Answers
Explanation:
Refer the explanation in the picture
Related Questions
hello humans ~
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explain how eyes get used to darkness after some time?
Answers
It is all about the dilation of pupils. When darkness falls, your pupils enlarge, whereas in daylight, your pupils shrink.
I am joyous to assist you at any time.
A 20 kg child and a 80 kg man are standing 10 meters apart on frictionless ice. How far from the man is the center of mass of the system?
1 meter?
2 meters?
3 meters?
4 meters?
5 meters?
6 meters?
7 meters?
8 meters?
9 meters?
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If you drop a ball off a cliff, it starts out at 0 m/s. after 1 s, it will be traveling at about 10 m/s. if air resistance is removed, what will happen in 2 s?
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The ball dropped of a cliff will have a final velocity of 19.6 m/s at 2s
The free fall formula and the procedure we will use is:
fv = g* t
Where:
fv = final velocityg = acceleration due to gravityt = time takenh = height traveledInformation of the problem:
g = 9.8 m/s².t = 2 svf = ?Applying final velocity formula we get:
fv = g* t
fv = 9.8 m/s² * 2 s
fv = 19.6 m/s
What is free fall?It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.
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what are the contents of register r1 in decimal after executing the following two instructions: (all numbers are hexadecimal. negative numbers are represented with two's complement.) mov r1, eb //moves data (eb) into register r1 mov r2, 57 //moves data (57) into register r2 sub r1, r2 // r1
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The contents of register r1 after executing these instructions is 148 in decimal. To determine the contents of register r1 in decimal after executing the given instructions, let's go through each step.
mov r1, eb: This instruction moves the data "eb" into register r1. Assuming the data is in hexadecimal, "eb" is equivalent to the decimal value 235.
mov r2, 57: This instruction moves the data "57" into register r2. Assuming the data is in hexadecimal, "57" is equivalent to the decimal value 87.
sub r1, r2: This instruction subtracts the value in register r2 (87) from the value in register r1 (235). The result of the subtraction is stored in r1.
Subtracting 87 from 235 gives us 148. Therefore, after executing these instructions, the contents of register r1 in decimal would be 148.
n the given scenario, the contents of register r1 in decimal after executing the instructions "mov r1, eb", "mov r2, 57", and "sub r1, r2" are 148.
The instruction "mov r1, eb" moves the hexadecimal value "eb" into register r1, which is equivalent to the decimal value 235.
The instruction "mov r2, 57" moves the hexadecimal value "57" into register r2, which is equivalent to the decimal value 87.
The instruction "sub r1, r2" subtracts the value in register r2 (87) from the value in register r1 (235). The result, 148, is stored in register r1.
Therefore, the contents of register r1 after executing these instructions is 148 in decimal.
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Write a statement that explains the relationship among velocity, speed, and direction.
Answers
Answer:
velocity is the speed and direction of a moving object
Explanation:
that is basicaly the defention
A long straight conductor carries a current of 100 A. At what distance from the axis is the magnetic field caused by the current equal in magnitude to earth's magnetic field which is 0.5 E-4 T
A) 0.4 m
B) 25 m
C) 2.5 m
D) 4.0 m
Answers
The correct answer is not provided in the given options A, B, C, or D. The distance from the axis at which the magnetic field caused by the current is equal in magnitude to Earth's magnetic field is 125 meters.
To find the distance from the conductor at which the magnetic field caused by the current is equal to the Earth's magnetic field, we'll use the formula for the magnetic field around a long straight conductor:
\(B = (de * I) / (2 * \pi * r)\)
Where B is the magnetic field, μ₀ is the permeability of free space (\(4\pi * 10^-7 Tm/A\)), I is the current, and r is the distance from the conductor. We want to find the value of r when B equals Earth's magnetic field (0.5 x 10⁻⁴ T).
\(0.5 * 10^-4 T = (4\pi * 10^-7 Tm/A * 100 A) / (2 * \pi * r)\)
To solve for r, we can first simplify the equation by cancelling the π terms:
\(0.5 * 10^-4 T = (4 * 10^-7 Tm/A * 100 A) / (2 * r)\)
Now, cancel out the A (Amperes) terms:
\(0.5 * 10^-4 T = (4 * 10^-7 Tm) / (2 * r)\)
Divide both sides by 4 x 10⁻⁷ T:
\(r = (0.5 * 10^-4 T) / (4 * 10^-7 T)\)
Simplify the equation:
r = \(0.5 * 10^3 m / 4\)
r = 500 / 4
r = 125
So, the correct answer is not provided in the given options A, B, C, or D. The distance from the axis at which the magnetic field caused by the current is equal in magnitude to Earth's magnetic field is 125 meters.
