Help!! Please!!!!

Helppp

Answer:

\(y=\frac{7}{2} - 4\)

Step-by-step explanation:

y = mx + b

Where M is the slope and b is the Y-intercept

One strategy that may help Emilio write more fluently is practicing speed writing or shorthand techniques.

Practicing speed writing or shorthand techniques can help Emilio increase his writing speed without sacrificing legibility. Speed writing involves using abbreviations, symbols, and shortcuts to represent words or phrases, allowing for faster transcription of thoughts onto paper.

Shorthand systems, such as Gregg shorthand or Pitman shorthand, provide structured methods for condensing words and phrases into simplified symbols.

By learning and practicing speed writing or shorthand techniques, Emilio can improve his writing efficiency and reduce the time it takes to write a few sentences. This strategy allows him to maintain neatness while increasing his writing speed, enabling him to express his thoughts more fluently.

With regular practice and familiarity, Emilio will become more comfortable with the shorthand system and experience a significant improvement in his writing speed and fluency.

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The inequality equation for the measurements of the rectangular field must satisfy t<225.

If two real numbers or the algebraic expressions are related by the symbols “>”, “<”, “≥”, “≤”, then the relation is called an inequality.

The length of the rectangle is 2t meters

the breadth of the rectangle is 50 meters

The perimeter of the rectangle is given by 2×(length+breadth)

Here the perimeter of rectangle is less than 1km=1000meter

Forming an equation with the given data

2×(2t+50)<1000

2t+50<\(\frac{1000}{2}\)

2t+50<500

2t<500-50

2t<450

t<\(\frac{450}{2}\)

t<225

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The correct question is "A rectangular field has these measurements kim walks around the edge of the field. she walks less than 1km. form and solve an equality to find the possible values of t when length of the field is 2t meters and breadth is 50 meters"

The least integer greater than each number for log₅1/47 = -3

All whole numbers and negative numbers are considered integers. This means that if we combine negative numbers with whole numbers, a collection of integers results.

Let y = log₅1/47

We know, logₐ x = y, only if a^y= x

Therefore, 5^y = 1/47

So, we must find an integer y such that 5 &gt; 1/47

5^y &gt; 1/47

5^{-3} &gt; 1/47

(As, 5² = 25; 5³ = 125) (Since, 5² &lt; 47, the answer will be 5³ as 5³ &gt; 47)In this case, y = -3 will be the least integer to satisfy this inequality.

Therefore, the ultimate answer to the equation is log₅1/47 = -3

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Step-by-step explanation:

3d + 4(d-1) ; d=7

Plug in 7 for d.

3(7) + 4(7-1)

Then multiply and distribute.

21 + 28 - 4

Add like terms.

21 + 24

Add like terms.

45

Hope this is what you were asking for :)

Answer:

Step-by-step explanation:

3d + 4(d – 1)

=3(7) + 4(7 – 1)

=21 + 28 – 4

=21 + 24

=55

Answer:

b > 3

Step-by-step explanation:

\(12b-15>21\\\\12b-15+15>21+15\\\\12b>36\\\\\frac{12b>36}{12}\\\\\boxed{b>3}\)

Hope this helps.

The probability that the second card is a jack given that the first card was a 2 is 52/51.

To calculate the probability that the second card is a jack given that the first card was a 2, we need to consider the remaining cards in the deck after the first card is drawn.

When the first card is drawn and it is a 2, there are 51 cards remaining in the deck, out of which there are 4 jacks.

The probability of drawing a jack as the second card, given that the first card was a 2, can be calculated using conditional probability:

P(Second card is a jack | First card is a 2) = P(Second card is a jack and First card is a 2) / P(First card is a 2)

Since the first card is already known to be a 2, the probability of the second card being a jack and the first card being a 2 is simply the probability of drawing a jack from the remaining 51 cards, which is 4/51.

The probability of the first card being a 2 is simply the probability of drawing a 2 from the initial deck, which is 4/52.

P(Second card is a jack | First card is a 2) = (4/51) / (4/52)

Simplifying the expression:

P(Second card is a jack | First card is a 2) = (4/51) * (52/4)

P(Second card is a jack | First card is a 2) = 52/51

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Step-by-step explanation:

B/-7 = 4

Cross multiple

-7×4 = B

-28 = B

Answer:

-28

Step-by-step explanation:

First, multiply 4*-7= -28.

You're done. B=-28

Hope this helps!

