HELP PLEASE

X P

0 0.03

1 0.13

2 0.70

3 0.10

4 0.04

Use the probability distribution table to answer the question.


P ( 2 < X ≤ 4)


Enter your answer, as a decimal, in the box.

Answer:

look it up :)

Step-by-step explanation:

:)

Answer:

Step-by-step explanation:

For commission on his sales is 7%

He makes a total sales of $ 12500

so 7 / 100 * 12500

it will be $ 875 as his total commission.

Answer:

ok

Step-by-step explanation:

ok

Answer:

niceeeeeee

Step-by-step explanation: even niceeeerrr

Answer:

60

Step-by-step explanation:

bceuase i got it right just multiply

To determine the total grade we mutiply each one by the percentage it represents of the overall grade in decimal form and add them, that is:

Therefore, the overall grade is 69

The rational function is given by y = (x + 3)(x + 1)/(x + 1)(x - 1). To determine the equations of vertical, horizontal, and slant, we need to consider the degree of the numerator and denominator of the rational function.

The degree of the numerator is 2, while that of the denominator is also 2. This means that there is no horizontal asymptote, and we need to consider the leading coefficients of the numerator and denominator to determine the equation of the slant asymptote. Since the degree of the numerator and denominator are equal, there is also no vertical asymptote.

In conclusion, the rational function has a slant asymptote given by y = x + 2. It has no horizontal or vertical asymptotes since the degree of the numerator and denominator are equal.

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The equation of the line perpendicular to line AB is determined as: y = (-5/2)x + 31/2.

To find the equation of a line perpendicular to line AB, we need to determine the slope of line AB and then find the negative reciprocal of that slope.

Given points A(3,8) and B(-2,6), we can calculate the slope of line AB using the formula:

slope = (change in y) / (change in x)

slope = (6 - 8) / (-2 - 3) = -2 / -5 = 2/5

The negative reciprocal of 2/5 is -5/2.

Now we can use the point-slope form of a linear equation to find the equation of the line perpendicular to AB passing through point A (3,8):

y - y₁ = m(x - x₁)

Using the coordinates (x₁, y₁) = (3,8) and the slope m = -5/2, the equation becomes:

y - 8 = (-5/2)(x - 3)

y - 8 = (-5/2)x + (15/2)

Bringing 8 to the other side:

y = (-5/2)x + (15/2) + 8

y = (-5/2)x + 31/2

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1)

x+10<-7

bring 10 to the other side

x<-10-7

x<-17

2)

-3x-4>5

bring -4 to the other side

-3x>9

divide -3 at the other side, since it is negative it changes to less than

x<-3

Let's calculate the products and check if they indeed have the same value:

Product of 32 and 46:

32 * 46 = 1,472

Reverse the digits of 23 and 64:

23 * 64 = 1,472

As you mentioned, the products are the same. This phenomenon is not unique to this particular pair of numbers. In fact, it occurs with any pair of two-digit numbers whose digits, when reversed, are the same as the product of the original numbers.

To find two other pairs of two-digit numbers that have this property, we can explore a few examples:

Product of 13 and 62:

13 * 62 = 806

Reversed digits: 31 * 26 = 806

Product of 17 and 83:

17 * 83 = 1,411

Reversed digits: 71 * 38 = 1,411

As for determining if a given pair of two-digit numbers will have this property without actually performing the multiplication, there is a simple rule. For any pair of two-digit numbers (AB and CD), if the sum of A and D equals the sum of B and C, then the products of the original and reversed digits will be the same.

For example, let's consider the pair 25 and 79:

A = 2, B = 5, C = 7, D = 9

The sum of A and D is 2 + 9 = 11, and the sum of B and C is 5 + 7 = 12. Since the sums are not equal (11 ≠ 12), we can determine that the products of the original and reversed digits will not be the same for this pair.

Therefore, by checking the sums of the digits in the two-digit numbers, we can determine whether they will have the property of the products being the same when digits are reversed.

Answer:

  yes; the distributive property applies to dot products

Step-by-step explanation:

The product of (a-b) with itself is ...

  (a -b)·(a -b) = a² -2ab +b²

because the commutative and distributive properties apply to multiplication.

