when the film is placed into the xcp holder with the smooth side of the film towards the throat, after processing it will appear dark. t/f
The given statement " When the film is placed into the XCP (extension cone paralleling) holder with the smooth side of the film towards the throat, after processing, it will appear darker" is false because it will lighter, not darker.
The smooth side of the film is the side that interacts with the X-ray radiation and receives the image, while the emulsion side contains the light-sensitive crystals that react to the radiation.
Placing the smooth side towards the throat ensures that the image is sharp and clear, as the X-ray beam travels through the teeth and soft tissues before reaching the film.
After processing, the exposed areas of the film turn dark, representing the captured X-ray image, while the unexposed areas remain light or clear.
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Whats the value of b?
Answer:
b = 5
Step-by-step explanation:
This triangle is a 30 - 60 - 90 special right triangle
As you can see in the image provided below the longer leg is equal to the short leg times √3
This means that the short leg is equal to the long leg divided by √3
Thus, b = \(\frac{5\sqrt{3} }{\sqrt{3} }\) which is equivalent to 5
help me
how do i graph
y=3-|x-1|
Answer:
- x= 10-6y+y²
Step-by-step explanation:
|x-1|=3-y
(|x-1|)²=(3-y)²
x-2x+1=9-6y+y²
-x=9-6y+y²+1
Elsa drove 737 miles in 11 hours.
At the same rate, how many miles would she drive in 13 hours?
Answer:
871 miles
Step-by-step explanation:
737/11= 67
67 x 13= 871
Solve for x.
A
6
B
12
С
14
D
18
Water has a freezing point of 32 mercury has a freezing point that is 70 lower heat is the freezing point of mercury
Mercury is used to measure high temperatures and alcohol has a lower freezing point that mercury.
The freezing point of any substance, describe the transition of liquid into solid.
The freezing point of water is \(0\) °C or \(32\) °F.
At zero-degree water molecules are moving very slowly, and formation of solid begins i.e. Ice.
When salt or sugar is combined that is mixed with water or ice and it is evenly distributed, the freezing point is lowered.
Lowering of freezing point allows the street ice to melt at lower temperatures, it prevent the accumulation of dangerous, slippery ice.
Alcohol is used to measure the lower temperatures.
Mercury boils at \(357\) degree Celsius where as alcohol boils at \(78\) degree Celsius.
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Jason is traveling by car from his home to his office. He has gone 3.5 miles so far. From this point on, he can cover 100 miles every 2 hours. What is
the equation of a line that models the total miles traveled, y, in x hours after this point?
A
y = 100x + 3.5
ОВ.
y = 100x - 3.5
Ос.
y = 50x + 3.5
OD
y=-50x + 3.5
Answer:
y = 50x + 3.5
Step-by-step explanation:
Given:
Distance already covered = 3.5 miles
100 miles covered in 2 hour
FInd;
Equation of given scenario
Computation:
Assume;
Total miles covered = y
Total number of hours = x
Speed of car = 100 / 2
Speed of car = 50 miles per hour
Total miles covered = Distance already covered + [Speed of car][Total number of hours]
y = 3.5 + [50][x]
y = 50x + 3.5
Elmer spent the day at the mall. First, he bought five rabbits for $10 each. Later, he bought four cupboards for $70 each. After that, he found a twenty dollar bill. Also, he returned one rabbit. Write the total change to Elmer's funds as an integer.
Answer:
-300
Step-by-step explanation:
Step 1: Find the amount Elmer's funds decreased after purchasing the rabbits:
Let x represent Elmer's funds.
Since Elmer bought five rabbits for $10 each, he lost $10 5 times.
x - (10 * 5)
x - 50
Thus, Elmer lost (spent) $50 for the 5 rabbits.
Step 2: Find the amount Elmer's funds decreased after purchasing the cupboards:
Since Elmer bought four cupboards for $70 each, he lost $70 4 times:
x - (50 + (70 * 4))
x - (50 + 280)
x - 330
Thus, after purchasing the rabbits and cupboards, Elmer lost $330.
Step 3: Find the amount Elmer's funds increased after finding the twenty-dollar bill:
Since Elmer found a twenty-dollar bill, he gained $20
x - (330 + 20)
x - 310
Step 4: Find the amount Elmer's funds increased after returning one rabbit:
Since Elmer returned one rabbit, he gained $10:
x - (310 + 10)
x - 300
Thus, Elmer's funds changed totally by -$300.