The union of events A and B, denoted by A∪B, contains all outcomes that are in A or B. Option B

In probability theory, events A and B represent sets of outcomes from a given experiment or sample space. The union of two events A and B is the set of all outcomes that belong to either A or B or both. It is formed by combining the elements from both sets without repetition.

Mathematically, the union of events A and B is defined as:

A∪B = {x : x ∈ A or x ∈ B}

This means that any outcome x that is in event A or event B (or both) will be included in the union of A and B.

To illustrate this concept, consider the following example:

Event A: Rolling an even number on a fair six-sided die

A = {2, 4, 6}

Event B: Rolling a number greater than 4 on a fair six-sided die

B = {5, 6}

The union of A and B, denoted by A∪B, will contain all outcomes that are in A or B:

A∪B = {2, 4, 5, 6}

Therefore, option B is the correct choice. The union of events A and B contains all outcomes that are in A or B.

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Answer:

6.2 is an integer

Step-by-step explanation:

Answer

6.2

Step-by-step explanation:

Answer:

Only f(x) has an x-intercept.

All three functions have the same domain values.

Step-by-step explanation:

Given

See attachment for table

Required

Select two correct options

Checking the domain:

The x values represent the domain.

From the attached table, we have:

\(x = \{-4.-3,-2,-1,1\}\)

These values of x apply to the three functions; f(x), g(x) and h(x).

This means that the functions have the same domain

Checking the greatest maximum

The maximum of each function is:

\(f(x) = 1\)

\(g(x) = -4\)

\(h(x) = 2\)

Compare these three values, we have:

\(h(x) > f(x) > g(x)\)

This means that h(x) has the greatest maximum

Checking the x intercept

When a function equals 0, then it has an x intercept

Of the three functions, we have:

\(f(-3) = 0\) --- This represents the x intercept.

Other functions do not have this value.

This means that only f(x) has an x intercept

Answer:

Only f(x) has an x-intercept.

All three functions have the same domain values.

or A and E on edg

Step-by-step explanation:

Lauren got 5 votes in class president election.

Number of votes Lisa got = 36

Let the number of votes of Lauren be x. So, forming the equation between the number of votes of Lisa and Lauren.

36 = x + 6x

Calculating the value of x from mentioned equation

36 = 7x

Rewriting the equation with 7 as denominator

x = 36/7

Performing division on Right Hand Side of the equation

x = 5.14

Rounding off the digits as number of votes will be whole number

x = 5

Based on the mentioned information, Lauren got 5 votes.

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Answer:

B.

Step-by-step explanation:

Answer:

YO THE PICTURE DIFFRENT

Step-by-step explanation:

Answer: y - 3 = -2(x + 2)

The line integral ∫[C] (Pdx + Qdy) over the given curve C consisting of the arc of the parabola y = x² from (0,0) to (1, 1), and the line segment from (1,1) to (0,1) is equal to 2/5.

What is integral?

The value obtained after integrating or adding the terms of a function that is divided into an infinite number of terms is generally referred to as an integral value.

To evaluate the line integral using Green's theorem, we need to find a vector field F = (P, Q) such that ∇ × F = Qₓ - Pᵧ, where Qₓ represents the partial derivative of Q with respect to x, and Pᵧ represents the partial derivative of P with respect to y.

Let's consider F = (P, Q) = (x²y², xy).

Now, let's calculate the partial derivatives:

Qₓ = ∂Q/∂x = ∂(xy)/∂x = y

Pᵧ = ∂P/∂y = ∂(x²y²)/∂y = 2x²y

The curl of F is given by ∇ × F = Qₓ - Pᵧ = y - 2x²y = (1 - 2x²)y.

Now, let's find the line integral using Green's theorem:

∫[C] (Pdx + Qdy) = ∫∫[R] (1 - 2x²)y dA,

where [R] represents the region enclosed by the curve C.

To evaluate the line integral, we need to parameterize the curve C.

The arc of the parabola y = x² from (0, 0) to (1, 1) can be parameterized as r(t) = (t, t²) for t ∈ [0, 1].

The line segment from (1, 1) to (0, 1) can be parameterized as r(t) = (1 - t, 1) for t ∈ [0, 1].

Using these parameterizations, the region R is bounded by the curves r(t) = (t, t²) and r(t) = (1 - t, 1).

Now, let's calculate the line integral:

∫∫[R] (1 - 2x²)y dA = ∫[0,1] ∫[t²,1] (1 - 2t²)y dy dx + ∫[0,1] ∫[0,t²] (1 - 2t²)y dy dx.

