Help, teacher timing this.
Question is below.
Thank you!!
-hello10olleh (hello)
Answers
Answer:
D
Step-by-step explanation:
1. Split the triangle in half so that x = 1/2x
2. Use the pythagorean theorem to find 1/2x. \(\sqrt{13^2-12^2} =5\)
3. Because 5 = 1/2x, multiply by 2 to get x = 10
Answer:
(D) x=10
Step-by-step explanation:
FIRST STEP:
Use a²+b²=c² form in which 12=a, 13=c, and x=b.
SECOND STEP:
Substitute a²+b²=c² for 12²+x²=13².
Simplify=144+x²=169.
THIRD STEP:
Take away 144 from both sides and get 25=x²
FOURTH STEP:
Since x is squared, we will have to square root both sides. After this happens, the equation will equal 5=x.
FIFTH STEP:
However, I only did half of the triangle, so I will multiply 5 by 2 and get 10.
So, the answer is 10=x
Related Questions
A plant is such that each of its seeds when one year old produce 21-fold and produce 44- fold when two years old or more. A seed is planted and as soon as a new seed is produced, it is planted taking u,, to be the number of seed produced at the end of the nth year, show that Un+1 = 21 un +44 (U₁ + ₂ +. + U₁-1) Hence show that un+2-22un+1-23un = 0 and find Un
Answers
The number of seeds produced at the end of the nth year is given by:
Un = (1/24)(23^(n+1)) + (1/24)(-1)^n
From the problem statement, we know that each seed produces 21-fold when it is one year old and 44-fold when it is two years old or more. Let u_n be the number of seeds produced at the end of the nth year.
The number of seeds produced at the end of the (n+1)th year can be expressed as:
U_n+1 = 21u_n + 44(u_1 + u_2 + ... + u_n-1)
To show this, consider that in the (n+1)th year, all the seeds from the previous year will produce 21-fold. Therefore, the total number of seeds produced from the previous year's seeds will be 21 * u_n.
In addition, some of the seeds from previous years may still be producing, and they will produce a 44-fold harvest. The total number of such seeds can be expressed as
44(u_1 + u_2 + ... + u_n-1)
Hence we have shown:
Un+1 = 21 un +44 (U₁ + ₂ +. + U₁-1)
Now we can use this equation to derive the required expression:
Un+2 = 21 Un+1 +44 (U₁ + ₂ +. + U₁-1)
Substituting for Un+1 using the previous equation,
Un+2 = 21(21un + 44(U1 + U2 + ... + Un-1)) + 44(U1 + U2 + ... + Un-1)
Simplifying and rearranging terms,
Un+2 - 22Un+1 - 23Un = 0
This is a linear homogeneous recurrence relation with constant coefficients. The characteristic equation is:
r^2 - 22r - 23 = 0
Solving for r gives:
r = 23 or r = -1
The general solution of the recurrence relation is given by:
Un = A(23)^n + B(-1)^n
Using the initial condition that U_1 = 1, we can solve for A and B:
1 = A(23)^1 + B(-1)^1
1 = 23A - B
Substituting this into the general solution gives:
Un = (1/24)(23^(n+1)) + (1/24)(-1)^n
Therefore, the number of seeds produced at the end of the nth year is given by:
Un = (1/24)(23^(n+1)) + (1/24)(-1)^n
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In problem 8-94 you found that if you are given three lengths to build the sides of a triangle, then if a triangle can be formed, all the triangles you could make were the same. Suppose you start with two triangles knowing that their three pairs of corresponding sides are the same, as shown in the diagram below.
Triangle, A B C, where side, A C, has one hatch mark, side, C B, has 2 hatch marks, and side, A B, has 3 hatch marks.
Triangle, P Q R, where side, R P, has one hatch mark, side, P Q, has 2 hatch marks, and side, R Q, has 3 hatch marks.
Examine the diagram. What do you think the markings indicate? Name the pairs of corresponding sides.
What can you say about the two triangles and why? What can you say about their angles? Why?
Answers
Work in groups of two to three (If possible). For each of the activities described have the required number of people in your group (usually 1) perform the activity as the others observe. Following the performance and observation, record what was seen. Make sure that you understand the activity prior to performance. The observers should choose their positions carefully with reference to the planes of motion.
Laboratory Report - Reflexes
1. Long Jump - perform 2 trials of each of these jumps in turn. Record the relative length of each jump
(which jumps are longer than others).