Putting all the information together, we have:
x - 10 - 10 - 10 - 10 - 10 - 70 - 70 - 70 - 70 + 20 + 10
x - 50 - 280 + 30
x - 330 + 30
x - $300
Michael’s youth group built a catapult that they use to launch pumpkins. Michael gathered data about the weights of several launched pumpkins and the distances they traveled. The scatter plot shows the data he gathered and the line of best fit.
The equation of the line of best fit is y = -9.21x + 168.7.
Based on the line of best fit, approximately how far is a 5-pound pumpkin predicted to travel when launched by the catapult?
A.
18 feet
B.
123 feet
C.
144 feet
D.
214 feet
Based on the line of best fit, a 5-pound pumpkin is predicted to travel approximately 122.65 feet when launched by the catapult. Option B
Based on the given equation of the line of best fit, which is y = -9.21x + 168.7, we can predict the distance traveled by a 5-pound pumpkin when launched by the catapult.
In the equation, 'y' represents the predicted distance traveled by the pumpkin, and 'x' represents the weight of the pumpkin. We know that the weight of the pumpkin is 5 pounds, so we substitute 'x' with 5 in the equation to find the predicted distance.
y = -9.21 * 5 + 168.7
y = -46.05 + 168.7
y ≈ 122.65
Therefore, based on the line of best fit, a 5-pound pumpkin is predicted to travel approximately 122.65 feet when launched by the catapult.
Since none of the given answer choices exactly match the predicted distance, we need to choose the closest option. Among the options provided, the closest value to 122.65 is 123 feet (Option B). Therefore, the most appropriate answer is B. 123 feet.
It's important to note that the prediction is based on the line of best fit, which is an estimation based on the available data. The actual distance traveled by a 5-pound pumpkin may vary due to factors such as launch angle, launch velocity, and environmental conditions. The line of best fit provides a general trend, but individual variations can occur.
Option B
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Daca adun sfertul lui a cu jumatatea lui b si cu treimea lui c, obtin 120. Stiind ca jumatatea lui b este cu 24 mai mare decat sfertul lui a si de 4 ori mai mare decat treimea lui c, afla cele 3 numere si suma acestora. Ajutor, va rog!
Answer:
Step-by-step explanation:
Dacă adaug un sfert de la jumătate de b și o treime de c, obțin 120.
Aceasta se exprimă ca:
1 / 4a + 1/2 b + 1 / 3c = 120 ..... Ecuația 1
Știind că jumătate din b este de 24 de ori mai mare decât un sfert de a
1 / 2b = (1/4 × a) 24
b / 2 = (a / 4) 24
b / 2 = 6a
Cross Multiply
b = 6a × 2
b = 12a
a = b / 12
Jumătate din b este de 4 ori mai mare decât o treime din c
1/2 × b = 4 × (1/3 × c)
b / 2 = 4 (c / 3)
b / 2 = 4c / 3
Cross Multiply
b = 2 × 4c / 3
b = 8c / 3
8c = 3b
c = 3b/8
1 / 4a + 1/2 b + 1 / 3c = 120 ..... Ecuația 1
Înlocuim
1/4 × b / 12 + 1 / 2b + 1/3 × 3b / 8= 120
b / 48 + b / 2 + b/8 = 120
Înmulțiți cu 48
b/48 × 48 + b/2 × 48 + b/8× 48 = 120 × 48
b + 24b + 6b = 5760
31b = 5760
Someone help me asap please
Answer:
x-intercepts = (8, 0) and (-4, 0)
y- intercept = (0, 8)
vertex = (2, 9)
Step-by-step explanation:
Sorry if its wrong but I think it's where the coordinates are according to the graph. The x-int would hit at the x-axis, y-int would hit the y-axis, and the vertex would be where it's highest point is
Ants pizza shop charges $12 for a large cheese pizza plus $0. 50 for each topping added. Write an equation Ant can use to be able to determine the total (y) for any large pizza no matter the number of toppings ordered (x)
The equation Ant can use to determine the total cost (y) for any large pizza, regardless of the number of toppings ordered (x), is y = 12 + 0.50x.
