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3. Light from the sun reaches Earth in 8.3 minutes. The speed of light is 3 x 108 m/s. How far is the Earth
from the Sun?

Answers

Answer 1
Set up a unit conversion problem, arrange units to convert minutes to seconds, then cancel all time units.

8.3 minutes x (60 seconds/1 minute) x ( 3.00x10^8 meters/1 second) = 149,400,000,000 meters

Since the time is the term with the fewest number of significant figures (2), your answer should only be expressed with two sig figs as well.

1.5x10^11 m

Related Questions

the voltage used by most households can be modeled by a sine function. The maximum voltge is 120 volts, and there are 60 cycles every second. Write an equation to represent the value of the voltage as it flows through the electric wires, where t is time in seconds

Answers

The required equation for the sine function can be written as; V = 120sin120πt

What is a sine function?

A sine function is a regular repeating function. We know that the voltage is represented using a sine function of the general form V= V-o sin2πft

Hence;

f = 60 cycles per second

V-o = 120 volts

So from the values that we have stated above;

V = 120sin120πt

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place celestial objects in order of increasing orbital period
Kuiper Belt - Mars - Neptune - Saturn - Venus - Asteroid Belt - Mercury - Jupiter - Uranus - Earth

Answers

The celestial objects in increasing order of orbital period are: Mercury - Venus - Earth - Mars - Asteroid Belt - Jupiter - Saturn - Uranus - Neptune - Kuiper Belt.

Determine the orbital period?

The orbital period refers to the time taken by a celestial object to complete one orbit around another object. Based on the given options, we can arrange them in increasing order of their orbital periods.

Mercury has the shortest orbital period among the listed objects, as it orbits the Sun closest to it. Venus comes next, followed by Earth and then Mars. The Asteroid Belt consists of numerous asteroids that have a wide range of orbital periods, so it is placed after Mars.

Moving to the outer planets, Jupiter has a longer orbital period than the Asteroid Belt. After Jupiter, we have Saturn, Uranus, and Neptune, with each having a progressively longer orbital period.

Finally, the Kuiper Belt, which is a region beyond Neptune, contains a vast number of icy objects and has the longest orbital period among the listed options.

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El cuentakilómetros de un coche marca 36 km/h. Un minuto más tarde marca 54 km/h. ¿Qué aceleración ha sufrido el coche? Exprésala en el SI. ¿Qué tipo de velocidades marca el cuentakilómetros?

Answers

The acceleration of the car with initial and final speeds is 8.3×10⁻² m/s². and the odometer shows the distance traveled by the car and the speedometer shows the instantaneous velocity.

Acceleration is defined as the change in velocity per unit time. If the velocity increases, it gives acceleration and if the velocity decreases, it represents deceleration. The SI unit of acceleration m/s².

Acceleration (a) = change in velocity/time

the initial speed of the car (u) = 36km/hr = 36×5/18 = 10 m/s  (km/hr is converted to m/min by multiplying 5/18).

the final speed of the car (v) = 54 km/hr = 54 ×5/18 = 15 m/s

time taken of the car = 1 minute = 60 seconds

Acceleration = v-u / t

                      = 15-10/60

                     = 5/60

                     = 0.083 m/s²

                     = 8.3×10⁻² m/s².

The acceleration of the car = 8.3×10⁻² m/s².

The odometer measures the distance traveled by car.

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The question is  incomplete but most probably your full question was,

The odometer of a car reads 36km/hr. A minute later it reads 54km/hr. What acceleration does the car undergo? Express it in the SI unit. What kind of speeds does the odometer show?

                 

A vector has initial point at (3, –5) and terminal point at (–2, 3). what are the characteristics of this vector? the magnitude is startroot 13 endroot, and the direction angle is about 58°. the magnitude is startroot 13 endroot, and the direction angle is about 122°. the magnitude is startroot 89 endroot, and the direction angle is about 58°. the magnitude is startroot 89 endroot, and the direction angle is about 122°.

