Help plz I’m Cunfused !!

Answer:

a=2.4m/s^2

Explanation:

Use V=vi+at

So, 13=25+a5

13-25=a5

\(\frac{-12}{5}\)=a

a=2.4m/s^2

The magnitude of the force that the garbage exert on the floor of the service elevator is equal to 238.05 Newtons.

The mass of the garbage in the elevator is 20.7 kg. The elevator is accelerated downward at a rate of 1.7 m/s².

The acceleration due to gravity is g.

As the elevator accelerator downward then the total net acceleration of the elevator in the download direction is

A =  (1.7 + 9.8) m/s².

A = 11.5 m/s².

The force that the garbage exert on the floor of the service elevator will be equal to the product of the mass of the garbage and the net acceleration with which the elevator is going downward,

F = 20.7 × 11.5

F = 238.05 N.

So, the force exerted by the garbage on the floor is 238.09 Newton.

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Answer:

With a pressure, for instance, of 4 atmospheres, and a volume of 5 liters yields 4 x 5 = 20. Divide the result by the number of moles of gas. If, for instance, the gas contains 2 moles of molecules: 20 / 2 = 10. Divide the result by the gas constant, which is 0.08206 L atm/mol K: 10 / 0.08206 = 121.86.

Answer:

A device that is used to break an electric circuit is called electric switch

The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.

The given parameters:

The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;

\(\Sigma F = 0\\\\T_1 sin(\theta) + T_2 sin(\theta) - W = 0\)

where;

The weight of the seashell is calculated as;

\(1.42 \times sin(75) \ + \ 1.42 \times sin(75) \ - W = 0\\\\2.743 - W = 0\\\\W = 2.743 \ N\)

The mass of the seashell is calculated as follows;

\(W = mg\\\\m = \frac{W}{g} \\\\m = \frac{2.743}{9.8} \\\\m = 0.28 \ kg\)

Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.

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The vertical speed of the rod varies inversely as the rotational speed for a given number of complete rotations

The equation that gives the vertical velocity, v₀ is  \(\, \underline{v_0= \dfrac{ g \cdot \pi \cdot n}{ \omega_0 }}\)

Reason:

From a similar question, the given parameters appear to be correctly given as follows;

The vertical speed of the rod = v₀

Angular velocity of the = ω₀

Required;

The value of, v₀, so that the rod has made exactly, n, number of turns when it returns to his hand

Where;

n = An integer

Solution;

The time the rod spends in the air is given as follows;

\(Height, \ h = u \cdot t - \dfrac{1}{2} \cdot g \cdot t^2\)

Where;

g = Acceleration due to gravity

t = Time of motion

When the rod returns to his hand, we have, h = 0, therefore;

\(0 = u \cdot t - \dfrac{1}{2} \cdot g \cdot t^2\)

\(u \cdot t = \dfrac{1}{2} \cdot g \cdot t^2\)

\(t^2 = \dfrac{u \cdot t }{\dfrac{1}{2} \cdot g } = \dfrac{2 \cdot u \cdot t }{g }\)

\(Time, \ t = \dfrac{2 \cdot u }{g }\)

We have;

\(Angular \ velocity, \ \omega_0 = \dfrac{ 2 \cdot \pi \cdot n}{t} \ (required)\)

\(\omega_0 = \dfrac{ 2 \cdot \pi \cdot n}{ \dfrac{2 \cdot v_0 }{g }} = \dfrac{ g \cdot \pi \cdot n}{ v_0 }\)

Therefore;

\(The \ vertical \ velocity, \, \underline{v_0= \dfrac{ g \cdot \pi \cdot n}{ \omega_0 }}\)

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Answer:

2. ( b ) zero

3. ( c ) 10 s

4. Uniform then decreasing

Explanation:

2.

Since the motion is uniform, initial and final velocity will be 0, hence acceleration will be zero.

3.

Initial velocity ( u ) = 5 m/s

Final velocity ( v ) = 35 m/s

Acceleration ( a ) 3 m/s^2

To find : Time ( t )

Formula : -

t = v - u / a

 = 35 - 5 / 3

 = 30 / 3

t = 10 s

Answer:

See below ~

Explanation:

Q2

The uniform circular motion in the movement of object in a circular path with fixed and perpendicular on the direction of the motion acceleration.

Q3

Q4

The vertical component for a projectile by acute angle on the horizontal axis changes from decreasing then increasing velocity.

Answer:

Protons

Explanation:

Answer:   protons

Explanation:        

a. The depth of flow in the pipe is approximately 0.425 m.

b. The critical depth for flow in the pipe is approximately 0.63 m.

c. The flow in the pipe is subcritical.

Pipe diameter (D) = 1 m

Discharge (Q) = 1.5 m³/s

Pipe length (L) = 100 m

Elevation drop (ΔE) = 0.8 m

Manning's roughness coefficient (n) = 0.015

a. To determine the depth of flow in the pipe, we can use the Manning's equation for open channel flow:

Q = (1/n) * A * R^(2/3) * S^(1/2)

Where:

A is the cross-sectional area of flow,

R is the hydraulic radius,

S is the slope of the energy line.

