Answer:
ok
Step-by-step explanation:
235 x 26 = estimate the answer
Answer:
6110
Step-by-step explanation:
(ECONOMICS- sorry there’s no button for it )
What motivates producers and consumers in the black market
The motivations for producers and consumers in the black market are largely driven by financial incentives and a desire to avoid legal consequences.
The black market refers to the illegal trade of goods and services that are not permitted by law, such as drugs, counterfeit items, and stolen goods. Producers and consumers in the black market are motivated by a variety of factors, including:
High profits, Producers in the black market can earn higher profits than they would in legal markets due to the lack of regulation and taxes.
Escaping legal consequences: Producers and consumers may participate in the black market to avoid legal consequences, such as fines or imprisonment, for engaging in illegal activities.
Limited availability, Some goods and services are only available on the black market due to legal restrictions or limited supply.
Low prices, Consumers in the black market can often purchase goods and services at lower prices than in legal markets due to the lack of taxes and regulations.
Desire for anonymity, The black market can provide anonymity for both producers and consumers, allowing them to engage in illegal activities without fear of detection or retribution.
However, participating in the black market also comes with significant risks, including the possibility of arrest, fines, and even violence.
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How many schools have fewer than 50 classrooms
Answer:
7 schools have fewer than 50 classrooms.
Evaluate the expression below when
X = 4 and y = (-3)
4x + 2xy
Step-by-step explanation:
4x + 2xy=
4×4 + 2×4×-3
= 16 + (-24)
= - 8
In a data distribution that is skewed left.
The median will be greater than the mean in a left-skewed distribution
We have,
In statistics, skewness is a measure of the asymmetry of a probability distribution around its mean.
A distribution is said to be skewed left if it has a long tail on the left side and the bulk of the data is on the right side.
When the data is skewed left, it means that the distribution is being pulled towards the left side.
This is because there are a few extreme values on the left side that are pulling the mean in that direction.
In contrast, the median is the middle value of the dataset, and it is not influenced by outliers.
For a left-skewed distribution,
The median will be greater than the mean because the mean is being pulled towards the left by the few extreme values.
In a data distribution that is skewed left, the mean will be less than the median.
This is because the mean is sensitive to outliers and is pulled towards the direction of the skewness, while the median is not affected by extreme values and is a more robust measure of central tendency.
Therefore,
The median will be greater than the mean in a left-skewed distribution
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Need help with precalc please! Thank you!
que es eso ._ .wooooooooo .
A hypothetical population consists of eight individuals ages 13, 14, 17, 20, 21, 22, 24, & 30 years.
Complete Question
A hypothetical population consists of eight individuals ages 13 14 17 20 21 22 24 30 years.
A: what is the probability that a person in this population is a teenager?
B: what is the probability of selecting a participant who is at least 20 years old?
We have that probability that a person in this population is a teenager and probability of selecting a participant who is at least 20 years old is
From the question we are told
A hypothetical population consists of eight individuals ages 13, 14, 17, 20, 21, 22, 24, & 30 years.
P(T)=0.38P(T')=0.63a)
Generally the equation for the probability that a person in this population is a teenager is mathematically given as
\(P(T)=\frac{no of teens}{n}\\\\P(T)=\frac{3}{8}\)
P(T)=0.38
b)
Generally the equation for the probability of selecting a participant who is at least 20 years old is mathematically given as
\(P(T)=\frac{ participants\ who\ is\ at\ least\ 20\ years old}{n}\\\\P(T)=\frac{5}{8}\)
P(T')=0.63
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Find the domain and range of the relation. Also determine whether the relation is a function.
{(6,3), (8,5), (-4,-4), (5,5)}
The domain is:
D: {-4, 5, 6, 8}
The range is:
R: {-4, 3, 5}
And yes, the relation is a function.
How to determine the domain and range?
For a relation that maps elements x into elements y (in the form (x, y)), we define the domain as the set of the inputs (values of x) and the range as the set of the outputs (values of y).
Here our relation is defined by: {(6,3), (8,5), (-4,-4), (5,5)}
The domain is the set of the first values of each pair, so we have:
D: {-4, 5, 6, 8}
The range is the set of the second values of each pair:
R: {-4, 3, 5}
Now, is this a function?