Answers

The magnitude of this vector is 9.43 and the direction angle of the vector is 58°.

The initial point and the terminal point of the vectors are (3 - 5) and (-2, 3) respectively.

The characteristics of the vector mainly includes the magnitude and the direction of the angle of the vector.

The magnitude of this vector will be given by,

M = √((-2-3)²+(3+5)²)

M = √(25+64)

M = √89

M = 9.43

The direction angle of this vector with the x-axis will be given by,

Tan A = (8/-5)

Tan A = -1.6

A = 58°.

The direction angle of this vector is 58 degree.

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Answer: D. The magnitude is StartRoot 89 EndRoot, and the direction angle is about 122°.

Explanation:

A vector has initial point at (3, 5) and terminal point at (2, 3). what are the characteristics of this

When any object is launched in the air, it moves up to the maximum height where the velocity of the object becomes zero, or we can say the total energy becomes potential. if air friction is neglected, what are the forces acting on the object after it is released

Answers

After an object is launched in the air and it reaches its maximum height, the forces acting on the object are the force of gravity and the normal force.

The force of gravity is pulling the object downward towards the Earth, while the normal force is pushing the object upward to counteract the force of gravity.

These forces are equal and opposite, so they cancel each other out, causing the object to remain at a constant height until another force acts on it. This is known as the principle of equilibrium.

If air friction is neglected, there are no other forces acting on the object. It will continue to move at a constant velocity until another force, such as air resistance or a collision with another object, changes its motion.

In summary, the forces acting on the object after it is released are the force of gravity and the normal force, which are equal and opposite, causing the object to remain at a constant height until another force acts on it.

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If Cl− is the only anion in the solution, what is the Cl− concentration in milliequivalents per liter?

Answers

Answer:

155mEq/L Cl-

Explanation:

A Ringer’s solution contains the following concentrations of cations: 146 mEq/L of Na+, 5 mEq/L of K+, and 4 mEq/L of Ca2+.

As Cl- is the only counterion of those cations:

For Na, the molecule is NaCl and the mEq/L of Cl- = mEq of Na+. The Cl- of the first ion is 146mEq/L Cl-

For K+, The molecule is KCl, mEq Cl- = 5mEq/L Cl-

And, for Ca2+, The molecule is CaCl2 but the equivalents of Ca2+ = Equivalents of Cl- = 4mEq/L Cl-

The total concentration of Cl- are:

146 + 5 + 4 =

155mEq/L Cl-

Scientists in the laboratory create a uniform electric field E⃗ = 1.5×106 k^V/m in a region of space where B⃗ =0⃗ .
What are the components of the electric field in the reference frame of a rocket traveling in the positive x-direction at 1.3×106 m/s ?
Express your answer using two significant figures separated by commas.
What are the components of the magnetic field in the reference frame of the rocket?
Express your answer using two significant figures separated by commas.

Answers

Scientists create a uniform electric field

\(E⃗ = 1.5×10^6 k^V/m\)in a region of space where\(B⃗ =0⃗.\\\) To find the components of the electric and magnetic fields in the reference frame of a rocket traveling in the positive x-direction at\(1.3×10^6 m/s\), we'll use the Lorentz transformation for electric and magnetic fields.

First, we need to determine the Lorentz factor (γ) for the rocket's speed:
\(γ = 1 / √(1 - v²/c²)\)
where\(v = 1.3×10^6 m/s and c = 3×10^8 m/s\)(speed of light).

\(γ ≈ 1 (since v²/c²\) is very small)

Now, we can use the Lorentz transformation to find the electric and magnetic field components in the rocket's reference frame.

