Answer:
Number 18 is 171 or (B).
james rolls a red number cube and a blue number cube that are both numbered to on each face. which expression could be used to find the probability that james rolls a on the red cube and a on the blue cube?
The probability of James rolling a 1 on the red cube and a 1 on the blue cube is 1/36, or approximately 2.78%.
The probability that James rolls a 1 on the red cube and a 1 on the blue cube can be calculated using the formula P(A and B) = P(A) x P(B). In this case, the probability of rolling a 1 on the red cube (P(A)) is 1/6, and the probability of rolling a 1 on the blue cube (P(B)) is also 1/6. Multiplying these two probabilities together gives us \(P(A and B) = (1/6) x (1/6) = 1/36\). This means that the probability of James rolling a 1 on the red cube and a 1 on the blue cube is 1/36, or approximately 2.78%.
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hich of the following are most likely to be dependent samples? multiple choice a study that compares the mean wait times at two different hospital emergency rooms a study that compares the salaries earned by men and women in the same job position a study that compares the weight gain for puppies who eat two different brands of food a study that compares standardized test scores before and after a course is taken
The statement which most likely represent "dependent-samples" is (d) study which compares standardized "test-scores" before and after course is taken.
The scores obtained before and after are linked, as they are obtained from the same group of individuals, and are therefore dependent samples.
For example, suppose a group of students is given a standardized test before and after taking a preparation course.
The scores obtained before the course are likely to be related to the scores obtained after the course, as they are both measures of the same group of students.
If the course has a significant impact on the scores, the before-and-after scores will likely be correlated, and the samples will be dependent.
Therefore, the correct option is (d).
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The given question is incomplete, the complete question is
Which of the following are most likely to be dependent samples?
(a) A study that compares the mean wait times at two different hospital emergency rooms
(b) A study that compares the salaries earned by men and women in the same job position
(c) A study that compares the weight gain for puppies who eat two different brands of food
(d) A study that compares standardized test scores before and after a course is taken.
k/5.1 + 92.1 = 11.2 solve please
Answer:
\(k=-412.59\)
Step-by-step explanation:
1) Subtract 92.1 from both sides.
\(\frac{k}{5.1} =11.2-92.1\)
2) Simplify 11.2 - 92.1 to -80.9.
\(\frac{k}{5.1} =-80.9\)
3) Multiply both sides by 5.1.
\(k=-80.9*5.1\)
4) Simplify 80.9 × 5.1 to 412.59.
\(k=-412.59\)
C
2
1
3
A. 21
B. 23
C.24
D. 25
b7
#
5
4
In the figure, which angle has the same measure as /2?
Answer:
the angle that has the same measure as /2 is A
Gordon types 2,584 words in 38 minutes.
Answer:
Gordon types 68 words per minute
Step-by-step explanation:
2584/38=68
3.1. Two friends. Ben and Mike, take part in a 15km fun
run. Ben took 1 h 23 min 12 sec and Mike took 1 h 39
min 4 sec. How long did Ben wait at the finish line for
Mike?
Answer: 15.867 min
Step-by-step explanation:
Given
Ben took \(1\ h\ \text{and}\ 23\ min\ 12\ s\) to complete 15 km
While Mike take \(1\ hr\ 39\ min\ 4\ s\) to complete the same
converting time into miniutes
Ben time
\(\Rightarrow 60+23+\frac{12}{60}=83.2\ min\)
Mike time
\(\Rightarrow 60+39+\frac{4}{60}=99.0667\ min\)
So, mike waited for
\(\Rightarrow 99.067-83.2=15.867\ min\)
In Phoenix, Arizona, the average temperature is 85 degrees Fahrenheit or higher during 25% of the year. During about how many weeks of the year is the average temperature below 85 degrees Fahrenheit?
Answer: 39 weeks
Step-by-step explanation:
Given
The average temperature is \(85^{\circ}F\) or higher
A year has 52 weeks
It is given 25% of the time-temperature is above \(85^{\circ}F\)
So, in the remaining 75% of the weeks, the average temperature is less than \(85^{\circ}F\)
No of weeks can be determined by
\(\Rightarrow 75\%\ \text{of}\ 52\\\\\Rightarrow \dfrac{75}{100}\times 52=39\ \text{weeks}\)
perseverance a certain water filtration system can remove 70% of the contaminants each time a sample of water is passed through it. if the same water is passed through the system four times, what percent of the original contaminants will be removed from the water sample?
