Help or I will eat all your money.
No links and no cashies.

Answer:

\(y(x)=\frac{9}{e^{1} } e^{-x} =3.310914971e^{-x}\)

Step-by-step explanation:

This problem is very simple, since they give the solution for the differential equation from the start. So basically, you need to evaluate the initial conditions into the solution, and the derivative of the solution in order to find the value of the constants \(c_1\) and \(c_2\).

So, first of all, let's find the derivative of \(y(x)\):

\(y'(x)=c_1 e^{x} -c_2e^{-x}\)

Now, let's evaluate the first initial condition:

\(y(-1)=c_1e^{-1} +c_2e^{-(-1)} =9\\\\c_1e^{-1} +c_2e^{1}=9\hspace{10}(1)\)

Now, the second initial condition:

\(y'(-1)=c_1 e^{-1} -c_2e^{-(-1)}=-9\\\\c_1 e^{-1} -c_2e^{1}=-9\hspace{10}(2)\)

Combining (1) and (2) we have a 2x2 System of Equations. Let's use elimination method in order to solve it:

\((1)+(2):\\\\c_1e^{-1} +c_2e^{1} +c_1e^{-1} -c_2e^{1}=9-9\\\\2c_1e^{-1} =0\\\\Hence\\\\c_1=0\)

Replacing \(c_1\) into (1)

\((0)e^{-1} +c_2e^{1}=9\\\\c_2e^{1}=9\\\\Hence\\\\c_2=\frac{9}{e^{1} } =3.310914971\)

Therefore the solution of the second-order IVP is:

\(y(x)=\frac{9}{e^{1} } e^{-x} =3.310914971e^{-x}\)

The probability that both players show rock in the first round is 1/9 or 0.1111 (rounded to four decimal places).

In rock, paper, scissors there are three possible outcomes for each player: rock, paper, or scissors. Assuming both players choose randomly and independently of each other, each player has a 1/3 chance of showing rock in the first round.

To find the probability that both players show rock in the first round, we can use the multiplication rule of probability for independent events. The multiplication rule states that the probability of the intersection of two independent events is the product of their probabilities.

Therefore, the probability that both players show rock in the first round can be calculated as follows:

P(both show rock) = P(player 1 shows rock) x P(player 2 shows rock) P(both show rock) = 1/3 x 1/3 P(both show rock) = 1/9

So the probability that both players show rock in the first round is 1/9 or approximately 0.111.

For more such question on probability

https://brainly.com/question/251701

#SPJ8

Answer:

$53.6

Step-by-step explanation:

\(\frac{4}{26.8} =\frac{8}{x} \\\\4x=214.4\\x=53.6\)

Answer:

1 is the answer

Answer: A

Step-by-step explanation:

Well when we use a calculator to determine the square root of 158 we get= 12.56980509.

And so option A woud be closest, smallest difference between all.

Answer: A

Step-by-step explanation: Square root of 158 simplified is 12.5698

In the given graph,

At x=0, y=-2

At x=3, y=0

So, the slope or rate of change between the inputs of 0 and 3 is = (0-(-2))/(3-0) = 2/3

At x=6, y=2

So the slope or rate of change between the domain values of 3 and 6 is given by = (2-0)/(6-3) = 2/3

Yes, the slope or rate of change is the same every time.

Since the slope is same so the function is Linear.

To know more about Slope refer to:

https://brainly.com/question/3493733

#SPJ1

Answer:

Step-by-step explanation:

Let the five courses with their corresponding credit hours be represented as shown;

FST 201 = 4

FST 203 = 5

FST 112 = 1

FST 219 = 5

FST 223 = 4

If a student earned grades of​ B, B,​ A, C, and D respectively in those courses with the following grading system  A =​4, B =​3, C =​2, D =​1, and F =0, before we can get the student GPA, we need to know the total credit point for the five courses.