Integrating with respect to y first:

∫[0,1] [(1 - 2t²)(1 - t²) - (1 - 2t²)t²] dt.

Simplifying:

∫[0,1] [1 - 3t² + 2t⁴] dt.

Integrating with respect to t:

[t - t³ + (2/5)t⁵]_[0,1] = 1 - 1 + (2/5) = 2/5.

Therefore, the line integral ∫[C] (Pdx + Qdy) over the given curve C consisting of the arc of the parabola y = x² from (0,0) to (1,1), and the line segment from (1,1) to (0,1) is equal to 2/5.

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A) The probability that a person selected at random from the general population is senior citizen who will get the flu this season is 0.017.

B) The probability that a person selected at random from the general population is a person under age 65 who will get the flu this year is 0.207.

C) a) 0.1547 community has 91% senior citizens.

    b) 0.0207 community has 91% senior citizens.

D) a) 0.0884 community has 52% senior citizens.

    b) 0.1104 community has 52% senior citizens.

Probability is a measure of the uncertainty of various phenomena. For example, if you roll a die, the possible outcomes are defined by probabilities. This distribution can be defined using random experiments with uncertain or unpredictable outcomes.

A) (a) The probability that a person selected at random from the general population is senior citizen who will get the flu this season is

                      0.10 x 0.17 = 0.017

(b) The probability that a person selected  randomly from the general population is a person under age 65 who will get the flu this year is

             (1 - 0.10) x 0.23 = 0.9 x 0.23 = 0.207

(c) (a) 0.91 x 0.17 = 0.1547

    (b) (1 - 0.91) x 0.23 = 0.09 x 0.23 = 0.0207

Therefore, 91% senior citizens has 0.1547 flu

        and b) 0.0207 senior citizens are there.

(d) (a) 0.52 x 0.17 = 0.0884

    (b) (1 - 0.52) x 0.23 = 0.48 x 0.23 = 0.1104

Therefore, 52% senior citizens has 0.0884 probability of getting flu.

             b) 0.1104 community has flu.

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The null hypothesis to test for instruments' relevance is option D) H0:π2=0 or π3=0 or π4=0.In order to test the relevance of the instrument, the first stage equation's null hypothesis should be stated as: H0: π2 = 0 or π3 = 0 or π4 = 0.The relevance requirement will be fulfilled if we can refute the null hypothesis.

The null hypothesis will not be rejected if the F-statistic is less than 10.0. However, if the F-statistic is greater than 10.0, the null hypothesis will be rejected, indicating that the variables are relevant and that the instrument satisfies the relevance requirement.In summary, to test for instruments' relevance in TSLS, the null hypothesis of the first stage equation is stated as H0: π2 = 0 or π3 = 0 or π4 = 0.

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For a sample of rating of an automobile manufacturer's van regarding rating of 28.3 miles/gallon (mpg), the Z-test statistic value is equals to the -1.631.

Z-test is a parametric test. When the sample size is sufficiently large, it is mostly used. This test statistic is computed a standard normal distribution. It is then compared with the critical value (obtained from z-table). If the test statistic value is greater than it, there is evidence to reject the null hypothesis. We have an automobile manufacturer with its van rating. A sample of 200 vans is randomly considered. Sample size, n = 200

Mean of rating = 28

Standard deviations = 2.6

Lavel of significance= 0.01

To test the firm'claim we have to consider hypothesis testing here. Since it is claimed by an automobile manufacturer that its car has a 28.3 miles/gallon (MPG) rating, therefore, the null hypothesis and alternative can be stated as:

\(H_0 :μ = 28.3\)

\(H_a :μ≠28.3\)

Now, to determine the value of the test statistic, consider the Z-test : \( z = \dfrac{{M - \mu }}{{\dfrac{\sigma }{{\sqrt n }}}}\)

where, M -> mean

n --> sample size

Substitute all known values in above formula, \(= \dfrac{{28 - 28.3}}{{\dfrac{{2.6 }}{{\sqrt {200} }}}}\\\)

\(= \dfrac{{-0.3}}{{\dfrac{{0.26 }}{{\sqrt {2} }}}}\\\)

=> z = - 1.631

Hence, required test statistic value is -1.631.

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If the value of the coefficient of the x² term when the expression (3.5x²-5+2x) is multiplied by (-5x -0.75) . The coefficient of the x² term is -2.625.

When multiplying (3.5x² - 5 + 2x) by (-5x - 0.75), we need to discover the product of the parts that contain x² in order to determine the coefficient of the x² term.