The equation is formed by considering the base cost of a large cheese pizza, which is $12. Each additional topping adds $0.50 to the total cost.
The variable x represents the number of toppings ordered, and y represents the total cost of the pizza. Multiplying the number of toppings (x) by the cost per topping ($0.50) gives the additional cost of the toppings.
By adding the base cost of the large cheese pizza ($12) to the additional cost of the toppings (0.50x), we obtain the equation y = 12 + 0.50x. This equation allows Ant to calculate the total cost for any large pizza based on the number of toppings chosen.
For example, if a customer orders 3 toppings, substituting x = 3 into the equation gives y = 12 + 0.50 * 3 = 12 + 1.50 = $13.50. Hence, the total cost for a large pizza with 3 toppings would be $13.50.
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The slope of the graph shown below is
Answer:
1/ 2.5
Step-by-step explanation:
one way to do this is rise over run, so from one red dot to the other it went up one and over 2.5. the other way to do this is by using the (y2-y1)/(x2-x1) this will give you the same answer :)
Cloud seeding has been studied for many decades as a weather modification procedure (for an interesting study of this subject, see the article in Technometrics "A Bayesian Analysis of a Multiplicative Treatment Effect in Weather Modification," Vol. 17, pp. 161- 166). The rainfall in acre-feet from 20 clouds that were selected at random and seeded with silver nitrate follows: 18.0, 30.7, 19.8, 27.1, 22.3, 18.8, 31.8, 23.4, 21.2, 27.9, 31.9, 27.1, 25.0, 24.7, 26.9, 21.8, 29.2, 34.8, 26.7, 31.6 Assume the rainfall is normally distributed. (a) Can you support a claim that mean rainfall from seeded clouds is 28.5 acre-feet? Use a = 0.05. (b) Explain how the question in part (a) could be answered by constructing a suitable confidence interval on the mean diameter.
There is no significant evidence to reject the claim that the mean rainfall from seeded clouds is 28.5 acre-feet at the 95% confidence level.
To test the claim that the mean rainfall from seeded clouds is 28.5 acre-feet, we can use a one-sample t-test.
First, we calculate the sample mean and standard deviation of the rainfall data:
Sample mean, \($\bar{x} = (18.0 + 30.7 + \ldots + 31.6)/20 = 26.545$\)
Sample standard deviation, s = 4.682
Using these values and the sample size, n = 20, we can calculate the t-statistic:
\(t = \frac{\bar{x} - \mu}{s/\sqrt{n}} = \frac{26.545 - 28.5}{4.682/\sqrt{20}} = -1.872\)
The degrees of freedom for the test are df = n - 1 = 19. Using a two-tailed t-table with α = 0.05 and df = 19, we find the critical values to be ±2.093. Since |t| = 1.872 < 2.093, we fail to reject the null hypothesis that the mean rainfall is 28.5 acre-feet.
To construct a confidence interval on the mean rainfall, we can use the formula:
\(\begin{equation*}CI = \bar{x} \pm t_{\alpha/2} \frac{s}{\sqrt{n}}\end{equation*}\)
where \(\bar{x}\), s, and n are the same as in part (a), and \(t_{\alpha/2}\) is the t-score for the desired level of confidence and degrees of freedom.
For a 95% confidence interval, α/2 = 0.025, and using df = 19, we find \(t_{0.025} = 2.093\).
Substituting the values into the formula, we get:
\($CI = 26.545 \pm 2.093 \times \frac{4.682}{\sqrt{20}} = (23.389, 29.701)$\)
Since 28.5 is within the confidence interval, we can say that there is no significant evidence to reject the claim that the mean rainfall from seeded clouds is 28.5 acre-feet at the 95% confidence level.
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The scatter plot shows the number of households, in millions, that have cable television over eight consecutive years. Scatter plot with x axis labeled Time in Years and y axis labeled Number of Households with points at 1 comma 3 and 8 tenths, 2 comma 5 and 8 tenths, 3 comma 6 and 2 tenths, 4 comma 7 and 5 tenths, 5 comma 7 and 2 tenths, 6 comma 8 and 3 tenths, 7 comma 9 and 3 tenths, and 8 comma 8 and 5 tenths. Which of the following is an appropriate line of best fit? y hat equals negative 13 hundredths times x plus 4 and 65 hundredths. y hat equals 13 hundredths times x plus 4 and 65 hundredths. y hat equals negative 67 hundredths times x plus 4 and 5 hundredths. y hat equals 67 hundredths times x plus 4 and 5 hundredths.