Assuming the flow is uniform, we can calculate the cross-sectional area (A) as:

A = (π/4) * D²

The hydraulic radius (R) is given by:

R = A / P

where P is the wetted perimeter of the flow.

The wetted perimeter (P) can be approximated as the circumference of a full circular pipe:

P = π * D

The slope of the energy line (S) can be determined as:

S = ΔE / L

Now, we can substitute the values into the Manning's equation and solve for the depth (H):

1.5 = (1/0.015) * [(π/4) * D²] * [(A / P)^(2/3)] * [(ΔE / L)^(1/2)]

By substituting the given values, we can solve this equation to find the depth (H) in the pipe, which is approximately 0.425 m.

b. The critical depth (Hc) for flow in the pipe can be calculated using the specific energy equation:

Hc = (Q² / (g * A))^(1/5)

Where g is the acceleration due to gravity. Substituting the values, we find Hc to be approximately 0.63 m.

c. To determine if the flow is subcritical or supercritical, we compare the actual flow depth (H) to the critical depth (Hc). If H < Hc, the flow is subcritical. In this case, since the depth (H) is approximately 0.425 m and the critical depth (Hc) is approximately 0.63 m, the flow in the pipe is subcritical.

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The most precise pipettor cannot be determined solely based on tables, as precision is determined by multiple parameters and depends on the specific experiment being performed.

To determine the most precise pipettor, one would need to look at the average, standard deviation, and coefficient of variation of the results obtained with each pipettor, as well as any systematic biases that might have affected the results.

Precision is a measure of the reproducibility or repeatability of a measurement, and is an important characteristic of laboratory equipment such as pipettors.

To determine the most precise pipettor, multiple parameters need to be considered, including the average, standard deviation, and coefficient of variation of the results obtained with each pipettor, as well as any systematic biases that might have affected the results.

The average is the mean or average value of the results obtained with each pipettor. The standard deviation is a measure of the variability or spread of the results, and is calculated as the square root of the variance. The coefficient of variation is a measure of the relative variability of the results and is calculated as the standard deviation divided by the mean.

The pipettor with the smallest standard deviation or coefficient of variation would be considered the most precise, as this would indicate that the results obtained with that pipettor are the most consistent and reproducible.

However, it is also important to consider any systematic biases that might have affected the results. For example, if one pipettor consistently gives results that are lower than expected, it may be considered less precise even if its standard deviation is smaller.

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Answer:

they may find ways of solving wars without fighting

Explanation:

This is because when the military understand why the other nation is planning a war they can resolve it simply

Answer:

the potential energy is 19.6J

the kinetic energy is 0.0.004J

Explanation:

using the formulas

P.E = mgh while

K.E =mv²/

In the given diagram, the process of generating electricity using a magnetic field is shown.

When you move a magnet around a coil of wire, or a coil of wire around a magnet, the electrons in the wire are pushed out and an electrical current is created.

In the given diagram, when we move the magnet upward, the galvanometer shows the presence of electric current. On the other hand, the galvanometer shows absence of electric current.

Therefore, the correct answer is option D.

"Using a magnetic field to generate electricity."

Answer: 11 meters

Explanation: i'm rlly sorry if i am wrong

Answer:

D. Nuclear energy

Explanation:

A nucleus is the result of nuclear energy if it is split into an other the same result shall happen it being nuclear energy.

The acceleration of gravity on the planet where the spaceship is located is 43.3m/s²

HOW TO CALCULATE ACCELERATION:

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The amount of work done by the ideal gas is 2475J.

The magnitude of the work done when a gas expands is therefore equal to the product of the pressure of the gas times the change in the volume of the gas.

w=−PΔV

The negative sign associated with the above equation indicates that the system loses energy. If the volume increases at constant pressure (ΔV > 0), the work done by the system is negative, indicating that a system has lost energy by performing work on its surroundings.

According to this question, an ideal gas initially at 50.0m³ at 1000.0 Pa expands to a volume of 300.0 m³ after heating. The work done can be calculated as follows:

W = -P∆V

W = - (0.0099 × {300000L - 50000L)

W = - (0.0099 × 250000)

W = 2475J

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Answer:

The magnetic fields of nearby atoms being aligned with each other

Explanation:

took the quiz c:

For a magnetic domain to be formed in a molecule, it follows that the  magnetic fields of nearby atoms are being aligned with each other.

The term magnetic domain refers to the arragement in the magnetic material which allows the material to be magnetic in nature.

For a magnetic domain to be formed in a molecule, it follows that the  magnetic fields of nearby atoms are being aligned with each other.

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Answer:

C

Explanation:

Answer:

C)  The gravity on the Moon is less than the gravity on Earth.

Explanation:

Since Moon is smaller than Earth, any mass on Moon will experience less gravitational force and so that mass will weigh less on Moon.

