Answer:
s = 2 1/3 + 1/2
t = 2/3 + 3/2
We have to find the sum of both s and t.
2 1/3 + 1/2 = 2 2/6 + 3/6 = 2 5/6
2/3 + 3/2 = 4/6 + 9/6 = 13/6 = 2 1/6
If we look at the number lines, we can see that c matches with both points.
2x+7x=77
5x+7y=115
solve for x & y that makes both expressions true.
The solution that makes both expressions true is x = 8.55556 and y = 10.31746.
To solve for x and y, we need to use a system of equations involves finding the values of x and y that satisfy both equations simultaneously.
We can start by using the first equation to solve for x:
2x + 7x = 77
Combining like terms:
9x = 77
Dividing both sides by 9:
x = 8.55556 (rounded to six decimal places)
Now that we know the value of x we can use either equation to solve for y. Let's use the second equation:
5x + 7y = 115
Substituting x = 8.55556:
5(8.55556) + 7y = 115
Simplifying:
42.7778 + 7y = 115
Subtracting 42.7778 from both sides:
7y = 72.2222
Dividing both sides by 7:
y = 10.31746 (rounded to six decimal places)
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Please help- question below....thank you
If the country doubled its initial food supply and maintained a constant rate of increase in the supply adequate for an additional 0.5 million people per year, would shortages still occur? In approximately which year?
Then shortages would still occur after doubling the food supply and maintaining a constant rate of increase in the supply adequate for an additional 0.5 million people per year.
The year when the food supply would be adequate for a population of P million people is approximately P + 1 years from the present year.
To determine if shortages would still occur after the country doubled its initial food supply and maintained a constant rate of increase in the supply adequate for an additional 0.5 million people per year, we need to compare the rate of increase in the food supply to the rate of population growth.
Assuming that the initial food supply was adequate for a certain number of people, let's say N, then doubling the food supply would make it adequate for 2N people.
If the constant rate of increase in the food supply is adequate for an additional 0.5 million people per year, then after n years, the food supply would be adequate for N + 0.5n million people.
If we assume that the population growth rate is constant at 0.5 million people per year, then after n years, the population would increase by 0.5n million people.
To determine if shortages would still occur, we need to compare the rate of increase in the food supply to the rate of population growth.
If the rate of increase in the food supply is greater than or equal to the rate of population growth, then shortages would not occur.
We need to solve the following inequality:
N + 0.5n ≤ 2N + 0.5n
Simplifying this inequality, we get:
N ≤ 0.5n
This means that if the initial food supply was adequate for less than or equal to 0.5 million people.
Assuming that the initial food supply was adequate for more than 0.5 million people, then shortages would not occur.
We can solve for the approximate year when the food supply would be adequate for a population of P million people:
P = N + 0.5n
n = 2(P - N)
Substituting the values of N and P, we get:
n = 2(P - N)
n = 2(0.5 + 0.5P) - N
n = P + 1
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3x^2+7-6+1+3+7 add , sub, mult, what is the answer
Answer:
If just combining like terms: 3x^2 + 12
If solving for x: 2i, -2i
Step-by-step explanation: Combine like terms, so 3x^2 + 12 = 0; move the 12 to the other side by subtracting (3x^2 = -12), then divide both sides by 3, which gives x^2 = -4. Then get the square root of both sides to cancel out the power on the x. Since -4 is negative, use imaginary numbers, which makes x = 2i and x = -2i
Suppose that there is a black urn containing nine black balls and three yellow balls and there is a yellow urn containing six black balls and six yellow balls. An experiment consists of selecting at random a ball from the black urn and then (without replacing the first ball) selecting at random a ball from the urn having the color of the first ball.
Required:
a. Construct a tree diagram showing the probabilities associated with this problem. Write a probability on each branch (6 branches).
b. Find the probability that the second ball is yellow.
Answer:
See Annex for tree diagram and all probabilities
b) P(2y) = 0,329
Step-by-step explanation:
a) Attached
b) Probability of the second ball is yellow P(2y) is equal to the probability of the second ball is yellow given that the first one is black ( 0,204 ) plus the probability f the second ball is yellow given that the first one is yellow ( 0,125)
P(2y) = 0,204 + 0,125
P(2y) = 0,329
Please anyone help me with my math!
