HELP PLEASE, ASAP!!

Evaluate the following when a = 3, b = 1/4 , and c = 5

b^-1/ ca^-1 - ac^-1


Please please help this will mean a lot to me if someone can answer this :(

Answer:

\(y=\frac{3}{10} x-\frac{16}{5}\)

Step-by-step explanation:

Equation for slope:

\(m=\frac{y_{1}- y_{2} }{x_{1}- x_{2} }\)

Substitute in your x and y values:

\(m=\frac{-2+5}{4+6} \\ m=\frac{3}{10}\)

Now write the equation:

\(y=\frac{3}{10} x\)

this is not done yet though since it does not work:

\(-2=\frac{3}{10} *4\\-2=1\frac{1}{5}\)

so we add the y- intercept \(b\) to make the equation equal:

\(-2=1\frac{1}{5}+b\)

From here we solve for \(b\):

\(b=-\frac{16}{5}\)

\(y=\frac{3}{10} x-\frac{16}{5}\)

Answer:

2 3/5

Step-by-step explanation:

The two equations are equivalent and represent the same line since the second equation can be obtained from the first equation by multiplying both sides by 3.

The given equations are:2y = x + 10 ..........(1)3y = 3x + 15 .......(2)

Let us check the properties of the equations given, we get:

Properties of equation 1:It is a linear equation in two variables x and y.

It can be represented in the form y = (1/2)x + 5.

This equation is represented in the slope-intercept form where the slope (m) is 1/2 and the y-intercept (c) is 5.Properties of equation 2:

It is a linear equation in two variables x and y.

It can be represented in the form y = x + 5.

This equation is represented in the slope-intercept form where the slope (m) is 1 and the y-intercept (c) is 5.

From the above information, we can conclude that both equations are linear and have a y-intercept of 5.

However, the slope of equation 1 is 1/2 while the slope of equation 2 is 1, thus the equations have different slopes.

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such pair of equation that have only one pair of solutions which satisfy both equation is linear equation

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Here is ur answer .. (refer image)

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The true statements of the angles of the parallel lines are

a) m∠1 = m∠8

b) m∠6 = m∠7

c) m∠4 + m∠6 = 180°

d) 180° - m∠7 = m∠9 + m∠10

Straight, equally spaced lines that never cross each other and are on the same plane are called parallel lines. The angles that are created when any two parallel lines are intersected by a line (referred to as the transversal) have a relationship. Corresponding angles, Alternate Interior Angles, Alternate Exterior Angles, and Consecutive Interior Angles are some of the several pairs of angles that are created at this intersection.

Corresponding angles

When two parallel lines are intersected by a transversal, the corresponding angles have the same relative position

Alternate Interior Angles

Alternate interior angles are formed on the inside of two parallel lines which are intersected by a transversal.

Alternate Exterior Angles

The pairs of angles formed on either side of a transversal that divides two parallel lines are known as alternate exterior angles.

Consecutive Interior Angles

When two parallel lines are cut by a transversal, the pairs of angles formed on the inside of one side of the transversal are called consecutive interior angles or co-interior angles.

Given data ,

The true statements are

a) m∠1 = m∠8 ( alternate exterior angles )

b) m∠6 = m∠7 ( vertically opposite angles )

c) m∠4 + m∠6 = 180° ( co-interior angles are supplementary )

d) 180° - m∠7 = m∠9 + m∠10 ( triangle exterior angle theorem )

Hence , the angles of the parallel lines are solved

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The unit price in dollars per centimeter is 80 cents.

:: Total wire length = 19.5 cm

:: Total amount paid = $15.60

Per unit price = [ (total amount paid) / (total wire length) ]

Per unit price = (15.60 / 19.5) $/cm

Per unit price = 0.8 ($/cm)

And as we know, $1 = 100 cents,

So,

$0.8 = 0.8 x 100 cents = 80 cents.

Therefore, the unit price in dollars per centimeter is 80 cents.

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Out of the given options, the one that is not an advantage of using a sample versus a census is population size. The reason for this is that whether you use a sample or a census, the population size remains the same. However, there are several advantages to using a sample over a census.