Yes, it is a function, because each input is mapped into only one output.
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Mary borrowed $3,000 from the bank with a simple interest rate of 6%
How much interest will Mary owe after one year?
How much interest will Mary owe after four years?
How much will Mary need to pay the bank after four years to completely pay off the loan?
Answer:
She will owe $180 of interest after one year.
She will owe $720 of interest after four years.
She will need to pay the bank $3,720 to completely pay off the loan.
Step-by-step explanation:
Hello I need help with my math please I need help with question to A and b thanks
Step-by-step explanation:
for what question ?
just in case, always remember Pythagoras
c² = a² + b²
with c being the Hypotenuse, a and b are the legs.
then there is the law of sine
a/sin(A) = b/sin(B) = c/sin(C)
a,b,c being the sides opposite of the A, B, C angles.
and as always : the sum of all angles in a triangle is always 180°.
1.
a)
angle A = 180 - 90 - 35 = 55°
a/sin(55) = 15/sin(90) = 15
a = 15×sin(55) = 12.28728066... m
b)
angle A = 180 - 90 - 25 = 65°
250/sin(65) = b/sin(90) = b = 275.8444797...
2.
a)
remember the trigonometric triangle with the up/down leg being sine (multiplied by the circle radius, which is the Hypotenuse of the triangle), and the left/ right leg being cosine (again multiplied by the Hypotenuse).
5 = 12×sin(x)
sin(x) = 5/12 = 0.416666666...
x = 24.62431835...°
b)
the same principle as for a), just now we need cosine.
12 = 15×cos(x)
cos(x) = 12/15 = 4/5 = 0.8
x = 36.86989765...°
3.
AB² = 125² + 65² = 15625 + 4225 = 19850
AB = sqrt(19850) = 140.890028... cm
angel C = 90°
125/sin(B) = 65/sin(A) = 140.890028.../sin(90)
sin(B) = 125/140.890028... = 0.887216801...
angle B = 62.52556837...°
angle A = 180 - 90 - 62.52556837... = 27.47443163...°
Find the length of side AB. Round to the nearest hundredth inch.
The value of length of side AB is,
⇒ AB = 5 units
We have to given that;
The figure is shown a trapezoid.
Hence, By using Pythagoras theorem we get;
⇒ AB² = 4² + (5.25 - 2.25)²
⇒ AB² = 16 + 3²
⇒ AB² = 16 + 9
⇒ AB² = 25
⇒ AB = √25
⇒ AB = 5 units
Therefore, The value of length of AB is,
⇒ AB = 5 units
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Categorize the graph as linear increasing, linear decreasing, exponential growth, or exponential decay. A. Linear increasing B. Linear decreasing C. Exponential growth D. Exponential decay
The graph in this problem is characterized as follows:
C. Exponential growth.
How to characterize the graph?First we must look at the format of the graph, which is a curve with an asymptote and not a line, meaning that it represents an exponential function.
Then we observe that the function is increasing, hence it represents an exponential growth function.
Missing InformationThe problem is given by the image presented at the end of the answer.
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Your firm purchases a business copier that costs $14,000 and requires $3,000 in maintenance for each year of its four-year life. After four years, the copier will be replaced. The copier falls into the MACRS three-year class life category. Use table 12.8 on page 415 in your textbook for DDB depreciation. If the tax rate is 32 percent, whats the depreciation tax shield for this project in year 4?
Answer:
The depreciation tax shield for this project in year 4 is $178.24.
Explanation:
To calculate the depreciation tax shield for this project in year 4, we need to first determine the depreciation expense for year 4 using the MACRS three-year class life category and the double-declining balance (DDB) method.
From Table 12.8 on page 415 of the textbook, we can see that the depreciation rate for year 1 is 33.33%, for year 2 it is 44.45%, for year 3 it is 14.81%, and for year 4 it is 7.41%.