Answer:
8. 10
9. 33
10. which number is greatest? 35
11. which number is least? 9
12. 35, 21, 16, 9
13. 17, 20, 23, 26, 29, 32
14. 2 less than 25 is 23
15. 21 is 3 more than 18
16. 24 = 2 tens and 4 ones
17. 18 = 1 ten and 8 ones
Step-by-step explanation:
50 Points! Solve the equation or inequality. Please show as much work as possible. Photo attached. Thank you!
The equation 5ʷ ⁺ ³ = 17 when solved for w is approximately w = 0.41
Solving the equations or inequalities for wFrom the question, we have the following parameters that can be used in our computation:
5ʷ ⁺ ³ = 17
Take the logarithm of both sides of the equation
So, we have
w + 3 = ln(17)/ln(3)
Evaluate the quotient on the left side of the equation
This gives
w + 3 = 2.59
So, we have
-3 + w + 3 = 2.59 - 3
Evaluate
w = 0.41
Hence, the equation when solved for w is approximately w = 0.41
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In a survey of 259 professional athletes, it was found that 110 of them owned a convertible, 91 of
them owned a giant screen TV, and 120 owned a sporting goods store. 15 owned a convertible and a
store, 43 owned a TV and a store, and 44 owned a covertible and a TV. 9 owned all three items.
1. How many athletes did not own any of the three items?
2. How many owned a covertible and a TV, but not a store?
3. How many athletes owned a convertible or a TV?
4. How many athletes owned exactly one type of item in the survey?
5. How many athletes owned at least one type of item in the survey?
6. How many owned a TV or a store, but not a convertible?
1. Number of athletes did not own any of the three items = 259 - 228
= 31.
2. Number of athletes own a convertible and a TV but not a store = 44 - 9
= 35.
3. Number of athletes own a convertible or a TV = 110 + 91 - 44
= 157.
4. Number of athletes owned exactly one type of item = 60 + 13 + 71 = 144.
5. Number of athletes owned at least one type of item = 259 - 31
= 228
6. Number of athletes own a TV or a store, but not a convertible = 13 + 34 +71
= 118.
The number of athletes did not own any of the three items need to subtract the number of athletes who own at least one item from the total number of athletes surveyed.
Total number of athletes surveyed = 259
Number of athletes own at least one item = 110 + 91 + 120 - 15 - 43 - 44 + 9 = 228
Number of athletes who did not own any of the three items = 259 - 228 = 31.
The number of athletes who owned a convertible and a TV but not a store need to subtract the number of athletes who own all three items from the number of athletes who own a convertible and a TV.
Number of athletes who own a convertible and a TV = 44
Number of athletes who own all three items = 9
Number of athletes who own a convertible and a TV but not a store = 44 - 9 = 35
The number of athletes who owned a convertible, or a TV need to add the number of athletes who own a convertible to the number of athletes who own a TV and then subtract the number of athletes own both a convertible and a TV.
Number of athletes who own a convertible or a TV = 110 + 91 - 44
= 157.
The number of athletes owned exactly one type of item need to add up the number of athletes who own a convertible only the number of athletes own a TV only and the number of athletes who own a store only.
Number of athletes own a convertible only = 110 - 15 - 9 = 86
Number of athletes own a TV only = 91 - 44 - 9 = 38
Number of athletes own a store only = 120 - 15 - 43 - 9 = 53
Number of athletes owned exactly one type of item = 60 + 13 + 71 = 144.
The number of athletes who owned at least one type of item can use the result from part (1).
Number of athletes who owned at least one type of item = 259 - 31
= 228
The number of athletes who owned a TV or a store but not a convertible need to subtract the number of athletes who own all three items, and the number of athletes own a convertible and a TV from the number of athletes own a TV or a store.
Number of athletes own a TV or a store = 91 + 120 - 43 - 9 = 159
Number of athletes own a TV or a store not a convertible = 13 + 34 +71
= 118.
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These triangles
are congruent by
the triangle
congruence
postulate [? ].
A. ASA
B. Neither, they are not congruent
C. AAS
Since in the two triangles,
2 angles and the side between them is given and equal, the triangles are congruent using the Criteria ASA.
Option A is the correct answer.
Help ASAP
When solving this equation, what operation happens first?
2x+11=27
-Subtract 11 from both sides.
-Multiply both sides by 2.
-Add 11 to both sides.