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A top sprinter reached his maximum instantaneous velocity of 12.28 meters per second 7.17 seconds after leaving the blocks. Calculate his acceleration. All key steps must be shown.
I am very confused will you please help me!!
Answers
Answer:
Here we will assume two things.
His acceleration is constant until he reaches his maximum velocity and then he stops accelerating.
When he leaves the blocks, his velocity is "zero", meaning that the initial velocity is zero.
Then:
For the acceleration of the sprinter we will have a constant, A:
a(t) = A.
for the velocity we need to integrate over time, we will get
v(t) = A*t + v0
Where v0 is a constant of integration, and this is the initial velocity, as we already said, this will be zero, so the velocity equation is:
v(t) = A*t
We know that at t = 7.17 seconds, his velocity is 12.28m/s
then:
v(7.17s) = 12.28m/s = A*7.17s
12.28m/s/7.17s = 1.71 m/s^2 = A.
The acceleration is: 1.71 m/s^2 for 0 < t < 7.17s
0 m/s^2 for 7.17s < t.
This is because that was his maximum velocity, then after that time he can not accelerate more.
The interior of the Earth is extremely hot. This heat can be brought to the surface by pumping cold water down and then receiving hot water when it comes back up. The water coming from these pumps can be used to generate electrical energy, from geothermal energy.
- Describe two benefits of using geothermal energy as a resource for energy.
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Answer:
Thermal energy and Mechanical
Explanation:
what is momentum of 1.5 kg boulder dropped from a cliff after 3.0 s
Answers
Given :
Mass of object, m = 1.5 kg.
To Find :
The momentum of boulder dropped from a cliff after 3 seconds.
Solution :
Speed of boulder after 3 seconds of free fall is given by :
v = u + gt ( Equation of motion )
v = 0 + 10×3 ( g = acceleration due to gravity )
v = 30 m/s
Now, momentum is given by :
P = m × v
P = 1.5 kg × 30 m/s
P = 45 kg m/s
Therefore, momentum of boulder is 45 kg m/s.
during the resting phase, what is the electric potential energy of a typical na ion outside of the cel
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During the resting phase, the electric potential energy of a typical Na+ ion outside of the cell is higher than inside the cell.
The resting membrane potential is the difference in electric potential between the inside and outside of a cell when the cell is at rest. This potential difference is maintained by the activity of ion channels and ion pumps in the cell membrane. The resting membrane potential of most cells is negative inside with respect to the outside.
For a typical neuron, the resting potential is around -70 mV, which means that the inside of the cell is negatively charged relative to the outside. This difference in charge creates an electric field that can do work on ions that move across the membrane.
In the case of a Na+ ion, the electric potential energy is higher outside the cell because the outside of the cell is more positively charged relative to the inside. This creates an electrochemical gradient that tends to drive Na+ ions into the cell.
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explain the working of a seismograph. with the help of diagram Please answer me fast
Answers
Answer:
Explanation:
Seismograph is an instrument that measures and records details of earthquakes
How does it work???
The instrument is simply a vibrating rod, or a pendulum, which
starts vibrating when tremors occur. A pen is attached to the vibrating system.
The pen records the seismic waves on a paper which moves under it. By studying
these waves, scientists can construct a complete map of the earthquake
Chicago, il is currently in the e climate zone.
a) true
b) false
Answers
Answer:
false
Explanation:
A hydraulic lift is used to raise an automobile of mass 1520 kg. The radius of the shaft of the lift is 8.00 cm and that of the piston is 1.00 cm. How much force must be applied to the piston to raise the automobile?
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To raise the automobile with a hydraulic lift, a force of approximately 19,000 N must be applied to the piston.
In a hydraulic lift, the principle of Pascal's law is applied, which states that pressure applied to an enclosed fluid is transmitted undiminished to all portions of the fluid and the walls of its container. By utilizing this principle, a smaller force applied to a smaller piston can generate a larger force on a larger piston.
In this scenario, the force needed to lift the automobile can be calculated using the formula:
\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)
where \(F_{1}\) is the force applied to the piston, \(A_{1}\) is the area of the piston, \(F_{2}\) is the force generated on the larger piston (required to lift the automobile), and \(A_{2}\) is the area of the larger piston.