\(E'x = Ex = 0 V/m\) (unchanged)
\(E'y = γ(Ey - vBz) = γ(Ey) = 1.5×10^6 V/m (since Bz = 0)\)
\(E'z = γ(Ez + vBy) = γ(Ez) = 0 V/m (since By = 0)\)

\(B'x = Bx = 0 T\)(unchanged)
\(B'y = γ(By + vEz/c²) = 0 T (since Ez = 0)\)
\(B'z = γ(Bz - vEy/c²) ≈ -vEy/c² = -1.3×10^6 × 1.5×10^6 / 3×10^8 ≈ -6.5×10^-3 T\\\)

The components of the electric field in the rocket's reference frame are: \(0 V/m, 1.5×10^6 V/m, 0 V/m\)
The components of the magnetic field in the rocket's reference frame are: \(0 T, 0 T, -6.5×10^-3 T\)

In two significant figures, your answer is:
Electric field components: \(0, 1.5×10^6, 0 V/m\)
Magnetic field components: \(0, 0, -6.5×10^-3 T\)

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Which of the following would be the best way to calculate the volume of a log with a serious defect? Question 14 options: Defects do not change the volume of a cut log. Assume at least half the volume of the log will be lost. Calculate the volume of the defect and subtract it from the total volume of the log. Calculate volume of the log and ignore the defect.

Answers

The best way to calculate the volume of a log with a serious defect is to calculate the volume of the defect and subtract it from the total volume of the log which is denoted as option C.

What is Volume?

This is referred to as the amount of space occupied by any three-dimensional solid which could be a square, rectangle etc.

In a scenario where a defect is present in the log, then it is  best to consider it by first calculating the volume of the defect after which it is then subtracted from the total volume of the log in other to give an accurate result.

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in viewing the far-field diffraction pattern of a single slit illuminated by a discrete-spectrum source with the help of absorption filters, one finds that the fifth minimum of one wavelength component coincidences exactly with the fourth minimum of the pattern due to a wavelength of 620 nm. what is the other wavelength?

Answers

The other wavelength is 775 nm, since (5/4) times 620 nm is 775 nm.

we need to understand that the diffraction pattern of a single slit consists of a series of bright fringes (maxima) and dark fringes (minima) that are spaced apart by certain angles. The position of these fringes depends on the wavelength of the incident light and the width of the slit.

In this case, we are told that the fifth minimum of one wavelength component coincides with the fourth minimum of the pattern due to a wavelength of 620 nm. Let's call this wavelength λ1. We want to find the other wavelength, which we'll call λ2.
sinθ = mλ / d
For the fifth minimum of λ1, we have:
sinθ1 = 5λ1 / d
For the fourth minimum of λ2, we have:
sinθ2 = 4λ2 / d
sinθ1 = sinθ2
5λ1 / d = 4λ2 / d
λ2 = (5/4) λ1

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What is radiation produces a wave full energy.

Answers

Answer:

electromagnetic radiation hopefully

at the instant he leaves the ground at the edge of the crevasse, alex's x velocity is blank and y velocity is

Answers

At the instant he leaves the ground at the edge of the crevasse, Alex's x-velocity is zero, and his y-velocity is upward.

When Alex leaves the ground at the edge of the crevasse, his x-velocity is zero, meaning there is no horizontal motion. This is because he jumps vertically and does not have any initial horizontal velocity.Simultaneously, his y-velocity is upward. When someone jumps vertically, their initial velocity in the y-direction is typically positive (upward) due to the force applied to propel themselves off the ground.When Alex jumps off the ground at the edge of the crevasse, his initial velocity in the x-direction is zero. This is because there is no horizontal force or motion involved in a vertical jump.In the y-direction, the force of his jump propels him upward, resulting in an initial positive velocity. This upward velocity indicates that his y-velocity is positive (upward) at the instant he leaves the ground.Therefore, at the instant he leaves the ground at the edge of the crevasse, Alex's x-velocity is zero, and his y-velocity is upward.

