Answer: 9.7 seconds
Step-by-step explanation:
\(16t^2=1503\\\\t^2 =\frac{1503}{16}\\\\t=\sqrt{1503/16} \text{ } (t > 0)\\\\t \approx 9.7\)
Which formula will return the correlation coefficient between data in cells A1:A5 and 11:35? Select an answer: =CORRELATE(B1:B5, A1:AS) =CORREL (A1:AS, B1:B5) =CORRELATE(A1:31, AS:85) CORREL (A1, B1)
The formula that will return the correlation coefficient between data in cells A1:A5 and B11:B35 is =CORREL(A1:A5, B11:B35).
The correlation coefficient is a statistical measure that quantifies the relationship between two variables. It ranges from -1 to 1, where a value of -1 indicates a perfect negative correlation, 1 indicates a perfect positive correlation, and 0 indicates no correlation.
To calculate the correlation coefficient using the CORREL function, we need to provide the two sets of data as arguments. In this case, the data in cells A1:A5 represents one set of values, and the data in cells B11:B35 represents another set of values.
The formula =CORREL(A1:A5, B11:B35) takes these two sets of data as input. It computes the correlation coefficient between the values in cells A1:A5 and B11:B35, considering each pair of corresponding values.
By using the CORREL function with the appropriate range of cells, we can obtain the correlation coefficient between the two sets of data. The resulting value will give us insights into the strength and direction of the relationship between the variables represented by the data.
It is worth noting that the CORREL function assumes a linear relationship between the variables. If the relationship is nonlinear, the correlation coefficient may not fully capture the nature of the association. Therefore, it is important to interpret the correlation coefficient in conjunction with other relevant information and consider the context of the data.
In summary, to calculate the correlation coefficient between data in cells A1:A5 and B11:B35, the formula =CORREL(A1:A5, B11:B35) should be used. This formula provides a measure of the linear relationship between the two sets of data and helps us understand the strength and direction of the association.
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Which could be an equation of the trend line shown in graph?
A. y = 6x + 12
B. y = 8x + 15
C. y = 6x + 6
D. y = 8x + 8
Answer C
Step-by-step explanation:.
It's a math problem about graphing. thank you
To reach the highest point, time taken by the rocket is taken from the x axis that is 16 seconds.
Explain about the parabolic path:A projectile that we launch travels along a parabolic path. Its motion has a horizontal component and then a vertical component, which can be investigated separately.
The projectile simply continues to travel horizontally at its initial horizontal velocity (its horizontal component of both the initial velocity) until it comes to a stop. Gravity and the vertical component of a velocity are present vertically.
From the given graph:
x-axis represents the time taken by the rocket to from launch to falling back on ground.
y-axis shows the height travelled by the rocket at the different time intervals.
From graph - Peak coordinates are( 16, 4096)
Highest point - 4096 feet
To reach the highest point, time taken by the rocket is taken from the x axis that is 16 seconds.
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Dora travels between the two mile markers shown and then finds her average speed in miles per hour. Select the three equations that represent this situation.
The image of the 2 mile markers is missing as well as the options and so i have attached them.
Answer:
> 1.5 hours = 105 miles/speed
> Speed = 105 miles/1.5 hours
> 105 miles = 1.5 hours × speed
Step-by-step explanation:
From the image attached, the distance of the first mile marker is given as 50 miles while the distance of the second mile marker is given as 155 miles.
Thus, difference in distance between the two markers; d = 155 - 50 = 105 miles
Also, we see that the time of first marker is 3 pm while the second marker is 4:30 pm.
Thus, difference in time = 4:30 - 3 = 1 hour 30 minutes or 1.5 hours.
We know that;
Speed = distance/time
Thus;
Speed = 105/1.5
Speed = 70 mph
Thus, the 3 equations that represent this situation from the options are;
> 1.5 hours = 105 miles/speed
> Speed = 105 miles/1.5 hours
> 105 miles = 1.5 hours × speed
Answer:
1.5 hours = 105 miles/speed
Speed = 105 miles/1.5 hours
105 miles = 1.5 hours × speed
Step-by-step explanation:
Solve for X on the triangle.