Using the DDB method, we can calculate the depreciation expense for each year as follows:
Year 1: Depreciation expense = $14,000 x 33.33% = $4,667
Year 2: Depreciation expense = ($14,000 - $4,667) x 44.45% = $3,554
Year 3: Depreciation expense = ($14,000 - $4,667 - $3,554) x 14.81% = $830
Year 4: Depreciation expense = ($14,000 - $4,667 - $3,554 - $830) x 7.41% = $557
The total depreciation expense over the four years is the sum of the individual year's depreciation expenses, which is:
$4,667 + $3,554 + $830 + $557 = $9,608
Now, we can calculate the depreciation tax shield in year 4. The depreciation tax shield is the amount of the depreciation expense that reduces the firm's taxable income, multiplied by the tax rate. In year 4, the depreciation tax shield is:
Depreciation tax shield = Depreciation expense in year 4 x Tax rate
Depreciation tax shield = $557 x 32% = $178.24
Therefore, the depreciation tax shield for this project in year 4 is $178.24.
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If UV=5x, VW = 8x - 17, and UW = 11x+11, what is UW
Answer:
UW=165
Step-by-step explanation:
UV + VW =UW
5x + 8x-17= 11x +11
13x - 17 = 11x + 11
Subtract 11x and add 17 to both sides:
2x= 28
Divide 2 both sides:
x=14
Plug in x to the equation of UW:
11 (14) +11
165
5-9.5= whats the awser to make the eqation true
Answer:
-4.5Step-by-step explanation:
5-9.5= whats the awser to make the eqation true
5 - 9.5 = -4.5
Answer:
its -4.5 so I hope this helps you out
solve the PDE using separation of variables method Uxx = 1/2 Ut 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)
The general solution of the partial differential equation is:
U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)
How to solve Partial Differential Equations?The partial differential equation (PDE) is given as:
Uxx = (1/2)Ut with the boundary and initial conditions as 0< X <3 with U(0,t) = U(3, t)=0, U(0, t) = 5sin(4πx)
Assume that the solution can be written as a product of two functions:
U(x, t) = X(x)T(t)
Substituting this into the PDE, we have:
X''(x)T(t) = (1/2)X(x)T'(t)
Dividing both sides by X(x)T(t), we get:
(X''(x))/X(x) = (1/2)(T'(t))/T(t)
Since the left side only depends on x and the right side only depends on t, both sides must be equal to a constant, denoted as -λ²:
(X''(x))/X(x) = -λ²
(1/2)(T'(t))/T(t) = -λ²
Simplifying the second equation, we have:
T'(t)/T(t) = -2λ²
Solving the second equation, we find:
T(t) = Ce^(-2λ²t)
Applying the boundary condition U(0, t) = 0, we have:
U(0, t) = X(0)T(t) = 0
Since T(t) ≠ 0, we must have X(0) = 0.
Applying the boundary condition U(3, t) = 0, we have:
U(3, t) = X(3)T(t) = 0
Again, since T(t) ≠ 0, we must have X(3) = 0.
Therefore, we can conclude that X(x) must satisfy the following boundary value problem:
X''(x)/X(x) = -λ²
X(0) = 0
X(3) = 0
The general solution to this ordinary differential equation is given by:
X(x) = Asin(λx) + Bcos(λx)
Applying the initial condition U(x, 0) = 5*sin(4πx), we have:
U(x, 0) = X(x)T(0) = X(x)C
Comparing this with the given initial condition, we can conclude that T(0) = C = 5.
Therefore, the complete solution for U(x, t) is given by:
U(x, t) = Σ [Aₙsin(λₙx) + Bₙcos(λₙx)]*e^(-2(λₙ)²t)
where:
Σ represents the summation over all values of n
λₙ are the eigenvalues obtained from solving the boundary value problem for X(x).
To find the eigenvalues λₙ, we substitute the boundary conditions into the general solution for X(x):
X(0) = 0: Aₙsin(0) + Bₙcos(0) = 0
X(3) = 0: Aₙsin(3λₙ) + Bₙcos(3λₙ) = 0
From the first equation, we have Bₙ = 0.
From the second equation, we have Aₙ*sin(3λₙ) = 0. Since Aₙ ≠ 0, we must have sin(3λₙ) = 0.
This implies that 3λₙ = nπ, where n is an integer.
Therefore, λₙ = (nπ)/3.