Given the radius of the shaft (small piston) as 0.08 m and the radius of the piston as 0.01 m, we can calculate the forces applied and generated as follows:
\(A_{1} = \pi (0.08)^2\\A_{2}= \pi (0.01)^2\)
\(\frac{F_{1}}{A_{1}} =\frac{F_{2}}{A_{2}}\)
Simplifying the equation and substituting the values, we can solve for \(F_{2}\):
\(F_{2}=\frac{F_{1}A_{2}}{A_{1}}\)
Plugging in the values, we find:
\(F_{2}=\frac{F_{1} \pi (0.01)^2 }{ \pi (0.08)^2} \\F_{2}= \frac{F_{1}\times 0.0001}{0.0064} \\F_{2}= 0.015625 \times F_{1}\)
Given that the mass of the automobile is 1520 kg and the acceleration due to gravity is \(9.8 \hspace m/s^{2}\), we can equate \(F_{2}\) to the weight of the automobile:
\(F_{2}= mg\\0.015625\times F_{1}= 1520\times 9.8\)
Solving for \(F_{1}\), we find:
\(F_{1}\approx \frac{1520\times 9.8}{0.015624} \\F_{1} \approx 19072 \hspace N\)
Therefore, a force of approximately 19,000 N must be applied to the piston in order to raise the automobile using the hydraulic lift.
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Learning Goal: To understand that centripetal acceleration is the acceleration that causes motion in a circle. Acceleration is the time derivative of velocity. Because velocity is a vector, it can change in two ways: the length (magnitude) can change and/or the direction can change. The latter type of change has a special name, the centripetal acceleration. In this problem we consider a mass moving in a circle of radius R with angular velocity ω, r⃗ (t)=R[cos(ωt)i^+sin(ωt)j^] =Rcos(ωt)i^+Rsin(ωt)j^. The main point of the problem is to compute the acceleration using geometric arguments. (Figure 1) Part A What is the velocity of the mass at a time t? You can work this out geometrically with the help of the hints, or by differentiating the expression for r⃗ (t) given in the introduction. (Figure 2) Express this velocity in terms of R, ω, t, and the unit vectors i^ and j^. V⃗ (t) = Part Assume that the mass has been moving along its circular path for some time. You start timing its motion with a stopwatch when it crosses the positive x axis, an instant that corresponds to t=0. [Notice that when t=0, r⃗ (t=0)=Ri^. ] For the remainder of this problem, assume that the time t is measured from the moment you start timing the motion. Then the time − t refers to the moment a time t before you start your stopwatch. Part B What is the velocity of the mass at a time − t? Express this velocity in terms of R, ω, t, and the unit vectors i^ and j^. V⃗ (−t) = SubmitMy AnswersGive Up Part C What is the average acceleration of the mass during the time interval from − t to t? (Figure 3) Express this acceleration in terms of R, ω, t, and the unit vectors i^ and j^.
Answers
Part A :The position of the particle in vector form is given by\(r⃗ (t)=R[cos(ωt)i^+sin(ωt)j^]\)where R is the radius of the circle and ω is the angular velocity.The velocity of the particle is given by taking the derivative of the position vector with respect to time.
Taking derivative with respect to time on both side we get \(v⃗ (t)=d/dt R[cos(ωt)i^+sin(ωt)j^]= R[-in(ωt)ωi^+cos(ωt)ωj^]=ωR[-sin(ωt)i^+cos(ωt)j^]v⃗ (t)=ωR[-sin(ωt)i^+cos(ωt)j^]\)Thus the velocity of the mass at a time t is given by \(v⃗ (t)=ωR[-sin(ωt)i^+cos(ωt)j^]\).
Part B :
We have to find the velocity at time -t. The velocity of the particle is given by taking the derivative of the position vector with respect to time. Thus the velocity of the mass at a time -t is given by \(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)
\(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)Part C :
The average acceleration of the particle can be computed using the formulaa = \(Δv/Δt\)The velocity at time t is given by\(v⃗ (t) = ωR[-sin(ωt)i^+cos(ωt)j^]\)
The velocity at time -t is given by \(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)
\(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)The change in velocity over the interval from -t to t is therefore
\(Δv = v(t) - v(-t) = 2ωR[sin(ωt)i^ + cos(ωt)j^]\)
The time interval over which this change occurs is\(Δt = 2t\)Thus the average acceleration of the particle is given by a = \(Δv/Δt = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\)
\(a = Δv/Δt = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\)
The acceleration can be expressed in terms of R, ω, t, and the unit vectors \(i^ and j^\) as \(a = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\).