Assign a rank order by distance:
_____a. Use a bobbing motion with the knees and arms.
_____b. Start the jump from a position of deep knee flexion, with no knee motion prior to the start of the jump.
_____c. Start the jump with the knees fully extended, using no knee motion.
Answers
a. Jump with a bobbing motion: Shortest jump b. Jump from deep knee flexion: Intermediate jump
c. Jump with fully extended knees: Longest jump ,In the long jump activity, three different jumping techniques were observed:
a) The bobbing motion involved bending and extending the knees and arms during the jump.
b) Starting from deep knee flexion meant initiating the jump from a position with knees bent and no motion prior to the jump.
c) Starting with fully extended knees involved jumping with the knees straight and no motion before the jump. During the performance, the lengths of each jump were measured. Trial results consistently indicated that the jump with the bobbing motion had the shortest length, while the jump starting from deep knee flexion had an intermediate length. The jump with fully extended knees consistently achieved the longest distance.
The observations reveal that starting the jump with fully extended knees and no knee motion results in the longest jump. The bobbing motion with knee and arm movements leads to the shortest jump. Deep knee flexion position falls between the two in terms of jump length.
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the solid s has a base described by the circle x2 y2=25. cross sections perpendicular to the x-axis and the base are semicircles. what is the volume of s? express your answer in terms of π.
Answers
According to the described way the volume of solid S is 156.25π.
Since the cross sections perpendicular to the x-axis and the base are semicircles, we know that the radius of each cross section is given by:
r = y = √(25 -\(x^{2}\) )
where x is the distance from the center of the circle to the cross section, which lies along the x-axis.
The circle \(x^{2}\)+ \(y^{2}\) = 25 has a radius of 5, and its center is at the origin (0,0). Thus, the farthest a cross section can be from the center of the circle is at x = 5 or x = -5.
To find the volume of the solid S, we need to integrate the area of each cross section over the range from x = -5 to x = 5. The area of each cross section is given by:
A = (1/2)πr^2
Substituting the expression for r above, we get:
A = (1/2)π(25 - x^2)
Integrating this expression over the range from x = -5 to x = 5 gives us:
V = ∫(-5)^5 (1/2)π(25 - x^2) dx
Using integration rules, we can evaluate this integral to get:
V = (1/2)π ∫(-5)^5 (25x - x^3) dx
V = (1/2)π [ (25/2)x^2 - (1/4)x^4 ]|_-5^5
V = (1/2)π [ (25/2)(5^2) - (1/4)(5^4) - (25/2)(-5^2) + (1/4)(-5^4) ]
V = (1/2)π [ 625/2 - 625/4 + 625/2 - 625/4 ]
V = (1/2)π (625/2)
V = (312.5/2)π
V = 156.25π
Therefore, the volume of solid S is 156.25π.
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The center of a sphere is
Answers
Answer:
a fixed point equidistant from all points on the surface of the sphere
Step-by-step explanation:
I assume you are taking the test, so that's the answer
The solution set for -18 < 5x - 3 is _____.
A. 3 > x
B. -3 > x
C. 3 < x
D. -3 < x
Answers
Answer:
D. -3 < x
Step-by-step explanation:
-18 < 5x - 3
-18 + 3 < 5x
-15/5 < 5x/5
-3 < x
1. In a radical engine the moving parts have a total moment of inertia of 1 kg m 2
, and this is concentrated in the plane of the single crankpin. The engine is directly connected to an air-screw of moment of inertia 18 kg m 2
, by a hollow shaft having outer and inner diameters of 80 mm, and 35 mm, and a single effective length of 0.30 m. The stiffness of the crank-throw alone is 2.5×10 4
Nm/rad. Estimate the natural frequency of torsional vibration of the custen What percentage is involved if the air-screw mass is assumed to be infinite. G=83000 N/mm 2
HINT The stiffness of the crank-throw may be reduced to an equivalent length of shaft at the same diameter as the engine using q
1
= q 1
1
+ q 2
1
Answers
The percentage change in frequency is 0%.Hence, the natural frequency of torsional vibration of the custen is given by f = 25.7 / L₀^(1/2) and the percentage change in frequency is 0%.