Substituting the eigenvalues into the general solution, we have:
U(x, t) = Σ [Aₙ*sin((nπ/3)x)]*e^(-(nπ/3)²t)
where Aₙ are the coefficients that can be determined from the initial condition.
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Solve the following problems using the Polygon Interior Angle Sum Theorem and Polygon Exterior Angle Sum Theorem.
Sum of the measures of the interior angles of the regular nonagon
Measure of each interior angle of the regular nonagon
Measure of each exterior angle of the regular nonagon
a) The sum of the measures of the interior angles of the regular nonagon is given by S₉ = 1260°
b) The measure of each interior angle of the regular nonagon is a = 140°
c) The measure of each exterior angle of the regular nonagon is b = 40°
Given data ,
Sum of the measures of the interior angles of a regular nonagon:
The Polygon Interior Angle Sum Theorem states that the sum of the measures of the interior angles of a polygon with n sides is given by the formula:
Sum of interior angles = (n - 2) * 180°
For a nonagon, which has 9 sides, we can plug in n = 9 into the formula:
Sum of interior angles = (9 - 2) * 180
Sum of interior angles = 7 * 180
Sum of interior angles = 1260°
So, the sum of the measures of the interior angles of a regular nonagon is 1260°
Measure of each interior angle of a regular nonagon:
Since a regular nonagon has 9 sides, we can divide the sum of the interior angles (which we calculated as 1260 degrees) by the number of sides to find the measure of each interior angle:
Measure of each interior angle = Sum of interior angles / Number of sides
Measure of each interior angle = 1260 / 9
Measure of each interior angle = 140°
So, the measure of each interior angle of a regular nonagon is 140°
Measure of each exterior angle of a regular nonagon:
The Polygon Exterior Angle Sum Theorem states that the sum of the measures of the exterior angles of a polygon with n sides is always 360°
Since a regular nonagon has 9 sides, we can divide 360 degrees by the number of sides to find the measure of each exterior angle:
Measure of each exterior angle = 360 / Number of sides
Measure of each exterior angle = 360 / 9
Measure of each exterior angle = 40°
Hence , the measure of each exterior angle of a regular nonagon is 40°
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find the coordinate of point C that is 7/8 of the distance from M to J
Using proportions, and considering that the points are M(x1,y1) and J(x2,y2), the coordinates of C are given by:
C = [7/8(x2 - x1), 7/8(y2 - y1)]
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
We consider that the points are M(x1,y1) and J(x2,y2), hence the point that is at 7/8 of the distance between them is found applying the proportion of 7/8, that is:
C = [7/8(x2 - x1), 7/8(y2 - y1)]
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40 POINTS!
Simplify 3x * 1/x^-4 * x^-3
3x
3x2
3
3x−2
Answer:
\(\sf {3x}^{2} \)
Step-by-step explanation:
\( \rightarrow \sf 3x(\frac{1}{{x}^{-4}}) {x}^{-3} \)
\( \rightarrow \sf \frac{ {3x}^{5} }{ {x}^{3} } \)
\( \rightarrow \sf {3x}^{2} \)
write an equation of a line passing thru the point (-4,-11) and perpendicular to the line 4x+5y= -45
Answer:
y = 5/4x - 6
Step-by-step explanation:
First, put 4x + 5y= -45 in y = mx + b form
4x + 5y= -45
5y = -4x - 45
y = -4/5x - 9
So, the slope is -4/5. Perpendicular lines have a opposite reciprocal slope, so the line's slope will be 5/4
To find the equation of the perpendicular line, plug in the slope and given point into y = mx + b, and solve for b
y = mx + b
-11 = 5/4(-4) + b
-11 = -5 + b
-6 = b
Plug in b and the slope into y = mx + b
y = 5/4x - 6
So, the equation is y = 5/4x - 6
what is the result of the following division 2x3 3x 5 x 3
63:
2x3=6
3x5=15
6+15=21
x 3 =…
63
Step-by-step explanation:
PQ=2x+1 and QR=5x-44; Find PR
Answer:
x=15
Step-by-step explanation:
subtract 1 from both sides so you are left with 2x=5x-45
then subtract 5x from both sides and you have -3x=-45
then finally divide -3 from -45 to get x=15
√-25/√9 please solve
Step-by-step explanation:
The expression you provided involves taking the square root of a negative number, which results in an imaginary number. In standard real number arithmetic, the square root of a negative number is undefined. However, in the realm of complex numbers, we can define a square root of negative numbers using the imaginary unit "i," where i is defined as the square root of -1.