Credit point for each course = Number of credit hour * point for each grade

FST 201 = 4 * 4 = 16points (A)

FST 203 = 5 * 4 = 20points (A)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 4 = 20points (A)

FST 223 = 4 * 4 = 16points (A)

Total credit point = 16+20+4+20+16 = 76points

Total credit point gotten by the student is calculated as thus;

FST 201 = 4 * 3 = 12points (B)

FST 203 = 5 * 3 = 15points (B)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 2 = 10points (C)

FST 223 = 4 * 1 = 4points (D)

Total credit point gotten by the student = 45points.

student's Grade Point Average​ (GPA) = Total credit point/Total credit point gotten by the student = 76/45 = 1.69 (to 2dp)

Given:

Quadrilateral ABCD is similar to Quadrilateral WXYZ.

\(AB =15,\ WX =25,\ XY =15\) and \(YZ =20\).

To find:

The measure of BC.

Solution:

We know that the corresponding sides of similar figures are proportional.

It is given that Quadrilateral ABCD is similar to Quadrilateral WXYZ. It means their corresponding sides are proportional.

\(\dfrac{AB}{WX}=\dfrac{BC}{XY}=\dfrac{CD}{YZ}=\dfrac{AD}{WZ}\)

Now,

\(\dfrac{AB}{WX}=\dfrac{BC}{XY}\)

After substituting the given values, we get

\(\dfrac{15}{25}=\dfrac{BC}{15}\)

\(\dfrac{3}{5}=\dfrac{BC}{15}\)

Multiply both sides by 15.

\(\dfrac{3}{5}\times 15=\dfrac{BC}{15}\times 15\)

\(9=BC\)

Therefore, the measure of BC is 9 units.

Work Shown:

Add up those items to get a sum of 145. Solve for x.

(x)+(x+2)+(x+4)+(x+6)+(x+8) = 145

5x+20 = 145

5x = 145-20

5x = 125

x = 125/5

x = 25

Then we can determine the following

In short the sequence of numbers is:  25, 27, 29, 31, 33

As verification,

25+27+29+31+33 = 145

which tells us the answer is correct.

Answer: The diagonals of a parallelogram bisect each other, then. QM = PQ = 21. Explore all similar answers.

Step-by-step explanation: got do the d

The coordinates of the point on y sin(x) that is closest to the point (4, y) is (3.579, 0.323).

To find the point on the curve y = sin(x) that is closest to the point (4, y), we can use the distance formula between two points. The distance between two points (x1, y1) and (x2, y2) is given by:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

We want to minimize this distance, so we can minimize the square of the distance:

d^2 = (x2 - x1)^2 + (y2 - y1)^2

Let (x, sin(x)) be a point on the curve y = sin(x). Then the distance squared between this point and (4, y) is:

d^2 = (x - 4)^2 + (sin(x) - y)^2

To minimize this distance, we can take the derivative of d^2 with respect to x, set it equal to zero, and solve for x:

d^2 = (x - 4)^2 + (sin(x) - y)^2

d^2/dx = 2(x - 4) + 2(sin(x) - y)cos(x) = 0

Simplifying this expression, we get:

x - 4 + (sin(x) - y)cos(x) = 0

We can solve this equation numerically using a numerical method such as Newton's method or the bisection method. Once we have found the value of x that minimizes the distance, we can find the corresponding value of y = sin(x) and the closest point on the curve is (x, sin(x)).

Using a numerical method, we can find that the value of x that minimizes the distance is approximately 3.579. Therefore, the closest point on the curve is (3.579, sin(3.579)) which is approximately (3.579, 0.323).

To learn more about coordinates here:

https://brainly.com/question/30176241

#SPJ4

3x-10=2(x+6)

3x-10=2x+12

subtract 2x (to cancel it out and combine like terms)

[3x-2x=x]

x-10=12

add 10

[12+10=22]

x=22

Answer:

A

Step-by-step explanation:

z = -3 - 5i

z (i) = i (-3 - 5 i)

z (i) = -3i - 5i^2

z (i) = -3i - 5 (-1)

z (i) = -3i + 5

z (i) = 5 - 3i

Therefore, letter A is the correct answer.

Answer:

A

Step-by-step explanation:

An algorithm for navigating or searching through tree or graph data structures is called depth-first search. The algorithm begins at the root node (choosing an arbitrary node to serve as the root node in the case of a graph) and proceeds to investigate each branch as far as it can go before turning around.

Thus, the basic concept is to begin at the root or any other random node, mark that node, then advance to the next nearby node that is not marked. This process is repeated until there are no more adjacent nodes that are unmarked. Then go back and look for more unmarked nodes to cross. Print the path's nodes lastly.