A farmer has 696 acres of pasture for sheep grazing, and 40 acres for growing cotton. An average of 8 sheep graze on one acre. How many sheep does the farmer have?
Step-by-step explanation:
\(1 \: acre \: = \: 8 \: sheeps \\ 696 \: acres \: = 8 \times 696 = 5568 \: sheeps\)
help
I'm really stuck
HELP IM BAD AT MATH
Answer:
B. Yes
Step-by-step explanation:
Compare the age of the earth to the age of the oldest known rocks found
The Earth is estimated to be around 4.54 billion years old, while the oldest known rocks found on Earth date back to about 4 billion years ago.
Determining the age of the Earth is a complex process that involves a variety of scientific disciplines. Geologists and other scientists have used a variety of methods to estimate the age of the planet, including radiometric dating, which involves measuring the decay of radioactive isotopes in rocks and other materials.
The age of the oldest known rocks found on Earth has also been determined using radiometric dating techniques. These rocks, which are primarily found in Western Greenland, have been dated to around 3.8 to 4.0 billion years old. The rocks are believed to have formed during the Hadean Eon, a period of Earth's history when the planet was still in its early stages of formation and was subject to intense meteorite bombardment.
It's important to note that the age of the Earth and the age of the oldest known rocks found on its surface are not precise measurements.
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if certain sheets of wrapping paper have a mean weight of 10 g each, with a standard deviation of 0.05 g, what are the mean weight
The mean weight of certain sheets of wrapping paper is 10 g each.
The mean weight of the sheets of wrapping paper is given as 10 g each. This means that on average, each sheet weighs 10 grams. The standard deviation of the weight of the sheets is given as 0.05 g.
This indicates the degree of variability or spread in the weight of the sheets around the mean weight of 10 g. A standard deviation of 0.05 g suggests that most of the sheets will have a weight that is very close to 10 g, with only a few sheets having a weight that deviates significantly from the mean.
The mean weight of the sheets of wrapping paper can be used as a reference point for determining the weight of a particular sheet or for calculating the weight of a bundle of sheets.
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a+1=1 find the value of b^a
Answer:
1
Step-by-step explanation:
a+1=1
a=1-1
a=0
b^a which means:
b^0
whenever power is 0 answer is always one
so value of b^a is 1
Carla has a rectangular garden in her backyard. The width of the garden is 9 meters. The area of the garden is 360 square meters. What is the length of the garden? Show your work.
Answer:
l = 40 m
Step-by-step explanation:
The formula for area of a rectangle is
A = lw, where
A is the area in square units,l is the length,and w is the widthStep 1: Since we're given the area and width, we plug in these two values for A and w and to solve for l (length):
360 = 9l
Step 2: Divide both sides by 9 to solve for l
(360 = 9l) / 9
40 m = l
Optional Step 3: We can check our answers by checking that the product of 40 and 9 is 360
40 * 9 = 360
360 = 360
Determine whether the zero state is a stable equilibrium of the dynamical system x(t+1)=Ax(t), where A=⎣⎡0.30.30.30.30.30.30.30.30.3⎦⎤ [Note: Zero state refers to the case where x(0)=0.]
We can see that one of the eigenvalues is λ = 0.Since one eigenvalue is 0, which has magnitude less than 1, we can conclude that the zero state is a stable equilibrium of the dynamical system x(t+1) = Ax(t) with the given matrix A.
To determine whether the zero state (x(0) = 0) is a stable equilibrium of the dynamical system x(t+1) = Ax(t), we need to examine the eigenvalues of the matrix A.
The zero state is a stable equilibrium if and only if all eigenvalues of A have magnitudes less than 1.