  (a -b)·(a -b) = a(a -b) -b(a -b) = a² -ab -ba +b² = a² -ab -ab +b² = a² -2ab +b²

__

The same expansion works for the dot product operation, because the commutative and distributive properties hold for that operation, as well.

  (u −v)•(u −v) = u•(u -v) -v•(u -v) = u•u -u•v -v•u +v•v

  = u•u -u•v -u•v +v•v = u•u -(u+u)•v +v•v = u•u -2u•v +v•v

_____

Additional comment

The proof of any of the properties of the dot product relies on expressing the vectors in component form. The distributive property is no exception.

Answer:

-12√3n

Step-by-step explanation:

We want to write this in its simplest form

48 = 16 * 3

√(48) = √16*3

√48 = 4 √3

so we have

-3 * 4 √3n

=

-12√3n

TRUE

The fatal accident rate for young drivers aged 16 to 19 is about four times higher than at night. Two or more passengers of the same age triple the risk of a fatal accident driving a teenager.

An accident in which someone dies. Synonyms: Accident. Type: Collateral damage.

Of the collisions between cars, angled collisions are the most deadly (about 8,000 in 2020). The interactive chart also shows the estimated number of fatalities, injuries, casualties, and all accidents in different types of car accidents.

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Answer:

Step-by-step explanation:

It is given that the area of a circle is 36.43cm² and we have to find the length of the radius.

So, first of we must know this formula :

⇒ πr² = Area(Circle)

Now, Substituting the given values in the formula :

⇒ 3.14 × r² = 36.43

⇒ r² = 36.43/3.14

⇒ r² = 11.60

⇒ r = √11.60

⇒ r = 3.40

Therefore,

Hey ! there

Answer:

Step-by-step explanation:

In this question we are given with area of circle that is 36.43 cm² . And we are asked to find the length of radius of circle rounded to two decimal points .

We know that ,

\( \qquad \quad \frak{Area_{(Circle)} = \pi r {}^{2} } \quad \bigstar\)

Where ,

Solution : -

According to question , area of Circle is equal to 36.43 . So ,

\( \longrightarrow \qquad \: \pi r {}^{2} = 36.43\)

Step 1 : Substituting value of π :

\( \longrightarrow \qquad \:3.14 \times r {}^{2} = 36.43\)

Step 2 : Transposing 3.14 to right side :

\( \longrightarrow \qquad \: r {}^{2} = \cancel{\dfrac{36.43}{3.14} }\)

On dividing 36.43 by 3.14 , We get :

\( \longrightarrow \qquad \: r {}^{2} = 11.60\)

Step 3 : For removing square from r , We are applying root on both sides :

\( \longrightarrow \qquad \: \sqrt{r {}^{ 2 }} = \sqrt{ 11.60}\)

We get :

\( \longrightarrow \qquad \:r = \sqrt{11.60} \)

Step 4 : Finding square root of 11.60 , We get :

\( \longrightarrow \qquad \: \purple{\underline{\boxed{\frak{r = 3.40 \: cm}}}} \)

Answer:

Step-by-step explanation:

$66, if you need an explanation on how then respond back.

1.8 Liters

olivia took out 8 glasses and poured juice from the pitcher.

The capacity of each glass is 3/10 liter.

If there was enough juice for 6 glasses.

This means that the amount of juice will be the total quantity of juice poured in 6 glasses.

Since, capacity of 1 glass= 3/10 liters=0.3 liters

Capacity of 6 glasses= 6×0.3=1.8 liters.

Answer:

12,000

Step-by-step explanation:

You can simply do this in your head by multiplying 3 x 4.

Answer:

0.00694444444444444444444444444444

Rounded to the nearest thousandths: 0.007

Step-by-step explanation:

Use calculator.

Hope this helps!

If not, I am sorry.

For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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Answer:

x = 4.

Step-by-step explanation:

4 - 5x = 12 - 7x

4 - 5x + 7x = 12 - 7x + 7x

4 + 2x = 12

4 - 4 + 2x = 12 - 4

2x = 8

x = 8/2 = 4.