We are given that:
Total moment of inertia of moving parts = I = 1 kgm²
Moment of inertia of air-screw = I = 18 kgm²
Outer diameter of hollow shaft = D₀ = 80 mm
Inner diameter of hollow shaft = Dᵢ = 35 mm
Length of hollow shaft = L = 0.30 m
Stiffness of the crank-throw = K = 2.5 × 10⁴ Nm/rad
Shear modulus of elasticity = G = 83000 N/mm²
We need to calculate the natural frequency of torsional vibration of the custen.
The formula for natural frequency of torsional vibration is: f = (1/2π) [(K/L) (J/GD)]^(1/2)
Where, J = Polar moment of inertia
J = (π/32) (D₀⁴ - Dᵢ⁴)
The formula for equivalent length of hollow shaft is given by:
q₁ = q₁₁ + q₁₂
Where, q₁₁ = (π/32) (D₀⁴ - Dᵢ⁴) / L₁q₁₂ = (π/64) (D₀⁴ - Dᵢ⁴) / L₂
L₁ = length of outer diameter
L₂ = length of inner diameter
For the given shaft, L₁ + L₂ = L
Let L₁ = L₀D₀ = D = 80 mm
Dᵢ = d = 35 mm
So, L₂ = L - L₁= 0.3 - L₀...(1)
For the given crank-throw, q₁ = (π/32) (D⁴ - d⁴) / L, where D = 80 mm and d = 80 mm
Hence, q₁ = (π/32) (80⁴ - 35⁴) / L
Therefore, q₁ = (π/32) (80⁴ - 35⁴) / L₀...(2)
From the formula for natural frequency of torsional vibration, f = (1/2π) [(K/L) (J/GD)]^(1/2)
Substituting the values of K, J, G, D and L from above, f = (1/2π) [(2.5 × 10⁴ Nm/rad) / (L₀) ((π/32) (80⁴ - 35⁴) / (83000 N/mm² (80 mm)³))]^(1/2)f = (1/2π) [(2.5 × 10⁴ Nm/rad) / (L₀) (18.12)]^(1/2)f = 25.7 / L₀^(1/2)...(3)
Now, if we assume that the air-screw mass is infinite, then the moment of inertia of the air-screw is infinite.
Therefore, the formula for natural frequency of torsional vibration in this case is:
f = (1/2π) [(K/L) (J/GD)]^(1/2)Substituting I = ∞ in the above formula, we get:
f = (1/2π) [(K/L) (J/GD + J/∞)]^(1/2)f = (1/2π) [(K/L) (J/GD)]^(1/2)f = 25.7 / L₀^(1/2)
So, in this case also the frequency is the same.
Therefore, the percentage change in frequency is 0%.Hence, the natural frequency of torsional vibration of the custen is given by f = 25.7 / L₀^(1/2) and the percentage change in frequency is 0%.
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please HELP
im preparing for my math exam tomorrow and i need help solving these types of questions I will give you brainliest and 5 stars and heart please help I was always bad at these types of questions
The length of a ribbon roll is 2.5 m. If 50 cm has been used from it, how much is left?
Answers
2.5 meters = 250 cm
If you use 50 cm, then you have
2 meters or 200 cm left
Answer:
200 cm (or 2 meters) or 80% of the original 250 cm is left. let me know if you have any questions.
Step-by-step explanation:
I'm not sure if that's asking for an exact amount or percent, so I will do both.
The trick either way is to match units. we have meters and centimeters. You could make either one match the other. so 2.5 m is 250 cm and 50 cm is .5 m.
You do have to know how many centimeters is in a meter, but once you know that you can set up unit conversions, which are super simple.
there are 100 cm in a m. a unit conversion is basically a fraction that cancels out units. starting with 2.5 m we want to cancel out m so the fraction we use has the m part in the denominator. so 2.5m * (100 cm)/(1 m). (100 cm)/(1 m) is the unit conversion, and just like variables the m in the denominator cancles out the m in the starting value so it turns into 2.5 * 100 cm/1 = 250 cm.
similarly to go from 50 cm to meters you make the unit conversion have cm in the denominator. so 50 cm * (1 m)/(100 cm) = .5 m. again, the cm int he denominator cancels out the cm in the unit being multiplied. Let me knwo if this is still not clear.
Anyway, now we have the numbers we need. let's make them all cm, I think using the smallest unit is usually easiest. so that's 250 cm total and 50 cm used.