The appropriate line of best fit for this scatter plot is y hat = 13/100 * x + 4.65. This equation represents the linear trend that approximates the relationship between time (x) and the number of households (y) with cable television over the eight-year period.
To determine the appropriate line of best fit for the given scatter plot, we need to analyze the trend and relationship between the variables. The scatter plot represents the number of households with cable television over eight consecutive years. Let's examine the given data points:
(1, 3.8), (2, 5.8), (3, 6.2), (4, 7.5), (5, 7.2), (6, 8.3), (7, 9.3), (8, 8.5)
By observing the data points, we can see that as the time (x-axis) increases, the number of households (y-axis) generally increases. Therefore, we expect a positive correlation between the variables.
Now, let's evaluate the given options for the line of best fit:
1. y hat = -13/100 * x + 4.65
2. y hat = 13/100 * x + 4.65
3. y hat = -67/100 * x + 0.45
4. y hat = 67/100 * x + 0.45
We can rule out options 1 and 3 as they both have a negative coefficient for x, which contradicts the positive correlation observed in the data.
Between options 2 and 4, we need to compare the slopes (coefficients of x) and y-intercepts. The slope in option 2 is positive (13/100), matching the positive correlation observed in the data. Additionally, the y-intercept (4.65) is closer to the average y-values in the dataset.
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help plsss; what is the inverse of f(x) = 5x - 1
Answer:
f^-1(x) = 1/5x + 1/5
Step-by-step explanation:
Switch the x and y values:
y = 5x - 1
x = 5y - 1
Put the equation back into y = form:
x = 5y - 1
x + 1 = 5y
1/5x + 1/5 = y
y = 1/5x + 1/5
f^-1(x) = 1/5x + 1/5
Answer: y = \(\frac{x+1}{5}\)
Step-by-step explanation:
I find it helpful if I change f(x) into y.
y = 5x - 1
Then, switch x and y
x = 5y - 1
Solve normally for y in terms of x
x+1 = 5y
\(\frac{x+1}{5}\) = y
So, the inverse is y = \(\frac{x+1}{5}\)
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Let f(x) = 11x + 2x^2 and g (x) = -7x - 3x^2 + 4 . Find (f + g) (x) and (f - g) (x) . Then evaluate f + g and f - g for x = 2
Composite functions are functions derived from combining other functions
The values of the composite functions are \((f + g)(2) = -3\) and \((f - g)(2) = 41\)
How to determine the composite functionsThe single functions are given as:
\(f(x) =11 + 2x^2\)
\(g(x) = -7x - 3x^2 + 4\)
To calculate (f + g)(x), we make use of
\((f + g)(x) = f(x) + g(x)\)
So, we have:
\((f + g)(x) = 11 + 2x^2 - 7x - 3x^2 + 4\)
Collect the like terms
\((f + g)(x) = 2x^2- 3x^2 - 7x + 4+11\)
Evaluate
\((f + g)(x) = - x^2 - 7x + 15\)
Substitute 2 for x
\((f + g)(2) = - 2^2 - 7(2) + 15\)
\((f + g)(2) = -3\)
To calculate (f - g)(x), we make use of
\((f + g)(x) = f(x) - g(x)\)
So, we have:
\((f - g)(x) = 11 + 2x^2 + 7x + 3x^2 - 4\)
Collect the like terms
\((f - g)(x) = 2x^2 + 3x^2+ 7x - 4 + 11\)
Evaluate
\((f - g)(x) = 5x^2+ 7x +7\)
Substitute 2 for x
\((f - g)(2) = 5 * 2^2+ 7* 2 +7\)
\((f - g)(2) = 41\)
Hence, the values of the composite functions are \((f + g)(2) = -3\) and \((f - g)(2) = 41\)
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The value of f(x) - g(x) and f(x) + g(x) are 52 and 0
Sum and differences of functionGiven the following function expressed as:
f(x) = 11x + 2x^2 and;
g (x) = -7x - 3x^2 + 4
Taking the sum of the function
f(x) + g(x) = 11x + 2x^2 -7x - 3x^2 + 4
f(x) + g(x) = -x^2 + 4x + 4
If x = 2,
f(x) + g(x) = -4 + 8 + 4
f(x) + g(x) = 0
For the difference;
f(x) - g(x) = 11x + 2x^2 + 7x + 3x^2 - 4
f(x) - g(x) = 5x^2 + 18x - 4
If x = 2,
f(x) - g(x) = 5(4) + 36 - 4
f(x) - g(x) = 52
Hence the value of f(x) - g(x) and f(x) + g(x) are 52 and 0
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Pls, help me with this math question
Answer:
Perimeter \(\sqrt{26}+\sqrt{5}+\sqrt{10}+\sqrt{17}\) units. Area 12 square units.