-Divide both sides by 2
Answer:
-Subtract 11 from both sides.
given the following function, what is the instantaneous rate of change at X=2?y=1/3x^3+2x^2-4x+1
To get the instantaneous rate of change, first we need to differentiate the function with respect to x:
\(\begin{gathered} \frac{dy}{dx}\text{ = }\frac{1}{3}(3x^{3-1})+2(2x^{2-1})-4(1x^{1-1})\text{ + 0} \\ \frac{\mathrm{d}y}{dx}\text{ = }\frac{1}{3}(3x^2)+2(2x^1)-4(1x^0)\text{ + 0} \\ \frac{\mathrm{d}y}{dx}\text{ = }x^2+2(2x^{})-4(1)\text{ + 0} \\ \frac{\mathrm{d}y}{dx}\text{ = }x^2+4x-4\text{ + 0} \\ \frac{\mathrm{d}y}{dx}\text{ = }x^2+4x-4 \end{gathered}\)At x = 2
\(\begin{gathered} \text{After differentiation, we will substitute 2 for x in the derivative:} \\ \frac{dy}{dx}=(2)^2\text{ + 4(2) - 4} \\ \frac{\mathrm{d}y}{dx}=4\text{ + 8 - 4} \\ \frac{\mathrm{d}y}{dx}=\text{ 8 (option B)} \end{gathered}\)Consider the following natural language sentence: If you see a penny, pick it up, all day long you'll have good luck. Which answer is a translation of this natural language sentence into formal logic? a.) S = You see a penny. P = You pick the penny up. G = All day long you'll have good luck. (SAP) ➡ G
The translation "If you see a penny, pick it up, all day long you'll have good luck" is represented as (SAP) ➡ G in formal logic.
In formal logic, we often use symbolic notation to represent statements and their logical relationships.
In this case, the natural language sentence is being translated into formal logic using symbolic variables and logical connectives.
The translation provided uses three variables:
S represents the statement "You see a penny."
P represents the statement "You pick the penny up."
G represents the statement "All day long you'll have good luck."
The arrow (➡) is a logical connective that represents implication.
It signifies that the statement on the left side of the arrow (SAP) implies the statement on the right side (G).
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let d be diagonal, with repeated diagonal entries grouped contiguously. show that if a commutes with d, then it must be block diagonal.
As, a is block diagonal, with diagonal blocks of size \(m_1 \times m_1\), \(m_2 \times m_2\), \(\dots\), \(m_k \times m_k\), respectively. So, if a commutes with d, then it must be block diagonal.
Let's suppose that d is a diagonal matrix with repeated diagonal entries grouped contiguously, i.e.,
d = \(\begin{pmatrix} D_1 & 0 & 0 & \cdots & 0 \ 0 & D_1 & 0 & \cdots & 0 \ 0 & 0 & D_2 & \cdots & 0 \ \vdots & \vdots & \vdots & \ddots & \vdots \ 0 & 0 & 0 & \cdots & D_k \end{pmatrix}\),
where \(D_1, D_2, \dots, D_k\) are scalars and appear with frequencies \(m_1, m_2, \dots, m_k\), respectively, so that \(m_1 + m_2 + \dots + m_k = n\), the size of the matrix.
Suppose that \(a\) is a matrix that commutes with d, i.e., ad = da.
Then, for any \(i \in {1, 2, \dots, k}\), we have
\(ad_{ii} = da_{ii}\)
Here, \(d_{ii}\) denotes the \(i$th\) diagonal entry of d, i.e., \(d_{ii} = D_i\) for \(i = 1, 2, \dots, k\). Since d is diagonal, \(d_{ij} = 0\) for \(i \neq j\), and
hence
\(ad_{ij} = da_{ij} = 0\)
for all \(i \neq j\).
Therefore, a is also diagonal, with diagonal entries \(a_{ii}\), and we have
\(a = \begin{pmatrix} a_{11} & 0 & 0 & \cdots & 0 \ 0 & a_{11} & 0 & \cdots & 0 \ 0 & 0 & a_{22} & \cdots & 0 \ \vdots & \vdots & \vdots & \ddots & \vdots \ 0 & 0 & 0 & \cdots & a_{kk} \end{pmatrix}\)
Thus, a is block diagonal, with diagonal blocks of size \(m_1 \times m_1\), \(m_2 \times m_2\), \(\dots\), \(m_k \times m_k\), respectively.
Therefore, if a commutes with d, then it must be block diagonal.