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What volume is represented by each small tick mark?
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what is accerlation due to gravity??
Answers
Answer:
When an object falls, gravity pulls the object towards the ground and causes the object to accelerate by 9.8m/s each second. Regardless of mass, every object accelerates at the same rate (9.8m/s) when dropped unless there´s air resistance.
An element has a charge of -3, has 8 protons, 11 neutrons, and electrons
Word Bank:
12 5 11 8 13
pls help
Answers
If it’s asking the no of electrons then -
No of electrons =no of protons in an atom of a element ....therefore there are 11 electrons
The speed of an object undergoing constant acceleration increases from 8.0 meters per second to 16.0 meters per second in 10. seconds. How far does the object travel during the 10. seconds?
Answers
Answer:
\( \boxed{d = 120\: meters} \)
Explanation:
Given:
\( v_{0} \) = 8.0 m/s\( v \) = 16.0 m/s\( t \) = 10 seconds\( d \) = ?We can use this equation with the variables given to solve:
\( d \: = \frac{t \: (v + v_{0})}{2}\) →
\( d \: = \frac{(10s) \: ((16.0 \: m/s) + (8.0 \: m/s))}{2} \) →
\( d \: = \frac{(10s) \: (24 \: m/s)}{2} \) →
\( d \: = \frac{(10 \: s \: • \: 24 \: m/s)}{2} \) →
\( d \: = \frac{240 \: m}{2} \) →
\( d \: = 120 \: m \)
The distance traveled by the object in 10 seconds is 120 meters.
Given to us,
Final velocity of the object, \(v= 16\ meter/sec\)
Initial velocity of the object, \(u= 8\ meter/sec\)
Time for traveling, \(t= 10\ sec\)
Using the first equation of motion, we can find out acceleration of the object \(a\),
\(v=u+at\\16=8+a\times 10\\a= 0.8\ meter/sec^2\)
Now using the second equation of motion and putting the value of \(a\),
The distance\((S)\) traveled by the object ,
\(\begin{aligned}S&= ut+\frac{1}{2}at^2\\&= 8\times 10+ \frac{1}{2}\times 0.8\times 10^2\\&= 120\ meters \\\end{aligned}\)
Hence,The distance traveled by the object in 10 seconds is 120 meters.
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El siguiente esquema representa un objeto con un volumen de 2cm^3 sumergido en un recipiente que contiene agua. La densidad del agua es 1 g/cm^3 . Si solo la mitad del objeto se encuentra sumergido, el valor de la masa del agua desalojada por el objeto es de:
Answers
Answer:
Ver explicación
Explanation:
Según los principios de Arquímedes, el empuje hacia arriba de un objeto sumergido en un fluido es igual al peso del fluido desplazado.
Por eso
Empuje hacia arriba = volumen del objeto * densidad del fluido * aceleración debida a la gravedad
Empuje hacia arriba = 2 * 10 ^ -6 / 2 * 1 * 10 ^ 3 * 10
Empuje hacia arriba = 0.01 N
Desde;
Empuje hacia arriba = peso del fluido desplazado
peso del fluido desplazado = 0.01 N
Masa de fluido desplazado = 0.01 N / 10 = 1 * 10 ^ -3 Kg o 1 g
which of the following is suitable to make a cable out of metal?
a. hard
b. insulative
c. ductile
d. elastic
Answers
Reasoning: ductile means able to be drawn out into a thin wire.
Which statement explains the similarity between momentum and kinetic energy of an object?
A. Both are inversely proportional to the mass and velocity of the object.
B. Both are directly proportional to the mass and velocity of the object.
C. Both are inversely proportional to force and displacement.
D. Momentum is directly proportional to the mass of the object and the square of the velocity of the object.
E. Kinetic energy is directly proportional to the mass of the object and the square of the velocity of the object.
Please help asap
Answers
Answer:
B. Both are directly proportional to the mass and velocity of the object.
Answer:
E. Kinetic energy is directly proportional to the mass of the object and the square of the velocity of the object.
Explanation:
I just took the test and it was right. Trust me on this one
What is the % yield if 4 moles of hydrogen is reacted with 3 moles of oxygen and produces 3 moles of water? 2 h2 + o2 2 h2o.