Now let  write out the product of the two polynomials:

(3.5x² - 5 + 2x) × (-5x - 0.75)

= -17.5x³ - 2.625x² + 25x + 3.75

So,

The x² term's coefficient which is -2.625 is the coefficient of the term that contains x².

Therefore the coefficient is  -2.625.

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The missing value of "a" is 2.5.

To find the value of "a", we can use the fact that "m" is the midpoint of segment "fg".

Given that "fm" = 8a + 1 and "fg" = 42, we can set up the equation:

fm = fg / 2

Substituting the given values, we get:

8a + 1 = 42 / 2

Simplifying the right side of the equation, we have:

8a + 1 = 21

To isolate "a", we can subtract 1 from both sides:

8a = 21 - 1
8a = 20

Now, we can solve for "a" by dividing both sides by 8:

a = 20 / 8
a = 2.5

Therefore, the missing value of "a" is 2.5.

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Answer:

BET

Step-by-step explanation:

70, GIVE ME BRAINLIESt

Answer:

12.2 yards

Step-by-step explanation:

pyhtarogem therom A^2 +b^2=c^2 a=36 c=38 so 38^2-36^2=12.2^2

Descriptive statistics is a branch of statistics that deals with the collection, analysis, interpretation, and presentation of data. It focuses on summarizing and describing the characteristics of a sample or population. The purpose of descriptive statistics is to provide a clear and concise summary of the data, including measures of central tendency, variability, and distribution.

True,This information can be used to make inferences about the population as a whole. Therefore, descriptive statistics helps statisticians to better understand and interpret the population data.

False, Descriptive statistics is a branch of statistics that focuses on summarizing and organizing data from a sample or population. It provides insights into the basic features of the data, such as the mean, median, and standard deviation, but does not make inferences about the population.

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The sum of the first 2021 positive even integers is (2021 x 2022). Therefore, Ray's sum exceeds Pat's sum by 2052.

The sum of the first 2021 positive even integers is given by 2+4+6+...+4040. To find this sum, we can use the formula for the sum of an arithmetic series:

S = (n/2)(a + l)

where S is the sum of the series, n is the number of terms, a is the first term, and l is the last term. In this case, n = 2021, a = 2, and l = 4040 (which is the 2021st even integer). So we have:

S = (2021/2)(2 + 4040)

= 2041210

Therefore, Pat's sum is 2041210.

The sum of the first 2022 positive even integers is given by 2+4+6+...+4042. Using the same formula as above, we have:

S = (2022/2)(2 + 4042)

= 2043262

Therefore, Ray's sum is 2043262.

To find by how much Ray's sum exceeds Pat's sum, we can subtract Pat's sum from Ray's sum:

2043262 - 2041210 = 2052

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Answer:

49

Step-by-step explanation:

Answer:

98/2=49

Hence, 49 is doubled to get 98.

Step-by-step explanation:

The solution to the systems of equations graphically is (2, 4)

From the question, we have the following parameters that can be used in our computation:

y = 2x

y = -x + 6

Next, we plot the graph of the system of the equations

See attachment for the graph

From the graph, we have solution to the system to be the point of intersection of the lines

This points are located at (2, 4)

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Total 56, integers are remained if all multiples of 4 and all multiples of 5 are removed from the set of integers from 1 through 100.

We have given that,

from the set of first 100 integers numbers, all the multiples of 5 and 4 are removed.

According to the question,

The multiples of 4 upto 100,

S = { 4, 8, 12......, 96}

it is an Arithmetic progression sequence with

a = 4 , l = 96 , d = 4

using an = a + (n-1)d where

n --> number of terms in sequence

d ---> common difference between two consecutive terms

a ---> first term

=> 96 = 4 + (n-1)4

=> (n-1) = 92/4

=> n = 23 + 1 = 24

Total multiples of 4 upto 100 is 24 .

Now, multiples of 5 upto 100

Q = { 5, 10, 15, ....,100}

Similarly as for above case

a = 5 , d = 5 , l = 100

=> 100 = 5 + (n-1)5

=> (n-1)5 = 95

=> n-1 = 19

=> n = 20

Total multiples of 5 upto 100 is 20.

Remained integers upto 100 = 100 - 20 -24

= 56

Hence, the required number of integers are 56.

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Answer:

i think 5

Step-by-step explanation:

because its 120 degree on the top so i think its 5 and if i'm wrong than sorry