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1. If a car sits out in the sun every day for a long time, can light from the sun damage the car's paint?
a
Yes. The paint can take in energy from the light, causing it to be damaged.
b
No. Light can only change things by warming them up. so it cannot damage the car's paint.
С
No. Light is not a physical thing, so it cannot change physical things like paint.
d
Yes. Light from the sun can pull energy out of the paint. causing it to be damaged.

Answers

\( \huge\boxed{ \tt option \: a}\)

Yes. The paint can take in energy from the light, causing it to be damaged.

the answer is

A , Yes. The paint can take in energy from the light, causing it to be damaged

How do you find average velocity during free fall?

Answers

The sum of the initial and final velocity divided by 2.
- 400 all over 5 minus 0 which is negative 400 minus 5 which is going to be negative 80 feet perMore

An odd-shaped object rotates at a speed of 10. 0 rev/s. A small 25 g

mass with moment of inertia I=1. 5x10-6 kg∙m2 is dropped onto the

object at a distance of 4. 5 cm from its center of mass. The odd-shaped

object slows to a speed of 9. 0 rev/s. What is the moment of inertia of

the odd-shaped object?

Answers

The moment of inertia of the odd-shaped object is: approximately 1.67x10⁻³ kg∙m².

To find the moment of inertia of the odd-shaped object, we can use the conservation of angular momentum principle. Angular momentum before the mass is dropped equals angular momentum after the mass is dropped.

Initially, only the odd-shaped object is rotating with an angular speed of 10.0 rev/s. After the 25 g mass with a moment of inertia I=1.5x10⁻⁶ kg∙m² is dropped onto the object at a distance of 4.5 cm (0.045 m) from its center of mass, the system's angular speed slows to 9.0 rev/s.

First, let's convert the angular speed from rev/s to rad/s:


Initial angular speed (ω1) = 10.0 rev/s * 2π rad/rev ≈ 62.83 rad/s
Final angular speed (ω2) = 9.0 rev/s * 2π rad/rev ≈ 56.55 rad/s

Let I_obj be the moment of inertia of the odd-shaped object. The angular momentum before and after the mass is dropped can be written as:

I_obj * ω1 = (I_obj + I + m * r²) * ω2

Solving for I_obj, we get:

I_obj = [(I + m * r²) * ω2] / ω1

Substituting the given values:

I_obj = [(1.5x10^-6 kg∙m² + (0.025 kg * (0.045 m)^2)) * 56.55 rad/s] / 62.83 rad/s

After calculating the above expression, we find that the moment of inertia of the odd-shaped object is approximately 1.67x10⁻³ kg∙m².

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If you lived close to the equator, which climate would you live in?

polar

dry/arid

mild/temperate

tropical

Answers

Answer:

Tropical

Explanation:

Dry/arid because it is hotter at the equator

A 1-kg mass, when attached to a large spring, stretches the spring a distance of 4.9 m: (a) Calculate the spring constant: (b) The system is placed in a viscous medium that sup- plies a damping constant / = 3 kgls. The system is allowed to come to rest_ Then the mass is displaced 1m in the downward direction and given a sharp tap; imparting an instantaneous velocity of 1 mls in the downward direction: Find the position of the mass as a function of time and plot the solution.

Answers

(a) The spring constant is 19.6 N/m.

(b) The position of the mass as a function of time can be expressed as x(t) = e^(-t/6)[Acos(2.27t) + Bsin(2.27t)] + 1, where A and B are constants determined by the initial conditions.

(a) The spring constant k can be calculated using Hooke's Law, which states that the force F exerted by a spring is directly proportional to its displacement x: F = -kx. Therefore, k = -F/x = -(1 kg)(9.81 m/s^2)/4.9 m = 19.6 N/m.

(b) The equation of motion for the damped harmonic oscillator is given by mx'' + bx' + kx = 0, where m is the mass, x'' is the second derivative of x with respect to time, b is the damping constant, and k is the spring constant.