Answers
The percent yield of this reaction is 100%, since 4 moles of hydrogen reacts with 3 moles of oxygen to produce 3 moles of water.
What is moles?Moles in physics refers to the amount of a substance in a given sample. It is expressed as the number of particles, such as atoms, molecules, or ions, in one mole (mol) of a substance. One mole of a substance is equal to 6.022×10^23 particles and is referred to as Avogadro’s number. The mole is the SI (International System of Units) unit for the amount of substance.
The percent yield of this reaction is 100%, since 4 moles of hydrogen reacts with 3 moles of oxygen to produce 3 moles of water. This means that all of the reactants are converted into products, and no reactants are left over.
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Two ideal inductors, L1 and L2, have zero internal resistance and are far apart, so their magnetic fields do not influence each other. (a) Assuming these inductors are connected in series, show that they are equivalent to a single ideal inductor having Leq = L1 + L2. (b) Assuming these same two inductors are connected in parallel, show that they are equivalent to a single ideal inductor having 1/Leq = 1/L1 + 1/L2. (c) What If? Now consider two inductors L1 and L2 that have nonzero internal resistances R1 and R2, respectively. Assume they are still far apart, so their mutual inductance is zero, and assume they are connected in series. Show that they are equivalent to a single inductor having Leq = L1 + L2 and Req = R1 + R2. (d) If these same inductors are now connected in parallel, is it necessarily true that they are equivalent to a single ideal inductor having 1/Leq = 1/L1 + 1/L2 and 1/Req = 1/R1 + 1/R2?
Answers
When Two ideal inductors, L1 and L2, have zero internal resistance and are far apart, so their magnetic fields do not influence each other
(a) When two ideal inductors L1 and L2 with zero internal resistance are connected in series, their inductances add up. This is because the total magnetic flux linkage in the combined system is equal to the sum of the individual flux linkages. Mathematically, Leq = L1 + L2, so they are equivalent to a single ideal inductor with inductance Leq.
(b) When the same inductors are connected in parallel, their equivalent inductance can be found using the formula for parallel connected components: 1/Leq = 1/L1 + 1/L2. This formula shows that the reciprocal of the equivalent inductance is equal to the sum of the reciprocals of the individual inductances.
(c) For inductors L1 and L2 with nonzero internal resistances R1 and R2, when connected in series, their equivalent inductance remains Leq = L1 + L2, as mutual inductance is still zero. The equivalent resistance in series connection is the sum of individual resistances: Req = R1 + R2.
(d) When these inductors with internal resistances are connected in parallel, the formula for equivalent inductance remains the same: 1/Leq = 1/L1 + 1/L2. However, the equivalent resistance formula also follows the parallel connection rule: 1/Req = 1/R1 + 1/R2.
Therefore, it is true that these inductors are equivalent to a single inductor with 1/Leq = 1/L1 + 1/L2 and 1/Req = 1/R1 + 1/R2 when connected in parallel.
How does the freezing method work when separating engine oil from water?
Answers
The freezing method works by exploiting the difference in freezing points between engine oil and water. However, its effectiveness may vary depending on the properties and composition of the mixture.
The freezing method for separating engine oil from water is based on the difference in freezing points between the two substances. Water has a higher freezing point than most engine oils, which means that when a mixture of oil and water is cooled to a temperature below the freezing point of water, the water will freeze while the oil remains in liquid form.
To use this method, the mixture is first placed in a container and then put in a freezer or other cooling device. As the temperature drops, the water in the mixture will begin to freeze, forming ice crystals. These can then be removed by either skimming them off the surface or pouring off the liquid oil, which should be separated from the frozen water.
It's worth noting that this method is not always effective, as some engine oils may have a higher freezing point than water, making it difficult to separate them using this technique. Additionally, it may not be suitable for larger quantities of oil and water or for more complex mixtures containing other substances.
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A wire whose resistance is R is stretched so that its length is tripled while its volume remains unchanged.
Determine the resistance of the stretched wire.
Express your answer in terms of R and appropriate constant
Answers
When a wire is stretched so that its length is tripled, its cross-sectional area decreases by a factor of 3, since the volume of the wire remains the same.
The resistance of a wire is given by the equation:
R = ρ L / A
where R is the resistance, ρ is the resistivity of the wire (a constant that depends on the material), L is the length of the wire, and A is the cross-sectional area of the wire.