Let's calculate the eigenvalues of matrix A. We solve the characteristic equation det(A - λI) = 0, where I is the identity matrix:
|0.3-λ 0.3 0.3|
| 0.3 0.3-λ 0.3|
| 0.3 0.3 0.3-λ|
Expanding the determinant, we get:
(0.3-λ) [(0.3-λ)^2 - 0.3^2] - 0.3 [(0.3-λ)(0.3-λ) - 0.3^2] + 0.3 [(0.3)(0.3-λ) - 0.3(0.3-λ)] = 0
Simplifying, we obtain:
(0.3-λ) (0.09 - 0.09λ) - 0.09(0.3-λ) + 0.09(0.3-λ) = 0
(0.3-λ) (0.09 - 0.09λ) = 0.
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Find the gradient of the line segment between the points (2,3) and (-3,8).
Answer:
\(m = -1\)
Step-by-step explanation:
Given
Points (2,3) and (-3,8)
Required
Determine the gradient
Gradient (m) is calculated by dividing the change in y values by the change in x values.
i.e.
\(m = \frac{y_2 - y_1}{x_2 - x_1}\)
Where:
\((x_1,y_1) = (2,3)\)
\((x_2,y_2) = (-3,8)\)
\(m = \frac{y_2 - y_1}{x_2 - x_1}\) becomes
\(m = \frac{8 - 3}{-3 -2}\)
\(m = \frac{5}{-5}\)
\(m = -1\)
Hence, the gradient is -1
Solve the following equations . a² = 64. 2x-2 = 16. 3y² = 27
Answer:
-3
Step-by-step explanation:
a² = 64
Taking the square root of both sides, we get:
a = ±√64
a = ±8
Therefore, the solutions to the equation a² = 64 are a = 8 and a = -8.
2x-2 = 16
Adding 2 to both sides, we get:
2x = 18
Dividing both sides by 2, we get:
x = 9
Therefore, the solution to the equation 2x-2 = 16 is x = 9.
3y² = 27
Dividing both sides by 3, we get:
y² = 9
Taking the square root of both sides, we get:
y = ±√9
y = ±3
Therefore, the solutions to the equation 3y² = 27 are y = 3 and y = -3.
2. Find {y}(0.4) for y^{\prime}+0.2 y=0, y(0)=5, h=0.2
Therefore, the value of y at t = 0.4 is 5.To find the value of y at t = 0.4, we can use the Euler's method. Here are the steps to solve the given differential equation.
1. Given the differential equation y' + 0.2y = 0, we need to find the value of y at t = 0.4.
2. Start with the initial condition y(0) = 5. This gives us the starting point for our approximation.
3. Let's choose a step size h = 0.2. This means we will approximate the value of y at t = 0.4 using the values of y at t = 0, t = 0.2, and t = 0.4.
4. To approximate y at t = 0.2, we use the formula:
y(0.2) = y(0) + h * (dy/dt)(0)
= 5 + 0.2 * [y'(0) + 0.2 * y(0)]
5. Substitute the values into the formula:
y(0.2) = 5 + 0.2 * [y'(0) + 0.2 * 5]
6. Now, let's find the value of y'(0):
Given the differential equation, y' + 0.2y = 0, we can rearrange it to find y':
y' = -0.2y
7. Substitute this value into the formula:
y(0.2) = 5 + 0.2 * [-0.2 * 5 + 0.2 * 5]
8. Simplify the equation:
y(0.2) = 5 + 0.2 * [0]
= 5
9. Now, to find y at t = 0.4, we repeat the process using the values of y at t = 0.2 and t = 0.4:
y(0.4) = y(0.2) + h * (dy/dt)(0.2)
= 5 + 0.2 * [y'(0.2) + 0.2 * y(0.2)]
10. Substitute the values into the formula:
y(0.4) = 5 + 0.2 * [(-0.2 * 5) + 0.2 * 5]
11. Simplify the equation:
y(0.4) = 5 + 0.2 * [0]
= 5.