The percent of the original contaminants will be removed from the water sample is 99.19 %.
Let the contaminant in water be x
70% contaminant remove by one pass
Then the remaining contaminants be 30%
In 1st as,
30x/100
= 3x/10
In 2nd pass,
3x/10 x 30/100
= 9x/100
In 3rd pass,
9x/100 x 30/100
= 27x/1000
In 4th pass,
27x/1000 x 30/100
= 81x/10000
Remaining contaminant after fourth pass = 81x/10000
Total removal of contaminant,
y = x - 81x/10000
= 9919x/10000
Therefore, the original contaminants will be removed from the water sample is 99.19%.
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Solve the given differential equation by undetermined coefficients
1/4 y'' + y' + y = x2 − 3x
y ( x) = \(C_{1} e^{-2x} + C_{2} e^{-2x} + x^{2} - 5 x + \frac{9}{2}\) is the result of solving the subsequent differential equation with unknown coefficients.
What do you mean by differential equation ?One or more functions and [some of] their derivatives are connected by a differential equation. The [first] derivative of the function with respect to the variable is illustrated in the following example. Differentials are a term used to describe the and elements.
given
1/4 y'' + y' + y = x2 − 3x
The auxilary equation is
1/4 \(m^{2}\) + m + 1 = 0
\(m^{2}\) + m + 1 = 0
\(( m- 2)^{2}\) = 0
m = -2 , -2
= A =1 , 2A+ B = -3 , 1/2A + B = 0
A = 1 , B = - 5 , C = 9/ 2
Then the general solution is
y = yc + yp
y ( x) = \(C_{1} e^{-2x} + C_{2} e^{-2x} + x^{2} - 5 x + \frac{9}{2}\) is the result of solving the subsequent differential equation with unknown coefficients.
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Determine whether y varies directly with x. If so,
find the constant of variation k and write the
equation
x y
7 14
21 42
63 126
189 378
Answer:
Yes.
Step-by-step explanation:
They both multiply by 3. K=3
x1=x0*3
x2=x1*3....
y1=y0*3
Y2=y1*3....
Answer:
see explanation
Step-by-step explanation:
If y varies directly with x then the equation relating them is
y = kx ← k is the constant of variation and
k = \(\frac{y}{x}\)
Check this ratio for each ordered pair, that is
k = \(\frac{14}{7}\) = \(\frac{42}{21}\) = \(\frac{126}{63}\) = \(\frac{378}{189}\) = 2
Thus k = 2 and
y = 2x ← equation of variation
A circle has a diameter of 26 unites. What would be the Area of the circle, round to the nearest hundredth
Answer:
530.93 units squared
Step-by-step explanation:
The formula for the area of a circle is \(A=\pi r^{2}\). Based on this, we must plug in the given values.
The diameter is always doubled the value of the radius. Therefore, in order to find the value of the radius (r), divide it by 2. This would give us a radius of 13 units; now we have all the values to plug into the formula
Answer:
530.93 units^2
Step-by-step explanation:
The area of a circle can be found using the following formula.
\(a=\pi r^2\)
First, we must find the radius. The radius is always half of the diameter, or
r=d/2
We know that the diameter is 26 units. Therefore, we can substitute 26 in for d.
r=26/2
r=13
The radius is 13 units.
Now we know the radius. Substitute 13 in for r in the area formula.
\(a=\pi r^2\)
r=13
\(a=\pi 13^2\)
Evaluate the exponent. 13^2 is equal to 13*13, which is equal to 169.
\(a=\pi *169\)
Multiply pi and 169.
a=530.929158457
Round to the nearest hundredth. The 9 in the thousandth place indicates the 2 in the hundredth place should be rounded up to a 3.
a=530.93
Add appropriate units. IN this case, the units are units^2.
a=530.93 units^2
The area of the circle is about 530.93 units^2.