Answer:

4-5x=12-7x

-5x+7x=12-4

2x=8

x=8/2

x=4

Step-by-step explanation:

To find the mean and standard deviation of the corrected pH measurements, we can use the following formulas:

Corrected Mean = (Original Mean + Correction Factor) * Multiplication Factor

Corrected Standard Deviation = Original Standard Deviation * Multiplication Factor

The correction factor is 0.3 and the multiplication factor is 1.4. Therefore, the corrected mean is:

Corrected Mean = (4.8 + 0.3) * 1.4 = 7.14

And the corrected standard deviation is:

Corrected Standard Deviation = 1.2 * 1.4 = 1.68

Therefore, the mean of the corrected pH measurements is 7.14 and the standard deviation is 1.68.

In summary, to find the corrected mean and standard deviation of the pH measurements, we need to add the correction factor (0.3) to the original mean, multiply the result by the multiplication factor (1.4), and multiply the original standard deviation by the multiplication factor. The corrected mean is 7.14 and the corrected standard deviation is 1.68.

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Answer:

Part A: 0

Part B: All real numbers

Step-by-step explanation:

Part A:

We have:

\((6^2)^x=1\)

First, let's evaluate the square:

\(36^x=1\)

Now, what to the xth power will equal 1?

Remember the fact that anything (except for 0) to the zeroth power is 1.

Therefore, our x is 0:

\(36^0=1\)

Part B:

We have:

\((6^0)^x=1\)

Like mentioned previously, anything to the zeroth power is 1. Thus:

\(1^x=1\)

Now, 1 is a special base because 1 to any (real) power is still going to be 1. For example:

\(1^0=1,1^1=1,1^{999},\text{ and } 1^{\pi}=1\)

Therefore, our values of x is all real numbers.

And we're done!

Equate the coefficient of each power of x to zero and solving the resulting recurrence relation which= (n+r)(n+r-1)cₙ + 5cₙ + rcₙ = 0

Frobenius' method is a technique used to solve second-order linear differential equations with a regular singular point. The method involves assuming a power series solution and determining the recurrence relation for the coefficients. Let's apply Frobenius' method to the given differential equations:

a) 2xy" + 5y + xy = 0:

Step 1: Assume a power series solution of the form y(x) = ∑(n=0)^(∞) cₙx^(n+r), where cₙ are the coefficients and r is the singularity.

Step 2: Differentiate y(x) twice to find y' and y":

y' = ∑(n=0)^(∞) (n+r)cₙx^(n+r-1)

y" = ∑(n=0)^(∞) (n+r)(n+r-1)cₙx^(n+r-2)

Step 3: Substitute the power series solution and its derivatives into the differential equation.

2x∑(n=0)^(∞) (n+r)(n+r-1)cₙx^(n+r-2) + 5∑(n=0)^(∞) cₙx^(n+r) + x∑(n=0)^(∞) cₙx^(n+r) = 0

Step 4: Simplify the equation and collect terms with the same power of x.

∑(n=0)^(∞) [(n+r)(n+r-1)cₙ + 5cₙ + rcₙ]x^(n+r) = 0

Step 5: Equate the coefficient of each power of x to zero and solve the resulting recurrence relation.

(n+r)(n+r-1)cₙ + 5cₙ + rcₙ = 0

b) xy" (x + 2)y' + 2y = 0:

Follow the same steps as in part a, assuming a power series solution and finding the recurrence relation.

Please note that solving the recurrence relation requires further calculations and analysis, which can be quite involved and require several steps. It would be more appropriate to present the detailed solution with the coefficients and recurrence relation for a specific case or order of the power series.

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Answer:

1. 3x²+5x-14/(3x-5)(x-1)

2. x=1.23013 and -1.8968

Step-by-step explanation:

cooking like a chef I'm a 5 star michelin :)

do you know where is India

becz I am an Indian

Answer:

2,49/4,10/9

Step-by-step explanation:

\(1.\sqrt{4} =2\\2.\sqrt{x} =3+\frac{1}{2} =\frac{7}{2} \\x=\frac{49}{4} \\3.\sqrt{x} =3+\frac{1}{3} =\frac{10}{3} \\x=\frac{100}{9}\)

Answer:

10 doll dresses

Step-by-step explanation:

Number of doll dresses = Length of fabric ÷ length of yard used for one doll

                                       = 4  ÷ (2/5)

                                       \(= 4 * \frac{5}{2}\\\\= 2 * 5\\= 10\)

Hence, we have identified Q in each of the symbols as alpha radiation, beta radiation, and positron emission radiation.