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In order to compute the area of a particular circle, Juan first measures the length of its diameter. The actual diameter is 20 cm, but Juan's measurement has an error of up to $20\%$. What is the largest possible percent error, in percent, in Juan's computed area of the circle
The largest possible error in the area of the circle is of 44%.
What is the area of a circle?The area of a circle of radius r is given by:
\(A = \pi r^2\)
With a diameter of 20 cm = radius of 10 cm, the area in cm² is given by:
\(A = \pi \times 10^2 = 100\pi\)
With the error, with a diameter of 20 x 1.2 = 24 cm = radius of 12 cm, the area in cm² is given by:
\(A = \pi \times 12^2 = 144\pi\)
The error is given by:
\(E = 144\pi - 100\pi = 44\pi\)
The percent error is the error divided by the initial amount, multiplied by 100%, hence:
\(P = \frac{44\pi}{100\pi} \times 100\% = 44\%\)
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Instructions
Choose the best answer. If necessary, use the paper you were given.
Question
A rectangular swimming pool is x meters wide. The length of the swimming pool is twice as long as the width.
If the perimeter of the pool is 64 meters, which of the following equations represents the given information?
x+x+2x+2x = 64
x+2x = 64
x+2+x+2 = 64
2x + 2x + 2x + 2x = 64
x + x +2x + 2x = 64 is the right equation
How to check perimeter of rectangle ?
In given question wide of swimming pool is xand the length of pool is twice of width that is 2x The given perimeter of pool is 64 meter.The formula for perimeter of rectangle is P = 2*(l+w)
we have perimeter , 64 = 2* (2x + x)
64 = x + x + 2x +2x
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Two people start from the same point. One bicycles west at 12 mi/h and the other jogs south at 5 mi/h. How fast is the distance between the prople changing three hours after they leave their starting point?
Three hours after they leave their starting point, the rate at which the distance between the two people is changing is 13 mi/h.
What is Distance?Distance is the actual path traveled by a moving particle in a given time interval. It is a scalar quantity.
To find the rate at which the distance between the two people is changing, we can use the concept of relative velocity. The relative velocity is the vector difference of the velocities of the two individuals.
Given that one person is moving west at 12 mi/h and the other is moving south at 5 mi/h, we can represent their velocities as:
Velocity of the person cycling west: v₁ = -12i (mi/h)
Velocity of the person jogging south: v₂ = -5j (mi/h)
Note that the negative sign indicates the direction opposite to their motion.
The distance between the two people can be represented as a vector from the starting point. Let's denote the distance vector as r = xi + yj, where x represents the displacement in the west direction and y represents the displacement in the south direction.
To find the rate of change of the distance between the two people, we differentiate the distance vector with respect to time (t):
dr/dt = (d/dt)(xi + yj)
Since the people start from the same point, the position vector at any time t can be expressed as r = xi + yj.
Differentiating with respect to time, we have:
dr/dt = (dx/dt)i + (dy/dt)j
The velocity vectors v₁ and v₂ represent the rates of change of x and y, respectively. Therefore, we have:
dr/dt = v₁+ v₂
Substituting the given velocities:
dr/dt = -12i - 5j
Now, we can find the magnitude of the rate of change of the distance vector:
|dr/dt| = |v₁+ v₂|
|dr/dt| = |-12i - 5j|
The magnitude of the velocity vector dr/dt is given by:
|dr/dt| = √((-12)² + (-5)²)
|dr/dt| = √(144 + 25)
|dr/dt| = √(169)
|dr/dt| = 13 mi/h
Therefore, three hours after they leave their starting point, the rate at which the distance between the two people is changing is 13 mi/h.
