Help please!!
Find the area of the figure!
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Answer:

It's 53, unless you entered the problem wrong then its 5/3

Step-by-step explanation:

Coefficents are the numbers attached to unknown variables

The probability that a randomly selected group of 16 individuals from the campus will be selected is 0.8023 or 80.23%

Based on the sign in the elevator of the college library, the limit of 16 persons and weight limit of 2,500 pounds need to be adhered to. To ensure compliance with both limits, we need to consider both the number of people and their weight.

Assuming that the distribution of weights of individuals on campus is approximately normal with an average weight of 155 pounds and a standard deviation of 29 pounds, we can use this information to estimate the total weight of a group of 16 randomly selected individuals.

The total weight of a group of 16 individuals can be estimated as follows:

Total weight = 16 x average weight = 16 x 155 = 2480 pounds

To determine if this total weight is within the weight limit of 2,500 pounds, we need to consider the variability in the weights of the individuals. We can do this by calculating the standard deviation of the total weight using the following formula:

Standard deviation of total weight = square root of (n x variance)

where n is the sample size (16) and variance is the square of the standard deviation (29 squared).

Standard deviation of total weight = square root of (16 x 29^2) = 232.74

Using this standard deviation, we can calculate the probability that the total weight of the group of 16 individuals is less than or equal to the weight limit of 2,500 pounds:

Z-score = (2,500 - 2,480) / 232.74 = 0.86

Using a standard normal distribution table or calculator, we can find that the probability of a Z-score less than or equal to 0.86 is approximately 0.8023.

Therefore, the probability that a randomly selected group of 16 individuals from the campus will comply with both the number and weight limits in the elevator of the college library is approximately 0.8023 or 80.23%.

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Concept: Proportion, to find the km/h return journer

3 hours to 84 km/hr = 3.5 hours to x km/hr

(since its inverse proportion, multiply the 1st to 2nd and 3rd to 4th)

Inverse proportion: as the other quantities increase, the other one decreases

3 : 84 = 3.5 : x

3(84) = 3.5x

252 = 3.5x                (divide 3.5 both sides)

x = 72

Step-by-step explanation:

Answer:

three hundred fifteen meters per second

Step-by-step explanation:

According to the question a trinomial with a leading coefficient of 3 and a constant term of -5 would be 3x² + x - 5.

A trinomial is a polynomial with three terms is in the form of Ax²+Bx+C, where, A is the leading coefficient of veriable X²,  B is the middle coefficient of x and C is the constant of polynomial.

A trinomial with a leading coefficient of 3 and a constant term of -5.

Here, a=3,c=-5 and consider b=1,

Therefore, a trinomial with a leading coefficient of 3 and a constant term of -5 would be 3x² + x - 5.

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Answer:

1. Slope is 2

2. slope is 1/4

3. Slope is undefined

4. Slope is -1/2

5. slope is 0

6. Slope is 3/2

Step-by-step explanation:

for example:  the y intercept is -3. The next point is (1, -1) you rose 2 and ran (went over) 1. 2/1 is 2

you do the same for all of them.

Undefined is when it goes continuously downward.

the slope is 0 when it is perfectly horizontal.

I hope this helps

0.5kg per foot

Answer:

Step-by-step explanation:

Answer:

See below

Step-by-step explanation:

Odds AGAINST are 3 to5        then odds FOR are  2 to 5

    2/5   = .4 = 40%   chance of winning

Answer:

x2 + 100 = (x + 10i)(x − 10i)

x2 + 36 = (x + 6i)(x − 6i)

16x2 + 9 = (4x + 3i)(4x − 3i)

Step-by-step explanation:

Edmentum Answer

The factors of the expressions have been determined as  ( x +10i) ( x -10i) ,  ( x +6i) (x-6i) ,  (4x + 3i) ( 4x - 3i)

An expression is a mathematical statement consisting of variables , constants and mathematical operators .

The expression given in the question is

x² + 100

x² + 36

16x²2 +9​

by the identity a² -b² = ( a+b)(a-b)

The expressions can be written as

( x² - ( 10i)²)  , (x² - ( 6i)²) , ( (4x)² - ( 3i)²)

It is known that i² = -1

Therefore here the expressions can be written as

( x² - ( 10i)²) = ( x +10i) ( x -10i)

(x² - ( 6i)²) = ( x +6i) (x-6i)

( (4x)² - ( 3i)²) = (4x + 3i) ( 4x - 3i)

Therefore the factors of the expressions have been determined.