How many students are enrolled in a course either in calculus, discrete mathematics, data structures, 7. or programming languages at a school if there are 507, 292, 312, and 344 students in these courses, respectively; 14 in both calculus and data structures; 213 in both calculus and programming languages; 211 in both discrete mathematics 558 and data structures; 43 in both discrete mathematics and programming languages; and no student may take calculus and discrete mathematics, or data structures and programming languages, concurrently
Answer:
974
Step-by-step explanation:
Let assume that:
The set of student that took part in Calculus be = C
Those that took part in discrete mathematics be = D
Let those that took part in data structures be = DS; &
Those that took part in Programming language be = P
Thus;
{C} = 507
{D} = 292
{DS} = 312
{P} = 344
For intersections:
{C ∩ DS} = 14
{C ∩ P} = 213
{D ∩ DS} = 211
{D ∩ P} =43
{C ∩ D} = 0
{DS ∩ P} = 0
{C ∩ D ∩ DS ∩ P} = 0
According to principle of inclusion-exclusion;
{C ∪ D ∪ DS ∪ P} = {C} + {D} + {DS} + {P} - {C ∩ D} - {C ∩ DS} - {C ∩ P} - {D ∩ DS} - {D ∩ P} - {DS ∩ P}
{C ∪ D ∪ DS ∪ P} = 507 + 292 + 312 + 344 - 14 - 213 - 211 - 43 - 0
{C ∪ D ∪ DS ∪ P} = 974
Hence, the no of students that took part in either course = 974
Please help i need this done in a little bit
Answer: w = 8 miles
Step-by-step explanation:
The area of the shaded region is 16 mi^2.
The height is already given as 4mi. Using this, we can set up the equation to find w, the base of the shaded region.
1/2*4*w = 16
2*w=16
w=8
Therefore, w=8 miles
a drawer has ten blue, ten white, and ten red socks. without looking at them you pull some socks out. what is the least number of socks you need to pull to ensure you get two pairs of matching socks? justify your answer.
Answer:
The answer is 7 socks.
Step-by-step explanation:
To ensure one matching pair, you need to pull out 4 socks. If none of the first three match, the fourth one will guarantee a matching pair.
You will then need to pull out 3 more socks, for a total of 7 socks, to ensure two matching pairs.
I dont know how to do this so yeah
Answer:
a). x = 12
b). m∠H = 90°
m∠I = 58°
m∠J = 62°
Step-by-step explanation:
a). Use the property of a triangle,
" Sum of all the angles in a triangle is 180°"
(2x + 34)° + (4x + 14)° = 180°
(2x + 4x) + (34 + 14) = 180
6x + 48 = 180
6x = 180 - 48
6x = 132
x = \(\frac{132}{6}\)
x = 12
b). m∠H = 90° [Given]
m∠I = (2x + 34)° = [(2 × 12) + 34]°
m∠I = 58°
m∠J = (4x + 14)° = [(4 × 12) + 14]°
m∠J = 62°
You have 80 grams of tellurium how much will be left after 8 months if it’s half-life is 2 months?
Answer:
5 grams.
Step-by-step explanation:
First, find out how many half-lives have passed. Divide the number of months by the length of a half-life.
8÷2=4
4 half-lives have passed.
Now figure out how much tellurium will be left after 4 half-lives have passed. Multiply the starting amount of tellurium by \(\frac{1}{2}\) a total of 4 times.
80 · \(\frac{1}{2}\)·\(\frac{1}{2}\)·\(\frac{1}{2}\)·\(\frac{1}{2}\) = 5
That calculation could also be written with exponents
80 · \((\frac{1}{2} )^{4}\) = 5
After 4 half-lives, the amount of tellurium left will be 5 grams.
George had $6,000 in a savings account earning simple interest at a rate of 5% per year. At the end of the year, George paid 25% in taxes on his interest. How much money did George earn in interest that year after paying taxes?
Answer:
$225
Step-by-step explanation:
Given that:
Principal = $6,000
Interest rate = 5%
Time = 1 year
Taxes paid = 25% on the interest earned
To find:
Money earned after paying taxes ?
Solution:
First of all, let us calculate the total interest earned:
Formula for Simple Interest is given as:
\(SI =\dfrac{PRT}{100}\)
Where P is the principal
R is the rate of interest
T is the time taken
Putting the given values:
\(SI =\dfrac{6000 \times 5\times 1}{100} =\$300\)
Now, it is given that 25% of the interest earned is given as taxes.
Taxes paid = 25% of $300
\(\Rightarrow \dfrac{25}{100} \times 300 =\$75\)
Therefore, the money earned = Interest earned - Taxes paid
The money earned = $300 - $75 = $225
What type of correlation/association exists?