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I need to know what z = xm + y, for x
Answer: xm + y = z xm = z - y x = (z - y)/(m)
Step-by-step explanation: hope this helped :)
Answer:
x = (z - y) / m
Step-by-step explanation:
z = xm + y
xm + y = z
xm = z - y
x = (z - y) / m
A conical paper cup is 10 cm tall with a radius of 10 cm. The cup is being filled with water so that the water level rises at a rate of 2 cm/sec. At what rate is water being poured into the cup when the water level is 9 cm
The required rate for water being poured into the cup when the water level is 9 cm = 40.5π cm³/sec
For given question,
We have been given the height of a conical paper cup i.e., h = 10 cm
and the radius of a conical paper cup r = 10 cm
The cup is being filled with water so that the water level rises at a rate of 2 cm/sec
We need to find the rate at which water being poured into the cup when the water level is 9 cm
We know that the volume of the cone is \(V=\frac{\pi r^2 h}{3}\)
We can relate h and r as we know that the slope = h/r
= 10/5
= 2
Now, we make the volume a formula in a single variable
\(\Rightarrow V=\frac{\pi (\frac{h}{2} )^2 h}{3}\\\\\Rightarrow V=\frac{\pi h^3}{12}\)
Differentiating above equation with respect to time,
\(\Rightarrow V'=\frac{3\pi h^2 h'}{12} \\\\\Rightarrow V'=\frac{\pi h^2 h'}{4}\)
Substituting values,
\(\Rightarrow V'=\frac{\pi \times 9^2\times 2}{4}\\\\\Rightarrow V'=40.5\pi~~cm^3/sec\)
Therefore, the required rate for water being poured into the cup when the water level is 9 cm = 40.5π cm³/sec
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a food marketing institute found that 32% of households spend more than $125 a week on groceries. assume the population proportion is 0.32 and a simple random sample of 145 households is selected from the population. what is the probability that the sample proportion of households spending more than $125 a week is less than 0.3?
Using the normal distribution, the probability that the sample proportion of households spending more than $125 a week is less than 0.3 is 30.29%.
Normal distribution refers to a continuous probability distribution wherein values lie in a symmetrical fashion mostly centered around the mean. In a normal distribution, the probability is calculated using the z-score of a measure X. A Z-score refers to a numerical measurement that defines a value's relationship to the mean (of a group of values).
In order to determine the probability of the sample proportion, the z-score of a measure X is determined.
z-score = (X - µ)/σ where µ is the mean and σ is the standard deviation.
The standard deviation σ = √(p(1-p)/n
From the given data:
n = no of random sample = 145
p = probability of success (household spending more than $125) = 0.32
Hence,
σ = √((0.32(1-0.32)/145) = 0.0387
Calculating the z-score when X = 0.3
z-score = (0.3 – 0.32)/0.0387 = -0.516
From the table, the probability of z = -0.516
P(X<z) = 0.30293 or 30.29%
The probability that the sample proportion of households spending more than $125 a week is less than 0.3 is 30.29%.
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The statement "P implies Q' is FALSE under which of the following conditions? Choose all that apply. a. P and Q are both true. b. P and Q are both false. c. P is true and Q is false. d. P is false and Q is true.
The statement "P implies Q" is false under the following conditions: a) P is true and Q is false, and d) P is false and Q is true.
The statement "P implies Q" can be expressed as "if P, then Q." It is a conditional statement where P is the antecedent (the condition) and Q is the consequent (the result).
To determine when the statement is false, we need to identify cases where P is true but Q is false, or when P is false but Q is true.
Option a) states that both P and Q are true. In this case, the statement "P implies Q" holds true because if P is true, then Q is true.
Option b) states that both P and Q are false. In this case, the statement "P implies Q" is considered true because the antecedent (P) is false.
Option c) states that P is true and Q is false. Under this condition, the statement "P implies Q" is false because when P is true, but Q is false, the implication does not hold.
Option d) states that P is false and Q is true. In this case, the statement "P implies Q" is true because the antecedent (P) is false.
Therefore, the conditions under which the statement "P implies Q" is false are a) P is true and Q is false, and d) P is false and Q is true.
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"Which of the Following is true based on the diagram?"