The general solution to this equation is x(t) = e^(-bt/2m)[Acos(ωt) + Bsin(ωt)], where ω = sqrt(k/m - b^2/4m^2) is the angular frequency.

Using the initial conditions x(0) = 1 and x'(0) = -1, we can solve for A and B and obtain the expression for x(t) given above. Plugging in the values of k, m, and b, we get ω = 2.27 rad/s.

The exponential term e^(-t/6) represents the decay of the motion due to damping. The position of the mass oscillates around the equilibrium point x = 1 with decreasing amplitude and frequency. A plot of the solution shows the decay of the oscillation over time.

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What happens when a falling object reaches terminal velocity?
it slows down.
it stops accelerating
It speeds up
it hits the ground and stops.

2. How does a falling object’s surface area affect calculations of terminal velocity?
The greater the objects surface area, the more air resistance it encounters
The greater the objects surface area, the greater the air density
Surface area does not affect an object’s terminal velocity
The greater the object’s surface area, the greater it’s terminal velocity

Answers

When the object reaches the terminal velocity the object stops accelerating. Option B

The greater the objects surface area, the more air resistance it encounters. Option A

What is the terminal velocity?

Terminal velocity is the maximum velocity an object reaches when falling through a fluid, such as air, due to the balance of gravitational force and fluid drag.

Surface area affects terminal velocity because a larger surface area results in greater fluid drag force, which slows the object's descent. A smaller surface area results in less fluid drag and a higher terminal velocity.

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the force of attraction between two objects is called gravity why do you think that an object like your note book pulls twords you​

Answers

gravitaional pull

not sure

which kind of waves are used to make and receive cellphone calls?

Answers

Answer:

Micro Waves

Explanation:

Microwaves in particular are used by cell phone calls for wireless communication. A portion of radio waves with higher frequency makes up these microwaves. The cellphone's antenna transforms speech data into microwaves during a call, and these microwaves travel through the atmosphere to the closest cell tower. The tower takes in and sends the microwaves to the mobile device of the intended receiver. The gadget receives the microwaves and transforms them back into electrical signals so the recipient can hear the voice data. By employing the strength of microwaves, this technology provides wireless communication and permits mobile users to communicate from anywhere inside the cellular network's service area.

The type of waves that are used to make and receive cellphone calls are radio waves.

Radio waves are a type of electromagnetic radiation that has a long wavelength and low frequency. These waves are used for communication purposes because they are able to travel long distances without losing their signal strength. When a person makes a call on their cellphone, their voice is converted into an electrical signal that is sent through the cellphone's antenna as a radio wave. This radio wave is then picked up by the nearest cell tower, which receives the signal and sends it through the network to the person on the other end of the call. The process is reversed when the other person responds, with their voice being converted into a radio wave that is sent back through the network to the caller's phone.

In summary, radio waves are the type of waves that are used to make and receive cellphone calls due to their ability to travel long distances without losing signal strength.

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what is the approximate noontime (maximum) sun angle in sacramento on the december solstice? (hint: sac's latitude is approx. 39.5°n)

Answers

Answer:

Below

Explanation:

The earth ( for the northern hemisphere) is tilted away 23.5° from the sun on the solstice....this lowers the sun in the sky

  Sacramento is already   39.5 degrees from equator

      90 - 39.5 - 23.5 = 27 degrees high

The approximate noontime (maximum) sun angle in Sacramento on the December solstice is about 27 degrees.

The approximate noontime (maximum) sun angle in Sacramento on the December solstice can be calculated using the following formula:

Maximum Sun Angle = 90° - Latitude + Declination

Where:

Latitude = 39.5°N (latitude of Sacramento)

Declination = -23.5° (declination angle on the December solstice)

Plugging in the values, we get:

Maximum Sun Angle = 90° - 39.5° + (-23.5°)

Maximum Sun Angle = 27°

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what are the types of measurement units used in colombia?