Firstly, a sample generates a smaller dataset to analyze, which can save time and resources. Secondly, using a sample can be less expensive than conducting a census, which involves surveying every member of the population. Lastly, using a sample provides ready access to respondents, as it is often easier to reach a smaller group of people than an entire population. However, it is important to note that using a sample also has its limitations, such as the potential for sampling bias and the need to ensure that the sample is representative of the population being studied. Overall, the choice between using a sample or a census depends on the research question, available resources, and the level of accuracy and precision required.

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Answer:

20 years is the brother

Step-by-step explanation:

quick maths

Answer:

Paul is 20

Step-by-step explanation:

13+7=20 :)

Answer:

3/20

Step-by-step explanation:

We can use the Pythagoras theorem, to solve the right-angled triangle.

What is a right-angled triangle?

A right triangle is a type of triangle that has one 90-degree angle, also known as a right angle. The sides of a right triangle can be classified as the hypotenuse (the side opposite the right angle) and the legs (the two sides that form the right angle).

To solve a right triangle given the length of one leg and the measure of one acute angle, you can use the Pythagorean theorem or trigonometric functions.

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs. This can be written as:

c² = a² + b²

where c is the length of the hypotenuse, and a and b are the lengths of the legs.

Hence, we can use the Pythagoras theorem, to solve the right-angled triangle.

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The value of the coordinate matrix is \(\begin{bmatrix} 2&3 &0 \\ 2& 2 & 6\\ 0& 2 &4 \\0 & 0& 2\end{bmatrix}\)

To find the coordinate matrix LFE, we need to express the images of the basis vectors of E in terms of the basis vectors of F. Let's start with e₁(t) = 1, which is a constant polynomial of degree 0. Applying L to this polynomial gives us L(e₁(t)) = 5(0) + 3(0) + 2(1) + 2t(1) = 2 + 2t. We want to express this polynomial as a linear combination of the basis vectors of F, so we write:

2 + 2t = a₁f₁(t) + a₂f₂(t) + a₃f₃(t) + a₄f₄(t)

where a₁, a₂, a₃, and a₄ are unknown coefficients. We can substitute the definitions of the basis vectors of F to obtain:

2 + 2t = a₁ + a₂t + a₃t² + a₄t³.

This is a system of linear equations in the variables a₁, a₂, a₃, and a₄. We can solve this system to obtain the coefficients as follows:

a₁ = 2

a₂ = 2

a₃ = 0

a₄ = 0

Therefore, the coordinate vector of L(e₁(t)) with respect to the basis F is [2, 2, 0, 0]ᵀ. Similarly, we can find the coordinate vectors of L(e₂(t)) and L(e₃(t)):

L(e₂(t)) = 5(0) + 3(1) + 2t(1) + 2t² = 2t² + 2t + 3

⇒ [L(e₂(t))]ₘ = [3, 2, 2, 0]ᵀ

L(e₃(t)) = 5(2) + 3(2t) + 2t²(1) + 2t(t²) = 2t³ + 4t² + 6t

⇒ [L(e₃(t))]ₘ = [0, 6, 4, 2]ᵀ

Finally, we can arrange these coordinate vectors as columns of a matrix to obtain the coordinate matrix LFE:

LFE = \(\begin{bmatrix} 2&3 &0 \\ 2& 2 & 6\\ 0& 2 &4 \\0 & 0& 2\end{bmatrix}\)

This is a 4x3 matrix because the range space has dimension 4 and the domain space has dimension 3. Each column of the matrix represents the coordinates of the image of a basis vector of E in terms of the basis vectors of F.

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Complete Question:

Let L: P2 → P3 be the linear transformation given by

L(p(t)) = 5p"(t) + 3p'(t) + 2p(t) + 2tp(t).

Let E = (e₁, e₂, e₃) be the basis of P2 given by e₁(t) = 1, e₂(t) = t, e₃(t) = t². and let F = (f₁, f₂, f₃, f₄) be the basis of P3 given by f₁(t) = 1, f₂(t) = t, f₃(t) = t² , f₄(t) =t³".

Find the coordinate matrix LFE of L relative to the ordered bases E and F.

Answer:

10 km in 97 seconds, 8 km in 83 seconds, 18 km in 198 seconds, 15 km in 168 seconds.

Step-by-step explanation:

The unit rate for each session can be found by dividing the kilometers by the seconds. Then, make an equivalent fraction by dividing both the numerator and denominator by the numerator. This will show how many seconds it took to finish 1 kilometer during that session.