Answer:

16. An object has a gravitational potential energy 41,772.5 Jof and has a mass of 1550 kg. How high is it above the ground? Plz help

A carpet which is 10 meters long is completely rolled up. When x meters have been unrolled, the force required to unroll it further is given by F(x)=900/(x+1)3 Newtons. The work done unrolling the entire 10-meter carpet is approximately 317.74 joules.

To calculate the work done unrolling the entire carpet, we need to find the integral of the force function F(x) = 900/(x+1)^3 with respect to x over the interval [0, 10]. This will give us the total work done in joules.

The integral is:
∫(900/(x+1)^3) dx from 0 to 10
Using the substitution method, let u = x + 1, then du = dx. The new integral becomes:
∫(900/u^3) du from 1 to 11

Now, integrating this expression, we get:
(-450/u^2) from 1 to 11
Evaluating the integral at the limits, we have:
(-450/121) - (-450/1) ≈ 317.74 joules
Therefore, the work done unrolling the entire 10-meter carpet is approximately 317.74 joules.

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Melting and the formation of magma can be caused by several factors related to plate tectonics:

a. Continental rifts: These occur when tectonic plates pull apart, allowing mantle material to rise and partially melt as it decompresses. This can result in the formation of basaltic magma. b. Continental shelves: The weight of a continental shelf can cause the underlying mantle to partially melt and form magma. c. Transform faults: These are areas where two plates slide past each other, which can cause frictional heating and the partial melting of rock. d. Hot spot volcanoes: These are areas of intense volcanic activity that are not associated with plate boundaries. They occur as a result of a mantle plume rising from deep within the Earth. e. Mid-ocean ridges: These are areas where new oceanic crust is formed as magma rises from the mantle and solidifies. This occurs as a result of decompression melting. f. Subduction zones: These occur where one tectonic plate is forced beneath another, causing it to partially melt as it descends into the mantle. This can result in the formation of andesitic and rhyolitic magma. In summary, melting and the formation of magma can occur due to a variety of plate tectonic processes, including rifts, hot spots, mid-ocean ridges, and subduction zones.

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Answer: The dimensions of a physical quantity are the power to which the fundamental quantities are raised to represent that quantity.

So, the dimension of 'Power' is 1 in mass, 2 in length, and -3 in time.

Answer:

D. 0.276 J

Explanation:

When I solved this, I got 0.275, so I chose the one closest.

To solve:

convert 17 cm and 19.2 cm to 0.17 m and 0.192 m

W(on spring) = 1/2 (0.192 m - 0.17 m)(25N)

                     = 1/2 (.022 m)(25 N)

                     = 0.275

D. 0.276 J

Work is force applied over distance.

Examples of work include lifting an object against the Earth's gravitation, driving a car up a hill, and pulling down a captive helium balloon.

Work is a mechanical form of energy.

The standard unit of work is the joule (J), equivalent to a newton - meter (N · m).

According to the question,

W = Fs

Convert 17 cm and 19.2 cm to 0.17 m and 0.192 m

W = \(\frac{1}{2}\)(0.192 m - 0.17 m)(25N)

    =\(\frac{1}{2}\) (.022 m)(25 N)

     = 0.276 J

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Answer:

at the top of the ramp before dropping in

Explanation:

Potential energy is basically the build up of energy before it's released.

Answer:

The total power they will consume in series is approximately 2.257 W

Explanation:

The connection arrangement of the headlight and the engine starter = Parallel to the battery

The voltage of the battery, V = 12.0 V

The power at which the headlight operates in parallel, \(P_{headlight}\) = 38 W

The power at which the kick starter operates in parallel, \(P_{kick \ starter}\) = 2.40 kW

We have;

P = V²/R

Where;

R = The resistance

V = The voltage = 12 V (The voltage is the same in parallel circuit)

For the headlight, we have;

R₁ = V²/\(P_{headlight}\)  = 12²/38 = 72/19

R₁ = 72/19 Ω

For the kick starter, we have;

R₂ = V²/\(P_{kick \ starter}\) = 12²/2.4 = 60

R₂ = 60 Ω

When the headlight and kick starter are rewired to be in series, we have;

Total resistance, R = R₁ + R₂

Therefore;

R = ((72/19) + 60) Ω = (1212/19) Ω

The current flowing, I = V/R

∴ I = 12 V/(1212/19) Ω = (19/101) A

We note that power, P = I²R

In the series connection, we have;

\(P_{headlight}\) = I² × R₁

∴ \(P_{headlight}\) = ((19/101) A)² × 72/19 Ω = 1368/10201 W ≈ 0.134 W

The power at which the headlight operates in series, \(P_{headlight, S}\) ≈ 0.134 W

\(P_{kick \ starter}\) = ((19/101) A)² × 60 Ω = 21660/10201 W ≈ 2.123 W

The power at which the kick starter operates in series, \(P_{kick \ starter, S}\) ≈ 2.123 W

The total power they will consume, \(P_{Total}\) = \(P_{headlight, S}\) + \(P_{kick \ starter, S}\)

Therefore;

\(P_{Total}\) ≈ 0.134 W + 2.123 W = 2.257 W