Answers

The types of measurement units used in Colombia is international System of Units (SI),  which is the successor of the Decimal Metric System.

What is the international System of Units?

The International System of Units, known by the international abbreviation SI in all languages and sometimes pleonastically as the SI system, is described as the modern form of the metric system and the world's most widely used system of measurement.

This means that since instead of inches, feet or miles, Colombia will  be using centimeters, meters and kilometers.

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consider the relationship between force and potential energy. on a single graph, propose two example plots of potential energy as a function of position, one corresponding to a weak force and the second a strong force that would restrict the motion of an object to a 1d region of space. explain your reasoning.

Answers

The two example plots of potential energy as a function of position will be Simple Harmonic Oscillator Potential and Potential Well.

Potentials of the following kind can limit a particle to a certain region of space:

1) Simple Harmonic Oscillator Potential: This potential restricts the motion of an attached mass on a spring and restricts the vibration of a heterogeneous molecule about its mean location.

Consequently, an upward parabola will represent the plot for this function. The weak force that this potential energy represents is that. (In this case, the Restoring Force is in charge of changing the particle's potential energy.)

2) Potential Well: Particles are imprisoned in an area with less energy than the potential energy surrounding it, and as a result, they require energy to leave the system. Consequently, a particle Outside of this area of high potential, no assistance is possible.

Protons and neutrons are held within the boundaries of the nucleus by the Strong Nuclear Force, which has an exceptionally high potential. These subatomic particles are imprisoned inside this potential and are therefore unable to leave without assistance.

Potential will be in the form of

V(x)=0   for -L<x<L

V(x)=V   for x<-L and x>L

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a police car coming toward you from the east (as you move westward) has a siren on at an unknow frequency. as he approaches you hear a frequency of 510 hertz but as he passes you and continues away you hear the pitch drop to 400 hz. you are traveling at a constant 15 m/sec speed throughout. how fast is the police car traveling?

Answers

This problem can be solved using the Doppler effect equation:

f' = f (v + u) / (v + u')

where:
- f is the frequency of the siren at rest (i.e., when the police car is not moving)
- f' is the frequency of the siren as heard by the observer (you)
- v is the speed of sound in air, which is approximately 343 m/s at room temperature
- u is the speed of the observer (you)
- u' is the speed of the source (the police car)

We can use this equation to solve for u':

Step 1: Calculate the frequency of the siren when the police car is moving away from you.

When the police car is moving away from you, the frequency of the siren as heard by you is lower than the frequency at rest. We can use the Doppler effect equation to calculate this frequency:

f' = f (v + u) / (v + u')
400 Hz = f (343 m/s + 15 m/s) / (343 m/s + u')
400 Hz (343 m/s + u') = f (343 m/s + 15 m/s)
u' = (f (343 m/s + 15 m/s) / 400 Hz) - 343 m/s

Step 2: Calculate the frequency of the siren when the police car is moving toward you.

When the police car is moving toward you, the frequency of the siren as heard by you is higher than the frequency at rest. We can use the Doppler effect equation to calculate this frequency:

f' = f (v + u) / (v - u')
510 Hz = f (343 m/s + 15 m/s) / (343 m/s - u')
510 Hz (343 m/s - u') = f (343 m/s + 15 m/s)
u' = (f (343 m/s + 15 m/s) / 510 Hz) - 343 m/s

Step 3: Calculate the speed of the police car.

We can now use the two equations we derived to solve for u':

(f (343 m/s + 15 m/s) / 400 Hz) - 343 m/s = (f (343 m/s + 15 m/s) / 510 Hz) - 343 m/s

Simplifying this equation, we get:

f / 400 Hz - f / 510 Hz = 15 m/s

(50 pts) How are beryllium and carbon made inside a star?
Thanks! :)

Answers

Answer:

Stars create new elements in their cores bu squeezing elements together in a process called unclear fusion. First stars fuse hydrogen atoms into heluim. Helium atorm then fuse to create berylluim and so on until fusion in the star’s core has created every element up to icon.

gas pressure is caused by question 1 options: barometers gas molecules hitting other gas molecules or their container gas molecules colliding with surfaces gas molecules condensing to a liquid

Answers

Gas pressure is caused by gas molecules colliding with surfaces.