The number of hours you sleep in and the number of hours you are awake during the day
Answer:
Negative Correlation
Step-by-step explanation:
there is a negative correlation between the number of hours you sleep in and the number of hours you are awake during the day as the longer you are either awake or asleep the less time you will be doing the other thing
Here is a graph I made that will hopefully help you understand.
Even if I switched around the label for the x or y-axis, the correlation would still remain the same because the more you stay asleep, the less you will be awake and vice versa.
What is the area of the shaded part ? Take(π=22/7)
Answer:
Given:
radius of bigger half circle[R]=(7+7+14)/2=14cm
radius of smaller half circle [r]=14/2=7cm
Area of shaded region =1/2[πR² -πr²]
=1/2×22/7×[14²-7²]=231cm²
Area of shaded region=231cm²
Market researchers interviewed a random sample of 60 men and a random sample of 55 women about their preferences for different color designs for the packaging of a certain product. Of those interviewed, 23 men and 28 women preferred color design X. Which of the following is the correct test statistic for a two-sample z-test for a difference in population proportions for men and women (men minus women) in their preference for color design X?
0.51 -0.38 (0.41)(0.56)(+ ++) 23-28 2= | (0.38) (051) ( ) 23-28 с | (0.44) (0.5) (= + =) 0.38-0.51 2= D (0.44) (0.56) () 0.38 0.51 2= E (0.44) (056) (+1)
The correct test statistic for the difference in population for the gender will be 0.38/0.51 root (0.44)(0.56)(1/65 + 55).
What is a test statistic?It should be noted that a test statistic simply means the number that is calculated from the statistical test of a hypothesis.
From the complete question, the test statistic for a two-sample z-test for a difference in population proportions for men and women is 0.38/0.51 root (0.44)(0.56)(1/65 + 55).
This is vital as it shows how the observed data matches the distribution that's expected under the null hypothesis.
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could you help me with 11% and 9% thank you Assuming that the current interest rate is 10 percent, compute the present value of a five-year, 10 percent coupon bond with a face value of $1,000. What happens when the interest rate goes to 11 percent? What happens when the interest rate goes to 9 percent?
As the interest rate increases from 10 percent to 11 percent, the present value of the bond decreases from $1,074.47 to $1,058.31. Conversely, when the interest rate decreases to 9 percent, the present value increases to $1,091.19. This is because the discount rate used to calculate the present value is inversely related to the interest rate, meaning that as the interest rate increases, the present value decreases, and vice versa.
To compute the present value of a five-year, 10 percent coupon bond with a face value of $1,000, we need to discount the future cash flows (coupon payments and face value) by the appropriate interest rate.
Step 1: Calculate the present value of each coupon payment.
Since the bond has a 10 percent coupon rate, it pays $100 (10% of $1,000) annually. To calculate the present value of each coupon payment, we need to discount it by the interest rate.
Using the formula: PV = C / (1+r)^n
Where PV is the present value,
C is the cash flow,
r is the interest rate, and
n is the number of periods.
At an interest rate of 10 percent, the present value of each coupon payment is:
PV1 = $100 / (1+0.10)^1 = $90.91
Step 2: Calculate the present value of the face value.
The face value of the bond is $1,000, which will be received at the end of the fifth year. We need to discount it to its present value using the interest rate.
At an interest rate of 10 percent, the present value of the face value is:
PV2 = $1,000 / (1+0.10)^5 = $620.92
Step 3: Calculate the total present value.
To find the present value of the bond, we need to sum up the present values of each coupon payment and the present value of the face value.
Total present value at an interest rate of 10 percent:
PV = PV1 + PV1 + PV1 + PV1 + PV1 + PV2
PV = $90.91 + $90.91 + $90.91 + $90.91 + $90.91 + $620.92
PV = $1,074.47
When the interest rate goes to 11 percent, we would repeat the above steps using the new interest rate.
Total present value at an interest rate of 11 percent:
PV = PV1 + PV1 + PV1 + PV1 + PV1 + PV2
PV = $90.91 + $90.91 + $90.91 + $90.91 + $90.91 + $620.92
PV = $1,058.31
When the interest rate goes to 9 percent, we would repeat the above steps using the new interest rate.