In pure numbers, that means 200 cm is left (which is 2 meters) after 50 cm gets used.
percents is a little trickier. if 250 is 100% then 50 is 20%, which you can get by doing 50/250. if you do not know, a fraction a/b gives you the percent a is of b. Or rather it gives you a decimal, and if you multiply it by 100 it gives you the percent.
anyway, if 20% is used then 80% is left. if you did 200/250 you would get that.
Solve the write an equation of the line that passes through a pair of points a. y=x+3 b. y=x-3 c. y=-x+2 d. y=-x-2
Answers
The equation of the line passing through the points (0,-2) and (2,0) is y = x - 2.
What is equation?An equation is a mathematical statement that shows that two expressions are equal. It typically consists of variables, constants, and mathematical operations, such as addition, subtraction, multiplication, and division, and can be represented using symbols and/or words. Equations are used to solve problems in mathematics, science, engineering, and other fields.
In the given question,
We can use the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept.
First, we need to find the slope of the line passing through the points (0,-2) and (2,0):
slope = (change in y)/(change in x)
slope = (0 - (-2))/(2 - 0)
slope = 2/2
slope = 1
Now that we have the slope, we can use one of the given equations and substitute the coordinates of one of the points to find the y-intercept:
y = mx + b
-2 = 1(0) + b
b = -2
So the equation of the line passing through the points (0,-2) and (2,0) is y = x - 2.
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what does 1-1-1-1-1-1-1-1-1-1-1-1-2-2-2-2-2-2-2-2-2-2-2-2-2-3-3-3-3-3-3-3-3-3-3-3-3-3-4-4-4-4-4-4-4-4-4-4-4-4-4-4-4-5-5-5-5-5-5-5-5-5-5-5-5-5-5-5-6-6-6-6-6-6-6-6-6-6-6-6-6-6-6-6-7-7-7-7-7-7-7-7-7-7-7-7-7-7-7-7-7-8-8-8-8-8-8-8-8-8-8-8-8-8-8-8-8-8-8-8-9-9-9-9-9-9-9-9-9-9-9-9-9-9-9-9-9-9-9-9-0-0-0-0-0-0-0-0-0-0-0-0-0-0-0-0-0-0-0-0-0-0-0-0-10-10-10-10-10-1000?
Answers
•ω• Hewo fren!
☆☆●◉✿Answer:✿◉●☆☆
-1807
☆☆●◉✿Step-by-step explanation:✿◉●☆☆
(Did the subtraction on paper-) geez this is a huge question- owo
HOPE I HELPED! ∧∧
→⇒brainliest please? ∑(OΔO )♥♥︎Answer:
-1807
you good
Step-by-step explanation:
help pleaseee!!!!! due td
Answers
Answer:
7x^4+4x^2-x-5
Step-by-step explanation:
I need help ASAPPPPPPPPP
Answers
Answer:
C) 3/8 < 1/2 good luck
Step-by-step explanation:
brainliest please
Hi help me please I don't know how to do it "using the formula evaluate (87)^2"
Answers
Answer:
7,569
Step-by-step explanation:
\((87)^{2} \\ = {(90 - 3)}^{2} \\ = {90}^{2} - 2 \times 90 \times 3 + {3}^{2} \\ = 8100 - 540 + 9 \\ = 8100 + 9 - 540 \\ = 8109 - 540 \\ = 7,569\)
PLEASE THIS IS URGENTTT
Answers
The functions and their transformations are
h(x) = 2(x + 1)² - 8: a translation down by 5 unitsk(x) = 2(x + 6)² - 3: a translation left by 5 units g(x) = 2(x - 4)² - 3: a translation right by 5 unitsj(x) = 2(x + 1)² + 2: a translation up by 5 unitsHow to match the functions and the transformations?From the question, we have the following parameters that can be used in our computation:
f(x) = 2(x + 1)² - 3
A translation down by 5 units is represented as
f(x) - 5
So, we have
f(x) - 5 = 2(x + 1)² - 3 - 5
f(x) - 5 = 2(x + 1)² - 8
Rewrite as
h(x) = 2(x + 1)² - 8
A translation left by 5 units is represented as
f(x + 5)
So, we have
f(x + 5) = 2(x + 1 + 5)² - 3
f(x + 5) = 2(x + 6)² - 3
Rewrite as
k(x) = 2(x + 6)² - 3
A translation right by 5 units is represented as
f(x - 5)
So, we have
f(x - 5) = 2(x + 1 - 5)² - 3
f(x - 5) = 2(x - 4)² - 3
Rewrite as
g(x) = 2(x - 4)² - 3
A translation up by 5 units is represented as
f(x) + 5
So, we have
f(x) + 5 = 2(x + 1)² - 3 + 5
f(x) + 5 = 2(x + 1)² + 2
Rewrite as
j(x) = 2(x + 1)² + 2
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if marie wants to go to south kotea but she needs at least 4,500$
and she gets paid 10$ weekly
how much years or days will it take 4,500
Answers
Answer:
Around 9 years or 9.3 to be exact.