1 AB←→ ⊥ CD←→
2 AB←→ // CD←→
3 AB←→ ∦ CD←→
The Image is in the file below
Answer:
Bro perpendicular is when the lines are connected in the form you know
This line I and j are parallel to each other so the answer Is 2
Please Help
Write an equation for the nth term of the arithmetic sequence 47, 38, 29, 20, ....
An equation for the nth term of the arithmetic sequence is
Answer:
-9
Step-by-step explanation:
They all follow the same sequence such as -9 for ex 47-9 is 38
Find the inequality represented by the graph.
Answer: y<3x-4
Step-by-step explanation:
\((0,-4) \ \ \ \ \ \ (1,-1)\)
The equation of the line
\(\displaystyle\\\boxed {\frac{x-x_1}{x_2-x_1}=\frac{y-y_1}{y_2-y_1} }\)
\(\displaystyle\\x_1=0\ \ \ \ x_2=1\ \ \ \ y_1=-4\ \ \ \ y_2=-1\\Hence,\\\frac{x-0}{1-0} =\frac{y-(-4)}{-1-(-4)} \\\\\frac{x}{1} =\frac{y+4}{-1+4} \\x=\frac{y+4}{3}\)
Умножьте обе части уравнения на 3:
\(3x=y+4\\3x-4=y+4-4\\3x-4=y\)
Thus, y<3x-4
simplify 1/2 a -4 pllleeeeeezzzzzzzzzzzzzzzz
Answer:
\( \frac{a}{2} - 4\)
Step-by-step explanation:
1) Simplify 1/2 a to a/2.
a/2 - 4
Therefor, the answer is a/2 - 4.
Answer:
a/2-4
Step-by-step explanation:
1) Simplify 1/2 a to a/2.
a/2 - 4
And then the answer is a/2 - 4.
Activated charcoal was used to absorb toxic compound in a solution of 500 mL0.2 M. After adding 1 g of activated charcoal, which has a surface area of 100 m 2
, the concentration of the toxic compound became 0.18M. (a) Determine the area occupied by a single molecule of the toxic compound on the surface of the charcoal. (Assume Avogadro number =6.022×10 23
per mole) (10 points) (b) Determine the surface area of the activated charcoal if the area occupied by a single molecule of the toxic compound on the surface of the charcoal is 3.32×10 −
21
m 2
. (Assume all other conditions remain the same) (10 points) (c) If 2 g of activated charcoal was added, what would happen to the concentration of the toxic materials?
The concentration of the toxic materials would decrease if 2 g of activated charcoal was added to the solution.
When activated charcoal is added to a solution, it adsorbs (not absorbs) the toxic compounds, meaning it binds to the surface of the charcoal particles. The surface area of the activated charcoal plays a crucial role in its adsorption capacity. In this case, the initial amount of activated charcoal added was 1 g, which had a surface area of 100 m²/g.
By adding 2 g of activated charcoal, the total surface area available for adsorption would double to 200 m². This increased surface area would allow more toxic compounds to bind to the charcoal particles, resulting in a decrease in their concentration in the solution.
It's important to note that the concentration reduction would not be linearly proportional to the increase in activated charcoal, as adsorption also depends on factors like the concentration of the toxic compounds and their affinity for the charcoal surface. Nonetheless, the overall effect would be a decrease in the concentration of the toxic materials in the solution.
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Do exponent laws apply all the time when simplifying variables?
It is true that exponent laws apply all the time when simplifying variables
How to determine the true statement?The laws of exponent state that:
\((ab)^m = a^m * b^m\)
\((a+ b)^m \ne a^m + b^m\)
\((a- b)^m \ne a^m - b^m\)
\((a/b)^m \ne a^m / b^m\)
The above laws must be followed in all variables.
When any of the law is misinterpreted, misrepresented or misused in simplifying variables, the result would be incorrect
Hence, it is true that exponent laws apply all the time when simplifying variables
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A group of adult males has foot lengths with a mean of 26.84 cm and a standard deviation of 1.29 cm. Use the range rule of thumb to identify the limits separating values that are significantly low or significantly high. Is the adult male foot length of 23.8 cm significantly low or significantly high?