Step-by-step explanation:
Perimeter: total distance around the figure.
Distance Formula: the distance between points \(\left(x_1,y_1\right) \text{ and } \left(x_2,y_2\right)\) is
\(d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\)
\(AB=\sqrt{(6-1)^2+(2-1)^2}=\sqrt{25+1}=\sqrt{26}\)
\(BC=\sqrt{(5-6)^2+(4-2)^2}=\sqrt{1+4}=\sqrt{5}\)\(CD=\sqrt{(2-5)^2+(5-4)^2}=\sqrt{9+1}=\sqrt{10}\)\(DA=\sqrt{(1-2)^2+(1-5)^2}=\sqrt{1+16}=\sqrt{17}\)
The perimeter is the sum of all those segment lengths.
One way to find the area of the figure is to surround it with a rectangle, insert some lines so that the areas you do not want can be found and subtracted from the rectangle's area. (See attached image.)
The area of the large rectangle around the figure is 5 x 4 = 20 square units.
The triangles have areas 1/2 (base) (height):
A. (1/2)(1)(4) = 2 square units
B. (1/2)(3)(1) = 1.5 square units
D. (1/2)(1)(2) = 1 square unit
E. (1/2)(5)(1) = 2.5 square units
Square C. (1)(1) = 1 square unit
Total of all the area you don't want to include:
2 + 1.5 + 1 + 2.5 + 1 = 8 square units
Subtract 8 from the surrounding rectangle's area of 20, and you get the area of the figure is 20 - 8 = 12 square units.
Quetion content area top left
Part 1
The rectangle hown ha a perimeter of 78 cm and the given area. It length i 3 more than twice it width. Write and olve a ytem of equation to find the dimenion of the rectangle
The length of the triangle is 39 cm and the width of the triangle is 13 cm.
Triangle:
A triangle is a polygon with three sides and three vertices. It is one of the basic shapes in geometry. A triangle with angles A, B, and C is represented by Δ ABC.
Now,
Let, width of rectangle = x cm
So, the length of rectangle = 3x
Given that,
perimeter of the rectangle = 78 cm
2 (length + breadth ) = 78
2(3x+x) = 78
Now,
2(3x + x) = 78
⇒ 2(4x) = 78
⇒ 4x = 78/2
⇒ 3x = 39
⇒ x = 39/3
⇒ x = 13
Thus, breadth/width of rectangle = 13 cm
So, length of rectangle =3x
=3 × 13
=39 cm
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consider a large block of iced in the shape of a cube. at the time the block is 1 ft on each side, the lengths of each side are increasing at a rate of 2 ft per hour. at what rate is the volume of the block increasing at this time
The volume of the block is increasing at a rate of \(6 ft^3/hour\) at this time.
Space in three dimensions is quantified by volume. It is frequently expressed as a numerical value using SI-derived units, other imperial units, or US customary units. Volume definition and length definition are connected.
The area occupied inside an object's three-dimensional bounds is referred to as its volume. The item's capacity is another name for it. A three-dimensional object's volume, which is expressed in cubic metres, is the quantity of space it takes up.
Let's start by finding the formula for the volume of a cube with side length s:
V = \(s^3\)
Now, let's differentiate both sides with respect to time (t):
dV/dt = \(3s^2(ds/dt)\)
We know that ds/dt = 2 ft/hour, and when s = 1 ft, we have:
dV/dt = \(3(1^2)(2) = 6 ft^3/hour\)
Therefore, the volume of the block is increasing at a rate of \(6 ft^3/hour\) at this time.
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If the zeros of a quadratic function are 3 and 8, what are the factors of the function?
A.
(x + 8) and (x − 3)
B.