Answer:

Step 1: Steps for construction

Take AB at 5.5 cm                                    

Step 2: construct as 45 degree  

Step 3: A draw angle ABY=45 degree    

Step 4: cut off from AY, a segment AD=5 cm

Step 5: With B as center and radius as 3.5cm draw an arc.

Step 6: With D as the center and mark radius as 5 cm and draw an arc cut the 1st arc at C

Step 7: join B to C and C to D

Result: Then ABCD is a required quadrilateral  

Hope this helps you hit the crown :D

tell me if correct ok?

9514 1404 393

Answer:

  see the attachment

Step-by-step explanation:

1. Lay out points A and B so they are 5.5 cm apart.

2. Set the compass to 5 cm and draw arcs that intersect above and below segment AB. Label the intersection points Y and Z.

3. Draw segment YZ as a perpendicular bisector of AB.

4. Label the intersection of YZ and AB point E.

5. Using E as the center and AE as the radius, draw an arc that intersects segment YZ at F.

6. Draw segment AD through F. D will lie on the circle of radius 5 cm centered at A. This segment makes 45° angle DAB.

7. Draw an arc of radius 4 cm centered at D through the vicinity of point C.

8. Draw an arc of radius 3.5 cm centered at B through the vicinity of C. The intersection point with the arc of step 7 is point C.

9. Draw quadrilateral ABCD meeting the given requirements.

_____

About the attachment

My geometry tool draws circles of a given radius more easily than arcs of a given radius, so you see circles where only arcs are needed.

The example that illustrates the difference between statistical significance and practial significance is

In a survey arranged by school-authority of a district on participation in sports by school-going boys and girls, it is found that 60% of boys and 57% of girls participate in outdoor sports. Thus the survey shows a 3% difference between school-going boy-participants and girl-participants in outdoor sports. Now the point is how much significance this 3% difference has statistically as well as practically. Statistical significance of this 3% depends upon the size of data used in determining the percentage of boys and girls participate in sports. If a sufficiently big sample size is used then the difference is statistically significant, and if a very small sample size is used then the difference is statistically insignificant. Thus bigger the sample size more is the statistical significance of a computed figure.

On the other hand practical significance of this 3% difference arises if decision is made or action is taken or needs to be taken on the basis of this 3% difference. If cost permits, the authority may consider promoting girl students participation in sports in order to bring about more gender parity in outdoor sports. In this case the 3% difference though small, may be practically significant.

Statistical significance is a measure of whether your research findings are meaningful. It is concerned with whether a research result is due to chance or sampling variability. Where, practical significance is concerened with wheteher the result is useful in the real world.

Therefore, the example that illustrates the difference between statistical significance and practial significance is

In a survey arranged by school-authority of a district on participation in sports by school-going boys and girls, it is found that 60% of boys and 57% of girls participate in outdoor sports. Thus the survey shows a 3% difference between school-going boy-participants and girl-participants in outdoor sports. Now the point is how much significance this 3% difference has statistically as well as practically. Statistical significance of this 3% depends upon the size of data used in determining the percentage of boys and girls participate in sports. If a sufficiently big sample size is used then the difference is statistically significant, and if a very small sample size is used then the difference is statistically insignificant. Thus bigger the sample size more is the statistical significance of a computed figure.

On the other hand practical significance of this 3% difference arises if decision is made or action is taken or needs to be taken on the basis of this 3% difference. If cost permits, the authority may consider promoting girl students participation in sports in order to bring about more gender parity in outdoor sports. In this case the 3% difference though small, may be practically significant.

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Let X be a geometric random variable with parameter p = and let Y be a Poisson random variable with parameter A 4. Assuming X and Y independent, then the expected value of the perimeter of the rectangle is 2( + 5), and the expected value of the area is 5.

For the expected values of the perimeter and area of the rectangle, we need to calculate the expected values of X and Y first, as well as their respective distributions.

We have,

X is a geometric random variable with parameter p =

Y is a Poisson random variable with parameter λ = 4

X and Y are independent

For a geometric random variable with parameter p, the expected value is given by E(X) = 1/p. In this case, E(X) = 1/p = 1/.

For a Poisson random variable with parameter λ, the expected value is equal to the parameter itself, so E(Y) = λ = 4.