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The conclusion is that there is evidence to show that a meaningful difference exists between the average number of ant species found at sites in the two regions.

The data given in the table suggests that the average number of ant species found at sites in Region A is 4.4 while the average number of ant species found at sites in Region B is 5.5. To determine whether there is a statistically significant difference between the average number of ant species found in these two regions, a t-test is needed.

At an alpha value of 0.05, the calculated t-value for this t-test is -3.31. Since this value is less than the critical value of -1.96, the conclusion is that there is evidence to show that a meaningful difference exists between the average number of ant species found at sites in the two regions.

Therefore, the conclusion is that there is evidence to show that a meaningful difference exists between the average number of ant species found at sites in the two regions.

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Based on the given information, the graph represents the relationship between the number of adults present and the maximum number of children allowed on a field trip. Since the trip is allowing for a maximum of 12 children, we will analyze the graph to determine how many adults will be present.

Without the graph, we cannot provide the exact number of adults needed for 12 children. However, once you have the graph in front of you, simply locate the point on the graph where the number of children allowed (y-axis) is equal to 12. Then, trace the point horizontally to the corresponding number of adults on the x-axis. This will give you the number of adults required to supervise the 12 children during the field trip.

Remember to follow any guidelines or ratios that may be established by your school or organization regarding adult-to-child ratios on field trips, as this can impact the number of adults needed for the trip.

this graph represents the maximum number of children that are allowed on a field trip depending on the number of adults present to supervise. a trip is allowing for a maximum of 12 children. how many adults will be present? enter your answer in the box.

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The probability of event A and event B is 6.

Given that, P(A)=6, P(B)=20 and P(A∩B)=6.

P(A/B) Formula is given as, P(A/B) = P(A∩B) / P(B), where, P(A) is probability of event A happening, P(B) is the probability of event B.

P(A/B) = P(A∩B) / P(B) = 6/20 = 3/10

We know that, P(A and B)=P(A/B)×P(B)

= 3/10 × 20

= 3×2

= 6

Therefore, the probability of event A and event B is 6.

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Answer:

April 12th

Step-by-step explanation:

1.  This means that at least one car had a speed of 4 miles per hour, which is the slowest speed observed among the 100 cars.

2.  This means that at least one car had a speed of 48 miles per hour, which is the fastest speed observed among the 100 cars.

3. In the situation of cars passing through a busy intersection, this means that half of the cars had a speed of 26 miles per hour or less.

4.  In the situation of cars passing through a busy intersection, this means that 25% of the cars had a speed of 12 miles per hour or less.

5.  In the situation of cars passing through a busy intersection, this means that 25% of the cars had a speed of 36 miles per hour or higher.

The smallest value in the data set is 4 miles per hour. In the situation of cars passing through a busy intersection, this means that at least one car had a speed of 4 miles per hour, which is the slowest speed observed among the 100 cars.

The largest value in the data set is 48 miles per hour. In the situation of cars passing through a busy intersection, this means that at least one car had a speed of 48 miles per hour, which is the fastest speed observed among the 100 cars.

The median is the middle value in the data set when arranged in ascending order. In this case, since we have 100 data points, the median would be the average of the 50th and 51st values. Looking at the given data, the median would be the average of 24 and 28, which is 26 miles per hour. In the situation of cars passing through a busy intersection, this means that half of the cars had a speed of 26 miles per hour or less.

The first quartile (Q1) represents the lower 25% of the data. To find Q1, we look for the value that separates the lowest 25% of the data. In this case, the first quartile is 12 miles per hour. In the situation of cars passing through a busy intersection, this means that 25% of the cars had a speed of 12 miles per hour or less.

The third quartile (Q3) represents the upper 25% of the data. To find Q3, we look for the value that separates the highest 25% of the data. In this case, the third quartile is 36 miles per hour. In the situation of cars passing through a busy intersection, this means that 25% of the cars had a speed of 36 miles per hour or higher.

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Answer:

\(\frac{\sqrt{3}}{2}\)

Step-by-step explanation:

The quickest way to solve this is to recognize this as a 30-60-90 triangle. The smallest angle is 30 degrees, and the answer is simply cos 30º.