Let's break down the expression step by step:
√(-25) / √9
The square root of -25 can be written as √(-1 * 25), which can further be simplified as √(-1) * √25.
√(-1) is equal to "i," and the square root of 25 is 5.
So, the expression becomes:
i * 5 / √9
The square root of 9 is 3.
Now, we can simplify further:
i * 5 / 3
Thus, the simplified expression is (5i) / 3, where "i" represents the imaginary unit.
The expression: 4xy – 2y(x + 1) can be simplified to
Answer:
2. 2xy-2y
Step-by-step explanation:
4xy-2y(x+1)=4xy-2xy-2y
=2xy-2y
Joanna ran a mile in physical education class after resting for 1 hour her heart rate was 60 beats per minute if her heart rate decreased it by 2/5 what was her heart rate and merely after she ran the mile
Answer:Since 2/5 is basically a part of a whole, you would have to divide 60 by 20. You would get thirty. Thirty times five is 150.
Step-by-step explanation:
What is the domain ?
The domain of the given set of functions is (Alex, Alesia, Bob, Yolanda, Maria , Elvis)
What is Domain ?The collection of all potential inputs for a function is its domain. Think of this box as the f(x) = 2x function. The domain is only the collection of natural numbers when the input values are x = 1,2,3,4,..., and the values that are returned are referred to as the range.
The collection of all a function's outputs is its range. Example: Let's have a look at the function f: A-> B, where f(x) = 2x and A and B each represent a "collection of natural numbers." The domain in this instance is A, and the co-domain is B. The range then appears as the function's output.
The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it may take as input. After we enter an x value, the function outputs this sequence of values.
The domain of the given set of functions is (Alex, Alesia, Bob, Yolanda, Maria , Elvis)
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PLSSSS HELPPP I WILL FIVE BRAINLY!!!!
Answer:
The first box : -4 the second one : 6
Step-by-step explanation:
subtract 7 from 3 for the first box, then add 10 to -4 for the second one.
Which word could describe the relationship of the lines
containing the points (1, 6) and (1, 3)?
A) coincident
B) parallel
C) perpendicular
D all of the above
Show that sin⁴x-cos⁴x/ sin²x-cos²x = 1
Proved that, sin⁴x-cos⁴x/ sin²x-cos²x = 1.
Here, we have,
given that,
the LHS is:
sin⁴x-cos⁴x/ sin²x-cos²x
now, we know that,
sin²x+cos²x = 1
and, we know that,
a² - b² = (a+b) (a-b)
so, we get,
sin⁴x-cos⁴x/ sin²x-cos²x
= (sin²x+cos²x) (sin²x-cos²x ) / sin²x-cos²x
=(sin²x+cos²x)
=1
= RHS
Hence, Proved that, sin⁴x-cos⁴x/ sin²x-cos²x = 1
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In country A, there were 131,000 foreign students from country B. This number is 23% more than the number from country C. How many foreign students were from country C
There were a total of 95,082 students from country C.
What is percentage?A percentage in mathematics is a figure or ratiο that is stated as a fractiοn of 100. The abbreviatiοns "pct.," "pct," and "pc" are alsο occasionally used. It is frequently denοted using the percent symbol "%," though. The amοunt of percentages has no dimensions. With a denominatοr of 100, percentages are basically fractiοns.
To shοw that a number is a percentage, place a percent symbol (%) next to it. Fοr instance, if you correctly answer 75 out of 100 questiοns on a test (75/100), you receive a 75%. Tο compute percentages, divide the amount by the tοtal and multiply the result by 100. The percentage is calculated using the fοrmula (value/total) x 100%.
x represents the number οf students from cοuntry C.
then 122percent of x = 116,000
122/100 * x = 116000
x = 116000 * 100/122 = 95,082 students
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