Now, let's calculate the expected values of the perimeter and area of the rectangle using the given side lengths X and Y + 1.

Perimeter = 2(X + Y + 1)

Area = X(Y + 1)

To find the expected value of the perimeter, we substitute the expected values of X and Y into the equation:

E(Perimeter) = 2(E(X) + E(Y) + 1)

            = 2( + 4 + 1)

            = 2( + 5)

To find the expected value of the area, we substitute the expected values of X and Y into the equation:

E(Area) = E(X)(E(Y) + 1)

       = ( )(4 + 1)

       = 5

Therefore, the expected value of the perimeter of the rectangle is 2( + 5), and the expected value of the area is 5.

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The required probability of occupying seats at the end of the row by April and Bobby is equals to 0.0333.

We have,

Number of chairs in a row =  5

April and Bobby need to occupy the two end chairs.

The other two people, Bill and Candace, can sit in any of the 3 remaining chairs.

The total number of ways to seat the 4 people in the 5 chairs is

= 5!/(5-4)!

= 5x4x3x2

= 120.

April can sit in either of the two end chairs, and then Bobby can sit in the other end chair.

Bill and Candace can then sit in either of the two remaining chairs, in either order.

The number of ways to seat April and Bobby at the ends of the row is,

=  2x1x2x1

= 4.

Probability that April and Bobby will occupy the seats at the end of the row is,

4/120

= 1/30

= 0.0333

Therefore, the probability of April and Bobby occupy seats at the end of the row is 1/30 or approximately 0.0333.

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Applying this to r and s, we have rs = GCD(r, s) * LCM(r, s), which demonstrates the desired result.

If the GCD of r and s is greater than 1, then the LCM cannot generate a cyclic group.

Applying this to r and s, we have rs = GCD(r, s) * LCM(r, s), which demonstrates the desired result.

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The least common denominator of 3/4 and 15/16 is 16.

So, LCD od 3/4 and 15/16:

Now, the denominator of both the fractions is the same which is 16.

Therefore, the least common denominator of 3/4 and 15/16 is 16.

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Answer:

22% decrease

Step-by-step explanation:

(1100-900)/900 = .22

The cross sectional area of the wing's is = 3404.8 cm²

In order to solve this

use n= 5 to estimate area of the wing's

a = 160

taking sum of thickness at n = 1, 3, 5, 7, 9

so sum of the measurement of the thickness at the given position

⇒ 19.9 +29.0 + 27.5 +20.9 + 9.1 = 106.4

Therefore,

The thickness is 106.4/5 = 21.28 cm

Hence,

cross sectional area of the wing's is = 160 × 21.28

                                                            = 3404.8 cm²

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The complete question is:

A cross-section of an airplane wing is shown. Measurements of the thickness of the wing, in centimeters, at 16-centimeter intervals are 6.1, 19.9, 26.7, 29.0, 27.2, 27.5, 23.6, 20.9, 15.8, 9.1, and 3.2. Use the Midpoint Rule with n = 5 to estimate the area of the wing's cross-section if a = 160. (Assume the thickness of the edges is nonzero.)

Answer has to be in cm³

A. Yes

B. No

I'm not really sure tbh, but if you take a look at the chart, it shows what the scale is, idek if it's an exponential function tho..    srry :c

Look at the chart:

A woman has invested $20 000 as a fixed deposit in a bank for 3 years. The interest rate is 5% per annum, calculated on a yearly basis. The woman needs to find the compound interest received for the period of 3 years.

Principal (P) = $20 000, Rate of Interest (R) = 5%, Time period (t) = 3 years, and compound interest.

We know that the compound interest is calculated as: Compound Interest (CI) = P [(1 + R/100) t - 1]

Using the given values, we have: CI = $20 000 [(1 + 5/100)3 - 1]CI = $20 000 [(1.05)3 - 1]CI = $20 000 [1.157625 - 1]CI = $20 000 [0.157625]CI = $3,152.5

Therefore, the woman will receive a compound interest of $3,152.5 at the end of 3 years if she does not withdraw any money from the fixed deposit during the period of 3 years.

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The statements that are true about the function when graphed on a coordinate plane include the following:

C. The relative minimum of the function is (3, 0)

E. When t > 3, the function is increasing.

In order to determine the minimum and maximum of this function, we would have to determine the critical points where the derivative of the function is equal to zero or undefined, and then evaluate the function at these critical points and at the endpoints of the interval.