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How long do you think it would take for the material to decay to 23% (without doing the actual calculation), make an explanation using the half-life being 12 years
Solution
The exponential decay can be expressed as;
\(A(t)=A_0(\frac{1}{2})^{^{\frac{t}{t_{half}}}}\)\(\begin{gathered} \Rightarrow0.23=(\frac{1}{2})^{\frac{t}{12}} \\ \\ \Rightarrow\ln(0.23)=\frac{t}{12}\ln(\frac{1}{2}) \\ \\ \Rightarrow t=\frac{12\times\ln(0.23)}{\ln(\frac{1}{2})}=25 \end{gathered}\)Hence, it will take about 25 years. (By calculation)
By Inspection.
12 years is 50%
24 years is 25%
It will take about 24 years to decay to 23%
pls help, thank you!!
Answer: 1, 3
For a cubic polynomial, there are either 3 real roots or 1 real root nad 2 complex roots in a conjugate pair.
Name the coordinate of P(-5, 8) under a translation along the
(x+2, y -1)
Sally bought 1.4 kilograms of bananas for AED 7.35 $ a kilo. How many kilograms
of apples sold at 10.20 $ per kilogram should you buy so that the kilogram of fruit
costs 8.15 $
You should buy approximately 1.067 kilograms of apples at $10.20 per kilogram in order to have the kilogram of fruit cost $8.15.
Let's assume that Sally bought x kilograms of apples at $10.20 per kilogram.
The total cost of bananas is given as AED 7.35 per kilogram, and Sally bought 1.4 kilograms of bananas. So, the cost of the bananas is:
Cost of bananas = AED 7.35 * 1.4 = AED 10.29
The total cost of apples is given by the equation:
Cost of apples = $10.20 * x
The total cost of the fruits combined should be AED 8.15 per kilogram. So, the equation becomes:
Total cost of fruits = (Cost of bananas + Cost of apples) / (1.4 + x) = AED 8.15
Substituting the known values, we have:
(10.29 + 10.20 * x) / (1.4 + x) = 8.15
Cross-multiplying and simplifying, we get:
10.29 + 10.20 * x = 8.15 * (1.4 + x)
Expanding the equation, we have:
10.29 + 10.20 * x = 11.41 + 8.15 * x
Rearranging the equation, we get:
10.20 * x - 8.15 * x = 11.41 - 10.29
1.05 * x = 1.12
Dividing both sides by 1.05, we find:
x = 1.12 / 1.05
x ≈ 1.067
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5th grade math. Correct answer will be marked brainliest.
Answer:
Step-by-step explanation:
find place on x axis first, then find y. <3
How would I solve this?
If you help me with my last question I will help you with this one
Translate each situation into an algerbraic equation: Aunt Bea, who bought $15 worth of makeup, spent $6 less than Helen spent.
need help ASAP!!!!!!
The first three terms of an arithmetic sequence are as follows.
- 11, - 16, - 21
Find the next term in the sequence.
Answer:
-26
Step-by-step explanation:
solve for x: x²/x-3=x+2/2x-5
Answer:
x=2
Step-by-step explanation:
x2
x
+−3=x+x+−5
Multiply all terms by x and cancel:
x2+−3x=xx+xx+−5x
x2−3x=2x2−5x(Simplify both sides of the equation)
x2−3x−(2x2−5x)=2x2−5x−(2x2−5x)(Subtract 2x^2-5x from both sides)
−x2+2x=0
x(−x+2)=0(Factor left side of equation)
x=0 or −x+2=0(Set factors equal to 0)
x=0 or x=2
Check answers. (Plug them in to make sure they work.)
x=0(Doesn't work in original equation)
x=2(Works in original equation)
Answer:
x=2
answer as a decimal with 3 significant digits
Answer:
0.08330.75Step-by-step explanation:
There are four different color marbles.
Probability of blue:
P(B) = 1/4,Next, there are 3 marbles left in the bag since no replacement.
Probability of red after blue:
P(R) = 1/3The probability of these two steps in order:
P(Blue then Red) = 1/4*1/3 = 1/12 = 0.0833Complement of R is:
P(Rc) = 1 - P(R) = 1 - 1/4 = 3/4 = 0.75Let S- (1,2,3,4,5,6) (a) How many subsets are there total? (b) How many subsets contain the elements 2,3 and 5? o) How many subsets contain at least one odd number? (d) How many subsets contain exactly one even number? (e) How many subsets are there of cardinality 4? (f) How many subsets of cardinality 4 contain the elements 2,3, and 5? (g) How many subsets of cardinality 4 contain at least one odd number? (h) How many subsets of cardinality 4 contain exactly one even number?