(x − 8) and (x + 3)
C.
(x + 8) and (x + 3)
D.
(x − 8) and (x − 3)
Answer:
D
Step-by-step explanation:
one way to write a quadratic equation is using the y = (x-s) (x-r) where r and s are positive zeros. another way to solve this and think about it would be to plug in your points and equate both sides.
example:(3,0) (8,0)0 = (3-8) (3-3)0 = 00 = (8-8) (8-3)0=0
300g of bananas cost £1.80. how much does 1kg cost?
Answer:
£6
Step-by-step explanation:
300 g = .3 kg
We can use ratios to solve
.3 kg 1 kg
------------- = -----------
1.8 x
Using cross products
.3x = 1 * 1.8
.3x = 1.8
Divide each side by .3
.3x/.3 = 1.8/.3
x =6
A college baseball stadium has 6,925 seats. During 12 games this season, the stadium sells out and fills every seat.
How many tickets were sold for those 12 games?
The number of tickets sold during the 12 games is 83,100 tickets
How to calculate the number of tickets sold ?The college stadium has 6,925 seats for the baseball games this season.
During the entire 12 baseball games, al the seats were filled up and tickets were sold out.
Therefore the number of tickets sold in the entire 12 games can be calculated by multiplying 6,925 by 12
= 6925 × 12
= 83,100
Hence 83,100 tickets were sold in the entire 12 games
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a company manufactures rice in 10 kg bags with a standard deviation of 1.25 kg per bag. what is the probability that a random sample of 15 bags will have a mean between 9 and 9.5 kgs?
Probability that a random sample of 15 bags will have a mean between 9 and 9.5 kgs is 0.0596.
What is probability ? Probability is simply the possibility that something will happen. We may talk about the possibility of one result, or the likelihood of numerous outcomes, when we don't know how an event will turn out. The study of events with a probability distribution is known as statistics.Calculation\(\sigmaT = \sigma / \sqrtn = 1.25 / \sqrt15 = 0.3227\)
\(= P[(9 - 10) / 0.3227 < (T - \muT ) / \sigmaT < (9.5 - 10) / 0.3227)]\)
= P(-3.10 < Z < -1.55)
= P(Z < -1.55) - P(Z < -3.10)
= 0.0606 - 0.001
= 0.0596
Probability that a random sample of 15 bags will have a mean between 9 and 9.5 kgs = 0.0596
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Which systems have infinite solutions? check all that apply. y = 0.5x 2.75 and 2y = x 2.75 y = 0.5x 2.75 and y – 0.5x = 2.75 y = 0.5x 2.75 and 0.5x y = 2.75 y = 0.5x 2.75 and y = 0.5(x 5.5) y = 0.5x 2.75 and y = –2(–0.25x ) 2.75
Both equations y = 0.5x + 2.75 and y – 0.5x = 2.75 are equal. Hence, these systems will have infinite solutions. Hence, Option a is the most suitable answer to this question.
The system of equations having an infinite number of solutions must be the same.
In option a -
we have, y = 0.5x + 2.75 and 2y = x + 2.75
Rewriting the second equation 2y = x + 2.75 in slope-intercept form, we get,
2y = x + 2.75
y = x/2 + 2.75/2
y = 0.5x + 1.375
Both equations are not similar.
Hence this option is not the right choice.
Similarly, we will check for option b -
we have, y = 0.5x + 2.75 and y – 0.5x = 2.75
From the second equation y - 0.5x = 2.75, this can be expressed as y = 0.5x + 2.75 in the slope-intercept form.
Here, we get both equations equal.
Thus, y = 0.5x + 2.75 and y – 0.5x = 2.75 will have infinite solutions.
Similarly, checking for other options, we do not get any similar equations.
Hence, option b is the correct answer to this question.