Step-by-step explanation:
hat If you add up 10 and 4 (the average amount of weeks in a month). She makes 40$ a month and you multiply that by 12(months in a year). Annually, she makes 480$. You divide her annual income with 4,500$ and there's your answer of how long it will take!
Hope this helps. I could be wrong!
Solve the equation.
p−3=−4
p=
Answers
The value of p in the given equation is -1.
Given is an equation p-3 = -4, we need to find the value of p,
So,
p-3 = -4
p = -4+3
p = -1
Hence, the value of p in the given equation is -1.
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PLEASE ANSWER ASAP!!!!!!!
A cheesecake has equally sized slices. Each slice is a different flavor. The diameter of the cheesecake is 10 inches, and the area of the slice of blueberry cheesecake is 25π16 square inches.
How many slices does the cheesecake have?
Answers
A cheesecake has equally sized slices. Each slice is a different flavor. The cheesecake has 12 slices.
What is the area of the circle?
The area of the circle is defined as the product of the pie and the square of the radius.
The area of the circle = πr²
In order to calculate the total area of the cheesecake, since it's a circle its area is given by:
cheesecake area = πr²
cheesecake area = π(10/2)² = π(5)²
cheesecake area = 25 π square inches
Therefore the number of slices is the ratio of the cheesecake total area by the area of each slice:
The number of slices = 25 π/(25 π/12)
The number of slices = 12
The cheesecake has 12 slices.
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Answer: 12 slices
Step-by-step explanation:
im a year late woo hoo
when the angle of an incline with a block resting on it increases the normal support force? A) decreases B) increases C) stays the same
Answers
Answer:
normal force decreases
Step-by-step explanation:
N=mgcosθ, and cosine decreases as theta increases
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Answer:
A) decreases
Step-by-step explanation:
As the angle of the incline increases, the normal force decreases, which decreases the frictional force. The incline can be raised until the object just begins to slide.
Shea wrote the expression 5(y + 2) + 4 to show the amount of money five friends paid for snacks at a baseball game. Which expression is equivalent to the one Shea wrote?
Answers
Answer:
1. \(5*y + 5*2 + 4\)
2. \(5*y + 10 + 4\)
3. \(5y + 14\)
Step-by-step explanation:
Given
\(5(y + 2) + 4\)
Required
Write an equivalent expression
\(5(y + 2) + 4\)
Start by opening the bracket.
\(5(y + 2) + 4 = 5 * y + 5 * 2 + 4\)
\(5(y + 2) + 4 = 5 y + 10 + 4\)
Add like terms (10 and 4)
\(5(y + 2) + 4 = 5 y + 14\)
Hence, equivalent expressions of \(5(y + 2) + 4\) are:
1. \(5*y + 5*2 + 4\)
2. \(5*y + 10 + 4\)
3. \(5y + 14\)
how to calculate personnel budget with nch/ppd practice problems
Answers
To calculate the personnel budget using NCH/PPD practice, multiply the NCH/PPD ratio by the number of patient days and the cost per nursing care hour
The personnel budget calculation involves three components: NCH/PPD ratio, number of patient days, and cost per nursing care hour.
First, determine the NCH/PPD ratio, which represents the average number of nursing care hours required per patient day. This ratio can be obtained from historical data or industry benchmarks.
Next, obtain the number of patient days, which refers to the total number of days that patients are present in the healthcare facility during a specified period. This information can be obtained from patient records or hospital administration.
Finally, determine the cost per nursing care hour, which includes wages, benefits, and any additional costs associated with nursing staff. This value can be obtained from the organization's financial records or by consulting with the finance department
To calculate the personnel budget, multiply the NCH/PPD ratio by the number of patient days, and then multiply that result by the cost per nursing care hour. This calculation provides an estimate of the personnel budget required for nursing staff based on the NCH/PPD practice. It's important to regularly review and update these calculations to ensure accuracy and account for any changes in patient volume or cost factors.