Significantly low values are ___ cm or lower.
Significantly high values are ___ cm or higher.
Select the correct choice below and fill in the answer box(es) to complete your choice.
A) The adult male foot length of 23.8 cm is not significant because it is between __ cm and __ cm
B) The adult male foot length of 23.8 cm is significantly low because it is less than __ cm
C) The adult male foot length of 23.8 cm is significantly high because it is greater than __ cm
The option B, "The adult male foot length of 23.8 cm is significantly low because it is less than 24.26 cm" is correct.
In the given question, a group of adult males has foot lengths with a mean of 26.84 cm and a standard deviation of 1.29 cm.
We have to find the adult male foot length of 23.8 cm significantly low or significantly high.
According to thumb rule, a value is significantly low if it is 2 standard deviations below mean and significantly high if it is 2 standard deviations above mean
Mean = 26.84 cm
Standard deviation = 1.29 cm
Significantly low value = 26.84 - 2*1.29 = 24.26 cm
Significantly high value = 26.84 + 2*1.29 = 29.42 cm
Significantly low values are 24.26 cm or lower.
Significantly high values are 29.42 cm or higher.
The adult male foot length of 23.8 is lower than the significant low value of 24.26.
So the option B, "The adult male foot length of 23.8 cm is significantly low because it is less than 24.26 cm" is correct.
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A box is to be made out of a 10 cm by 20 cm piece of cardboard. Squares of side length cm will be cut out of each corner, and then the ends and sides will be folded up to form a box with an open top. (a) Express the volume V of the box as a function of x. V = cm^3 (b) Give the domain of V in interval notation. (Use the fact that length and volume must be positive.) = ? (c) Find the length L , width W, and height H of the resulting box that maximizes the volume. (Assume that W < or = to L ) L= ?cm W= ?cm H= ? cm (d) The maximum volume of the box is ? cm^3.
(a) The volume V of the box as a function of x is V = 4x^3-60x^2+200x
(b) The domain of V in interval notation is 0<x<5,
(c) The length L , width W, and height H of the resulting box that maximizes the volume is H = 2.113, W = 5.773, L= 15.773
(d) The maximum volume of the box is 192.421 cm^2.
In the given question,
A box is to be made out of a 10 cm by 20 cm piece of cardboard. Squares of side length cm will be cut out of each corner, and then the ends and sides will be folded up to form a box with an open top.
(a) We have to express the volume V of the box as a function of x.
If we cut out the squares, we'll have a length and width of 10-2x, 20-2x respectively and height of x.
So V = x(10-2x) (20-2x)
V = x(10(20-2x)-2x(20-2x))
V = x(200-20x-40x+4x^2)
V = x ( 200 - 60 x + 4x^2)
V = 4x^3-60x^2+200x
(b) Now we have to give the domain of V in interval notation.
Since the lengths must all be positive,
10-2x > 0 ≥ x < 5 and x> 0
So 0 < x < 5
(c) Now we have to find the length L , width W, and height H of the resulting box that maximizes the volume.
We take the derivative of V:
V'(x) = 12x^2-120x+200
Taking V'(x)=0
0 = 4 (3x^2-30x+50)
3x^2-30x+50=0
Now using the quadratic formula:
x=\(\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)
From the equationl a=3, b=-30, c=50
Putting the value
x=\(\frac{30\pm\sqrt{(-30)^2-4\times3\times50}}{2\times3}\)
x= \(\frac{30\pm\sqrt{900-600}}{6}\)
x= \(\frac{30\pm\sqrt{300}}{6}\)
x= \(\frac{30\pm17.321}{6}\)
Since x<5,
So x= \(\frac{30-17.321}{6}\)
x= 2.113
So H = 2.113, W = 5.773, L= 15.773.
d) Now we have to find the maximum volume of the box.
V = HWL
V= 2.113*5.773*15.773
V = 192.421 cm^3
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