When gas molecules move and collide with the walls of a container, they exert a force on the walls, which causes the pressure of the gas in the container.

This is why gas pressure is often measured in units of force per unit area, such as pounds per square inch (psi) or pascals (Pa). While barometers can be used to measure gas pressure indirectly by measuring atmospheric pressure, the underlying cause of gas pressure is the collision of gas molecules with surfaces.

Thus, we can say that gas pressure is caused by gas molecules colliding with surfaces.

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Can we make electromagnet with copper​

Answers

Answer:

only if you take copper

Explanation:

Any electric current has an associated magnetic field, so a current-carrying conductor is an electromagnet, regardless of what material it is made. ... However, using copper alone will not make a strong electromagnet

An electromagnet is a coil of wire with an electric current flowing through it.
When the wire is coiled around in a cylinder, we call this a solenoid. The solenoid becomes an electromagnet when a current flows through it.


Why use copper?

Copper is used because it has a low electrical resistance (see conducting properties). This means that it is easy for the current to flow through it. Also, copper wire can be easily shaped to make a coil

What's the field like?

When the current flows through the wire, it makes the coil into a magnet. We call this an electromagnet.
The field of the electromagnet is similar to the field of a bar magnet. The coil has a north pole at one end and a south pole at the other.

Remember, that we show the lines of force coming out of the north pole and going into the South Pole.

what other items did edison invent that helped make the light bulb practical?

Answers

Thomas Edison was a prolific inventor who held over 1,000 patents. In addition to the light bulb, he also invented several other items that helped make it practical. One of the most important of these was the electrical power distribution system.

Prior to Edison's invention, electricity was mainly used for telegraphy and was not widely available for general use. Edison's distribution system made it possible to deliver electricity to homes and businesses, making the light bulb a viable option for everyday use.

Edison also invented the first practical incandescent lamp, which used a carbon filament that could last for over 1,200 hours. He also developed a system of vacuum pumps that removed air from the bulb to increase its lifespan. Additionally, Edison's work on improving electrical generators and transformers made it possible to produce and distribute electricity more efficiently.

Overall, Edison's numerous inventions and improvements in electrical technology helped make the light bulb practical and paved the way for the widespread adoption of electric lighting.

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What does temperature measure?
a.)average kinetic energy of the particles in an object or substance
b.)relative heat of an object or substance compared to its environment
c.)potential energy stored in the chemical bonds of an object or substance
d.) kinetic energy of objects or substances

Answers

Answer:b

Explanation:

Answer:

B

Explanation:

Which chamber of the heart receives blood with sugar and high oxygen levels from the lungs? A. left atrium B. right atrium C. left ventricle D. right ventricle

Answers

Answer:

left atrium

Explanation:

its the first chamber of the heart to receive oxygenated blood from the lungs

9. Waves originate from

Answers

Wind is the most frequent cause of waves. The friction between the wind and the surface of the water produces wind-driven waves, also known as surface waves. A wave crest is produced when wind continuously disturbs the water's surface in an ocean or lake.

What is meant by wave?

A wave exists an energetic disturbance in a medium that doesn't include any net particle motion. Elastic deformation, a change in pressure, an electric or magnetic intensity, an electric potential, or a change in temperature are a few examples.

Wind is the most frequent cause of waves. The friction between the wind and the surface of the water produces wind-driven waves, also known as surface waves. A wave crest is produced when wind continuously disturbs the water's surface in an ocean or lake.

Waves are oscillations or vibrations that revolve around a resting point. As an illustration, sound waves force air molecules to oscillate. Water molecules vibrate up and down due to ripples.

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