Total present value at an interest rate of 9 percent:
PV = PV1 + PV1 + PV1 + PV1 + PV1 + PV2
PV = $90.91 + $90.91 + $90.91 + $90.91 + $90.91 + $620.92
PV = $1,091.19
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find the most general antiderivative of the function. (check your answer by differentiation. use c for the constant of the antiderivative.) f(x) = 5 x4
The most general antiderivative of the function f(x) = 5x^4 is F(x) = x^5 + C, where C represents the constant of integration.
To find the antiderivative of a function, we need to reverse the process of differentiation. In this case, we have the function f(x) = 5x^4. To find its antiderivative, we can apply the power rule for integration. According to the power rule, when integrating a term of the form x^n, where n is any real number except -1, we add 1 to the exponent and divide the term by the new exponent. Applying this rule to our function, we add 1 to the exponent 4, resulting in 5x^5. However, since integration is an indefinite process, we include the constant of integration, denoted by C, to account for all possible antiderivatives. Thus, the most general antiderivative is F(x) = x^5 + C. To verify our answer, we can differentiate F(x) and confirm that it indeed yields the original function f(x) = 5x^4.
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(a) cause-in-fact (b) assumption of risk (c) seclusion (d) res ipsa loquitur (e) slander (f) punitive damages (g) absolute privilege
The legal context and definitions are (a) Negligence - Establishes the link between the defendant's actions and the plaintiff's harm. (b) Negligence defenses - Plaintiff voluntarily accepts known risks, relieving the defendant of liability. (c) Invasion of privacy - Unjustified intrusion into private affairs that would offend a reasonable person. (d) Negligence - Accident itself suggests defendant's negligence without direct evidence (e) Defamation - False spoken statements harming someone's reputation (f) Monetary awards to punish and deter egregious behavior. (g) Defamation defenses - Immunity for certain statements made in specific contexts.
(a) Cause-in-fact
Legal context: Negligence.
Definition: Cause-in-fact refers to the actual cause or link between the defendant's conduct and the plaintiff's harm, establishing that the harm would not have occurred without the defendant's actions.
(b) Assumption of risk
Legal context: Negligence defenses.
Definition: Assumption of risk is a defense in negligence cases where the plaintiff voluntarily and knowingly accepts the risks associated with a certain activity, relieving the defendant of liability for any resulting harm.
(c) Seclusion
Legal context: Invasion of privacy.
Definition: Seclusion refers to the intentional and unjustified intrusion into an individual's private affairs or seclusion, which would highly offend a reasonable person.
(d) Res ipsa loquitur
Legal context: Negligence.
Definition: Res ipsa loquitur is a doctrine where the occurrence of an accident or injury itself suggests that the defendant was negligent, allowing the plaintiff to establish a prima facie case without direct evidence of negligence.
(e) Slander
Legal context: Defamation.
Definition: Slander is a form of defamation that involves making false spoken statements about someone that harm their reputation.
(f) Punitive damages
Legal context: Various tort subject areas.
Definition: Punitive damages are monetary awards beyond compensatory damages, awarded in certain cases to punish the defendant for particularly egregious behavior and to deter others from similar conduct.
(g) Absolute privilege
Legal context: Defamation defenses.
Definition: Absolute privilege is a defense in defamation cases that grants immunity from liability for statements made in certain contexts, such as during legislative or judicial proceedings, regardless of their truth or intent.
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--The given question is incomplete, the complete question is given below " For each term (1) identify the legal context in which it arises; and (2) define the term.
For the legal context part of your answer for each term, indicate which tort subject area the term relates to (e.g., "fraud," “false imprisonment,” “defamation,” “defamation defenses,” “invasion of privacy,” “interference with contract,” “interference with prospective economic advantage,” “negligence,” “negligence defenses,” “strict liability,” or, if and where appropriate, “intentional torts” generally).
In addition, the definition portions of your answers need not be more than one sentence for each term. Your answer for each term is worth a maximum of 2 points.
(a) cause-in-fact
(b) assumption of risk
(c) seclusion
(d) res ipsa loquitur
(e) slander
(f) punitive damages
(g) absolute privilege"--
Need an answer fast, please.