You can also use the pythagorean theorem to find the length of the hypotenuse, then use SOH-CAH-TOA to get the answer.

Answer:

0.4 or 40 Cents.

Step-by-step explanation:

1.20/3 = 0.4

The probability that the customer is a good risk is 0.70 and the probability that the customer is not a poor risk is 0.957.

To calculate the probability of the customer being a good risk, we need to divide the total number of good risk customers (7732) by the total number of customers (11,102). This gives us 7732/11102 = 0.7000. To calculate the probability of the customer not being a poor risk, we can subtract the total number of poor risk customers (949) from the total number of customers (11,102). This gives us 11102-949 = 10,153. We then divide this number by the total number of customers, giving us 10,153/11,102 = 0.9571. Therefore, the probability that the customer is a good risk is 0.70 and the probability that the customer is not a poor risk is 0.9571.

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The 95% confidence interval for the difference in the two means = (-2.56 , 0.16)

What is Confidence Interval?

The mean of your estimate plus and minus the range of that estimate constitutes a confidence interval. Within a specific level of confidence, this is the range of values you anticipate your estimate to fall within if you repeat the test. In statistics, confidence is another word for probability.

Given,

Sample statistics                         size(n)               mean(x)                s.d(s)

Construction site                           16                  x₁ = 5.584               1.812

Undistributed Location                 16                  x₂ = 6.789               1.945

Standard error = 0.665

Degree of freedom = 30

Critical T-value for 95% confidence interval is 2.0423

The 95% confidence interval for the difference in the two means

(construction site - undistributed location)

= x₁ -x₂ ± (t-value) (standard error)

= 5.584 - 6.786 ± (2.0423) (0.665)

= -1.2020 ± 1.358130

= (-1.2020 - 1.358130 , -1.2020 + 1.358130)

= (-2.56 , 0.156)

= (-2.56 , 0.16)

for complete question see the attachment

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Given,

Sample statistics                         size(n)               mean(x)                s.d(s)

Construction site                           16                  x₁ = 5.584               1.812

Undistributed Location                 16                  x₂ = 6.789               1.945

Standard error = 0.665

Degree of freedom = 30

Critical T-value for 95% confidence interval is 2.0423

The 95% confidence interval for the difference in the two means

(construction site - undistributed location)

= x₁ -x₂ ± (t-value) (standard error)

= 5.584 - 6.786 ± (2.0423) (0.665)

= -1.2020 ± 1.358130

= (-1.2020 - 1.358130 , -1.2020 + 1.358130)

= (-2.56 , 0.156)

= (-2.56 , 0.16)

If there are N persons and N-1 options for the number of people with whom every person can shake hands, at least two people have shaken hands with an equal number of people.

A pigeon hole principle would be a counting argument that states "if you have n items to place into m n boxes, then there are at least two items in a single boxes."

Now, according to the question;

There are N persons at a party, some of whom have shaken hands and others who have not. When two people shake hands, it counts to both of them shaking hands with one person.

As a result, it is impossible to tell who initiated the greeting. Then there's the following proposal:

It is said that at least two individuals have shaken hands the same amount of individuals.

Thus,

Although you can shake hands to yourself, an individual can shake hands had between 0 and N-1 persons. That is N different options. If a person had shaken hands to everyone else, then no one has not touched hands with anyone. And the opposite is true.

As a result, the possibilities 0 and N-1 are mutually exclusive. So we're down to N-1 people with whom each individual can shake hands.

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The correct answer is:

X=2

Morty most likely has an external locus of control according to expectancy theory, which suggests that he believes outcomes are determined by external factors and not within his control.

Expectancy theory is a psychological framework that examines individuals' motivation and decision-making processes. It posits that people's motivation to exert effort is influenced by three key factors: expectancy, instrumentality, and valence.

Locus of control is an important concept within expectancy theory and refers to individuals' beliefs about the degree to which they have control over the outcomes in their lives.

In Morty's case, his belief that promotions are completely random and beyond his control indicates an external locus of control.

He perceives promotions as being determined by external factors such as luck or favoritism, rather than his own efforts or abilities.

This belief diminishes his motivation to try hard at work because he does not see a direct link between his performance and the desired outcome of promotion.