a) There are 2^6 = 64 subsets total.
b) There are 2^3 = 8 subsets total
c) There are 2^5 = 32 subsets total
d) There are 32^4 = 48 subsets total
e) There are (6 choose 4) = 15 subsets total
f) There are 32 = 6 subsets total
g) There are is (6 choose 4) - (3 choose 4) = 15 - 0 = 15 subsets total
h) There are (3 choose 1) * (3 choose 3) = 3 subsets total
a) There are 2^6 = 64 subsets total.
b) Since we need to include elements 2, 3, and 5 in a subset, we have 3 elements fixed, and we need to choose 1, 2, or 3 elements from the remaining 3 elements (1, 4, and 6). Therefore, there are 2^3 = 8 subsets that contain the elements 2, 3, and 5.
c) There are 2^5 = 32 subsets that contain at least one odd number. This can be seen by noticing that if a subset does not contain any odd numbers, then it must be {2,4,6}, which is not a valid subset since it does not satisfy the condition that it be a subset of S.
d) There are 32^4 = 48 subsets that contain exactly one even number. To see why, notice that there are 3 choices for which even number to include (2, 4, or 6), and then there are 2^4 = 16 choices for which of the remaining 4 odd numbers to include in the subset.
e) There are (6 choose 4) = 15 subsets of cardinality 4. This is the number of ways to choose 4 elements from a set of 6.
f) Since we need to include elements 2, 3, and 5 in a subset of cardinality 4, we have 3 elements fixed, and we need to choose 1 element from the remaining 3 even elements, and 1 element from the remaining 2 odd elements. Therefore, there are 32 = 6 subsets of cardinality 4 that contain the elements 2, 3, and 5.
g) The number of subsets of cardinality 4 that contain at least one odd number is equal to the total number of subsets of cardinality 4 minus the number of subsets of cardinality 4 that contain only even numbers. This is (6 choose 4) - (3 choose 4) = 15 - 0 = 15.
h) The number of subsets of cardinality 4 that contain exactly one even number is equal to the number of ways to choose 1 even number out of 3, and then the number of ways to choose 3 odd numbers out of 3. This is (3 choose 1) * (3 choose 3) = 3.
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Find the output, y, when the input, x, is -9.
y =
Answer:
when x=-9, y=1
Step-by-step explanation:
the graph shows when the x is at -9, the y is at 1
There are 200 kids in the 7th grade at smith middle school. If 25% of them purchase a school t-shirt that costs $20, how much money did the 7th grade spend on t-shirts?
Answer:
$1,000.
Step-by-step explanation:
200 kids divided by 25% or 4 = 50 then 50 x 20 = 1,000.
The value of Maggie's car decreased by 30% since last year, when she bought it. If the car is now worth $22,000.00, how much was the car worth when
she bought it?
A.
$29.333.33
ОВ.
$33,846.15
Oc.
$31,428.57
OD.
$28,600.00
Answer:
$18,200
Step-by-step explanation:
To solve this, you would need to add 30% back to $14,000. To do that, simply multiply $14,000 by 30%. Remember that we will need to also change 30% into its decimal form (30% -> 0.3). $14,000 x 0.3 = $4,200 To find out how much the car was worth when Maggie first bought it, we simply add $4,200 to $14,000. $14,000 + $4,200 = $18,200
Hope it helps!
HELP By Today
Please
The number of permutations of 5 objects taken 2 at a time is P(5,2). The value of
5!
P(5,2) could be found by applying 5P2=
(5 – 2)
What is the value of P(5,2)?
A-60
B-20
C-6
D-120
Answer:
20
Step-by-step explanation:
Find the size of the angle 2 x
Answer:
Given - Angles measure 2x , X and 3x
To find - Measures of 2x
Solution -
2x + X = 180° ( forming linear pair )
3x = 180°
x = 180/3
x = 60°
2x = 2 × 60 = 120°
Answer:
120°
plz give brainlist
Step-by-step explanation:
since 2x and x form a straight angle you get the equation
2x + x = 180
combine like terms
3x = 180
devide by 3
x = 60
evaluate 2x
2(60) = 120
Instructions: Select all of the operations that polynomials are closed under.
Required:
The operations that polynomials are closed under
Explanation:
Polynomials follow all the operations which are Addition, Multiplication, Subtraction and Division.
Final Answer:
Addition, Multiplication, Subtraction and Division