To solve the issue, adhere to the instructions listed below:

Make a recursive function that accepts a visited array and the node's index.

STEP -1

// C++ program to print DFS traversal from

// a given vertex in a given graph

#include <bits/stdc++.h>

using namespace std;

// Graph class represents a directed graph

// using adjacency list representation

class Graph {

public:

map<int, bool> visited;

map<int, list<int> > adj;

// function to add an edge to graph

void addEdge(int v, int w);

// DFS traversal of the vertices

// reachable from v

void DFS(int v);

};

void Graph::addEdge(int v, int w){

adj[v].push_back(w); // Add w to v’s list.}

void Graph::DFS(int v)

{

// Mark the current node as visited and

// print it

visited[v] = true;

cout << v << " ";

// Recur for all the vertices adjacent

// to this vertex

list<int>::iterator i;

for (i = adj[v].begin(); i != adj[v].end(); ++i)

if (!visited[*i])

DFS(*i);

}

// Driver's code

int main()

{

// Create a graph given in the above diagram

Graph g;

g.addEdge(0, 1);

g.addEdge(0, 2);

g.addEdge(1, 2);

g.addEdge(2, 0);

g.addEdge(2, 3);

g.addEdge(3, 3);

cout << "Following is Depth First Traversal"

" (starting from vertex 2) \n";

// Function call

g.DFS(2);

return 0;

STEP- 2

Time complexity: O(V + E), where V is the number of vertices and E is the number of edges in the graph.

Auxiliary Space: O(V), since an extra visited array of size V is required.

Pseudocode:

Depth_First_Search(matrix[ ][ ] ,source_node, visited, value)

{

If ( sourcce_node == value)                

return true // we found the value

visited[source_node] = True

for node in matrix[source_node]:

  If visited [ node ] == false

  Depth_first_search ( matrix, node, visited)

  end if

end for

return false //If it gets to this point, it means that all nodes have been explored.

                   //And we haven't located the value yet.

}

final answer-

A tree data structure or a graph's vertices can be searched using a recursive technique called t. Beginning with the first node of graph G, the depth-first search (DFS) algorithm digs down until it reaches the target node, also known as the node with no children.

The DFS method can be implemented using a stack data structure due to its recursive nature. The DFS algorithm implementation procedure is comparable to that of the BFS algorithm.

The following describes how to implement DFS traversal step-by-step. -

Create a stack with all of the graph's vertices in it first.

Select whatever vertex you want to use as the first vertex in the traverse, and add it to the stack.

uses for the DFS algorithm

The following list of uses for the DFS algorithm includes:

The topological sorting can be implemented using the DFS algorithm.

It can be applied to determine the routes connecting two vertices.

It can also be used to find graph cycles.

DFS technique is also applied to puzzles with a single solution.

If a graph is bipartite or not, it can be determined using DFS.

To learn more about Algorithm visit:

brainly.com/question/27522570

#SPJ4

The correct answer is (1,1) because both of the lines meet together at these numbers

Answer:

16,000

Step-by-step explanation:

11,319 rounded to the nearest thousand is 11,000.

4,895 rounded to the nearest thousand is 5,000.

11,000 + 5,000 is equal to 16,000.

Multiply both sides by \(x^{-3}\) to get a homogeneous equation.

\((2xy^2 - x^3) \, dy + (y^3 - 2yx^2) \, dx = 0 \\\\ \implies \left(2\dfrac{y^2}{x^2} - 1\right) \, dy + \left(\dfrac{y^3}{x^3} - 2\dfrac yx\right) \, dx = 0\)

Substitute \(y=vx\) and \(dy = x\,dv + v\,dx\). This makes the equation separable.

\((2v^2 - 1) (x\,dv + v\,dx) + (v^3 - 2v) \, dx = 0\)

\(x (2v^2 - 1) \,dv + (2v^3 - v) \, dx + (v^3 - 2v) \, dx = 0\)

\(x (2v^2 - 1) \,dv + (3v^3 - 3v) \, dx = 0\)

Separate the variables.

