ + b(6)² - 6c + 0 = 0

216a + 36b + 6c  + 0 = 0        .. [3]

Adding Eq[1] and Eq[3], we get -

- 216a + 36b - 6c + 216a + 36b + 6c = 0

72b = 0

b = 0

Then equation [2] will become -

8a + 2c = 32

4a + c = 16                 .. [4]

Subtracting Eq[1] and Eq[3], we get -

216a + 36b + 6c - (- 216a + 36b - 6c) = 0

216a + 36b + 6c + 216a - 36b + 6c = 0

432a + 12c = 0              .. [5]

Multiply [4] by 12, we get -

48a + 12c = 1922     .. [6]

Subtracting Eq[6] and Eq[5], we get -

432a + 12c - 48a - 12c = - 1922

384a = - 1922

a = - 5.01

Then -

4 x - 5.01 + c = 16

c = 16 + 20.02

c = 36.02

So -

[a] = - 5.01

[b] = 0

[c] = 36.02

[d] = 0

Therefore, the equation representing the graph as shown in the figure is y = - 5.01x³ + 36.02x

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Answer:

Step-by-step explanation:

5%×g= 5g/100

g-5g/100

Answer:

Cost of first pair shoe = a = $23

Cost of second pair shoe = b = $46

Cost of third pair shoe = c = $28

Step-by-step explanation:

Let

Cost of first pair shoe = a

Cost of second pair shoe = b

Cost of third pair shoe = c

The first pair of shoes were not too expensive, but the second pair was twice as much as the first pair.

b = 2a......... Equation 1

The third pair of shoes were $5 more than the first pair.

c = a + 5...... Equation 2

She paid with a $100 bill and got $3 in change.

a + b + c = $100 - $3

a + b + c = 97........... Equation 3

Substitute 2a for b and a + 5 for c in Equation 3

a + 2a + a + 5 = 97

4a = 97 - 5

4a = 92

a = 92/4

a =$23

The cost of the first pair of shoe = $23

b = 2a......... Equation 1

b = 2($23)

b = $46

The cost of the second pair of shoe = $46

c = a + 5...... Equation 2

c = $23 +$5

c = $28

The cost of the third pair of shoe = $28

(a) The firm's output supply function is given by q = (p + 199) / 2.

(b) The market-equilibrium price is $32.56, and the equilibrium number of firms is 10.

(c) Each firm sells 70 computers in the long run.

(39 - 0.009q) = (2q - 2) / q

Simplifying the equation, we find:

q = (p + 199) / 2

This represents the firm's output supply function.

p = 39 - 0.009((p + 199) / 2)

Simplifying and solving for p, we get:

p ≈ $32.56

Substituting this price back into the output supply function, we find:

q = (32.56 + 199) / 2 ≈ 115.78

Given that each firm produces 70 computers in the long run, we can calculate the equilibrium number of firms:

Number of firms = q / 70 ≈ 10

70 * 10 = 700

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2 hours will pass before they meet.

"Information available from the question"

In the question:

Aaron starts riding a bike at a rate of 3 mi/h on a road toward a store 20 mi away.

Zhang leaves the store when Aaron starts riding his bike, and he rides his bike toward Aaron along the same road at 2 mi/h.

Now, According to the question:

Total distance = 20mi

Aaron starts riding a bike at a rate of  = 3mi/h

Zhang rides his bike toward Aaron along the same road at  = 2mi/h

Let y be the number of hours for them to meet.

The expression is given as

3y + 2y = 20

solving for y, we have

5y = 20

y = 20/5

y = 4hrs

Therefore, 2 hours will pass before they meet.

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Given what we know, we can confirm that the perimeter of the image is  9 units.

Therefore, given that  \(15units * \frac{3}{5} = 9 units\), we can confirm that the perimeter of the image is 9 units.

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a) The points\((x, y) = (-1, 2)\) are the equilibrium solutions

b) The solutions are decreasing since \((y-2)\) is negative and \((x+1)\) is positive.

c) The solution curves concave up if y'' is positive, and concave down if y'' is negative.

a)  Either \(y = 2 or x = -1\)is required for this equation to be true. Therefore, the points\((x, y) = (-1, 2)\) are the equilibrium solutions.

We must set \(y = 0\) and solve for y in order to find the equilibrium solutions. So:

\((y-2)(x+1) = 0\)

b) We need to look at the sign of y' in various areas of the xy-plane to figure out where the solutions are rising or decreasing. The solutions are growing if y' is positive; they are shrinking if y' is negative.

Since \((y-2)\) and \((x+1)\)are both negative, y' is positive and the solutions are increasing if\(x -1\)and \(y 2.\) When \(x > -1\)and \(y 2, (y-2)\) becomes negative and (x+1) becomes positive, indicating that y' is negative and the solutions are getting smaller. If \(y > 2\), then y' is positive and the solutions are getting bigger because \((y-2)\) and \((x+1)\) are both positive. for x is greater than \(-1\) and y is greater than \(2\), the solutions are decreasing since \((y-2)\) is negative and \((x+1)\) is positive. This is the case for \(y 2.\)

The expression for y' shows that when \((y-2)\) and \((x+1)\)have the same sign, and when they have the opposite sign, respectively, it will be positive.

c) We need to look at the sign of y'' in various areas of the xy-plane to figure out where the solution curves are concave up-concave down. By taking the derivative of y', we may find y'':

\(y'' = (y-2) - 2(x+1)\)

The solution curves concave up if y'' is positive, and concave down if y'' is negative.