Given, Each of the following represents a type of radiation. Identify Q in each of the symbols.0 4 0 a. Q b. Qc. e+1 0 4 0 2+1The symbols given represent the type of radiation and we need to identify Q in each of the symbols. Q represents the type of radiation in each of the symbol.

The types of radiation are given below: Symbol: 040 a type of radiation: Alpha radiation Q: Symbol: 0Qb. Q Type of radiation: Beta radiation Q: e+1 040 2+1Type of radiation: Positron emission radiation

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The car's velocity was 12.5 m/s between 2 seconds and 6 seconds, and -5.5714 m/s between 6 seconds and 13 seconds. The car's acceleration was 3.125 m/s^2 between 2 seconds and 6 seconds, and -1.5102 m/s^2 between 6 seconds and 13 seconds.

We are given three position and time data points for a car traveling in a straight-line path relative to its starting point. Let's use this information to determine the car's velocity and acceleration.

First, we can calculate the car's average velocity between each pair of time points:

Between 2 seconds and 6 seconds, the car travels a displacement of 80 meters - 30 meters = 50 meters in a time of 6 seconds - 2 seconds = 4 seconds. Therefore, the average velocity is:

v1 = (80 m - 30 m) / (6 s - 2 s) = 12.5 m/s

Between 6 seconds and 13 seconds, the car travels a displacement of 41 meters - 80 meters = -39 meters (since the car is moving in the opposite direction) in a time of 13 seconds - 6 seconds = 7 seconds. Therefore, the average velocity is:

v2 = (-39 m) / (7 s) = -5.5714 m/s

Note that the negative sign indicates that the car is moving in the opposite direction.

Next, we can use the average velocities to calculate the car's acceleration:

The average acceleration between 2 seconds and 6 seconds is:

a1 = (v1 - 0 m/s) / (6 s - 2 s) = 3.125 m/s^2

The average acceleration between 6 seconds and 13 seconds is:

a2 = (v2 - v1) / (13 s - 6 s) = -1.5102 m/s^2

Note that the negative sign indicates that the car is decelerating (slowing down).

Therefore, the car's velocity was 12.5 m/s between 2 seconds and 6 seconds, and -5.5714 m/s between 6 seconds and 13 seconds. The car's acceleration was 3.125 m/s^2 between 2 seconds and 6 seconds, and -1.5102 m/s^2 between 6 seconds and 13 seconds.

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The book is opened to pages 11 and 12.

How to get the product of the page

x * (x + 1) = 132

Expanding the equation, we get:

x² + x = 132

To solve for x, we need to rewrite the equation as a quadratic equation:

x²+ x - 132 = 0

Now, we can factor the quadratic equation:

(x - 11)(x + 12) = 0

This equation has two solutions for x:

x = 11

x = -12

Since page numbers cannot be negative, we discard the second solution. Thus, the left-hand page number is 11, and the right-hand page number is 11 + 1 = 12.

So, the book is opened to pages 11 and 12.

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Answer:

The answer is below

Step-by-step explanation:

The ratio of Keith's height and his nephew's height is 15:7. Let keith height be x cm and his nephews height be y cm.

\(\frac{x}{y}=\frac{15}{7} \\x=\frac{15}{7}y\)

Keiths height increased by 16% , therefore Keith new height is (100% + 16%) × x = 1.16x

The nephew height is doubled, therefore his new height is 2y.

Given that Keith is now 34 cm taller than his nephew

1.16x = 2y + 34

but x = (15/7)y

\(1.16(\frac{15}{7} )y=2y+34\\\\\frac{87}{35} y=2y+34\\\\\frac{87}{35} y-2y=34\\\\\frac{17}{35}y=34\\ \\y=\frac{34*35}{17}\\ \\y=70\ cm\)

The nephews new height = 2y = 2(70) = 140 cm

Keith new height = 2y + 34 = 140 + 34 = 174 cm

Their total current height = 140 cm + 174 cm = 314 cm