If the length of the wire is tripled while its volume remains constant, the cross-sectional area of the wire must decrease by a factor of 3. Therefore, the new cross-sectional area of the wire is 1/3 of its original value.
Let A' be the new cross-sectional area of the wire. Then :--
A' = A / 3
Substituting this expression for A' into the equation for resistance gives:--
R' = ρ (3L) / (A/3) = 9ρL / A
Therefore, the resistance of the stretched wire is 9 times the resistance of the original wire. In terms of the original resistance R, we have:--
R' = 9R
So the resistance of the stretched wire is 9 times the resistance of the original wire.
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Mario golpea el balón con el pie para lanzárselo a Tamara que está situada a 18 m de distancia. El ángulo de salida del balón es de 30° sobre la horizontal y la velocidad a la que sale el balón de la bota de Mario es de 15 mis. ¿A qué altura deberá poner el pie Tamara para hacer el control de la pelota que le envía Mario?
Answers
Answer:
y = 0.99 m
Explanation:
This is a projectile launching exercise, let's start by finding the components of the initial velocity, using trigonometry
cos θ = v₀ₓ / v₀
sin θ = v_{oy} / v₀
v₀ₓ = vo cos θ
v_{oy} = I go sin θ
v₀ₓ = 15 cos 30 = 12.99 m / s
v_{oy} = 15 sin 30 = 7.5 m / s
Let's find the time it takes to travel x = 18 m
x = v₀ₓ t
t = x / v₀ₓ
t = 18 / 12.99
t = 1,385 s
at this point it is at a height of
y = v_{oy} - ½ g t²
y = 7.5 1.385 - ½ 9.8 1.385²
y = 0.99 m
therefore the camera must place the foot 99 cm from the ground
two point charges placed 5 cm aparnt on the xa axis. at what points along the x axis is the potential zero?
Answers
The point where the potential is zero is located at \(x = 5 cm * k * Q1/(Q1 + Q2)\)
The potential at a point in space due to a point charge is given by the equation:
V = k * Q/r
where V is the potential, k is the Coulomb constant \((8.99 x 10^9 N * m^2/C^2)\), Q is the charge, and r is the distance from the point charge to the point where the potential is being calculated.
In this problem, we have two point charges placed 5 cm apart on the x-axis. How about we call the charges Q1 and Q2, and we should assume that Q1 is located at the origin (x = 0) and Q2 is located at x = 5 cm.
The potential at a point along the x-axis is the amount of the potentials due to each of the point charges.
V = k * Q1/r1 + k * Q2/r2
where r1 is the distance from the point to Q1 and r2 is the distance from the point to Q2.
In the event that the potential at a point is zero, the amount of the potential due to each of the point charges is zero.
So, k * Q1/r1 + k * Q2/r2 = 0
To find the points along the x-axis where the potential is zero, we can set the equation above equal to zero and address for x.
r1 = x and r2 = |x - 5 cm|
k * Q1/x + k * Q2/|x - 5 cm| = 0
x = k * Q1/Q2 * |x - 5 cm|
x = k * Q1 * (5 cm - x)/Q2
x = 5 cm * k * Q1/(Q1 + Q2)
In this way, the point where the potential is zero is located at
x = 5 cm * k * Q1/(Q1 + Q2)
This is valid for any point in the x-axis, and these points are called equipotential points.
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why is there a metal grid in a microwave? explain using reference to the em spectrum
Answers
Answer:
Visible light has much smaller wavelengths and can pass through the holes unobstructed. It isn't possible to see (resolve) objects and features smaller than the wavelength of light (electromagnetic radiation) used so this is why the mesh works.
Explanation:
a child jumps on a trampoline. draw energy bar diagrams to show the forms of energy present in the following situations.
a. the child is at the highest point.
b. the child is at the lowest point
Answers
Answer:
a
Explanation:
A ship is travelling due east at 30 km/hr and a boy runs across the deck
in a south west direction at 10 km/hr. Find the velocity of the boy
relative to sea.
Answers
Answer:
Vr = 20 [km/h]
Explanation:
In order to solve this problem, we have to add the relative velocities. We must remember that velocity is a vector, therefore it has magnitude and direction. We will take the sea as the reference measurement level.
Let's take the direction of the ship as positive. Therefore the boy moves in the opposite direction (Negative) to the reference level (the sea).
\(V_{r}=30-10\\V_{r}=20 [km/h]\)