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The complete question is -
Which systems have infinite solutions? Check all that apply.
a) y = 0.5x + 2.75 and 2y = x + 2.75
b) y = 0.5x + 2.75 and y – 0.5x = 2.75
c) y = 0.5x + 2.75 and 0.5x + y = 2.75
d) y = 0.5x + 2.75 and y = 0.5(x + 5.5)
e) y = 0.5x + 2.75 and y = –2(–0.25x )+ 2.75
Answer: look at the screenshot below I hope it helps you, my friend
have a lovely day :3 :) :D
UWU
Step-by-step explanation:
which of the following statements correctly outputs the names of voters who live in district 6 and all voters who live in district 7?
the following statements correctly outputs the names of voters who live in district 6 and all voters who live in district 7:
if(district == 6 || district == 7)
System.out.println("Name is " + name);
What is output?Output is any information processed by and transmitted by a computer or other electronic device. Anything visible on your computer monitor screen, such as the text you write on your keyboard, is an example of output. The information produced by a system or process as a result of a certain input is referred to as output. The inputs are what are placed into a system in the context of systems theory, and the outputs are the outcomes gained after executing a whole process or just a tiny section of a process. The system's inputs are the signals or data it receives, and its outputs are the signals or data it sends. The phrase can also refer to an activity; to "perform I/O" is to carry out an action.
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Deon's coffee shop makes a blend that is a mixture of two types of coffee. type a coffee costs deon $5.45 per pound, and type b coffee costs $4.20 per pound. this month's blend used four times as many pounds of type b coffee as type a, for a total cost of $578.50. how many pounds of type a coffee were used?
Deon's Coffee Shop used 26 pounds of type A coffee.
Let's consider Deon's Coffee Shop, which used "a" pounds of type A coffee and "4a" pounds of type B coffee. The total cost of the blend is $578.50, so we can equate the total cost of the type A and type B coffee to that amount. This leads us to the following equation: 5.45a + 4.20(4a) = 578.50.
To solve the equation, we simplify it: 5.45a + 16.80a = 578.50. Combining like terms, we get 22.25a = 578.50.
To find the value of "a," we divide both sides of the equation by 22.25. Therefore, a = 26. Hence, Deon's Coffee Shop used 26 pounds of type A coffee.
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Using suitable identity, find the value of 87^3+ 13^3/
87^2 −87 ×13 + 13^2
The value of the given expression [\(87^3+ 13^3/87^2 -87 * 13 + 13^2\)] by simplifying the numerator and denominator using suitable identities is 100.
We will first calculate the numerator:
As (\(a^3\) + \(b^3\)) = (a + b)(\(a^2\) - ab + \(b^2\)) :
\(87^3\) + \(13^3\) = (87 + 13)(\(87^2\) - \(87 * 13\) + \(13^2\))
= 100(\(87^2\) - 87 * 13 + \(13^2\))
Now, calculate the denominator:
\(87^2 - 87 * 13 + 13^2\)
As,(\(a^2 -2ab +b^2\)) =\((a - b)^2\):
\(87^2 - 87 * 13 + 13^2 = (87 - 13)^2\)
\(= 74^2\)
So by solving the equation further:
\((87^3+13^3) / (87^2- 87 * 13+13^2) = 100*(87^2- 87 *13 + 13^2)/(87^2 - 87 * 13 + 13^2)\)
As we can see the numerator and denominator are the same expressions (\(87^2 - 87 * 13 + 13^2\)). so, they cancel each other:
\((87^3 + 13^3) / (87^2 - 87 * 13 + 13^2) = 100\)
So, the value of the given expression is 100.
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What is an equation of the line that passes through the points
(−4,−5) and
(−2,−6)? Put your answer in fully reduced form.
Answer:
(– 4,– 5) = –9
(– 2,– 6) = –8
a boat travels 30 miles up the river in the same amount of time it takes to travel 42 miles down the same river. if the current is 3 miles per hour, what is the speed of the boat in still water? in still water, the boat travels at miles per hour.
The boat travels at 18 miles per hour.
What is speed?
Speed is calculated as follows: speed = distance / time. Knowing the units for distance and time is necessary to calculate the units for speed.
The rate at which an object travels a certain distance can be described using the speed formula. The distance that a body travels in a certain amount of time is a common way to measure speed.
Given: A boat travels 30 miles up the river in the same amount of time it takes to travel 42 miles down the same river. The current is 3 miles per hour.
From the above information we can write,
Let, u is the boat speed in still water, then
\(\frac{30}{u-3} = \frac{42}{u+3}\)
Taking cross multiplication,
30(u + 3) = 42(u - 3)
Solving,
30u + 90 = 42u - 126
42u - 30u -126 -90 = 0
12u = 216
u = 18
Therefore, the speed of boat in still water is, 18 miles per hour.
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