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Write an equation through the point (0,13) with a slope 11/3
Answers
Answer:
13=11/3(0)+c
c=13
y=11/3X+13
Step-by-step explanation:
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Use the diagram to complete the statements.
The angle of depression from point R to point S is angle
.
The angle of elevation from point S to point R is angle
.
Angle 2 is the angle of elevation from
.
Angle 1 is the angle of
.
Answers
The angle of depression from point R to point S is ∠1.
The angle of elevation from point S to point R is ∠2.
∠2 is the angle of elevation from S to R.
∠1 is the angle of depression from point R to point S.
What is an angle of depression?
If the line of sight is directed downward from the horizontal line, then an angle is created with the horizontal line. The angle formed between the horizontal line and the observer's line of sight is known as the angle of depression if the object being observed is below the observer's level.
There is an angle of elevation from point R to S. Thus point R is lie above S.
The angle of depression from point R to point S is ∠1.
The angle of elevation from point S to point R is ∠2.
∠2 is the angle of elevation from S to R.
∠1 is the angle of depression from point R to point S.
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if your p-value is .11, and the significance level is .05, what do you conclude?
Answers
The p-value is .11 and the significance level is .05, then we fail to reject the null hypothesis.
The p-value represents the probability of obtaining the observed results, or results more extreme, assuming the null hypothesis is true. In this case, the p-value is greater than the significance level, which means that the observed results are not significant enough to reject the null hypothesis.
With a p-value of .11 and a significance level of .05, we can conclude that there is not enough evidence to reject the null hypothesis.
When comparing the p-value to the significance level (0.05), if the p-value is less than or equal to the significance level, you would reject the null hypothesis, indicating that there is a significant effect or difference.
If the p-value is greater than the significance level, you would fail to reject the null hypothesis, meaning that you cannot conclude that there is a significant effect or difference.
Hence, the p-value (0.11) is greater than the significance level (0.05), you fail to reject the null hypothesis, which means you cannot conclude that there is a significant effect or difference.
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If the measure of base angle ABC is 75 , what is m
Answers
The sum of the angles of any triangle is 180°.
75° + 75° + m<BAC = 180°
m<BAC = 180° - (75° + 75°) = 30°
Consider a simulation experiment in which the population distribution is quite skewed. The figure below shows the density curve for lifetimes of_a certain type of electronic control [this is actually a lognormal distribution with E(ln(X)) = 3 and V(ln(X)) = 0.16]. The statistic of interest is the sample mean X. The experiment utilized 500 replications and considered these sample sizes: n = 5, n = 10, n = 20, and n = 30. The resulting histograms along with a normal probability plot from MINITAB for the x values based on n = 30 are shown in the figures below. Density curve for the simulation experiment (E(A) = 21.7584, V(X) = 82.1449]
Answers
In this simulation experiment, the population distribution represents the lifetimes of a certain type of electronic control and the density curve in the figure represents the population distribution.
The distribution is skewed and follows a lognormal distribution with an expected value of ln(X) equal to 3 and a variance of ln(X) equal to 0.16. The experiment consisted of 500 replications and examined different sample sizes: n = 5, n = 10, n = 20, and n = 30.
The density curve in the figure represents the population distribution, with an expected value of E(A) equal to 21.7584 and a variance of V(X) equal to 82.1449. The histograms shown illustrate the distribution of sample means for the different sample sizes. Additionally, a normal probability plot from MINITAB is included for the x-values based on a sample size of n = 30, allowing for an assessment of the normality assumption for the sample means.
These visual representations provide valuable insights into the characteristics of the simulated experiment's population distribution, as well as the behavior of the sample means for different sample sizes.
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The complete question is:
Consider a simulation experiment in which the population distribution is quite skewed. The figure below shows the density curve for lifetimes of_a certain type of electronic control [this is actually a lognormal distribution with E(ln(X)) = 3 and V(ln(X)) = 0.16]. The statistic of interest is the sample mean X. The experiment utilized 500 replications and considered these sample sizes: n = 5, n = 10, n = 20, and n = 30. The resulting histograms along with a normal probability plot from MINITAB for the x values based on n = 30 are shown in the figures below. Density curve for the simulation experiment (E(A) = 21.7584, V(X) = 82.1449].