By taking the first derivative of the given function and factorizing, we have:

f(t) = t³ - 6t² + 9t

f'(t) = 3t² - 12t + 9  

3t² - 12t + 9 = 0

t² - 4t + 3 = 0

(t - 3)(t - 1) = 0

t = 3 and t = 1

Therefore, the critical points of the function are at t = 1 and t = 3.

By taking the second derivative of the given function and factorizing, we have:

f''(t) = 6t - 12

At point t = 1, we have:

f''(1) = 6(1) - 12 = -6 (it is less than zero).

Therefore, f(t) has a local maximum at t = 1.

At point t = 3, we have:

f''(3) = 18 - 12 = 6 (it is greater than zero).

Therefore, the function f(t) has a local minimum at t = 3.

At t = 4, f''(4) = 24 - 12 = 12

At t = 5, f''(5) = 30 - 12 = 18

In conclusion, the relative minimum of the function is (3, 0) and when t > 3, the function would increase.

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Answer:

166,649.

Step-by-step explanation:

49

∑ (2n + 1)^2 =    4∑n^2 + 4∑n + 49

0

=  (4/6)n(n +1)(2n + 1) + 4/2 n(n + 1) + 49

=  2/3 * 49* 50 *99 + 2*49*50 + 49

= 161700 + 4900 + 49

= 166649

Answer:

\(11xy+4x^{2} t\)

Step-by-step explanation:

1. Collect Like Terms

\((7xy+4xy)+(-x^{2} t+5x^{2} t)\\\)

2. Simplify.

\(11xy+4x^{2} t\)

Therefore, f(w ∩ x) = {0} ≠ f(w) ∩ f(x), which shows that the statement f(w ∩ x) = f(w) ∩ f(x) is false in general.

Let's consider the function f: R -> R defined by f(x) = x^2 and the subsets w = {-1, 0} and x = {0, 1} of the domain R.

f(w) = {1, 0} and f(x) = {0, 1}, so f(w) ∩ f(x) = {0}.

On the other hand, w ∩ x = {0}, and f(w ∩ x) = f({0}) = {0}.

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Raise both sides of the first equation to the exponent y

\(a = 6^x\\\\a^y = (6^x)^y\\\\a^y = 6^{xy}\\\\\)

Raise both sides of the second equation to the exponent of x.

\(b = 6^y\\\\b^x = (6^y)^x\\\\b^x = 6^{xy}\\\\\)

Multiplying them gets us

\(a^y*b^x = 36\\\\6^{xy}*6^{xy} = 6^2\\\\6^{xy+xy} = 6^2\\\\6^{2xy} = 6^2\\\\2xy = 2\\\\xy = 2/2\\\\xy = 1\\\\\)

This concludes the proof.

The product of the variables 'x' and 'y' will be one. So, the condition is proven.

The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.

PEMDAS rule means the Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to solve the equation in a proper and correct manner.

The definition of simplicity is making something simpler to achieve or grasp while also making it a little less difficult.

\(\rm a = 6^x\\\\b= 6^y\\\\a^y\cdot b^x=36\)

From the above equations, then we have

\(\rm 6^x^y \cdot 6^y^x=36\\\\\rm (6)^{xy + yx}=36\\\\6^(2xy) = 36\\\\36^{xy} = 36^1\)

Compare the powers on both sides, then we have

xy = 1

The product of the variables 'x' and 'y' will be one. So, the condition is proven.

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Answer:

2[(1 + 5x) (1 - 5x)]

Step-by-step explanation:

Given:

Expression

2 - 50x²

Find:

Factorization of the given expression

Computation:

2 - 50x²

By taking 2 as common

⇒ 2[1 - 25x²]

⇒ 2[(1)² - (5x)²]

We know that;

⇒ a² - b² = (a + b)(a - b)

In given expression;

⇒ a = 1

⇒ b = 5x

⇒ 2[(1)² - (5x)²]

2[(1 + 5x) (1 - 5x)]

Factorization of the given expression

2[(1 + 5x) (1 - 5x)]

Answer:

13.33 yards

Step-by-step explanation:

Answer:13.33

Step-by-step explanation:

btw..Milk is gross