Answer:
D. 15x² + 62x + 63
Step-by-step explanation:
rectangle area: length * width
Here the length is ( 3x + 7 ) and width is (5x+9)
using the formula:
( 3x + 7 )(5x+9)
15x²+27x+35x+63
15x² + 62x + 63
Answer:
D. 15x^2 + 62x +63
Step-by-step explanation:
Area of rectangle = L x W
L = 3x + 7 ; W = 5x + 9
=> A = (3x + 7) x (5x +9) = 15x^2 + 62x +63
how many seconds are there in a month of 30 days express it in scientific notation
You roll a fair six-sided die with the hopes of rolling a 5 or a 6. These two events are ___________ because they have no sample points in common.
You roll a fair six-sided die with the hopes of rolling a 5 or a 6. These two events are mutually exclusive because they have no sample points in common.
When two events are mutually exclusive, it means that they cannot happen at the same time. In this case, you cannot roll a 5 and a 6 at the same time because they are two different outcomes on a single roll of the die.A fair six-sided die has six equally likely outcomes: 1, 2, 3, 4, 5, or 6. The probability of rolling a 5 or a 6 on a single roll of a fair six-sided die is 2/6 or 1/3. This is because there are two outcomes (5 and 6) that are favorable, out of a total of six possible outcomes. Hence, the two events of rolling a 5 or a 6 on a fair six-sided die are mutually exclusive because they have no sample points in common.
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Exercise 1. Two servers (S. and Ss) with exponential service time and same service rate are busy completing service of two jobs at time t = 0. The server that completes service first is referred to as the winning server (Sw), the other is referred to as the losing server (St). Jobs must complete their service before departing from the queue. A) Compute the probability of S to be the winning server, i.e., P(S = S1) = P(S = S2). Compute the probability of S, to be the winning server, i.e., P(S = Sx) = P(S = Si) (pt. 10). B) Compute the expected departure time of the winning server, defined as ty > 0 [pt. 10). C) Compute the expected departure time of the losing server, defined as t > t pt. 10).
A) Here, we have two servers: Server 1 (S1) and Server 2 (S2). And we need to compute the probability of S to be the winning server, i.e., P(S = S1) = P(S = S2).Since we have two servers with the same service rate, the jobs have equal chances of being assigned to either server.
Therefore, P(S = S1) = P(S = S2)
= 1/2.
(Both servers have equal probabilities of winning).
B) Expected departure time of the winning server, defined as ty > 0. It is also called the mean service time (MST) or the expected value of the service time. The expected value of an exponential distribution is equal to the reciprocal of the service rate. Thus, if the service rate of both servers is μ, then the expected departure time of the winning server will be 1/μ.
C) Expected departure time of the losing server, defined as t > t0. Since the two jobs can't leave until their services are complete, the service time of the winning server will be the total time taken by both jobs. Thus, the expected departure time of the losing server can be calculated by taking the expected departure time of the winning server (which is 1/μ) and subtracting the mean service time (MST) of a single job, which is 1/2μ. Therefore, the expected departure time of the losing server will be 1/μ - 1/2μ = 1/2μ.
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In a mathematics test, Jack scored 17 marks more than Yazid while Susan scored twice Yazid's score. If their total score is 161, what is Jack's score?
Answer:
53
Step-by-step explanation:
Let yazid's score be x
x + x + 17 + 2x = 161
4x + 17 = 161
4x = 144
x = 36
jack = x + 17
jack = 53
Answer:
Jack: 36
Bonus: Yazid: 53 and Susan: 72
Step-by-step explanation:
Let J, Y, and K stand for Jack, Yazin, Susan's scores.
We are told that:
J = Y + 17 [Jack scored 17 marks more than Yazid]
S = 2Y [Susan scored twice Yazid's score]
J + Y + S = 161 [total score is 161]
Substitute the first two expressions into the last equation:
J + Y + S = 161
(Y+17) + Y + (2Y) = 161
4Y = 144
Y = 36
Use Y = 36 to find the other scores:
J = Y + 17
J = 36 + 17
J = 53
S = 2Y
S = 2*(36)
S = 72
CHECK:
Does 36+53+72 = 161?
YES
Alan added 27 fish to his pond over a period of 9 days. He added the same number of fish each day. What was the change in the number of fish in the pond each day?
If you have a mass of 55g that has a volume of 11 ml, what is the density?
Answer:
D=5g/ml
Step-by-step explanation:
D=M/V
D=55/11