We may deduce that y'' is positive when\(y > 2 + 2(x+1)\) and negative when \(y 2 + 2(x+1)\) from the expression for y''. As a result, when the solution curves are above the line\(y = 2 + 2(x+1)\), they are concave up, and when they are below it, they are concave down.

a) \(y > 2 + 2(x+1)\)

b) \(y 2 + 2(x+1)\)

c)\(y = 2 + 2(x+1)\)

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Complete Question:

Let y' =(y-2)(x+1). a) Determine all equilibrium solutions. b) Determine the region in the xy - plane where the solutions are increasing, and where the solutions are decreasing. c) Determine the regions in the xy - plane where the solution curves are concave up, and determine those regions where they are concave down. Solve the following differential equations.

a) dy + 2xy2 = 0 doc ? =

b) x - y = 2x?y, y(i)=1 y *1) b dy dx

Answer:

Equation of line is given as y = mx + c, where m is the slope and c is the y-intercept.

Since the line has a slope of -3, equation of line is y = -3x + c.

Substitute (1,-3) into the equation to find c.

-3 = -3(1) + c

c = 0

Since y-intercept is 0, equation of line is y = -3x.

Equation of the line which passes through the point (1,-3) and the slope of the line is -3 is equal to y = -3x .

As given in the question,

Line passes through the point ( 1, -3) and the slope of the line is equal to -3.

Standard equation of the line passes through the point ( x₁ , y₁) and slope m is given by :

( y -y₁ ) / ( x - x₁ ) = m

Substitute the given value of the point ( x₁ , y₁)  = (1, -3 ) and slope m = -3 in the standard form we get,

( y -(-3) ) / ( x - 1) = -3

⇒ ( y +3 ) = -3 ( x -1)

⇒ y = -3x + 3 - 3

⇒ y = -3x

Therefore, equation of the line which passes through the point (1,-3) and the slope of the line is -3 is equal to y = -3x.

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Answer:

-700 final score

Step-by-step explanation:

-300 - 400 = -700

Subtracting a negative by a negative is ALWAYS another negative.

Subtracting a negative number is the same as adding a positive number — that is, go up on the number line. This rule works regardless of whether you start with a positive number or a negative number.

Using a regression equation, the predicted carbon dioxide emission amount can be determined for various values of GDP. The predictions will be provided in their original units without rounding.

Regression analysis allows us to establish a mathematical relationship between two or more variables. In this case, we have a regression equation that can be used to predict the carbon dioxide emission amount based on GDP. However, it's important to note that the specific regression equation is not provided, so we'll assume it is a valid equation for this analysis.

To make predictions, we substitute different values of GDP into the regression equation and calculate the corresponding predicted carbon dioxide emission amount. The predictions will be presented without any rounding, maintaining the precision of the calculation.

Please provide the specific values of GDP for which you would like the carbon dioxide emission predictions, and the corresponding regression equation. With that information, I will be able to generate the predictions accurately.

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Answer:

The answer is C

Answer:

c = 13.50g + 55p

Step-by-step explanation:

You multiply the cost of the item by the amount you bought.

An equation for the total cost of video games and controllers is c = 13.50g + 55p.

Given that, Thomas went to the store to buy video games for $13.50 each and controllers that cost $55 each.

We need to write an equation where c represents the total cost, g is the number of games he bought, and p is the number of controllers he bought.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Now, the total cost of video games=13.50g

The total cost of controllers=55p

Total cost =c = 13.50g + 55p

Therefore, an equation for the total cost of video games and controllers is c = 13.50g + 55p.

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Total 1,512,000 "words" can be formed by rearranging INQUISITIVE so that U does not immediately follow Q.

In the given question, we have to find how many "words" can be formed by rearranging INQUISITIVE so that U does not immediately follow Q.

The given word is INQUISITIVE.

The total alphabets in the word INQUISITIVE is 11.

Let us first count the words without U and then insert U wherever applicable.

Now without U we have total 10 alphabets and the alphabet I is repeated by 4 times.

So permutations is 10!/4! = 151,200

Now we need to put U, we can see its 11 alphabets but U should not follow Q so it becomes 10 alphabets.

Hence, Total number of words = 151,200*10

Total number of words = 1,512,000

Hence, 1,512,000 "words" can be formed by rearranging INQUISITIVE so that U does not immediately follow Q.

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Answer: 95.15

Step-by-step explanation:

To find the answer, you have to multiply the original cost by the percent subtracted from 100. For example, 380.60 x .25=95.15

(I got the .25 from subtracting 100-75, and the 75 is the percent)

Answer: 95.15

Step-by-step explanation:

Multiply 380.60 by .75 and you get 285.45 subtract 380.60 and 285.45 and you should get 95.15

To write the expression \(6 \frac{7}{12}\)  in radical form.

To express the radical form in simplest it just means simplifying the radical so that there are further no more square root, cube root etc.

Use the rule:

\(a\frac{x}{y}\) = \(\sqrt[y]{a^{2} }\)

Apply this rule on the the given expression:

\(6\frac{7}{12} = \sqrt[12]{6^{7} }\)

Therefore, the expression in radical form is \(\sqrt[12]{6^{7} }\)