The function defined by y = square root r^2 - x^2 has as its graph a semicircle of radius r with center at (0, 0) (as shown in the figure to the right). Find the volume that results when the semicircle y = square root 49 - x^2 is rotated about the x-axis. The volume is cubic units. (Type an exact answer, using pi as needed.)
Answers
Answer:
Step-by-step explan ation:
Yarım Dairenin Hacmi = pi x r 2 x 2r x 1/2
Yarım Dairenin Hacmi =pi x 7 2 x 14 x 1/2
Yarım Dairenin Hacmi = 343pi/2
simplify: [2]
(−3d'2e'4)'3
_________
9d'2e'5
" ' " is used for square..
Answers
Answer:
\(81 {d}^{4} {e}^{7} \)
Step-by-step explanation:
Use properties of degrees:
1. When multiplying different degrees on one term, the degree indicators must be multiplied, for example:
\(( { {x}^{2}) }^{3} = {x}^{2 \times 3} = {x}^{6} \)
2. When dividing like terms (with the same base) with different degrees, the degree indicators must be subtracted, for example:
\( \frac{ {x}^{5} }{ {x}^{2} } = {x}^{5 - 2} = {x}^{3} \)
3. When squaring a negative term in parentheses, the minus is eliminated, for example:
\(( { - 3x})^{2} = 9 {x}^{2} \)
.
\( \frac{ {(( { - 3d})^{2} \times {e}^{4} )}^{3} }{ {9d}^{2} \times {e}^{5} } = \frac{729 {d}^{6} \times {e}^{12} }{9 {d}^{2} \times {e}^{5} } = 81 {d}^{4} \times {e}^{7} \)
please solve :)
2y < y + 2
Answers
Explanation:
Subtract y from both sides. This will isolate y.
2y < y+2
2y-y < y+2-y ... subtract y from both sides
y < 2
The solution involves any number smaller than 2.
Find the GCF and LCM of each number using any of the methods.
Answers
The GCF is the smallest shared prime factor for each term.
The LCM is the smallest whole number that both numbers share as multiples.
For example, take #16.
Factors of 25: 1 , 5, 25
Factors of 75: 1 , 3, 5, 15, 25 ,75
The GCF that is shared would then be 25.
The smallest multiple that both share as multiples:
Multiples of 25: 25, 50, 75, etc.
Multiples of 75: 75, etc.
The LCM that is shared would then be 75.
16) 25 and 75
GCF: 25
LCM: 75
17) 35 and 5
GCF: 5
LCM: 35
18) 27 and 36
GCF: 9
LCM: 108
19) 21 and 56
GCF: 7
LCM: 168
20) 54 and 72
GCF: 18
LCM: 216
you are going to create a caramel cheese popcorn mixture. one cup of caramel popcorn contains 183 calories, 5.4 grams fat, 22.5 grams sugar, and 87 mg of sodium. one cup of cheese popcorn contains 58 calories, 3.7 grams fat, 0.1 grams sugar, and 98 mg sodium. if you create a mixture that has two times as much cheese popcorn as caramel popcorn and contains a total of 254 calories, how many cups of each item would be in your mixture. be sure to clearly define the variables used, define the two equations, and show and explain all work.
Answers
The mixture would contain approximately 0.849 cups of caramel popcorn and 1.698 cups of cheese popcorn.
Let's define the variables:
Let x be the number of cups of caramel popcorn in the mixture
Let y be the number of cups of cheese popcorn in the mixture
We are given that the mixture has two times as much cheese popcorn as caramel popcorn, so y = 2x.
We are also given that the total number of calories in the mixture is 254. To find an equation that relates x and y, we can use the calorie information for each type of popcorn:
Calories from caramel popcorn = 183x
Calories from cheese popcorn = 58y = 58(2x) = 116x
Total calories in the mixture = 183x + 116x = 299x
Setting the total calories equal to 254 and solving for x:
299x = 254
x = 0.849
So we would need 0.849 cups of caramel popcorn in the mixture.
To find the number of cups of cheese popcorn, we can use the equation y = 2x:
y = 2(0.849) = 1.698
So we would need 1.698 cups of cheese popcorn in the mixture.
Therefore, the mixture would contain approximately 0.849 cups of caramel popcorn and 1.698 cups of cheese popcorn.
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