\(x (2v^2 - 1) \, dv = (3v - 3v^3) \, dx\)

\(\dfrac{2v^2-1}{3v-3v^3} \, dv = \dfrac{dx}x\)

\(\dfrac13 \dfrac{1 - 2v^2}{v(v-1)(v+1)} \, dv = \dfrac{dx}x\)

Expand the left side into partial fractions.

\(\dfrac{1-2v^2}{v(v-1)(v+1)} = \dfrac av + \dfrac b{v-1} + \dfrac c{v+1} \\\\ \dfrac{1-2v^2}{v(v-1)(v+1)} = \dfrac{a(v^2-1) + bv(v+1) + cv(v-1)}{v(v-1)(v+1)} \\\\ 1-2v^2 = (a+b+c) v^2 + (b-c) v - a\)

Solve for the coefficients \(a,b,c\).

\(\begin{cases} a + b + c = -2 \\ b-c = 0 \\ -a = 1 \end{cases} \implies a=-1, b=c=-\dfrac12\)

Thus our equation becomes

\(\left(-\dfrac1{3v} - \dfrac1{6(v-1)} - \dfrac1{6(v+1)}\right) \, dv = \dfrac{dx}x\)

Integrate both sides.

\(\displaystyle \int \left(-\dfrac1{3v} - \dfrac1{6(v-1)} - \dfrac1{6(v+1)}\right) \, dv = \int \dfrac{dx}x\)

\(\displaystyle -\frac13 \ln|v| - \frac16 \ln|v-1| - \frac16 \ln|v+1| = \ln|x| + C\)

Solve for \(v\) (as much as you can, anyway).

\(\displaystyle -\frac16 \left(2\ln|v| + \ln|v-1| + \ln|v+1|\right) = \ln|x| + C\)

\(\displaystyle \ln\left|\frac1{\sqrt[6]{v^2(v^2-1)}}\right| = \ln|x| + C\)

\(\displaystyle \frac1{\sqrt[6]{v^4-v^2}} = Cx\)

\(\sqrt[6]{v^4-v^2} = \dfrac Cx\)

\(\left(\sqrt[6]{v^4-v^2}\right)^6 = \left(\dfrac Cx\right)^6\)

\(v^4-v^2 = \dfrac C{x^6}\)

Put the solution back in terms of \(y\).

\(\left(\dfrac yx\right)^4-\left(\dfrac yx\right)^2 = \dfrac C{x^6}\)

\(y^4 - x^2y^2 = \dfrac C{x^2}\)

\(\boxed{x^2y^4 - x^4y^2 = C}\)

which is about as simple as we can hope to get this.

Answer:1

Step-by-step explanation: so bro if yo do 5*1/25 u can see

Answer

she worked 1 week and 1 day

Step-by-step explanation

The FitnessGram PACER Test is a multistage aerobic capacity test that progressively gets more difficult as it continues.

Answer:

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

To graph this equation, start at the origin (0,0) since there is not y-intercept.

Because slope is characterized by rise/run ( i.e. how many units up or down depending on whether it is positive or negative and then however many units to the right.

Because the rise (up and down, numerator) is 1, we know that we will go up one unit.

The run (side to side, denominator) is 4, so we will go to the right 4 units.

This makes the first point (4, 1).

Continue doing this until you get an idea of the line and connect the points to get the graph

Answer:

Info down in Explaination

Step-by-step explanation:

To graph this equation, start at the origin (0,0) since there is not y-intercept.

Because slope is characterized by rise/run ( i.e. how many units up or down depending on whether it is positive or negative and then however many units to the right.

Because the rise (up and down, numerator) is 1, we know that we will go up one unit.

The run (side to side, denominator) is 4, so we will go to the right 4 units.

This makes the first point (4, 1).

Continue doing this until you get an idea of the line and connect the points to get the graph

Answer:

43.6 has 3 significant figures.

Answer

\(\pink\sf{y=-1}\)

Step-by-step explanation

I'm assuming that this exercise is asking us to simplify the equation \(\sf{y=0.5(6)-4}\).

We know that 0.5 (6) means 0.5 multiplied by 6. That is the same as 6 divided by 2, which is 3:

\(\sf{y=3-4}\)

And now we just simplify the last part:

\(\sf{y=-1}\)

∴ answer: y = -1

A²+B²= C²

31²+ 21²= z²

961+441 = z²

1402= z²

z= 37.443290454

The area of the given shape which is a sector of the circle is 3.14 sq.units.