Individuals with an external locus of control tend to attribute outcomes to external forces, such as luck or fate, rather than their own actions.

They may feel powerless and have lower motivation to actively pursue their goals or exert effort to achieve desired outcomes.

In Morty's case, his perception that promotions are random suggests that he lacks the belief that his efforts will directly influence his chances of promotion, leading to reduced motivation and a lack of effort in his work.

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Answer:

Step-by-step explanation:

5 less than the product of a number squared and 8, translating the expression:

Answer:

6.4

Step-by-step explanation:

70.4/11

= 6.4

Answer:

\(\huge\boxed{-1}\)

Step-by-step explanation:

\(\frac{-5^2}{(-5)^2}\)

=> \(\frac{-25}{25}\)

=> -1

Answer:

-1

Step-by-step explanation:

-5^2 is -25 because you have to do exponents first, so 5^2 is 25. Add a negative symbol there, it becomes -25.

For the denominator, we do the exact same process, except a little different. Since there are parentheses around the negative five, we have to apply the negative symbol on the 5 before we do the exponents. After, we do -5^2 which is 25 because when you are multiplying negative, you always get a positive.

When we are all done with that, we put the numerator over the denominator to get -25/25, which is equivalent to -1.

Answer:

Step-by-step explanation:

Answer:

x = 11

Step-by-step explanation:

\( \frac{wvu}{wv} = \frac{wg}{wh} \\ \\ \frac{28}{40} = \frac{7}{x = 1} \\ \\ 28(x - 1) = 40 \times 7 \\ \\ 28 \: x - 28 = 280 \\ 28x = 308 \\ x = 11\)

Answer:

a) 4

b) 6

e) -12

f) -8

Step-by-step explanation:

let me know if my answers were incorrect

a. The general solution to the given differential equation is y(x) = c₁x + c₂x² - λ²x⁴/4.

b. The eigenvalue of the system is λ = ±2n, where n is a positive integer.

c. The eigenfunction of the system is y(x) = c₁x + c₂x² - (±2n)²x⁴/4, where n is a positive integer.

d. The first four positive eigenvalues and eigenfunctions are:

  - Eigenvalue λ₁ = 2, eigenfunction y₁(x) = c₁x + c₂x² - 4x⁴/4.

  - Eigenvalue λ₂ = 4, eigenfunction y₂(x) = c₁x + c₂x² - 16x⁴/4.

  - Eigenvalue λ₃ = 6, eigenfunction y₃(x) = c₁x + c₂x² - 36x⁴/4.

  - Eigenvalue λ₄ = 8, eigenfunction y₄(x) = c₁x + c₂x² - 64x⁴/4.

a. To find the general solution to the given differential equation x²y" - 2xy' + 2y + λ²y = 0, we can assume a power series solution of the form y = ∑(n=0 to ∞) aₙxⁿ.

b. By substituting the power series solution into the differential equation, we can solve for λ. This will lead to a characteristic equation that determines the eigenvalue of the system.

c. Substituting the power series solution into the differential equation and solving for the coefficients aₙ will give us the eigenfunction of the system.

d. To compute the first four positive eigenvalues and eigenfunctions, we need to find the corresponding values of λ and the coefficients aₙ by solving the characteristic equation and the equations obtained by substituting the power series solution into the differential equation.

By solving the characteristic equation and the equations for the coefficients aₙ, we can obtain the first four positive eigenvalues and their corresponding eigenfunctions, which will be expressed as power series solutions. These eigenvalues and eigenfunctions will provide insights into the behavior of the system and help analyze its stability and dynamics.

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Answer:

Step-by-step explanation:

Given

The first 5 terms are:

A person will wait at least 1.8720 seconds before the wave crashes when the waves are crashing onto the beach every 4.8 second

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

\(P(X\leq x)\) = x-a / b-a

Uniform distribution from 0 to 4.8 seconds.

This means that a=0 , b=4.8

61% of the time a person will wait at least how long before the wave crashes in?

This is the 100 - 61 = 39% percentile, which is x for which \(P( X\leq x)= 0.39\) . So

\(P(X\leq x)= \frac{x-a}{b-a}\)

x= 1.8720

the time a person will wait at least 1.8720 seconds before the wave crashes in.

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