What is a sector of a circle?

An area of a circle that is contained within its two radii and the arc that connects them is called a sector. A semicircle, which represents one-half of a circle, is the most typical sector of a circle.

Given a sector of a circle.

The radius of the circle  = 2

Given π = 3.14

Area of circle = πr²

Area of sector  = ( θ / 360° ) *  πr²

where θ =  sector angle

For the given shape, sector angle = 90°

Area of sector = (90°/360°) × 3.14 × 2² = (1/4) × 3.14 × 4 = 3.14

Therefore the area of the given sector of the circle is 3.14 sq.units.

To learn more about the sector of a circle, follow the link.

https://brainly.com/question/22972014

#SPJ1

Given that 16 families went on a trip and the cost of the trip was Rs. 2,16,352.The amount paid by each family is to be determined by unitary method Hence each family paid Rs.13522

Now, let's solve this by using the method of unitary method. To find the cost of 1 family trip, we will divide the total cost of the trip by the number of families.2,16,352 / 16 = 13,522 So, the cost of the trip per family is Rs. 13,522.Hence, each family paid Rs. 13,522 for the trip.

to know more about unitary method

https://brainly.com/question/28276953

Answer:

Step-by-step explanation

1. The total cost of the trip for all 16 families is Rs 2,16,352.
2. To find out how much each family paid, we need to divide the total cost by the number of families: Rs 2,16,352 ÷ 16.
3. When we do the division, we get the result: Rs 13,522.

Now let's check if this result is correct:

1. If each family paid Rs 13,522 for the trip, then the total cost for all 16 families would be: 16 × Rs 13,522 = Rs 2,16,352.
2. This is exactly the same as the total cost given in the problem statement.

So we have shown that each family paid **Rs 13,522** for the trip

Answer:

Step-by-step explanation:

200 x 115.5/8 = $23,100.00

Answer:

Step-by-step explanation:

Given equation

The roots are

Substitute values into equation

This is matching the option B

Answer:

\(x=\dfrac{3 \pm \sqrt{29}}{2}\)

Step-by-step explanation:

Given equation:

\(x^2-3x-5=0\)

To find the exact solutions of the given equation, use the quadratic formula or complete the square.

Method 1:  Quadratic Formula

\(x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0\)

Therefore:

\(a=1, \quad b=-3, \quad c=-5\)

Substituting these values into the formula:

\(\implies x=\dfrac{-(-3) \pm \sqrt{(-3)^2-4(1)(-5)} }{2(1)}\)

\(\implies x=\dfrac{3 \pm \sqrt{29}}{2}\)

Method 2:  Completing the square

Move the constant to the right side by adding 5 to both sides:

\(\implies x^2-3x-5+5=0+5\)

\(\implies x^2-3x=5\)

Add the square of half the coefficient of x to both sides:

\(\implies x^2-3x+\left(\dfrac{-3}{2}\right)^2=5+\left(\dfrac{-3}{2}\right)^2\)

\(\implies x^2-3x+\dfrac{9}{4}=\dfrac{29}{4}\)

Factor the perfect trinomial on the left side:

\(\implies \left(x-\dfrac{3}{2}\right)^2=\dfrac{29}{4}\)

Square root both sides:

\(\implies \sqrt{\left(x-\dfrac{3}{2}\right)^2}=\sqrt{\dfrac{29}{4}}\)

\(\implies x-\dfrac{3}{2}=\pm\dfrac{\sqrt{29}}{2}\)

Add 3/2 to both sides:

\(\implies x-\dfrac{3}{2}+\dfrac{3}{2}=\pm\dfrac{\sqrt{29}}{2}+\dfrac{3}{2}\)

\(\implies x=\dfrac{3 \pm \sqrt{29}}{2}\)

Learn more about completing the square here:

https://brainly.com/question/27933930

Answer:

Step-by-step explanation:

Of The Students Who Repo Drinking Alcohol, The Percentage Who Reported Random samples of students at 112 four-year colleges were interviewed  who reported bingeing at least three times within the past two weeks was 42.5% of Estimate the difference between the proportions in 2007 and 1998, and interpret.